Answer:
3
Step-by-step explanation:
Because the number 5 is a number that you get from 7 more than n, and 2 is the other divisor that means n must equal 10 and 7 less than 10 is 3.
When five times a number is divided by 7 more than the number and the result is 2, then the number is 14/3, which is solved using the linear equation in one variable 5x/(x+ 7) = 2, where x is the required number.
What are linear equations in one variable?Linear equations are first-order equations. Lines in the coordinate system are determined by linear equations. A linear equation in one variable is defined as an equation with a homogeneous variable of degree 1 (i.e. only one variable).
How to solve the given question?In the question, we are asked to find a number, which satisfies the statement, "Five times a number is divided by 7 more than the number. The result of this division is 2".
We assume the number to be x.
Now we try to form a linear equation in one variable from the given statement.
Five times a number is 5x.
7 more than a number is x + 7.
We are said that five times a number is divided by 7 more than a number. This can be shown as 5x/(x + 7).
Now, the result is given as 2, which can be shown as:
5x/(x+ 7) = 2, which is the required linear equation in one variable.
To get the number, we solve the equation using the following steps:
5x/(x+ 7) = 2
or, {5x/(x+ 7)}*(x + 7) = 2*(x + 7) (Multiplying both sides by (x + 7))
or, 5x = 2x + 14 (Simplifying)
or, 5x - 2x = 2x + 14 - 2x (Subtracting 2x from both sides)
or, 3x = 14 (Simplifying)
or, 3x/3 = 14/3 (Dividing both sides by 3)
or, x = 14/3 (Simplifying)
∴ When five times a number is divided by 7 more than the number and the result is 2, then the number is 14/3, which is solved using the linear equation in one variable 5x/(x+ 7) = 2, where x is the required number.
Learn more about the linear equation in one variable at
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what is the sum of 1 2/5 and 5 3/4
Answer:
[tex]7\frac{3}{20}[/tex]
Step-by-step explanation:
Hey there!
Well to add this we need to pu it in improper form.
7/5 + 23/4
Now we need to find the LCM.
5 - 5, 10, 15, 20, 25, 30
4 - 4, 8, 12, 16, 20, 24, 28
So the LCD is 20.
Now we need to change the 5 and 4 to 20.
5*4 = 20
7*4 = 28
28/20
4*5=20
23*5=115
115/20
Now we can add 28 and 115,
= 143/20
Simplified
7 3/20
Hope this helps :)
Answer:
[tex] \boxed{7 \frac{3}{20} }[/tex]Step-by-step explanation:
[tex] \mathrm{1 \frac{2}{5} + 5 \frac{3}{4} }[/tex]
Add the whole numbers and fractional parts of the mixed numbers separately
[tex] \mathrm{ = (1 + 5) + ( \frac{2}{5} + \frac{3}{4} })[/tex]
Add the numbers
[tex] \mathrm{=6 + ( \frac{2}{5} + \frac{3}{4} )}[/tex]
Add the fractions
[tex] \mathrm{=6 + (\frac{2 \times 4 + 3 - 5}{20} )}[/tex]
[tex] \mathrm{=6 + \frac{23}{20} }[/tex]
Convert the improper fractions into a mixed number
[tex] \mathrm{=6 + 1 \frac{3}{20} }[/tex]
Write the mixed number as a sum of the whole number and the fractional part
[tex] \mathrm {= 6 + 1 + \frac{3}{20} }[/tex]
Add the numbers
[tex] \mathrm{ = 7 + \frac{3}{20} }[/tex]
Write the sum of the whole number and the fraction as a mixed number
[tex] \mathrm{ = 7 \frac{3}{20} }[/tex]
Hope I helped
Best regards!
PLEASE PLEASE PLEASE HELP PLEAS :( THE SECOND ONE JEJEJEJDD PLEASEEEEEE
Answer:
P
Step-by-step explanation:
Count the line endings in each letter as you write it down.
Answer:
I agree with tonb .Ace,he's/she's right
RVLC2019] IC/Off
In AMNO, m = 20, n = 14, and mZM = 51°. How many distinct triangles can be formed given these measurements?
O There are no triangles possible.
VX
O There is only one distinct triangle possible, with m N= 33º.
O There is only one distinct triangle possible, with mZN 147º.
O There are two distinct triangles possible, with m2N 33° or mZN-147º.
Done
) Intro
DO
There is only one distinct triangle possible, with m N= 33º. Therefore, option B is the correct answer.
What is sine rule?Law of Sines In trigonometry, the law of sines, sine law, sine formula, or sine rule is an equation relating the lengths of the sides of any triangle to the sines of its angles.
The formula for sine rule is sinA/a=sinB/b=sinC/c
Given that, in ΔMNO, m = 20, n = 14, and m∠M = 51°.
Now, sin51°/20=sinN/14
0.7771/20=sinN/14
0.038855=sinN/14
sinN=14×0.038855
sinN=0.54397
N=33°
Therefore, option B is the correct answer.
Learn more about the sine rule here:
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Brainliest for the correct awnser!!! The function is not an example of a rational function. True or false?
Answer:
true
Step-by-step explanation:
Find the area under the standard normal probability distribution between the following pairs of z-scores. a. z=0 and z=3.00 e. z=−3.00 and z=0 b. z=0 and z=1.00 f. z=−1.00 and z=0 c. z=0 and z=2.00 g. z=−1.58 and z=0 d. z=0 and z=0.79 h. z=−0.79 and z=0
Answer:
a. P(0 < z < 3.00) = 0.4987
b. P(0 < z < 1.00) = 0.3414
c. P(0 < z < 2.00) = 0.4773
d. P(0 < z < 0.79) = 0.2852
e. P(-3.00 < z < 0) = 0.4987
f. P(-1.00 < z < 0) = 0.3414
g. P(-1.58 < z < 0) = 0.4429
h. P(-0.79 < z < 0) = 0.2852
Step-by-step explanation:
Find the area under the standard normal probability distribution between the following pairs of z-scores.
a. z=0 and z=3.00
From the standard normal distribution tables,
P(Z< 0) = 0.5 and P (Z< 3.00) = 0.9987
Thus;
P(0 < z < 3.00) = 0.9987 - 0.5
P(0 < z < 3.00) = 0.4987
b. b. z=0 and z=1.00
From the standard normal distribution tables,
P(Z< 0) = 0.5 and P (Z< 1.00) = 0.8414
Thus;
P(0 < z < 1.00) = 0.8414 - 0.5
P(0 < z < 1.00) = 0.3414
c. z=0 and z=2.00
From the standard normal distribution tables,
P(Z< 0) = 0.5 and P (Z< 2.00) = 0.9773
Thus;
P(0 < z < 2.00) = 0.9773 - 0.5
P(0 < z < 2.00) = 0.4773
d. z=0 and z=0.79
From the standard normal distribution tables,
P(Z< 0) = 0.5 and P (Z< 0.79) = 0.7852
Thus;
P(0 < z < 0.79) = 0.7852- 0.5
P(0 < z < 0.79) = 0.2852
e. z=−3.00 and z=0
From the standard normal distribution tables,
P(Z< -3.00) = 0.0014 and P(Z< 0) = 0.5
Thus;
P(-3.00 < z < 0 ) = 0.5 - 0.0013
P(-3.00 < z < 0) = 0.4987
f. z=−1.00 and z=0
From the standard normal distribution tables,
P(Z< -1.00) = 0.1587 and P(Z< 0) = 0.5
Thus;
P(-1.00 < z < 0 ) = 0.5 - 0.1586
P(-1.00 < z < 0) = 0.3414
g. z=−1.58 and z=0
From the standard normal distribution tables,
P(Z< -1.58) = 0.0571 and P(Z< 0) = 0.5
Thus;
P(-1.58 < z < 0 ) = 0.5 - 0.0571
P(-1.58 < z < 0) = 0.4429
h. z=−0.79 and z=0
From the standard normal distribution tables,
P(Z< -0.79) = 0.2148 and P(Z< 0) = 0.5
Thus;
P(-0.79 < z < 0 ) = 0.5 - 0.2148
P(-0.79 < z < 0) = 0.2852
Four friends are on a basketball team. During a game, each friend kept track of how many shots they attempted and how many of those attempts they made. Henry made 0.45 of his shots. Allison made Arthur made of her shots. of his shots. Trevor missed 58% of his shots. Which friend had the best record for the number of shots made?
Answer:
Henry had the best record for the number of shots made
Step-by-step explanation:
From the given information.
Four friends are on a basketball team.
Henry
Allison
Arthur
Trevor
We are being told that Henry made 0.45 of his shots out of all his attempts
Allison made Arthur made of her shots of his shots.
i,e Arthur did the work for Allison , so out of Arthur's shot , we have to figured out Allison shots,
Trevor missed 58% of his shots.
i.e Trevor failed 0.58 of his shot, If he failed 0.58 shot
Then the attempts Trevor made is :
= 1 - 0.58
= 0.42
SO , Trevor made 0.42 shots out of all his attempt
N:B We are not given any information about Arthur's shots , so we can't determine Allison shot as well.
Therefore; we will focus on only Henry and Trevor shots
So ;
Henry made 0.45 of his shots
Trevor made 0.42 out of his shots
We can thereby conclude that :
Henry had the best record for the number of shots made
If one termite can destroy 1.2mg of wood per day, how many kilograms of wood can 10 termites destroy in 1 week? *Can someone please explain how to do this*
Answer:
10 termites will destroy 0.000084kg of wood per week
Step-by-step explanation:
Convert milligram to kilogram
1.2mg=(1.2 / 1,000,000)kg
1.2mg=0.0000012kg
1 termite destroys=0.0000012kg per day
10 termites will destroy (per day) =0.0000012×10 termites per day
10 termites in one day will destroy=0.000012kg
There are 7 days in a week
Therefore,
10 termites will destroy=destruction per day × 7 days
=0.000012×7
=0.000084kg per week
ALGEBRA HELP PLEASE THANKS Evaluate the expression using exponential rules. Write the result in standard notation. [tex]\frac{4 x 10^{-4} }{20 x 10^{2} }[/tex]
Answer:
[tex]2 \times 10 {}^{ - 7} [/tex]
Step-by-step explanation:
[tex] \frac{4 \times 10 {}^{ - 4} }{20 \times 10 {}^{2} } = \frac{0.0004}{2000} = 2 \times 10 {}^{ - 7} [/tex]
Hope this helps ;) ❤❤❤
Question
Given that cot(0)= -1/2
and O is in Quadrant II, what is sin(0)? Write your answer in exact form. Do not round.
Provide your answer below:
Answer:
sin(O) = 2/sqrt(5) or 2sqrt(1/5)
Step-by-step explanation:
using 1+cot^2(x) = csc^2(x)
we have, taking reciprocal on both sides,
sin(x) = 1/sqrt(1+cot^2(x)
= 1/sqrt(1+(-1/2)^2)
= 1/sqrt(5/4)
= 2/sqrt(5) or 2sqrt(1/5)
Since angle x is in the second quadrant, sin(x) is positive.
g There are 60 mountain climbers in a club. 10 of these have climbed Mt. Everest. 15 have climbed Mt. Rainier. 8 have climbed both. How many have not climbed either mountain?
Answer:
43 mountain climbers have not climbed either mountain.
Step-by-step explanation:
Total number of mountain climbers, i.e. n(U) = 60
Number of mountain climbers who have climbed Mt. Everest, n(E) = 10
Number of mountain climbers who have climbed Mt. Rainier, n(R) = 15
Number of mountain climbers who have climbed both, n(E [tex]\cap[/tex] R) = 15
Using the formula to find number of climbers who have climbed either of the mountains:
[tex]n(A \cup B) = n(A)+n(B)-n(A\cup B )[/tex]
[tex]\therefore n(E \cup R) = n(E)+n(R)-n(E\cup R )\\\Rightarrow n(E \cup R) = 10+15-8 = 17[/tex]
To find, who have not climbed either mountain:
[tex]n(E\cup B)'=n(U) - n(E\cap B)\\\Rightarrow n(E\cup B)'=60 - 17 = \bold{43}[/tex]
So, the answer is:
43 mountain climbers have not climbed either mountain.
here are the 2 questions in the 2 pics separated lol
Answer:
60 and 87
Step-by-step explanation:
Question 1: The chance of losing would be 100% - 40% = 60%.
Question 2: Again, we just have to do 100% - 13% = 87%.
Answer:
Below
Step-by-step explanation:
First question:
Jade has a 40% chance of winnig wich could be expressed as 2/5
The chance of losing is the remainning pourcentage from 100%
●100-40 =60%
60% is the chance of losing wich could be expressed as 3/5
The sum of 3/5 and 2/5 is 1 so it's true.
■■■■■■■■■■■■■■■■■■■■■■■■■
Same method for the 2nd question:
The person has a 13 % chance of winning.
The chance of losing is 87%
● 100-13 =87
22,403 Check:
- 8,675
how i do this
Answer:
Hello!! :) The answer to your question is 13,728
Steps will be below.
Step-by-step explanation:
So we will subtract 22,403 and 8,675.
When we do that we will get 13,728
To check your answer we have to do the opposite of subtracting which will be adding.
This is how we check our work: the answer we got was 13,728...we have to take that answer and add it to 8,675 which will give us 22,403
(Both of the numbers are from the question)
At the bottom I attached a picture of how I did the subtracting and how I checked my work.
Sorry for my handwriting......if you can’t understand my handwriting, I attached another picture which is more clearer.
ANSWER TO YOUR QUESTION: 13,728
Brainliest would be appreciated! Thank you :3
Hope this helps! :)
Answer:
The answer is 13,728
Step-by-step explanation:
Check your work with addition.
A magazine article states that the mean weight of one-year-old boys is the same as that of one-year-old girls. Does the confidence interval contradict this statement? The confidence interval this statement
Answer:
Yes, the confidence interval contradict this statement.
Step-by-step explanation:
The complete question is attached below.
The data provided is:
[tex]n_{1}=318\\n_{2}=297\\\bar x_{1}=25\\\bar x_{2}=24.1\\s_{1}=3.6\\s_{2}=3.8[/tex]
Since the population standard deviations are not provided, we will use the t-confidence interval,
[tex]CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\cdot s_{p}\cdot\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}[/tex]
Compute the pooled standard deviation as follows:
[tex]s_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2}}=\sqrt{\frac{(318-1)(3.6)^{2}+(297-1)(3.8)^{2}}{318+297-2}}=2.9723[/tex]
The critical value is:
[tex]t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.05/2, (318+297-2)}=t_{0.025, 613}=1.962[/tex]
*Use a t-table.
The 95% confidence interval is:
[tex]CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\cdot s_{p}\cdot\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}[/tex]
[tex]=(25-24.1)\pm 1.962\times 2.9723\times \sqrt{\frac{1}{318}+\frac{1}{297}}\\\\=0.90\pm 0.471\\\\=(0.429, 1.371)\\\\\approx (0.43, 1.37)[/tex]
The 95% confidence interval for the difference between the mean weights is (0.43, 1.37).
To test the magazine's claim the hypothesis can be defined as follows:
H₀: There is no difference between the mean weight of 1-year old boys and girls, i.e. [tex]\mu_{1}-\mu_{2}=0[/tex].
Hₐ: There is a significant difference between the mean weight of 1-year old boys and girls, i.e. [tex]\mu_{1}-\mu_{2}\neq 0[/tex].
Decision rule:
If the confidence interval does not consists of the null value, i.e. 0, the null hypothesis will be rejected.
The 95% confidence interval for the difference between the mean weights does not consists the value 0.
Thus, the null hypothesis will be rejected.
Conclusion:
There is a significant difference between the mean weight of 1-year old boys and 1-year old girls.
3 = 1/2x + 1/2x + 1/2x.
Answer:
x =2
Step-by-step explanation:
3 = 1/2x + 1/2x + 1/2x
Combine like terms
3 = 3/2 x
Multiply each side by 2/3 to isolate x
3 * 2/3 = 2/3 * 3/2 x
2 =x
4km in the ratio 9:4:7
Answer:
500km
Step-by-step explanation:
add all the proportions and then divide by 3. with conversion.
11. Caroline wraps packages at a store. She wraps
9 packages each hour. Which statement is true
about the number of packages she wraps?
A. In 2 hours, Caroline wraps an odd number of
packages.
B. In 3 hours, Caroline wraps an even number of
packages.
C. In 5 hours, Caroline wraps an odd number of
packages.
D. In 7 hours, Caroline wraps an even number of
packages.
Answer:
C. in five hours Caroline wraps an odd number of packages
Step-by-step explanation:
for A until hours you would multiply 2 by 9 and 2 by 9 is 18 and that's an even number so it's not A.
A eliminated.
for B in 3 hours 3 by 9 is 27 and that's an odd number so B is automatically eliminated.
for C in 5 hours all you would do is multiply the 9 by 5 and 9 by 5 is 45 and 45 is indeed an odd number so C is your answer.
for D 7 by 9 is 63 and 63 is an odd number so we already know that C is the answer but still we got to check and D is wrong because 63 is not an even number.
Section 8
Find the mean of these numbers:
24 18
37
82 17
26
Answer:
[tex]\boxed{Mean = 34.33}[/tex]
Step-by-step explanation:
Mean = Sum of Observations / No. Of Observations
Mean = (24+18+37+82+17+26)/6
Mean = 206 / 6
Mean = 34.33
Find the solution(s) of the system of equations: x2 + y2 = 8 y = x – 4 options: (–2,–6) (2,–2) and (–2,–6) (2,–2) No solutions
Answer: x=2 y=-2
(2,-2) one solution
Step-by-step explanation:
Solve by substitution
[tex]\begin{bmatrix}x^2+y^2=8\\ y=x-4\end{bmatrix}[/tex]
[tex]\mathrm{Subsititute\:}y=x-4[/tex]
[tex]\begin{bmatrix}x^2+\left(x-4\right)^2=8\end{bmatrix}[/tex]
[tex]2x^2-8x+16=8[/tex]
[tex]\mathrm{Isolate}\:x\:\mathrm{for}\:2x^2-8x+16=8:\quad x=2[/tex]
[tex]\mathrm{For\:}y=x-4[/tex]
[tex]\mathrm{Subsititute\:}x=2[/tex]
[tex]y=2-4[/tex] [tex]2-4=-2[/tex]
[tex]y=-2[/tex]
[tex]The\:solutions\:to\:the\:system\:of\:equations\:are[/tex]
[tex]x=2,\:y=-2[/tex]
Need Help with these (Giving brainiest if you can solve these)
Answer: try using sine for this equasion
Step-by-step explanation:
WHY IS THERE ANY HELP? PLEASE Solve the system of equations by using the substitution method. [tex]\left \{ {{x+y=6} \atop {x=2y}} \right.[/tex] Is there a solution, no solution, or infinite number? If there's a solution, what's the ordered pair?
Answer:
There is a solution. The ordered pair is (4, 2).
Step-by-step explanation:
Solve the system of equations by using the substitution method.
[tex]x+y=6\\x=2y[/tex]
Substitute x as 2y in the first equation and solve for y.
[tex]2y+y=6\\ 3y=6\\(3y)/3=6/3\\y=2[/tex]
Substitute y as 2 in the second equation and solve for x.
[tex]x=2(2)\\x=4[/tex]
An estimator is said to be consistent if: the difference between the estimator and the population parameter grows smaller as the sample size grows larger. it is an unbiased estimator. the variance of the estimator is zero. the difference between the estimator and the population parameter stays the same as the sample size grows larger.
Answer:
the difference between the estimator and the population parameter grows smaller as the sample size grows larger.
Step-by-step explanation:
In Statistics, an estimator is a statistical value or quantity, which is used to estimate a parameter.
Generally, parameters are the determinants of the probability distribution. Thus, to determine a normal distribution we would use the parameters, mean and variance of the population.
An estimator is said to be consistent if the difference between the estimator and the population parameter grows smaller as the sample size grows larger. This simply means that, for an estimator to be consistent it must have both a small bias and small variance.
Also, note that the bias of an estimator (b) that estimates a parameter (p) is given by; [tex]E(b) - p[\tex]
Hence, an unbiased estimator is an estimator that has an expected value that is equal to the parameter i.e the value of its bias is equal to zero (0).
A sample variance is an unbiased estimator of the population variance while the sample mean is an unbiased estimator of the population mean.
Generally, a consistent estimator in statistics is one which gives values that are close enough to the exact value in a population.
State the degrees of freedom error in each of the following tests. (a) A consultant measures job satisfaction in a sample of 14 supervisors, 14 managers, and 14 executives at a local firm. (b) A researcher tests how nervous public speakers get in front of a small, medium, or large audience. Ten participants are randomly assigned to each group. (c) A high school counselor has 8 students in each of five classes rate how much they like their teacher.
Answer:
.
Step-by-step explanation:
Which of the following triangles can be proven similar through AA?
A)
B)
C)
D)
Answer:
The options that have two angles, which are A and D prove both triangles to be similar.
Step-by-step explanation:
The postulate AA is exactly what it sounds like, and you can find the two angles, which will prove the similarity of two triangles sharing those two angles.
The reason being is if two angles are the same between the two triangles, the third can't be different.
of the 1248 students enrolled 24% did not like the new mascot design. what is the mean of this binomial distribution
A. 299.5
B. 948.5
C. 17.3
D. 300.3
Answer: A. 299.5
Step-by-step explanation:
1248 · 24%
1248 · 0.24=299.50
The average student loan debt for college graduates is $25,800. Suppose that that distribution is normal and that the standard deviation is $14,150. Let X = the student loan debt of a randomly selected college graduate. Round all probabilities to 4 decimal places and all dollar answers to the nearest dollar The middle 20% of college graduates' loan debt lies between what two numbers?
The measure of position called the midquartile of a data set is found using the formula StartFraction Upper Q 1 plus Upper Q 3 Over 2 EndFraction . Find the midquartile of the given data set. 23 37 49 34 35 41 40 26 32 22 38 42
Answer:
35.25
Step-by-step explanation:
Give the data set:
23 37 49 34 35 41 40 26 32 22 38 42
We are expected to calculate the midquartile of the given data set.
22 23 26 32 34 35 37 38 40 41 42 49
First step is to find the lower quartile which comprises of
22 23 26 32 34 35
Here the Q1 is (26+32)/2 = 58/2= 29
Second step to find the upper quartile which comprises of
37 38 40 41 42 49
Here the Q3 is (40+41) /2 = 81/2 = 41.5
Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5
= (29+41.5)/2
= (70.5) /2 = 35.25
CAN ANYONE HELP ME PLEASE? Jen Butler has been pricing Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $106. Two adults and three children must pay $75. Find the price of the adult's ticket and the price of a child's ticket.
Answer:
The adult ticket costs $18 and the children ticket costs $13.
Step-by-step explanation:
Let the price of the adult ticket be a.
Let the price of the children ticket be c.
Three adults and four children must pay $106. This implies that:
3a + 4c = 106 _______(1)
Two adults and three children must pay $75. This implies that:
2a + 3c = 75 ________(2)
We have two simultaneous equations:
3a + 4c = 106 _____(1)
2a + 3c = 75 ______(2)
Multiply (1) by 2 and (2) by 3 and subtract (1) from (2):
6a + 9c = 225
- (6a + 8c = 212)
c = $13
Put this value of c in (2):
2a + 3*13 = 75
2a + 39 = 75
=> 2a = 75 - 39
2a = 36
a = 36/2 = $18
Therefore, the adult ticket costs $18 and the children ticket costs $13.
Show that between any two terminating decimals ,there is another terminating decimal
Answer:
1.5+1.7/2=1.6
Step-by-step explanation:
which of the following is equivalent to the expression below? log2-log14 A. LOG(1/7) B. LOG(-12) C. LOG 12 D. LOG 7
Answer:
The answer is option A.
Step-by-step explanation:
Using the properties of logarithms
that's
[tex] log(x) - log(y) = log( \frac{x}{y} ) [/tex]
log 2 - log 14 is
[tex] log(2) - log(14) = log( \frac{2}{14} ) [/tex]
Simplify
We have the final answer as
[tex] log( \frac{1}{7} ) [/tex]
Hope this helps you
Answer:
log ( 1/7)
Step-by-step explanation:
log2-log14
We know that log ( a/b) = log a - log b
log (2 /14)
log ( 1/7)
The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance, and standard deviation of the population data set.
2, 10, 15, 4, 11, 10, 15, 10, 2, 10
Answer:
a
[tex]R =13[/tex]
b
[tex]\= x =8.9[/tex]
c
[tex]var(x) = 16.57[/tex]
d
[tex]\sigma = 4.1[/tex]
Step-by-step explanation:
From the question we are given a data set
2, 10, 15, 4, 11, 10, 15, 10, 2, 10
The sample size is n = 10
The range is
[tex]R = maxNum - MinNum[/tex]
Where maxNum is the maximum number on the data set which is 15
and MinNum is the minimum number on the data set which is 2
So
[tex]R = 15 - 2[/tex]
[tex]R =13[/tex]
The mean is mathematically represented as
[tex]\= x = \frac{\sum x_i}{N}[/tex]
substituting values
[tex]\= x = \frac{2 + 10 + 15 + 4 + 11 + 10 + 15 + 10 + 2 + 10 }{10}[/tex]
[tex]\= x =8.9[/tex]
The variance is mathematically evaluated as
[tex]var(x) = \frac{\sum (x - \= x)^2}{N}[/tex]
substituting values
[tex]var(x) = \frac{(2 - 8.9 )^2 + (10 - 8.9 )^2 + (15 - 8.9 )^2 +(4 - 8.9 )^2 +(11 - 8.9 )^2 +(10 - 8.9 )^2 +(15 - 8.9 )^2 +(10 - 8.9 )^2 +} {10}[/tex] [tex]\frac{(2 - 8.9 )^2 +(10 - 8.9 )^2 }{10}[/tex]
[tex]var(x) = 16.57[/tex]
The standard deviation is [tex]\sigma = \sqrt{var(x)}[/tex]
substituting values
[tex]\sigma = \sqrt{16.57}[/tex]
[tex]\sigma = 4.1[/tex]