A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 33.1 ◦C . In an attempt to cool the liquid, which has a mass of 185 g , 90.3 g of ice at 0.0 ◦C is added. At the time at which the temperature of the tea is 26.3 ◦C , find the mass of the remaining ice in the jar. The specific heat of water is 4186 J/kg · ◦ C . Assume the specific heat capacity of the tea to be that of pure liquid water. Answer in units of g.(2 significant digits pls)​

Answers

Answer 1

Answer:

74.54g

Explanation:

First, let’s calculate the heat lost by the tea when it cools down from 33.1°C to 26.3°C. We can use the formula Q = mcΔT, where Q is the heat lost, m is the mass of the tea, c is the specific heat capacity of water, and ΔT is the change in temperature.

In the context of the problem,

m represents the mass of the tea, which is given as 185g.c represents the specific heat capacity of water, which is given as 4186 J/kg·°C.ΔT represents the change in temperature, which is (33.1 - 26.3)°C = 6.8°C.

So, the heat lost by the tea is: Q = (185g) * (4186 J/kg·°C) * (6.8°C) = 5345.68 J

This heat is gained by the ice, causing it to melt and warm up to 0°C. The heat required to melt ice is given by Q = mL, where m is the mass of ice melted and L is the latent heat of fusion of water.

The latent heat of fusion of water is 334 kJ/kg. So, we can calculate the mass of ice melted as: m = Q / L = (5345.68 J) / (334 kJ/kg) = 0.016 kg or 16g

However, not all of the ice will melt. Some of it will remain as ice and some will become water at 0°C.

Let’s say that x grams of ice melts completely and becomes water at 0°C. The remaining (90.3 - x) grams of ice will stay as ice.

The heat required to melt x grams of ice is: Q1 = x * L

The heat required to warm up x grams of water from 0°C to 26.3°C is: Q2 = x * c * (26.3 - 0)

The total heat gained by the ice and water is: Q = Q1 + Q2

Substituting the values we get: 5345.68 J = x * L + x * c * (26.3 - 0)

Solving for x, we get: x = (5345.68 J) / (L + c * (26.3 - 0)) ≈ 15.76g

Therefore, out of the initial 90.3g of ice, only approximately 15.76g melts completely and becomes water at 0°C.

The remaining mass of ice in the jar is: (90.3 - 15.76)g ≈ 74.54g.


Related Questions

How long does it take for radiation from a cesuim-133 atom to complete 1.5 million cycles

Answers

A cesium-133 atom's radiation goes through 1.5 million cycles in around 0.1633 microseconds (or 163.3 nanoseconds).

What frequency does one kind of radiation that cesium-133 emits have?

9,192,631,770 hertz (cycles per second) is the frequency of the microwave spectral line that the isotope cesium-133 emits. The basic unit of time is provided by this. Cesium clocks have an accuracy and stability of 1 second in 1.4 million years.

The radiation emitted by cesium-133 has a frequency of 9,192,631,770 cycles per second, or 9.192631770 109 Hz.

The following formula may be used to determine how long 1.5 million radiation cycles take to complete:

Time is equal to the frequency of cycles.

Plugging in the numbers, we get:

time = 1.5 million / 9.192631770 × 10^9 Hz

time = 1.632995101 × 10^-7 seconds

So it takes approximately 0.1633 microseconds (or 163.3 nanoseconds) for radiation from a cesium-133 atom to complete 1.5 million cycles.

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What is the real reason the skies blue

Answers

Answer:

Rayleigh scattering

Explanation:

The blue color of the sky is due to a phenomenon called Rayleigh scattering. When sunlight enters the Earth's atmosphere, the shorter blue wavelengths of light are scattered more than the other colors by the tiny molecules of nitrogen and oxygen in the air. This causes the blue light to be redirected in many different directions, making the sky appear blue to our eyes. The other colors of light are scattered as well, but to a lesser extent, which is why the sky appears blue instead of a mixture of all colors. This effect is also the reason why the sun appears more yellow, orange or red during sunrise or sunset, when its light has to travel through more of the Earth's atmosphere before reaching our eyes, causing the shorter blue wavelengths to be scattered even more, leaving behind the longer wavelengths of light.

A 2,900-kg truck runs into the rear of a 1,000-kg car that was stationary. The truck and car are locked together after the collision and move with speed 8 m/s. Compute how much kinetic energy was "lost" in this inelastic collision.

Answers

A 1,000-kg automobile that was stopped Collision with a 9,100-kg truck's back. Following the incident, the truck the car are stuck together and moving at a speed of 8 m/s.

How improbable is a collision on reality?

In the real world, energy changes almost always occur, making this highly implausible. In the actual world, collisions typically take this form. Flying balls or a spaceship passing close to a planet without being impacted by its gravity are two examples of this.

What distinguishes a collision from an impact?

Impact can refer to a collision between two objects, at least half of which is being pushed in the direction of the other. Collision refers to the coming contact of more than one thing with enough force that either all of them sustain damage or that their movement is significantly slowed.

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A ball thrown straight upward returns to its original level in 2.75 seconds. A second ball is thrown at an angle of 40 degrees above the horizontal. What is the initial speed ball if it also returns to its original level in 2.75 seconds?

Answers

The initial speed (magnitude of velocity) of the second ball thrown at an angle of 40 degrees above the horizontal is approximately 12.93 m/s.

What is the initial speed ball?

Let's consider the motion of the second ball thrown at an angle of 40 degrees above the horizontal. We can break down its motion into horizontal and vertical components.

Given:

Time taken for the ball to return to its original level (time of flight): t = 2.75 seconds

Angle of projection (above the horizontal): θ = 40 degrees

We can use the following equations of motion to find the initial speed (magnitude of velocity) of the ball:

Horizontal motion:

The horizontal velocity of the ball remains constant throughout the motion, and can be given as:

vx = v0 * cos(θ), where v0 is the initial speed.

Vertical motion:

The vertical velocity of the ball changes due to the force of gravity. We can use the following equation:

vy = v0 * sin(θ) - g * t,

where;

g is the acceleration due to gravity

Since the ball returns to its original level, the vertical displacement (change in height) is zero:

Δy = 0

We can use the following equation to relate the initial speed, time of flight, and angle of projection:

Δy = v0 * sin(θ) * t - (1/2) * g * t^2 = 0

Plugging in the values and solving for v0:

0 = v0 * sin(40) * 2.75 - (1/2) * 9.8 * (2.75)^2

v0 * sin(40) * 2.75 = (1/2) * 9.8 * (2.75)^2

v0 = (1/2) * 9.8 * (2.75)^2 / (sin(40) * 2.75)

v0 = 12.93 m/s (rounded to two decimal places)

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Cary calculated the surface area of a box in the shape of a rectangular prism. She wrote the equation 148 = 2 (6w + 6h + hw) to represent the width and height of the box. She solved for w and got w = StartFraction 74 minus 6 h Over h + 6 EndFraction Which of the following is an equivalent equation?
w = StartFraction 148 minus 6 h Over 12 + h EndFraction
w = StartFraction 148 minus 12 h Over 12 + 2 h EndFraction
w = 136 minus 14 h
w = 136 minus 10 h

Answers

The correct equivalent equation from the options provided is:

w = (24.67 - h) / (h + 6)

What is Equivalent Equation?

An equivalent equation is an equation that has the same solution or solutions as the original equation. In other words, if two equations produce the same values for the variables, they are considered equivalent equations.

The equivalent equation for w, based on the given equation and solving for w, is:

w = (148 - 6h) / (h + 6)

To simplify this equation, we can factor out 6 from the numerator:

w = 6(24.67 - h) / (h + 6)

Now we can further simplify by dividing both numerator and denominator by 6:

w = (24.67 - h) / (h + 6)

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A 27 g block of ice is cooled to −65 ◦C. It is added to 525 g of water in an 80 g copper calorimeter at a temperature of 25◦C. Find the final temperature. The specific
heat of copper is 387 J/kg ◦C and of ice is 2090 J/kg ◦C . The latent heat of fusion of
water is 3.33 × 105 J/kg and its specific heat is 4186 J/kg ◦C . Answer in units of ◦C.

Answers

The final temperature after adding the ice to the water and calorimeter will be approximately 8.37 ◦C.

What is Temperature?

Temperature is a measure of the average kinetic energy of the particles in a substance or system. It is a scalar quantity that indicates how hot or cold an object or medium is. Temperature is commonly measured using various scales, such as Celsius (°C), Fahrenheit (°F), and Kelvin (K), which represent different reference points and units of measurement.

Since energy is conserved, we can set Q_ice equal to Q_water+calorimeter:

m_ice * c_ice * ΔT_ice = (m_water + m_calorimeter) * c_water+calorimeter * ΔT_water+calorimeter

27 g * 2090 J/kg ◦C * (T_f + 65) = (525 g + 80 g) * (4186 J/kg ◦C + 387 J/kg ◦C) * (T_f - 25)

Simplifying and solving for T_f:

27 * 2090 * (T_f + 65) = 605 * (T_f - 25)

56130 T_f + 361350 = 605 T_f - 15125

56130 T_f - 605 T_f = -15125 - 361350

-44,970 T_f = -376475

T_f = (-376475) / (-44,970)

T_f ≈ 8.37 ◦C

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A pipe of constant radius carried water at 3.25 m/s. Please answer in PA.

Answers

Pipe of constant radius, we can use Bernoulli's equation, which relates the pressure, velocity, and height of a fluid at two points in a flow system.the pressure of water in the pipe is approximately 105,142 Pa.

What is a system?

System refers to a collection of related components or parts that work together to achieve a specific goal or purpose. The concept of a system can be applied to a wide range of fields and disciplines, including science, engineering, economics, and social sciences.

In science, a system is often defined as a portion of the universe that is being studied or analyzed. This can include anything from a single atom or molecule to an entire ecosystem or planet. By defining the boundaries of a system, scientists can focus their attention on understanding the interactions and relationships between the various components within that system.

In engineering, a system refers to a collection of components that are designed to work together to perform a specific function or task. This can include everything from simple mechanical systems like gears and pulleys to complex electrical or computer systems.

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explain HOW heat conduction works if you pour a hot cup of hot chocolate into a cold cup. What happens to the cup and HOW does it happen?

Answers

With time, the hot chocolate's thermal energy will permeate into the atmosphere, causing the cup to chill.

How does the heat energy from a cup of hot chocolate get to you?

Conduction, which transfers heat through direct touch, transports heat from the hot chocolate to the mug. As the molecules of the hot chocolate clash with those of the mug, energy is transferred to both of them as well as to the surrounding air.

How is the spoon made heated by the heat from a cup of hot chocolate?

Conduction into the metal spoon will speed up the transfer of heat from the cocoa. The heat will be dispersed throughout the spoon's body because it is a thermal conductor.

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30 POINTS!!!! NO CHATGPT OR ANY BOTS_


As you sit in a fishing boat, you notice that 12 waves pass the boat every 45 s
. If the distance from one crest to the next is 9.0 m
, what is the speed of these waves?
Express your answer to two significant figures and include the appropriate units.

Answers

The speed of the waves can be expressed to two significant figures as 0.2 m/s. The unit for this expression is meters per second (m/s).

What is wave crest?

A wave crest is the highest point of a wave. It is the top of the wave, where the wave is moving most up and away from the equilibrium position. It is the point of highest amplitude (height) of the wave and is followed by a wave trough, which is the lowest point of the wave.

The speed of the waves can be calculated using the formula speed = distance over time.

We know the distance between wave crests is 9.0 m and the time it takes for 12 waves to pass the boat is 45 s. Therefore, the speed of the waves can be calculated as:

Speed = 9.0 m / 45 s

Speed = 0.2 m/s

The speed of the waves can be expressed to two significant figures as 0.2 m/s. The unit for this expression is meters per second (m/s).

This calculation shows that the speed of the waves passing the boat is 0.2 m/s. This speed can be further broken down into how many meters the waves travel in one second if necessary.

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HELP ILL MARK BRIANLIEST

identify the independent variable
identify the dependent variable
Which statement best describes the relationship between the data (IV & DV)
Which statement best describes the relationship between the change in temperature data and the kinetic energy ?

Answers

1. The independent variable is the initial temperature of the water.

2. The dependent variable is the amount of ice in grams that melts.

3. The statement that best describes the relationship between the data (Independent Variable & Dependent Variable) is that as the initial temperature of the water increases, the amount of ice required to reach the final temperature generally decreases.

4.  As the change in temperature increases (meaning a larger difference between the initial and final temperatures), the kinetic energy transfer from the water to the ice also increases. This is because the greater the temperature difference, the more energy is required to be transferred for the system to reach an equilibrium.

How do you identify the independent and dependent variables?

You find the independent variable by looking at the factors being manipulated or changed during the experiment. In this case, the initial temperature of the water is the independent variable because it's the one being altered in each trial.

The other variables, such as the final temperature and the amount of ice, are affected by the changes in the initial temperature. As a general rule, the independent variable is the one that is deliberately changed to observe its effect on other variables (dependent variables) in the experiment

The above answer is based on the variables provided below as seen in the picture;

             

                                            Temperature of water

                                                 170ml of water

Trials      initial temperature   Final temperature    Amount of ice in grams

1.                   18°C                              12.3 °C                    60.1g

2.                 50.4 °C                          46.6 °C                    57.4g

3.                  5.0 °C                              0 °C                        70.8g

4.                 15.1 °C                             4.3 °C                      135g

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Can anyone please help me

Answers

To solve this problem, we can use Coulomb's law, which states that the electric force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.

We can then use the electric force to find the electric field at the location of q3 and the initial acceleration of q3.

a) To find the electric field at the location of q3, we can first find the electric force on q3 due to q1 and q2 and then use the definition of the electric field, which is the electric force per unit charge. The electric force on q³ due to q¹ and q² is:

F1 = k x q¹ x q³/ r1²

F2 = k x q² x q³ / r2²

where r¹ and r² are the distances from q¹ and q² to q³, respectively, and k is Coulomb's constant.

Since q³ is equidistant from q¹ and q², we have r¹ = r² = 0.20 m. Substituting the given values, we get:

F1 = (9.0 x 10⁹ N-m²/C²) x (4.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = 1.8 N

F2 = (9.0 x 10⁹ N-m⁻²/C²) x (-6.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = -5.4 N

The negative sign of F2 indicates that the force on q³ due to q² is in the opposite direction to the force due to q¹.

The net electric force on q3 is the vector sum of the forces due to q1 and q2:

Fnet = F1 + F2 = 1.8 N - 5.4 N = -3.6 N

The electric field at the location of q³ is then:

E = Fnet / q³ = (-3.6 N) / (2.0 x 10⁻⁶ C) = -1.8 x 10⁻⁶N/C

The negative sign of the electric field indicates that the field is directed towards q².

b) To find the initial acceleration of q³, we can use Newton's second law, which states that the net force on an object is equal to its mass times its acceleration:

Fnet = ma

where m is the mass of q³ and a is its initial acceleration.

Substituting the given values, we get:

-3.6 N = (2.0 x 10⁻⁶ kg) x a

Solving for a, we get:

a = -1.8 x 10³ m/s²

The negative sign of the acceleration indicates that it is directed towards q².

c) The direction of the initial acceleration of q³ is towards q².

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A .35 kg block at -27.5 ºC is added to .217 kg of water at 25.0 ºC. They come to equilibrium at 16.4 ºC. What is the specific heat of the block?

Answers

Answer:

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To solve this problem, we can use the formula for heat transfer:

q = mcΔT

where q is the heat transferred, m is the mass of the object, c is its specific heat capacity, and ΔT is the change in temperature.

We know that the mass of the block is 0.35 kg and that its initial temperature is -27.5 ºC. We also know that the mass of water is 0.217 kg and that its initial temperature is 25.0 ºC.

When they come to equilibrium at 16.4 ºC, we can calculate how much heat was transferred from the water to the block:

q = mcΔT q = (0.217 kg)(4186 J/kg ºC)(25.0 ºC - 16.4 ºC) q = 1825 J

This amount of heat was transferred from the water to the block, so we can set it equal to the amount of heat absorbed by the block:

q = mcΔT 1825 J = (0.35 kg)c(16.4 ºC - (-27.5 ºC)) 1825 J = (0.35 kg)c(43.9 ºC) c = 148 J/kg ºC

Therefore, the specific heat capacity of the block is 148 J/kg ºC.

Explanation:

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A 25 kg child plays on a swing having support ropes that are 2.20 m long. A friend pulls her back until the ropes are ăÿÿfrom the vertical and releases her from rest. (a) What is the potential energy for the child just as she is released compared with the potential energy at the bottom of the swing? (b) How fast will she be moving at the bottom of the swing? (c) How much work does the tension in the ropes do as the child swings from the initial position to the bottom?

Answers

Answer:

A) P.E = 138.44 J

B) The velocity of swing at bottom, v = 3.33 m/s

C) The work done, W = -138.44 J

Explanation:

Given,

The mass of the child, m = 25 Kg

The length of the swing rope, L = 2.2 m

The angle of the swing to the vertical position, ∅ = 42°

A) The potential energy at the initial position ∅ = 42° is given by the relation

                               P.E = mgh joule

Considering h  = 0 for the vertical position

The h at ∅ = 42° is  h = L (1 - cos∅)

                              P.E = mgL (1 - cos∅)

Substituting the given values in the above equation

                              P.E = 25 x 9.8 x 2.2 (1 - cos42°)

                                     = 138.44 J

The potential energy for the child just as she is released, compared to the potential energy at the bottom of the swing is, P.E = 138.44 J

B) The velocity of the swing at the bottom.

At bottom of the swing the P.E is completely transformed into the K.E

                 ∴                 K.E = P.E

                                    1/2 mv² = 138.44

                                    1/2 x 25 x v² 138.44

                                           v² = 11.0752

                                            v = 3.33 m/s

The velocity of the swing at the bottom is, v = 3.33 m/s

C) The work done by the tension in the rope from initial position to the bottom

            Tension on string, T = Force acting on the swing, F

                     

                           

                           =

                           = - 2.2 x 25 x 9.8 [cos0 - cos 42°]

                           = - 138.44 J

The negative sign in the in energy is that the work done is towards the gravitational force of attraction.

The work done by the tension in the ropes as the child swings from the initial position to the bottom of the swing, W = - 138.44 J

We can use conservation of energy to solve this problem. At the initial position, the child has no kinetic energy and all her energy is potential energy due to her height above the lowest point of the swing. At the bottom of the swing, the child has no potential energy and all her energy is kinetic energy due to her speed.

(a) The potential energy of the child just as she is released can be calculated as:
PE = mgh
where m is the mass of the child, g is the acceleration due to gravity, and h is the height of the child above the lowest point of the swing. At the initial position, h = 2.20 m, so the potential energy is:
PE_initial = mgh = (25 kg)(9.81 m/s^2)(2.20 m) = 544 J

At the bottom of the swing, h = 0, so the potential energy is zero:
PE_bottom = 0 J

The potential energy at the initial position is greater than the potential energy at the bottom of the swing, since the child loses potential energy as she swings down.

(b) We can use conservation of energy to find the speed of the child at the bottom of the swing. At the initial position, all the energy is potential energy. At the bottom of the swing, all the energy is kinetic energy. Therefore, the potential energy at the initial position is equal to the kinetic energy at the bottom of the swing:
PE_initial = KE_bottom
mgh = (1/2)mv^2
where v is the speed of the child at the bottom of the swing. Solving for v, we get:
v = sqrt(2gh)
where sqrt means square root. Substituting the values, we get:
v = sqrt(2(9.81 m/s^2)(2.20 m)) = 6.26 m/s

Therefore, the child will be moving at a speed of 6.26 m/s at the bottom of the swing.

(c) The work done by the tension in the ropes as the child swings from the initial position to the bottom can be found as the change in the total mechanical energy of the child:
W = ΔE = KE_bottom - PE_initial
Substituting the values, we get:
W = (1/2)mv^2 - mgh
W = (1/2)(25 kg)(6.26 m/s)^2 - (25 kg)(9.81 m/s^2)(2

A rock climber stands on top of a 59 m -high cliff overhanging a pool of water. He throws two stones vertically downward 1.0 s apart and observes that they cause a single splash. The initial speed of the first stone was 1.7 m/s . Include value and units.
a) How long after the release of the first stone does the second stone hit the water?
b) What was the initial speed of the second stone?
c) What is the speed of the first stone as it hits the water?
d) What is the speed of the second stone as it hits the water?

Answers

a) The time after the release of the first stone that the second stone hits the water is 2.0 s.

b) 15.7 m/s is the initial speed of the second stone.

c)  The speed of the first stone as it hits the water is 15.7 m/s.

d) The speed of the second stone as it hits the water is 28.2 m/s.

What is velocity?

Velocity is a vector quantity that measures both the speed and direction of an object's motion. It is equal to the rate of change of an object's position with respect to time. Velocity is usually represented by the symbol v and is measured in meters per second (m/s).

a) The time between first and second stone's release is 1.0 s. Since the time of release of first stone and the time of splash of both stones are same, the time between the release of second stone and the splash of both stones is 1.0 s.

Thus, the time after the release of the first stone that the second stone hits the water is 2.0 s.

b) The initial speed of the second stone can be calculated using the equation of motion,

v² = u² + 2as

where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (9.8 m/s²), and s is the displacement.

Substituting the values,

v² = (1.7)² + 2(9.8) * 59

v = 15.7 m/s

c) The speed of the first stone as it hits the water can be calculated using the equation of motion,

v² = u² + 2as

where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (9.8 m/s²), and s is the displacement.

Substituting the values,

v² = (1.7)² + 2(9.8) * 59

v = 15.7 m/s

d) The speed of the second stone as it hits the water can be calculated using the equation of motion,

v² = u² + 2as

where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (9.8 m/s²), and s is the displacement.

Substituting the values,

v² = (15.7)² + 2(9.8) * 59

v = 28.2 m/s

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Unit 2 Test Study Guide (Electricity and Magnetism)
1. How does distance affect gravitational force between 2 objects?
2. How does mass affect gravitational force between 2 objects?
3. Draw a bar magnet with the magnetic field lines and be able to identify a diagram of this.
4. What are the parts of an electromagnet?
5. What is a solenoid?
6. What are 2 ways to strengthen an electromagnet?
7. What happens to the magnetic force in an electromagnet if the electricity is turned off?
8. How could you test the strength of an electromagnet?
9. Besides the amount of mass an electromagnet produces, what else could you use to measure the strength? (Think about the 2 factors affecting magnetic force between objects).
10. What is electromagnetic induction?
11. Moving a permanent magnet through a coil of wire attached to a circuit produces what?
12. What do ammeters and galvanometers do?
13. What mechanism do they use for this?
14. What is the role/purpose of the generator in a hydroelectric power plant (or any power plant)?
15. What are the energy conversions in an electric generator?
16. What happens when electric current
flows into a simple electric motor?
17. What are the energy conversions in an electric motor?
18. Would an electromagnet or an electric motor include a spinning magnet?
19. What energy source produces light in a flashlight you have to crank?
20. What device uses a rotating coil of wire in a magnetic field to produce motion?
21. What device increases or decreases electrical energy?

Answers

1. The gravitational force between two objects decreases as the distance between them increases.

What is gravitational?

Gravitational force is the attraction between two objects that is produced by their masses.

2. The gravitational force between two objects increases as the mass of one of the objects increases.

3. A bar magnet with magnetic field lines looks like a line of arrows pointing from the North Pole to the South Pole.

4. The parts of an electromagnet are the core, the coil, and the electricity.

5. A solenoid is a coil of wire wrapped around a core, usually made of iron, that produces a magnetic field when electricity is passed through it.

6. Two ways to strengthen an electromagnet are to increase the number of coils in the solenoid and to increase the strength of the electric current.

7. When the electricity is turned off, the magnetic force in an electromagnet decreases.

8. To test the strength of an electromagnet, you can measure the amount of mass it produces when it is turned on.

9. Besides the amount of mass an electromagnet produces, you can also measure the strength by measuring the current and number of turns in the coil.

10. Electromagnetic induction is the production of an electric current when a magnetic field is changed.

11. When a permanent magnet is moved through a coil of wire attached to a circuit, it produces an electric current.

12. Ammeters and galvanometers measure electric current in a circuit.

13. They use the principle of electromagnetic induction to measure the electric current in a circuit.

14. The generator in a hydroelectric power plant (or any power plant) is used to convert mechanical energy from the turbine into electrical energy.

15. In an electric generator, mechanical energy is converted into electrical energy through electromagnetic induction.

16. When electric current flows into a simple electric motor, it causes a spinning magnet to move and generate motion.

17. In an electric motor, electrical energy is converted into mechanical energy through electromagnetic induction.

18. An electromagnet does not include a spinning magnet, while an electric motor does.

19. The energy source that produces light in a flashlight you have to crank is mechanical energy.

20. The device that uses a rotating coil of wire in a magnetic field to produce motion is an electric motor.

21. A transformer is a device that increases or decreases electrical energy.

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Harmonic Motion Basics

10. Calculate the period of a pendulum that has a length of 68 cm.​

Answers

The period of the pendulum with a length of 68 cm is 1.65 seconds.

What is period of the pendulum?

The period of a pendulum is the time taken for one complete back-and-forth swing or oscillation. It is the time taken for the pendulum to move from its highest point (the point of maximum displacement) to its lowest point and back again to the highest point. The period of a pendulum depends on its length and the acceleration due to gravity.

The period of a pendulum can be calculated using the formula:

T = 2π√(L/g)

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.81 m/s²).

Converting the length of the pendulum to meters:

L = 68 cm = 0.68 m

Substituting the values into the formula:

T = 2π√(0.68 m / 9.81 m/s²)

Simplifying:

T = 2π√(0.0694 s²)

Calculating the square root:

T = 2π x 0.263 s

Simplifying:

T = 1.65 s

Therefore, the period of the pendulum with a length of 68 cm is 1.65 seconds.

What is an acceleration of the pendulum?

An acceleration of a pendulum refers to the rate at which its velocity changes as it swings back and forth. The acceleration of a pendulum is not constant but rather varies as the pendulum swings, with the greatest acceleration occurring at the endpoints of its swing, where it changes direction.The acceleration of a pendulum is directly proportional to the displacement of the pendulum from its equilibrium position.

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Complete question is: The period of the pendulum with a length of 68 cm is 1.65 seconds.

please help me in this question is physics​

Answers

a) Yes, the girl has kinetic energy with respect to the escalator since she is moving relative to it.

b) Yes, the kinetic energy of the girl depends on the chosen reference frame. If we consider the reference frame of the man who is stationary on the ground, then the girl has kinetic energy with respect to him as well.

How to explain the energy

However, if we choose a reference frame that is moving at the same velocity as the escalator, then the girl appears to be at rest and does not have any kinetic energy with respect to that reference frame.

It's important to note that the amount of kinetic energy the girl has will be different in each reference frame, but the total amount of energy she has (kinetic energy + potential energy) will be the same in all reference frames, as long as we ignore any energy losses due to friction. This is because energy is conserved, and it can only be transferred between different forms, but not created or destroyed.

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50 POINTS!! NO BOTS
A tsunami (tidal wave) traveling across deep water can have a speed of 750 km/h
and a wavelength of 270 km
What is the frequency of such a wave?
Express your answer to two significant figures and include the appropriate units

Answers

The frequency of the tsunami wave is estimated at  0.001 Hz

How do we calculate?

Frequency is described as the number of occurrences of a repeating event per unit of time

Using  the formula for the speed of a wave:

v = λ  x frequency

where v is the wave speed, λ is the wavelength, and f_ is the frequency.

frequency = v / λ

Substituting  the values given in the problem, we have

frequency  = 750 km/h / 270 km = 2.78 h^(-1)

f_ = 2.78 h^(-1) * (3600 s/h) = 1.00 x 10^(-3) s^(-1) or   0.001 Hz

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A Carnot Engine operates between two heat reservoirs. The cold reservoir is maintained at 20.0 °C. What temperature must the hot reservoir be at in order for the efficiency of the engine to be 20.0 %?

Answers

A heat engine with a 65.0% Carnot efficiency is currently being developed. Between a reservoir that is 25.00C and one that is 3750C, a heat engine is operational.

What is the formula for Carnot efficiency ?

The equation is: Carnot efficiency is equal to 1 - Tc/Th, wherein Tc is the cycle's cold end temperature and Th is its hot end temperature. In other words, efficiency is equal to one minus the difference between the hot and cold temperatures.

Explanation: The cold reservoir's temperature is TL=20C=20+273=293K. T L = 20 ∘ C = 20 + 273 = 293 K .

A Carnot cycle running between both of these two reservoirs has a thermal efficiency of = 1 TC/TH. This value exceeds the value of the Otto cycle, which is operating between similar reservoirs by a large margin.

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A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 30.7 ◦C.
In an attempt to cool the liquid, which has a mass of 188 g , 129 g of ice at 0.0 ◦C is added. At the time at which the temperature of the tea is 26.6 ◦C , find the mass of the remaining ice in the jar. The specific heat of water is 4186 J/kg◦ C . Assume the specific heat capacity of the tea to be that of pure liquid water. Answer in units of g.

Answers

The mass of the remaining ice in the jar is 188 g.

What is Equilibrium?

Equilibrium refers to a state of balance or stability where opposing forces or factors are balanced, resulting in a state of overall stability and no net change. In various contexts, equilibrium can have different meanings and applications.

We can rearrange the equations to solve for the mass of ice remaining (mice):

Qtea = Qice

mtea * ctea * ΔT = mice * cice * ΔT

mice = (mtea * ctea * ΔT) / (cice * ΔT)

Plugging in the given values:

mtea = 188 g

ctea = 4186 J/kg◦ C (specific heat capacity of water)

ΔT = 30.7 - 26.6 = 4.1 ◦C (change in temperature of the tea)

cice = 4186 J/kg◦ C (specific heat capacity of ice)

mice = (188 * 4186 * 4.1) / (4186 * 4.1)

mice = 188 g

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The nearest neighboring star to the Sun is about 4 light-years away. If a planet happened to be orbiting this star at an orbital radius equal to that of the Earth-Sun distance, what minimum diameter would an Earth-based telescope's aperture have to be in order to obtain an image that resolved this star-planet system? Assume the light emitted by the star and planet has a wavelength of 550 nm
. The Earth-Sun distance is 149.6×106km
, and 1ly=9.461×1015m
.

Answers

To resolve the star-planet system at a distance of 4 light-years, a telescope on Earth would need an aperture with a minimum diameter of 55.88 mm.

What does microscopy's Rayleigh criterion mean?

In optical microscopy, the Rayleigh criterion is frequently used to estimate the resolution of the microscope. The resolution limit imposed by this criterion has long been regarded as a roadblock to using an optical microscope to study biological phenomena at the nanoscale.

We can use the Rayleigh criterion,

θ = 1.22 λ / D

θ = angular resolution

λ = wavelength of light

D = diameter of the telescope's aperture

θ = arctan (r / d)

r = radius of the planet's orbit

d = distance to the star

Now, we use the given values,

r = 149.6×106 km = 149.6×109 m

d = 4 × 9.461×1015 m = 3.7844×1016 m

λ = 550 nm = 550×10-9 m

θ = arctan (r / d)

   =arctan (149.6×109 / 3.7844×1016) = 0.000012 radians

we can use the Rayleigh criterion,

θ = 1.22 λ / D

D = 1.22 λ / θ

D = 1.22 × 550×10-9 / 0.000012

D = 55.88 mm

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On the water surface, there are two sources of oscillating waves of the same phase located at A and B, emitting two coherent waves of wavelength λ. Let Δ be the line perpendicular to AB at B. On Δ there are 16 interference maxima, the distance between the two closest and farthest interference maxima is 2.71 cm and 229.55 cm, respectively. . Which of the following is the length of line segment AB closest to?

Answers

Two or greater sources are said to be coherent if they emit waves that have the identical wavelength (or frequency) and amplitude and which maintain a steady phase difference.

Do two coherent sources have equal wavelength?

If two sources have the identical wavelength, frequency, and segment difference, they are said to be coherent. Therefore, we can conclude that coherent sources have the identical wavelength.

Two microwave coherent factor sources emitting waves of wavelenths λare positioned at 5λdistance apart. The interference is being observed on a flat non-reflecting surface alongside a line passing through on sources ,in a course perpendicular to the line joining the two sources

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Which are different forms of an element that have different numbers of neutrons?

ions
isotopes
compounds
molecules
.
.

Answers

Answer:A

Explanation:

Isotopes are members of a family of an element that all have the same number of protons but different numbers of neutrons. The number of protons in a nucleus determines the element's atomic number on the Periodic Table.

B
Isotopes because are members of a family of an element that all have the same number of protons but different numbers of neutrons. The number of protons in a nucleus determines the element's atomic number on the Periodic Table.

If the speed of a wave is 400 cm/s with a frequency of 80 Hz, what is the wavelength for this wave?
32,000 cm
32,000 m
5 cm
5m

Answers

The speed of a wave is represented by the equation:

Speed = wavelength x frequency

We can rearrange this equation to solve for wavelength:

Wavelength = Speed / frequency

Plugging in the given values, we get:

Wavelength = 400 cm/s / 80 Hz
Wavelength = 5 cm

Therefore, the wavelength for this wave is 5 cm.

The average compensation for demale tennis players in $283,635, but the median compensation is much lower at around $76,000. Why are these numbers so different?

Answers

The difference in these numbers is likely due to the fact that there are a few very highly paid female tennis players who skew the average upwards.

What is average?

Average is a term used to describe a value that is representative of a set of data. It is calculated by adding up all the values in a set and dividing by the number of values in the set. Average can be used to describe the mean, median, or mode of a set of data. It is often used to average out the highs and lows in a set of data, to give an overall picture of the data set. Average can also be used to compare different sets of data to each other.

The median, however, only takes into account the middle value of the data set, so it doesn't take into account outliers like the highly paid female tennis players. This is why the median is usually considered a better measure of central tendency than the average.

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Within the living area of the colony, what atmospheric gases must be present on Venus?

Answers

Humans would need a breathable environment like that on Earth in the living section of a colony on Venus in order to survive. Nitrogen, oxygen, and trace amounts of other gases, such as carbon dioxide, make up the majority of the atmosphere on Earth.

What gases are present in Venus' atmosphere?

The clouds are made of sulfuric acid, and the atmosphere is primarily carbon dioxide, the same gas that causes the greenhouse effect on Venus and Earth. And the heated, high-pressure carbon dioxide acts corrosively at the surface.

What gases are found in Mars' and Venus' atmospheres?

For instance, compared to Earth, which has 99% nitrogen and oxygen in its atmosphere, Venus and Mars both contain more than 98% carbon dioxide and nitrogen.

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50 examples of Scaler quantities​

Answers

Answer:

Explanation: Mass of an object

Distance traveled

Temperature in Celsius or Fahrenheit

Time elapsed

Area of a square or rectangle

Volume of a container

Energy consumed

Speed of a moving object

Amount of money

Density of a substance

Electric charge

Length of a rod or wire

Amount of substance (moles)

Angle of rotation

Electric potential (voltage)

Pressure of a gas or fluid

Frequency of a wave

Conductivity of a material

Viscosity of a fluid

Radioactivity

Magnetic field strength

Refractive index of a medium

Gravitational force

Work done

Power of an electrical device

Resistivity of a material

Specific heat capacity of a substance

Modulus of elasticity

Torque or moment of force

pH of a solution

Electrostatic charge

Atomic or molecular weight

Charge of an electron or proton

Electrical resistance

Illuminance or brightness

Concentration of a solute in a solution

Efficiency of a machine

Absorbance or transmittance of light

Electrochemical potential

Activity of a radioactive sample

Ratio of two lengths

Ratio of two areas

Ratio of two volumes

Ratio of two speeds

Ratio of two masses

Ratio of two times

Ratio of two temperatures

Ratio of two pressures

Ratio of two concentrations

Ratio of two densities

A ball is traveling at a constant speed of 4 m/s in a circle with a radius of 0.8 m. What is the centripetal acceleration of the ball?

Answers

According to the question the centripetal acceleration of the ball is 20 m/s².

What is centripetal acceleration?

Centripetal acceleration is the acceleration that a body experiences when it is moving in a curved path. It is always directed towards the center of the curve, and its magnitude is equal to the square of the body's velocity divided by the radius of the curve. It is also known as the radial acceleration, since it is directed along the radius of the curve.

The centripetal acceleration of an object in a circular path is given by the equation:

[tex]a_c[/tex] = v²/r
where a_c is the centripetal acceleration, v is the speed of the object, and r is the radius of the circular path.
In this case, the speed of the ball is 4 m/s, and the radius of the circular path is 0.8 m. Plugging these values into the equation, we get:

[tex]a_c[/tex] = 4²/0.8 = 16/0.8 = 20 m/s²
Therefore, the centripetal acceleration of the ball is 20 m/s².

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5. Two equal charges are situated in a vacuum 10.0cm apart, if they repel each other with a force of 0.5N, calculate the value of the charge on each. [4π)¹ = 9.0 x 10⁹ I​

Answers

The value of the charge on each particle is [tex]1.05 x 10^-8 C[/tex].

What is Coulomb's law?

Coulomb's law is a fundamental principle of electrostatics that describes the interaction between electric charges. It states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. We can use Coulomb's law to solve this problem. Mathematically,

[tex]F = k(q1q2)/r^2[/tex]

where F is the force of attraction or repulsion between the two charged particles,[tex]q1[/tex] and [tex]q2[/tex] are the magnitudes of the charges on the two particles, r is the distance between them, and k is Coulomb's constant, which has a value of [tex]9.0 x 10^9 Nm^2/C^2.[/tex]

In this problem, we know that the charges are equal and the distance between them is 10.0 cm. We also know that the force between them is 0.5 N. Therefore,

[tex]0.5 N = k(q^2)/(0.1 m)^2[/tex]

Solving for q, we get:

[tex]q = \sqrt{[(0.5 N)(0.1 m)^2/k]}[/tex]

[tex]q = \sqrt{(0.5 N)(0.01 m)/(9.0 x 10^9 Nm^2/C^2)}[/tex]

[tex]q = 1.05 x 10^-8 C[/tex]

Therefore, the value of the charge on each particle is [tex]1.05 x 10^-8 C.[/tex]

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A model rocket blast off and moves upward with an acceleration of 12m/s2 until it reaches a height of 26m, at which point its engine shuts off and it continues its flight in free fall.
a) What is the maximum height attained by the rocket?
b) What is the speed of the rocket just before it hits the ground?
c) What is the total duration of the rocket's flight?

Answers

To solve this problem, we can use the kinematic equations of motion.

a) To find the maximum height attained by the rocket, we need to find the time it takes to reach that height. We can use the equation:

h = vi*t + (1/2)*a*t^2

where h is the maximum height attained, vi is the initial velocity (which is zero), a is the acceleration, and t is the time taken to reach the maximum height.

Plugging in the values given, we get:

26m = 0*t + (1/2)*12m/s^2*t^2

Simplifying the equation, we get:

t^2 = (2*26m) / 12m/s^2
t^2 = 3.5s^2
t = 1.87s

Now that we know the time taken to reach the maximum height, we can use another kinematic equation to find the maximum height:

v = vi + a*t

where v is the final velocity at the maximum height.

Plugging in the values given, we get:

v = 0 + 12m/s^2*1.87s
v ≈ 22.44m/s

Now we can find the maximum height using the equation:

h = vi*t + (1/2)*a*t^2

Plugging in the values given, we get:

h = 0*1.87s + (1/2)*12m/s^2*(1.87s)^2
h ≈ 26.2m

Therefore, the maximum height attained by the rocket is approximately 26.2 meters.

b) To find the speed of the rocket just before it hits the ground, we can use the equation:

v^2 = vi^2 + 2*a*h

where h is the maximum height attained, vi is the initial velocity (which is zero), a is the acceleration, and v is the final velocity just before hitting the ground.

Plugging in the values given, we get:

v^2 = 0 + 2*12m/s^2*26m
v^2 = 624m^2/s^2
v ≈ 25m/s

Therefore, the speed of the rocket just before it hits the ground is approximately 25 meters per second.

c) The total duration of the rocket's flight is the time taken to reach the maximum height plus the time taken to fall back
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