Which phase of matter does line segment CD represent?
A. plasma
B. liquid
C. gas
D. solid

alpha is the excess return on an investment after adjusting for market related volatility and random fluctuations.

beta is a measure of volatility relative to a benchmark ,such as the S&P 500.

Explanation:

alpha and beta are two different parts of an equation used to explain the performance of stocks and investments funds. But in maths alpha and beta is the Greek alphabet

51.448 g is the required answer!

Answer:

Surface tension is the downward force acting on the surface of liquid due to presence of inter molecular forces or cohesive forces between the particles of liquid.

Surface tension decreases with increase in temperature as the forces among particles decrease due to increase in kinetic energy and thus the cohesive nature decreases and thus surface tension also decreases.

Surface tension may decrease or increase with increase in soluble impurities .Insoluble impurities decrease the surface tension.

Answer:

[tex]W=70 * 5cos20 = 328.89 J[/tex]

[tex]W_n = 0[/tex]

[tex]W_g=0[/tex]

[tex]W_f= -184.59J[/tex]

Work done is 0

Explanation:

From the question we are told that

Weight of block =15.0kg

Force acting on the block = 70.0N

At an angle of 20 degree

Displacement of block is 5m

Coefficient of kinetic friction 0.3

b) Generally work done by force is give by [tex]W=fdcos \theta[/tex]

therefore

      [tex]W=70 * 5cos20 = 328.89 J[/tex]

c) there is no work done by the normal force in this scenario because

normal force in this case is perpendicular to the displacement of the motion

       [tex]W_n = 0[/tex]

d) The displacement in the vertical direction is 0

Therefore the gravitational work done is 0  [tex]W_g=0[/tex]

e)Generally in finding work done by friction we first find frictional force

Mathematically the equation for frictional force is given [tex]f = \alpha N[/tex]

Given that

       [tex]N=mg-Fsin20[/tex]

       [tex]N= 15.0*9.8 - 70 sin20[/tex]

       [tex]N=123 N[/tex]

       [tex]f=0.3* 123.06 = 36.92N[/tex]

Mathematically solving to get work done by frictional force [tex]W_f[/tex]

        [tex]W_f= -fd\\W_f = -36.92 * 5[/tex]

         [tex]W_f= -184.59J[/tex]

the frictional force work done is  [tex]W_f= -184.59J[/tex]

Answer:

The torque τ on an electric dipole with dipole moment p in a uniform electric field E is given by τ = p × E where the "X" refers to the vector cross product. Ref: Wikipedia article on electric dipole moment.

Explanation:

Answer:

    [tex]\frac{V}{2av}[/tex]

Explanation:

From the question we are told that

Volume V

Contains N particles

Leaks from a small hole of area A

Generally the equation for Flow rate is given as

Volume Flow Rate  [tex]V_r = A * v[/tex]

Mathematically we find the  time taken to flow half way which is given by

          [tex]\frac{(V/2)}{A*v}[/tex]

Therefore the  time taken is

           [tex]\frac{V}{2av}[/tex]

Answer:

(a) The acceleration is 7.85 m/s²

(b) It takes the car to change speed from 10.0 m / s to 20 m / s in a time of 1.27 seconds.

(c) Doubling the time will double the change in velocity if the acceleration is kept constant.

Explanation:

(a)  Acceleration is the physical quantity that measures the rate of change of velocity with time. That is, acceleration relates changes in speed with the time in which they occur, that is, it measures how fast the changes in speed are.

The average acceleration is calculated using the following expression:

[tex]a=\frac{vf-vi}{t}[/tex]

where a is the acceleration, vf is the final velocity, vi is the initial velocity and t is the time.

In this case:

Replacing:

[tex]a=\frac{20.4 \frac{m}{s} - 0\frac{m}{s} }{2.60 s}[/tex]

a= 7.85 m/s²

The acceleration is 7.85 m/s²

(b) In this case you know:

Replacing:

[tex]7.85 \frac{m}{s^{2} } =\frac{20 \frac{m}{s} - 10\frac{m}{s} }{t}[/tex]

and solving you get:

[tex]t=\frac{20 \frac{m}{s} - 10\frac{m}{s} }{7.85 \frac{m}{s^{2} } }[/tex]

t=1.27 s

It takes the car to change speed from 10.0 m / s to 20 m / s in a time of 1.27 seconds.

(c)  Being:

[tex]a=\frac{vf-vi}{t}[/tex]

Then:

a*t= vf - vi

vf - vi represents the change in velocity. You can see that, if a (acceleration) is constant, then (vf - vi) is directly proportional to the time t: therefore, if t doubles, the change in velocity doubles as well.

In other words, doubling the time will double the change in velocity if the acceleration is kept constant.

Answer:

Wavelength, frequency and the photon energy changes as the one goes across the ranges of the electro-magnetic radiations.

Explanation:

Electro-magnetic radiations may be defined as the form of energy that is radiated or given by the electro-magnetic radiations. The visible light that we can see is the one of the electro-magnetic radiations. Other forms are the radio waves, gamma waves, UV rays, infrared radiations, etc.

The wavelength of the radiations decreases as we go from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.

The frequency of the radiations increases when we move from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.

The photon energy of the radiations increases when we move from a. radio waves -- b. infrared radiation -- c. visible light -- d. ultraviolet radiation -- e. gamma radiation.

Answer:

Where is the picture

Explanation:

WHERE IS THE PICTURE

Answer:

a) 113N

b) 0.37

Explanation:

a) Using the Newton's second law:

\sum Fx =ma

Since the crate doesn't move (static), acceleration will be zero. The equation will become:

\sum Fx = 0

\sumFx = Fm - Ff = 0.

Fm is the applied force

Ff is the frictional force

Since Fm - Ff = 0

Fm = Ff

This means that the applied force is equal to the force of friction if the crate is static.

Since applied force is 113N, hence the magnitude of the static friction force will also be 113N

b) Using the formula

Ff = nR

n is the coefficient of friction

R is the reaction = mg

R = 31.2 × 9.8

R = 305.76N

From the formula

n = Ff/R

n = 113/305.76

n = 0.37

Hence the minimum possible value of the coefficient of static friction between the crate and the floor is 0.37

Given :

Force provided, F = 112 N.

Acceleration of the bag, a = 0.79 m/s².

To Find :

a. What is the mass of the fertilizer bag?

b. How much does the fertilizer bag weigh?

Solution :

We know, force is given by :

F = ma

m = F/a

m = 112/0.79 kg

m = 141.77 kg

Now, weight is given by :

W = mg

W = 141.77 × 9.8 N

W = 1389.35 N

Therefore, the mass of fertilizer bag is 141.77 kg and weight us  1389.35 N.

Answer:

1 m/s

Explanation:

Using law of conservation of momentum

m1v1 + m2v2 = (m1 + m2)vf , where

m1 = mass of object at rest, 20 kg

v1 = initial velocity of object at rest, 0 m/s

vf = final velocity of the bodies

m2 = mass of object in motion, 10 kg

v2 = initial velocity of object in motion, 3 m/s

On substituting, we have

(20 * 0) + (10 * 3) = (20 + 10) vf

0 + 30 = 30 vf

vf = 30 / 30

vf = 1 m/s

Therefore, the velocity of the bodies after hitting each other is 1 m/s

Answer:

The weight is defined as:

W = m*g

where:

m = mass

g = gravitational acceleration.

We know that in Earth the astronaut weights 190 lb-f (this is force, not mass, the correct unit here is 190 lb*m/s^2)

then:

190 lb*m/s^2 = m*9.8m/s^2

(190 lb*m/s^2)/(9.8m/s^2) = 19.39 lb

Now we know the mass of the astronaut.

a) wieght on the moon in Newtons.

Newtons uses kilograms as the units of mass, then we need to rewrite the mass of the astronaut in kg.

we know that 1lb = 0.454 kg

Then 19.39 lb is equal to: 19.39*0.454 kg = 8.8 kg

We know that the acceleration due to gravity on the Moon is one-sixth that on Earth.

then: g = (9.8m/s^2)/6

And the weight of the astronaut in the moon will be:

W = 8.8 kg*(9.8m/s^2)/6 = 14.37 N

b) The weight on mars, where the acceleration due to gravity is 0.38 times that on Earth, we have:

g = (9.8m/s^2)*0.38

then the weight will be:

W = 8.8kg*(9.8m/s^2)*0.38 = 32.77 N

Answer:

Low-temperature blackbody

Explanation:

There are 3 types of blackbody temperatures.

Low-temperature blackbody

High temperature extended area blackbody

High-temperature cavity blackbody

A Low-temperature blackbody is a type of black body radiation that has the range of -40° C to 175° C, typically between 233 K and 448 K. A perfect fit for the temperature range mentioned in the question, "a few hundred Kelvin". Therefore, it's the kind of blackbody temperature that the object would emit.

Explanation:

Given that,

Distance covered, d = 40 m

Time, t = 9.5 s

Final velocity, v = 2.75 m/s

(a) Let u be the original speed of the truck. We can find it using first equation of motion.

[tex]v=u+at\\\\2.75=u+2.75\times 9.5\\\\2.75-26.125=u\\\\u=-23.375\ m/s[/tex]

(b) Acceleration = rate of change of velocity

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{2.75-(-23.375)}{9.5}\\\\=2.75\ m/s^2[/tex]

So, the original speed is -23.375 and acceleration is 2.75 m/s².

Answer:

-4.35 × 10^-6 N

Explanation:

i just answered it on ap3x :)

The question incomplete, the complete question is;

Two identical blocks fall a distance H. One falls directly down, the other slides down a frictionless incline.

(A)the one falling vertically

(B)the one on the incline

(C)Both have the same speed.

(D)cannot be determined

Answer:

(C)Both have the same speed.

Explanation:

When we consider the question closely, we will discover that an object falling down a frictionless incline is comparable to an object falling freely under gravity.

In both instances, the acceleration of objects is just the same irrespective of mass.

Hence, the object falling vertically and the object sliding down a frictionless plane will have the same speed at the bottom.

Answer:

√2

Explanation:

From the question, we're given that the

Acceleration of the leaf is 1 m/s²

Change in displacement of the leaf is 1 m/s.

Again, from the question, we can tell that the initial velocity u = 0, since the object starts at rest

Now, to solve this, we don't the equation of motion to ur

S = ut + 1/2at², substituting the whole parameters, we then have

1 = 0 * t + 1/2 * 1 * t²

1 = 1/2 * t²

t²/2 = 1

t² = 2

t = √2 seconds

Therefore the time it takes the leaf to dislodge is 2 seconds

Answer:

1/3

Explanation:

Gay Lusaac's law states that "the pressure of a given mass of gas is directly proportional with the absolute temperature of the gas, provided that the volume is kept constant."

In formula, we say that

P/T = k

Where

P = pressure at different points

T = temperature at different points

k = constant of proportionality

From the stated formula, if we multiply the temperature by 3, we have

P/3T = k

P * 1/3T = k

And from this, we see the pressure will change by a value of 1/3

Answer:

The frequency [tex]f = 0.8048 \ Hz[/tex]

Explanation:

From the question we are told that

    The mass of the object is  [tex]m = 19 \ kg[/tex]

      The spring constant is  [tex]k = 486 \ N/ m[/tex]

Generally the maximum frequency is mathematically represented as  

        [tex]f = \frac{1}{2 \pi } * \sqrt{ \frac{k}{m } }[/tex]

=>     [tex]f = \frac{1}{2 * 3.142 } * \sqrt{ \frac{486}{ 19 } }[/tex]

=>     [tex]f = 0.8048 \ Hz[/tex]

Answer:

the max is 2,500 or less

Explanation:

because you cant owe anymore

Answer:

The amount of energy is directly proportional to the photon's electromagnetic frequency and thus, equivalently, is inversely proportional to the wavelength. The higher the photon's frequency, the higher its energy. Equivalently, the longer the photon's wavelength, the lower its energy.

Explanation:

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Hello!

[tex]\large\boxed{a = \frac{2}{3}m/s^{2}}[/tex]

Use the equation F = m · a to solve. We are given the force (N) and mass (kg), so we can solve for the acceleration by plugging in the given values:

0.8 = 1.2a

0.8 / 1.2 = a

a = 2/3 m/s²

Answer:

umm  becuase it is a test and you need them

Explanation:

Answer:

The answer would be a

Explanation:

Answer:

a) 113N

b) 0.37

Explanation:

a) Using the Newton's second law:

\sum Fx =ma

Since the crate is not moving then its acceleration will be zero. The equation will become:

\sum Fx = 0

\sumFx = 0

Fm - Ff = 0.

Fm is the moving force

Ff is the frictional force

Fm = Ff

This means that the moving force is equal to the force of friction if the crate is static.

Since applied force is 113N, hence the magnitude of the static friction force will also be 113N

b) Using the formula

Ff = nR

n is the coefficient of friction

R is the reaction = mg

m is the mass of the crate = 31.2kg

g is the acceleration due to gravity = 9.8m/s²

R = 31.2 × 9.8

R = 305.76N

Recall that;

n = Ff/R

n = 113/305.76

n = 0.37

Hence the minimum possible value of the coefficient of static friction between the crate and the floor is 0.37

Answer:

The second graph, B

Explanation