#15 Please HELP!!!!!!!!!!!!!!!

Step-by-step explanation: Solve for y by simplifying both sides of the equation, then isolating the variable. y = 0

Hope it helped :D

The Probability that a student will complete the exam 0.2676.

The probability of completing the exam in one hour or less is:

[tex]P (x < 60)[/tex]

= [tex]P (z < (60-83)/13)[/tex]

=[tex]P (z < -1.77)[/tex]

= 0.0384.

The probability that a student will complete the exam in more than 60 minutes, but less than 75 minutes is.

[tex]P (60 < x < 75)[/tex]

= [tex]P (x < 75)-P (x < 60)[/tex]

Now,

[tex]P (x < 75)[/tex]

=[tex]P (z < (75-83)/13)[/tex]

= [tex]P (z < -0.62)[/tex]

=0.2676.

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Answer:

To calculate the minimum sample size required for a given margin of error and confidence level, we can use the following formula:

n = (z^2 * p * (1-p)) / E^2

where:

Substituting the values, we get:

n = (2.576^2 * 0.5 * (1-0.5)) / 0.05^2

n = 664.3

Rounding up to the nearest whole number, the smallest number of consumers that Timex can survey to guarantee a margin of error of 0.05 or less at a 99% confidence level is 665.

The sample space are:

{AR, AS, AT, AE, RA, RS, RT, RE, SA, SR, ST, SE, TA, TR, TS, TE, EA, ER, ES, ET}

The favorable outcomes care:

{RS, RT, SR, ST, TR, TS}

The probability is  0.3 or 30%

Part A:

The sample space represents all possible outcomes that can occur when two cards are randomly selected without replacement from the given pile of cards.

The sample space can be represented as follows:

{AR, AS, AT, AE, RA, RS, RT, RE, SA, SR, ST, SE, TA, TR, TS, TE, EA, ER, ES, ET}

Part B:

The favorable outcomes are those outcomes in which both cards are consonants. In this case, the consonants are R, S, and T.

The favorable outcomes can be represented as follows:

{RS, RT, SR, ST, TR, TS}

Part C:

To calculate the probability of selecting 2 cards that are consonants, we need to find the ratio of favorable outcomes to the sample space.

The number of favorable outcomes is 6, and the size of the sample space is 20.

Therefore, the probability of selecting 2 cards that are consonants is:

P(consonants) = favorable outcomes / sample space

P(consonants) = 6 / 20

P(consonants) = 0.3 or 30%

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Thus, the appropriate measure of variability found for the given data is 10.

The difference here between maximum and smallest values in a data set is known as the range. Utilizing the exact same units as the data, it measures variability. More variability is shown by larger values.

Given length of ribbons:

3, 6, 9, 11, 12, 13

Minimum value = 3

Maximum value = 13

Actually, the range, which is determined by deducting the lowest value from the greatest value in the dataset, would be the proper measure of variability for this data.

Range = Maximum value - Minimum value

Range = 13 - 3

Range = 10

Thus, the appropriate measure of variability found for the given data is 10.

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Answer:

49th term = 225

Step-by-step explanation:

The following sequence: -15, -10, -5, 0, -5... is an example of an arithmetic progression.

An arithmetic progression or AP for short, is a sequence in which the difference between successive terms is constant. This difference is known as the common difference, and can be found by subtracting a term by its preceding term.

The general formula, for the nth term of an arithmetic progression, is thus:

Tn = a + (n - 1)d, where a = first term, and d = common difference.

In the sequence: -15, -10, -5, 0, 5...,

a = -15, and d = -10--15 = 5

T49 = -15 + (49 - 1)5 = 225

∴ 49th term = 225

∠A = ∠C in trapezoid ABCD with arcAB = arcCD, can be proven with the property of isosceles triangles.

Since arcAB = arcCD, the lengths of the two arcs are equal. This implies that the lengths of the segments subtended by these arcs, AB and CD, are also equal.

Let E and F be the midpoints of the non-parallel sides AD and BC, respectively. Connect E and F with a line segment EF.

Since E and F are midpoints, DE = EA and BF = FC. In addition, since AB = CD = L, we can say that:

DE + EA = BF + FC

EA = FC

So, by the Hypotenuse-Leg (HL) theorem of congruence, triangles AEF and CFE are congruent:

ΔAEF ≅ ΔCFE

Now, since the triangles are congruent, their corresponding angles are equal:

∠A = ∠C

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The work done in lifting the lower end of the chain to the ceiling so that it is level with the upper end is 250 ft-lb.

The work done in lifting the lower end of the chain to the ceiling can be calculated using the formula for work, which is given by:

Work = force x distance

In this case, the force is the weight of the chain, which is 25 lb, and the distance is the length of the chain, which is 10 ft.

So, the work done in lifting the lower end of the chain to the ceiling is:

Work = 25 lb x 10 ft

Work = 250 ft-lb

Therefore, the work done in lifting the lower end of the chain to the ceiling so that it is level with the upper end is 250 ft-lb.

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The work done in lifting the lower end of the chain to the ceiling so that it is level with the upper end is 125 ft-lb.

The work done in lifting the lower end of the chain to the ceiling so that it is level with the upper end is 125 ft-lb.

To find the work done in lifting the lower end of the chain to the ceiling, we need to consider the average weight of the chain as it is being lifted.

1. First, find the weight per foot of the chain:Weight of chain = 25 lbLength of chain = 10 ftWeight per foot = (25 lb) / (10 ft) = 2.5 lb/ft2.

Determine the average weight being lifted:Since you're lifting the chain from one end, the average weight you're lifting is half of the chain's total weight.

Average weight = (25 lb) / 2 = 12.5 lb3. Calculate the work done:Work done = Force x DistanceForce = Average weight = 12.5 lbDistance = Length of chain = 10 ftWork done = (12.5 lb) x (10 ft) = 125 ft-lb

So, the work done in lifting the lower end of the chain to the ceiling so that it is level with the upper end is 125 ft-lb.

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We'd need a sample size of at least 659 to estimate the population proportion with a periphery of error of 0.03.

To find the sample size demanded a confidence interval with a periphery of error of 0.03, we need to use the following formula

n = ( zσ/ E) * ( zσ/ E) * pq

where

z is the z- score corresponding to the asked position of confidence( let's assume 95 confidence, which corresponds to a z- score of 1.96)

σ is the population standard deviation( which is unknown in this case, so we'll use a conservative estimate of0.5)

E is the periphery of error( which is0.03)

p is the estimated proportion( which is0.41)

q = 1- p

Plugging in the values, we get

n = (1.960.5/0.03) * (1.960.5/0.03*0.41( 1-0.41) ≈658.72

Rounding up, we get a sample size of 659. thus, we'd need a sample size of at least 659 to estimate the population proportion with a periphery of error of 0.03, assuming a 95 confidence position and a population proportion estimate of 0.41.

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We can see that they are similar because the ratio of the corresponding sides of the triangle are the same = 5/3.

A triangle is a polygon with three sides and three angles. It is one of the most basic shapes in geometry and is formed when three non-collinear points are connected by straight lines. The three sides of a triangle can have different lengths, and the three angles can have different measures. Triangles can be classified based on their sides and angles.

BC/DE = AD/AB

15/9 = AB/6

AB = (15 × 6)/9 = 90/9 = 10.

15/9 = 10/6 = 5/3.

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The scouts are using quantitative analysis.

If the shaded area of a circle is 25 cm squared. if the diameter of the circle is 10cm, the percentage of the circle is shaded is: 31.83% .

We can start by finding the area of the entire circle. The formula for the area of a circle is:

A = πr^2

where A is the area and r is the radius. Since the diameter of the circle is 10 cm, the radius is half of that, or 5 cm. Therefore, the area of the entire circle is:

A = π(5 cm)^2 = 25π cm^2

Next, we can find what percentage of the circle is shaded by dividing the shaded area by the total area of the circle and multiplying by 100:

Percentage shaded = (shaded area / total area) x 100

Percentage shaded = (25 cm^2 / 25π cm^2) x 100

Percentage shaded = 100 / π ≈ 31.83%

Therefore, approximately 31.83% of the circle is shaded.

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Therefore (t) can  be written as **(2 - 3Q) / (Q + 4)**.

Within the given equation, Q is a variable. It stands for an unknowable amount or value that can be ascertained by equation-solving.

A quantity that can take on any one of a number of values is referred to as a variable. A variable in mathematics is a symbol or letter that denotes an unknowable amount or value. The variable Q in the given equation stands for an unknowable quantity or value that can be ascertained by resolving the equation.

The equation is as follows:

Q = (2 - 4t) / (t + 3)

When we divide both sides by (t + 3), we obtain:

Q(t + 3) = 2 - 4t

When we increase the left side of the equation, we obtain:

Qt + 3Q = 2 - 4t

The result of adding 4t to both sides of the equation is:

Qt + 3Q + 4t = 2

Combining related concepts gives us:

t(Q + 4) = 2 - 3Q

The result of dividing both sides by (Q + 4) is:

t = (2 - 3Q) / (Q + 4)

t can therefore be written as **(2 - 3Q) / (Q + 4)**.

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Answer:

Step-by-step explanation:

Rolling a number greater than 7 on a number cube with sides numbered 1 through 6: The probability of rolling a number greater than 7 on a number cube with sides numbered 1 through 6 is 0, as it is not possible to roll a number greater than 6 on a standard six-sided die.

Picking the 8 of Hearts from a standard deck of playing cards: The probability of picking the 8 of Hearts from a standard deck of playing cards is 0, as there is no 8 of Hearts in a standard deck of playing cards.

A spinner with 6 equal sections labeled 1 through 6 lands on a number less than 7: The probability of a spinner with 6 equal sections labeled 1 through 6 landing on a number less than 7 is 1, as all the sections are labeled with numbers less than 7.

Flipping a coin and having it land with the heads side facing up: The probability of flipping a coin and having it land with the heads side facing up is 0.5 or 50%, assuming the coin is fair and has two equally likely sides.

Rolling a sum of 14 with two number cubes with sides 1-6: The probability of rolling a sum of 14 with two number cubes with sides 1-6 is 0, as the highest possible sum that can be obtained by rolling two number cubes with sides 1-6 is 12 (6 + 6).

What is the probability of rolling an even number on a dice? The dice is numbered 1-6: The probability of rolling an even number on a dice numbered 1-6 is 0.5 or 50%, as there are three even numbers (2, 4, and 6) and three odd numbers (1, 3, and 5) on a standard six-sided die.

The following M & M colors are in the bowl: 4 yellow, 6 orange, 3 green, 5 blue, 2 brown. What is the probability of selecting a blue candy? The probability of selecting a blue candy from the bowl is 5/20 or 1/4, as there are 5 blue candies in the bowl out of a total of 20 candies.

A number cube is labeled 1 through 6. The probability of randomly rolling a 4 is 1 over 6. What is the probability of not rolling a 4? The probability of not rolling a 4 on a number cube labeled 1 through 6 is 5/6, as there are 5 possible outcomes that are not 4 (1, 2, 3, 5, and 6) out of a total of 6 possible outcomes.

Picking a purple ball from a bag containing 7 purple balls and 1 green ball: The probability of picking a purple ball from a bag containing 7 purple balls and 1 green ball is 7/8, as there are 7 purple balls out of a total of 8 balls in the bag.

im sorry I don't know how to delete this but i now realize that my awnser was completely wrong.

The total number of defective iphones from a batch of 16,530 iphones is equal to 513 .

Total  number of iphones examined by quality-control inspector =290

Total number of iphones in a batch = 16,530

Number of iphones defective out of 290 = 9

Let us consider x be the number of defective iPhones in the batch of 16,530 iPhones.

Use proportions to find out how many defective iPhones there will be in a batch of 16,530 iPhones.

The proportion of defective iPhones in the sample of 290 iPhones is,

= 9/290

Proportion of defective iPhones in a batch of 16,530 iPhones,

Set up a proportion,

9/290 = x/16530

To solve for x, we can cross-multiply,

⇒ 9 x 16530 = 290 x

⇒ 148,770 = 290 x

⇒ x = 513

Therefore, there will be approximately 513 defective iPhones in a batch of 16,530 iPhones.

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Answer: 13

Step-by-step explanation:

The equation with the new substitutions and conversion factor is a'B'T' = (1/6) * (2/3)^(1/3) * a^(1/3) * d^(1/2)*a^6/6 where k is (1/6) * (2/3)^(1/3) * a^(1/3) * d^(1/2) The intercept value of the log-log graph would have been -1.108.

Starting with Equation 4: T = ka^6/6, we can substitute a = (d/k)^(1/6) and b = (2/3)^(1/2) * (d/k)^(1/3) to get

T = k[(d/k)^(1/6)]^6/6

T = k(d/k)^(1/2)/6

T = (k^(1/2)/6) * d^(1/2)

Now we can rearrange the equation so that a, b, and t are on the left side

a'B'T' = ka^6/6

(a/d)^(1/6) * b^(2/3) * T' = k[(a/d)^(1/6)]^6/6 * T'

(a/d)^(1/6) * (2/3)^(1/2) * (d/k)^(1/3) * T' = (k^(1/2)/6) * d^(1/2) * T'

(2/3)^(1/2) * (a/d)^(1/6) * d^(1/3) * T' = (k^(1/2)/6) * d^(1/2) * T'

(2/3)^(1/2) * (a/d)^(1/6) * d^(1/3) = k^(1/2)/6

k = [(2/3)^(1/2) * (a/d)^(1/6) * d^(1/3)]^2/6

k = (1/6) * (2/3)^(1/3) * a^(1/3) * d^(1/2)

With this new conversion factor, the intercept of the log-log graph would have changed. The intercept represents the value of T when a = 1 (since log(1) = 0). Using the new conversion factor, we have

T = (1/6) * (2/3)^(1/3) * d^(1/2) * a^(1/3)

T = (1/6) * (2/3)^(1/3) * d^(1/2)

log(T) = log[(1/6) * (2/3)^(1/3) * d^(1/2)]

log(T) = log(1/6) + log[(2/3)^(1/3)] + log(d^(1/2))

log(T) = log(1/6) + (1/3) * log(2/3) + (1/2) * log(d)

So the intercept of the log-log graph would be log(1/6) + (1/3) * log(2/3) = -1.108, assuming that d is held constant. This intercept represents the value of log(T) when log(a) = 0, or when a = 1. In other words, when a = 1, the predicted value of T would be 0.162 (or 16.2% of its maximum value).

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--The given question is incomplete, the complete question is given

" Plug the two substitutions into Equation 4 (T = ka^6/6)). Rearrange the equation so that a, b,t are on the left side of the equation and d remains on the right side, e.g. a'B'T' = ka^6/6 you will figure out what the "k" if you used this version of the equation (including your new conversion factor, how would this have changed the intercept of your log-log graph? what would its value have been?"--

Answer: To solve for c and v, we need to use the equation:

4c + 6v = 80

We have two variables and one equation, so we need another equation to solve for c and v. We can use the fact that the number of students transported by the drivers is 80. Since each car can seat 4 students and each van can seat 6 students, we can write:

4c + 6v = 80

c + v = number of drivers

Since we want to minimize the number of drivers, we want to minimize the value of c + v. We can use substitution to solve for c and v in terms of one variable. Solving for c in terms of v from the first equation, we get:

4c + 6v = 80

4c = 80 - 6v

c = (80 - 6v)/4

Substituting this expression for c into the second equation, we get:

c + v = number of drivers

(80 - 6v)/4 + v = number of drivers

Multiplying both sides by 4 to clear the fraction, we get:

80 - 6v + 4v = 4(number of drivers)

80 - 2v = 4(number of drivers)

20 - 0.5v = number of drivers

We want to minimize the value of c + v, so we want to minimize the value of v. Since v must be a whole number, we want to find the smallest integer value of v that satisfies the equation. We can plug in integer values of v and find the corresponding value of c, and check if the sum of c and v is less than or equal to the current minimum. Starting with v = 1, we get:

v = 1 -> c = 19.5 -> c + v = 20.5

v = 2 -> c = 18.0 -> c + v = 20.0

v = 3 -> c = 16.5 -> c + v = 19.5

v = 4 -> c = 15.0 -> c + v = 19.0

v = 5 -> c = 13.5 -> c + v = 18.5

v = 6 -> c = 12.0 -> c + v = 18.0

The smallest integer value of v that satisfies the equation is v = 6, which gives c = 12. Therefore, we need 12 cars and 6 vans to transport 80 students.

Step-by-step explanation:

Answer:47

7•7

Step-by-step explanation:

the surface area of the cylinder represented by the given net is approximately 166.306 square feet.

To calculate the surface area of a cylinder using its net, we need to identify the different components of the net and their measurements.

Without the specific net provided, I will assume a standard net of a cylinder, consisting of two circles for the top and bottom faces, and a rectangle for the lateral (side) surface.

Given that the measurements provided are 10 ft and 16 ft, we can assume that the height of the cylinder is 10 ft and the circumference of the circular bases is 16 ft.

The surface area of a cylinder is given by the formula:

Surface Area [tex]= 2 \times \pi \times r \times (r + h)[/tex]

where r is the radius of the circular base and h is the height of the cylinder.

Since the circumference of the circular base is given as 16 ft, we can calculate the radius (r) using the formula:

Circumference [tex]= 2 \times π times r[/tex]

[tex]16 = 2 \times π \times r[/tex]

[tex]r = 16 / (2 \times \pi)[/tex]

[tex]r v\ approx 2.546 ft[/tex] (rounded to three decimal places)

Now that we know the radius (r) and the height (h) of the cylinder, we can substitute these values into the formula for surface area:

Surface Area  [tex]= 2 \times π \times 2.546 \times (2.546 + 10)[/tex]

Surface Area  [tex]\approx 166.306 ft^2[/tex] (rounded to three decimal places)

Therefore, the surface area of the cylinder represented by the given net is approximately  [tex]166.306[/tex] square feet.

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If x is a non-negative real number, then the expression √ x is called the Principal square root. The answer is Principal Square Root.

What is Principal Square Root?

The positive square root of a non-negative real integer is the principal square root. It is the one and only non-negative real number that, when squared, yields the given non-negative real number. The principal square root of 9 is 3, for example, because 3 multiplied by itself equals 9.

The radical sign (√) is frequently used to represent the principal square root. The term √x denotes Principal square root of x. The sign can be used to indicate the negative square root of x in some settings, but this is less frequent.

The principal square root notion is significant in mathematics, including algebra, geometry, and calculus. It's used to solve equations, simplify expressions, and calculate lengths and distances. It's also used in a wide range of scientific and engineering applications.

Therefore, if x is a non-negative real number, then the expression √ x is called the Principal square root.

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If x is a nonnegative real number, then the expression √ x is called the square root of x. The square root of a nonnegative real number is a value that, when multiplied by itself, equals the original number.

If x is a nonnegative real number, then the expression √x is called the "principal square root" of x. The principal square root of a nonnegative real number x is the nonnegative real number that, when multiplied by itself, equals x. In other words, if y = √x, then y * y = x. This ensures that the result is also a nonnegative real number.

For example, the square root of 4 is 2 because 2 multiplied by 2 equals 4. The square root function is denoted by the symbol √ and is used to find the positive number that, when squared, gives the input value.

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9. The volume of the triangular pyramid is given by:

V = (1/3)Bh

Here, B is the base area.

The base is shaped as a right triangle thus, using the Pythagoras Theorem we have:

h = sqrt(26.7² - 11.7²) = 23.274 km

The area if the base is:

B = (1/2)bh = (1/2)(11.7 km)(23.4 km) = 136.89 sq. km

Now, the volume is:

V = (1/3)(136.89)(15) = 2053.35 cubic km

Hence, the volume of the triangular pyramid is 2053.35 cubic km.

9. The volume of the triangular pyramid is 2053.35 cubic km. 11. The area of the shaded portion is 348.19 cubic in 13. The slant height of the cone is 8.53 meters.

A fundamental conclusion in geometry relating to the lengths of a right triangle's sides is known as Pythagoras' theorem. According to the theorem, the square of the length of the hypotenuse, the side that faces the right angle, in any right triangle, equals the sum of the squares of the lengths of the other two sides, known as the legs.

9. The volume of the triangular pyramid is given by:

V = (1/3)Bh

Here, B is the base area.

The base is shaped as a right triangle thus, using the Pythagoras Theorem we have:

h = √(26.7² - 11.7²) = 23.274 km

The area if the base is:

B = (1/2)bh = (1/2)(11.7 km)(23.4 km) = 136.89 sq. km

Now, the volume is:

V = (1/3)(136.89)(15) = 2053.35 cubic km

Hence, the volume of the triangular pyramid is 2053.35 cubic km.

11. The volume of a cone is given by:

V = (1/3)πr²h

The dimension of the bigger cone is radius is 9 in, and height 15 in:

V1 = (1/3)π(9 in)²(15 in) = 381.7 cubic in

The dimension of the smaller cone is radius is 4 in, and height 10 in:

V2 = (1/3)π(4 in)²(10 in) = 33.51 cubic in

Now, the area of the shaded portion is:

V1 - V2 = 381.7 - 33.51  = 348.19

13. The volume of a cone is given by:

V = (1/3)πr²h

Substituting the values we have:

542.87 = (1/3)π(6 m)²h

h = 542.87 / [(1/3)π(6 m)²] = 6.05 m

Now, using the Pythagoras Theorem for the slant height we have:

s² = r² + h²

s² = (6 m)² + (6.05 m)²

s² = 72.9

s = √(72.9) = 8.53 m

The slant height of the cone is 8.53 meters.

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A congruence transformation that maps triangle RST to triangle UVW is a reflection along the line y = 1, followed by a translation 2 units right and down by 1 units.

A congruence transformation that maps triangle RST to triangle UVW is a rotation of 180°, followed by a translation 2 units left and down by 5 units.

In Mathematics and Geometry, a transformation is the movement of a point from its initial position to a new location. This ultimately implies that, when a geometric figure or object is transformed, all of its points would also be transformed;

In Mathematics and Geometry, a reflection can be defined as a type of transformation which moves every point of the geometric figure such as a triangle, by producing a flipped, but mirror image of the geometric figure.

By critically observing the geometric figures, we can reasonably infer and logically deduce that the pre-image underwent a sequence of congruence transformation to produce the image.

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The results of the balls in Phillip's bag are:

The mean = 8.

The median = 7.

The mode = blue

The range = 12

The mean (or the average) is the sum of all the values divided by the total number of values. Let's calculate the mean for the given data:

Total number of balls = 8 + 3 + 6 + 3 + 13 + 15 = 48

Mean = (8 + 3 + 6 + 3 + 13 + 15) / 6 = 48 / 6 = 8

Mean = 8.

The median is the middle value when a set of values is arranged in ascending or descending order.

Let's arrange the given data in ascending:

3, 3, 6, 8, 13, 15

As the total number of values is even, the median will be the average of the two middle values, which are 6 and 8.

Median = (6 + 8) / 2 = 7

The median = 7.

The mode is the value that appears most frequently in a set of values. Let's find the mode of the given data:

Red balls: 8

Green balls: 3

Yellow balls: 6

Orange balls: 3

Black balls: 13

Blue balls: 15

Blue balls have the highest frequency (i.e., 15) among all the colors.

The range is the difference between the highest and lowest values in a set of values. Let's find the range of the given data:

Highest value = 15 (blue balls)

Lowest value = 3 (green balls and orange balls)

Range = Highest value - Lowest value = 15 - 3 = 12

Range = 12.

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More people that rode the roller coaster are between the ages of 11 and 30, than people that are between the ages of 41 and 60 is the best description of the data which is obtained by using the arithmetic operations.

What are arithmetic operations?

Any real number may be explained using the four basic operations, also referred to as "arithmetic operations." Operations like division, multiplication, addition, and subtraction come before operations like quotient, product, sum, and difference in mathematics.

We are given a chart. From the chart we get the following data:

Number of people aged 11 - 20 riding roller coaster = 20

Number of people aged 21 - 30 riding roller coaster = 15

Number of people aged 31 - 40 riding roller coaster = 10

Number of people aged 41 - 50 riding roller coaster = 5

Number of people aged 51 - 60 riding roller coaster = 0

Using addition operation, we get

Total people = 20 + 15 + 10 + 5 + 0

Total people = 40

Now,

Total riders between 11 - 30 = 20 + 15

Total riders between 11 - 30 = 35

Similarly,

Total riders between 41 - 60 = 5 + 0

Total riders between 41 - 60 = 5

Hence, the fourth option is the correct answer.

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There were about 557 principals in attendance."

"The college will have about 480 students who prefer cookies."

The best prediction is "The college will have about 480 students who prefer cookies."

Bus 18 typically has the faster travel time, and the closest answer choice is "Bus 18, with a median of 13."

Out of the 70 people in the exhibit room, 52 were principals. Thus, the proportion of principals in that room was 52/70 = 0.74. If we assume that the proportion of principals in the entire conference was similar, we can predict the number of principals in attendance by multiplying the total number of attendees by 0.74:

Number of principals = 750 * 0.74 = 555

So the closest answer choice is "There were about 557 principals in attendance."

Out of the 225 students surveyed, 27 preferred cookies. To estimate the number of cookies the college will need, we can use the ratio of students who prefer cookies to the total number of students:

Number of cookies = (27/225) * 4000 = 480

Therefore, the best prediction is "The college will have about 480 students who prefer cookies."

The given data represents the number of students who prefer each sport. The appropriate graph to display this data is a bar graph. The bars should be labeled with the sports, and the heights of the bars should correspond to the number of students.

The correct graph is: bar graph with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44

To compare the travel times of the two buses, we need to look at the measure of center that represents the typical value. The median is the middle value when the data is arranged in order, and the mean is the average value. We can see from the line plots that the travel times for both buses are somewhat spread out, so the median is likely to be a more reliable measure of center than the mean.

Looking at the two line plots, we can see that Bus 18 has more dots to the left of the center of the distribution than Bus 47, indicating that Bus 18 generally has shorter travel times. To confirm this, we can calculate the median for each bus:

For Bus 18, the median is the average of the two middle values, which are 12 and 14. So the median is (12 + 14) / 2 = 13.

For Bus 47, the median is the middle value, which is 16.

Therefore, Bus 18 typically has the faster travel time, and the closest answer choice is "Bus 18, with a median of 13."

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The probability Milo will be assigned a writing homework is equal to 0,50.

Let us consider the event 'A' represents the assigned Math's homework.

And 'B' represents the assigned writing homework.

Probability of Milo assigned math homework = 0. 35

⇒P(A) = 0.35

Probability of Milo assigned math and writing homework = 0. 20

⇒P(A∩B ) = 0.20

Probability of Milo assigned either homework = 0. 65

⇒P(A∪B) = 0.65

Let the Probability of Milo assigned  writing homework = P(B)

Using the Formula of probability we get,

P(A∪B) = P(A) + P(B) - P(A∩B )

Substitute the value we have,

⇒ 0.65 = 0.35 + P(B) - 0.20

⇒P(B) = 0.65 - 0.15

⇒P(B) = 0.50

Therefore, the probability of writing homework being assigned to Mila is equal to 0.50.

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Therefore, the 99% confidence interval for the population mean is 305 - 30 to 305 + 30, which is between 275 and 335 pages.

The correct interpretation of the 99% confidence interval is that we estimate with 99% confidence that the true population mean is between 275 and 335 pages. This is because the confidence interval is based on the sample mean and the standard deviation of the sample, and it provides a range of values within which we can be reasonably confident that the true population mean lies. The fact that the sample was randomly selected helps to ensure that the estimate is representative of the overall population of books in the library. The population standard deviation of 45 pages is used to calculate the standard error of the mean, which in turn is used to construct the confidence interval.
We estimate with 99% confidence that the true population mean is between 275 and 335 pages.

Explanation:
1. A random sample of 15 books is taken from the library.
2. The sample mean (305 pages) is calculated from the random sample.
3. The population standard deviation is given as 45 pages.
4. To construct a 99% confidence interval for the population mean, we need to use the standard deviation and the sample mean.
5. The formula for the margin of error in a confidence interval is: Margin of Error = Z-score * (Standard Deviation / [tex]\sqrt{SampleSize}[/tex])
6. For a 99% confidence interval, the Z-score is approximately 2.576.
7. Margin of Error = 2.576 * (45 / √15) ≈ 30
8. The confidence interval for the population mean is: (Sample Mean - Margin of Error) to (Sample Mean + Margin of Error)
9. Therefore, the 99% confidence interval for the population mean is 305 - 30 to 305 + 30, which is between 275 and 335 pages.

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the correct interpretation of the 99% confidence interval is:

"We estimate with 99% confidence that the true population mean is between 275.08 and 334.92 pages."

Based on the given information, we can calculate the 99% confidence interval for the true population mean of pages per book in the library.

Here are the steps to calculate the confidence interval:
Identify the given information:

population standard deviation [tex](\sigma) = 45[/tex] pages, sample size [tex](n) = 15[/tex] books, and sample mean [tex](\bar x) = 305[/tex] pages.
Calculate the standard error (SE) of the sample mean:

[tex]SE = \sigma / \sqrt n = 45 / \sqrt 15 \approx 11.62.[/tex]
The critical value (z) for a 99% confidence level:

[tex]z \approx 2.576[/tex] (from a standard normal distribution table or using a calculator).
Calculate the margin of error (ME):

[tex]ME = z \times SE \approx 2.576 \times 11.62 \approx 29.92.[/tex]
Determine the confidence interval:

[tex](\bar x - ME, \bar x + ME) = (305 - 29.92, 305 + 29.92) \approx (275.08, 334.92).[/tex]

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