The factor that leads to loess deposit is when the wind carries fine sediment. That is option C.
What are loess deposits?The loess deposits are those deposits that are usually found at the edge of deserts.
The major factor that causes the formation of loess is the wind because they are entrained, transported, and deposited by the wind.
The fine particles carried by wind contains find grained sediments, organic particles that are capable of forming loess.
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A .35 kg block at -27.5 ºC is added to .217 kg of water at 25.0 ºC. They come to equilibrium at 16.4 ºC. What is the specific heat of the block?
Answer:
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To solve this problem, we can use the formula for heat transfer:
q = mcΔT
where q is the heat transferred, m is the mass of the object, c is its specific heat capacity, and ΔT is the change in temperature.
We know that the mass of the block is 0.35 kg and that its initial temperature is -27.5 ºC. We also know that the mass of water is 0.217 kg and that its initial temperature is 25.0 ºC.
When they come to equilibrium at 16.4 ºC, we can calculate how much heat was transferred from the water to the block:
q = mcΔT q = (0.217 kg)(4186 J/kg ºC)(25.0 ºC - 16.4 ºC) q = 1825 J
This amount of heat was transferred from the water to the block, so we can set it equal to the amount of heat absorbed by the block:
q = mcΔT 1825 J = (0.35 kg)c(16.4 ºC - (-27.5 ºC)) 1825 J = (0.35 kg)c(43.9 ºC) c = 148 J/kg ºC
Therefore, the specific heat capacity of the block is 148 J/kg ºC.
Explanation:
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A model rocket blast off and moves upward with an acceleration of 12m/s2 until it reaches a height of 26m, at which point its engine shuts off and it continues its flight in free fall.
a) What is the maximum height attained by the rocket?
b) What is the speed of the rocket just before it hits the ground?
c) What is the total duration of the rocket's flight?
Within the living area of the colony, what atmospheric gases must be present on Venus?
Humans would need a breathable environment like that on Earth in the living section of a colony on Venus in order to survive. Nitrogen, oxygen, and trace amounts of other gases, such as carbon dioxide, make up the majority of the atmosphere on Earth.
What gases are present in Venus' atmosphere?The clouds are made of sulfuric acid, and the atmosphere is primarily carbon dioxide, the same gas that causes the greenhouse effect on Venus and Earth. And the heated, high-pressure carbon dioxide acts corrosively at the surface.
What gases are found in Mars' and Venus' atmospheres?For instance, compared to Earth, which has 99% nitrogen and oxygen in its atmosphere, Venus and Mars both contain more than 98% carbon dioxide and nitrogen.
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On the water surface, there are two sources of oscillating waves of the same phase located at A and B, emitting two coherent waves of wavelength λ. Let Δ be the line perpendicular to AB at B. On Δ there are 16 interference maxima, the distance between the two closest and farthest interference maxima is 2.71 cm and 229.55 cm, respectively. . Which of the following is the length of line segment AB closest to?
Two or greater sources are said to be coherent if they emit waves that have the identical wavelength (or frequency) and amplitude and which maintain a steady phase difference.
Do two coherent sources have equal wavelength?If two sources have the identical wavelength, frequency, and segment difference, they are said to be coherent. Therefore, we can conclude that coherent sources have the identical wavelength.
Two microwave coherent factor sources emitting waves of wavelenths λare positioned at 5λdistance apart. The interference is being observed on a flat non-reflecting surface alongside a line passing through on sources ,in a course perpendicular to the line joining the two sources
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https://brainly.com/question/12495315#SPJ1A 0.80kg block of carbon (solid) is dropped into 1.4kg of water. If the carbon starts at -20C, the water starts at 92C, and they have equal final temperatures, what is the final temperature of the system?
The system's final temperature is roughly 16.7°C.
What is a system's final temperature?You may determine your substance's final heat by multiplying the temperature change by the initial temperature. Your water's final temperature would be 24 + 6, or 30 degrees Celsius, for instance, if it started off at 24 degrees Celsius.
The following is the formula for energy conservation:
Q1 + Q2 = 0
Q = mcΔT
Q1 + Q2 = 0
568.8
Simplifying and solving for
6394.4 - 106768 = 0
= 16.7°C
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A ball thrown straight upward returns to its original level in 2.75 seconds. A second ball is thrown at an angle of 40 degrees above the horizontal. What is the initial speed ball if it also returns to its original level in 2.75 seconds?
The initial speed (magnitude of velocity) of the second ball thrown at an angle of 40 degrees above the horizontal is approximately 12.93 m/s.
What is the initial speed ball?Let's consider the motion of the second ball thrown at an angle of 40 degrees above the horizontal. We can break down its motion into horizontal and vertical components.
Given:
Time taken for the ball to return to its original level (time of flight): t = 2.75 seconds
Angle of projection (above the horizontal): θ = 40 degrees
We can use the following equations of motion to find the initial speed (magnitude of velocity) of the ball:
Horizontal motion:
The horizontal velocity of the ball remains constant throughout the motion, and can be given as:
vx = v0 * cos(θ), where v0 is the initial speed.
Vertical motion:
The vertical velocity of the ball changes due to the force of gravity. We can use the following equation:
vy = v0 * sin(θ) - g * t,
where;
g is the acceleration due to gravitySince the ball returns to its original level, the vertical displacement (change in height) is zero:
Δy = 0
We can use the following equation to relate the initial speed, time of flight, and angle of projection:
Δy = v0 * sin(θ) * t - (1/2) * g * t^2 = 0
Plugging in the values and solving for v0:
0 = v0 * sin(40) * 2.75 - (1/2) * 9.8 * (2.75)^2
v0 * sin(40) * 2.75 = (1/2) * 9.8 * (2.75)^2
v0 = (1/2) * 9.8 * (2.75)^2 / (sin(40) * 2.75)
v0 = 12.93 m/s (rounded to two decimal places)
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If the speed of a wave is 400 cm/s with a frequency of 80 Hz, what is the wavelength for this wave?
32,000 cm
32,000 m
5 cm
5m
Can anyone please help me
To solve this problem, we can use Coulomb's law, which states that the electric force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.
We can then use the electric force to find the electric field at the location of q3 and the initial acceleration of q3.
a) To find the electric field at the location of q3, we can first find the electric force on q3 due to q1 and q2 and then use the definition of the electric field, which is the electric force per unit charge. The electric force on q³ due to q¹ and q² is:
F1 = k x q¹ x q³/ r1²
F2 = k x q² x q³ / r2²
where r¹ and r² are the distances from q¹ and q² to q³, respectively, and k is Coulomb's constant.
Since q³ is equidistant from q¹ and q², we have r¹ = r² = 0.20 m. Substituting the given values, we get:
F1 = (9.0 x 10⁹ N-m²/C²) x (4.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = 1.8 N
F2 = (9.0 x 10⁹ N-m⁻²/C²) x (-6.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = -5.4 N
The negative sign of F2 indicates that the force on q³ due to q² is in the opposite direction to the force due to q¹.
The net electric force on q3 is the vector sum of the forces due to q1 and q2:
Fnet = F1 + F2 = 1.8 N - 5.4 N = -3.6 N
The electric field at the location of q³ is then:
E = Fnet / q³ = (-3.6 N) / (2.0 x 10⁻⁶ C) = -1.8 x 10⁻⁶N/C
The negative sign of the electric field indicates that the field is directed towards q².
b) To find the initial acceleration of q³, we can use Newton's second law, which states that the net force on an object is equal to its mass times its acceleration:
Fnet = ma
where m is the mass of q³ and a is its initial acceleration.
Substituting the given values, we get:
-3.6 N = (2.0 x 10⁻⁶ kg) x a
Solving for a, we get:
a = -1.8 x 10³ m/s²
The negative sign of the acceleration indicates that it is directed towards q².
c) The direction of the initial acceleration of q³ is towards q².
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A tsunami (tidal wave) traveling across deep water can have a speed of 750 km/h
and a wavelength of 270 km
What is the frequency of such a wave?
Express your answer to two significant figures and include the appropriate units
The frequency of the tsunami wave is estimated at 0.001 Hz
How do we calculate?Frequency is described as the number of occurrences of a repeating event per unit of time
Using the formula for the speed of a wave:
v = λ x frequency
where v is the wave speed, λ is the wavelength, and f_ is the frequency.
frequency = v / λ
Substituting the values given in the problem, we have
frequency = 750 km/h / 270 km = 2.78 h^(-1)
f_ = 2.78 h^(-1) * (3600 s/h) = 1.00 x 10^(-3) s^(-1) or 0.001 Hz
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5. Two equal charges are situated in a vacuum 10.0cm apart, if they repel each other with a force of 0.5N, calculate the value of the charge on each. [4π)¹ = 9.0 x 10⁹ I
The value of the charge on each particle is [tex]1.05 x 10^-8 C[/tex].
What is Coulomb's law?Coulomb's law is a fundamental principle of electrostatics that describes the interaction between electric charges. It states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. We can use Coulomb's law to solve this problem. Mathematically,
[tex]F = k(q1q2)/r^2[/tex]
where F is the force of attraction or repulsion between the two charged particles,[tex]q1[/tex] and [tex]q2[/tex] are the magnitudes of the charges on the two particles, r is the distance between them, and k is Coulomb's constant, which has a value of [tex]9.0 x 10^9 Nm^2/C^2.[/tex]
In this problem, we know that the charges are equal and the distance between them is 10.0 cm. We also know that the force between them is 0.5 N. Therefore,
[tex]0.5 N = k(q^2)/(0.1 m)^2[/tex]
Solving for q, we get:
[tex]q = \sqrt{[(0.5 N)(0.1 m)^2/k]}[/tex]
[tex]q = \sqrt{(0.5 N)(0.01 m)/(9.0 x 10^9 Nm^2/C^2)}[/tex]
[tex]q = 1.05 x 10^-8 C[/tex]
Therefore, the value of the charge on each particle is [tex]1.05 x 10^-8 C.[/tex]
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A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 30.7 ◦C.
In an attempt to cool the liquid, which has a mass of 188 g , 129 g of ice at 0.0 ◦C is added. At the time at which the temperature of the tea is 26.6 ◦C , find the mass of the remaining ice in the jar. The specific heat of water is 4186 J/kg◦ C . Assume the specific heat capacity of the tea to be that of pure liquid water. Answer in units of g.
The mass of the remaining ice in the jar is 188 g.
What is Equilibrium?
Equilibrium refers to a state of balance or stability where opposing forces or factors are balanced, resulting in a state of overall stability and no net change. In various contexts, equilibrium can have different meanings and applications.
We can rearrange the equations to solve for the mass of ice remaining (mice):
Qtea = Qice
mtea * ctea * ΔT = mice * cice * ΔT
mice = (mtea * ctea * ΔT) / (cice * ΔT)
Plugging in the given values:
mtea = 188 g
ctea = 4186 J/kg◦ C (specific heat capacity of water)
ΔT = 30.7 - 26.6 = 4.1 ◦C (change in temperature of the tea)
cice = 4186 J/kg◦ C (specific heat capacity of ice)
mice = (188 * 4186 * 4.1) / (4186 * 4.1)
mice = 188 g
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A locust jumps at an angle of 55.0° and lands 0.750 m from where it jumped.
Aproximately 1.09 m/s was the locust's first speed.
What role do vectors have in mechanics?In engineering mechanics, vectors are used to express values with both a magnitude and a direction. For analysis, vector representations of a variety of engineering quantities—including forces, displacements, velocities, and accelerations—are required.
Δy = vsin(θ)t - 0.5gt²
0 = v*sin(55°)t - 0.5(-9.81 m/s²)*t²
t = 2vsin(55°)/g
Now, we can use the horizontal motion of the locust to find the initial velocity v. The horizontal distance traveled by the locust is given by:
Δx = v*cos(55°)*t
Substituting the expression for t that we just found:
0.750 m = vcos(55°)2vsin(55°)/g
Solving for v:
v = √(0.750 mg/(2sin(55°)*cos(55°)))
v ≈ 1.09 m/s
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URGENT!!! 50 POINTS NO CHATGPT!
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surface of the water It takes a time of 3.00 s for the boat to travel from its highest point to its lowest, a total distance of 0.650 m
mThe fisherman sees that the wave crests are spaced a horizontal distance of 5.90 m apart
Part A
How fast are the waves traveling?
Express the speed v in meters per second using three significant figures.
What is the amplitude A of each wave?
Express your answer in meters using three significant figures.
Answer:
Part A: [tex]1.97ms^{-1}[/tex] (2 s.f.)
Part B: 0.33m (2 s.f.)
Explanation:
Part A:
Frequency = [tex]\frac{1}{period} = \frac{1}{3}[/tex] Hz
Wavespeed = frequency x wavelength
Wavelength = distance between two crests = 5.90
Freq = 1/3 Hz
Therefore: Wavespeed = 1/3 x 5.90
Wavespeed = 1.967 ms^-1
Part B:
Amplitude = [tex]\frac{peak-to-peak- amplitude }{2}[/tex]
Peak to peak amplitude = 0.65m
Amplitude = 0.65/2 = 0.325m = 0.33m 2sf
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As you sit in a fishing boat, you notice that 12 waves pass the boat every 45 s
. If the distance from one crest to the next is 9.0 m
, what is the speed of these waves?
Express your answer to two significant figures and include the appropriate units.
The speed of the waves can be expressed to two significant figures as 0.2 m/s. The unit for this expression is meters per second (m/s).
What is wave crest?A wave crest is the highest point of a wave. It is the top of the wave, where the wave is moving most up and away from the equilibrium position. It is the point of highest amplitude (height) of the wave and is followed by a wave trough, which is the lowest point of the wave.
The speed of the waves can be calculated using the formula speed = distance over time.
We know the distance between wave crests is 9.0 m and the time it takes for 12 waves to pass the boat is 45 s. Therefore, the speed of the waves can be calculated as:
Speed = 9.0 m / 45 s
Speed = 0.2 m/s
The speed of the waves can be expressed to two significant figures as 0.2 m/s. The unit for this expression is meters per second (m/s).
This calculation shows that the speed of the waves passing the boat is 0.2 m/s. This speed can be further broken down into how many meters the waves travel in one second if necessary.
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A Carnot Engine operates between two heat reservoirs. The cold reservoir is maintained at 20.0 °C. What temperature must the hot reservoir be at in order for the efficiency of the engine to be 20.0 %?
A heat engine with a 65.0% Carnot efficiency is currently being developed. Between a reservoir that is 25.00C and one that is 3750C, a heat engine is operational.
What is the formula for Carnot efficiency ?The equation is: Carnot efficiency is equal to 1 - Tc/Th, wherein Tc is the cycle's cold end temperature and Th is its hot end temperature. In other words, efficiency is equal to one minus the difference between the hot and cold temperatures.
Explanation: The cold reservoir's temperature is TL=20C=20+273=293K. T L = 20 ∘ C = 20 + 273 = 293 K .
A Carnot cycle running between both of these two reservoirs has a thermal efficiency of = 1 TC/TH. This value exceeds the value of the Otto cycle, which is operating between similar reservoirs by a large margin.
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The nearest neighboring star to the Sun is about 4 light-years away. If a planet happened to be orbiting this star at an orbital radius equal to that of the Earth-Sun distance, what minimum diameter would an Earth-based telescope's aperture have to be in order to obtain an image that resolved this star-planet system? Assume the light emitted by the star and planet has a wavelength of 550 nm
. The Earth-Sun distance is 149.6×106km
, and 1ly=9.461×1015m
.
To resolve the star-planet system at a distance of 4 light-years, a telescope on Earth would need an aperture with a minimum diameter of 55.88 mm.
What does microscopy's Rayleigh criterion mean?In optical microscopy, the Rayleigh criterion is frequently used to estimate the resolution of the microscope. The resolution limit imposed by this criterion has long been regarded as a roadblock to using an optical microscope to study biological phenomena at the nanoscale.
We can use the Rayleigh criterion,
θ = 1.22 λ / D
θ = angular resolution
λ = wavelength of light
D = diameter of the telescope's aperture
θ = arctan (r / d)
r = radius of the planet's orbit
d = distance to the star
Now, we use the given values,
r = 149.6×106 km = 149.6×109 m
d = 4 × 9.461×1015 m = 3.7844×1016 m
λ = 550 nm = 550×10-9 m
θ = arctan (r / d)
=arctan (149.6×109 / 3.7844×1016) = 0.000012 radians
we can use the Rayleigh criterion,
θ = 1.22 λ / D
D = 1.22 λ / θ
D = 1.22 × 550×10-9 / 0.000012
D = 55.88 mm
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Harmonic Motion Basics
10. Calculate the period of a pendulum that has a length of 68 cm.
The period of the pendulum with a length of 68 cm is 1.65 seconds.
What is period of the pendulum?
The period of a pendulum is the time taken for one complete back-and-forth swing or oscillation. It is the time taken for the pendulum to move from its highest point (the point of maximum displacement) to its lowest point and back again to the highest point. The period of a pendulum depends on its length and the acceleration due to gravity.
The period of a pendulum can be calculated using the formula:
T = 2π√(L/g)
where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.81 m/s²).
Converting the length of the pendulum to meters:
L = 68 cm = 0.68 m
Substituting the values into the formula:
T = 2π√(0.68 m / 9.81 m/s²)
Simplifying:
T = 2π√(0.0694 s²)
Calculating the square root:
T = 2π x 0.263 s
Simplifying:
T = 1.65 s
Therefore, the period of the pendulum with a length of 68 cm is 1.65 seconds.
What is an acceleration of the pendulum?
An acceleration of a pendulum refers to the rate at which its velocity changes as it swings back and forth. The acceleration of a pendulum is not constant but rather varies as the pendulum swings, with the greatest acceleration occurring at the endpoints of its swing, where it changes direction.The acceleration of a pendulum is directly proportional to the displacement of the pendulum from its equilibrium position.
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Complete question is: The period of the pendulum with a length of 68 cm is 1.65 seconds.
A ball is traveling at a constant speed of 4 m/s in a circle with a radius of 0.8 m. What is the centripetal acceleration of the ball?
According to the question the centripetal acceleration of the ball is 20 m/s².
What is centripetal acceleration?Centripetal acceleration is the acceleration that a body experiences when it is moving in a curved path. It is always directed towards the center of the curve, and its magnitude is equal to the square of the body's velocity divided by the radius of the curve. It is also known as the radial acceleration, since it is directed along the radius of the curve.
The centripetal acceleration of an object in a circular path is given by the equation:
[tex]a_c[/tex] = v²/r
where a_c is the centripetal acceleration, v is the speed of the object, and r is the radius of the circular path.
In this case, the speed of the ball is 4 m/s, and the radius of the circular path is 0.8 m. Plugging these values into the equation, we get:
[tex]a_c[/tex] = 4²/0.8 = 16/0.8 = 20 m/s²
Therefore, the centripetal acceleration of the ball is 20 m/s².
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Cary calculated the surface area of a box in the shape of a rectangular prism. She wrote the equation 148 = 2 (6w + 6h + hw) to represent the width and height of the box. She solved for w and got w = StartFraction 74 minus 6 h Over h + 6 EndFraction Which of the following is an equivalent equation?
w = StartFraction 148 minus 6 h Over 12 + h EndFraction
w = StartFraction 148 minus 12 h Over 12 + 2 h EndFraction
w = 136 minus 14 h
w = 136 minus 10 h
The correct equivalent equation from the options provided is:
w = (24.67 - h) / (h + 6)
What is Equivalent Equation?
An equivalent equation is an equation that has the same solution or solutions as the original equation. In other words, if two equations produce the same values for the variables, they are considered equivalent equations.
The equivalent equation for w, based on the given equation and solving for w, is:
w = (148 - 6h) / (h + 6)
To simplify this equation, we can factor out 6 from the numerator:
w = 6(24.67 - h) / (h + 6)
Now we can further simplify by dividing both numerator and denominator by 6:
w = (24.67 - h) / (h + 6)
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In the diagram, q₁, q2, and q3 are in a straight line.
Each of these particles has a charge of
-2.35 x 10-6 C. Particles q₁ and q2 are separated
by 0.100 m and particles q2 and q3 are separated
by 0.100 m. What is the net force on particle q₁?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
The net force on particle q₁ is 9.22 × 10^-13 N, and it points to the left.
How do we calculate?The net force on particle q₁ due to particles q2 and q3 can be found using Coulomb's law.
Coulomb's law states that the force between two charged particles is given as
F= k * (q₁ * q₂) / r^2
Since q₁ and q₂ have the same charge, the force between them is repulsive, i.e., it points to the left. Using Coulomb's law, we can find the magnitude of this force:
F₁₂ = k * (q₁ * q₂) / r₁₂^2
F₁₂ = (9 × 10^9 Nm^2/C^2) * (-2.35 × 10^-6 C)^2 / (0.100 m)^2
F₁₂ = -4.61 × 10^-13 N
Here, the force between q₁ and q₂ points to the left, and its magnitude is 4.61 × 10^-13 N.
The force between q₂ and q₃ also points to the left, and its magnitude is given as
F₂₃ = k * (q₂ * q₃) / r₂₃^2
F₂₃ = (9 × 10^9 Nm^2/C^2) * (-2.35 × 10^-6 C)^2 / (0.100 m)^2
F₂₃ = -4.61 × 10^-13 N
Here, the force between q₂ and q₃ also points to the left, and its magnitude is 4.61 × 10^-13 N.
F_net = -F₁₂ - F₂₃
F_net = -(-4.61 × 10^-13 N) - (-4.61 × 10^-13 N)
F_net = 9.22 × 10^-13 N
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a wave has a frequency of 40 hertz and a wavelength of 2 meters . what is the wave speed ?
Answer:
[tex]80\; {\rm m\cdot s^{-1}}[/tex].
Explanation:
The frequency [tex]f[/tex] of a wave is the number of cycles completed in unit time ([tex]1\; {\rm s}[/tex] in this example.) In this question, [tex]f = 40\; {\rm s^{-1}}[/tex] ([tex]1\; {\rm Hz} = 1\; {\rm s^{-1}}[/tex]) means that the wave would complete [tex]40[/tex] cycles in every [tex]1\; {\rm s}[/tex].
The wavelength [tex]\lambda[/tex] of a wave is the distance the wave travels in each cycle. It is given that [tex]\lambda = 2\; {\rm m}[/tex].
The goal is to find the wave speed, which is the distance that this wave travels in unit time ([tex]1\; {\rm s}[/tex].)
In this question, it is given that [tex]\lambda = 2\; {\rm m}[/tex] and [tex]f = 40\; {\rm s^{-1}}[/tex]. Thus, this wave would travel a total of [tex]40\, (2\; {\rm m}) = 80\; {\rm m}[/tex] for the [tex]40[/tex] cycles completed in each unit time of [tex]1\; {\rm s}[/tex] ([tex]\lambda = 2\; {\rm m}[/tex] for each cycle.) The speed of this wave would be [tex]80\; {\rm m\cdot s^{-1}}[/tex].
Formally, the speed [tex]v[/tex] of this wave can be found by multiplying the wavelength [tex]\lambda[/tex] of this wave by its frequency [tex]f[/tex]:
[tex]\begin{aligned}v &= \lambda\, f \\ &= (2\; {\rm m})\, (40\; {\rm s^{-1}) \\ &= 80\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
A 25 kg child plays on a swing having support ropes that are 2.20 m long. A friend pulls her back until the ropes are ăÿÿfrom the vertical and releases her from rest. (a) What is the potential energy for the child just as she is released compared with the potential energy at the bottom of the swing? (b) How fast will she be moving at the bottom of the swing? (c) How much work does the tension in the ropes do as the child swings from the initial position to the bottom?
Answer:
A) P.E = 138.44 J
B) The velocity of swing at bottom, v = 3.33 m/s
C) The work done, W = -138.44 J
Explanation:
Given,
The mass of the child, m = 25 Kg
The length of the swing rope, L = 2.2 m
The angle of the swing to the vertical position, ∅ = 42°
A) The potential energy at the initial position ∅ = 42° is given by the relation
P.E = mgh joule
Considering h = 0 for the vertical position
The h at ∅ = 42° is h = L (1 - cos∅)
P.E = mgL (1 - cos∅)
Substituting the given values in the above equation
P.E = 25 x 9.8 x 2.2 (1 - cos42°)
= 138.44 J
The potential energy for the child just as she is released, compared to the potential energy at the bottom of the swing is, P.E = 138.44 J
B) The velocity of the swing at the bottom.
At bottom of the swing the P.E is completely transformed into the K.E
∴ K.E = P.E
1/2 mv² = 138.44
1/2 x 25 x v² 138.44
v² = 11.0752
v = 3.33 m/s
The velocity of the swing at the bottom is, v = 3.33 m/s
C) The work done by the tension in the rope from initial position to the bottom
Tension on string, T = Force acting on the swing, F
=
= - 2.2 x 25 x 9.8 [cos0 - cos 42°]
= - 138.44 J
The negative sign in the in energy is that the work done is towards the gravitational force of attraction.
The work done by the tension in the ropes as the child swings from the initial position to the bottom of the swing, W = - 138.44 J
A rock climber stands on top of a 59 m -high cliff overhanging a pool of water. He throws two stones vertically downward 1.0 s apart and observes that they cause a single splash. The initial speed of the first stone was 1.7 m/s . Include value and units.
a) How long after the release of the first stone does the second stone hit the water?
b) What was the initial speed of the second stone?
c) What is the speed of the first stone as it hits the water?
d) What is the speed of the second stone as it hits the water?
a) The time after the release of the first stone that the second stone hits the water is 2.0 s.
b) 15.7 m/s is the initial speed of the second stone.
c) The speed of the first stone as it hits the water is 15.7 m/s.
d) The speed of the second stone as it hits the water is 28.2 m/s.
What is velocity?Velocity is a vector quantity that measures both the speed and direction of an object's motion. It is equal to the rate of change of an object's position with respect to time. Velocity is usually represented by the symbol v and is measured in meters per second (m/s).
a) The time between first and second stone's release is 1.0 s. Since the time of release of first stone and the time of splash of both stones are same, the time between the release of second stone and the splash of both stones is 1.0 s.
Thus, the time after the release of the first stone that the second stone hits the water is 2.0 s.
b) The initial speed of the second stone can be calculated using the equation of motion,
v² = u² + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (9.8 m/s²), and s is the displacement.
Substituting the values,
v² = (1.7)² + 2(9.8) * 59
v = 15.7 m/s
c) The speed of the first stone as it hits the water can be calculated using the equation of motion,
v² = u² + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (9.8 m/s²), and s is the displacement.
Substituting the values,
v² = (1.7)² + 2(9.8) * 59
v = 15.7 m/s
d) The speed of the second stone as it hits the water can be calculated using the equation of motion,
v² = u² + 2as
where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (9.8 m/s²), and s is the displacement.
Substituting the values,
v² = (15.7)² + 2(9.8) * 59
v = 28.2 m/s
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franchising why is it the best option for you as an entrepreneur
Answer:
ttrockstars
Explanation:
it's math you to be an expert at math thank you
A 27 g block of ice is cooled to −65 ◦C. It is added to 525 g of water in an 80 g copper calorimeter at a temperature of 25◦C. Find the final temperature. The specific
heat of copper is 387 J/kg ◦C and of ice is 2090 J/kg ◦C . The latent heat of fusion of
water is 3.33 × 105 J/kg and its specific heat is 4186 J/kg ◦C . Answer in units of ◦C.
The final temperature after adding the ice to the water and calorimeter will be approximately 8.37 ◦C.
What is Temperature?
Temperature is a measure of the average kinetic energy of the particles in a substance or system. It is a scalar quantity that indicates how hot or cold an object or medium is. Temperature is commonly measured using various scales, such as Celsius (°C), Fahrenheit (°F), and Kelvin (K), which represent different reference points and units of measurement.
Since energy is conserved, we can set Q_ice equal to Q_water+calorimeter:
m_ice * c_ice * ΔT_ice = (m_water + m_calorimeter) * c_water+calorimeter * ΔT_water+calorimeter
27 g * 2090 J/kg ◦C * (T_f + 65) = (525 g + 80 g) * (4186 J/kg ◦C + 387 J/kg ◦C) * (T_f - 25)
Simplifying and solving for T_f:
27 * 2090 * (T_f + 65) = 605 * (T_f - 25)
56130 T_f + 361350 = 605 T_f - 15125
56130 T_f - 605 T_f = -15125 - 361350
-44,970 T_f = -376475
T_f = (-376475) / (-44,970)
T_f ≈ 8.37 ◦C
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A researcher investigated whether job applicants with popular (i.e. common) names are viewed more favorably than equally qualified applicants with less popular (i.e. uncommon) names. Participants in one group read resumes of job applicants with popular (i.e. common) names, while participants in the other group read the same resumes of the same job applicants but with unpopular (i.e. uncommon) names. The results showed that the differences in the evaluations of the applicants by the two groups were not significant at the .001 level
The researcher did not find strong evidence to support the idea that job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.
What factors plan an important role in the hiring process for a job?It sounds like the researcher conducted an experiment to investigate whether job applicants with popular names are viewed more favorably than equally qualified applicants with less popular names.
Based on the information provided, the researcher found that the differences in the evaluations of the applicants by the two groups were not significant at the .001 level.
The factors that play an important role in the hiring process for a job:
(1) Qualifications and experience: Employers typically look for candidates who possess the necessary qualifications and experience for the job. This includes education, training, certifications, and work experience.
(2) Skills and abilities: Employers also consider a candidate's skills and abilities related to the job. These may include technical, interpersonal, communication, and problem-solving skills.
(3) Personal characteristics: Personal characteristics, such as motivation, work ethic, and adaptability, can also play a role in the hiring process. Employers may look for candidates who demonstrate a positive attitude, a willingness to learn, and the ability to work well with others.
(4) Fit with company culture: Companies may also consider whether a candidate fits with their company culture, values, and mission. This can include factors such as teamwork, creativity, and innovation.
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explain HOW heat conduction works if you pour a hot cup of hot chocolate into a cold cup. What happens to the cup and HOW does it happen?
With time, the hot chocolate's thermal energy will permeate into the atmosphere, causing the cup to chill.
How does the heat energy from a cup of hot chocolate get to you?Conduction, which transfers heat through direct touch, transports heat from the hot chocolate to the mug. As the molecules of the hot chocolate clash with those of the mug, energy is transferred to both of them as well as to the surrounding air.
How is the spoon made heated by the heat from a cup of hot chocolate?Conduction into the metal spoon will speed up the transfer of heat from the cocoa. The heat will be dispersed throughout the spoon's body because it is a thermal conductor.
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How long does it take for radiation from a cesuim-133 atom to complete 1.5 million cycles
A cesium-133 atom's radiation goes through 1.5 million cycles in around 0.1633 microseconds (or 163.3 nanoseconds).
What frequency does one kind of radiation that cesium-133 emits have?9,192,631,770 hertz (cycles per second) is the frequency of the microwave spectral line that the isotope cesium-133 emits. The basic unit of time is provided by this. Cesium clocks have an accuracy and stability of 1 second in 1.4 million years.
The radiation emitted by cesium-133 has a frequency of 9,192,631,770 cycles per second, or 9.192631770 109 Hz.
The following formula may be used to determine how long 1.5 million radiation cycles take to complete:
Time is equal to the frequency of cycles.
Plugging in the numbers, we get:
time = 1.5 million / 9.192631770 × 10^9 Hz
time = 1.632995101 × 10^-7 seconds
So it takes approximately 0.1633 microseconds (or 163.3 nanoseconds) for radiation from a cesium-133 atom to complete 1.5 million cycles.
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Which are different forms of an element that have different numbers of neutrons?
ions
isotopes
compounds
molecules
.
.
Answer:A
Explanation:
Isotopes are members of a family of an element that all have the same number of protons but different numbers of neutrons. The number of protons in a nucleus determines the element's atomic number on the Periodic Table.
Did the same thing happen to every type of light when it hit glass? Gamma Ray, x-ray, UV, visible, IR, microwave, radio?
Answer:
When light interacts with glass or any other transparent medium, its behavior depends on the wavelength or frequency of the light. Different types of light, such as gamma rays, X-rays, ultraviolet (UV) rays, visible light, infrared (IR) rays, microwaves, and radio waves, have different wavelengths and frequencies, and thus interact with glass in different ways.
In general, glass is transparent to visible light, allowing it to pass through without significant absorption or scattering. This is why we can see through glass windows or lenses. However, for other types of light, such as gamma rays, X-rays, and UV rays, glass can absorb or scatter them to varying degrees depending on the energy or frequency of the light and the composition of the glass. For example, lead glass or certain types of high-density glass can effectively block or absorb high-energy radiation such as gamma rays and X-rays.
Infrared (IR) rays, which have longer wavelengths than visible light, are also generally transmitted through glass, although some types of glass may absorb or scatter them at specific wavelengths. Microwave and radio waves, which have much longer wavelengths, are also generally transmitted through glass without significant absorption or scattering.
It's important to note that the interaction of light with glass can also depend on other factors, such as the thickness and quality of the glass, as well as the angle at which the light strikes the glass surface. In some cases, glass may exhibit special properties, such as polarization or refraction, which can affect the behavior of light passing through it. Overall, the interaction of different types of light with glass can vary, and it depends on the specific characteristics of the light and the glass material involved.
Explanation: