Question 9(Multiple Choice Worth 2 points)
(Creating Graphical Representations LC)
A teacher was interested in the subject that students preferred in a particular school. He gathered data from a random sample of 100 students in the school and wanted to create an appropriate graphical representation for the data.
Which graphical representation would be best for his data?
Stem-and-leaf plot
Histogram
Circle graph
Box plot
Question 10(Multiple Choice Worth 2 points)
(Circle Graphs MC)
A New York City hotel surveyed its visitors to determine which type of transportation they used to get around the city. The hotel created a table of the data it gathered.
Type of Transportation Number of Visitors
Walk 120
Bicycle 24
Car Service 45
Bus 30
Subway 81
Which of the following circle graphs correctly represents the data in the table?
circle graph titled New York City visitor's transportation, with five sections labeled walk 80 percent, bus 16 percent, car service 30 percent, bicycle 20 percent, and subway 54 percent
circle graph titled New York City visitor's transportation, with five sections labeled walk 40 percent, bicycle 8 percent, car service 15 percent, bus 10 percent, and subway 27 percent
circle graph titled New York City visitor's transportation, with five sections labeled subway 40 percent, bus 8 percent, car service 15 percent, bicycle 10 percent, and walk 27 percent
circle graph titled New York City visitor's transportation, with five sections labeled subway 80 percent, bicycle 20 percent, car service 30 percent, bus 16 percent, and walk 54 percent
Question 11(Multiple Choice Worth 2 points)
(Circle Graphs LC)
Chipwich Summer Camp surveyed 100 campers to determine which lake activity was their favorite. The results are given in the table.
Lake Activity Number of Campers
Kayaking 15
Wakeboarding 11
Windsurfing 7
Waterskiing 13
Paddleboarding 54
If a circle graph was constructed from the results, which lake activity has a central angle of 54°?
Kayaking
Wakeboarding
Waterskiing
Paddleboarding
Question 12(Multiple Choice Worth 2 points)
(Making Predictions MC)
A recent conference had 750 people in attendance. In one exhibit room of 70 people, there were 18 teachers and 52 principals. What prediction can you make about the number of principals in attendance at the conference?
There were about 193 principals in attendance.
There were about 260 principals in attendance.
There were about 557 principals in attendance.
There were about 680 principals in attendance.
Question 13(Multiple Choice Worth 2 points)
(Making Predictions MC)
A college cafeteria is looking for a new dessert to offer its 4,000 students. The table shows the preference of 225 students.
Ice Cream Candy Cake Pie Cookies
81 9 72 36 27
Which statement is the best prediction about the number of cookies the college will need?
The college will have about 480 students who prefer cookies.
The college will have about 640 students who prefer cookies.
The college will have about 1,280 students who prefer cookies.
The college will have about 1,440 students who prefer cookies.
Question 15
The line plots represent data collected on the travel times to school from two groups of 15 students.
A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 4, 6, 14, and 28. There are two dots above 10, 12, 18, and 22. There are three dots above 16. The graph is titled Bus 47 Travel Times.
A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 8, 9, 18, 20, and 22. There are two dots above 6, 10, 12, 14, and 16. The graph is titled Bus 18 Travel Times.
Compare the data and use the correct measure of center to determine which bus typically has the faster travel time. Round your answer to the nearest whole number, if necessary, and explain your answer.
Bus 18, with a median of 13
Bus 47, with a median of 16
Bus 18, with a mean of 13
Bus 47, with a mean of 16
1) A histogram would be the best graphical representation for the teacher's data on the subject preferences of students. 2) The correct circle graph is option 2. 3) Option 4: Paddleboarding.
What is a histogram?The frequency or relative frequency of the data points falling within each interval is depicted by the height of the bars in a histogram, which is a graphical representation of the distribution of continuous data. Histograms are frequently used in data analysis to show how a single variable is distributed and to spot any patterns or trends. Additionally, they can be used to compare the distributions of two or more variables or to spot anomalies or outliers in the data.
1) A histogram would be the best graphical representation for the teacher's data on the subject preferences of students.
2) Given the type of transportation we have he total number of visitors as:
(120+24+45+30+81=300)
Now, for walk we have:
120/300 = 40/100 = 40%
For Bicycle we have:
24/300 = 8%
Thus, the correct circle graph is option 2: circle graph titled New York City visitor's transportation, with five sections labeled walk 40 percent, bicycle 8 percent, car service 15 percent, bus 10 percent, and subway 27 percent
3) For the central angle to be 54 the number of campers needs to correspond to this number. The activity that corresponds to 54 degrees is Paddleboarding.
4) For the number of principals in conference we set up a proportionality with total people as follows:
We know that, 52 principals out of 70 people thus:
52/70 = x/750
Now,
x = (52/70) * 750
x = 557.14
Hence, we can predict that there were about 557 principals in attendance at the conference.
5) Given that, out of 225 students 27 prefer cookies thus,
27/225 = 0.12
That is 12% students like cookies.
Now, for the total number of students we have:
0.12 * 4000 = 480
Thus, option A: The college will have about 480 students who prefer cookies.
6) For the given description of the line plot the median is:
For Bus 47 = 16
For Bus 18 = 13
The faster bus is Bus 47, with a median of 16.
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Given that £1 = $1.62
a) How much is £650 in $?
b) How much is $405 in £?
Answer:
a 1053
b 250
multiply 650 by 1.62 for part a.
for part b divide by 1.62 since pound is less than dollar
hope this helps :)
HURRY 40 POINTS!!
What is the surface area of this right rectangular prism?
Enter your answer as a mixed number in simplest form by filling in the boxes.
ft²
The surface area of the rectangular prism is 29 2/3 ft²
How to determine the surface areaThe formula for calculating the surface area of a rectangular prism is expressed as;
SA = 2(wl + hw + hl)
Where the parameters are;
SA is the surface areaw is the width of the prismh is the height of the prisml is the length of the prismFrom the information given, we have that;
Wl = 3 × 5/2
multiply the values
wl = 15/2
hw = 4/3 × 3
hw = 4
hl = 4/3 × 5/2 = 20/6 = 10/3
Substitute the values
Surface area = 2(4 + 10/3 + 15/2)
Surface area = 2(24 + 20 + 45/6)
Surface area = 2(89)/6
Surface area = 89/3 = 29 2/3 ft²
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the rule T(-3,1) is applied to point 2,-7 in which part of the coordinate system is the translated point
the translated point is located in the third quadrant of the coordinate system, since both coordinates are negative.
What is Cartesian coordinate?
A coordinate system, also known as a Cartesian coordinate system, is a system used to describe the position of points in space. It is named after the French mathematician and philosopher René Descartes, who introduced the concept in the 17th century. In a coordinate system, each point is assigned a unique pair of numbers, called coordinates, that describe its position relative to two perpendicular lines, called axes. The horizontal axis is usually labeled x and the vertical axis is usually labeled y.
To apply the translation rule T(-3, 1) to the point (2, -7), we need to add the translation vector (-3, 1) to the coordinates of the point:
(2, -7) + (-3, 1) = (-1, -6)
The resulting point after the translation is (-1, -6).
Therefore, the translated point is located in the third quadrant of the coordinate system, since both coordinates are negative.
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in a role playing game two special dice are rolled. one die has 4 faces numbered 1 through 4 and the other has 6 faces numbered 1 thorugh 6. what is the probabilty that the total shown on the two dice after they are rolled is greater than or equal to 8?
The probability that the total shown on the two dice after they are rolled is greater than or equal to 8 is 1/9.
Exit
6-3: PRACTICE Part 2 Logarithms in Equations Algebra 2
Michael invests $1,000 in an account that earns a 4.75% annual percentage rate compounded continuously. Peter invests $1,200 in an account that earns a 4.25% annual
percentage rate compounded continuously. Which person's account will grow to $1,800 first?
Michael's account will grow to $1,800 after about year(s). Peter's account will grow to $1,800 after about year(s). So,
(Round to the nearest whole number as needed.)
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Answer: To solve this problem, we need to use the continuous compound interest formula:
A = Pe^(rt)
where A is the amount in the account, P is the initial principal, e is the mathematical constant e (approximately 2.71828), r is the annual interest rate (as a decimal), and t is the time in years.
For Michael's account, we have:
A = 1000e^(0.0475t)
For Peter's account, we have:
A = 1200e^(0.0425t)
We want to find the time it takes for each account to reach $1,800. So we can set up the following equations:
1000e^(0.0475t) = 1800
1200e^(0.0425t) = 1800
We can solve each equation for t by taking the natural logarithm of both sides and isolating t:
ln(1000) + 0.0475t = ln(1800)
ln(1200) + 0.0425t = ln(1800)
Subtracting ln(1000) or ln(1200) from both sides, we get:
0.0475t = ln(1800) - ln(1000)
0.0425t = ln(1800) - ln(1200)
Dividing both sides by the interest rate and simplifying, we get:
t = (ln(1800) - ln(1000)) / 0.0475 ≈ 10.16 years for Michael's account
t = (ln(1800) - ln(1200)) / 0.0425 ≈ 10.62 years for Peter's account
Therefore, Michael's account will grow to $1,800 first, after about 10 years (rounded to the nearest whole number).
Step-by-step explanation:
what is the maximum number of consecutive odd positive integers that can be added together before the sum exceeds ?
The maximum number of consecutive odd positive integers that can be added together before the sum exceeds 401 is 11.
Let's assume the first odd integer is x. Then, the sum of the next n consecutive odd integers would be given by:
x + (x+2) + (x+4) + ... + (x+2n-2) = nx + 2(1+2+...+n-1) = nx + n(n-1)
We want to find the largest n such that the sum is less than or equal to 401:
nx + n(n-1) ≤ 401
Since the integers are positive and odd, we can start with x=1 and then try increasing values of n until we find the largest value that satisfies the inequality:
n + n(n-1) ≤ 401
n² - n - 401 ≤ 0
Using the quadratic formula, we find that the solutions are:
n = (1 ± √(1+1604))/2
n ≈ -31.77 or n ≈ 32.77
We discard the negative solution and round down to the nearest integer, giving us n = 11. Therefore, the maximum number of consecutive odd positive integers that can be added together before the sum exceeds 401 is 11.
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Complete Question:
what is the maximum number of consecutive odd positive integers that can be added together before the sum exceeds 401?
three bolts and three nuts are in a box. two parts are chosen at random. find the probability that one is a bolt and one is a nut.
The probability of picking one bolt and one nut is 1/2 or 50%.
To find the probability that one is a bolt and one is a nut, we need to use the formula for calculating the probability of two independent events happening together: P(A and B) = P(A) × P(B)
Let's first calculate the probability of picking a bolt from the box:
P(bolt) = number of bolts / total number of parts = 3/6 = 1/2
Now, let's calculate the probability of picking a nut from the box:
P(nut) = number of nuts / total number of parts = 3/6 = 1/2
Since the events are independent, the probability of picking a bolt and a nut in any order is:
P(bolt and nut) = P(bolt) × P(nut) + P(nut) × P(bolt)
P(bolt and nut) = (1/2) × (1/2) + (1/2) × (1/2)
P(bolt and nut) = 1/2
Therefore, the probability of picking one bolt and one nut is 1/2 or 50%.
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the probability that one chosen part is a bolt and the other chosen part is a nut is 1, or 100%. This makes sense because if we choose two parts at random, we must get one bolt and one nut since there are three of each in the box.
To find the probability that one chosen part is a bolt and the other chosen part is a nut, we need to use the formula for probability:
Probability = (number of desired outcomes) / (total number of outcomes)
There are two ways we could choose one bolt and one nut: we could choose a bolt first and a nut second, or we could choose a nut first and a bolt second. Each of these choices corresponds to one desired outcome.
To find the number of ways to choose a bolt first and a nut second, we multiply the number of bolts (3) by the number of nuts (3), since there are 3 possible bolts and 3 possible nuts to choose from. This gives us 3 x 3 = 9 total outcomes.
Similarly, there are 3 x 3 = 9 total outcomes if we choose a nut first and a bolt second.
Therefore, the total number of desired outcomes is 9 + 9 = 18.
The total number of possible outcomes is the number of ways we could choose two parts from the box, which is the number of ways to choose 2 items from a set of 6 items. This is given by the formula:
Total outcomes = (6 choose 2) = (6! / (2! * 4!)) = 15
Putting it all together, we have:
Probability = (number of desired outcomes) / (total number of outcomes)
Probability = 18 / 15
Probability = 1.2
However, this answer doesn't make sense because probabilities should always be between 0 and 1. So we made a mistake somewhere. The mistake is that we double-counted some outcomes. For example, if we choose a bolt first and a nut second, this is the same as choosing a nut first and a bolt second, so we shouldn't count it twice.
To correct for this, we need to subtract the number of outcomes we double-counted. There are 3 outcomes that we double-counted: choosing two bolts, choosing two nuts, and choosing the same part twice (e.g. choosing the same bolt twice). So we need to subtract 3 from the total number of desired outcomes:
Number of desired outcomes = 18 - 3 = 15
Now we can calculate the correct probability:
Probability = (number of desired outcomes) / (total number of outcomes)
Probability = 15 / 15
Probability = 1
So the probability that one chosen part is a bolt and the other chosen part is a nut is 1, or 100%. This makes sense because if we choose two parts at random, we must get one bolt and one nut since there are three of each in the box.
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profitability empirical rule with this dataset? why or why not. no, the measures the proportion of a movies budget recovered. a profitability less than 1 the movie did not make enough money to cover the budget, while a profitability greater than means means it made a profit. a boxplot of the profitability ratings of 136 movies that came out in 2011 is shown below. (the largest outlier is the movie 1 insidi high gross revenue.)
The empirical rule does not apply to this dataset because the empirical rule is used to describe data that is normally distributed.
The empirical rule is a statistical rule that states that for a normal distribution.
Approximately 68% of the data will fall within one standard deviation of the mean, 95% of the data will fall within two standard deviations of the mean, and 99.7% of the data will fall within three standard deviations of the mean.
The dataset is normally distributedThe dataset is normally distributed, determine if the empirical rule appliesThe empirical rule does not apply, identify an alternative method to describe the datasetThe empirical rule does not apply to this dataset because the empirical rule is used to describe data that is normally distributed.
This dataset does not appear to be normally distributed, as evidenced by the large outlier (1 Insidi High Gross Revenue).
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Please help me !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
The equivalent exponential expression for this problem is given as follows:
A. 4^15 x 5^10.
How to simplify the exponential expression?The exponential expression in the context of this problem is defined as follows:
[tex]\left(\frac{4^3}{5^{-2}}\right)^5[/tex]
To simplify the expression, we must first apply the power of power rule, which means that when one exponential expression is elevated to an exponent, we keep the base and multiply the exponents, hence:
4^(15)/5^(-10)
The negative exponent at the denominator means that the expression can be moved to the numerator with a positive exponent, hence the simplified expression is given as follows:
4^15 x 5^10.
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Answer every question. Pick one option for each question. Show your work.
1. Over one week, a snack booth at a fair sold 362 cans of soft drinks for $1.75 each and
221 hot dogs for $2.35 each. Which calculation will give the total sales of soft drinks and
hot dogs?
A. 362(2.35) + 221(1.75)
B. 221(2.35) + 362(2.35)
C. 221(1.75) + 362(1.75)
D. 362(1.75) + 221(2.35)
What is the answer to this problem?
The area of the shaded area is 3.27 ft²
How to the area of the shaded area?We can find the area of the shaded area by subtracting the area of the triangle from the area of the sector. That is;
Area of shaded area = Area of sector - area of triangle
Area of shaded area = (60/360 * π * 6²) - (1/2 * 6 * 6 * sin 60)
Area of shaded area = (60/360 * 22/7 * 36) - (1/2 * 36 * 0.866)
Area of shaded area = 3.27 ft²
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Divide and write your answer in standard notation to the nearest whole number with commas.
Answer:
The answer is 1×10⁶ to the nearest whole number
Step-by-step explanation:
7.6×10⁰/5.4×10‐⁶
7.6×10^(0-(-6)/5.4
7.6×10^(0+6)/5.4
7.6×10⁶/5.4
=1×10⁶ to the nearest whole number
an agency has specialists who analyze the frequency of letters of the alphabet in an attempt to decipher intercepted messages. suppose a particular letter is used at a rate of 6.6%. what is the mean number of times this letter will be found on a typical page of 2650 characters? 174.9 what is the standard deviation for the number of times this letter will be found on a typical page of 2650 characters ? round your answer to 1 decimal place. in an intercepted message, a page of 2650 characters is found to have the letter occurring192 times. would you consider this unusual?
Standard deviation normal distribution table or calculator to determine the probability of observing a z-score of 1.3 or higher.
The probability is approximately 0.0968, or 9.68%.
To determine the mean number of times the letter appears on a page, we can multiply the probability of the letter appearing (0.066) by the total number of characters on the page (2650):
[tex]Mean = 0.066 \times 2650 = 174.9[/tex]
To calculate the standard deviation, we can use the formula:
Standard deviation = [tex]\sqrt(n \times p \times q)[/tex]
n is the sample size (2650), p is the probability of success (0.066), and q is the probability of failure [tex](1 - p = 0.934)[/tex].
Standard deviation = [tex]sqrt(2650 \times 0.066 \times 0.934) = 13.2[/tex] (rounded to 1 decimal place)
Determine whether 192 occurrences of the letter on a page is unusual, we can use the z-score formula:
z = (x - mean) / standard deviation
x is the observed number of occurrences (192), mean is the expected number of occurrences (174.9), and standard deviation is the standard deviation we just calculated (13.2).
[tex]z = (192 - 174.9) / 13.2 = 1.3[/tex]
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the average height of students at uh from an srs of 19 students gave a standard deviation of 3.2 feet. construct a 95% confidence interval for the standard deviation of the height of students at uh. assume normality for the data. a) (1.418, 10.732) b) (1.918, 5.732) c) (2.418, 4.732) d) (6.418, 11.732) e) (5.418, 9.732) f) none of the above
The 95% confidence interval for the standard deviation of the height of students at UH is (1.918, 5.732), which corresponds to option b.
To construct a 95% confidence interval for the standard deviation of the height of students at UH, we will use the Chi-square distribution. Given the sample standard deviation (s) of 3.2 feet, a sample size (n) of 19 students, and assuming normality for the data, we can find the confidence interval as follows:
1. Determine the degrees of freedom: df = n - 1 = 19 - 1 = 18
2. Identify the Chi-square values for the confidence level (95%): χ²_lower = 7.632, χ²_upper = 32.852 (using a Chi-square table or calculator)
3. Calculate the lower and upper bounds of the confidence interval:
Lower bound = sqrt((n - 1) * s² / χ²_upper) = sqrt(18 * (3.2)² / 32.852) ≈ 1.918
Upper bound = sqrt((n - 1) * s² / χ²_lower) = sqrt(18 * (3.2)² / 7.632) ≈ 5.732
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The 95% confidence interval for the standard deviation of the height of students at UH is approximately (1.918, 5.732), Option B.
Construct a 95% confidence interval for the standard deviation of the height of students at UH, we'll use the given data and the Chi-Square distribution.
Here's a step-by-step explanation:
SRS (simple random sample) of 19 students, which means the degrees of freedom (df) = n - 1 = 19 - 1 = 18.
The sample standard deviation (s) is given as 3.2 feet.
Assume normality for the data.
A 95% confidence interval, we'll use the Chi-Square distribution table to find the critical values.
The two tail probabilities are 0.025 and 0.975, so we'll look up the Chi-Square values for 18 degrees of freedom and these probabilities:
[tex]- X^2_{0.025} = 30.191 (upper limit)[/tex]
[tex]- X^2_{0.975} = 8.231 (lower limit)[/tex]
Calculate the confidence interval for the population standard deviation (σ):
[tex][tex](\sqrt((n - 1) \times s^2 / X^2_{upper}), \sqrt((n - 1) \times s^2 / X^2_{lower}))[/tex][/tex]
Plug in the values:
[tex]- n = 19[/tex]
[tex]- s = 3.2[/tex]
[tex]- df = 18[/tex]
[tex][tex]- X^{2} _{upper} = 30.191[/tex][/tex]
[tex][tex]- X^2_{lower} = 8.231[/tex][/tex]
Calculate the confidence interval:
[tex](√((18 \times 3.2^2) / 30.191), \sqrt((18 \times 3.2^2) / 8.231)) \approx (1.918, 5.732)[/tex]
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I need help answering this question and understanding it
The amount of money less per hour which Melanie earn than Olivia is equal to $268.
What is the slope-intercept form?In Mathematics and Geometry, the slope-intercept form of the equation of a straight line is given by this mathematical expression;
y = mx + c
Where:
m represents the slope or rate of change.x and y are the points.c represents the y-intercept or initial value.Based on the information provided about Melanie's earnings, we have the following:
y = 22.2x
When x = 40 hours, the y-value is given by;
y = 22.2(40)
y = $888.
Difference in earnings can be calculated as follows;
Difference = $1156 - $888
Difference = $268.
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Kubin Company’s relevant range of production is 25,000 to 33,500 units. When it produces and sells 29,250 units, its average costs per unit are as follows: Average Cost per Unit Direct materials $ 8. 50 Direct labor $ 5. 50 Variable manufacturing overhead $ 3. 00 Fixed manufacturing overhead $ 6. 50 Fixed selling expense $ 5. 00 Fixed administrative expense $ 4. 00 Sales commissions $ 2. 50 Variable administrative expense $ 2. 00 Required: 1. For financial accounting purposes, what is the total amount of product costs incurred to make 29,250 units? 2. For financial accounting purposes, what is the total amount of period costs incurred to sell 29,250 units? 3. For financial accounting purposes, what is the total amount of product costs incurred to make 33,500 units? 4. For financial accounting purposes, what is the total amount of period costs incurred to sell 25,000 units? (For all requirements, do not round intermediate calculations. )
1. Total amount of product costs
2. Total amount of period costs incurred
3. Total amount of product costs
4. Total amount of period costs
For the relevant range of production of units total amount of product and period cost as per units are,
Total amount of product costs for 29,250 units is $687,375.
Total amount of period costs incurred for 29,250 units is $58,511.50
Total amount of product costs for 33,500 units is equal to $787,250.
Total amount of period costs for 25,000 units is equal to $50,011.50.
Average Cost per Unit Direct materials = $ 8. 50
Direct labor = $ 5. 50
Variable manufacturing overhead = $ 3. 00
Fixed manufacturing overhead = $ 6. 50
Fixed selling expense = $ 5. 00
Fixed administrative expense = $ 4. 00
Sales commissions = $ 2. 50
Variable administrative expense = $ 2. 00
Total unit produced = 29,250 units,
Total product costs
= (Direct materials + Direct labor + Variable manufacturing overhead + Fixed manufacturing overhead) x Number of units produced
= ($8.50 + $5.50 + $3.00 + $6.50) x 29,250
= $23.50 x 29,250
= $687,375
The total amount of product costs incurred to make 29,250 units is $687,375.
Total period costs
= Fixed selling expense + Fixed administrative expense + Sales commissions + (Variable administrative expense x Number of units sold)
= $5.00 + $4.00 + $2.50 + ($2.00 x 29,250)
= $5.00 + $4.00 + $2.50 + $58,500
= $58,511.50
The total amount of period costs incurred to sell 29,250 units is $58,511.50
For the number of units produced changed to 33,500.
Total product costs
= (Direct materials + Direct labor + Variable manufacturing overhead + Fixed manufacturing overhead) x Number of units produced
= ($8.50 + $5.50 + $3.00 + $6.50) x 33,500
= $23.50 x 33,500
= $787,250
The total amount of product costs incurred to make 33,500 units is $787,250.
The number of units sold changed to 25,000.
Total period costs
= Fixed selling expense + Fixed administrative expense + Sales commissions + (Variable administrative expense x Number of units sold)
= $5.00 + $4.00 + $2.50 + ($2.00 x 25,000)
= $5.00 + $4.00 + $2.50 + $50,000
= $50,011.50
The total amount of period costs incurred to sell 25,000 units is $50,011.50.
Therefore, the total amount of the product and period cost for different situations are,
Total amount of product costs is equal to $687,375.
Total amount of period costs incurred is equal to $58,511.50
Total amount of product costs is equal to $787,250.
Total amount of period costs is equal to $50,011.50.
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Select the GCF of these numbers. 48 and 60 22 ·3 2· 112 32 23 · 5 13· 193 ·232
The GCF of 48 and 60 is 12
To find the greatest common factor (GCF) of 48 and 60, we can start by finding the prime factorization of each number
48 = 2^4 × 3
60 = 2^2 × 3 × 5
Next, we can identify the common factors of both numbers by looking at their prime factorization
The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
The common factors of 48 and 60 are: 1, 2, 3, 4, 6, and 12.
The greatest common factor is the largest number that both 48 and 60 can be divided evenly by. In this case, that number is 12. Therefore, the GCF is 12.
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The given question is incomplete, the complete question is:
Find the GCF of 48 and 60.
Can someone help me asap? It’s due tomorrow. I will give brainiest if it’s correct. Provide an explanation
We can expect approximately 144 students in Chloe's school to own pets. The answer is 144.
What is mean by Proportion ?A proportion is an equation in which two ratios are set equal to each other. For example, if there is 1 boy and 3 girls you could write the ratio as: 1 : 3 (for every one boy there are 3 girls) 1 / 4 are boys and 3 / 4 are girls. 0.25 are boys (by dividing 1 by 4)
Based on the simulation results, we can count the number of times the number cube landed on digits 1, 2, 3, and 4, which represent the number of students who own pets. We add up these counts and divide by the total number of rolls (25) to get the proportion of rolls that resulted in a student owning a pet:
(5+1+4+4+3+3+2+2+2+1+5+2+1) / 25 = 0.6
So, approximately 60% of the rolls resulted in a student owning a pet. If we assume this proportion holds for the entire school, we can estimate the number of students who own pets out of the total number of students in the school:
Number of students who own pets = Proportion of students who own pets * Total number of students
Number of students who own pets = 0.6 * 240 = 144
Therefore, we can expect approximately 144 students in Chloe's school to own pets. The answer is 144.
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Footy. You play in an inter- school footy competition. Curiously, in one of the rounds the total number of points scored by each team is the same, so that all games are not only drawn, but also have the same final score. In that same round your team scored 1/13th of all goals and 1/15th of all behinds. How many teams play in the competition?
There are 195 games played in the competition.
Let the total number of points scored in each game be represented by the variable "x". Since a goal is worth 6 points and a behind is worth 1 point, we can write an equation in terms of "x":
6a/13 + b/15 = x
where "a" is the total number of goals scored and "b" is the total number of behinds scored by your team in the round.
Since all games have the same final score, we know that the total number of points scored in the round is equal to the number of games played times the final score:
x * number of games = total points scored
We also know that the total number of points scored in the round is equal to the total number of goals scored (by all teams) times 6 plus the total number of behinds scored (by all teams):
x * number of games = 6 * total number of goals + total number of behinds
Substituting the first equation into the second equation, we get:
(6a/13 + b/15) * number of games = 6 * total number of goals + total number of behinds
Simplifying this equation and solving for "number of games", we get:
number of games = 1170/(2a/13 + b/15)
Since the number of games must be an integer, we can see that 2a/13 + b/15 must be a divisor of 1170. The possible values of 2a/13 + b/15 are:
2/13 + 78/15 = 72/5
4/13 + 72/15 = 56/5
6/13 + 66/15 = 44/5
8/13 + 60/15 = 32/5
The only divisor of 1170 among these values is 72/5, which corresponds to a = 26 and b = 312. Therefore, the number of games played in the round is:
number of games = 1170 / [(2a/13) + (b/15)]
= 1170 / [(2*26/13) + (312/15)]
= 195
As a result, 195 games have been played in the competition.
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we call a number a mountain number if its middle digit is larger than any other digit. for example, 284 is a mountain number. how many 3-digit mountain numbers are there?
If we consider a mountain number with its middle digit is larger than any other digit, then there are possible three-digit mountain numbers are equals the 240.
A number is called a 'mountain' if its decimal digits insitiate with 1, i.e. 'base camp', increase continuously to one largest digit, then decrease continuously back to one i.e. back to base camp. We have a number is called a mountain number. Now, there are 100 to 999 total 3-digit numbers. Now, with 2 in the middle, we have = 2 numbers[1 x 2] - 120 = 121
With 3 in the we have = 6 numbers[2 x 3] - 130, 131, 132, 230, 231, 232.......and so on.With 4 in the middle,we have = 12 numbers[3 x4]With 5 in the middle, we have = 20 numbers[4 x 5]With 6 in the middle, we have = 30 numbers[5 x 6]With 7 in the middle, we have = 42 numbers[6 x 7]With 8 in the middle, we have = 56 numbers[7 x 8]With 9 in the middle, we have = 72 numbers[8 x 9]So, we have a total of Total Number = 2 + 6 + 12 + 20 + 30 + 42 + 56 + 72 = 240 "mountain numbers". Hence, the required number , value is 240.
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PLEASE HELPPPPP!!!!! Which statement correctly compares the shapes of the of the distributions!
Answer:
Could be B
Step-by-step explanation:
Southview HS is mirrored or symmetrical while the other is going up.
The radius of a circle is 10 cm. Find its area in terms of π.
The area of a circle is given by the formula:
A = πr^2
where r is the radius of the circle.
Substituting the value of the radius as r = 10 cm, we get:
A = π(10)^2
A = 100π
Therefore, the area of the circle with radius 10 cm is 100π square centimeters.
~~~Harsha~~~
A large rectangular prism is 5 feet long, 3 feet wide, and 4 feet tall. A small rectangular prism is 2.5 feet long, 1.5 feet wide, and 2 feet tall.
How many small prisms would it take to fill the large prism?
Write your answer as a whole number or decimal. Do not round.
The answer of the given question based on the rectangular prism is , , it would take 8 small rectangular prisms to fill the large rectangular prism.
What is Rectangular prism?A rectangular prism, also known as a rectangular parallelepiped, is a three-dimensional solid object that has six rectangular faces, with opposite faces being congruent and parallel. It is a special case of a parallelepiped in which all angles are right angles and all six faces are rectangles.
To find how many small rectangular prisms will fit inside the large rectangular prism, we need to calculate the volume of each prism and then divide the volume of the large prism by the volume of the small prism.
The volume of the large prism is:
V_large = length × width × height = 5 ft × 3 ft × 4 ft = 60 feet³
The volume of the small prism is:
V_small = length × width × height = 2.5 ft × 1.5 ft × 2 ft = 7.5 feet³
Dividing the volume of the large prism by the volume of the small prism, we get:
number of small prisms = V_large / V_small = 60 ft³ / 7.5 ft³ = 8
Therefore, it would take 8 small rectangular prisms to fill the large rectangular prism.
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Which of the following best describes the expression 9(x + 7)? (20 brainly points)
A: The sum of constant factors 9 and x + 7
B: The product of constant factors 9 and x + 7
C: The product of a constant factor 9 and a 2-term factor x + 7
D: The sum of a constant factor 9 and a 2-term factor x + 7
The statement that express 9(x + 7) is product of constant factors 9 and x + 7. The Option B.
What does the expression 9(x + 7) represent?The expression 9(x + 7) represents the product of constant factors 9 and x + 7. To evaluate the expression, you would distribute the 9 to both terms inside the parentheses, resulting in 9x + 63.
This expression can also be written as a 2-term factor of 9 and x + 7. It is important to understand the different terms and factors in an expression to simplify and solve equations.
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Part B
Based on your construction, what do you know about ΔABD and ΔBCD?
The construction and the resulting triangles are interesting because they allow us to explore the properties of perpendicular lines and the angles they form.
Now, let's look at the two triangles that are formed as a result of this construction - ΔABD and ΔBCD. Since line BD is perpendicular to line AC, we know that angle ABD and angle CBD are both right angles. This is because any line that is perpendicular to another line forms a right angle with that line.
Now, let's look at the other sides of the triangles. In ΔABD, we have side AB, which is different from side BC in ΔBCD. Similarly, in ΔBCD, we have side CD, which is different from side AD in ΔABD.
So, although the two triangles share a common side (BD), they have different lengths for their other sides. This means that the two triangles are not congruent, since congruent triangles must have the same length for all their sides.
However, we can still find some similarities between the two triangles. For example, since angle ABD and angle CBD are both right angles, we know that they are congruent. Additionally, we can use the fact that angle ADB is congruent to angle CDB, since they are alternate interior angles formed by a transversal (line BD) intersecting two parallel lines (line AC and the line perpendicular to it passing through point B).
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Complete Question:
Draw a line through point B that is perpendicular to line AC Label the intersection of the line and line AC as point D. Take a screenshot of your work, save it, and insert the image in the space below.
Part B
Based on your construction, what do you know about ΔABD and ΔBCD?
The area of a rectangle is 8811m if the width of the garden is 89 m what’s the length
The length of the garden is 99 m.
What’s the length?The formula for the area of a rectangle is:
Area = Length x Width
We are given that the area of the rectangle is 8811 [tex]m^{2}[/tex] and the width is 89 m. Substituting these values into the formula, we get:
8811 [tex]m^{2}[/tex] = Length x 89 m
To solve for the length, we can divide both sides of the equation by 89 m:
Length = 8811 [tex]m^{2}[/tex] / 89 m
Simplifying, we get:
Length = 99 m
Therefore, the length of the garden is 99 m.
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What is the equation of the line in slope-intercept form?
Answer:
y = 3/5x + 3
Step-by-step explanation:
points on the graph
(-5,0) and (0,3)
0- 3 = -3
-5 - 0 = -5
-3/-5= 3/5
y = 3/5x + B
use a point from the graph
3 = 3/5 x 0 + B
3 = 0 + B
3 -0 = 3
3 = B
check answer
(-5,0)
Y = 3/5 x -5 + 3
Y = -15/3 + 3
Y = -3 + 3
Y = 0
Making the equation true y = 3/5x + 3
A student is helping a family member build a storage bin for their garage. They would like for the bin to have a volume of 240 ft3 If they already have the length measured at 8 feet and the width at 6 feet, what is the height needed to reach the desired volume?
(A) 3 feet
(B) 3.5
(C) 4 feet
(D) 5 feet
Answer: The answer to your question is D! Brainliest?
Step-by-step explanation:
To find the height needed to reach a volume of 240 ft^3, we can use the formula:
Volume = length x width x height
Substituting the given values, we get:
240 = 8 x 6 x height
Simplifying:
240 = 48 x height
height = 240/48
height = 5
Therefore, the height needed to reach a volume of 240 ft^3 is 5 feet.
Answer: (D) 5 feet.
when utilizing a matlab built-in ode solver, in the function for one's states the variable for the state derivatives must be organized as a column vector. group of answer choices true false
It is true to say that when utilizing MATLAB's built-in ode solver, the function for one's states the variable for the state derivatives must be set as column vectors.
The Ordinary Differential Equation (ODE) solvers in MATLAB solve initial value problems with a varient state of properties. They consider state spaces as a column vector. For example, two solve a second degree ODE, It's two states in state space has to be arranges in a 1x2 column vector to pass it into a ODE solver.
Initial value problems with different attributes can be solved using theODE solvers in MATLAB.
Here the first ODE is of third order, so it will be converted to three equivalent first order ODEs. The second ODE is second order, so it will be converted to two equivalent first order ODEs.These solver can be used to solve the different type like the differential algebraic equations (DAEs), problems involving a mass matrix, and fully implicit problems. ODE45, is most frequently used ODE solver in MATLAB.It used to compare methods of orders four and five to determine an estimate error.
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