A 25.0 kg mass is traveling to the right with a speed of 2.80 m/s on a smooth horizontal surface when it collides with and sticks to a second 25.0 kg mass that is initially at rest but is attached to one end of a light, horizontal spring with force constant 170.0 N/m. The other end of the spring is fixed to a wall to the right of the second mass.
1) Find the frequency of the subsequent oscillations.2) Find the amplitude of the subsequent oscillations.3) Find the period of the subsequent oscillations.4) How long does it take the system to return the first time to the position it had immediately after the collision?

Answers

Answer 1

Answer:

Explanation:

1 ) angular frequency ω = √ ( k / m )

=√ ( 170 / 50 )

= 1.844 rad /s

2πn = 1.844 where n is frequency of oscillation

n = 1.844 / (2 x 3.14 )

= .294 per sec

= .294 x 60 = 18 approx. per minute .

Velocity just after collision of composite mass ( using law of conservation of momentum )

= 25 x 2.8 / 50

v = 1.4 m/s

If new amplitude be A

1/2 k A² = 1/2 m v²

m = 25 + 25 = 50 kg

170 x A² = 50 x 1.4²

A = 0.76 m

3 ) period of oscillation = 1 /n

= 1 / .294

= 3.4 s

4 ) It will take complete one period of oscillation ie 3.4 s to come to its original position.


Related Questions

if 36C ofcharge pass through a write in 4s current is it carrying?​

Answers

Answer:

The current flowing through the wire is 9 A.

Explanation:

Given;

quantity of charge passing through the wire, Q = 36 C

duration of the charge flow, t = 4 s

The current flowing through the wire is calculated as;

Q = It

I = Q / t

where;

I is the current flowing in the wire

I = 36/4

I = 9 A

Therefore, the current flowing through the wire is 9 A.

Volcanic process refers to the eruptive and noneruptive activities that occur on a volcano. Volcanic activities usually
results if one of the following happens: A). Deep within the core of the Earth, it is so hot that some rocks melt and
become a thick and sticky substance called (16)_
Magma B) This substance gets hotter and hotter and pressure
builds deep in the (17)
of the volcano. C) Eventually, magma will push up toward the surface of the
Earth through the volcano's crater and escape through vents in the earth. D) When magma erupts from the volcano, it is
called (18)
During an eruption, volcanic asin and ouiet rock pa licies called (19)
alsu escape
violently into the air and can cause major damage to the volcano's surrounding environment. E) (20)
that erupts from the volcano will fall back down onto the Earth like powdery snow that can cover and suffocate
anlants and animals and also contaminate streams and rivers.

Answers

I need help too anyone know

1. A 2,000-turn solenoid is 65 cm long and has cross-sectional area 30 cm2. What rate of change of current will produce a 600 Volts emf in this solenoid.

Answers

Answer:

[tex]\frac{dI}{dt} = 2.59\ x\ 10^4\ A/s[/tex]

Explanation:

First, we will calculate the inductance of the solenoid by using the following formula:

[tex]L = \frac{\mu_o AN^2}{l}[/tex]

where,

L = self-inductance of solenoid = ?

μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

A = Cross-sectional area = 30 cm² = 3 x 10⁻³ m²

N  = No. of turns = 2000

l = length = 65 cm = 0.65 m

Therefore,

[tex]L = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(3\ x\ 10^{-3}\ m^2)(2000)^2}{0.65\ m}\\\\L = 0.0232\ H[/tex]

Now, we will use Faraday's law to calculate the rate of change of current:

[tex]emf = L\frac{dI}{dt}\\\\ \frac{dI}{dt} =\frac{emf}{L} \\\\ \frac{dI}{dt} =\frac{600\ V}{0.0232\ H}\\\\ \frac{dI}{dt} = 2.59\ x\ 10^4\ A/s[/tex]

You throw a tennis ball straight up. Air resistance can be neglected.
(a) The maximum height above your hand that the ball reaches is H. At what speed does the ball leave your hand?
(b) What is the speed of the ball when it is a height H/2 above your hand? Express your answer as a fraction of the speed at which it left your hand.
(c) At what height above your hand is the speed of the ball half as great as when it left your hand? Express your answer in terms of H.

Answers

Answer:

(a) [tex]\sqrt{2gH}[/tex]

(b) [tex]\sqrt{gH}[/tex]

(c) [tex]\frac{3u^{2}}{8g}[/tex]

Explanation:

The maximum height = H

(a) Let the speed of the ball as it leaves the hand is u.

Use third equation of motion

[tex]v^{2}=u^{2}+2as\\0 = u^{2}- 2 gH\\u=\sqrt{2 gH}[/tex]

(b) Let the speed of the ball at H/2 is v.

Use third equation of motion

[tex]v^{2}=u^{2}+2as\\v^{2} = u^{2}- 2 g\frac{H}{2}\\v^{2}=2 g H - gH = gH\\v =\sqrt{gH}[/tex]

(c) Let the height is h.

[tex]v^{2}=u^{2}+2as\\\frac{u^{2}}{4} = u^{2}- 2 gh \\\\2 g h = \frac{3u^{2}}{4}\\h =\frac{3u^{2}}{8g}[/tex]

. Two identical vehicles traveling at the same speed are made to collide with barriers in an insurance company collision test. The first vehicle collides with a concrete barrier, and stops in a time of approximately 0.1 s. The second vehicle collides with a collapsible barrier, and comes to rest in about 1 second. Which object is subject to a larger force

Answers

Answer:

F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

Explanation:

For this exercise let's use the relationship between momentum and momentum.

         I = F t = Δp

in this case the final velocity is zero

        F t = 0 -m v₀

        F = m v₀ / t

in order to answer the question we must assume that the two vehicles have the same mass and speed

concrete barrier

        F₁ = -p₀ / 0.1

        F₁ = - 10 p₀

barrier collapses

         F₂ = -p₀ / 1

let's look for the relationship of the forces

        F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

NEED HELP PLZ!!! ASAP

Which of the following happens during a solar eclipse?

The moon appears red.
The moon casts a shadow on Earth.
Earth, the moon, and the sun form a triangle.
Earth comes between the sun and the moon.

Ok so I'm Confused, that last answer- Shouldnt that say the moon comes between the sun and the earth? This is what it says on my test instead..

Answers

U r correct mate it's the right answer.

Hope it helps u

Plz mark me brainlest

The take-up reel of a cassette tape has a radius of 2.5 cm. Find the length of the tape that passes around the reel in 7.1 s when the reel rotates at an average angular speed of 1.9 rad/s.

Answers

Answer:

s = 0.337 m

Explanation:

First, we will find the angular displacement of the reel:

[tex]\theta = \omega t[/tex]

where,

θ = angular displacement = ?

ω = angular speed = 1.9 rad/s

t = time taken = 7.1 s

Therefore,

θ = (1.9\ rad/s)(7.1 s)

θ = 13.5 rad

Now, we will find out the length of tape:

s = rθ

where,

s = length of tape = ?

r = radius of reel = 2.5 cm = 0.025 m

Therefore,

s = (0.025 m)(13.5 rad)

s = 0.337 m

Draw Aufbua diagram of sodium ion​

Answers

Answer:

Aufbau diagram of sodium ion:

2s²,2p⁶,3s¹

If a team of workers comes to a consensus, what probably happened in the meeting?
A. They compromised with each other to reach an agreement.
B. They disagreed and were unable to come to a decision.
OC. They were forced by their manager to follow a new policy.
O D. They all turned in their letters of resignation.

Answers

Answer:

A

Explanation:

A consensus is when you come to an agreement

What type of boundary creates earthquakes? What type of boundaries create volcanoes? Compare and contrast these two types of plate movements, and explain how these geologic events occur.

Answers

Answer:

The three types of plate boundaries are Convergent, Divergent and Transform.

The convergent plate boundary is when two plates move towards each other. In this case it has three possibilities:

An oceanic-continental convergent: In this case the the oceanic plate goes beneath the continental in a subduction zone. And due to this process, the continental crust crumples and forms mountains.

An oceanic-oceanic convergent: Here the denser plate goes beneath the other in a subduction zone.

A continental-continental convergent: And in this case the thickness of the crust doubles as the convergent makes mountains.

The divergent plate boundary is when two plates move away from each other. This type of plate boundaries happens between the same plate type, this way it has two possibilities:

An oceanic-oceanic divergent: In this case when two plates goes apart, the magma from the mantle goes up to fill the gap that the separation made.

A continental-continental divergent: And here it’s characterized by rift valleys.

The third and last type is the transform plate boundary. And this one happens when two plates slide along each other horizontally.

this is the correct answer

please mark brainliest

A Ring, a solid Cylinder and a solid sphere all having the same mass and the Same radius are held at the top of an inclined plane if the objects are roll without slipping and the (see the picture)between each object and the plane is 0.3 if they are released from an incloed plane at the same time which wal bee reach the bottom first?​

Answers

Answer:

Since they all have the same mass and radius they all experience the same amount of torque.

Torque = moment of inertia * angular acceleration

The one with the smallest moment of inertia will experience the greatest angular acceleration and thus reach the bottom first.

I = M r^2     ring

I = 1/2 M r^2  cylinder

I = 2/5 M r^2   sphere

The sphere will reach the bottom first.

how are force and motion related

Answers

Force is used to put things in motion you can’t have motion without force!
Even if it just pushing a piece of paper you still use force to put the paper in motion!

a 60 kg pupil runs for 600m in 1 minute uniformly calculate kinetic energy​

Answers

velocity = traveled distance ÷ time of the traveled distance is seconds

velocity = 600 ÷ 60

velocity = 10 m/s

_________________________________

Kinetic Energy = 1/2 × mass × ( velocity )^2

KE = 1/2 × 60 × ( 10 )^2

KE = 30 × 100

KE = 3000 j

g You shine orange laser light that has a wavelength of 600 nm through a narrow slit. The slit forms a diffraction pattern on a distant screen that has been set up behind the slit. The first dark fringe in the diffraction pattern is 4.0 cm from the center point of the pattern. If you replace the orange laser with an unknown laser and observe that the second dark fringe of the diffraction pattern appear at 4.0 cm from the center point, what is the wavelength of the unknown laser

Answers

Answer:

 λ = 3 10⁻⁷ m,   UV laser

Explanation:

The diffraction phenomenon is described by the expression

         a sin θ = m λ

let's use trigonometry

         tan θ = y / L

as in this phenomenon the angles are small

        tan θ = [tex]\frac{sin \ \theta}{cos \ \theta}[/tex] = sin θ

        sin θ = y / L

we substitute

      a y / L = m  λ

let's apply this equation to the initial data

       a  0.04 / L = 1 600 10⁻⁹

       a / L = 1.5 10⁻⁵

now they tell us that we change the laser and we have y = 0.04 m for m = 2

      a 0.04 / L = 2  λ

       a / L = 50  λ

we solve the two expression is

         1.5 10⁻⁵ = 50  λ

          λ = 1.5 10⁻⁵ / 50

          λ = 3 10⁻⁷ m

    UV laser

How do you make a mirages?​

Answers

Answer: when the ground is very hot and the air is cool. The hot ground warms a layer of air just above the ground. When the light moves through the cold air and into the layer of hot air it is refracted (bent). A layer of very warm air near the ground refracts the light from the sky nearly into a U-shaped bend.

Explanation:

Just a thought
If you had let’s say two pieces of glass one being much more rudder than the other, and you try to break the tougher glass with the other piece
Example: throwing a glass ball at a glass door

Question: is it possible to break a tougher piece of glass with a weaker piece of glass ?

Suspicion: I’m guessing at high speeds it’s possible but I’m not sure anyone care to put their input ?

Answers

Answer:

Explanation:

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A truck with a mass of 1520 kg and moving with a speed of 16.0 m/s rear-ends a 663 kg car stopped at an intersection. The collision is approximately elastic since the car is in neutral, the brakes are off, the metal bumpers line up well and do not get damaged. Find the speed of both vehicles after the collision in meters per second. vcar

Answers

Answer:

Speed of truck after collision = 6.28 m/s

Speed of car after collision = 22.28 m/s

Explanation:

By law of conservation of momentum  

momentum before collision = momentum after collision

[tex]m_1u_1+m_2u_2 = m_1v_1+m_2v_2\\plugging/values\\1520\times16+ 0= 1520\times v_1 + 663\times v_2\\24320= 1520v_1+663v_2[/tex]

Since, collision is elastic

[tex]16 = v_2-v_1///v_2 = v_1+16 ....(b)[/tex]

solving the above two equations we get

v_1 = 6.28 m/s and v_2 = 22.28 m/s

Speed of truck after collision = 6.28 m/s

Speed of car after collision = 22.28 m/s

what makes molecules move. A. covection. B. Radiation. C. Thermal or heat. D. conduction.​

Answers

Radiation or Conduction?

Answer:

the answer is C

Explanation:

Bob uses a wheelbarrow to move soil from his garden to a new flowerbed. He exerts an average force of 185 N while pushing the wheelbarrow, and he does 6.1 kJ of work while moving each load of soil. How far is he moving the soil?


A. 0.026 m

B. 0.039 m

C. 26 m

B. 39 m

Answers

Answer:

A. reduce the amount of soil by one-half and apply the same amount of force

Explanation:

A pair of slits, separated by 0.150 mm, are illuminated by light with a wavelength of 643 nm. An interference pattern is observed on a screen at 140 cm from the slits. Consider a point seen on the screen that is located 1.80 cm to the right of the central bright fringe. Will the point be a minimum (destructive) point, a maximum (constructive) point or somewhere in between

Answers

Answer:

Explanation:

slit separation d = .15 mm

screen distance D = 1.4 m

wavelength of light used λ= 643 x 10⁻⁹ m

position of n th bright fringe x

x = n x λ D / d

1.8 x 10⁻² = n x 643 x 10⁻⁹ x 1.4 / .15 x 10⁻³

1.8 x 10⁻² = n x 6 x 10⁻³

n = 3

So 3 rd bright fringe will be formed at a point 1.8 cm from the central bright fringe .

A vehicle reaches a speed of 7.5 m/s over 15 seconds. What is its acceleration if it
starts from rest?
a. -0.5 m/s2
b. 0.5 m/s?
c. 2 m/s?
d. 22.5 m/s2

Answers

[tex]acceleration = \frac{velocity}{time} = \frac{7.5}{15} = 0.5ms^-^2[/tex]

So the answer is option b.

8 A car accelerates at a rate of 10m/s
for a time of 4s and it reaches a speed of 52m/s . calculate the initial value

Answers

Answer:

From the First Law of Motion

Vf = Vi + at

"It reaches a speed of 52m/s" meaning the Final speed Vf=52

a(acceleration)=10m/s²

t=4s

Applying the formula

52=Vi + 10(4)

Vi = 52-40

Vi = 12m/s

A 4.50-kg centrifuge takes 200 s to spin up from rest to its final angular speed with constant angular acceleration. A point P located 10.0 cm from the axis of rotation of the centrifuge moves with a speed of 150 m/s when the centrifuge is at full(final) speed. a) [4 points] What was its final angular speed

Answers

Answer:

Explanation:

ω = v / R

where ω is angular speed of a point situated at distance R from axis and having a linear speed of v .

Given v = 150 m/s ; R =.10 m

ω = 150 / .10

= 1500 radian /s .

Final angular speed is 1500 radian /s .

How many significant figures are in the number 54,100?

Answers

Answer:

3

Explanation:

The answer must be 3

सत्मार्ग र शान्तिले नै समाजलाई सभ्य बनाउँछ भन्ने विषयमा ५० शब्दसम्मको एउटा अनुच्छेद
लेख्नुहोस्।​

Answers

Answer:

So you have a question

Explanation:

either way have a nice day

1. A ford engine is provided with 80,000 W power by burning its fuel. The engine produces a kinetic energy of 96 kJ for 20 seconds before its cut out.
a. Calculate the output power by the engine in watts.
b. What is the efficiency of the engine?
c. Why is there a considerable difference in the power input and output?

Answers

Answer: a) 4800 W  b) 6 %  c) most of the energy of fuel is converted to heat in combustion engine

Explanation: a) Power P = W/t = 96 000 J / 20 s = 4800 W

b) efficiency η = P(putput) / P(intake) = 4800 W / 80000 W = 0,06

“Is it true or wrong to say that an automobile at rest can be accelerating very fast? Either yes or no explain it with mathematical background

Answers

Answer:

Yes.

a = dv/dt

but v might be zero in an instant.

Take the example of a pendulum.

Acceleration is defined as the rate of change of the velocity of the body. Yes, an automobile at rest can accelerate very fast.

What is acceleration?

Acceleration is defined as the rate of change of the velocity of the body. Its unit is m/sec².It is a vector quantity. It requires both magnitudes as well as direction to define.

[tex]\rm a=\frac{dv}{dt}[/tex]

a is the acceleration of the body

dv is the change of velocity of the body

dt is the change in the time interval

The acceleration is defined as the change in velocity, and the slope of velocity is found as acceleration. It can be said that the body is at rest its velocity is zero.

The acceleration of the body can be increased when the body changes its direction. So the moment at which the body changes the direction the body is at rest after that the body can accelerate.

To learn more about acceleration refer to the link;

https://brainly.com/question/969842

problema de coeficiente de rozamiento

Answers

If you take the positive horizontal direction to be to the right (the same direction as F₂), then by Newton's second law, the block has

• a net horizontal force of

F = F₁ cos(-50°) + F₂ - f = m a

• a net vertical force of

F = F₁ sin(-50°) + n - m g = 0

where

f = µ n = magnitude of friction

• µ = coefficient of kinetic friction

• n = magnitude of the normal force

• m = 20 kg

• a = acceleration of the block

Solve for n :

n = m g + F₁ sin(50°)

n = (20 kg) (9.80 m/s²) + (50 N) sin(50°)

n ≈ 234.302 N

If the block accelerates uniformly from rest with acceleration a, then this acceleration is equal to its average, given by

a = ∆v / ∆t = (9 m/s - 0) / (3 s) = 3 m/s²

Solve for f :

f = F₁ cos(50°) + F₂ - m a

f = (50 N) cos(50°) + 80 N - (20 kg) (3 m/s²)

f ≈ 52.1394 N

Solve for µ :

µ = f / n

µ ≈ (52.1394 N) / (234.302 N)

µ ≈ 0.22253 ≈ 0.22

A ball has a mass of 0.046kg. Calculate the change in gravitational potential energy when the ball is lifted through a vertical height of 2.05 m.


The mass of a ball is 0.046kg. The ball is released. Calculate the kinetic energy of the ball when the speed of the ball is 3.5 m/s

Answers

Answer:

PE=0.92414J and KE=0.28175J

Explanation:

Gravitational potential energy=mass*gravity*height

PE=mgh

Data,

M=0.046kg

H=2.05m

g=9.8m/s^2

PE=0.046kg * 9.8m/s^2 * 2.05m

PE =0.92414J

KE=1/2mv^2

M=0.046kg

V=3.5m/s

KE=[(0.046kg)*(3.5m/s)^2]\2

KE=0.28175J

Cora’s doctor suspects that she has acid reflux. He prescribes
for her.

Answers

Answer: antacids

Explanation: Excess acid secretion in the stomach often causes nausea, chest pain, and leaves a bitter taste in the mouth. Doctors perscribe antacids to neutralize the acid.

Answer: antacids


Explanation: Excess acid secretion in the stomach often causes nausea, chest pain, and leaves a bitter taste in the mouth. Doctors perscribe antacids to neutralize the acid.

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