Answer:
95.45%
Step-by-step explanation:
To go about this, what we do is to calculate the z-scores of the values in the range given.
Mathematically;
z-scores = (x-mean)/SD
Here in this case , mean is 3 and standard deviation is 0.25
So for 2.5 minutes, we have ;
z-score = (2.5-3)/0.25 = -0.5/0.25 = -2
For 3.5 minutes, we have;
z-score = (3.5-3)/0.25 = 0.5/0.25 = 2
The required probability we want to calculate according to the range is thus;
P(-2<z<2)
We can calculate this value by the use of the standard normal table
Mathematically, we can have the above as;
P(-2<z<2) = P(z<2) - P(z<-2)
We proceed using the table and we have the values as follows;
P(-2<z<2) = 0.97725 - 0.02275 = 0.9545
Now the value 0.9545 in percentage would be 95.45%
Evaluate 3x2 - 4 when x = 2.
A. 12
B. 32
c. 2
D. 8
Answer:
8
Step-by-step explanation:
3x^2 - 4
Let x = 2
3 * 2^2 -4
Exponents first
3 *4 -4
Then multiply
12 -4
Now subtract
8
[tex]\text{Plug in and solve:}\\\\3(2)^2-4\\\\3(4)-4\\\\12-4\\\\8\\\\\boxed{\text{D). 8}}[/tex]
Bella's back garden deck cost ₹5,391.47 per square metre to build. The deck is 11 metres wide and 12 metres long. How much did it cost to build the deck ...? brainliest as well as thanks also pleaase
Answer:
₹711,674.04
Step-by-step explanation:
1.firstly we need to solve for the total area of Bella's back garden deck.
2. Then we need to estimate mate the total cost of the garden given that a square metre cost ₹5,391.47 to build.
Given
length of garden = 12 metres
width of garden = 11 metres
Hence the area of the garden is given as
[tex]Area= length* width[/tex]
[tex]Area = 12*11= 132m^2[/tex]
if a square metre cost ₹5,391.47 to build.
132 square metre will cost= ₹5,391.47*132= ₹711,674.04
find the slope and y intercept of the line y=7/5x-3 5/7; 3 3; 7/5 7/5;-3 -3; 7/5
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
From the question
y = 7/5x - 3
Comparing with the above formula
Slope / m = 7/5c/ y intercept = - 3Hope this helps you
The value of the slope of the line is 7/5 and the y-intercept is -3
Given the line equation :
y = 7/5x - 3The general form of the equation is :
y = bx + cslope = b ; intercept = cComparing the equations :
b = 7/5 c = -3Hence, the slope and y-intercept are 7/5 and -3
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Harry took a loan from the bank. D represents Harry's remaining debt (in dollars) after t months. D = -200t + 9000 What was the size of Harry's loan? Please HELPPP Im not allowed to stand up from my chair until i finish this and i've been at it for 1 HOUR PLEASEEEEEEEEEE thank you so much to who ever answers this YOU ARE THE BESTTTTTTT
Answer:
9000
Step-by-step explanation:
the inital ammout which is 9k is the size of the loan
-200 because he years 200 dollars per month
but the start up number is 9000 and he repays the load at 200 dollars a month
PLEASE HELPPPPPP 65 points
Answer:
x + 2y ≤ 12
x + 2y = 12
Step-by-step explanation:
The teachers can not give more than 12 hours of homework so this is the answer. those are the 2 equations you can use. It under 12 hours or equal to 12 hours.
Answer:
Part A: x + 2y ≤ 12.
Part B: y = -1/2x + 6.
Part C: (0, 0).
Step-by-step explanation:
Part A: The total hours of homework have to be 12 hours, and it has to be either 12 hours or less. So, we have ≤ 12.
They take 1 math course with x hours of homework, so in total, that is 1 * x = x hours of math homework.
They take 2 science courses with y hours of homework, so in total, that is 2 * y = 2y hours of science homework.
The inequality would then be x + 2y ≤ 12.
Part B: x + 2y = 12
2y = -x + 12
y = -1/2x + 6
You can use the Math is Fun: Function Grapher and Calculator to find the graph of the line, shown below.
Part C: Since the inequality uses a ≤ symbol, we know that the shading will be underneath the line. An appropriate point below the line includes (0, 0). We will test out whether it works as a point included in the inequality.
x + 2y ≤ 12
0 + 2 * 0 ≤ 12
0 + 0 ≤ 12
0 ≤ 12
Since this is a true statement, (0, 0) holds true for the inequality.
Hope this helps!
very simple challenge hard question
Answer:
-58.41509433
Step-by-step explanation:
0.4+8(5-0.8*5/8)-5/(2.5)=34.4
[0.4+8(5-4/8)-(2)]=
[0.4+8(40-4)/8)-2=34.4 ( nominator)
15-(8.9-2.6/(2/3))*34*2/5 =-53
15-(8.9-3.9)*68/5
15-5*68/5=
15-68=-53 ( denominator)
(34.4/-53) *90
-58.41509433
Find the missing side length of the right triangle shown. Round to the nearest tenth, if
necessary.
Answer:
? = 26 in
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
?² = 24² + 10² = 576 + 100 = 676 ( take the square root of both sides )
? = [tex]\sqrt{676}[/tex] = 26
Answer:
26 inch
Step-by-step explanation:
unknown side can be found using Pythagorean theorem
a*a+b*b=c*c
24*24+10*10=c*c
576+100=c*c
√676=c
c=26inche
find the value of x and y if the distance of the point (x,y) from (-2,0) and (2,0) are both 14 units.
Answer:
[tex] (0, 8\sqrt{3}) [/tex] and [tex] (0, -8\sqrt{3}) [/tex] are both 14 units from points (-2, 0) and (2, 0).
Step-by-step explanation:
distance formula
[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
We want the distance, d, from points (-2, 0) and (2, 0) to be 14.
Point (-2, 0):
[tex] 14 = \sqrt{(x - (-2))^2 + (y - 0)^2} [/tex]
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
Point (2, 0):
[tex] 14 = \sqrt{(x - 2)^2 + (y - 0)^2} [/tex]
[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]
We have a system of equations:
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{(x - 2)^2 + y^2} = 14 [/tex]
Since the right sides of both equations are equal, we set the left sides equal.
[tex] \sqrt{(x + 2)^2 + y^2} = \sqrt{(x - 2)^2 + y^2} [/tex]
Square both sides:
[tex] (x + 2)^2 + y^2 = (x - 2)^2 + y^2 [/tex]
Square the binomials and combine like terms.
[tex] x^2 + 4x + 4 + y^2 = x^2 - 4x + 4 + y^2 [/tex]
[tex] 4x = -4x [/tex]
[tex] 8x = 0 [/tex]
[tex] x = 0 [/tex]
Now we substitute x = 0 in the first equation of the system of equations:
[tex] \sqrt{(x + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{(0 + 2)^2 + y^2} = 14 [/tex]
[tex] \sqrt{4 + y^2} = 14 [/tex]
Square both sides.
[tex] y^2 + 4 = 196 [/tex]
[tex] y^2 = 192 [/tex]
[tex] y = \pm \sqrt{192} [/tex]
[tex] y = \pm \sqrt{64 \times 3} [/tex]
[tex] y = \pm 8\sqrt{3} [/tex]
The points are:
[tex] (0, 8\sqrt{3}) [/tex] and [tex] (0, -8\sqrt{3}) [/tex]
which of the following is equivalent to (x+4)(3x^2+2x)??
Answer:
c
Step-by-step explanation:
which answer is equivalent to √16/√49
Answer:
sqroot 16/49 A
Step-by-step explanation:
The expression [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] is equivalent to expression [tex]\sqrt{\frac{16}{49}}[/tex] because by property [tex]\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b} }[/tex].
The expression [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] can be simplified by taking the square root of 16 and the square root of 49 separately.
√16 equals 4 because the square root of 16 is the number that, when multiplied by itself, gives 16.
Similarly, √49 equals 7 because the square root of 49 is the number that, when multiplied by itself, gives 49.
So, the expression [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] simplifies to 4/7.
and we know that [tex]\frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b} }[/tex]
[tex]\sqrt{\frac{16}{49}}[/tex] is equivalent to [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] , which simplifies to 4/7.
Therefore, [tex]\sqrt{\frac{16}{49}}[/tex] is equivalent to [tex]\frac{\sqrt{16}}{\sqrt{49}}[/tex] .
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Can somebody please help? i need to graph the piecewise function. i won't forget to give brainliest.
Answer: see graph (attached)
Step-by-step explanation:
Plot coordinates for each line. You MUST include the boundary points.
y = 3x - 5 x ≤ 1
Choose x = -2, then y = 3(-2) - 5 = -11
Must include x = -1, then y = 3(-1) - 5 = -8
Draw a line starting at (-1, -8) and passing through (-2, -11)
y = -2x + 3 -1 < x < 4
Must include x = -1, then y = -2(-1) + 3 = 5
Must include x = 4, then y = -2(4) + 3 = -5
Draw a line segment starting at (-1, 5) and ending at (4, -5).
Note that both are strictly less than so must have open dots.
y = 2 x ≥ 4
Must include x = 4, then y = 2
Choose x = 5, then y = 2
Draw a line starting at (4, 2) and passing through (5, 2)
Please answer this in two minutes
Answer:
x ≈ 5.7
Step-by-step explanation:
Using the Sine rule in Δ WXY
[tex]\frac{WY}{sinX}[/tex] = [tex]\frac{XY}{sinW}[/tex] , substitute values
[tex]\frac{x}{sin33}[/tex] = [tex]\frac{10}{sin107}[/tex] ( cross- multiply )
x sin107° = 10 sin33° ( divide both sides by sin107° )
x = [tex]\frac{10sin33}{sin107}[/tex] ≈ 5.7 ( to the nearest tenth )
Eiko is wearing a magic ring that increases the power of her healing spell by 30\%30%30, percent. Without the ring, her healing spell restores HHH health points. Which of the following expressions could represent how many health points the spell restores when Eiko is wearing the magic ring?
Answer:
Options B: and C:
Step-by-step explanation:
Remember that 30% in fraction form is
The amount of health points (H) restored would depend on the amount of the current H so it means it would add 30% of the current which we can write as:
And since it would add that to the current total we can right the current total as:
So our equation would be:
For option B:
We can factor out the H and you will be left with:
Combine or add the fractions inside the parenthesis and you will have:
For option C:
We can simplify the fractions which will result in:
Then factor out the H and you will have:
Options B: and C:
Step-by-step explanation:
Remember that 30% in fraction form is
The amount of health points (H) restored would depend on the amount of the current H so it means it would add 30% of the current which we can write as:
And since it would add that to the current total we can right the current total as:
So our equation would be:
For option B:
We can factor out the H and you will be left with:
Combine or add the fractions inside the parenthesis and you will have:
For option C:
We can simplify the fractions which will result in:
Then factor out the H and you will have:
HOPE I HELPED
PLS MARK BRAINLIEST
DESPERATELY TRYING TO LEVEL UP
✌ -ZYLYNN JADE ARDENNE
JUST A RANDOM GIRL WANTING TO HELP PEOPLE!
PEACE!
Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and the other is quadratic–without graphing the system of equations.
Answer:
To determine the number of real number solutions of as system of equations in which one equation is linear and the other is quadratic
1) Given that there are two variables, x and y as an example, we make y the subject of the equation of the linear equation and substitute the the expression for y in x into the quadratic equation
We simplify and check the number of real roots with the quadratic formula, [tex]x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}[/tex] for quadratic equations the form 0 = a·x² - b·x + c
Where b² > 4·a·c there are two possible solutions and when b² = 4·a·c equation there is only one solution.
Step-by-step explanation:
Answer:
Isolate one variable in the system of equations. Use substitution to create a one-variable equation. Then, set the quadratic equation equal to zero and find the discriminant. If the discriminant is negative, then there are no real number solutions. If the discriminant is zero, then there is one real number solution. If the discriminant is positive, then there are two real number solutions.
Step-by-step explanation:
I just took the test on Edge 2020
plzzzz answer right away will mark BRAINLIST AND FIVE STARS PLUS The table below shows the possible outcomes of rolling a six-sided number cube and flipping a coin. A 7-column table with 2 rows. Column 1 has entries H, T. Column 2 is labeled 1 with entries H 1, T 1. Column 3 is labeled 2 with entries H 2, T 2. Column 4 is labeled 3 with entries H 3, T 3. Column 5 is labeled 4 with entries H 4, T 4. Column 6 is labeled 5 with entries H 5, T 5. Column 7 is labeled 6 with entries H 6, T 6. What is the probability of getting a number less than 3 and a tails? StartFraction 1 over 12 EndFraction StartFraction 1 over 6 EndFraction One-fourth One-third
Answer:
P((1 or 2) and Tail) = 1/6 = StartFraction 1 over 6
Step-by-step explanation:
A six-sided die and a coin.
Probability of getting <3 and tail.
P((1 or 2) and Tail)
= 2/6 * 1/2
= 1/6
Answer:
1/6
Step-by-step explanation:
This is used for the next few questions: The rating for the new scary movie has a scale of 0 to 10. The average response was that the regular movie attendant enjoyed the movie with 8.3 points and a standard deviation of 0.5 points. What is the percent of people who gave the movie a rating between 6.8 and 8.8? (Write the number as a percent only without a percent sign.)
Answer:
The percentage that of people who gave the movie a rating between 6.8 and 8.8
P(6.8≤X≤8.8) = 83.9≅ 84 percentage
Step-by-step explanation:
Step(i):-
Mean of the Population = 8.3 points
Standard deviation of the Population = 0.5 points
Let 'X' be the random variable in normal distribution
Let X = 6.8
[tex]Z = \frac{x-mean}{S.D} = \frac{6.8-8.3}{0.5} = -3[/tex]
Let X = 8.8
[tex]Z = \frac{x-mean}{S.D} = \frac{8.8-8.3}{0.5} = 1[/tex]
The probability that of people who gave the movie a rating between 6.8 and 8.8
P(6.8≤X≤8.8) = P(-3≤Z≤1)
= P(Z≤1)- P(Z≤-3)
= 0.5 + A(1) - ( 0.5 -A(-3))
= A(1) + A(3) (∵A(-3)=A(3)
= 0.3413 +0.4986 (∵ From Normal table)
= 0.8399
Conclusion:-
The percentage that of people who gave the movie a rating between 6.8 and 8.8
P(6.8≤X≤8.8) = 83.9≅ 84 percentage
-1+(4+7)=(-1+4)+7 what property is this
Answer:
Associative Property.
Step-by-step explanation:
The Associative Property is the property that says that (a + b) + c = a + (b + c).
Hope this helps!
Answer:
Associate Property
Step-by-step explanation:
I found my answer at baba com
The roots of $7x^2 + x - 5 = 0$ are $a$ and $b.$ Compute $(a - 4)(b - 4).$[tex]The roots of $7x^2 + x - 5 = 0$ are $a$ and $b.$ Compute $(a - 4)(b - 4).$[/tex]
Using the factor theorem, we have
[tex]7x^2+x-5=7(x-a)(x-b)[/tex]
and expanding gives us
[tex]7x^2+x-5=7(x^2-(a+b)x+ab)\implies\begin{cases}ab=-5\\a+b=-1\end{cases}[/tex]
So we have
[tex](a-4)(b-4)=ab-4(a+b)+16=-5-4(-1)+16=\boxed{15}[/tex]
Find the perimeter of a square with a diagonal of 15√2.
Answer:
15
Step-by-step explanation:
Answer:
21.213
Step-by-step explanation:
A sphere and a cylinder have the same radius and height. The volume of the cylinder is 50 feet cubed. A cylinder with height h and radius r. A cylinder with height h and radius r. What is the volume of the sphere?
Answer:
Volume of the sphere is 66.67r/h
Step-by-step explanation:
Hello,
Volume of a sphere = ⁴/₃πr³
Volume of a cylinder = πr²h
The volume of the cylinder = 50ft³
But the cylinder and sphere both have the same radius and height
Volume of a cylinder = πr²h
50 = πr²h
Make r² the subject of formula
r² = 50/πh
Volume of a sphere = ⁴/₃πr³
Put r² into the volume of a sphere
Volume of a sphere = ⁴/₃π(50/πh)r
Volume of a sphere = ⁴/₃ × 50r/h
Volume of a sphere = ²⁰⁰/₃ r/h
Volume of a sphere = 66.67r/h
The volume of the sphere is 66.67r/h
Find the vertex of the graph
Answer:
(-3, -11)
i needed to put more characters so here
1. an alloy contains zinc and copper in the ratio of 7:9 find weight of copper of it had 31.5 kgs of zinc.
2. compare the following ratios
i) 2:3 and 4:5
ii) 11:19 and 19:21
iii) ½ : ⅓ and ⅓ : ¼
iv ) 1⅕ : 1⅓ and ⅖ : 3/2
v) if a : b = 6:5 and b:c = 10:9, find a:c
vi) if x : y = ⅙:⅛ and y : z = ⅛: ⅒, find X : z
sorry many questions
Answer:
Step-by-step explanation:
Question (1). An alloy contains zinc and copper in the ratio of 7 : 9.
If the weight of an alloy = x kgs
Then weight of copper = [tex]\frac{9}{7+9}\times (x)[/tex]
= [tex]\frac{9}{16}\times (x)[/tex]
And the weight of zinc = [tex]\frac{7}{7+9}\times (x)[/tex]
= [tex]\frac{7}{16}\times (x)[/tex]
If the weight of zinc = 31.5 kg
31.5 = [tex]\frac{7}{16}\times (x)[/tex]
x = [tex]\frac{16\times 31.5}{7}[/tex]
x = 72 kgs
Therefore, weight of copper = [tex]\frac{9}{16}\times (72)[/tex]
= 40.5 kgs
2). i). 2 : 3 = [tex]\frac{2}{3}[/tex]
4 : 5 = [tex]\frac{4}{5}[/tex]
Now we will equalize the denominators of each fraction to compare the ratios.
[tex]\frac{2}{3}\times \frac{5}{5}[/tex] = [tex]\frac{10}{15}[/tex]
[tex]\frac{4}{5}\times \frac{3}{3}=\frac{12}{15}[/tex]
Since, [tex]\frac{12}{15}>\frac{10}{15}[/tex]
Therefore, 4 : 5 > 2 : 3
ii). 11 : 19 = [tex]\frac{11}{19}[/tex]
19 : 21 = [tex]\frac{19}{21}[/tex]
By equalizing denominators of the given fractions,
[tex]\frac{11}{19}\times \frac{21}{21}=\frac{231}{399}[/tex]
And [tex]\frac{19}{21}\times \frac{19}{19}=\frac{361}{399}[/tex]
Since, [tex]\frac{361}{399}>\frac{231}{399}[/tex]
Therefore, 19 : 21 > 11 : 19
iii). [tex]\frac{1}{2}:\frac{1}{3}=\frac{1}{2}\times \frac{3}{1}[/tex]
[tex]=\frac{3}{2}[/tex]
[tex]\frac{1}{3}:\frac{1}{4}=\frac{1}{3}\times \frac{4}{1}[/tex]
= [tex]\frac{4}{3}[/tex]
Now we equalize the denominators of the fractions,
[tex]\frac{3}{2}\times \frac{3}{3}=\frac{9}{6}[/tex]
And [tex]\frac{4}{3}\times \frac{2}{2}=\frac{8}{6}[/tex]
Since [tex]\frac{9}{6}>\frac{8}{6}[/tex]
Therefore, [tex]\frac{1}{2}:\frac{1}{3}>\frac{1}{3}:\frac{1}{4}[/tex] will be the answer.
IV). [tex]1\frac{1}{5}:1\frac{1}{3}=\frac{6}{5}:\frac{4}{3}[/tex]
[tex]=\frac{6}{5}\times \frac{3}{4}[/tex]
[tex]=\frac{18}{20}[/tex]
[tex]=\frac{9}{10}[/tex]
Similarly, [tex]\frac{2}{5}:\frac{3}{2}=\frac{2}{5}\times \frac{2}{3}[/tex]
[tex]=\frac{4}{15}[/tex]
By equalizing the denominators,
[tex]\frac{9}{10}\times \frac{30}{30}=\frac{270}{300}[/tex]
Similarly, [tex]\frac{4}{15}\times \frac{20}{20}=\frac{80}{300}[/tex]
Since [tex]\frac{270}{300}>\frac{80}{300}[/tex]
Therefore, [tex]1\frac{1}{5}:1\frac{1}{3}>\frac{2}{5}:\frac{3}{2}[/tex]
V). If a : b = 6 : 5
[tex]\frac{a}{b}=\frac{6}{5}[/tex]
[tex]=\frac{6}{5}\times \frac{2}{2}[/tex]
[tex]=\frac{12}{10}[/tex]
And b : c = 10 : 9
[tex]\frac{b}{c}=\frac{10}{9}[/tex]
Since a : b = 12 : 10
And b : c = 10 : 9
Since b = 10 is common in both the ratios,
Therefore, combined form of the ratios will be,
a : b : c = 12 : 10 : 9
By visual inspection, determine the best-fitting regression model for the
scatterplot.
Need help ASAP please
Answer:
its a! sorry im so late
Step-by-step explanation:
The path followed by a roller coaster as it climbs up and descends down from a peak can be modeled by a quadratic function, where h(x) is the height, in feet, and x is the horizontal distance, also in feet. The path begins and ends at the same height, covers a total horizontal distance of 100 feet, and reaches a maximum height of 250 feet. Which of the functions could be used to model this situation? A. h(x)=-0.1x^2-50x+250 B. h(x)=-0.1(x-50)^2+250 C. h(x)=-0.1(x-100)^2+250 D. h(x)=-0.1x^2+100x+250
Answer:
C
Step-by-step explanation:
0.1(x - 100)² + 250
0.1[(x - 100)(x - 100)] + 250
0.1(x² -200x + 10000) + 250
0.1x² - 20x + 1000 + 250
0.1x² - 20x + 1250
0.1x² - 25x + 5x + 1250
0.1x(x - 250) + 5(x + 250)
∴ (0.1x + 5)(x - 250) or (0.1x + 5)(x + 250)
DatGuy! Sekkrit! Wishing! Anyone? Find the discriminant of 3x²+5x-2 = 0
Answer:
49
Step-by-step explanation:
[tex]3x^2+5x-2 = 0[/tex]
Apply discriminant formula : [tex]D = b^2- 4ac[/tex]
[tex]D=discriminant\\b=5\\a=3\\c=-2[/tex]
[tex]D = b^2- 4ac[/tex]
Plug in the values for a, b, and c.
[tex]D = 5^2- 4(3)(-2)[/tex]
Evaluate.
[tex]D = 25- 12(-2)[/tex]
[tex]D = 25- - 24[/tex]
[tex]D=25+24[/tex]
[tex]D=49[/tex]
Answer:
49
Step-by-step explanation:
3x²+5x-2 = 0
This is in the form
ax^2 + bx + c=0
a=3 b=5 c = -2
The discriminant is
b^2 -4ac
5^2 -4(3) (-2)
25 + 24
49
The discriminant is 49
Clinical Trial When XELJANZ (tofacitinib) was administered as part of a clinical trial for this rheumatoid arthritis treatment, 1336 subjects were given 5 mg doses of the drug, and here are the numbers of adverse reactions: 57 had headaches, 21 had hypertension, 60 had upper respiratory tract infections, 51 had nasopharyngitis, and 53 had diarrhea. Does any one of these adverse reactions appear to be much more common than the others? (Hint: Find the relative frequencies using only the adverse reactions, not the total number of treated subjects.)
Answer:
Relative frequencies:
Headaches = 23.55 %
Hypertension = 8.68%
Upper respiratory tract infections =24.79%
Nasopharyngitis = 21.07
Diarrhea = 21.09%
None of these adverse reactions appear to be much more common than the others.
Step-by-step explanation:
Compute frequency:
The number of adverse reactions categories:
Headaches
Hypertension
Upper respiratory tract infections
Nasopharyngitis
Diarrhea
Frequency of each adverse reaction:
Adverse reaction Frequency
Headaches 57
Hypertension 21
Upper respiratory tract infections 60
Nasopharyngitis 51
Diarrhea 53
Compute total frequency
Total frequency is compute dby taking sum of all frequencies;
Sum of frequencies = 57 + 21 + 60 + 51 + 53
= 242
Compute relative frequency:
In order to find if any one of these adverse reactions appear to be much more common than the others, we have to compute relative frequency using these adverse reactions.
By calculating relative frequency we are looking at the number of times a specific adverse reaction appears to be more common, compared to the others.
To calculate relative frequency, divide the frequency of each adverse reaction by the total frequency i.e. 242.
Relative frequency for Headache = 57 / 242
= 0.2355
= 23.55 %
Relative frequency for Hypertension = 21 / 242
= 0.0868
= 8.68 %
Relative frequency for Upper respiratory tract infections = 60 / 242
= 0.2497
= 24.97 %
Relative frequency for Nasopharyngitis = 51 / 242
= 0.2107
= 21.07 %
Relative frequency for Diarrhea = 53 / 242
= 0.2190
= 21.90 %
If you observe the relative frequencies of all the adverse reactions, none of them appear to be much more common than the others. Relative frequencies of headaches, upper respiratory tract infections, nasopharyngitis and diarrhea are almost equally common however, relative of hypertension appears to be very less than the other three.
How does the graph of y = a(x – h)2 + k change if the value of h is doubled? The vertex of the graph moves to a point twice as far from the x-axis. The vertex of the graph moves to a point twice as far from the y-axis. The vertex of the graph moves to a point half as far from the x-axis. The vertex of the graph moves to a point half as far from the y-axis.
Answer:
The vertex of the graph moves to a point twice as far from the y-axis.
Step-by-step explanation:
How does the graph of y = a(x – h)2 + k change if the value of h is doubled?
The vertex of the graph moves to a point twice as far from the x-axis.
The vertex of the graph moves to a point twice as far from the y-axis.because the role of h is to indicate the distance of the vertex from the y-axis.
The vertex of the graph moves to a point half as far from the x-axis.
The vertex of the graph moves to a point half as far from the y-axis.
Transformation involves changing the position of a function.
When h is doubled in [tex]\mathbf{y = a(x - h)^2 + k}[/tex], the vertex of the graph moves to a point twice as far from the y-axis.
The function is given as:
[tex]\mathbf{y = a(x - h)^2 + k}[/tex]
When the value of h is doubled, the new function becomes:
[tex]\mathbf{y' = a(x - 2h)^2 + k}[/tex]
Rewrite as:
[tex]\mathbf{y' = a(x - h- h)^2 + k}[/tex]
The above equation means that:
Function y will be translated to the right by h units
Assume the vertex is:
[tex]\mathbf{Vertex = (2,5)}[/tex]
The new vertex will be:
[tex]\mathbf{Vertex = (4,5)}[/tex]
Comparing the vertices, it means that:
The new function will have its vertex twice as far from the y-axis
Hence, option (b) is correct.
Read more about transformation at:
https://brainly.com/question/13801312
What is the simplified form of the following expression?
[tex]2 (\sqrt[4]{16x}) - 2 (\sqrt[4]{2y} ) + 3 (\sqrt[4]{81x} ) - 4 (\sqrt[4]{32y} )[/tex]
We have
[tex]16=2^4\implies\sqrt[4]{16}=2[/tex]
[tex]81=3^4\implies\sqrt[4]{81}=3[/tex]
[tex]32=2^5\implies\sqrt[4]{32}=2\sqrt[4]{2}[/tex]
So
[tex]2\sqrt[4]{16x}-2\sqrt[4]{2y}+3\sqrt[4]{81x}-4\sqrt[4]{32y}[/tex]
is equivalent to
[tex]2^2\sqrt[4]{x}-2\sqrt[4]{2y}+3^2\sqrt[4]{x}-8\sqrt[4]{2y}[/tex]
which reduces to
[tex]13\sqrt[4]{x}-10\sqrt[4]{2y}[/tex]
For f(x) = 2x + 1 and g(x) = x2 – 7, find (f – g)(x).
Answer:
-x^2 +2x +8
Step-by-step explanation:
f(x) = 2x + 1
g(x) = x^2 – 7,
(f – g)(x) = 2x +1 - ( x^2 -7)
Distribute the minus sign
= 2x+1 - x^2 +7
Combine like terms
= -x^2 +2x +8
Answer:
its not true. Answer is (f + g)(x) = x2 + 2x - 6
Step-by-step explanation:
Trust me. Good luck.
Find the value of x.
08*
ος
Ο Α. 58ο
Ο Ο Ο
Ο Β. 32ο
C. 669
D. 68ο
Answer:
x = 66°
Step-by-step explanation:
Hello,
This question involves use of rules or theorems of angles in a right angled triangle
<DAB + <BAC = 180°
Sum of angles on a straight line = 180°
98° + <BAC = 180°
<BAC = 180° - 98°
<BAC = 82°
Now, we can use <BAC to find x because some of angles in a triangle is equal to 180°
32° + 82° + x = 180°
Sum of angles in a triangle = 180°
114° + x = 180°
x = 180° - 114°
x = 66°
Angle x = 66°