A stone is dropped into a lake, creating a circular ripple that travels outward at a speed of 70 cm/s. Find the rate at which the area within the circle is increasing after each of the following. A. After 1 second B. After 5 seconds C. After 6 seconds

The given expression is

=ab+cd+ef+gh

The meaning of expression is equal to terms which contains variables and constants and operation between them is Addition, Subtraction,  Multiplication and Division.

→The expression consists of four terms which are, ab, cd, ef, and gh.

→Each term contains

Two factors.

plz mark as brainliest

Answer:

[tex]r = 1.34[/tex]

Step-by-step explanation:

Given

Solid = Cylinder + 2 hemisphere

[tex]Volume = 10cm^3[/tex]

Required

Determine the radius (r) that minimizes the surface area

First, we need to determine the volume of the shape.

Volume of Cylinder (V1) is:

[tex]V_1 = \pi r^2h[/tex]

Volume of 2 hemispheres (V2) is:

[tex]V_2 = \frac{2}{3}\pi r^3 +\frac{2}{3}\pi r^3[/tex]

[tex]V_2 = \frac{4}{3}\pi r^3[/tex]

Volume of the solid is:

[tex]V = V_1 + V_2[/tex]

[tex]V = \pi r^2h + \frac{4}{3}\pi r^3[/tex]

Substitute 10 for V

[tex]10 = \pi r^2h + \frac{4}{3}\pi r^3[/tex]

Next, we make h the subject

[tex]\pi r^2h = 10 - \frac{4}{3}\pi r^3[/tex]

Solve for h

[tex]h = \frac{10}{\pi r^2} - \frac{\frac{4}{3}\pi r^3 }{\pi r^2}[/tex]

[tex]h = \frac{10}{\pi r^2} - \frac{4\pi r^3 }{3\pi r^2}[/tex]

[tex]h = \frac{10}{\pi r^2} - \frac{4r }{3}[/tex]

Next, we determine the surface area

Surface area (A1) of the cylinder:

Note that the cylinder is covered by the 2 hemisphere.

So, we only calculate the surface area of the curved surface.

i.e.

[tex]A_1 = 2\pi rh[/tex]

Surface Area (A2) of 2 hemispheres is:

[tex]A_2 = 2\pi r^2+2\pi r^2[/tex]

[tex]A_2 = 4\pi r^2[/tex]

Surface Area (A) of solid is

[tex]A = A_1 + A_2[/tex]

[tex]A = 2\pi rh + 4\pi r^2[/tex]

Substitute [tex]h = \frac{10}{\pi r^2} - \frac{4r }{3}[/tex]

[tex]A = 2\pi r(\frac{10}{\pi r^2} - \frac{4r }{3}) + 4\pi r^2[/tex]

Open bracket

[tex]A = \frac{2\pi r*10}{\pi r^2} - \frac{2\pi r*4r }{3} + 4\pi r^2[/tex]

[tex]A = \frac{2*10}{r} - \frac{2\pi r*4r }{3} + 4\pi r^2[/tex]

[tex]A = \frac{20}{r} - \frac{8\pi r^2 }{3} + 4\pi r^2[/tex]

[tex]A = \frac{20}{r} + \frac{-8\pi r^2 }{3} + 4\pi r^2[/tex]

Take LCM

[tex]A = \frac{20}{r} + \frac{-8\pi r^2 + 12\pi r^2}{3}[/tex]

[tex]A = \frac{20}{r} + \frac{4\pi r^2}{3}[/tex]

Differentiate w.r.t r

[tex]A' = -\frac{20}{r^2} + \frac{8\pi r}{3}[/tex]

Equate A' to 0

[tex]-\frac{20}{r^2} + \frac{8\pi r}{3} = 0[/tex]

Solve for r

[tex]\frac{8\pi r}{3} = \frac{20}{r^2}[/tex]

Cross Multiply

[tex]8\pi r * r^2 = 20 * 3[/tex]

[tex]8\pi r^3 = 60[/tex]

Divide both sides by [tex]8\pi[/tex]

[tex]r^3 = \frac{60}{8\pi}[/tex]

[tex]r^3 = \frac{15}{2\pi}[/tex]

Take [tex]\pi = 22/7[/tex]

[tex]r^3 = \frac{15}{2 * 22/7}[/tex]

[tex]r^3 = \frac{15}{44/7}[/tex]

[tex]r^3 = \frac{15*7}{44}[/tex]

[tex]r^3 = \frac{105}{44}[/tex]

Take cube roots of both sides

[tex]r = \sqrt[3]{\frac{105}{44}}[/tex]

[tex]r = \sqrt[3]{2.38636363636}[/tex]

[tex]r = 1.33632535155[/tex]

[tex]r = 1.34[/tex] (approximated)

Hence, the radius is 1.34cm

The radius of the cylinder that produces the minimum surface area is 1.34cm and this can be determined by using the formula area and volume of cylinder and hemisphere.

Given :

The volume of a cylinder is given by:

[tex]\rm V = \pi r^2 h[/tex]

The total volume of the two hemispheres is given by:

[tex]\rm V' = 2\times \dfrac{2}{3}\pi r^3[/tex]

[tex]\rm V' = \dfrac{4}{3}\pi r^3[/tex]

Now, the total volume of the solid is given by:

[tex]\rm V_T = \pi r^2 h+\dfrac{4}{3}\pi r^3[/tex]

Now, substitute the value of the total volume in the above expression and then solve for h.

[tex]\rm 10 = \pi r^2 h+\dfrac{4}{3}\pi r^3[/tex]

[tex]\rm h = \dfrac{10}{\pi r^2}-\dfrac{4r}{3}[/tex]

Now, the surface area of the curved surface is given by:

[tex]\rm A = 2\pi r h[/tex]

Now, the surface area of the two hemispheres is given by:

[tex]\rm A'=2\times (2\pi r^2)[/tex]

[tex]\rm A'=4\pi r^2[/tex]

Now, the total area is given by:

[tex]\rm A_T = 2\pi rh+4\pi r^2[/tex]

Now, substitute the value of 'h' in the above expression.

[tex]\rm A_T = 2\pi r\left(\dfrac{10}{\pi r^2}-\dfrac{4r}{3}\right)+4\pi r^2[/tex]

Simplify the above expression.

[tex]\rm A_T = \dfrac{20}{r} + \dfrac{4\pi r^2}{3}[/tex]

Now, differentiate the total area with respect to 'r'.

[tex]\rm \dfrac{dA_T}{dr} = -\dfrac{20}{r^2} + \dfrac{8\pi r}{3}[/tex]

Now, equate the above expression to zero.

[tex]\rm 0= -\dfrac{20}{r^2} + \dfrac{8\pi r}{3}[/tex]

Simplify the above expression in order to determine the value of 'r'.

[tex]8\pi r^3=60[/tex]

r = 1.34 cm

For more information, refer to the link given below:

https://brainly.com/question/11952845

Answer:

d=-124

Step-by-step explanation:

To find the discriminant use the equation b^2-4ac

So, 20^2-4(-131)(-1)

400-524= -124

d=-124

Answer:

67

Step-by-step explanation:

Took a test

Answer:

4.

Step-by-step explanation:

(x^2 + 7x - 9) + (3x^2 - 2x) + (x^2 + 7x - 9) + (3x^2 - 2x)

x^2 + 7x - 9 + 3x^2 - 2x + x^2 + 7x - 9 + 3x^2 - 2x

Rearranging order:

3x^2 + 3x^2 + x^2 + x^2 + 7x + 7x - 2x - 2x - 9 - 9

Combine like terms

8x^2 + 10x - 18

Answer: a) 62.591 lb  b) 7.5

Step-by-step explanation:

Answer:

a) 62.625 lb

b) 8.35

Step-by-step explanation:

a) Use a proportion.

4 gal is to 33.4 lb as 7.5 gal is to x lb.

4/33.4 = 7.5/x

4x = 33.4 * 7.5

4x = 250.5

x = 62.625

Answer: 62.625 lb

b) 33.4/4 = 8.35

Tada!!!!!

Answer:

a) 0.0977

b) 0.3507

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

Mean = 1395 grams

Standard deviation = 200 grams. Use the TI-84 Plus calculator to answer the following.

We solve using z score formula

z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

(a) What proportion of broilers weigh between 1160 and 1250 grams?

For x = 1160

z = 1160 - 1395/300

= -0.78333

Probability value from Z-Table:

P(x = 1160) = 0.21672

For x = 1250 grams

z = 1250 - 1395/300

z = -0.48333

Probability value from Z-Table:

P(x = 1250) = 0.31443

The proportion of broilers weigh between 1160 and 1250 grams is

0.31443 - 0.21672

= 0.09771

≈ 0.0977

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

For x = 1510

= z = 1510 - 1395/300

z = 0.38333

Probability value from Z-Table:

P(x<1510) = 0.64926

P(x>1510) = 1 - P(x<1510) = 0.35074

Approximately = 0.3507

(c) Is it unusual for a broiler to weigh more than 1610 grams?

For x = 1610

= z = 1610 - 1395/300

z = 0.71667

Probability value from Z-Table:

P(x<1610) = 0.76321

P(x>1610) = 1 - P(x<1610) = 0.23679

No it is not unusual for a broiler to weigh more than 1610 grams

No change in area if sides of rectangle are equal.

Hope this helps.

Answer: C ( square root of 1.5 x 3.6)

Step-by-step explanation:

The price for the variance is 3.6 times 1.5. Standard deviation is the square root of variance, so the answer is the square root of 1.5 x 3.6.

The standard deviation expression of the distribution P is √(1.50 × 3.6)

Given the Parameters :

The price for the variance of the distribution can be written as :

The standard deviation of the distribution D is related to the variance by the formular :

Therefore, the standard deviation in $ of P will be √(1.50 × 3.6)

Learn more :https://brainly.com/question/18153040

Answer:

yes

Step-by-step explanation:

I figured this out by determining how many times 3 fits into 7.

7/3 is equal to 2 and 1/3

2 1/3 < 6

Hope this helps <3

please give brainliest

Answer:

See below.

Step-by-step explanation:

What you wrote means:

[tex] r = \dfrac{n}{2}(b + H) [/tex]

If that is what you meant, then the answer is:

[tex] \dfrac{2r}{n} = b + H [/tex]

[tex] H = \dfrac{2r}{n} - b [/tex]

On the other hand, if this is what you meant:

[tex] r = \dfrac{n}{2(b + H)} [/tex]

then the answer is:

[tex] 2r(b + H) = n [/tex]

[tex] 2rb + 2rH = n [/tex]

[tex] 2rH = n - 2rb [/tex]

[tex] H = \dfrac{n - 2rb}{2r} [/tex]

Answer:

Step-by-step explanation:

[tex]\frac{n}{2}(b + H) = r\\\\b +H = r * \frac{2}{n}\\\\b + H = \frac{2r}{n}\\\\H = \frac{2r}{n} - b[/tex]

Answer:

$1,815

Step-by-step explanation:

Use the simple interest formula, I = prt

Plug in the values we know:

I = prt

I = (1,500)(0.07)(3)

I = 315

Add this to the original amount:

1500 + 315

= 1,815

So, John will have $1,815 in his account after 3 years.

Answer: The answer is 384 if your question is 12x1/2x64

Answer:

it's 2

Step-by-step explanation:

a= -3/4

b=0

c=2

Answer: x=6/5

Step-by-step explanation:

Answer:

6/5

Step-by-step explanation:

Answer:

y = -2x - 3

Step-by-step explanation:

Given:

Equation of -x +2y =4

Point of (-2,1)

-x + 2y = 4

y = x/2 + 2 or y = 1/2x + 2

Which means the equation's slope is m = 1/2.

The slope of the perpendicular line is negative inverse which is m = -2.

Now we have an equation of y = -2x + a.

Use (-2, 1) to find a:

1 = (-2)(-2) + a

a = -3

y = - 2x - 3

Answer:

Step-by-step explanation:

From the given information:

[tex]R_{in} = ( \dfrac{1}{2} \ lb/gal) (6)\ gal /min \\ \\R_{in} = 3 \ lb/min[/tex]

Given that the solution is pumped at a slower rate of 4gal/min

Then:

[tex]R_{out} = \dfrac{4A}{100+(6-4)t}[/tex]

[tex]R_{out}= \dfrac{2A}{50+t}[/tex]

The differential equation can be expressed as:

[tex]\dfrac{dA}{dt}+ \dfrac{2}{50+t}A = 3 \ \ \ ... (1)[/tex]

Integrating the linear differential equation; we have::

[tex]\int_c \dfrac{2}{50 +t}dt = e^{2In |50+t|[/tex]

[tex]\int_c \dfrac{2}{50 +t}dt = (50+t)^2[/tex]

multiplying above integrating factor fields; we have:

[tex](50 +t)^2 \dfrac{dA}{dt} + 2 (50 + t)A = 3 (50 +t)^2[/tex]

[tex]\dfrac{d}{dt}\bigg [ (50 +t)^2 A \bigg ] = 3 (50 +t)^2[/tex]

[tex](50 + t)^2 A = (50 + t)^3+c[/tex]

A = (50 + t) + c(50 + t)²

Using the given conditions:

A(0) = 20

⇒ 20 = 50 + c (50)⁻²

-30 = c(50) ⁻²

c = -30 × 2500

c =  -75000

A = (50+t) - 75000(50 + t)⁻²

The no. of pounds of salt in the tank after 35 minutes is:

A(35) = (50 + 35) - 75000(50 + 35)⁻²

A(35) = 85 - [tex]\dfrac{75000}{7225}[/tex]

A(35) =69.6193 pounds

A(35) [tex]\simeq[/tex] 70 pounds

Thus; the number of pounds of salt in the tank after 35 minutes is 70 pounds.

Answer:

7) y = -2

8) x = 4

Step-by-step explanation:

Any straight horizontal/vertical line you find will be x= or y=. The vertical lines are always x= because they only touch the x axis. It's the opposite for horizontal lines. For example, on number 7, the line touches -2 on the y axis. That's why it's "y=-2". Same goes for 8. the line only touches 4.

I hope this helped and wasn't confusing!

Answer:

The first one

The area of a rectangle is the product of length and width thus the area will be 1358 square meters.

A rectangle is a geometrical figure in which opposite sides are equal.

The angle between any two consecutive sides will be 90 degrees.

The perimeter of the rectangle = 2( length + width).

It is known that,

Area of rectangle = length × width.

Area = 97 x 14 = 1358 sqare meters

Hence "The area of a rectangle is the product of length and width thus the area will be 1358 square meters".

For more about rectangles,

https://brainly.com/question/15019502

#SPJ5

Answer:

(f o g)(x) = x + 5

General Formulas and Concepts:

Algebra I

Algebra II

Step-by-step explanation:

Step 1: Define

f(x) = x + 2

g(x) = x + 3

(f o g)(x) = f(g(x))

Step 2: Find

Answer:

f(x+3)=x+5

Goodluck to you

Answer:

A negative number, a negative integer, a negative multiple of 3, etc.

Step-by-step explanation:

Answer:

integer

???????

Step-by-step explanation:

I'm not sure

Answer:

3

Step-by-step explanation:

Given a line with points; (2, 5) (3, 8).

1. Find the slope of the given line

The formula for finding the slope is:

[tex]\frac{y_{2}-y_{1} }{x_{2} - x_{1}}[/tex]

Substitute in the values;

[tex]x_{1} = 2\\y_{1} = 5\\x_{2} = 3\\y_{2} = 8[/tex]

[tex]\frac{8-5}{3-2}[/tex]

simplify;

[tex]\frac{3}{1}[/tex]

= 3

2. Find the slope of the parallel line;

Remember, when two lines are parallel, they run alongside each other, of infinitely long, but they never touch. Hence two parallel lines have the same slope. Therefore, the slope of a line that is parallel to the given one will also have the same slope as the given one, which is 3.

9514 1404 393

Answer:

  4 1 5 3 6 2

Step-by-step explanation:

The general approach to this proof is to show the triangles created by the diagonal are congruent. Then, parts of those triangles (opposite sides) are congruent. The congruence of the triangles is shown by making use of the fact that alternate interior angles are congruent, and the diagonal is congruent to itself. Thus, you have two angles and the side between shown as congruent, and can invoke the ASA postulate.

The steps of the proof (1 to 6) are already in order. The task is to find the geometric relation the step is describing from the list on the left.

__

Statements A to F on the left match with numbered statements 1 to 6 on the right as follows:

A - 4 (reflexive prop)

B - 1 (given)

C - 5 (ASA)

D - 3 (alt int angle)

E - 6 (the end point of the proof)

F - 2 (definition)

It is false that the expressions 4x − 2(5x − 1) and 6x + 2 are equivalent expressions

The expression is given as:

4x − 2(5x − 1)

Open the bracket

4x − 2(5x − 1) = 4x − 10x + 2

Evaluate the like terms

4x − 2(5x − 1) = − 6x + 2

− 6x + 2 and 6x + 2 are not equal expressions

Hence, 4x − 2(5x − 1) and 6x + 2 are not equivalent expressions

Read more about equivalent expressions at:

https://brainly.com/question/2972832

#SPJ2

Answer:

4y + 6x ≤ 96

12y + 2x ≤ 96

Step-by-step explanation:

Paper shredders produced :

Home :

Assembling time = 4 hours

Finishing work unit = 12

Office :

Assembling time = 6 hours

Finishing work unit = 2

Maximum number of assembly hours = 96 / day

Maximum number of finishing hours = 96/ day

Let

x = the number of office model shredders produced per day and

y = the number of home model shredders produced per day

(office Assembly hours x Number of office model) + (Assembly hours * number home models)

OFFICE MODEL:

Assembly operation :

Home + office ≤ 96

4y + 6x ≤ 96

Finishing operation :

Home + office ≤ 96

12y + 2x ≤ 96

Answer:

$69.21

Step-by-step explanation:

Since the box has a square base the length and breadth of the box will be equal. Let it be [tex]x[/tex]

Let h be the height of the box

V = Volume of the box = [tex]620\ \text{cm}^3[/tex]

[tex]x^2h=620\\\Rightarrow h=\dfrac{620}{x^2}[/tex]

Now surface area of the box with an open top is given

[tex]s=x^2+4xh\\\Rightarrow s=x^2+4x\dfrac{620}{x^2}\\\Rightarrow s=x^2+\dfrac{2480}{x}[/tex]

Differentiating with respect to x we get

[tex]\dfrac{ds}{dx}=2x-\dfrac{2480}{x^2}[/tex]

Equating with zero

[tex]0=2x-\dfrac{2480}{x^2}\\\Rightarrow 2x^3-2480=0\\\Rightarrow x^3=\dfrac{2480}{2}\\\Rightarrow x=(1240)^{\dfrac{1}{3}}\\\Rightarrow x=10.74[/tex]

Double derivative of the function

[tex]\dfrac{d^2s}{ds^2}=2+\dfrac{4960}{x^3}=2+\dfrac{4960}{1240}\\\Rightarrow \dfrac{d^2s}{ds^2}=6>0[/tex]

So, x at 10.74 is the minimum value of the function.

[tex]h=\dfrac{620}{x^2}\\\Rightarrow h=\dfrac{620}{10.74^2}\\\Rightarrow h=5.37[/tex]

So, minimum length and breadth of the box is 10.74 cm while the height of the box is 5.37 cm.

The total area of the sides is [tex]4xh=4\times 10.74\times 5.37=230.7\ \text{cm}^2[/tex]

The area of the base is [tex]x^2=10.74^2=115.35\ \text{cm}^2[/tex]

Cost of the base is $0.40 per square cm

Cost of the side is  $0.10 per square cm

Minimum cost would be

[tex]230.7\times 0.1+0.4\times 115.34=\$69.21[/tex]

The minimum cost of the box is 69.21 dollars.