BRAINLIEST IF UR RIGHT!!!

Answer:

1) MANTLE 2) MAGMA 3) MINERALS

Explanation:

I just did the assignment and got it correct hope this helps

Rocks beneath the surface are forced toward the mantle. This increases pressure and heat. Magma pockets rise, increasing heat. Temperature and pressure cause to change minerals

A Metamorphic rock is a type of rock which has been changed by extreme heat and pressure

Subduction is the process in which a dense tectonic plate slips beneath a more buoyant one . Hence ,Metamorphic rock  and minerals of lithosphere transported to the mantle .

hence , Rocks beneath the surface are forced toward the  Mantle

The reduction in overlying pressure , decompression enables the mantle rock and form magma

hence ,magma pockets rise, increasing heat.

When pressure and temperature change , chemical reactions occur to cause the mineral in the Metamorphic rock to change to an assemblage that is stable at the new pressure and temperature conditions.

Temperature and pressure cause to change minerals

learn more about Metamorphic rock

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Answer:10N

Explanation:

Answer:

255N

Explanation:

Given parameters:

Mass of barrel  = 75kg

Acceleration  = 3.4m/s²

Unknown:

Force exerted  = ?

Solution:

Force is the product of mass and acceleration according to Newton's second law of motion.

  Force  = mass x acceleration

Now insert given parameters and solve,

       Force  = 75 x 3.4  = 255N

The net force on the barrel is the sum of the pulling force (magnitude p, acting upward) and the barrel's weight (mag. w, opposing p ). So by Newton's second law,

∑ F = p - w = m a

p = w + m a

p = m g + m a

p = m (g + a)

p = (75 kg) (9.80 m/s² + 3.4 m/s²)

p = 990 N

Answer:

sound wave-electrical wave-radio wave

Answer:

D

Explanation:

on edg

Answer:

m = 0.164 kg

Explanation:

T (period)

k (force/spring constant)

m (mass)

T = 2*Pi*sqrt(m/k)

T/(2*Pi) = sqrt(m)/sqrt(k)

(T/(2*Pi))*sqrt(k) = sqrt(m)

m = ((T/(2*Pi))*sqrt(k))^2

m = 4.5*((1.2/(2*Pi)))^2

m = 0.1641403175

300 feet because 5x60=300 and there is 60 seconds in a min

Answer:

4

Explanation:

As you can see in the free body diagram there are 4 forces acting on the body.

Answer:

0.33 m/s

Explanation:

The graph given is that of distance against time. The slope of such a graph gives the velocity of the object while travelling.

In this graph the change in distance for the last 6 seconds is given by;

The distance is : 10-8 = 2 m

The time in seconds is: 6 s

The velocity =  2/6 = 1/3 m/s

The velocity expressed in decimal form is : 0.33 m/s

Answer:

What is the acceleration of your vehicle?

+ 2.0 m/s^2 ✔

- 2.0 m/s^2

+ 8.0 m/s^2

- 6.0 m/s^2

Answer:

Choice a. approximately [tex]2 \times 10^{-18}\; \rm N[/tex] to the right.  

Explanation:

Look up the Coulomb constant, [tex]k[/tex]:

[tex]k \approx 8.987552 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}[/tex].

Coulomb's Law may be used to find the magnitude of the electric force between the electron and each proton.

Let [tex]q_1[/tex] and [tex]q_2[/tex] denote the magnitude of electric charge on two point charges. Let [tex]r[/tex] denote the distance between these two charges.

By Coulomb's Law, the magnitude of the force between these two point charges would be:

[tex]\displaystyle F = \frac{k\, q_1\, q_2}{r^2}[/tex].

The unit of distance in the Coulomb's constant here[tex]k \approx 8.987552 \times 10^{9}\; \rm N \cdot m^{2} \cdot C^{-2}[/tex] is meters. However, the distance between the electron and each proton is given in micrometers, [tex]\rm \mu m[/tex]. Note that [tex]1\; \rm \mu m = 10^{-6}\; \rm m[/tex].

Convert these units to meters:

[tex]30 \; \rm \mu m = 30 \times 10^{-6}\; \rm m[/tex].

[tex]10 \; \rm \mu m = 10 \times 10^{-6}\; \rm m[/tex].

The question states that the magnitude of electric charge on each proton and each electron is [tex]1.6\times 10^{-19}\; \rm C[/tex].

Using these information, find the magnitude of the electric force between the electron and each proton:

The two protons in this question will both attract the electron. Therefore, the force between the electron and the proton on the left-hand side of the electron would point to the left. Similarly, the force between the electron the proton on the right-hand side of the electron would point to the right.

The magnitude of the net electric force on the electron would be:

[tex]2.56 \times 10^{-18}\; \rm N - 0.26\times 10^{-18}\;\rm N \approx 2\times 10^{-18}\; \rm N[/tex].

These two forces act along the same line in opposite direction. Therefore, the resultant force of these two force would be in the direction of the larger force of the two.

In this question, the electric force between the electron and the proton on the right-hand side of the electron is larger. Hence, the net electric force of the protons on the electron should point to the right (towards the proton that is closer to the electron.)

Answer:

m/s2 m/s

Explanation:

Answer:

thermal or heat energy

If someone is attempting to focus on multiple tasks at one time, it could be said that they have divided attention. the statement is true.

The capacity for active processing of a particular piece of environmental information while tuning out other details is known as attention. In order to make sense of the world, we need to be able to properly manage the attentional resources we have at our disposal because attention is constrained in terms of both capacity and duration.

Our brain's capacity to attend to two separate stimuli at once and respond to the various demands of our environment is known as divided attention. Divided attention, a type of simultaneous attention, enables us to successfully process several information sources and do multiple tasks at once. It is crucial to have these cognitive abilities since they help us live more effectively every day.

When someone is attempting to focus on multiple tasks at one time, his brain attends more than one stimuli at the same time and respond to the more than one demands of his surroundings. So, it could be said that they have divided attention.

To learn more about divided attention, refer the link:

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Answer: Equal and Opposite

Explanation:

Answer:

Particles in a: gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

i hope this helps your answer

Answer:

liquids vibrate, move about, and slide past each other. solids vibrate but generally do not move from place to place.

Answer:

I believe the answer is 5718.75. Respond if it is wrong please.

Explanation:

I used a calculator.

Complete Question

The diagram of with this question is shown on the first uploaded image

Answer:

The value is  [tex]v = -6.543 \^ i + 9.47 \^ j + 0 \^ k[/tex]

Explanation:

From the question we are told that

   The mass of the rock is  [tex]m = 0.250 \ kg[/tex]

    The length of the string is  [tex]L = 0.75 \ m[/tex]

    The angle the string makes horizontal is  [tex]\theta = 11.9^o[/tex]

     The angle which the projection of the string onto  the xy -plane makes with the positive x-axis is  [tex]\phi = 34.6^o[/tex]

    The angular velocity of the rock is  [tex]w = 2.50 rev/s = 2.50 * 2\pi =15.7 \ rad/s[/tex]

Generally the radius of the circle made by the length of the string is mathematically represented as

               [tex]r = L cos(\theta )[/tex]

=>            [tex]r = 0.75 cos(11.9 )[/tex]

=>            [tex]r = 0.734 \ m[/tex]

Generally the resultant tangential velocity is mathematically represented as

      [tex]v__{R}} = w * r[/tex]

=>  [tex]v__{R}} = 15.7 *0.734[/tex]

=>  [tex]v__{R}} = 11.5 \ m/s[/tex]

Generally the tangential velocity along the x-axis is  

      [tex]v_x = -v__{R}} * sin(\phi)[/tex]

=>   [tex]v_x =- 11.5 * sin(34.6)[/tex]

=>   [tex]v_x = -6.543 \ m/s[/tex]

The negative sign show that the velocity is directed toward the negative x-axis

Generally the tangential velocity along the y-axis is  

      [tex]v_y = v__{R}} * cos(\phi)[/tex]

=>   [tex]v_y = 11.5 * cos(34.6)[/tex]

=>   [tex]v_y = 9.47 \ m/s[/tex]

Generally the tangential velocity along the y-axis is  

      [tex]v_z = v__{R}} * cos(90)[/tex]

=>   [tex]v_z = 0 \ m/s[/tex]

Generally the tangential velocity at that instant is mathematically represented as

       [tex]v = -6.543 \^ i + 9.47 \^ j + 0 \^ k[/tex]

Answer:

They would probably not be looking good.. like if u don't sort it out they won't be shaped well and there are many types of plastic and if we combine them together they won't give the correct form..

hope this helps :)

Answer:

Mass = 4281.35 kg

Explanation:

From Newton's law of motion, the weight of an object is given by the formula;

W = mg

Where;

W is weight

m is mass

g is acceleration due to gravity which has a constant value of 9.81 m/s².

We are given weight W = 42000 N.

Thus;

42000 = m × 9.81

m = 42000/9.81

m ≈ 4281.35 kg

Answer:

55

Explanation:

I hope this answer help u

Answer:

i think no. A is the coeerct answer

hope this will help you

Answer:

she had socks one and was shuffeling so she had static

Explanation:

Answer:

i) a = 0.977 [m/s²]

ii) x = 115.06 [m]

Explanation:

In order to determine the acceleration, we must use the following equation of kinematics.

[tex]v_{f} ^{2} =v_{o} ^{2} -2*a*x[/tex]

where:

Vf = final velocity = 7 [m/s]

Vo = initial velocity = 15 [m/s]

a = acceleration [m/s²]

x = displaciment = 90 [m]

Now replacing:

[tex](7)^{2} =(15)^{2} -2*a*90\\2*a*90 = 15^{2} - 7^{2} \\180*a=176\\a=0.977[m/s^{2}][/tex]

When the bus coming to rest.

[tex]v_{f}^{2} =v_{o} ^{2} -2*a*x\\0 = 15^{2} -2*0.977*x\\x = 115.06[m][/tex]

Answer:

tetrahedral shape.

Explanation:

Answer:

Molecular Geometries. The VSEPR theory describes five main shapes of simple molecules: linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral. Apply the VSEPR model to determine the geometry of molecules where the central atom contains one or more lone pairs of electrons.

Density is mass per unit of volume, usually measured in g/cm³. So first determine the volume of the cylinder:

v = π r ² h = π ((39.0 mm) / 2)² (39.0 mm)

v = 59,319/4 π mm³ ≈ 46,589 mm³ ≈ 46.589 cm³

Then the density is

ρ = m / v

ρ = (1 kg) / v = (1000 g) / v

ρ ≈ 21.464 g/cm³

Or, if you want to preserve the given units, that's

ρ ≈ 0.00002146 kg/mm³

Answer:

that is cool and i have one interesting fact

Explanation: North Korea and Cuba are the only places you can't buy Coca-Cola

Answer:

The majority of chemical digestion occurs in the small intestine. Digested chyme from the stomach passes through the pylorus and into the duodenum.

Answer:

a) The complete free body diagram of the system is presented in the image attached below according to the Newton's Law.

b) The acceleration of the top block is 0.962 meters per square second in the -x direction and the acceleration of the bottom block is 0.962 meters per square second in the -x direction.

c) The tension on the rope is 9.770 newtons.

Explanation:

a) The complete free body diagram of the system is presented in the image attached below according to the Newton's Law.

b) At first we have to construct corresponding equations of equilibrium for each mass:

Mass A

[tex]\Sigma F_{x} = T - \mu_{k}\cdot N_{A} = m_{A}\cdot a_{A}[/tex] (1)

[tex]\Sigma F_{y} = N_{A}-m_{A}\cdot g = 0[/tex] (2)

Mass B

[tex]\Sigma F_{x} = -P+\mu_{k}\cdot N_{A}+\mu_{k}\cdot N_{B}+T= -m_{B}\cdot a_{A}[/tex] (3)

[tex]\Sigma F_{y} = N_{B}-N_{A}-m_{B}\cdot g= 0[/tex] (4)

Where:

[tex]P[/tex] - Force exerted on the bottom block, measured in newtons.

[tex]N_{A}[/tex], [tex]N_{B}[/tex] - Normal forces, measured in newtons.

[tex]m_{A}[/tex], [tex]m_{B}[/tex] - Masses of the top and bottom blocks, measured in kilograms.

[tex]\mu_{k}[/tex] - Kinetic coeffcient of friction, dimensionless.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]a_{A}[/tex], [tex]a_{B}[/tex] - Net accelerations of the top and bottom blocks, measured in meters per square second.

From (2):

[tex]N_{A} = m_{A}\cdot g[/tex] (5)

(2) in (4):

[tex]N_{B}=(m_{A}+m_{B})\cdot g[/tex] (6)

(5) in (1):

[tex]T = m_{A}\cdot a_{A}+\mu_{k}\cdot m_{A}\cdot g[/tex] (7)

(6) in (3):

[tex]T = -m_{B}\cdot a_{A}+P-\mu_{k}\cdot m_{A}\cdot g-\mu_{k}\cdot (m_{B}+m_{A})\cdot g[/tex]

[tex]T = -m_{B}\cdot a_{A}+P -\mu_{k}\cdot (2\cdot m_{A}+m_{B})\cdot g[/tex] (8)

And we obtain an expression for the magnitude of the acceleration by eliminating tension:

[tex]m_{A}\cdot a_{A} +\mu_{k}\cdot m_{A}\cdot g = -m_{B}\cdot a_{A}+P-\mu_{k}\cdot (2\cdot m_{A}+m_{B})\cdot g[/tex]

[tex](m_{A}+m_{B})\cdot a_{A} = P-\mu_{k}\cdot (3\cdot m_{A}+m_{B})\cdot g[/tex]

[tex]a_{A} = \frac{P-\mu_{k}\cdot (3\cdot m_{A}+m_{B})\cdot g}{m_{A}+m_{B}}[/tex]

If we know that [tex]P = 45\,N[/tex], [tex]m_{A} = 2\,kg[/tex], [tex]m_{B} = 4\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\mu_{k} = 0.4[/tex], then the magnitude of the acceleration is:

[tex]a_{A} = \frac{45\,N-(0.4)\cdot [3\cdot (2\,kg)+4\,kg]\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{2\,kg+4\,kg}[/tex]

[tex]a_{A} = 0.962\,\frac{m}{s^{2}}[/tex]

The acceleration of the top block is 0.962 meters per square second in the -x direction and the acceleration of the bottom block is 0.962 meters per square second in the -x direction.

c) By means of (7) and knowing that [tex]m_{A} = 2\,kg[/tex], [tex]a_{A} = 0.962\,\frac{m}{s^{2}}[/tex],  [tex]\mu_{k} = 0.4[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], we find that the tension on the rope is:

[tex]T = (2\,kg)\cdot \left(0.962\,\frac{m}{s^{2}} \right)+(0.4)\cdot (2\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]T = 9.770\,N[/tex]

The tension on the rope is 9.770 newtons.