A car and driver weighing 5060N passes a sign stating "Bridge out 27.5 meters ahead." She slams on the brakes and the car decelerates at a constant rate of 14 m/s^2. The acceleration of gravity is 9.8 m/s^2. What is the magnitude of the work done stopping the car if the car just stops in time to avoid diving into the water?
Answer in units of J.

Answer:

9.70 kilograms

Explanation:

I got a 100% on my test

The mass of the object is 9.7 kg. Option (A) is correct.

Every day, we experience the normal force. For instance, when a book is placed on a table, the usual response force prevents the book from falling through the table, even though gravity is pulling the book downward. That implies that there is a force acting to push it upward. The word "normal force" refers to the force. Normal in this context refers to being perpendicular to the ground.

Given parameters:

the normal force acting on the object is: N =  95.0 newtons.

coefficient of static friction: μ = 0.110.

We have to find mass of the object: m = ?

We know that:

Normal force = weight of the object

⇒ N = mg

⇒ m = N/g = 95.0/9.8 kg = 9.7 kg

Hence, the mass of the object be 9.7 kg.

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Answer:

I believe its forward or south :D

Explanation:

If Dominic has a brain injury, then he must have sustained a serious injury.

The brain coordinates all the activities in the body such as speech, locomotion, coordination and intelligence. This makes the brain the master point of control in the body.

Whenever there is an injury to the brain, various parts of the body could be affected. Functions such as speech, locomotion and general coordination may become largely impaired.

Therefore, if Dominic has a brain injury, then he must have sustained a serious injury.

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Answer:

Satellites don't fall from the sky because they are orbiting Earth. Even when satellites are thousands of miles away, Earth's gravity still tugs on them. Gravity--combined with the satellite's momentum from its launch into space--cause the satellite go into orbit above Earth, instead of falling back down to the groundv

Explanation:

Answer:

The centripetal acceleration of a point on the outer tip of a blade is 1.097 m/s²

Explanation:

Given;

length of the fan blade, r = 0.25 m

angular speed = 20 rpm

The angular speed in rad/s is given as;

[tex]\omega = \frac{20 \ rev}{ \ \ \min} \ \times \ \frac{2\pi}{1 \ rev} \ \times \ \frac{1 \ \min}{60s} = 2.095 \ rad/s \\\\[/tex]

The centripetal acceleration of a point on the outer tip of a blade is given as;

[tex]\alpha_c = \frac{v^2}{r} = \omega ^2r[/tex]

[tex]\alpha _c = (2.095)^2(0.25)\\\\\alpha _c =1.097 \ m/s^2[/tex]

Therefore, the centripetal acceleration of a point on the outer tip of a blade is 1.097 m/s²

Answer:

Explanation:

Given

[tex]rpm = 20[/tex]

therefore,

[tex]20rpm = \frac{20*2\pi}{60}\\\\=2.1 rad/s = w[/tex]

From,

[tex]V = rw\\\\V = 0.25 * 2.1\\\\V = 0.525m/s[/tex]

Centripetal acceleration,

[tex]a_c = \frac{V^2}{r}\\\\a_c = \frac{0.525^2}{0.25}\\\\a_c = 1.1m/s^2[/tex]

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