Answer:
[tex]\boxed{x=-27, \: x=67}[/tex]
Step-by-step explanation:
There can be two values of x.
The range is largest no. - smallest no.
Range = 64
Let x be the smallest no.
largest no. from the list is 37
37 - x = 64
-x = 64 - 37
x = -27
Let x be the largest no.
smallest no. from the list is 3
x - 3 = 64
x = 64 + 3
x = 67
The needed two values of x are: 67 and -27.
Given sequence of 8 numbers as:
[tex]4, 32, 6, x, 10, 3, 35, 37[/tex]
Given range of above sequence: 64
The range of a sequence is defined as the difference between the maximum and minimum value of the sequence.
Since the value x can assume any value, it have option to be minimum value in the sequence or maximum value in the sequence such that the range remains at 64.
Case 1: x as minimum value of given sequence:
If so, then the maximum value is 37. Then-
[tex]range = maximum \:value - minimum \:value\\or\\64 = 37-x\\or\\x = -27\\[/tex]
Case 2: x as maximum value of the given sequence:
If so, then the minimum value of the sequence is 3. Then-
[tex]range = maximum \:value - minimum \:value\\or\\64 = x - 3\\or\\x = 67\\[/tex]
Thus the needed two values of x are: 67 and -27.
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PLEASE help me with this question with solutions
Answer:
D
Step-by-step explanation:
the inscribed angle intersects an arc that twice the measure of the arc interested by the central angle. The inscribed angle's arc measures 144° and the central angle's arc measures 72°
>central angle and the arc the intersected arc are equal i.e they are both 72°
>the inscribed angle is half of the measure of the intersected arc i.e since the inscribed angle is 72° the arc interested is 144°
Solve.
5x– 2y = 27
-3x +2y=-17
Enter your answer, in the form (x,y), in the boxes.
Answer:
x=5,y=-1
Step-by-step explanation:
5x– 2y = 27
-3x +2y=-17
Add the two equations together to eliminate y
5x– 2y = 27
-3x +2y=-17
----------------------
2x = 10
Divide by 2
2x/2 = 10/2
x = 5
Now find y
-3x +2y = -17
-3(5)+2y = -17
-15+2y =-17
Add 15 to each side
-15+15 +2y = -17+15
2y = -2
Divide by 2
2y/2 = -2/2
y =-1
Which of these triangle pairs can be mapped to each other using both a translation and a reflection across the line containing AB? Triangles X Y Z and A B C are congruent. Triangle X Y Z is reflected across a line to form triangle A B C. It is also slightly higher than triangle A B C. Triangles A B C and A Y C are congruent and share common side A C. Triangle A B C is reflected across line A C to form triangle A Y C. Triangles A B C and X Y Z are congruent. Triangle X Y Z is slightly higher and to the right of triangle A B C. Triangles A B C and X Y Z are congruent. Triangle A B C is rotated to the right to form triangles X Y Z. Triangle X Y Z is also higher and to the right of triangle A B C.
Answer:
B. Triangles A B C and A Y C are congruent and share common side A C. Triangle A B C is reflected across line A C to form triangle A Y C.
Step-by-step explanation:
Translation and reflection are examples of methods of rigid transformation. Translation ensure that each point on a given figure is moved the same distance with respect to the reference plane. Reflection involves the flipping of a given figure across a given line.
From the question, both reflection and transformation would map the triangles into one another. Since the reference line contains AB, then the two triangles are congruent and would share a common side.
Thus, the triangle pairs that can be mapped into each other is that of option B.
Based on the information given, the triangle pairs that can be mapped to each other using both a translation and a reflection across the line containing AB will be A. Triangles X Y Z and A B C are congruent. Triangle X Y Z is reflected across a line to form triangle A.
Triangles.The triangle pair that can be mapped to each other using both translation and reflection across line containing AB is the first triangle pair.
The first figure consists of ΔXYZ and ΔABC that are a reflection of each other across the line AB and a translation.
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The sand used for sanding icy roads in the winter is stored in a conical-shaped structure with a radius of 10 m and a height of 16 m. Calculate the maximum amount of sand which can be stored in this structure.
Answer:
1,675.516
Step-by-step explanation:
The formula for a cone is V = pi r^2 h/3.
Plugging in the values of the radius and height, V = pi 10^2 16/3
Solving, you get:
V = pi 100 5.3333333
V = 1,675.516
Match the system with the amounts of solutions. pls
From top to bottom, the answers are
no solutionsone solutioninfinitely many solutionsone solution==============================================
Explanation:
The first system of equations has each equation with the same slope 2, but different y intercepts. This indicates we have parallel lines. Parallel lines never cross, so there are no solutions. A solution is where the two lines cross.
The second system of equation has one solution where the two lines cross. This is because the slopes are different
The third system has infinitely many solutions. We have the same line graphed out twice. One line is directly on top of the other to yield infinitely many intersection points.
The fourth system is similar to the second system. Different slopes lead to exactly one solution. The y intercept doesn't affect the number of solutions (whether its 0, 1 or infinitely many)
For each equation shown, they are in the form y = mx+b with m as the slope and b as the y intercept.
Which of the following is a point-slope equation for a line with the point
(-2, 4) and a slope of 3?
O A. y-2-3(x-4)
B. y-4-3(x-2)
O C. y +2 = 3(x-4)
O D. y - 4 - 3(x+2)
Hi there! :)
Answer:
Choice D. (y - 4) = 3(x + 2)
Step-by-step explanation:
An equation in point-slope form is:
(y - y1) = m(x - x1)
Where:
y1 = y-coordinate of a point
m = slope
x1 = x-coordinate of a point
In this instance, the point given is (-2, 4) with a slope of 3. Therefore, the equation in point-slope form would be Choice D. (y - 4) = 3(x + 2)
Answer:
Step-by-step explanation:
answer is C
Because formula of equation of slop is
Y-y1=m(x-x1)
Determine the equation for the line of best fit to represent the data.
Answer:
Y= -1/5x + 1
Step-by-step explanation:
Just type it on a graphing calculator an click graph
Find the other endpoint of the line segment with the given endpoint
and midpoint
Endpoint 1: (9,1)
Midpoint: (1,6)
Endpoint 2= (
Step-by-step explanation:
Let the other endpoint be (x,y)
Since, (1,6) is the midpoint between (9,1) and (x,y)
Therefore,
1=(9+x)/2
=> 2=9+x
=> x= -7
and,
6=(1+y)/2
=>12= 1+y
=> y=11
So, the other endpoint is ( -7, 11)
Answer:
( - 7 , 11)Step-by-step explanation:
Let the coordinates of Endpoint 2 be
(x ,y)
The midpoint of the endpoints is given by
[tex](1,6) = ( \frac{9 + x}{2} , \frac{1 + y}{2} )[/tex]
Where x and y are coordinates of Endpoint 2
Comparing with the midpoint we have
[tex]1 = \frac{9 + x}{2} \\ 2 = 9 + x \\ \\ x = 2 - 9 \\ \\ x = - 7[/tex]
[tex]6 = \frac{1 + y}{2} \\ 12 = 1 + y \\ \\ y = 12 - 1 \\ \\ y = 11[/tex]
Therefore x = - 7 and y = 11
The coordinates of Endpoint 2 are
( - 7 , 11)Hope this helps you
a parabola had a vertex of (-5,0) and passes through the point (-3,1)
Answer:
Step-by-step explanation:
let the parabola be y=a(x+5)²+0
or y=a(x+5)²
∵ it passes through (-3,1)
1=a(-3+5)²
4a=1
a=1/4
so parabola is y=1/4(x+5)²
Clase de estadistica la moda es una medida de tendencia central que: ¿por que? a) tiene muchos datos b) tiene la mayor frecuencia c) tiene poca frecuencia d) al ordenar los datos de menor a mayor es el dato que se ubica en el centro
Answer:
b) tiene la mayor frecuencia
Step-by-step explanation:
Las medidas de tendencia central se refieren a un centro alrededor del cual se encuentran todos los datos y estas medidas son: la media, la moda y la mediana. La media es el valor promedio de un grupo de datos, la moda es el dato que se repite más veces y la mediana es el valor que se encuentra en el centro cuando los datos se ubican de menor a mayor. De acuerdo a esto, la respuesta es que la moda es una medida de tendencia central que tiene la mayor frecuencia.
Los otras opciones no son correctas porque el tamaño del conjunto de datos no depende de las medidas de tendencia central, esto depende de cada situación y pueden ser muchos o pocos datos. Además la opción "al ordenar los datos de menor a mayor es el dato que se ubica en el centro" se refiere a la mediana.
Alexandria is practicing her long distance running. On day 0, she can run 2 miles without stopping. She wants to add 1/4 mile to her run each day. What is the slope for this linear relationship?
Answer:
1/4
Step-by-step explanation:
The slope of a graph is always the rate of change for every value of x, in this case, days. Since she is adding 1/4 of a mile to her run each day, this means that the slope of this linear relationship is 1/4.
She increases a full mile in 4 days, just a little note.
Problem Water boils at 212^\circ212 ∘ 212, degrees Fahrenheit. Write an inequality that is true only for temperatures (t)(t)left parenthesis, t, right parenthesis that are higher than the boiling point of water.
Answer:
t > 212
Step-by-step explanation:
Given
Boiling point = 212°F
Required
Inequality that shows temperature greater than the boiling point
From the question, temperature is represented with t.
The inequality "greater than" is represented with >
So, temperature greater than the boiling point implies that t > 212
Answer: t > 212
Step-by-step explanation:
The question says "Write an inequality that is true only for temperatures that are higher than the boiling point of water."
This means t has to be higher than 212 since it says only for temperatures that are higher than the boiling point.
But since we have to write an inequality the answer would be: t > 212.
I know I did this very late and you probably don't need it but i was bored
In a study with four groups and 10 participants in each group, the sum of squares for the between-groups source of variation is 60. What is the value for the mean square between groups in this study
Answer:
20
Step-by-step explanation:
Given that:
The study group n = 4
number of participants = 10
the sum of squares for the between-groups source of variation is 60
The objective is to determine the mean square between groups in this study
The mean square between groups in this study compares the means of the group with the sum of squares for the between-groups source (i.e the grand mean)
For this analysis;
the degree of freedom = n-1
the degree of freedom = 4 - 1
the degree of freedom = 3
Thus; the mean square between groups = [tex]\dfrac{60}{3}[/tex]
the mean square between groups = 20
solve systems by substitution method x + y = 20 3x + 4y = 72
Answer:
x = 8; y = 12.
Step-by-step explanation:
x + y = 20
x = -y + 20
3x + 4y = 72
3(-y + 20) + 4y = 72
-3y + 60 + 4y = 72
y = 12
x + 12 = 20
x = 8
Check your work!
3(8) + 4(12) = 72
24 + 48 = 72
72 = 72
Hope this helps!
Answer:
X=-12 and Y= 32
Step-by-step explanation:
x+y=20 -> 1
3x+4y=72 -> 2
Form 1,
[x+y=20]×4
4x+4y=60 ->3
Form 2,
3x+4y=72
4y= 72 -3x ->4
Sub (4) into (3)
4x+72-3x= 60
x = -12
Sub X=-12 into (1)
-12+y=20
y= 32
Hope this helps.
A polygon with 9 sides is shown. An exterior angle has a measure of x degrees. In the regular nonagon shown, what is the measure of angle x? 36° 40° 45° 60°
Answer:
40°Step-by-step explanation:
First we must know that the sum of all the exterior angle of all polygons is 360°.
Measure of each angle of a polygon = 360°/total sides of the polygon
Since a regular nonagon has 9 sides, the measure of each angle of a polygon is expressed as thus;
Measure of each angle of a polygon = 360°/9
Measure of each angle of a polygon = 40°
Hence the measure of an exterior angle x of a nonagon is 40°
Answer:
B in Edg
Step-by-step explanation:
why the system of si unit is developed
Step-by-step explanation:
Hi, there!!!!
The main purpose of developing si unit is to have standard unit of measurements and to bring uniformity in whole world in terms of measurements.
I hope it helps you...
Find the 20th term from the last term of the AP:3,8,13,..., 253.
Answer:
158
Step-by-step explanation:
The sequence is 3, 8, 13, ..., 253.
Going backwards, it's 253, 248, 243, ..., 3.
First term is 253, common difference is -5.
The nth term is:
a = 253 − 5(n − 1)
The 20th term is:
a = 253 − 5(20 − 1)
a = 158
The cylinder shown has a volume of 150 cubic inches and its height is equal to its radius. The cylinder and the sphere shown have the same radius. What is the volume of the sphere?
Answer:
V = 200
Step-by-step explanation:
Cylinder
V = pi r^2 h
150 = pi r^2 h
We know that h = r
150 = pi r^2 r
150 = pi r^3
Divide each side by pi
150 /pi = r^3
Take the cube root of each side
( 150 / pi ) ^ 1/3 = r
3.627831679 = r
Rounding to 3.63
Now find the volume of the sphere
V = 4/3 pi r^3
Replacing r^3 with 150 /pi
V = 4/3 * pi ( 150/pi)
V = 4*150 /3
V = 200
A swimming pool can be emptied in 6 hours using a 10-horsepower pump along with a 6-horsepower pump. The 6-horsepower pump requires 5 hours more than the 10-horsepower pump to empty the pool when working by itself. How long will it take to empty the pool using just the 10-horsepower pump?
Answer: 10 hours
Step-by-step explanation:
The 10hp pump takes x hours to empty the pool which means it gets [tex]\dfrac{1}{x}[/tex] of the job done in one hour.
The 6hp pump takes x+5 hours to empty the pool which means it gets [tex]\dfrac{1}{x+5}[/tex] of the job done in one hour.
Together, they can get [tex]\dfrac{1}{x}+\dfrac{1}{x+5}[/tex] of the job done in one hour.
It is given that together they get the job done in 6 hours which means they get [tex]\dfrac{1}{6}[/tex] of the job done in one hour.
10 hp pump + 6 hp pump = Together
[tex]\dfrac{1}{x}\quad +\quad \dfrac{1}{x+5}\quad =\quad \dfrac{1}{6}[/tex]
Multiply by 6x(x+5) to eliminate the denominator:
[tex]\dfrac{1}{x}(6x)(x+5) +\dfrac{1}{x+5}(6x)(x+5) = \dfrac{1}{6}(6x)(x+5)[/tex]
Simplify and solve for x:
6(x + 5) + 6x = x(x + 5)
6x + 30 + 6x = x² + 5x
12x + 30 = x² + 5x
0 = x² - 7x - 30
0 = (x - 10)(x + 3)
0 = x - 10 0 = x + 3
10 = x -3 = x
Since the number of hours cannot be negative, disregard x = -3.
So, the only valid answer is x = 10.
You measure the sides of a pool and find that it is 20 yards wide and 50 yards long. Approximately, how far would it be diagonally between corners of the pool?
A. 54 yards
B. 58 yards
C. 62 yards
D. 66 yards
Answer:
[tex]\boxed{d = 54 yards}[/tex]
Step-by-step explanation:
Formula for diagonal is as follows:
[tex]d = \sqrt{l^2+w^2}[/tex]
Where d is diagonal, l is length (50 yards) and w is width (20 yards)
[tex]d = \sqrt{(50)^2+(20)^2}[/tex]
[tex]d = \sqrt{2500+400}[/tex]
[tex]d = \sqrt{2900}[/tex]
d = 53.85 yards
d ≈ 54 yards
Answer:
[tex]\boxed{\mathrm{54 \: yards}}[/tex]
Step-by-step explanation:
The shape of the pool is a rectangle.
The diagonal of a rectangle can be found through a formula by using Pythagorean theorem.
[tex]d^2=l^2 +w^2[/tex]
[tex]d=diagonal\\l=length\\w=width[/tex]
The length is given 50 yards, and width is given 20 yards. Find the diagonal.
[tex]d^2 =50^2 +20^2[/tex]
[tex]d^2 =2500+400[/tex]
[tex]d^2 =2900[/tex]
[tex]d=\sqrt{2900}[/tex]
[tex]d \approx 53.851648[/tex]
[tex]d \approx 54[/tex]
The tee for the sixth hole on a golf course is 305 yards from the tee. On that hole, Marsha hooked her ball to the left, as sketched below. Find the distance between Marsha’s ball and the hole to the nearest tenth of a yard.
Answer:
Correct answer is option D. 96.4 yd.
Step-by-step explanation:
Please refer to the attached figure for labeling of the given diagram.
ABC is a triangle with the following labeling:
A is the hole, B is the Tee and C is the point where the ball is.
Sides are labeled as:
[tex]a =255\ yd\\c = 305\ yd\\\angle B =17^\circ[/tex]
To find:
Side [tex]b = ?[/tex]
Solution:
Here, we have one angle and two sides . Third side of the triangle is to be found opposite to the given angle.
We can use cosine formula here to find the value of the unknown side.
[tex]cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}[/tex]
Putting all the values:
[tex]cos 17 = \dfrac{255^{2}+305^{2}-b^{2}}{2\times 255\times 305}\\\Rightarrow 0.956 = \dfrac{65025+93025-b^{2}}{155550}\\\Rightarrow 148753.2= 158050-b^{2}\\\Rightarrow b^{2}= 158050-148753.2\\\Rightarrow b^{2}= 9296.795\\\Rightarrow b= 96.42\ yd[/tex]
So, the distance between the Ball and hole is 96.42 yd
Correct answer is option D. 96.4 yd.
Answer:
D.) 96.4 yd
Step-by-step explanation:
I got it correct on founders edtell
Consider the matrix A = \begin{pmatrix} 7 & 9 & -3 \\ 3 & -6 & 5 \\ 4 & 0 & 1 \end{pmatrix} ⎝ ⎛ 7 3 4 9 −6 0 −3 5 1 ⎠ ⎞ . What is the value of minor M_{11}M 11 ? 5 -6 0 -4
Answer:
The value of M₁₁ is -6.
Step-by-step explanation:
The minor, [tex]M_{ij}[/tex] is the determinant of a square matrix, say P, formed by removing the ith row and jth column from the original square matrix, P.
The matrix provided is as follows:
[tex]A=\left[\begin{array}{ccc}7&9&-3\\3&-6&5\\4&0&1\end{array}\right][/tex]
The matrix M₁₁ is:
Remove the 1st row and 1st column to form M₁₁,
[tex]M_{11}=\left|\begin{array}{cc}-6&5\\4&0\end{array}\right|[/tex]
Compute the value of M₁₁ as follows:
[tex]M_{11}=\left|\begin{array}{cc}-6&5\\4&0\end{array}\right|[/tex]
[tex]=(-6\times 1)-(5\times 0)\\\\=-6-0\\=-6[/tex]
Thus, the value of M₁₁ is -6.
HELP ASAP MONEY & WAGES!
Answer: $26.70 per hour
Step-by-step explanation:
Regular hours consists of 8 hrs
Overtime hours is 12 - 8 = 4 hours
Regular pay at "x" per hour = 5(8)(x) = 40x
Overtime pay at "2x" per hour = 5(4)(2x) = 40x
Total pay = 80x
Total Pay = $2136 = 80x
[tex]\dfrac{\$2136}{80}=x[/tex]
$26.70 = x
Jane’s mobile phone plan charges $0.05 per minute at daytime rates before 8 p.m. and $0.03 per minute at nighttime rates after 8 p.m. A conference call costs 1.5 times the normal rate. Calculate the cost of a conference call lasting from 7 p.m. to 8:30 p.m.
Answer
5.85
Step-by-step explanation:
$0.05 x 1.5 = 0,075 x 1 hour (60) = 4,5
$0.03 x 1.5 = 0,045 x half an hour (30) = 1,35
So 4.5 + 1.35 = 5.85
Answer:
Step-by-step explanation:
Cost of the conference call before 8 pm =0.15 * 0.05 = $ 0.075
Cost of the conference call after 8 pm = 0.15 * 0.03 = $ 0. 045
Cost of the conference call from 7pm to 8pm that last 60 minutes= 0.075 * 60
= $ 4.50
Cost of the conference call 8pm to 8:30pm =0.045 * 30 = $ 1.35
Cost of the conference call 7 pm to 8:30 pm = 4.50 + 1.35 = $ 5.85
Please help Asap!!!Math question
Answer:
first one
Step-by-step explanation:
convert this number to scientific notation 1260000
Answer:
1.26 * 10 ^6
Step-by-step explanation:
1260000
Scientific notation is of the form a* 10 ^b
where a is a number between 1 and less than 10
Move the decimal 6 places to the left
1.26 ( dropping the extra zeros)
b = +6 since we moved the decimal 6 places)
1.26 * 10 ^6
The number 1260000 in scientific notation is 1.26 x [tex]10^6[/tex].
We have,
1260000
Write the zeroes in powers of 10.
Write a number between 1 to 10 along with the power of 10.
Now,
126 x 10000
This can be written as,
126 x [tex]10^4[/tex]
Now,
126 can be written as 126/100 x 100.
i.e
1.26 x 100 or 1.26 x 10²
Now,
1.26 x 10² x [tex]10^4[/tex]
1.26 x [tex]10^{2 + 4}[/tex]
1.26 x [tex]10^6[/tex]
Thus,
The number 1260000 in scientific notation is 1.26 x [tex]10^6[/tex].
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A cylinder has radius r and height h. A. How many times greater is the surface area of a cylinder when both dimensions are multiplied by a factor of 2? 3? 5? 10? B. Describe the pattern in part (a).
Answer: A. Factor 2 => 4x greater
Factor 3 => 9x greater
Factor 5 => 25x greater
Step-by-step explanation: A. A cylinder is formed by 2 circles and a rectangle in the middle. That's why surface area is given by circumference of a circle, which is the length of the rectangle times height of the rectangle, i.e.:
A = 2.π.r.h
A cylinder of radius r and height h has area:
[tex]A_{1}[/tex] = 2πrh
If multiply both dimensions by a factor of 2:
[tex]A_{2}[/tex] = 2.π.2r.2h
[tex]A_{2}[/tex] = 8πrh
Comparing [tex]A_{1}[/tex] to [tex]A_{2}[/tex] :
[tex]\frac{A_{2}}{A_{1}}[/tex] = [tex]\frac{8.\pi.rh}{2.\pi.rh}[/tex] = 4
Doubling radius and height creates a surface area of a cylinder 4 times greater.
By factor 3:
[tex]A_{3} = 2.\pi.3r.3h[/tex]
[tex]A_{3} = 18.\pi.r.h[/tex]
Comparing areas:
[tex]\frac{A_{3}}{A_{1}}[/tex] = [tex]\frac{18.\pi.r.h}{2.\pi.r.h}[/tex] = 9
Multiplying by 3, gives an area 9 times bigger.
By factor 5:
[tex]A_{5} = 2.\pi.5r.5h[/tex]
[tex]A_{5} = 50.\pi.r.h[/tex]
Comparing:
[tex]\frac{A_{5}}{A_{1}}[/tex] = [tex]\frac{50.\pi.r.h}{2.\pi.r.h}[/tex] = 25
The new area is 25 times greater.
B. By analysing how many times greater and the factor that the dimensions are multiplied, you can notice the increase in area is factor². For example, when multiplied by a factor of 2, the new area is 4 times greater.
SIMPLIFY: M2 x M5 xM3 PLEASE HELP!!! ASAP!!!!
Answer: M^10
Step-by-step explanation:
since the base number is the same, just add up the exponents: 2+5+3=10
Answer:
Step-by-step explanation:
If its like M^2 x M^5 x M^3 (exponents)
then just add 2+5+3=10
so M^10
Its a rule when the bottom (M) is the same you add the exponents.
If its 2M x 5M x 3M then you multiply
2x5x3=30
so 30M
Hope this helps!
What is the domain of the function graphed below
Answer:
-∞ < x< -∞
Step-by-step explanation:
The domain is the values that x takes
The values that x can take is all real values of x
-∞ < x< -∞
pleaseeeeeeeeee helllllllpppppp pleaseeeeee hellpppp
Answer:
a. u = 19b. t = 6c. a = 2Step-by-step explanation:
a. Given,
v = 34 , a = 5 , t = 3
[tex]v = u + at[/tex]
plugging the values:
[tex]34 = u + 5 \times 3[/tex]
Calculate the product
[tex]34 = u + 15[/tex]
Move 'u' to L.H.S and change its sign
[tex] - u + 34 = 15[/tex]
Move constant to RHS and change its sign
[tex] - u = 15 - 34[/tex]
Calculate
[tex] - u = - 19[/tex]
The difference sign (-) will be cancelled in both sides:
[tex]u = 19[/tex]
b. Given,
v = 50 , u = 20 , a = 5
[tex]v = u + at[/tex]
plugging the values
[tex]50 = 20 + 5 \times t[/tex]
[tex]50 = 20 + 5t[/tex]
Move 5t to L.H.S and change its sign.
Similarly, Move 50 to R.H.S and change its sign
[tex] - 5t = 20 - 50[/tex]
Calculate
[tex] - 5t = - 30[/tex]
The difference sign (-) will be cancelled in both sides
[tex]5t = 30[/tex]
Divide both sides of the equation by 5
[tex] \frac{5t}{5} = \frac{30}{5} [/tex]
Calculate
[tex]t = 6[/tex]
c. Given,
v = 22 , u = 8 , t = 7
[tex]v = u + at[/tex]
plugging the values
[tex]22 = 8 + a \times 7[/tex]
[tex]22 = 8 + 7a[/tex]
Move 7a to LHS and change its sign
Similarly, Move constant to R.H.S and change its sign
[tex] - 7a = 8 - 22[/tex]
Calculate
[tex] - 7a = - 14[/tex]
The difference sign (-) will be cancelled in both sides
[tex]7a = 14[/tex]
Divide both sides of the equation by 7
[tex] \frac{7a}{7} = \frac{14}{7} [/tex]
Calculate
[tex]a = 2[/tex]
Hope this helps...
Good luck on your assignment..