Select all the words that describe what the elements have in common if they are located on the same PERIOD.

Orbitals
Rounds
Shells
Dots
Energy Levels
Circles

Answers

Answer 1

Answer:

Orbitals

Shells

Energy Levels

Explanation:

Elements in the same period will have the same energy levels which is the same as orbitals and shells.

The period of an element indicates the energy level in an atom. Elements in period 1 will have one energy level or shell or orbitals. Down a group this is not the case. The energy level increases from top to bottom. As we go down the group, we are transiting from one period to another.

Related Questions

In order for photosynthesis to take place
what must be present?

Answers

Answer:

For photosynthesis to take place, plants need to take in carbon dioxide (from the air), water (from the ground) and light (usually from the sun)

Explanation:

Answer:

water carbon dioxide sunlight and the plant

Explanation:

Reactant A illustrates an example of which of the following?

Answers

Answer: molecules of an element

The diagram shown in the A section shows molecules of an element because they all look the same, and they are in circular shape.

- Best of Luck!

The ratio of effusion ratios between He(g) and SF6(g) is

Answers

rate He = 6 x rate SF₆

Further explanation  

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

[tex]\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }[/tex]

or  

[tex]\rm M_1\times r_1^2=M_2\times r_2^2[/tex]

M He = 4 g/mol

M SF₆ = 146 g/mol

[tex]\tt \dfrac{r_{He}}{r_{SF_6}}=\sqrt{\dfrac{146}{4} }=6.04\approx 6\\\\r_{He}=6~r_{SF_6}[/tex]

For a substance to change phases, the amount of internal energy must change. Water exists in three phases: liquid, solid (ice), and gas (water vapor) Which of the following lists the phases in order of increasing total energ/?
gas, liquid, solid
O solid, gas, liquid
o solid, liquid, gas
O liquid, gas, solid

Answers

Answer:

Solid, liquid, gas

Explanation:

add thermal energy to solid and it becomes liquid, add thermal energy to liquid it becomes gas

why sulphur dichloride has higher boiling point than sulphur hexafluoride?​

Answers

Explanation:

Sulphur dichloride has higher boiling point as compare to sulphur hexafluoride because

Sulphur dichloride has stronger intermolecular forces among the molecules and sulphur hexafluoride has weaker intermolecular forces among molecules.

Stronger the intermolecular forces higher the boiling point that the reason sulphur dichloride has a higher boiling point than the sulphur hexafluoride.


What are the oxidation states of the atoms in a diatomic gas?

Answers

it's d

o3o

(sorry still typing because I need 20 characters to submit this)

When 100.0 mL of 1.000 M HCl is reacted with 100.0 mL of 1.000 M NH4OH, the solution’s temperature increases 7.01 °C. Calculate LaTeX: \DeltaΔHreaction in units of kJ/mol. The specific heat of the salt solution is 4.184 J/g-°C and the density is 1.010 g/mL.

Do not use units or labels in answer. Make sure answer has the correct sig figs.

Answers

Answer:

Explanation:

volume of solution = 100 + 100 = 200 mL

mass of reaction mixture = 200 x 1.010 = 202 g

specific heat of solution mixture = 4.184 J/g-°C

heat evolved = mass x specific heat x rise in temperature

= 202 x 4.184 x 7.01

= 5924.63 J

100 mL of 1 M HCl

= .1 L of 1M HCl will contain .1 mole of HCl

.1 mole reacts with .1 mole of NH₄OH to make 5924.63 J of heat

1 mole reacts with 1 mole of NH₄OH to make 59246.3 J of heat

heat of reaction = 59246.3 J / mol

= 59.246 kJ / mol

= 59.3 kJ / mol .

Name the following compounds

Answers

Answer:

What are the compounds

Explanation:

Answer:

Where is the picture?

Explanation:

what is an advantage of power plants powered by natural gas when compared to coal and oil​

Answers

Natural gas is a fossil fuel, though the global warming emissions from its combustion are much lower than those from coal or oil. Natural gas emits 50 to 60 percent less carbon dioxide (CO2) when combusted in a new, efficient natural gas power plant compared with emissions from a typical new coal plant

how do the properties of alloys compare to the properties of the materials used to form them?

Answers

Answer:

An alloy is a mixture or metallic-solid solution composed of two or more elements. Examples of alloys include materials such as brass, pewter, phosphor bronze, amalgam, and steel. Complete solid solution alloys give single solid phase microstructure. Partial solutions give two or more phases that may or may not be homogeneous in distribution, depending on thermal history. An alloy’s properties are usually different from those of its component elements.

Examples of alloys include materials such as brass, pewter, phosphor bronze, amalgam, and steel. Complete solid solution alloys give single solid phase microstructure. Partial solutions give two or more phases that may or may not be homogeneous in distribution, depending on thermal history. An alloy’s properties are usually different from those of its component elements.

image

Steel: Steel is an alloy whose major component is iron.

Alloy constituents are usually measured by mass. An alloy is usually classified as either substitutional or interstitial, depending on its atomic arrangement. In a substitutional alloy, the atoms from each element can occupy the same sites as their counterpart. In interstitial alloys, the atoms do not occupy the same sites. Alloys can be further classified as homogeneous (consisting of a single phase), heterogeneous (consisting of two or more phases), or intermetallic (where there is no distinct boundary between phases).

Alloying a metal involves combining it with one or more other metals or non-metals, which often enhances its properties. For example, steel is stronger than iron, its primary element. Physical properties (density, reactivity, conductivity) of an alloy may not differ greatly from those of its constituent elements, but its engineering properties (tensile strength and shear strength) may be substantially different.

Explanation:

An isotope has three forms. 30% have a mass of 15 amu, 20% have a mass of 16 amu and 50% have a mass of 17 amu. What is the average atomic
mass of this element?
a. 15.8 amu
b. 16.0 amu
c. 16.2 amu
d. 16.4 amu

Answers

Answer:

Explanation:

a

Give reasons.
a.Steel is an alloy.
b.Sodium is a metal.

Answers

Answer:

steel is an alloy because steel when other elements comprising metals and nonmetals are added to Carbon steel , alloy steel is formed.Sodium is a metal because it is highly reactive metal.it is the member of alkali metal family about the periodic table .it has one electron in the outermost electron shell.

Explanation:

Hope it's help !

A chemical compound has a molecular weight of 89.05 g/mole. 1.400 grams of this compound underwent complete combustion under constant pressure conditions in a special calorimeter. This calorimeter had a heat capacity of 2980 J °C.1 (Note that the calorimeter was made of a metal shell, a water "substitute" - a special oil, and a thermocouple). The temperature went up by 11.95 degrees.

Required:
Calculate the molar heat of combustion of the compound.

Answers

Answer:

[tex]\Delta _{comb}H=-2,265\frac{kJ}{mol}[/tex]

Explanation:

Hello!

In this case, for such calorimetry problem, we can notice that the combustion of the compound releases the heat which causes the increase of the temperature by 11.95 °C, it means that we can write:

[tex]Q _{comb}=-C_{calorimeter}\Delta T_{calorimeter}[/tex]

In such a way, we can compute the total released heat due to the combustion considering the calorimeter specific heat and the temperature raise:

[tex]Q _{comb}=-2980\frac{J}{\°C} *11.95\°C\\\\Q _{comb}=-35,611J[/tex]

Next, we compute the molar heat of combustion of the compound by dividing by the moles, considering 1.400 g were combusted:

[tex]n=1.400g*\frac{1mol}{89.05g} =0.01572mol[/tex]

Thus, we obtain:

[tex]\Delta _{comb}H=\frac{Q_{comb}}{n}=\frac{-35,611J}{0.01572mol} \\\\\Delta _{comb}H=-2,265,331\frac{J}{mol}*\frac{1kJ}{1000J} \\\\\Delta _{comb}H=-2,265\frac{kJ}{mol}[/tex]

Best regards!

Roger has a car that accelerates at 5 m/s2. If the car has a mass 0f 1000 kg, how much force does the car produce?

Answers

Answer:

The answer is 5000 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 1000 × 5

We have the final answer as

5000 N

Hope this helps you

Answer:

5OOON

Explanation:

IM SMARTTT

What process that occurred in the Midwestern United States in the 1930s is now occurring in the Sahel region of Africa, south of the Sahara Desert?


Industrial pollution

Radioactive soil

Over fertilization of streams

Dust storms and desertification

Answers

Answer:

dust storms and desertification

Explanation:

Answer:

Dust storms and desertification

Explanation:

i need help with this

Answers

Answer: B

Explanation: Most of the time they form over oceans which bring cool and moist weather.

What is the limiting reagent when a 2.00 g sample of ammonia is mixed with 4.00 g of oxygen?​

Answers

Answer:

Ammonia is limiting reactant

Amount of oxygen left  = 0.035 mol

Explanation:

Masa of ammonia = 2.00 g

Mass of oxygen = 4.00 g

Which is limiting reactant = ?

Balance chemical equation:

4NH₃ + 3O₂     →     2N₂ + 6H₂O

Number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 2.00 g/ 17 g/mol

Number of moles = 0.12 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 4.00 g/ 32 g/mol

Number of moles = 0.125 mol

Now we will compare the moles of ammonia and oxygen with water and nitrogen.

                      NH₃          :            N₂

                        4             :             2

                      0.12           :           2/4×0.12 = 0.06

                      NH₃         :            H₂O

                        4            :             6

                        0.12       :           6/4×0.12 = 0.18

                       

                       O₂            :            N₂

                        3             :             2

                      0.125        :           2/3×0.125 = 0.08

                        O₂           :            H₂O

                        3              :             6

                        0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                        NH₃          :             O₂

                           4            :              3

                           0.12       :          3/4×0.12= 0.09

Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

A sample of 18.0 g of O2 has a temperature of 350 K, and pressure of 0.720 atm. What is the volume of the sample?

Answers

Answer:

V = 22.36 L

Explanation:

Given data:

Mass of oxygen = 18.0 g

Temperature = 350 K

Pressure = 0.720 atm

Volume of gas = ?

Solution:

Number of moles of oxygen :

Number of moles = mass/molar mass

Number of moles = 18.0 g/ 32 g/mol

Number of moles = 0.56 mol

Volume of oxygen:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

0.720 atm × V =  0.56 mol × 0.0821 atm.L/ mol.K   × 350 K

V = 16.1 atm.L /0.720 atm

V = 22.36 L

equation for the oxidation of octane.

Answers

Answer:

I think its 2 C8H18 + 25 O2 = 18 H2O + 16 CO2

Im not sure!

Explanation:

Help Plz 20 points -------------

Answers

Answer:

B

Explanation:

Compounds are made up of 2 or more different atoms that bond to form a compound.

ALL OF THEMMMMM


:))))

1) Describe the appearance of each of the three curves on your graph.

Answers

Answer:PROCESSING THE DATA To analyze the relationship between conductivity and volume, use this method to calculate the linear-regression statistics for your data. Then plot the linear regression curve on your graph. Note the conductivity of pure water: 0 uS/cm Conductivity Data Table Drops 1M NaCl(aq) 1M CaCl2(ag) (uS/cm) (uS/cm) 1 150 uS/cm 110 uS/cm 2 280 uS/cm 155 uS/cm 405 uS/cm 245 uS/cm 4 516 uS/cm 340 uS/cm 3 Use 1 mL = 20 drops to Plot Conductivity (in the y axis) vs. volume of each salt solution (x axis). Do a best fit straight line through these points. Make sure to use the pure water conductivity as your zero drop. On this same graph determine the slope for both the NaCl and CaCl2, make sure to use pure water as your 0 drop. Sketch your prediction of what you would expect the AlCl3 drops to look like.

Explanation:

Suppose 215 g of NO3- flows into a swamp each day. What volume of CO2 would be produced each day at 17.0°C and 1.00 atm?

Answers

Answer:

The answer is "[tex]41.23 \ L\ N_2[/tex]"

Explanation:

[tex]2 NO_3^{-} + 10 e^{-} + 12 H^{+} \longrightarrow N_2 + 6 H_2O\\\\= \frac{( 215 \ g \ NO_3^{-})}{(62.0049 \frac{\ g NO_3^{-}}{mol})} \times \frac{(1 \ mol \ N_2}{ 2 \ mol \ NO_3^{-})}\\\\[/tex]

[tex]=3.46746789 \times 0.5\\\\= 1.733 \ mol \ N_2 \\\\\to V = \frac{nRT}{P} \\\\= (1.733 \ mol) \times (0.08205746 \frac{L\ atm}{Kmol}) \times \frac{ (17 + 273) K}{(1.00 atm)}\\\\= 41.23[/tex]

The volume of CO2 is 206.27 L

The ideal gas equation is used to determine the volume, pressure, temperature, or number of moles. It can be mathematically expressed as:

PV = nRT

From the given information:

The equation for the reaction can be expressed as:

[tex]\mathbf{2NO_3^-_{(aq)} + 5CO_{(g)} + 2H^+_{(aq)} \to N_2{(g)} + 5CO_2_{(g)} + H_2O_{(l)}}[/tex]

The mass of NO₃⁻ = 215 gThe temperature = 17.0°C = (273 + 17) = 290 KPressure = 1.00 atm

The number of moles of CO2 from the reaction is;

[tex]\mathbf{= \dfrac{215 \ g}{62.0049} \times \dfrac{5 \ mol \ of \ CO_2}{2 \ mol \ of \ NO_3^-} }[/tex]

[tex]\mathbf{= 8.669 \ moles \ of \ CO_2 }[/tex]

From ideal gas, by making the volume the subject of the, we have:

The volume of CO₂ [tex]\mathbf{V= \dfrac{nRT}{P}}[/tex]

[tex]\mathbf{V= \dfrac{8.669 \ moles \times 0.08205 L atm/ kmol \times 290\ K}{1 \ atm }}[/tex]

[tex]\mathbf{V= 206.27 \ L \ of \ CO_2 \ gas}[/tex]

Learn more about the volume of CO2 gas here 206.27 L

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The average titration volume of the 0.09876 M NaOH used in back titration is 29.59
ml. Calculate the number of mmoles of HCl in the 250 ml volumetric flask.​

Answers

Answer:

The number of moles of HCl in the 250 mL volumetric flask is 0.003 moles

Explanation:

Firstly, we solve for the concentration of acid using the formula

CaVa/CbVb = nₐ/nb

where Ca is the concentration of acid

Cb is the concentration of base

Va is the volume of acid

Vb is the volume of base

nₐ is the number of moles of acid (from the equation)

nb is the number of moles of base (from the equation)

Ca × 250/0.09876 × 29.59 = 1/1

Ca = 0.09876 × 29.59/250

Ca = 0.012 M

To determine the number of moles of HCl acid present in the 250 ml volumetric flask, the formula for molarity is used

Molarity = number of moles ÷ volume (in liter or dm³)

Volume needs to be converted to liter; 250 ml ⇒ 0.25 L

Molarity of the acid is 0.012 M

From the formula above, number of moles = molarity × volume (in liter)

number of moles = 0.012 × 0.25

number of moles of acid = 0.003 moles

The Molar Mass (g/mol) of an ideal gas whose density is 2.5g/L at 1.8 atm and 30,0 Celsius ?
35 g/mol
64 g/mol
44 g/mol
38 g/mol

Answers

Answer:

M = 35 g/mol

Explanation:

Given data:

Density = 2.5 g/L

Pressure = 1.8 atm

Temperature = 30°C (273.15 +30 = 303.15 K)

Molar mass = ?

Solution:

d = PM/RT

M = dRT/P

M =  2.5 g/L × 0.0821 atm.L/mol.K ×  303.15 K / 1.8 atm

M = 62.22 atm. g/mol/ 1.8 atm

M = 35 g/mol

You start with 4800 grams uranium - 238. It's radioactive and goes
through alpha decay. How many grams remain after 7 half-lives.

Answers

Answer:

37.5g

Explanation:

The half-life is the time taken for a radioactive substance to decay to half its original composition;

 Original composition here is  = 4800g  of U-238

How many grams remain after 7 half-lives;

 After each life, the uranium reduces by half;

 Amount remaining  = 4800 x [tex](\frac{1}{2})^7[/tex]  

                                  = 37.5g

After 7 half lives, 37.5g of the original sample will remain.

In a car engine gasoline is burning to create mechanical energy which of the following statements is true? A. Some energy is lost as heat B. the total amount of energy in the system increases C. the total amount of energy in the system degrees D. the nuclear energy is transformed into mechanical energy​

Answers

Answer:

Some energy is lost as heat

Explanation:

It is correct to say that as the gasoline is converted to mechanical energy in the automobile engine, some of the energy is lost as heat.

Heat energy is on of the ways energy is lost in any system. The movement of mechanical parts and even the combustion of the gasoline produces heat energy.

These energy are usually lost to the environment.

1. Which liquid sample is a pure substance?
Table 1: Boning point of the samples
Samples Temperature Observation while heating
Liquid A
Liquid B
2. Which soăc sample is a pure substance?
Scenario 1: Meiting point of the said samples
Samples Appearance Observation while melting
Solid
Solid B

Answers

The whole Activity , poem and paragraph is missing in the question.

Answer:

(1) Liquid A

(2) Solid A

Explanation:

Using this part of the given poem

Substances and mixtures behave differently,

During boiling and melting most especially

Boiling point of substance is fixed while mixture is not

Substance melts completely but mixture does not

The boiling point of the Pure substance remain fixed after reaching its boiling point this is shown by Liquid A

Solid A is melting completely so Solid A is a pure substance.

Electrons _______ around the nucleus of an atom.
Options:
- valence electrons
- atomic number
- atomic mass
- amu - atomic mass unit
- ionization energy
- electronegativity
- ionic bond
- covalent bond
- metallic bond

Answers

Answer:

Orbit/Orbital

Explanation:

Elections orbit around the nucleus of an atom.

Fove seconds without gravity would be detrimental to earth.
A.True
B.False​

Answers

Answer:true

Explanation:

The density of a metal is 11.4 g/cm3. How much volume (in cm3) would a sample of 30.5 g have?

Answers

The Concept:

We are given the density of a sample of the metal = 11.4 grams / cm³

and we need to find the volume occupied by a sample of 30.5 grams

For this solution, we will use dimensional analysis

from the given information, we can also say that the density of the metal is:

1 cm³ / 11.4 grams

If we multiply this value by 30.5 grams, the 'grams' in the numerator and the denominator will cancel out and we will be left with the volume occupied by 30.5 grams of the metal

Solving for the volume:

[tex]\frac{ 1 cm^{3} }{11.4 grams}[/tex]  X  30.5 grams  = (30.5 / 11.4) cm³

Volume of 30.5 grams of the sample = 2.68 cm³

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