Step-by-step explanation:
1. Yes addition, subtraction, multiplication, and division can be performed on polynomials. like our everyday arithmetic dealings with mathematical operators, polynomials are no exception when it comes to math operators, the four basic operations addition, subtraction, multiplication, and division can be performed on polynomials as well.
2. It can be less handy plus the operation can get messy if you do not have a good sense/understanding/hold of what you are doing things can get messy.
3. I personally know that the simplest is the addition of polynomials
4. I cant say which is difficult, but the operation that can get things messy for me most time is the division operation
I need help with the image below ASAP
Answer:
a
Step-by-step explanation:
The standard form of the equation of a circle is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here (h, k) = (0, 0), thus
(x - 0)² + (y - 0)² = r², that is
x² + y² = r² → a
Which choice is equivalent to the expression below?
V-64
Explanation:
By definition, i = sqrt(-1)
Which means,
sqrt(-64) = sqrt(-1*64)
sqrt(-64) = sqrt(-1)*sqrt(64)
sqrt(-64) = i*sqrt(8^2)
sqrt(-64) = i*8
sqrt(-64) = 8i
On the second line, I used the rule sqrt(x*y) = sqrt(x)*sqrt(y). The fourth line used the rule sqrt(x^2) = x when x is nonnegative.
Answer:
Click 8i for Correct Answer
Step-by-step explanation:
HELP PLS WITH BRAINLIEST
Answer:
cos C
Step-by-step explanation:
Using the cosine ratio in the right triangle
cos C = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{12}{13}[/tex]
Pleaseeeeeee HELP❤️❤️❤️
Answer:
1) [tex]\boxed{Option \ 3}[/tex]
2) [tex]\boxed{Option \ 2}[/tex]
Step-by-step explanation:
A) [tex]x^2-5x+6[/tex]
Using mid term break formula
[tex]x^2-6x+x-6\\x(x-6)+1(x-6)\\Taking \ (x+6) \ as \ common\\(x-6)(x+1)[/tex]
B) [tex]\frac{-20p^{-5}qr^6}{16p^{-2}q^{-3}r^4}[/tex]
Solving it using the two rules: => [tex]\frac{a^m}{a^n} = a^{m-n} \ and \ a^m * a^n = a^{m+n}[/tex]
=> [tex]\frac{-5p^{-3}q^4r^2}{4}[/tex]
We need to put p in the denominator to cancel its negative sign
=> [tex]\frac{-5q^4r^2}{4p^3}[/tex]
Answer:
C and b
Step-by-step explanation:
First question:
The polynomial expression we want to factor is x^2-5x-6
Let's calculate the discriminant to find the roots. The discrminant is b^2-4ac
● b= -5
● a = 1
● c = -6
b^2-4ac= (-5)^2-4*1*(-6) = 25+24 = 49>0
So this polynomial expression has two roots since the discriminant is positive
Let x" and x' be the roots:
● x'= (-b-7)/2a = (5-7)/2= -1
● x"= (-b+7)/2a = (5+7)/2 =6
7 is the root square of the discrminant
The factorization of this pulynomial is:
● a(x - x') (x-x")
● 1*(x-(-1)) (x-6)
● (x+1)(x-6)
So the right answer is c
■■■■■■■■■■■■■■■■■■■■■■■■
Second question:
The expression is: (-20*p^(-5)*q*r^(6))/(16*p^(-2)*q^(-3)*r^3)
To make it easier we will simplify the similar terms one by one.
● Constant terms
-20/16 = (-5*4)/(4*4) = -5/4
● terms containing p
-p^(-5)/p^(-2) = p^(-5-(-2)) = p^(-3) =1/p^3
● terms containg q
q/q^(-3)= q(1-(-3)) = q^4
● terms containg r
r^6/r^4 = r^(6-4) = r^2
Multiply all terms together:
● -5/4 *1/p^3 *q^4 *r^2
● (-5*q^4*r^2)/(4p^3)
The right answer is b
Here is the histogram of a data distribution. All class widths are 1.
Which of the following numbers is closest to the mean of this distribution?
A.6
B.7
C.3
D.4
E.5
=======================================================
Explanation:
The distribution is perfectly symmetrical about the center 6. Notice how the left side is a mirror copy of the right side, due to the heights being the same. Because of this, the mean, median and mode are all the same value and that is 6. The mode is equal to 6 as this is the most frequent value.
The longer way to do this problem is to add up each value shown. We have four copies of '2', six copies of '3', and so on. The total sum you would get is 372. Divide this over 62 because there are 62 smaller green squares. The final result is the mean of 6.
The number closest to the mean of the given distribution is 6. Therefore, option A is the correct answer.
What is mean?In statistics, the mean refers to the average of a set of values. The mean can be computed in a number of ways, including the simple arithmetic mean (add up the numbers and divide the total by the number of observations).
From the given histogram,
Number Frequency
2 4
3 6
4 7
5 9
6 10
7 9
8 7
9 6
10 4
Here, the mean = [2(4)+3(6)+4(7)+5(9)+6(10)+7(9)+8(7)+9(6)+10(4)]/[4+6+7+9+10+9+7+6+4]
= [8+18+28+45+60+63+56+54+40]/62
= 372/62
= 6
Therefore, option A is the correct answer.
To learn more about an arithmetic mean visit:
https://brainly.com/question/15196910.
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A chemist is mixing two solutions, solution A and solution B Solution A is 15% water and solution Bis 20% water. She already has a
beaker with 10mL of solution A in it. How many mL of solution B must be added to the beaker in order to create a mixture that is 18%
water?
Answer:
15 mL of the solution with 20% water will be needed.
Step-by-step explanation:
Use the inverse relationship
10 mL * (18-15)% = x mL * (20-18)%
x = 10 mL * (3/2) = 15 mL
Answer: 15mL
Step-by-step explanation:
Create a table. Multiply across and add down. The bottom row (Mixture) creates the equation.
Qty × % = Total
Solution A 10 15% → 0.15 10(0.15) = 1.5
Solution B x 20% → 0.20 x(0.20) = 0.20x
Mixture 10 + x × 18% → 0.18 = 1.5 + 0.20x
(10 + x)(0.18) = 1.5 + 0.20x
1.8 + 0.18x = 1.5 + 0.20x
1.8 = 1.5 + 0.02x
0.3 = 0.02x
15 = x
The quotient of two rational numbers is positive. What can you conclude about the signs of the dividend and the divisor? That’s us my question it’s confusing please someone help meee I’m in grade 7
Answer:
The divisor and dividend have the same signs.
Step-by-step explanation:
Let's look at all of the possible outcomes of dividing with different signs.
Positive / positive = positive
Positive / negative = negative
Negative / positive = negative
Negative / negative = positive
We can see that whenever the signs are the same, the quotient is positive.
Which equation is represented by the graph below?
Answer: A. y-In x-3
explanation:
I been stuck on this question for the longest please help
Answer: C. [tex]\sqrt{9} * \sqrt{4}[/tex]
Step-by-step explanation:
There is a square root rule that states [tex]\sqrt{x*y} = \sqrt{x} * \sqrt{y} \\[/tex]
We can apply this rule to this problem.
Given [tex]\sqrt{9*4}[/tex]
We can use the rule to make it equal to [tex]\sqrt{9} * \sqrt{4}[/tex]
This is answer choice C.
Answer: c
Step-by-step explanation: 9*4=36 36* 36 = 1296
9 * 9 = 81 4 * 4 = 16 81 * 16 = 1296 hope this helps
Helen has three lessons in the morning.
Lesson 1 starts at 0910.
Each lesson is 60 minutes long.
There is a 15-minute break between lessons 2 and 3.
At what time does lesson 3 end?
Answer:
1225
Step-by-step explanation:
Please see attached picture for full solution.
how would i simplify this?
Answer:
3^6-4x=3^3x-3
Step-by-step explanation:
9^3-2x = 27^x-1 ( 9 is 3² and 27 is 3³)
(3²)^3-2x= (3³)^x-1 in case of exponential between brackets , multiply the exponents.
3^6-4x=3^3x-3
Answer:
x = 9/7
Step-by-step explanation:
9^3-2x = 27^x-1
(3^2)^3-2x = (3^3)^x-1
3^2(3-2x) = 3^3(x-1)
2(3-2x) = 3(x-1)
2(-2x+3) = 3x - 3
-4x + 6 = 3x - 3
-4x = 3x - 9
-7x = -9
x = -9/-7
x = 9/7
What constant acceleration is required to increase the speed of a car from 26 mi/h to 51 mi/h in 3 seconds? (Round your answer to two decimal places.) ft/s2
Answer: 12.22 ft/sec²
Step-by-step explanation:
An increase from 26 to 51 is an increase of 51 - 26 = 25 mi/hr
We need to do this in 3 seconds --> 25 mi/hr ÷ 3 sec
Note the following conversion: 1 mile = 5280 ft
[tex]\dfrac{25\ miles}{hr}\times \dfrac{1}{3\ sec}\times \dfrac{5280\ ft}{1\ mile}\times \dfrac{1\ hr}{60\ min}\times \dfrac{1\ min}{60\ sec} \\\\\\=\dfrac{5280(25)\ ft}{3(60)(60)\ sec^2}\\\\\\=\large\boxed{12.22\ ft\slash sec^2}[/tex]
The constant acceleration that is required to increase the speed of a car from 26 mi/h to 51 mi/h in 3 seconds is 12.22 ft/s².
What is acceleration?Acceleration can be defined as the rate of change of the velocity of an object with respect to time.
[tex]\rm Acceleration=\dfrac{Final\ velocity- Initial\ Velocity}{Time}[/tex]
As the velocity that is given to us is 51 miles/hour and 26 miles/hour, therefore, we first need to convert the units of the velocity in order to get the acceleration in ft/s².
[tex]\rm Final\ velocity= 51\ mi/hr = \dfrac{51\times 5280}{3600} = 74.8\ m\s^2[/tex]
[tex]\rm Initial\ velocity= 26\ mi/hr = \dfrac{26\times 5280}{3600} = 38.134\ m\s^2[/tex]
Now, acceleration is written as the ratio of the difference between the velocity and the time needed to increase or decrease the velocity of the object.
[tex]\rm Acceleration=\dfrac{Final\ velocity- Initial\ Velocity}{Time}[/tex]
Substituting the values we will get,
[tex]\rm Acceleration = \dfrac{74.8-38.134}{3} = 12.22\ \ ft/s^2[/tex]
Hence, the constant acceleration that is required to increase the speed of a car from 26 mi/h to 51 mi/h in 3 seconds is 12.22 ft/s².
Learn more about Acceleration:
https://brainly.com/question/12134554
Please help me... having a hard time
Answer:
Graph (B)
Step-by-step explanation:
For x < 3,
An arrow starting with a hollow circle at x = 3 and heading towards 0 will represent the given inequality on a number line.
Similarly, x ≥ 5,
An arrow starting with a dark circle at x = 5 and heading towards 12 will represent the given inequality on a number line.
When we combine these inequalities on a number line, Graph (B) will be the answer.
HELP ME ASAP! BRAINLIEST UP FOR GRABS
Answer:
-5 ≤ x≤ 3
Step-by-step explanation:
The domain is the values for x
x starts and -5 and includes -5 since the circle is closed
and goes to 3 and includes 3 since the circle is closed
-5 ≤ x≤ 3
Answer:
first option
Step-by-step explanation:
The domain are the values from the x- axis that can be input into the function.
The closed circles at the ends of the graph indicate that x can equal these values.
left side value of x = - 5 and right hand value of x = 3, thus
domain is - 5 ≤ x ≤ 3
I'll mark you brainlyist, if I know how to do it, if you help me out real quick thx
Answer:
4 in
Step-by-step explanation:
as you see from the first rectangle it has been reduced 3 times of length
so the breadth also should be reduced 3 times
Answer:
x = 4
Step-by-step explanation:
the simplest way to do that is to divide
12 / 18 = 2 / 3
then we move to the another square:
x / 6 = 2 / 3
x = 6 x 2 / 3
x = 4
.. ..
does not
Ether.
1-36. If y varies directly with x and y is 12 when x is 4, then
what is y when x is 8?
what is when x is 3?
what is x when y is 6?
a.
b.
n.
C.
Answer:
Step-by-step explanation:
Hello!
Y varies directly with X, meaning that every time X increases/ decreases, the value of Y is modified.
If Y=12 when X=4 then you can say that Y varies 3 times every time X varies 1 unit
12= 4*z
z=12/4= 3
So Y= 3x
With this in mind:
1) x= 8
Y= 3*8= 24
2) x= 3
Y= 3*3= 9
3) Y= 6
Y= 3x
x=Y/3= 6/3= 1
I hope this helps!
What is the unit price of a quart of juice for $0.79?
A. $3.16/gallon
B. 3 half-gallons for $5.40
C. $3.16/1b
D. 7 pints for $4.20
Answer:
a
Step-by-step explanation:
there are 4 quarts in a gallon.
4 times $0.79 =$3.16
If we increase the number 100 by 10% and then reduce the resulting number by 20% what would the answer be plz show how u did it and I will mark brainliest for the best explanation
Answer:
88
Step-by-step explanation:
The original number ⇒ 100
100 is increased by 10%
The result is 20% reduced.
Calculate increase.
100 × (1 + 10%)
100 × (1.1)
= 110
Calculate decrease.
110 × (1 - 20%)
110 × 0.8
= 88
The sum of two even consecutive integers is −46. If the smaller integer is divided by 4 and the larger integer is increased by 11, what is the product of the two resulting integers? PLEASE HELP!!!
Answer is 66.
I hope it will help you:)
Answer:
= 66
Step-by-step explanation:
The two integers are -22 and -24, because they are both even and consecutive, and adding them equals -46.
-24 divided by 4 is -6, and -22 plus 11 is -11
Now all we have to do is find the product (multiply -11 and -6)
And this gives us the answer: 66
HELP ME ASAP WITH MATH MONEY & WAGES
Answer:
96,220
Step-by-step explanation:
187,400 x .3 (30%)= 56,220
56220+40000= *96,220
Answer:
96,220
Step-by-step explanation:
187,400 x 0.3 = 56,220
56220+40000= 96,220
hope this helps, have a great day :)
4.3) Consider the following function. (If an answer does not exist, enter DNE.) f(x) = ln(4 − ln(x)) (a) Find the vertical asymptote(s). (Enter your answers as a comma-separated list.) x =
Answer: [tex]x=0\text{ and }x=e^4[/tex]
Step-by-step explanation:
The vertical asymptote is at the zero of the argument and at points where the argument approaches to ∞ .Given function: [tex]f(x) = \ln(4 - \ln(x))[/tex]
Since, [tex]\ln 0=\infty[/tex]
Here, if
[tex]f(x)\to \infty\\\Rightarrow\ 4-\ln x=0\Rightarrow\ln x=4\Rightarrow\ x=e^4\\\text{OR}\ln x=\infty\Rightarrow\ x=0[/tex]
Hence, the vertical asymptotes of f(x) are:
[tex]x=0\text{ and }x=e^4[/tex].
Using it's concept, it is found that the vertical asymptotes of the function are: [tex]\mathbf{x = 0, x = e^4}[/tex]
A vertical asymptote of a function f(x) are the values of x for which the function is outside it's domain.
For the ln function, that is, [tex]\ln{g(x)}[/tex], they are the values of x for which:
[tex]g(x) = 0[/tex]
In this problem, the function is:
[tex]f(x) = \ln{(4 - \ln{(x)})}[/tex]
For the inner function, x = 0 is a vertical asymptote, as [tex]\ln{0}[/tex] is outside the domain.
For the outer function:
[tex]4 - \ln{(x)} = 0[/tex]
[tex]\ln{(x)} = 4[/tex]
[tex]e^{\ln{(x)}} = e^4[/tex]
[tex]x = e^4[/tex]
A similar problem is given at https://brainly.com/question/23535769
Andrew is about to leave for school. If he walks at a speed of 50 meters per minute, he will arrive 3 minutes after the bell rings. If he runs at a speed of 80 meters per minute, he will arrive 3 minutes before the bell rings. In how many minutes will the bell ring?
Answer:
The answer is: 13 minutes
Step-by-step explanation:
First Let us form equations with the statements in the two scenario
[tex]time=\frac{distance}{speed}[/tex]
Let the time in which the bell rings be 'x'
1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes
[tex]3 + x =\frac{distance}{50}\\distance = 50(3+x) - - - - - (1)[/tex]
2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes
[tex]x - 3 = \frac{distance}{80} \\distance = 80(x-3) - - - - - (2)[/tex]
In both cases, the same distance is travelled, therefore, equation (1) = equation (2)
[tex]50(3+x)=80(x-3)[/tex]
[tex]150 +50x=80x-240\\[/tex]
Next, collecting like terms:
[tex]150 + 240 = 80x - 50x\\390 = 30x\\30x = 390\\[/tex]
dividing both sides by 3:
x = 390÷30 = 13
∴ x = 13 minutes
-5x-2y=-6
Slope:
y-intercept:
Answer:
Slope = m = -5/2
Y-intercept = b = -3
Step-by-step explanation:
[tex]-5x-2y = -6[/tex]
Getting it in a slope - intercept form:
[tex]-2y = 5x+6\\Dividing \ both \ sides \ by \ -2\\y = \frac{-5x}{2} + (-3)\\y = \frac{-5x}{2} -3\\[/tex]
Comparing it wit the slope intercept equation [tex]y = mx+b[/tex] we get
Slope = m = -5/2
Y-intercept = b = -3
This is a ratio question, is this correct?
Answer:
C
Step-by-step explanation:
Before expressing as a ratio the quantities must have the same denomination
$2 = 200 cents, thus
40 cents : $2
= 40 cents : 200 cents ( divide both parts by 40 )
= 1 : 5 → C
Need help i dont understand
Answer:
The answer is d
Step-by-step explanation:
Please answer it now in two minutes
Answer:
[tex]2\sqrt{33}[/tex].
Step-by-step explanation:
This triangle is a 30-60-90 triangle. That means that the hypotenuse is double the length of the smaller side.
Since the smaller side measures [tex]\sqrt{33}[/tex], the hypotenuse is [tex]2\sqrt{33}[/tex].
Hope this helps!
I need help answer quickly please this is timed! What is the product? Assume x greater-than-or-equal-to 0 (StartRoot 3 x EndRoot + StartRoot 5 EndRoot) (StartRoot 15 x EndRoot + 2 StartRoot 30 EndRoot)
Answer:
3x√5 + 6√10x + 5√3x + 10√6
Step-by-step explanation:
(√3x + √5)(√15x + 2√30)
The above expression can be evaluated as follow:
(√3x + √5)(√15x + 2√30)
Expand
√3x (√15x + 2√30) + √5(√15x + 2√30)
x√45 + 2√90x + √75x + 2√150
Express in the best possible surd form.
x•3√5 + 2•3√10x + 5√3x + 2•5√6
3x√5 + 6√10x + 5√3x + 10√6
We can not simplify further.
Therefore,
(√3x + √5)(√15x + 2√30) =
3x√5 + 6√10x + 5√3x + 10√6
Given that α and β are the roots of the quadratic equation [tex]2x^{2} +6x-7=p[/tex], and α=2β, a) find the value of p. b) form a quadratic equation with roots α+2 and β+2
Answer:
[tex]\large \boxed{\sf \ \ \ p=-11 \ \ \ }[/tex]
Step-by-step explanation:
Hello,
[tex]\alpha \text{ and } \beta \text{ are the roots of the following equation}[/tex]
[tex]2x^2+6x-7=p[/tex]
It means that
[tex]2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\[/tex]
And we know that
[tex]\alpha= 2\cdot \beta[/tex]
So we got two equations
[tex]2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\<=>8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\<=>6\beta^2+6\beta =0\\\\<=>\beta(\beta+1)=0\\\\<=> \beta =0 \ or \ \beta=-1[/tex]
For [tex]\beta =0, \ \ \alpha =0, \ \ p = -7[/tex]
For [tex]\beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11[/tex]
I assume that we are after two different roots so the solution for p is p=-11
b) [tex]\alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1[/tex]
So a quadratic equation with the expected roots is
[tex]x(x-1)=x^2-x[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Simplify. Rewrite the expression in the form 4^n. 4^11/4^-8
Answer:
S6tep-by-step explanation:
4^(11+8) = 4^19 is the solution
18a - 24ay + 48b - 64by
Answer:
Step-by-step explanation:
6a(3-4y)+16b(3-4y)
(6a-16b)(3-4y)
2(3a-8)(3-4y)