Answer:
740 m^2
Step-by-step explanation:
The real numbers $x$ and $y$ are such that \begin{align*} x + y &= 4, \\ x^2 + y^2 &= 22, \\ x^4 &= y^4 - 176 \sqrt{7}. \end{align*}Compute $x - y.$
You get everything you need from factoring the last expression:
[tex]x^4-y^4=-176\sqrt7[/tex]
The left side is a difference of squares, and we get another difference of squares upon factoring. We end up with
[tex]x^4-y^4=(x^2-y^2)(x^2+y^2)=(x-y)(x+y)(x^2+y^2)[/tex]
Plug in everything you know and solve for [tex]x-y[/tex]:
[tex]-176\sqrt7=(x-y)\cdot4\cdot22\implies x-y=\boxed{-2\sqrt7}[/tex]
Answer:
-2sqrt(7)
Step-by-step explanation:
Solution:
From the third equation, $x^4 - y^4 = -176 \sqrt{7}.$
By difference of squares, we can write
\[x^4 - y^4 = (x^2 + y^2)(x^2 - y^2) = (x^2 + y^2)(x + y)(x - y).\]Then $-176 \sqrt{7} = (22)(4)(x - y),$ so $x - y = \boxed{-2 \sqrt{7}}.$
Find the area of the shape shown below
Answer: 28
Step-by-step explanation:
I can't really think of a way to explain this well without visuals and idk how to add images on my answer. But, what I normally do is draw out the shape on paper divide the shape into different sections. Solve the area of the separate sections. It simplifies the more complex figure and turns them into basic shapes. After solving each shape, add all of them together and that leaves you with the area. Hopefully you understand what I mean. I hope this sort of helped:)
From the top of a vertical cliff 75.0m high, forming one bank of a river, the angles of depression of the top and bottom of a vertical cliff which forms the opposite bank are 22° and 58° respectively. Determine the height of the second cliff and width of the river
Answer:
a. 46.9 m b. 56.1 m
Step-by-step explanation:
a. Width of the river
The angle of depression of the bottom of the second vertical cliff from the first vertical cliff = angle of elevation of the top of the first vertical cliff from the bottom of the second vertical cliff = 58°.
Since the height of the vertical cliff = 75.0 m, its distance from the other cliff which is the width of the river, d is gotten from
tan58° = 75.0 m/d
d = 75.0/tan58° = 46.87 m ≅ 46.9 m
b. Height of the second cliff
Now, the difference in height of the two cliffs is gotten from
tan22° = h/d, since the angle of depression of the top of second cliff from the first cliff is the angle of elevation of the top of the first cliff from the second cliff = 22°
h = dtan22° = 18.94 m
So, the height of the second cliff is h' = 75.0 - h = 75.0 m - 18.94 m = 56.06 m ≅ 56.1 m
Helppppppppppppppppp
Answer/Step-by-step explanation:
Surface area of cylinder = 2πrh + 2πr²
Surface area of the cylinder with,
height (h) = 4 ft
radius (r) = 5 ft
Surface area = 2*3.14*5*4 + 2*3.14*5²
= 125.6 + 157
= 282.6 ft²
Surface area of the cylinder with,
height (h) = 12 yd
radius (r) = 3 yd
Surface area = 2*3.14*3*12 + 2*3.14*3²
= 282.74 yd²
Points A(-l, y) and B(5,7) lie on a circle with centre 0(2, -3y). Find the values of y. Hence, find the radius of the circle
Answer:
The answer is below
Step-by-step explanation:
Points A(-l, y) and B(5,7) lie on a circle with centre O(2, -3y). This means that AB is the diameter of the circle and OA = OB = radius.
For two points X([tex]x_1,y_1[/tex]) and Y([tex]x_2, y_2[/tex]), the coordinates of the midpoint (x, y) between the two points is given as:
[tex]x=\frac{x_1+x_2}{2},y=\frac{y_1+y_2}{2}[/tex].
For A(-l, y) and B(5,7) with center O(2, -3y), the value of y can be gotten by:
[tex]For\ x\ coordinate:\\2=\frac{-1+5}{2}\\ 2=2.\\For\ y\ coordinate:\\-3y=\frac{y+7}{2}\\ -6y=y+7.\\-6y-y=7\\-7y=y\\y=-1[/tex]
The value of y is -1. Therefore A is at (-1, -1) and O is at (2, -3(-1))= (2, 3)
The radius of the circle = OA. The distance between two points X([tex]x_1,y_1[/tex]) and Y([tex]x_2, y_2[/tex]) is given as:
[tex]|OX|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\Therefore\ the\ radius \ |OA|\ is :\\|OA|=\sqrt{(2-(-1))^2+(3-(-1))^2}=\sqrt{25}=5[/tex]
The radius of the circle is 5 units
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2ab-6a+5b+___ Please include an explanation too!
Answer:
[tex]2ab - 6a + 5b - 15[/tex]
Step-by-step explanation:
Given
[tex]2ab - 6a + 5b + \_[/tex]
Required
Fill in the gap to produce the product of linear expressions
[tex]2ab - 6a + 5b + \_[/tex]
Split to 2
[tex](2ab - 6a) + (5b + \_)[/tex]
Factorize the first bracket
[tex]2a(b - 3) + (5b + \_)[/tex]
Represent the _ with X
[tex]2a(b - 3) + (5b + X)[/tex]
Factorize the second bracket
[tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]
To result in a linear expression, then the following condition must be satisfied;
[tex]b - 3 = b + \frac{X}{5}[/tex]
Subtract b from both sides
[tex]b - b- 3 = b - b+ \frac{X}{5}[/tex]
[tex]- 3 = \frac{X}{5}[/tex]
Multiply both sides by 5
[tex]- 3 * 5 = \frac{X}{5} * 5[/tex]
[tex]X = -15[/tex]
Substitute -15 for X in [tex]2a(b - 3) + 5(b + \frac{X}{5})[/tex]
[tex]2a(b - 3) + 5(b + \frac{-15}{5})[/tex]
[tex]2a(b - 3) + 5(b - \frac{15}{5})[/tex]
[tex]2a(b - 3) + 5(b - 3)[/tex]
[tex](2a + 5)(b - 3)[/tex]
The two linear expressions are [tex](2a+ 5)[/tex] and [tex](b - 3)[/tex]
Their product will result in [tex]2ab - 6a + 5b - 15[/tex]
Hence, the constant is -15
48 - 8x equivalent expression
Answer:
8(6-x)
Step-by-step explanation:
Both 48 and 8 can be divisible by 8.
48 ÷ 8 = 6
8 ÷ 8 = 1
Therefore you get the answer 8(6-x)
as the simplest form.
Hope this helps.
Triangle ABC has vertices at A(2,5), B(4,11) and C(-1,6). Determine the angles in this triangle.
I need this solved using vectors please
Answer:
The angles are
∠A = 90°, ∠B = 26.56°, ∠C = 63.43°
Step-by-step explanation:
We have that the angles of a vector are given as follows;
[tex]cos\left ( \theta \right ) = \dfrac{\mathbf{a\cdot b}}{\left | \mathbf{a} \right |\left | \mathbf{b} \right |}[/tex]
Whereby the vertices are represented as
A= (2, 5, 0), B = (4, 11, 0), C = (-1, 6, 0),
AB =(4, 11, 0) - (2, 5, 0) = (2, 6, 0) , BA = (-2, -6, 0)
BC = (-1, 6, 0) - (4, 11, 0) = (-5, -5, 0), CB = (5, 5, 0)
AC = (-1, 6, 0) - (2, 5, 0) = (-3, 1, 0), CA = (3, -1, 0)
θ₁ = AB·AC
a·c = a₁c₁ + a₂c₂ + a₃c₃ = 2×(-3) + 6×1 = 0
Therefore, θ₁ = 90°
BA·BC = (-2)×(-5) + (-6)×(-5) = 40
[tex]{\left | \mathbf{}BA \right |\left | \mathbf{}BC \right |}[/tex] = (√((-2)² + (-6)²)) × (√((-5)² + (-5)²)) = 44.72
cos(θ₂) = 40/44.72 = 0.894
cos⁻¹(0.894) =θ₂= 26.56°
CA·CB = 5×3 + 5×(-1) = 10
[tex]{\left | \mathbf{}CA \right |\left | \mathbf{}CB \right |}[/tex] = (√((3)² + (-1)²)) × (√((5)² + (5)²)) = 22.36
10/22.36 = 0.447
cos(θ₃) = 0.447
θ₃ = cos⁻¹(0.447) = 63.43°.
first correct answer gets best marks
Answer:
the answer would be x is less than 6.
Step-by-step explanation:
the reason why it would not be x is less than or equal to 6 is that the circle is not filled in.
Answer:
B
Step-by-step explanation:
x≤6
We can see from the graph that it starts from 6 and goes to 5, 4, 3, 2.
Hope this helps ;) ❤❤❤
Jane exchanged £100 for 216 Swiss francs. After buying a meal and a present to take home,she had 70 francs left.How much is this in £?
Answer:
£32.4
Step-by-step explanation:
£100 = 216 Swiss francs
x = 70 francs
70 x 100=7000/216=32.4
the diagrams shows a right-angled triangle. find the size of angle x. give your answer correct to 1 decimal place.
Answer:
1. 40.8 degrees
2. 65.6 degrees
Step-by-step explanation:
1.
sin(x) = opposite / hypotenuse = 17/26
x = arcsin(17/26) = 40.83 degrees
2. tan(x) = opposite / adjacent = 11/5 = 2.2
x = arctan(11/5) = 65.56 degrees
Pls help I need help with 12
Answer:
B. 14
Step-by-step explanation:
22/x = 11/(21-x)
462 - 22x = 11x
462 = 33x
x = 14
Answer: The value of x is 14, answer choice B
Let y be the other line segment connected to x
Using proportions:
[tex]\dfrac{11}{22}=\dfrac{y}{x}[/tex]
Cross multiply and simplify
[tex]22y=11x[/tex]
[tex]y=\dfrac{1}{2}x[/tex]
We know that x and y add to 21, so we can create the following equation:
[tex]x+y=21[/tex]
Substitute y=(1/2)x
[tex]x+\dfrac{1}{2}x=21[/tex]
Simplify by adding like terms
[tex]\dfrac{3}{2}x=21[/tex]
Divide both sides by 3/2
[tex]x=14[/tex]
Let me know if you need any clarifications, thanks!
Help please thanks don’t know how to do this
Answer:
a = 11.71 ; b = 15.56
Step-by-step explanation:
For this problem, we need two things. The law of sines, and the sum of the interior angles of a triangle.
The law of sines is simply:
sin(A)/a = sin(B)/b = sin(C)/c
And the sum of interior angles of a triangle is 180.
45 + 110 + <C = 180
<C = 25
We can find the sides by simply applying the law of sines.
length b
7/sin(25) = b/sin(110)
b = 7sin(110)/sin(25)
b = 15.56
length a
7/sin(25) = a/sin(45)
a = 7sin(45)/sin(25)
a = 11.71
If 18% of q is 27 , what is 27% of 2q
In this problem, there are two parts. We will need to find what q is if 18% of q is 27, and what 27% of 2q is.
First, let's set up and solve the equation for 18% of q is 27.
18 / 100 = 27 / q
100q = 486
q = 4.86
Next, we'll find the value of 2q.
2(4.86) = 9.72
Finally, we'll set up a proportion and solve for 27% of 2q.
27 / 100 = x / 9.72
100x = 262.44
x = 2.6244
If 18% of q is 27, then 27% of 2q is 2.6244 (round to tenths/hundredths place as needed).
Hope this helps!! :)
Answer:
81Step-by-step explanation: Let's first find the value of q
[tex]18/100 \times q = 27\\\frac{18q}{100} = \frac{27}{1}\\18q = 2700\\\frac{18q}{18} = \frac{2700}{18} \\q= 150.\\[/tex]
Now we can find 27% of 2q
[tex]27 \% \times 2q = \\27 \% \times 2(150)\\\frac{27}{100} \times 300\\\\= \frac{8100}{100} \\= 81[/tex]
The side lengths of a triangle are 9, 12, and 15. Is this a right triangle?
Answer:
Yes, this is a right triangle.Step-by-step explanation:
Hypotenuse always have the highest number than base and perpendicular.
Hypotenuse ( h ) = 15
Base ( b ) = 9
Perpendicular ( p ) = 12
Let's see whether the given triangle is a right triangle or not
Using Pythagoras theorem:
[tex] {h}^{2} = {p}^{2} + {b}^{2} [/tex]
Plugging the values,
[tex] {15}^{2} = {12}^{2} + {9}^{2} [/tex]
Evaluate the power
[tex]225 = 144 + 81[/tex]
Calculate the sum
[tex]225 = 225[/tex]
Hypotenuse is equal to the sum of perpendicular and base.
So , we can say that the given lengths of the triangle makes a right triangle.
Hope this helps..
Best regards!!
Answer:
[tex]\boxed{Yes.}[/tex]
Step-by-step explanation:
To solve this equation, we can use the Pythagorean Theorem: [tex]a^2 + b^2 = c^2[/tex], where [tex]a[/tex] and [tex]b[/tex] are regular side lengths and [tex]c[/tex] is the hypotenuse.
The hypotenuse is the longest side of a triangle and is assigned to the [tex]c[/tex]-variable.The other two side lengths can be assigned to either [tex]a[/tex] or [tex]b[/tex] because of the commutative property: [tex]a + b = b + a[/tex].Now, just substitute the side lengths into the formula and solve!
[tex]9^2 + 12^2 = 15^2[/tex] Simplify the equation by taking each value to its power.
[tex]81 + 144 = 225[/tex] Simplify by adding like terms.
[tex]225 = 255[/tex]
Therefore, this is indeed a right triangle.
At the shop near the beach, ice cream is offered in a cone or in a cylindrical cup as shown
below. The ice cream fills the entire cone and has a hemisphere on top. The ice cream
levelly fills the cylindrical cup.
radius of cone= 3 cm
radius of cylinder= 4.5 cm
height of cone = 10 cm
height of cylinder = 5 cm
Determine how much more ice cream the larger option has. Show your work. ( 19)
Answer:
B
Step-by-step explanation:
Please help fast! 25 points and brainliest!!
Let f(x) = 36x5 − 44x4 − 28x3 and g(x) = 4x2. Find f of x over g of x
Answer:
The answer is
9x³ - 11x² - 7xStep-by-step explanation:
f(x) = 36x^5 − 44x⁴ − 28x³
g(x) = 4x²
To find f(x) / g(x) Divide each term of f(x) by g(x)
That's
[tex] \frac{f(x)}{g(x)} = \frac{ {36x}^{5} - {44x}^{4} - {28x}^{3} }{ {4x}^{2} } \\ \\ = \frac{ {36x}^{5} }{ {4x}^{2} } - \frac{ {44x}^{4} }{ {4x}^{2} } - \frac{ {28x}^{3} }{ {4x}^{2} } \\ \\ = {9x}^{3} - {11x}^{2} - 7x[/tex]
Hope this helps you
Answer:
9x³ - 11x² - 7x
Step-by-step explanation:
guy abpove is right or bwlowe
Calcule o valor dos produtos a) (-4). (-7/8) b) (-4). (-7/8) n sei pq tá repetido tá aqui na folha ;-; c) (-4).(+ 3,5) d) (-2).(-3/4). (-1/7) PRA HOJEE
Answer:
a) (-4). (-7/8) = 28/8
b) (-4). (-7/8)= 28/8
c) (-4).(+ 3/5) = -12/5
d) (-2).(-3/4). (-1/7) = (6/4)(-1/7)= -6/28
Step-by-step explanation:
a) (-4). (-7/8) = 28/8
b) (-4). (-7/8)= 28/8
c) (-4).(+ 3/5) = -12/5
d) (-2).(-3/4). (-1/7) = (6/4)(-1/7)= -6/28
É repetido talvez com sinal alterado para mostrar a diferença na resposta. Se o sinal for alterado, a resposta também se tornará negativa. Seria - 28/8.
Quando um número negativo é multiplicado por um número negativo, obtém um número positivo. Mas quando um número positivo é multiplicado por um número negativo, dá uma resposta negativa.
Sempre se lembre
negativo * negativo = positivo
positivo * negativo = negativo
negativo * positivo = negativo
positivo * positivo = positivo
Em palavras simples, dois sinais diferentes dão um sinal negativo e dois sinais semelhantes dão um sinal positivo na multiplicação.
English
a) (-4). (-7/8) = 28/8
b) (-4). (-7/8)= 28/8
c) (-4).(+ 3/5) = -12/5
d) (-2).(-3/4). (-1/7) = (6/4)(-1/7)= -6/28
Its repeated maybe with a changed sign to show the difference in the answer. If the sign is changed the answer would also become negative . It would become - 28/8.
When a negative number is multiplied with a negative number it gives a positive number. But when a positive number is multiplied with a negative number it gives a negative answer.
Always remember
negative * negative= positive
positive *negative=negative
negative *positive =negative
positive * positive = positive
In simple words two unlike signs give a negative sign and two similar signs give a positive sign in multiplication.
What fraction is equal to six-sevenths times eight-fifths?
Answer:
1 13/35 (mixed number) or 48/35 (simplified)
Step-by-step explanation:
6/7 times 8/5
= (6 times 8) / (7 times 5)
= 48/35 or 1 13/35
hope this helped :)
Answer:
48/35
Step-by-step explanation:
6/7*8/5=48/35
The following box plot shows the number of years during which 40 schools have participated in an interschool swimming meet: A box and whisker plot is drawn using a number line from 0 to 10 with primary markings and labels at 0, 5, 10. In between two primary markings are 4 secondary markings. The box extends from 1 to 6 on the number line. There is a vertical line at 3.5. The whiskers end at 0 and 8. Above the plot is written Duration of Participation. Below the plot is written Years. At least how many schools have participated for more than 1 year and less than 6 years?
Answer:
Step-by-step explanation:
The box encloses data between the two quartiles, namely at least half of the data. If there are 40 schools, then half of them would be in the box, between 1 and 6.
see attached plot.
Answer:
really hard to tell what the box plot is like without an attachment so im gonna help u find it out anyway
Step-by-step explanation:
basically when u look at a box plot and the range the line in the middle is the median and then the max the lowest range the lower quartile and then the higher quartile you can find ur anser, simply find the median first, find where the lower quartile is and then the lowest number in the group thats in betweeen 1 and 6
When deriving the quadratic formula by completing the square, what expression can be added to both sides of the equation to create a perfect square trinomial?
Answer:
According to steps 2 and 4. The second-order polynomial must be added by [tex]-c[/tex] and [tex]b^{2}[/tex] to create a perfect square trinomial.
Step-by-step explanation:
Let consider a second-order polynomial of the form [tex]a\cdot x^{2} + b\cdot x + c = 0[/tex], [tex]\forall \,x \in\mathbb{R}[/tex]. The procedure is presented below:
1) [tex]a\cdot x^{2} + b\cdot x + c = 0[/tex] (Given)
2) [tex]a\cdot x^{2} + b \cdot x = -c[/tex] (Compatibility with addition/Existence of additive inverse/Modulative property)
3) [tex]4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x = -4\cdot a \cdot c[/tex] (Compatibility with multiplication)
4) [tex]4\cdot a^{2}\cdot x^{2} + 4\cdot a \cdot b \cdot x + b^{2} = b^{2}-4\cdot a \cdot c[/tex] (Compatibility with addition/Existence of additive inverse/Modulative property)
5) [tex](2\cdot a \cdot x + b)^{2} = b^{2}-4\cdot a \cdot c[/tex] (Perfect square trinomial)
According to steps 2 and 4. The second-order polynomial must be added by [tex]-c[/tex] and [tex]b^{2}[/tex] to create a perfect square trinomial.
Answer: D
Step-by-step explanation:
EDGE 2023
Please answer this in two minutes
6. Find d.
Please help
Answer:
Step-by-step explanation:
The first thing we are going to do is to fill in the other angles that we need to solve this problem. You could find ALL of them but all of them isn't necessary. So looking at the obtuse angle next to the 35 degree angle...we know that those are supplementary so 180 - 35 = the obtuse angle in the small triangle. 180 - 35 = 145. Within the smaller triangle we have now the 145 and the 10, and since, by the Triangle Angle-Sum Theorem all the angles have to add up to equal 180, then 180 - (10 + 145) = the 3rd angle, so the third angle is 180 - 155 = 25. Now let's get to the problem. If I were you, I'd draw that out like I did to keep track of these angles cuz I'm going to name them by their degree. In order to find d, we need to first find the distance between d and the right angle. We'll call that x. The reference angle is 35, the side opposite that angle is 12 and the side we are looking for, x, is adjacent to that angle. So we will use the tan ratio to find x:
[tex]tan(35)=\frac{12}{x}[/tex] Isolating x:
[tex]x=\frac{12}{tan(35)}[/tex] so
x = 17.1377 m
Now we have everything we need to find d. We will use 25 degrees as our reference angle, and the side opposite it is 12 and the side adjacent to it is
d + 17.1377, so that is the tan ratio as well:
[tex]tan(25)=\frac{12}{d+17.1377}[/tex] and simplifying a bit:
[tex]d+17.1377=\frac{12}{tan(25)}[/tex] and a bit more:
d + 17.1377 = 25.73408 so
d = 8.59, rounded
Simplify (2^3)^–2. PLEASE I NEED HELP U WILL GET 10 POINTS
Answer:
I won't give you the answer straight away so you take the time to read my answer and understand
Step-by-step explanation:
We knoe that 2 to the third is 8. when you square to a negative power, you do squaring normally, and then take the reciprocal of that number. so 8 to the second power is 64, and we flip it over, sp the answer is 1/64
Can somebody plz help me 15-[7+(-6)+1]^3
Answer:
7.
Step-by-step explanation:
15 - [7 + (-6)+ 1]^3
Using PEMDAS:
= 15 - [ 7-6+1]^3
Next work out what is in the parentheses:
= 15 - 2*3
Now the exponential:
= 15 - 8
= 7.
Step-by-step explanation:
Hi,
I hope you are searching this, right.
=15[7+(-6)+1]^3
=15[7-6+1]^3
=15[2]^3
=15-8
=7...is answer.
Hope it helps..
Find the area ratio of a regular octahedron and a tetrahedron regular, knowing that the diagonal of the octahedron is equal to height of the tetrahedron.
Answer:
[tex]\frac{4}{3}[/tex]
Step-by-step explanation:
The area of a regular octahedron is given by:
area = [tex]2\sqrt{3}\ *edge^2[/tex]. Let a is the length of the edge (diagonal).
area = [tex]2\sqrt{3}\ *a^2[/tex]
Given that the diagonal of the octahedron is equal to height (h) of the tetrahedron i.e.
a = h, where h is the height of the tetrahedron and a is the diagonal of the octahedron. Let the edge of the tetrrahedron be e. To find the edge of the tetrahedron, we use:
[tex]h=\sqrt{\frac{2}{3} } e\\but\ h=a\\a=\sqrt{\frac{2}{3} } e\\e=\sqrt{\frac{3}{2} }a[/tex]
The area of a tetrahedron is given by:
area = [tex]\sqrt{3}\ *edge^2[/tex] = [tex]\sqrt{3} *(\sqrt{\frac{3}{2} }a)^2=\frac{3}{2}\sqrt{3} *a^2[/tex]
The ratio of area of regular octahedron to area tetrahedron regular is given as:
Ratio = [tex]\frac{2\sqrt{3}\ *a^2}{\frac{3}{2} \sqrt{3}*a^2} =\frac{4}{3}[/tex]
Solve by the quadratic formula: x^2= 6x-4
Answer:
3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex].
Step-by-step explanation:
x^2 = 6x - 4
x^2 - 6x + 4 = 0
Now, we can use the quadratic formula to solve.
[tex]\frac{-b\pm\sqrt{b^2 - 4ac} }{2a}[/tex], where a = 1, b = -6, and c = 4.
[tex]\frac{-(-6)\pm\sqrt{(-6)^2 - 4 * 1 * 4} }{2 * 1}[/tex]
= [tex]\frac{6\pm\sqrt{36 - 4 * 4} }{2}[/tex]
= [tex]\frac{6\pm\sqrt{36 - 16} }{2}[/tex]
= [tex]\frac{6\pm\sqrt{20} }{2}[/tex]
= [tex]\frac{6\pm2\sqrt{5} }{2}[/tex]
= 3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex]
x = 3 [tex]\pm[/tex] [tex]\sqrt{5}[/tex].
Hope this helps!
Please help i will mark brainliest
Answer:
See below.
Step-by-step explanation:
To find the equation, we need to find the slope and the y-intercept. Afterwards, we can put the numbers into the slope-intercept form:
[tex]y=mx+b[/tex]
From the graph, we can see that the line crosses the y-intercept at y=-6. Thus, the y-intercept (b) is -6.
Now we need to find the slope. Pick any two points where the line crosses. I'm going to pick (0,-6) and (4,-7).
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-7-(-6)}{4-0}= -1/4[/tex]
Therefore, the equation of the line would be:
[tex]y=mx+b\\y=-1/4x-6[/tex]
I NEED HELP WITH THIS! I need to pass...
Answer: A) The log parent function has negative values in the range.
Step-by-step explanation:
The domain of y = ln (x) is D: x > 0
The domain of y = [tex]\sqrtx[/tex][tex]\sqrt x[/tex] is D: x ≥ 0
The range of y = ln (x) is: R: -∞ < y < ∞
So the only valid option is A because the range of a log function contains negative y-values when 0 < x < 1.
dentify which of these types of sampling is used: random, systematic, convenience, stratified, or cluster. To determine her air qualityair quality, MirandaMiranda divides up her day into three parts: morning, afternoon, and evening. She then measures her air qualityair quality at 33 randomly selected times during each part of the day. What type of sampling is used?
Answer:
The sampling method used is a stratified sampling method
Step-by-step explanation:
sampling is the selection of a predetermined representative subpopulation from a larger population, to estimate the characteristics of the whole population.
Stratified sampling: Here, the total population are divided into subcategories (strata) before sampling is done. The strata are formed based on some common characteristics. In our example, the times of the day (morning, afternoon and evening) has widely varying atmospheric conditions which will add biases to the measurement of air quality. For example, the air in the morning if compared to the afternoon in an industrial area may be purer because of minimal industrial activity, hence effective comparison will be made by stratification.