Using the binomial distribution, it is found that there is a 4% probability of Anne winning two matches.
What is the binomial distribution formula?The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.In this problem:
She plays two matches, hence n = 2.She wins a match 20% of the time, hence p = 0.2.The probability that he wins two matches is P(X = 2), hence:
[tex]P(X = 2) = C_{2,2}.(0.2)^{2}.(0.8)^{0} = 0.04[/tex]
4% probability of Anne winning two matches.
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Miranda thought her new jeans would cost $32. The price was actually $36. What was percent error?
A - 87.5%
B - 11.1%
C - 12.5%
D - 88.9%
Answer:
the answer; 32÷36×100 will give the answer (d) -88.9%
Helpp me with my sister's math
Answer:
pq - 12r
step by step explanation:
Please help I will give brainliest.
Answer:
Ten apples cost 9 dollars
Step-by-step explanation:
C(10) = 9
The input is 10 and the output is 9
You bought 10 apples for 9 dollars
Answer:
The last one
Step-by-step explanation:
10 is a function of C which says that the cost of 10 = 9.
mia draws a cone with a height of 9 inchess and a radius of 4 inches
The volume of the cone that was drawn by Mia is equal to 150.816 cubic inches.
How to calculate the volume of a cone.
Mathematically, the volume of a cone is given by this formula:
[tex]V = \frac{1}{3} \pi r^2h[/tex]
Where:
h is the height.r is the radius.Given the following data:
Radius of cone = 4 inches.
Height of cone = 9 inches.
Substituting the given parameters into the formula, we have;
Volume = 1/3 × 3.142 × 4² × 9
Volume = 3.142 × 16 × 3
Volume = 150.816 in³
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Brandon rolls a six sided die twenty times, and records the result in the table below. how many times did brandon roll above the average? 6 1 3 4 4 4 6 5 5 3 6 4 4 5 2 3 5 4 4 2 a. 14 b. 7 c. 5 d. 4
The average is the arithmetic mean of all the observations of a set of numbers. The number of times Brandon rolls above the average is 7.
What is average?The average is the arithmetic mean of all the observations of a set of numbers. it is found by dividing the sum of all the observations of the set by the number of observations in the set.
[tex]\rm{Average=\dfrac{Sum\ of\ observations}{Number\ of\ observations}[/tex]
In order to know the number of times Brandon rolls the dice above the average, we first need to calculate the average of the twenty rolls.
The average of the 20 times dice rolls,
[tex]\rm Average = \dfrac{6+1+3+4+4+4+6+5+5+3+6+4+4+5+2+3+5+4+4+2}{20}[/tex]
[tex]\rm Average = \dfrac{80}{20} = 4[/tex]
Thus, the average of the 20 rolls of the dice is 4.
Now, the number of times the result of the dice roll is above 4(x>4) is 7.
Hence, the number of times Brandon rolls above the average is 7.
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A pupil who scored 50 in his paper 1
exam got ill and missed paper 2.
use the line of best fit to predict what
his paper 2 mark could have been.
The graph of the pupil's score is an illustration of scatter plots
The student's expected score in paper 2 is 62
How to predict the score in the missed paperTo predict the score of the pupil in the missed paper, we simply interpret the points on the line of best fit of the scatter plot
From the graph (see attachment), we have:
Paper 2 = 62 when Paper 1 = 50
This means that the student's expected score in paper 2 is 62
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An equilateral triangle has an area of 50 units 2. What is the length of each side?
Answer:
Length of each side of equilateral Traingle is 10.75 unitsStep-by-step explanation:
Given that area of an equilateral traingle 50 square units.
Let the length of side of equilateral traingle be 'x' units. To calculate length of each side we will use the formula of area of equilateral traingle:
[tex] \: \: { \underline { \boxed{\pmb { \sf{ \purple {Area_{(equilateral \: traingle)} = \dfrac{\sqrt 3}{4} \times (Side)^2}} }}}} \\ [/tex]
By substituting the values in above formula:
[tex]~[/tex]
[tex] : \implies \sf \: \: 50 = \dfrac{ \sqrt{3} }{4} \times {(x)}^{2} \\ \\ \\ : \implies \sf \: \: {(x)}^{2} = \dfrac{50 \times 4}{ \sqrt{3} } \\ \\ \\ : \implies \sf \: \: {(x)}^{2} = \dfrac{200}{ \sqrt{3} } \\ \\ \\ : \implies \sf \: \: x = \sqrt{ \dfrac{200}{ \sqrt{3} } } \\ \\ \\ : \implies \: \: { \boxed{\pmb{ \frak{ x = 10.75 \: units }}}}\\ \\ \\ [/tex]
Hence, Length of each side of equilateral Traingle is 10.75 unitsWrite your answers using set notation.
Answer:
domain = {-8, -6, 8}
range = {-4, -1, 0, 8}
Step-by-step explanation:
The domain is the set of first numbers of the ordered pairs. The range is the set of second numbers. We generally like to have the elements of a set arranged in order, with duplicates eliminated.
domain = {-8, -6, 8}
range = {-4, -1, 0, 8}
In the adjoining figure triangle PQR is similar to triangle PMN , PM= 2MQ And PN = 2NR . Determine ratio of MN/QR
The triangles PQR and PMN are similar triangles
The ratio MN/ QR is 2/3
How to detemine the ratio MN/QR?The question is incomplete, as the figure of the triangles are not given.
So, I will give a general explanation
The given parameters are:
PM= 2MQ
PN = 2NR
Rewrite PM= 2MQ as:
PM/MQ = 2/1
The equation becomes
PM/(PM + MQ) = 2/(2 + 1)
PM/(PM + MQ) = 2/3
Add PM and MQ
PM/PQ = 2/3
The above means that:
PM/PQ = MN/ QR = 2/3
Hence, the ratio MN/ QR is 2/3
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Caleb invested $1400 in an account that pays 4% interest compounded annually.
Assuming no deposits or withdrawals are made, find how much money Caleb would
have in the account 7 years after his initial investment. Round to the nearest tenth (if
necessary
Answer:
$1842.30
Step-by-step explanation:
Calculation Steps:
First, convert R as a percent to r as a decimal
r = R/100
r = 4/100
r = 0.04 rate per year,
Then solve the equation for A
A = P(1 + r/n)^nt
A = 1,400.00(1 + 0.04/1)^(1)^(7)
A = 1,400.00(1 + 0.04)^(7)
A = $1,842.30
determine the distance travelled by the car during this time D =(2m x t2)/2
Answer:
D = 2mt
Step-by-step explanation:
D = (2m × 2t)/2
[tex] \sf \: d \: = \frac{2m \times t(2)}{2} [/tex]
[tex] \rightarrow \: \sf \: d = \frac{2m \times 2t}{2} [/tex]
[tex] \rightarrow \: \sf \: d = \frac{4mt}{2} [/tex]
[tex] \rightarrow \: \sf \: d = 2mt[/tex]
~Done~
------
A small company has $8,250,000 in (annual) revenue, spends 49% of its revenues on purchases, and has a net profit margin of 8. 5%. They would like to increase their profits and they are looking at focusing in one of two directions. First, they think they can save 2. 05% on their purchase expenses. Or second, they can focus on increasing sales. By how many dollars would they have to increase sales in order to equal a 2. 05% savings to purchasing expenses? (Display your answer as a whole number. )
as far as I can read that, well, the company has a revenue income of 8250000 and their expenditure on purchases is 49% of that amount, how much is that?
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{49\% of 8250000}}{\left( \cfrac{49}{100} \right)8250000}\implies 4042500[/tex]
so on saving 2.05% of purchasing expenses or namely 2.05% of 4042500
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{2.05\% of 4042500}}{\left( \cfrac{2.05}{100} \right)4042500}\implies 82871.25[/tex]
so sales must be increased by that much in order to match the 2.05% of 4042500.
Can u do these for me
Answer:
Step-by-step explanation:
Compare the decimals using >, <, or =
2.95 > 2.949 (2.95 can be written as 2.950, which is > 2.949)3.75 < 3.8 (3.8 can be written as 3.80, which is > 3.75)0.98 = 0.980 (0.98 can be written as 0.980, which is = 0.980)0.86 < 0.861 (0.86 can be written as 0.860, which is < 0.861)1.76 < 2 (2 can be written as 2.00, which is > 1.76)3.15 < 3.2 ( 3.2 can be written as 3.20, which is > 3.15)Name two equivalent fractions for each fraction listed below.
2/4 = 1/2 = 4/81/3 = 2/6 = 3/91/10 = 2/20 = 3/30If there are 16 cups in one gallon, how many cups are in 3 gallons?
16 cups = 1 gal.
? cups = 3 gals.
3 * 16 = 48 cups
How many cups are in 5 gallons?
5 * 16 = 80 cups
Compare and contrast squares are rectangles
Squares: have four sides and four equal sides
Rectangles: have four sides and have 2 parallel sides, meaning that they have 2 opposite sides that are equal.
Hope this helps!
Answer number 9 please. Thank you.
The above attachment is the answer. Hope it helps?
Solve these pair of simultaneous equations.In each case the first step is to subtract the two equations.Give both solutions;x and y.
x-6y=32
x-4y =24
2x-3y =2
2x + 4y = 44
Please work it out
"Your teacher brings two bags of colored goldfish crackers to class. Bag I has 25% red crackers and Bag II has 35% red crackers. Each bag contains more than 1000 crackers. Using a paper cup, your teacher takes an SRS of 50 crackers from Bag I and a separate SRS of 40 crackers from Bag II. Let p1-p2 be the difference in the sample proportions of red crackers. " The object is to find the standard deviation. I have 0. 971. Is this correct? I would like to verify
Using the Central Limit Theorem, it is found that the standard deviation is of 0.0971.
What does the Central Limit Theorem states?It states that for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1 - p)}{n}}[/tex], as long as [tex]np \geq 10[/tex] and [tex]n(1 - p) \geq 10[/tex].It also states that when two variables are subtracted, the standard deviation is the square root of the sum of the variances.In this problem, for each sample, the standard error is given by:
[tex]s_I = \sqrt{\frac{0.25(0.75)}{50}} = 0.0612[/tex]
[tex]s_{II} = \sqrt{\frac{0.35(0.65)}{40}} = 0.0754[/tex]
Hence, for the distribution of differences, it is given by:
[tex]s = \sqrt{s_I^2 + s_{II}^2} = \sqrt{0.0612^2 + 0.0754^2} = 0.0971[/tex]
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Given that cosθ= - 21/29 and the angle θ terminates in quadrant II, then what is the value of tan θ
Answer: -20/21
Step-by-step explanation:
Using the Pythagorean identity, we can get that the sine of angle theta is [tex]\pm 20/29[/tex].
But since theta terminates in Quadrant II, the sine of angle theta is positive, meaning that it has a value of 20/29.
Now, since tan = sin/cos, tan theta = (20/29)/(-21/29) = -20/21
HELP ME PLEASE
PRETTY PLEASEEEEEEEEEEE
Answer:
93
Step-by-step explanation:
19x-2 = 18x+3
x=5
15(5) -2=93
18(5)+3=93
Jake has 900 cm³ of material. He uses 14. 5 cm³ to make a right triangular prism. He wants to make a second prism that is a dilation of the first prism with a scale factor of 4. How much more material does Jake need in order to make the second prism? Select from the drop-down menu to correctly complete the statement. Jake needs an additional Choose. Cm³ of material to make the second prism.
A ratio shows the relation between two numbers. The amount of more material that is needed by Jake is 42.5 cm³.
What is a Ratio?A ratio shows us the number of times a number contains another number.
Given that the volume of the first prism is 14.5cm³, while the scale factor is 4. Since the scale factor is applicable to dimension, and volume is always the cube of three-dimension.
Therefore, the volume of the scaled prism will be the cube the of the volume of the first prism, which can be written as,
[tex]\rm \text{Volume of the Scaled prism}= (Scale\ factor)^3 \times \text{Volume of the first prism}[/tex]
Substitute the values,
[tex]\rm \text{Volume of the Scaled prism}= 4^3 \times 14.5 = 928\ cm^3[/tex]
Since, the volume of material with Jake is 900 cm³, while the material he has already used is 14.5 cm³, thus the volume of the material that is left with Jake is 885.5 cm³(900cm³-14.5cm³).
Now, since the material needed to make the scaled prism is 928 cm³, the amount of material that is with Jake is 885.5 cm³, therefore, the amount of the material that is needed by Jake to complete the scaled prism can be written as,
The Amount of more material Needed by Jake = Amount of material needed to make the scaled prism - Amount of material left with Jake
The Amount of more material Needed by Jake = 928 cm³ - 885.5 cm³
= 42.5 cm³
Hence, the amount of more material that is needed by Jake is 42.5 cm³.
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20 = (-10) = (-20) +10
1) Is the equation up there true or false?
2) Support your decision below.
Help quick
Answer:
No, 20 ≠ -10
Step-by-step explanation:
20 = (-10) = (-20)+10
20≠-10=-20+10
20≠-10=-10
A functionf(θ) is periodic if after some periodt, it repeats. In other wordsf(θ t) =f(θ) for allθ. Lettingθbe a real number, isf(θ) =eiθperiodic? (2 points) if so, what is its period? (2points)
The period of the given function is T = 2π
What is the period of the function?The period T of a function f(x) is such that:
f(x + T) = f(x).
In this case, our function is:
f(θ) = e^{iθ}
Remember that this can be written as:
f(θ) = cos(θ) + i*sin(θ)
So yes, this is in did a periodic function.
Then the period of the function f(θ) is the same as the period of the cosine and sine functions, which we know is T = 2π.
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The period of the considered function f(θ) = e^{iθ} is found to be P = 2π (assuming 'i' refers to 'iota' and 'e' refers to the base of the natural logarithm)
What is euler's formula?For any real value θ, we have:
[tex]e^{i\theta} = \cos(\theta) + i\sin(\theta)[/tex]
where 'e' is the base of the natural logarithm, and 'i' is iota, the imaginary unit.
What are periodic functions?Functions which repeats their values after a fixed interval, are called periodic function.
For a function [tex]y = f(x)[/tex], it is called periodic with period 'T' if we have:
[tex]y = f(x) = f(x + T) \: \forall x \in D(f)[/tex]
where D(F) is the domain of the function f.
Suppose that, the period of the function [tex]f(\theta) = e^{i \theta}[/tex] be P, then we get:
[tex]f(\theta + P) = f(\theta)\\\\e^{i(\theta)} = e^{i(\theta + P)}\\\\\cos(\theta) + i\sin(\theta) = \cos(\theta + P) + i\sin(\theta + P)[/tex]
When two complex numbers are equal, then their real parts are equal and their imaginary parts are equal.
That means,
[tex]\cos(\theta) + i\sin(\theta) = \cos(\theta + P) + i\sin(\theta + P)[/tex] implies that:
[tex]\cos(\theta) = \cos(\theta + P)\\\sin(\theta) = \sin(\theta + P)[/tex]
Also, we know that the period of sine and cosine function is [tex]2\pi[/tex]
Thus, we get:
[tex]P = 2\pi[/tex]
Thus, the period of the function [tex]f(\theta) = e^{i \theta}[/tex] is P = 2π
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When Derek planted a tomato plant, he expected to be picking his first ripe tomato in 45 days. His estimate was 25% less than the actual time. How long did it take before Derek picked his first ripe tomato?
Answer:
60 days.
Step-by-step explanation:
Let the actual time be x, then:
x - 0.25x = 45
0.75x = 45
x = 45/0.75
= 60 days.
Find the value of the following:
a) 25 - 7.36
b) 8.65 + 4.23 - 3.5
Answer:
a 25-7.36
=17.64
b 8.65+4.23-3.5
=12.88-3.5
=9.38
Answer:
a) 17.64
b) 9.38
Step-by-step explanation:
a) 25 - 7.36 = 25 - 7 - 0.36 = 18 - 0.36 = 17.64
b) 8.65 + 4.23 - 3.5 = 8.65 - 3.5 + 4.23 = 5.15 + 4.23 = 9.38
Hope this helps :)
Have a nice day!
PLEASE HELPPP
find the value of x
Answer:
x = 62°
Step-by-step explanation:
Concepts:
All angles in a triangle add up to 180°, and there are three angles in a triangle. In this case, we're given the three angles as 50°, 68°, and x°. This means that x + 50 + 68 = 180.Solving
Step 1: Combine like terms.
[tex](x)+(50+68)=180[/tex] [tex]x+118=180[/tex]Step 2: Subtract 118 from both sides.
[tex]x+118-118=180-118[/tex][tex]x=62[/tex]Step 3: Check if solution is correct.
[tex]62+50+68=180[/tex][tex]112+68=180[/tex] [tex]180=180[/tex]Therefore, the answer is x = 62°.
The company warehouse contains 100 pallets of office paper, 25 pallets of photo paper, and 50 pallets of card stock. Each pallet of office paper is valued at $96, each pallet of photo paper is valued at $180, and each pallet of card stock is valued at $110.
Your partner is calculating the inventory value of these papers but thinks there is an error. Where in the calculations below is the error?
Step Description Result
1 Multiply 100 by $96 $ 9,600
2 Multiply 25 by $180 $ 4,500
3 Add $13,100
4 Multiply 50 by $110 $ 5,500
5 Add $18,600
A. Step 1
B. Step 2
C. Step 3
D. Step 4
E. Step 5
Answer:
c.
Step-by-step explanation:
Which equation can be used to solve for m∠1? m∠1 = one-half(a – b) m∠1 = one-half(a b) m∠1 = one-half(c – d) m∠1 = one-half(c d)
The equation will be:
[tex]m\angle 1=\dfrac{1}{2}(arc\ a-arc\ b)[/tex]
What is arc of circle?The arc of the circle is the curved line on the circle formed by the angle and the radius of the circle.
In the attached picture of the question, we can see that
The measure of the interior angle is the semi-sum of the arches that comprise it and its opposite.
So the equation will be
[tex]m\angle 1=\dfrac{1}{2}(arc\ a-arc\ b)[/tex]
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Answer: a
Step-by-step explanation:
find the slope of the line that passes through the pints (2,7) and (2,6)
Answer:
Undefined Slope
Step-by-step explanation:
The points (2,6) and (2,7) are on the same vertical line of 2, which results in an undefined slope.
Answer:
m=undefined
Step-by-step explanation:
The formula to find the slope isn't very complicated. The formula is:
y₂-y₁
m= --------
x₂-x₁
You have the points (2,7) and (2,-6). In (2,7) 2 is your x and 7 is your y. Since (2,7) is your first coordinate set, we put 2 as our x₁ . We put 7 as our y₁ .
In (2,-6) 2 is your x and -6 is your y. Since (2,-6) is your second coordinate set, we put 2 as our x₂ . We put -6 as our y₂ .
Let's substitute all of these numbers in:
-6-7 -13
m= ------- = -------
2-2 0
So we have -13/0 .You would think that any number divided by 0 is 0, right?
No. Any number divided by 0 is undefined.
Therefore, you slope, m, would be:
m=undefined .
Find the 8th term of the sequence whose common ratio is 1/3 and whose first term is 3
Answer:
The 8th term is [tex]\frac{1}{729}[/tex].
Step-by-step explanation:
Let's begin with the formula for a geometric sequence. We know this is geometric because we are working with a common ratio, or the number we multiply to find each term.
[tex]a_n=a_0(r)^{n-1}[/tex]
In this formula, [tex]a_0[/tex] is the first term, [tex]r[/tex] is the common ratio, and [tex]n[/tex] is the desired term. We know the values of [tex]r[/tex], [tex]a_0[/tex], and [tex]n[/tex] from the given information:
[tex]a_0=3\\r=\frac{1}{3}\\n=8[/tex]
Substituting those values we get:
[tex]a_8=3(\frac{1}{3})^{8-1}[/tex]
[tex]a_8=3(\frac{1}{3})^7\\a_8=3(\frac{1}{2187})\\a_8=\frac{3}{2187}\\a_8=\frac{1}{729}[/tex]
Daniel has read 70% of a book. He has 24 more pages to finish. How many pages are there in the book?
Answer:
80
Step-by-step explanation:
if he's read 70% then the 24 pages that are left are equal to 30 percent.
so the answer is 80. if you need extra steps don't hesitate to ask.
Helppp meee please this one confuses me
Step-by-step explanation:
=[tex] =(3x + 2)(x + 1) \\ = 3x(x + 1) + 2(x + 1) \\ = {3x}^{2} + 3x + 2x + 2 \\ = {3x}^{2} + 5x + 2[/tex]
Answer:
Bro really?? Anyway it's
[tex]anyway \: its \: 3x { }^{2} + 3x + 2x + 2[/tex]