The braking force applied to Dizzy's car is approximately 50,600 Newtons in the opposite direction to the car's motion.
What is braking force?Braking force is the force applied by a vehicle's brakes to slow down or stop the vehicle. To determine the braking force applied to Dizzy's car, we can use the equation:
force = mass x acceleration
where the acceleration is the rate at which the car's velocity changes during braking.
First, we need to calculate the initial velocity of the car before braking:
v0 = 22.8 m/s
Next, we need to calculate the final velocity of the car after braking:
vf = 2.9 m/s
The change in velocity, or delta-v, is:
delta-v = vf - v0 = 2.9 m/s - 22.8 m/s = -19.9 m/s
Note that the negative sign indicates a decrease in velocity.
We also need to calculate the time it takes for the car to come to a stop. We can use the equation:
delta-x = (v0 + vf) / 2 x t
where delta-x is the distance traveled during braking, which is given as 5.55 m.
Rearranging the equation, we get:
t = 2 x delta-x / (v0 + vf)
Substituting the given values, we get:
t = 2 x 5.55 m / (22.8 m/s + 2.9 m/s) = 0.393 s
Now we can calculate the acceleration:
acceleration = delta-v / t = (-19.9 m/s) / (0.393 s) = -50.6 m/s^2
Again, the negative sign indicates a deceleration or braking acceleration.
Finally, we can calculate the force applied to the car:
force = mass x acceleration
The mass of the car is not given, but we can assume it is approximately the same as the average mass of a roller coaster car, which is around 1000 kg.
Substituting the values, we get:
force = 1000 kg x (-50.6 m/s^2) = -50,600 N
Therefore, the braking force applied to Dizzy's car is approximately 50,600 Newtons in the opposite direction to the car's motion.
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life stage what is fusing where? what is supporting the core of the star against gravitational collapse? protostar a) (choose one) nothing. helium in a shell. helium in the core. hydrogen in a shell. hydrogen in the core. b) (choose one) nothing. thermal pressure. radiation pressure. degeneracy pressure. main sequence star c) (choose one) nothing. helium in a shell. helium in the core. hydrogen in a shell. hydrogen in the core. d) (choose one) nothing. thermal pressure. radiation pressure. degeneracy pressure. red giant (subgiant) e) (choose one) nothing. helium in a shell. helium in the core. hydrogen in a shell. hydrogen in the core. f) (choose one) nothing. thermal pressure. radiation pressure. degeneracy pressure.
Life stage refers to the specific phase or period in the evolution of a star. When a protostar is forming, it undergoes a process called "fusing," where hydrogen in its core is converted into helium through nuclear fusion. The correct option is (C).
During fusing, the supporting force that prevents the protostar from collapsing under its own gravity is thermal pressure. As the protostar continues to evolve and grow in mass, it eventually becomes a main sequence star. At this stage, hydrogen continues to fuse in the core, and the supporting force against gravitational collapse is still thermal pressure.
After the main sequence phase, the star may evolve into a red giant or subgiant, during which it fuses helium in the core and/or shell. The supporting force at this stage is degeneracy pressure, which is a result of the electrons being squeezed together so tightly that they resist further compression.
In conclusion, the supporting force against gravitational collapse varies depending on the life stage of the star. During the protostar and main sequence phases, thermal pressure is the supporting force, while degeneracy pressure is the supporting force during the red giant or subgiant phase.
a) Protostar:
- Fusing: Hydrogen in the core.
- Supporting the core against gravitational collapse: Thermal pressure.
b) Main Sequence Star:
- Fusing: Hydrogen in the core.
- Supporting the core against gravitational collapse: Thermal pressure and radiation pressure.
c) Red Giant (Subgiant):
- Fusing: Helium in the core and hydrogen in a shell.
- Supporting the core against gravitational collapse: Radiation pressure and degeneracy pressure.
Therefore, the considering option is (C).
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if a plunge pool undercuts the support of the resistant rock layer above and causes it to collapse, then the
If a plunge pool undercuts the support of the resistant rock layer above and causes it to collapse, then this can result in a potentially dangerous situation, the collapse can cause erosion of the surrounding soil and vegetation, leading to further instability of the area.
The collapse of the resistant rock layer can lead to a landslide or rockfall, which can cause significant damage to the surrounding area and pose a threat to anyone in the vicinity. Additionally, the collapse can cause erosion of the surrounding soil and vegetation, leading to further instability of the area.
To prevent such occurrences, it is important to properly design and maintain plunge pools. The proper design includes ensuring that the pool is not located near a resistant rock layer or if it is, that measures are put in place to prevent the pool from undercutting the rock.
This may include reinforcing the rock layer, installing retaining walls or other support structures, or moving the pool to a different location.
Regular maintenance of the plunge pool is also crucial to prevent erosion and undercutting of the rock layer. This may involve monitoring the pool for signs of erosion or instability and taking corrective action if necessary, such as repairing or reinforcing the surrounding area.
Overall, it is important to ensure that plunge pools are designed and maintained properly to prevent the undercutting of resistant rock layers and potential collapses, which can have serious consequences.
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in an interference experiment of the young type, the distance between slits is 0.5 mm, and the wavelength of the light is 600 nm. a) if it is desired to have a fringe spacing of 1 mm at the screen, what is the proper screen distance? b) if a thin plate of glass (n
a) The proper screen distance is 0.83 meters.
b) The lateral fringe displacement at the screen is 0.08 millimeters.
a)To find the proper screen distance (D) for a fringe spacing (x) of 1 mm, we can use the formula for fringe spacing in a double-slit interference experiment:
x = (λD) / d
Where x is the fringe spacing, λ is the wavelength of the light, D is the screen distance, and d is the distance between the slits. Plugging in the given values (converting units to meters):
0.001 m = (600 x [tex]10^{-9}[/tex] m * D) / 0.0005 m
Now, we can solve D:
D = (0.001 m * 0.0005 m) / (600 x [tex]10^{-9}[/tex] m)
D = 0.83 m
So, the proper screen distance is approximately 0.83 meters.
b) When a thin plate of glass is placed over one of the slits, the path length of the light passing through that slit is increased by the thickness of the glass, causing a phase shift.
This phase shift will cause the interference pattern to shift laterally.
To find the lateral fringe displacement, we can use the formula:
Δy = (tλ)/(nd)
where t is the thickness of the glass, n is the refractive index of the glass, and d is the distance between the slits.
Plugging in the values given, we get:
Δy = (100 μm)(600 nm)/(1.5)(0.5 mm) = 0.08 mm
Therefore, the lateral fringe displacement at the screen is 0.08 millimeters.
The Question was Incomplete, Find the full content below :
In an interference experiment of the Young type the distance between slits is 0.5 mm and the wavelength of the light is 600 nm. a) If it is desired to have a fringe spacing 1 mm at the screen, what is the proper screen distance? b) If a thin plate of glass n=(1.5) of thickness 100 μm is placed over one of the slits, what is the lateral fringe displacement at the screen?
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a positive point charge of 0.00044 c is located 2 m from another positive point charge of 5.281454e-5 c. their electric potential energy is
To calculate the electric potential energy between two positive point charges, we will use the formula:
Electric potential energy (U) = (k * q1 * q2) / r
where k is the electrostatic constant (8.99 x 10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges (0.00044 C and 5.281454 x 10^-5 C), and r is the distance between the charges (2 m).
1. Plug in the values into the formula:
U = (8.99 x 10^9 N m^2/C^2) * (0.00044 C) * (5.281454 x 10^-5 C) / (2 m)
2. Calculate the product of the charges and the electrostatic constant:
(8.99 x 10^9 N m^2/C^2) * (0.00044 C) * (5.281454 x 10^-5 C) = 207.06092464 J m/C^2
3. Divide the product by the distance between the charges:
207.06092464 J m/C^2 / 2 m = 103.53046232 J
The electric potential energy between the two positive point charges is approximately 103.53 Joules.
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For a satellite to orbit Earth at a constant distance, its centrifugal acceleration must be equal and opposite Earth's gravitational acceleration. If a satellite is to orbit at a constant distance from Earth at a circular radius of 8,000,000 m, what is the required velocity of the satellite? (Assume the acceleration due to Earth's gravity is 6.2 m/s2 at this altitude.).
The required velocity of the satellite to orbit Earth at a constant distance of 8,000,000 m is 7,905 m/s.
What is Gravity?
Gravity is a force that attracts two bodies with mass towards each other. It is one of the four fundamental forces of nature and is responsible for holding planets in orbit around stars and stars in orbit around galaxies. Gravity is described by Einstein's theory of general relativity, which states that gravity is the result of the curvature of spacetime caused by the presence of mass or energy.
where G is the gravitational constant M is the mass of the Earth and r is the distance between the satellite and the center of the Earth (8,000,000 m).
First, we need to calculate the gravitational acceleration due to the Earth's gravity at this altitude using the formula:
g = GM/[tex]r^{2}[/tex]
g = (6.67 x 10^-11 N [tex]m^{2}[/tex]/[tex]kg^{2}[/tex]) x (5.97 x [tex]10^{24}[/tex] kg) / (8,000,000 m)^2
g = 6.19 m/[tex]s^{2}[/tex]
The required velocity can be found using:
v = √(GM/r)
v = √[(6.67 x 10^-11 N[tex]m^{2}[/tex]/[tex]kg^{2}[/tex]) x (5.97 x [tex]10^{24}[/tex] kg) / (8,000,000 m)]
v = 7,905 m/s
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part a what is the highest order that contains the entire visible spectrum? (the wavelength range of the visible spectrum is approximately 400-700 nm .)
The highest order that contains the entire visible spectrum is the first order. The visible spectrum is the range of wavelengths of light that are visible to the human eye.
The first order is the smallest wavelength range that contains the entire visible spectrum, which ranges from approximately 400-700 nm.
This is because the visible spectrum is a relatively small range of the electromagnetic spectrum compared to other regions, such as radio waves or X-rays.
When light is diffracted through a diffraction grating, the first order is the most commonly used order as it contains the majority of the visible spectrum.
However, higher orders can also contain parts of the visible spectrum, but they are less commonly used as they contain smaller ranges of wavelengths.
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a particle with a cahrge of 1 c is moving at 45 angle with respect to the positive x axis in teh horizontal xy-plane. the velocity of the charge is 1 m/s. a magnetic field of 1 t is directed in the negative x direction. what is the magnetic force acting on the charge?
The magnetic force acting on the charged particle is -0.707 N in the k direction and 0.707 N in the j direction.
In this problem, the charge of the particle is given as 1 C, and the velocity of the particle is 1 m/s at an angle of 45 degrees to the positive x-axis. We can break down the velocity vector into its x and y components as follows:
vx = vcos(45) = 0.707 m/s
vy = vsin(45) = 0.707 m/s
The magnetic field is given as 1 T in the negative x direction.
Substituting these values into the formula for the magnetic force, we get:
F = q * (vxi + vyj + 0k) x (-Bi)
where I, j, and k are the unit vectors in the x, y, and z directions, respectively.
Expanding the cross product, we get:
F = q*(-vxB)k + qvyB*j
Substituting the values for q, vx, vy, and B, we get:
F = (1 C) (-0.707 m/s) (1 T) k + (1 C) (0.707 m/s) *(1 T) *j
Simplifying, we get:
F = -0.707 k + 0.707 j
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if a water wave vibrates up and down 3 times each second and the distance between wave crest is 2.5 what is the wavelength of the wave
what is the frequency of the wave?
What is the wavelength of the wave?
What is the speed of the wave
Therefore, the frequency of the wave is three Hz, the wavelength is 2 meters, and the wave speed is 6 meters per second.
What is the system for frequency of a wave?f=vλ
If the wavelength and speed of a wave are known, these can be used to locate the frequency of a wave the usage of the equation f=vλ f = v λ , the place λ is the wavelength in meters and v is the pace of the wave in m/s. This also gives the frequency of the wave in Hertz.
Wave pace is associated to wavelength and wave frequency by means of the equation: Speed = Wavelength x Frequency. This equation can be used to calculate wave pace when wavelength and frequency are known.
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https://brainly.com/question/254161#SPJ1starting from rest, a disk rotates about its central axis with constant angular acceleration. in 5.0 s, it rotates 50 rad. what is the instantaneous angular velocity of the disk at the end of the 20.0 s?
The instantaneous angular velocity is 20.0 s is 400 rad/s.
What is the final instantaneous angular velocity of a disk rotating about its central axis with constant angular acceleration?Since the angular acceleration is constant, we can use the formula:
[tex]θ = 1/2 * α * t^2 + ω0 * t[/tex]
where
[tex]θ = angle rotated = 50 rad[/tex]
[tex]α = angular acceleration[/tex]
[tex]t = time = 5.0 s[/tex]
[tex]ω0 = initial angular velocity = 0 (starting from rest)[/tex]
Solving for α, we get:
[tex]α = 2 * (θ - ω0 * t) / t^2 = 2 * 50 rad / 5.0 s^2 = 20 rad/s^2[/tex]
Now, using the formula:
[tex]ω = α * t + ω0[/tex]
where
ω = instantaneous angular velocity at the end of 20.0 s (what we need to find)
[tex]α = angular acceleration = 20 rad/s^2[/tex]
[tex]t = time = 20.0 s[/tex]
[tex]ω0 = initial angular velocity = 0 (starting from rest)[/tex]
we get:
[tex]ω = 20 rad/s^2 * 20.0 s + 0 = 400 rad/s[/tex]
Therefore, the instantaneous angular velocity of the disk at the end of 20.0 s is 400 rad/s.
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using the rule of thumb method, what sized furnace (rated value, whole btuh) would you need to heat a 3,200 ft2 passive solar home in austin, texas?
A furnace with a rated value of 96,000 - 128,000 BTU per hour would be needed to heat a 3,200 ft2 passive solar home in Austin, Texas, using the rule of thumb method.
The rule of thumb method for sizing a furnace is to estimate the required heating capacity based on the square footage of the home. A common guideline is to have a furnace with a heating capacity of 30-40 BTU per square foot.
For a 3,200 ft2 passive solar home in Austin, Texas, we can estimate the required heating capacity as follows:
Heating capacity = (30-40) BTU per square foot x 3,200 square feet
Heating capacity = 96,000 - 128,000 BTU per hour
Therefore, a furnace with a rated value of 96,000 - 128,000 BTU per hour would be needed to heat a 3,200 ft2 passive solar home in Austin, Texas, using the rule of thumb method.
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what is the longest-wavelength electromagnetic radiation that can eject a photoelectron from silver? is this in the visible range?
The radiation that can eject a photoelectron from silver is not visible to the human eye.
The longest wavelength electromagnetic radiation that can eject a photoelectron from silver is determined by the work function of silver, which is 4.7 electron volts (eV). Using the formula λ = hc/E, where λ is the wavelength, h is Planck's constant, c is the speed of light, and E is the energy of the photon, we can calculate that the longest wavelength radiation is approximately 263 nanometers, which is in the ultraviolet range. This wavelength is shorter than the visible range, which is approximately 400-700 nanometers.
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What does it mean when we say our sense of motion depends on our frame of reference? Include the phrases “fixed frame” and “moving frame” in your answer.
frame of reference that is not inertial. A non-inertial frame is now defined as a frame that accelerates relative to the underlying inertial reference frame. Newton's law won't be valid.
How does the framework function?
Performance could change depending on the lighting. The Frame automatically modifies the Plasma tvs brightness and contrasting settings after analyzing the lighting conditions in the room and the light level of your content.
What distinguishes a system from a frame?
the hard architecture (bones and condyle) that serves as an animal's body's framework. skeletal system, skeleton, and systema skeletale. system: a collection of organs or bodily parts that function or are anatomically related; "the body contains a system for organs for digestion."
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The school bus slows from 60 km/h to 40 km/h when entering the school zone.
Given that this change of speed occurred over 8 seconds, calculate the average deceleration of the bus.
To calculate the average deceleration of the bus, we can use the following formula:
Average deceleration = (Final velocity - Initial velocity) / Time takenHere, the initial velocity (v1) is 60 km/h, the final velocity (v2) is 40 km/h, and the time taken (t) is 8 seconds. To make the units consistent, we'll convert the velocities from km/h to m/s.
1 km/h = 1000 m / 3600 s = 5/18 m/sv1 = 60 km/h * (5/18) = (60 * 5) / 18 = 50/3 m/s v2 = 40 km/h * (5/18) = (40 * 5) / 18 = 100/9 m/sNow, we can plug the values into the formula:
Average deceleration = (v2 - v1) / t Average deceleration = ((100/9) - (50/3)) / 8Now, we'll find a common denominator for the fractions and simplify:
Average deceleration = ((300 - 450) / 27) / 8 = (-150 / 27) / 8Lastly, we'll divide the fraction by 8:Average deceleration = -150 / (27 * 8) = -150 / 216So, the average deceleration of the bus is approximately -150/216 m/s².
4. the magnitude of a magnetic field a distance 3.0 micrometers from a wire is 20.0 x 10-4 t. how much current is flowing through the wire. assume the wire is the only contributor to the magnetic field.
The current flowing through the wire is 3.0 A.
The magnitude of the magnetic field around a current-carrying wire at a distance r from the wire is given by the formula:
[tex]B = \frac{\mu_0 I}{2 \pi r}[/tex]
where B is the magnetic field, μ₀ is the permeability of free space ([tex]4\pi \times 10^{-7} \text{T}\cdot\text{m}/\text{A}[/tex]), I is the current flowing through the wire, and π is the mathematical constant pi (approximately 3.14).
To solve for the current I, we can rearrange the formula as follows:
[tex]I = \frac{2 \pi r B}{\mu_0}[/tex]
Plugging in the given values, we get:
[tex]I = \frac{2 \pi (3.0 \times 10^{-6}\text{ m}) (20.0 \times 10^{-4}\text{ T})}{4\pi \times 10^{-7}\text{ T}\cdot\text{m}/\text{A}}[/tex]
Simplifying the expression and cancelling out the units, we get:
[tex]I = 3.0 A[/tex]
Therefore, the current flowing through the wire is 3.0 A.
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A SHM has the equation y = 2.0cos 4t+ 45) What is the initial phase angle? b) What is the displacement at t=0 s? c) Calculate velocity at t=0 s. d) What is the maximum velocity?
a) The initial phase angle is 45 degrees, (b) displacement at t=0 s is 1.414 m, (c) the velocity at t=0 s is -5.656 m/s, (d) maximum velocity is 1.568 m/s.
What is simple harmonic motion (SHM)?Simple harmonic motion (SHM) is a type of periodic motion in which an object oscillates back and forth around a central point with a constant amplitude and a sinusoidal pattern.
The equation of a simple harmonic motion (SHM) is given by:
y = A cos(ωt + φ)
where A is the amplitude, ω is the angular frequency, t is the time, and φ is the phase angle.
Comparing with the given equation, we have:
A = 2.0
ω = 4
φ = 45 degrees
a) The initial phase angle is 45 degrees.
b) To find the displacement at t=0 s, we substitute t=0 in the given equation:
y = 2.0 cos(4t + 45)
y = 2.0 cos(45)
y = 1.414 m
Therefore, the displacement at t=0 s is 1.414 m.
c) To find the velocity at t=0 s, we differentiate the given equation with respect to time:
v = dy/dt = -2.0ω sin(ωt + φ)
Substituting t=0, we get:
v = -2.0 x 4 sin(45)
v = -8.0 x 0.707
v = -5.656 m/s (Note: the negative sign indicates that the direction of the velocity is opposite to the direction of the displacement)
Therefore, the velocity at t=0 s is -5.656 m/s.
d) To find the maximum velocity, we differentiate the given equation with respect to time and set it equal to zero (since the maximum velocity occurs when the displacement is zero):
v = -2.0ω sin(ωt + φ) = 0
Solving for t, we get:
ωt + φ = nπ (where n is an integer)
4t + 45 = nπ
t = (nπ - 45)/4
At t=0, n=1, so:
t = (1π - 45)/4 = -11.25 degrees
(Note: the negative sign indicates that the displacement is at its maximum position, whereas the velocity is zero)
Substituting this value of t in the expression for velocity, we get:
v = -2.0 x 4 sin(-11.25 + 45)
v = 8.0 x 0.196
v = 1.568 m/s
Therefore, the maximum velocity is 1.568 m/s.
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a 30.00 ml sample of 0.125 m hcooh is being titrated with 0.175 m naoh. what is the ph after 15.0 ml of naoh has been added? ka of hcooh = 1.8 × 10−4
The pH after 15.0 mL of 0.175 M NaOH has been added is 11.58.
The balanced equation for the reaction between formic acid (HCOOH) and sodium hydroxide (NaOH) is:
[tex]HCOOH + NaOH $\rightarrow$ NaCOOH + H$_2$O[/tex]
First, we need to determine how many moles of HCOOH are present in the initial 30.00 mL sample:
moles of HCOOH = (0.125 mol/L) x (0.03000 L) = 0.00375 mol
Next, we can use the stoichiometry of the reaction to determine how many moles of NaOH are required to neutralize all of the HCOOH:
1 mol HCOOH reacts with 1 mol NaOH
moles of NaOH = 0.00375 mol
Now, we can calculate the concentration of NaOH after 15.0 mL has been added:
final volume = 30.00 mL + 15.0 mL = 45.00 mL = 0.04500 L
moles of NaOH = (0.175 mol/L) x (0.01500 L) = 0.002625 mol
initial moles of HCOOH = 0.00375 mol
moles of HCOOH remaining after reaction = 0.00375 mol - 0.002625 mol = 0.001125 mol
The concentration of HCOOH at this point is:
[HCOOH] = 0.001125 mol / 0.04500 L = 0.025 M
The Ka expression for formic acid is:
Ka = [H+][HCOO-] / [HCOOH]
We can assume that the [H+] concentration is equal to the [OH-] concentration at this point, since the reaction is at the equivalence point. Therefore:
Ka = (x)(x) / 0.025
where x is the concentration of [OH-].
Solving for x, we get:
x = sqrt(Ka*[HCOOH]) = sqrt(([tex]1.8x10^-4[/tex])*(0.025)) = 0.003794
pOH = -log[OH-] = -log(0.003794) = 2.42
pH = 14.00 - pOH = 11.58
Therefore, the pH after 15.0 mL of 0.175 M NaOH has been added is 11.58.
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NEED HELP PLEASE.
QUESTION: imagine that you carry a box of books, weighing 67.8 N, up a flight of stairs. if each step is 15.0 cm high, and there are 22 steps in the flight of stairs, how much work do you do on the box of books
Answer:
The answer for Work done is ≈224J or 224Nm
Explanation:
Work done=F×D
F=mg
F=W
d=15×22=330cm=3.3m
W=67.8×3.3
W=223.74J or 223.7Nm
W≈224J or 224 Nm
A 20 Kg bike accelerates at 10 m/s^2. With what force was the person pedaling
Newton's first law of motion states that an object in motion will stay in motion unless acted upon by a force.
What are two forces on earth that could change the motion of the object?
Responses
friction and gravity
friction and gravity
speed and acceleration
heat and light
direction and time
The two forces on Earth that could change the motion of an object are friction and gravity.
Friction is a force that opposes the motion of an object when it is in contact with another surface. It can cause an object to slow down or come to a stop.
Gravity is a force of attraction between two objects, and it can cause an object to accelerate toward the center of the earth or towards another massive object. The gravitational force on an object depends on its mass and the distance between it and the other object.
Speed and acceleration are not forces, but rather measures of motion. Heat and light are also not forces that can change the motion of an object, but rather forms of energy that can be transferred to an object and affect its temperature or behavior. Direction and time are not forces, but concepts related to an object's motion.
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a certain pendulum on earth has a period of 1.1 s. what would be the period of this pendulum if it were taken to another planet that had 2.5 times the mass of the earth and 2 times the earth's radius? express your answer in seconds to three significant digits.
The period of the pendulum on this planet would be 2.51 seconds to three significant digits.
The period of a pendulum is given by the formula:
T = 2π√(L/g)
where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
Since the length of the pendulum is not changing, we can see that the period is directly proportional to the square root of the acceleration due to gravity.
On the other planet, the acceleration due to gravity will be:
[tex]g' = (GM')/r'^2[/tex]
where G is the gravitational constant, M' is the mass of the planet, and r' is the radius of the planet.
We are told that this planet has 2.5 times the mass of the Earth and 2 times the Earth's radius. Therefore,
[tex]M' = 2.5M[/tex]
[tex]r' = 2r[/tex]
Substituting these values into the formula for g', we get:
[tex]g' = (GM')/r'^2 = (G(2.5M))/(4r^2) = (5/8)g[/tex]
So the acceleration due to gravity on this planet is (5/8) times the acceleration due to gravity on Earth.
Using the formula for the period of a pendulum, we can see that the period of the pendulum on this planet would be:
[tex]T' = 2π√(L/g') = 2π√(L/(5/8)g) = 2.51s[/tex]
Therefore, the period of the pendulum on this planet would be 2.51 seconds to three significant digits.
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The potential energy of an apple is 6.0 Joules. The apple is 1.22m high. What is the mass of the apple?
Answer:
The mass of the apple is 0.49kg
Explanation:
Potential energy=mgh
P=mgh
6=m×1.22×10
6=12.2m
divide both sides by 12.2
m=6/12.2
m=0.49kg
describe the relationship between the angle of incoming light and the percentage of light that is transmitted through the water versus the percentage of light that is reflected
The angle of incoming light plays a significant role in determining the percentage of light that is transmitted through water versus the percentage of light that is reflected. As the angle of incidence of light increases, the amount of light that is transmitted through the water decreases, while the amount of light that is reflected off the surface of the water increases.
This is due to the fact that at higher angles of incidence, the light has to travel through more water, which causes it to be absorbed and scattered more, leading to a decrease in the amount of transmitted light. Additionally, the angle of incidence also affects the polarization of the reflected light, which can impact the amount of light that is reflected.Overall, the relationship between the angle of incoming light and the percentage of light that is transmitted versus reflected is complex and depends on a variety of factors, including the properties of the water, the characteristics of the light, and the angle of incidence.To learn more about angle of incidence please visit:
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satellite motion: if earth had twice its present mass but it orbited at the same distance from the sun as it does now, its orbital period would be 1 year 1,5 year 2 year 2,5 year
The orbital period of the Earth around the Sun is determined by its distance from the Sun and its mass. If the Earth had twice its present mass but orbited at the same distance from the Sun, its gravitational attraction to the Sun would be stronger, resulting in a longer orbital period. Using Kepler's third law of planetary motion, we can calculate the new orbital period as follows:
T^2 = (4π^2/G) x (r^3/m)
where T is the orbital period, G is the gravitational constant, r is the distance from the Earth to the Sun, and m is the mass of the Earth.
Plugging in the values, we get:
T^2 = (4π^2/6.6743 x 10^-11) x [(149.6 x 10^6)^3 / (2 x 5.9722 x 10^24)]
T^2 = 1.085 x 10^20
T = √(1.085 x 10^20)
T = 1.09 x 10^10 seconds
Converting this to years, we get:
T = 346 years
Therefore, if the Earth had twice its present mass but orbited at the same distance from the Sun as it does now, its orbital period would be approximately 346 years.
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a skydiver reaches terminal velocity during her dive. which statements are correct about her motion while she is traveling at terminal velocity?multiple select question.there are now no forces acting on her.there is no net force acting on her.she is no longer accelerating.the air resistance force is equal in magnitude to her weight.she has stopped moving.she is still accelerating downward.
A skydiver reaches terminal velocity during her dive. At terminal velocity, the correct statements about her motion are b. there is no net force acting on her, c. she is no longer accelerating, and d. the air resistance force is equal in magnitude to her weight
There is no net force acting on her, when a skydiver reaches terminal velocity, the air resistance force acting on her is equal in magnitude to her weight (gravitational force). This means the net force acting on her becomes zero. She is no longer accelerating, as there is no net force acting on the skydiver, she is no longer accelerating. At terminal velocity, the skydiver moves at a constant speed.
The air resistance force is equal in magnitude to her weight, when a skydiver reaches terminal velocity, the air resistance force acting against her motion is equal to her weight (gravitational force). This balance of forces is what keeps her from accelerating further. A skydiver reaches terminal velocity during her dive. At terminal velocity, the correct statements about her motion are b. there is no net force acting on her, c. she is no longer accelerating, and d. the air resistance force is equal in magnitude to her weight.
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two masses are separated by a distance r. if the distance is doubled how does the force between them change, if at all?multiple choiceit doubles.it quadruples.it halves.it is reduced by a factor of 4.it remains the same.
The force between two masses decreases by a factor of 4 when the distance between them is doubled because the gravitational force weakens with distance, following an inverse square law.
The formula for the force between two masses is F = G(m1m2)/r^2, where G is the gravitational constant, m1 and m2 are the masses, and r is the distance between them. When the distance between the masses is doubled, the denominator of the equation becomes 4 times larger, resulting in a force that is 1/4th of the original force. Therefore, the force between the two objects decreases by a factor of 4 when the distance between them is doubled.
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a crane uses a block and tackle to lift a 2000 N flagstone to a height of 30 m. How much work is done on the flagstone
which force pairs must be equal because they are action/reaction pairs?multiple select question.the upward normal force on a car and the downward push of the car on the ground.the rightward force of a pull on a box traveling at constant velocity and the leftward friction force.the upward normal force on a book at rest on the table and its downward weight.the rightward force of you pushing on a wall and the leftward force of the wall pushing on you.
Force pairs that must be equal because they are action/reaction pairs. According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. This means that action and reaction forces are always equal in magnitude but opposite in direction.
Some examples of action/reaction force pairs include:
1. When you push a book across a table (action), the book pushes back with an equal force (reaction).
2. When a person jumps off a diving board (action), the diving board exerts an equal and opposite force on the person (reaction).
3. A person walking on the ground pushes against the ground (action), and the ground pushes back with an equal force (reaction).
In all these cases, the action/reaction force pairs are equal and opposite, illustrating Newton's Third Law of Motion.
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a piece of wood is has a density of 0.600 g/cm3. when dipped in water, what fraction of the wood is submerged inside water? (give answer to 3 significant figures)
To determine the fraction of the wood submerged in water, we need to compare the density of the wood to the density of water.
The density of water is 1.000 g/cm3 at standard temperature and pressure.
If the wood has a density of 0.600 g/cm3, it is less dense than water, which means it will float on water.
To determine the fraction of the wood submerged in water, we can use the following formula:
fraction submerged = (volume submerged) / (total volume)
Since the wood floats on water, the volume of water displaced by the wood is equal to the volume of the submerged portion of the wood.
The total volume of the wood is equal to its mass divided by its density:
total volume = mass / density
We don't have the mass of the wood, but we can use any arbitrary value to determine the fraction submerged.
Let's assume the wood has a mass of 100 g.
total volume = mass / density = 100 g / 0.600 g/cm3 = 166.67 cm3
Now, let's assume that when the wood is submerged in water, it displaces 80 cm3 of water.
fraction submerged = (volume submerged) / (total volume) = 80 cm3 / 166.67 cm3 = 0.48
Therefore, approximately 48% of the wood is submerged in water.
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polaris and the star at the other end of the little dipper, kochab, are both apparent magnitude 2. in a photo of the night sky, they would appear similar to how they appear here in a planetarium simulation: larger than other stars. this is because
Polaris and Kochab's apparent magnitude of 2 and their proximity to the celestial pole make them appear larger in a photo or planetarium simulation compared to other stars.
A comparatively brilliant star as compared to other stars in the night sky, Kochab and Polaris both have an apparent magnitude of 2, making them both bright stars. In addition, they are both close to the celestial pole, which gives them a motionless appearance in the sky while giving the impression that other stars are rotating around them.
They stand out in the night sky because of their fixed location and brightness, and because of their brightness and proximity to the celestial equator, they look bigger than other stars in pictures or planetarium simulations.
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An asteroid is 4. 5 times as far from the sun as the earth. What is the period of that asteroid in terms of earth years?
The period of the asteroid in terms of Earth years is approximately 8.13 years. This means that it takes the asteroid 8.13 years to complete one orbit around the sun, while the Earth takes one year to complete its orbit.
To determine the period of an asteroid orbiting the sun, we can use Kepler's Third Law, which states that the square of the period of an object in orbit around the sun is proportional to the cube of its average distance from the sun. Mathematically, this can be expressed as:
[tex]\frac{(T_{\text{asteroid}})^2}{(T_{\text{earth}})^2} = \left(\frac{d_{\text{asteroid}}}{d_{\text{earth}}}\right)^3[/tex]
where T is the period of the asteroid and earth respectively, and d is the average distance from the sun.
Given that the asteroid is 4.5 times farther from the sun than the Earth, we can plug this ratio into the equation:
[tex]\frac{(T_{\text{asteroid}})^2}{(1 \text{ year})^2} = 4.5^3[/tex]
Solving for T asteroid, we get:
[tex](T_{\text{asteroid}})^2 = 4.5^3[/tex]
[tex]T_{\text{asteroid}} = \sqrt{4.5^3}[/tex] = 8.13 years
It is important to note that this calculation assumes a circular orbit, which is not always the case for asteroids.
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