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Answer:

A 70 kg box is slid along the floor by a 400 n force. The coefficient of friction between the box and the floor is 0. 50 when the box is sliding

Answer:

I'm not a genius ok?

Explanation:

1. Radar communication, Analysis of the molecular and atomic structure, telephone communication

2. c

Answer:

a

Explanation:

if forces on an object are balanced a moving object continues to move at the same speed and in the same direction

Answer:

i think its going to be 150 because its half of 300

Explanation:

Answer:

If and only if the object has 0 speed. Any other case is a no.

Explanation:

In increasing math complexity:

If the graph of a distance/time is a straight line with a non-zero slope it means that the velocity-time graph is an horizontal line where every point has the same second coordinate, equal to the value of the slope of the first line (ie, if the first line has equation [tex]y=2t[/tex] the second line will have equation [tex]y=2[/tex] - I'm using y to denote either the distance or the speed, read it as "the non-time variable")

If the graph of a speed/time is a straight line, the graph of the distance/time is the area of the region of space beneath the straight line in the first graph, ie a triangle. And as you increase the sides of that triangle keeping the angles fixed, you get a parabolic curve.

Bonus case: if [tex]v(t)= 0; d(t) = 0[/tex], they are both straight lines, they both pass through the origin, and they are the exact same line.

With calculus (or: math becomes fun after you add the alphabet to it)

You are asking if the answer of the IVP

[tex]\left \{ {{x'=x} \atop {x(0)=0}} \right.[/tex]

is a linear function. The answer is: besides the obvious [tex]x(t)'=x(t)=0 \ \forall t[/tex] there are no other solutions, linear or otherwise.

Answer:

25A°C=2L

35A°C=? More

=35/25×2L

=7/5×2L

=14L/5

=2.8L

Answer:

2000 and 156300

jade it jawaban nya

Answer:   F = (200 kg + 70 kg) * 4 m/s² = 270 kg* 4m/s² = 1080 N

Answer:

F = 1080 N

Explanation:

A ball swung around on a rope of a radius of 0.25 meters in a time of 0.40 seconds, then the velocity of the ball will be equal to 3.925 m/s.

Velocity is the rate of change of a traveling object's direction, as measured by a certain unit of time and as seen from a specific vantage point. Speed is a basic concept in kinematics, the branch of special relativity that studies how bodies move.

A scientific vector quantity called velocity must have both a magnitude and direction to be described.

As per the data provided in the question,

Radius, r = 0.25

Time, t = 0.40 seconds

Circumference of the circle, d = 2πr

d = 2π(0.25)

d = 1.570 m

Velocity, v = d / t

v = 1.570 / 0.40

v = 3.925 m/s.

Therefore, the velocity of the ball will be 3.925 m/s.

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Answer:

France

Explanation:

France is the undisputed champion in the world of skiing.

Answer:

[tex]\displaystyle v = 12.4134 \ m/s[/tex]

General Formulas and Concepts:

Energy

Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2}mv^2[/tex]

Explanation:

Step 1: Define

Identify variables.

KE = 7250 J

m= 94.1 kg

Step 2: Solve for v

Topic: AP Physics 1 - Algebra Based

Unit: Energy

Hi there!

We can begin by summing forces acting on the load:

∑F = T - Mg (where g ≈10 m/s²)

ma = T - Mg

We can plug in the given values to solve:

ma = 2000 - 175(10)

175a = 250  

a = 250/175 = 1.43 m/s² UPWARDS

Answer:

a = 1.63 m/s^2

Explanation:

m = 176kg

Ft = 2000N

  2000 = 175 (9.8) +175(a)

    2000   = 1715 +175a

    -1715       -1715

285 = 175a

175     175

a = 1.63m/s^2  

Answer:

a) Answer: 0.16331 m/s

b) Answer: 8522.66 joules

Explanation:

The final speed is  0.1633 m/s.

When the freight car receives this scrap metal, 7915.72 Joule kinetic energy is lost.

A body has momentum while it is moving, according to our understanding. It is said that a body's momentum is equal to the sum of its mass and speed. A body's direction is important when discussing momentum. Its direction belongs to the body's direction of motion.

(a) Given parameter:

Mass of the railroad car, M = 2900 Kg.

Mass of the scrap metal, m= 11750 Kg.

Initial speed of the car, u = 0.0825 m/s.

Initial speed of the scrap metal = 0 m/s.

Final speed of the system, v = ?

Then, initial momentum of the  system = initial momentum of the car +  initial momentum of the scrap metal .

= (29000×0.825 + 117500×0) kg.m/s.

= 23925 kg.m/s.

Final momentum of the system = total mass of the system× final speed

= (29000 + 117500)× v kg.m/s

= 146500v kg.m/s.

Hence, from principle of conservation of momentum,

initial momentum of the  system = Final momentum of the system

⇒ 23925 = 146500v

⇒ v = 0.1633 m/s.

The final speed of the  loaded freight car is 0.1633 m/s.

(b) Lost in kinetic energy = initial kinetic energy of the car - final kinetic energy of the loaded car.

= 1/2*29000*0.825² -1/2*(29000 + 117500)* 0.1633² Joule.

= 7915.72 Joule.

Hence, 7915.72 Joule kinetic energy is lost in this process.

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Answer:

66,000J

Explanation:

Mechanical energy = Gravitational energy + Kinetic Energy

ME = 6,000 + 60,000 = 66000 J

Hi there!

We can begin by doing a summation of forces. Let the acceleration be positive in the direction of the DOWNWARD movement of the hanging block.

(A)

The system will flow in the direction of the hanging block's movement downwards.

(B)

Summation of forces of block on incline:

∑F = -M₁gsinФ + T

Summation of forces of hanging block:

∑F = M₂g - T

Sum both summations:

∑F =  -M₁gsinФ + T + M₂g - T

∑F = M₂g -M₁gsinФ

According to Newton's Second Law:

∑F = ma

Thus:

(M₁ + M₂)a = M₂g -M₁gsinФ

[tex]a = \frac{M_2g -M_1gsin\theta}{M_1 + M_2}[/tex]

Plug in the values:

[tex]a = \frac{(5 * 9.8) -(8 * 9.8 * sin30)}{8 + 5} = \large\boxed{0.754 m/s^2}[/tex]

(C)

Calculate the rope's tension using one of the above equations:

∑F₂ = M₂g - T

Rearrange for T:

T = M₂g - m₂a

Plug in values:

T = 5(9.8) - 5(0.754) = 45.23 N

Answer:

Having more plants performing photosynthesis could help reduce the amount of carbon dioxide in the atmosphere.

Explanation:

sample answer

The plants can be used in the future to help counteract some human

emissions they absorb carbon dioxide from the air and release oxygen.

It is a process carried out by photosynthetic autotrophic organisms, such as plants, algae and some prokaryotes. These organisms capture sunlight, convert it into chemical energy, which will be used to produce organic compounds, based on water and carbon dioxide.

Trees, like other plants, in the process called photosynthesis, absorb carbon dioxide from the air and release oxygen. They also make the air wetter and cooler. In this way, plants contribute to the good quality of the air we breathe.

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Answer:Thus for n=1 number of electrons is 2 and for n=2 the number of electrons is 8. Hence the electronic configuration of the element X is 2,8,6 and its atomic number is 16. In the Modern Periodic Table, the element Sulphur has atomic number 16. So, the solution is that the element X is Sulphur and it is non metallic.

Answer:

Explanation:

Answer: Thus for n=1 number of electrons is 2 and for n=2 the number of electrons is 8. Hence the electronic configuration of the element X is 2,8,6 and its atomic number is 16. In the Modern Periodic Table, the element Sulphur has atomic number 16. So, the solution is that the element X is Sulphur and it is non metallic.

Answer:

One of Canada's best-known poems, “In Flanders Fields” was written on May 2, 1915, when Canadian serviceman John McCrae was stationed at an army hospital in Flanders, Belgium, during World War I.

Explanation:

Hi there!

[tex]\large\boxed{F_{A} = -5000N}}[/tex]

For an object to be moving at constant velocity:

∑F = 0 (The sum of the forces acting on the object MUST be 0 N)

We can do a summation of forces for this helicopter in the HORIZONTAL direction:

∑Fₓ = Ft (Force of Thrust) + Fa (Force of air resistance) = 0

Thus, if we substitute in the given value for Ft:

Ft = -Fa

5000N = -Fa

Fa = -5000N

Answer:

Energy = Power × Time

[tex]{ \tt{E = ( \frac{60}{1000} ) \times ( \frac{5}{60}) }} \\ \\ { \tt{E = 0.005 \: kwh {}^{ } }}[/tex]

Formulas change from F to degree C : C = (F – 32) / 1.8

so we have (176-32) /1.8= 80 oC

Formulas change from F to degree K : K = 5 / 9 x (F – 32) + 273.15

so we have 5/9 x (176-32) + 273.15 = 353 oK

ok done. Thank to me :>

We are able to walk toward because b) we push on the ground.

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[tex] 😘 \: 😉 \: 😈 \; 😫 \: 😤 \: 😡 \: 😘[/tex]

At the top of the building, the speed of the ball is zero.

The speed increases steadily as the ball falls.

When it hits the street, its speed is 39.6 m/s.

The correct answer is the 3rd answer, gravity would increase its pull on the small object

hope this helps! :)

Answer:

3.0 m

Explanation:

The height of the wave is just 1.5 m + 1.5 m which equals 3.0 m

Answer:

Nuclear Fusion

Explanation:

At large distances, two nuclei repel one another because of the repulsive electrostatic force between their positively charged protons. If two nuclei can be brought close enough together, however, the electrostatic repulsion can be overcome by the attractive nuclear force, which is stronger at close distances.

Hi there!

For an object moving in a circle:

Centripetal force = ∑F = mv²/r

Thus:

56 = mv²/r

Rearrange to solve for velocity:

√(56r/m) = v

√(56 × 21)/650 = 1.345 m/s

Answer:

Explanation:

have a good day

Depends upon how soon you want to stop. You know the mass of the car, you know the initial velocity of 8.9 m/s. You know the final velocity which is zero. You can now calculate the deceleration of the car if you know how soon you want to stop.

Let's say you want to stop in one second.

a = (vf - vi) / t = - 8.9 m/s^2 (negative sign indicates deceleration).

F = ma = 800 x 8.9 = 7120 Newtons (kg*m/s^2)

The kinetic energy of the toy before hitting the ground is 294.3 J

From the question given above, the following data were obtained:

Mass (m) = 3 Kg

Height (h) = 10 m

Acceleration due to gravity (g) = 9.81 m/s²

Before the toy will hit the ground, the potential and kinetic energy of the toy will be the same.

KE = PE = mgh

KE = 3 × 9.81 × 10

Therefore, the kinetic energy of the toy is 294.3 J

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