a 200 kg rock lies on the surface of a planet. the acceleration due to gravity on the surface of the planet is 6,0. calculate the mass of the planet if it's radius is 700km​

Answers

Answer 1

Answer:

4.41 × 10²² kg

Explanation:

Let the mass of planet be M, rock be m

Therefore,

[tex]net \: force \: on \: rock \: = weight \\ (200)(6) = \frac{(6.67 \times 10 {}^{ - 11})(200)(m) }{(700000) {}^{2} } \\ m = 4.41 \times 10 {}^{22} \: kg[/tex]


Related Questions

can someone help me :)

Answers

Answer:

mass= 60kg

velocity= 10m/s

momentum = mass × velocity

p=m×v

p= 60×10

p= 600kgm/s


9- When the moon comes in an orbit higher from earth, ......... solar eclipse are formed.
a) total
b) annular
c) partial. d) annular and partial

Answers

C partial solar eclipse are formed

2. A3 kg ball rolls forward toward a 6 kg ball moving in the opposite direction at 4.6 m/s to
the left. After their collision, the 3 kg ball bounces backward at 4.2 m/s to the left and the 6 kg
ball continues to the left at 1.5 m/s in the same direction. What was the initial velocity of the
3 kg ball?

Answers

Answer:

m1 v1 + m2 v2 = m1 V1 + m2 V2       conservation of momentum

m1 = 3    m2 = 6

v2 = -4.6

V1 = -4.2

V2 = -1.5

v1 = (m1 V1 + m2 V2 - m2 v2) / m1

v1 = (3 * -4.2 + 6 * -1.5 - 6 * -4.6) / 3

v1 = (-12.6 - 9 + 27.6) / 3 = 2  initial velocity of 3 kg ball

Check:

3 * 2 + 6 * -4.6 = -21.6

3 * -4.2 + 6 -1.5 = -21.6

Which statements about braking a car are true?
The greater the kinetic energy of a car, the longer it takes for the car to stop.
The lower the kinetic energy of a car, the longer it takes for the car to stop.
If the speed of a car doubles, the car’s kinetic energy and braking distance quadruple.
If the speed of a car doubles, the car’s kinetic energy and braking distance remain the same.

Answers

Answer:

the first statement...

Answer:

The first answer is correct.

Plz mark brainliest.

Hope I helped.

Explanation:

Explain in detail why you cannot hear in space but you can see light(explanation includes particle movement of liquid, solids, gases, and plasma)

Answers

Answer:

The reason why one cannot hear in space but light can be seen is because light and sound are different kinds of wave

Light is an electromagnetic wave that propagates by a changing magnetic field hat creates a changing electric field. Light is created by a vibrating electric charge, and is transmitted through a medium by the absorption and reemission of the light by the medium particles

Sound is a longitudinal mechanical wave that is propagated by the vibration of the particles of the medium.

Sound requires a medium to propagate and it cannot be propagated or heard through space which is a vacuum.

Sound is created by a source that is vibrating and the vibration is transmitted to particles in the medium including solids, liquids, gases and plasma that the vibrating energy is in direct contact with and the transfer of the sound energy continues between layers of adjacent particles for the medium for the sound to be propagated from place to place

Explanation:

HELP!!

Differentiate between hertz and decibel.​

Answers

Answer:

Explanation:Hertz is used to measure frequency, but decibel is used to measure intensity level.

A wire of radius 5 x 10⁻⁴ m is needed to prepare a coil of resistance 40 Ω. The resistivity of the material of the wire is 3.14x10⁻⁷ Ωm. Calculate the length of the wire.

Answers

Answer:

100 m

Explanation:

From the question,

R = Lρ/A.................... Equation 1

Where R = resistance of the wire, L = length of the wire, ρ = resistivity of the wire, A = cross sectional area of the wire.

But,

A = πr².................... Equation 2

Where r = radius of the wire.

Substitute equation 2 into equation 1

R = Lρ/πr²

Make L the subject of the equation

L = Rπr²/ρ...................... Equation 3

Given: R = 40 Ω, r = 5×10⁻⁴ m, ρ = 3.14×10⁻⁷ Ωm

Constant: π = 3.14

Substitute these values into equation 3

L = [40×3.14×( 5×10⁻⁴)²]/ (3.14×10⁻⁷)

L = 40×3.14×25×10⁻⁸/(3.14×10⁻⁷)

L = 100 m

Hence the length of the wire is 100 m

A moving object has a kinetic energy of 150J and a momentum of 20.3kgxm/s find the speed of the object in m/s

Answers

Answer:

[tex]v = 14.78m/s[/tex]

Explanation:

Given

[tex]KE = 150J[/tex]

[tex]p = 20.3kgm/s[/tex]

Required

Determine the object's speed

Kinetic Energy is calculated as:

[tex]KE = \frac{1}{2}mv^2[/tex]

Make m the subject

[tex]m = \frac{2KE}{v^2}[/tex]

Momentum is calculated as:

[tex]p = mv[/tex]

Make m the subject

[tex]m = \frac{p}{v}[/tex]

So, we have:

[tex]m = \frac{p}{v}[/tex] and [tex]m = \frac{2KE}{v^2}[/tex]

Equate both expressions: [tex]m = m[/tex]

[tex]\frac{2KE}{v^2} = \frac{p}{v}[/tex]

Multiply both sides by v

[tex]v * \frac{2KE}{v^2} = \frac{p}{v}*v[/tex]

[tex]\frac{2KE}{v} = p[/tex]

Make v the subject

[tex]v = \frac{2KE}{p}[/tex]

Substitute [tex]KE = 150J[/tex] and [tex]p = 20.3kgm/s[/tex]

[tex]v = \frac{2 * 150}{20.3}[/tex]

[tex]v = \frac{300}{20.3}[/tex]

[tex]v = 14.78m/s[/tex]

A race car has a mass of 710kg. It starts from rest and speeds up to 12m/s in 12.0s. The car is uniformly accelerated during the entire time. What net force is applied to it?

Answers

First calcualte the acceleration =V/t=12/12=1m/s2
Second calcualte the net force according to the Newton second law
F=ma=710x1=710N

A + 32.2 μC charge feels a 0.544 N force from a + 12.3p μC charge. How far apart are they? (u stands for micro.) [?] m

Answers

Answer:

r = 2.55 m

Explanation:

Given that,

First charge, q₁ = 32.2 μC

Second charge, q₂ = + 12.3 μC

The force between charges, F = 0.544 N

We need to find the distance between charges. The force between two charges is given by the formula as follows :

[tex]F=k\dfrac{q_1q_2}{r^2}\\\\r=\sqrt{\dfrac{kq_1q_2}{F}} \\\\r=\sqrt{\dfrac{9\times 10^9\times 32.2\times 10^{-6}\times 12.3\times 10^{-6}}{0.544}} \\\\r=2.55\ m[/tex]

So, the charges are 2.55 m apart.

Answer:

2.55

Explanation:

Right on Acellus

Give the other guy brainliest

You can only give brainliest if 2 people answer

Calculati rezistenta filamentului unui bec al lanternei de buzunar daca la tensiunea de 3,5 v el este parcurs de un curent cu intensitatea de 0,28 A

Answers

Answer:

Resistencia = 12.5 Ohmios

Explanation:

Dados los siguientes parámetros;

Voltaje = 3.5 Volts

Corriente = 0.28 Amps

Para encontrar el resistencia;

La ley de Ohm establece que a temperatura constante, la corriente que fluye en un circuito eléctrico es directamente proporcional al voltaje aplicado en los dos puntos e inversamente proporcional a la resistencia en el circuito eléctrico.

Matemáticamente, La ley de Ohm viene dada por la fórmula;

Voltaje = corriente * resistencia

Resistencia = voltaje/corriente

Resistencia = 3.5/0.28

Resistencia = 12.5 Ohmios

Por tanto, la resistencia del filamento de una linterna de bolsillo es de 12,5 ohmios.

The body needs small amounts of ________ to help enzymes break down proteins.

Answers

Answer:

I would say vitamin B-6

Explanation:

it is also known as pyridoxine. it helps ebzymes break down protein and carry the dismantled amino acids to the blood stream

Hope this helps ✌✌

Answer:

The body needs small amount of vitamin B-6 to help enzymes break down protein and carry the dismantled amino acids to the blood stream.

Define Inertia.
___________✨​

Answers

Answer:

a tendency to do nothing or to remain unchanged.

Explanation:

Answer:

Inertia: The resistance an object has to a change in its state of motion.

Explanation:

Hope it helps....

Have a great day!!

A 1,000 kg car traveling 15.0 m/s brakes and comes to a stop after traveling 20.0 m.


a. What is the car’s initial kinetic energy?
b. What is the car’s final kinetic energy?
c. How much work does it take to stop the car?
d. How much constant force is applied in bringing the car to a stop?

Answers

a. initial kinetic
Ek=1/2mv ²
Ek=1/2(1000)(15²)
Ek=112,500J

b. final kinetic energy=0J
as it comes to a stop so v=0

c. Work = ∆Energy
Or
Work=Fs

∆E/W= initial energy - final energy
∆E/W=112,500-0
∆E/W=112,500 J

d.W=Fs

112,500=F(20)
112,500/20 =F
F=5625 N

A. The car’s initial kinetic energy is 112500 J

B. The car’s final kinetic energy is 0 J

C. The amount of work done to stop the car is –112500 J

D. The force applied in bringing the car to a stop is –5625 N

A. How to determine the initial kinetic energy Mass (m) = 1000 KgInitial velocity (u) = 15 m/sInitial kinetic energy (KEᵢ) =?

KEᵢ = ½mu²

KEᵢ = ½ × 1000 × 15²

KEᵢ = 112500 J

B. How to determine the final kinetic energy Mass (m) = 1000 KgFinal velocity (v) = 0 m/sFinal kinetic energy (KEբ) =?

KEբ = ½mv²

KEբ = ½ × 1000 × 0²

KEբ = 0 J

C. How to determine the workdone Initial kinetic energy (KEᵢ) = 112500 J Final kinetic energy (KEբ) = 0 JWorkdone (Wd) =?

Wd = KEբ – KEᵢ

Wd = 0 – 112500

Wd = –112500 J

D. How to determine the force

We'll begin by calculating the acceleration. This can be obtained as follow:

Initial velocity (u) = 15 m/sFinal velocity (v) = 0 m/sDistance (s) = 20 mAcceleration (a) =?

v² = u² + 2as

0² = 15² + (2 × a × 20)

0 = 225 + 40a

Collect like terms

0 – 225 = 40a

–225 = 40a

Divide both side by 40

a = –225 / 40

a = –5.625 m/s²

Finally, we shall determine the force. This is illustrated below:

Mass (m) = 1000 KgAcceleration (a) = –5.625 m/s²Force (F) =?

F = ma

F = 1000 × –5.625

F = –5625 N

Learn more about energy:

https://brainly.com/question/10703928

Which of the following combinations would result in the least acceleration?
O SN and 0.35 kg
60N and 2.0 kg
O 12N and 1.0 kg
O IN and 0.20 kg

Answers

1N and 0.20 kg/////////

a solid sphere of mass and radius 20kg and 4m is rotating with an angular velocity of 40rad/sec is accelerated uniformly to 60rad/sec in 2sec what is the torque acting on the sphere? (I=0•4MR^2)​

Answers

Answer:

1280Nm

Explanation:

torque= I×alpha(angular acceleration)

so Angular acceleration is found by the following process.

A sound wave is propagating through the air from left to right as shown in the diagram below.

Answers

Answer:

Explanation: Pules

Answer: longitudinal (compression)

Explanation:

please help!!

A baseball cannon fires balls at an initial speed of 29 m/s. The cannon is tilted at a 52o angle.
(a) How long could one of these balls stay in the air ?
(b) How far from the cannon, will the ball hit the ground ?
(c) What will be ball’s maximum altitude ?

Answers

Answer:

(a) The time the ball stays in the air is approximately 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is approximately 83.18 meters

(c) The maximum altitude of the ball is approximately 26.62 m

Explanation:

The given parameters of the question are;

The initial velocity at which a baseball cannon fires balls, u = 29 m/s

The angle at which the cannon is tilted, θ = 52°

(a) The time duration the ball stays in the air is given by the time of flight of the projected ball as follows;

[tex]2 \cdot t = \dfrac{2 \cdot u \cdot sin (\theta)}{g}[/tex]

Where;

t = The time it takes the baseball to reach maximum height

2·t = The total time of flight = The time the ball stays in the air

θ = The angle at which the ball is tilted = 52°

g = The acceleration due to gravity ≈ 9.81 m/s²

u = The initial velocity = 29 m/s

Therefore, we have;

[tex]2 \cdot t = \dfrac{2 \times 29 \ m/s\times sin (52^{\circ})}{9.81 \ m/s^2} \approx 4.66 \ s[/tex]

The time the ball stays in the air, 2·t ≈ 4.66 seconds

(b) The distance from the cannon at which the ball will hit the ground is given by the horizontal range, 'R', of the projectile as follows;

[tex]Horizontal \ range, R = \dfrac{u^2 \cdot sin(2 \cdot \theta) }{g}[/tex]

∴ The distance from the cannon at which the ball will hit the ground = R

[tex]Horizontal \ range, R = \dfrac{(29 \ (m/s))^2 \cdot sin(2 \times 52^{\circ}) }{9.81 \ m/s^2} \approx 83.18 \, m[/tex]

The distance from the cannon at which the ball will hit the ground = R ≈ 83.18 meters

(c) The maximum altitude of the ball is equal to the maximum height reached by the ball, H, which is given as follows;

[tex]H = \dfrac{u^2 \cdot sin^2 (\theta)}{2 \cdot g}[/tex]

Therefore, we have;

[tex]H = \dfrac{(29 \ m/s)^2 \times sin^2 (52^{\circ})}{2 \times 9.81 \ m/s^2} \approx 26.62 \ m[/tex]

The maximum altitude of the ball ≈ 26.62 m

A lawn mower is pushed with a force of 79 N. If 11,099 J of work are done on mowing the lawn, what is the total distance the lawn mower was pushed? Round your answer to a whole number (no decimal places).

Answers

Answer:

141m

Explanation:

Wondering if you have enough rope to rappel to the ground, you drop a rock off the top, and hear the sound of it hitting the bottom 4.2 seconds later. Find the height of the cliff ignoring the time that the sound takes to travel back to you from the bottom.

Answers

Answer:

86.5 m

Explanation:

[tex]s = ut + \frac{1}{2} at {}^{2} \\ s = (0)(4.2) + \frac{1}{2} (9.81)(4.2) {}^{2} \\ s = 86.5m [/tex]

Answer:

86.5 m

Explanation:

e Which of the following particles that may be emitted in radioactive decay is not ionising?
A alpha
B beta minus
C neutron
D beta plus

Answers

Explanation:

C. neutron.

it does not contain ionizing characteristics.

hope it helps. :)

1. On planet Jupiter, the acceleration due to
gravity is about 26 m/s2. How high would a boy
be able to throw a ball on Jupiter if he can
throw it vertically 10m high on Earth?​

Answers

Answer:

The boy can throw the ball to a height of 3.85 m on Jupiter

Explanation:

We'll begin by calculating the initial velocity at which the ball is thrown on EARTH. This can be obtained as follow:

On Earth:

Acceleration due to gravity (g) = 10 m/s²

Maximum height (h) = 10 m

Final velocity (v) = 0 m/s (at maximum height)

Initial velocity (u) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = u² – 2 × 10 × 10

0 = u² – 200

Collect like terms

0 + 200 = u²

200 = u²

Take the square root of both side

u = √200 m/s

Finally, we shall determine the maximum height of the ball at JUPITER. This can be obtained as followb

On Jupiter:

Acceleration due to gravity (g) = 26 m/s²

Initial velocity (u) = √200 m/s

Final velocity (v) = 0 m/s (at maximum height)

Maximum height (h) =..?

v² = u² – 2gh (since the ball is going against gravity)

0² = (√200)² – 2 × 26 × h

0 = 200 – 52h

Collect like terms

0 – 200 = –52h

–200 = –52h

Divide both side by –52

h = –200 / –52

h = 3.85 m

Thus, the boy can throw the ball to a height of 3.85 m on Jupiter.

PLZ HELP ME ASAP!!! 50 POINTS IF CORRECT! AND BRAINLEST

Answers

Answer:

B and C is the Answer

Follow me please

Mark brainliest

A object is placed between the focal point and the lens of a concave lens. Where will the image be formed?

Answers

Answer:

When object is placed between convex lens and focal point, image formed is virtual and magnified which is shown in the diagram. Was this answer helpful?

1.what are barriers that you have encountered in dancing?

2.how do you think you can overcome them?

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Answers

Answer:

heyy tell me ur yo u tube ch annel name I'll subscribe it and how many sub scriber u have friend

Explanation:

and are u from Ireland?

Define the unit of current. Name the device which is used to measure

electric current in a circuit.​

Answers

Answer:

The ampere, symbol A, is the SI unit of electric current. It is defined by taking the fixed numerical value of the elementary charge e to be 1.602 176 634 x 10-19 when expressed in the unit C, which is equal to A s, where the second is defined in terms of ΔνCs.

the device used to measure current in a circuit is ammeter

10 Waves Question 2 of 10 A wave travels at a speed of 74 m/s. If the distance between crests is 12 m, what is the frequency of the wave? Use j A. 0.16 Hz B. 6.2 Hz C. 890 Hz D. 62 Hz SUBMIT​

Answers

Answer: B  6.2 Hz

Explanation:  Equation for waves v = λf.

Frequency = speed / wavelength    f = v/λ

   f = 74 m/s / 12 m = 6.166... Hz

Answer:

Rounding is necessary: the answer is 6.2 Hz

Explanation:

It takes 20 Newtons to move a box. How long will it take a 25 Watt motor to move this box 5 meters?

Answers

Answer:

With F = MA Its should take 500 Newtons

Explanation:

F = MA

Some people say that you can contract HIV by sharing a drink with someone who has HIV. True or false? Why?

Answers

Answer: This is definitely false... you have to.. have séx with someone who has H.I.V to actually get H.I.V

Excluding the noble gas group, how does the number of valence electrons in an element influence its chemical stability?
A. Elements with intermediate numbers of valence electrons are the last chemically stable.
B. Elements with the highest number of valence electrons are the most chemically stable.
C. Elements with intermediate number of valence electrons are the most chemically stable.
D. Elements wit the lowest number of valence electrons are the most chemically stable.

Answers

Answer:

C. Elements with intermediate number of valence electrons are the most chemically stable.

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