Hi I’m in fourth grade and I need help about angles can you please help me

the probability that a randomly selected passenger car gets more than 35 mpg is approximately 0.3665.

the probability that the average mpg of four randomly selected passenger cars is more than 35 mpg is approximately 0.087

the probability that all of the passenger cars get more than 35 mpg is approximately 0.015.

We need to find [tex]P(X > 35),[/tex] where X is the mpg rating of a randomly selected passenger car.

The standard normal distribution and Table 1, we have:

[tex]z = (35 - 33.8) / 3.5 = 0.34[/tex]

[tex]P(X > 35) = P(Z > 0.34) = 0.3665[/tex]

[tex]P(\bar X > 35)[/tex], were [tex]\bar X[/tex] is the sample mean mpg rating of four randomly selected passenger cars.

The population standard deviation, we use the t-distribution with [tex]n-1[/tex] degrees of freedom (were [tex]n = 4[/tex]) and Table 1. We have:

[tex]t = (35 - 33.8) / (3.5 / \sqrt(4)) = 1.83[/tex]

Using Table 1 with 3 degrees of freedom ([tex]n-1 = 4-1[/tex]), we find:

[tex]P(T > 1.83) = 0.087[/tex]

We need to find [tex]P(X1 > 35[/tex] and [tex]X2 > 35[/tex] and [tex]X3 > 35[/tex] and [tex]X4 > 35[/tex]), where X1, X2, X3, and X4 are the mpg ratings of four randomly selected passenger cars.

Since the mpg ratings of the four cars are independent and identically distributed, we have:

[tex]P(X1 > 35[/tex]and[tex]X2 > 35[/tex] and [tex]X3 > 35[/tex] and [tex]X4 > 35[/tex]) =[tex]P(X > 35)^4[/tex]

From part (a), we know that[tex]P(X > 35) = 0.3665.[/tex]

[tex]P(X1 > 35[/tex]and [tex]X2 > 35[/tex] and[tex]X3 > 35[/tex] and [tex]X4 > 35) = 0.3665^4 \approx 0.015[/tex]

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Answer:

Step-by-step explanation:

25

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a

b

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10

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1

Answer: To minimize the time taken by the woman to reach point C, she should minimize the total distance traveled, which is the sum of the distance she walks and the distance she rows.

Let's call point B the point where the woman switches from walking to rowing. We can find the location of point B by drawing a straight line from A to the center of the lake, and then continuing that line on the other side of the lake to point C. Point B is the point where this line intersects the circle of the lake.

Since the radius of the lake is 4, the distance from A to the center of the lake is also 4. Therefore, the distance from A to B is also 4. The distance from B to C is also 4, since C is diametrically opposite to A.

Let's call the distance that the woman rows from B to C d. Then the distance that she walks from A to B is 4 - d.

The time taken to walk a distance of (4 - d) miles is:

t1 = (4 - d) / 10

The time taken to row a distance of d miles is:

t2 = d / 5

The total time taken is:

T = t1 + t2 = (4 - d) / 10 + d / 5

Simplifying, we get:

T = (8 + d) / 20

To minimize T, we need to find the value of d that minimizes (8 + d) / 20. We can do this by taking the derivative of (8 + d) / 20 with respect to d and setting it to 0:

d(T) / d(d) = 1/20

Setting this to 0, we get:

1/20 = 0

This is obviously not true, so there is no minimum value of T. However, we can see that as d gets larger, T gets larger, and as d gets smaller, T gets smaller. Therefore, the minimum value of T occurs at one of the endpoints of the interval [0, 4]. Since d cannot be negative, the only endpoint we need to consider is d = 4.

When d = 4, the woman rows the entire distance from B to C, and does not need to walk at all. Therefore, the total time taken is:

T = (8 + 4) / 20 = 0.6 hours

Therefore, the woman should walk to point B, and then row the rest of the way to point C, to arrive in the shortest possible time.

Step-by-step explanation:

The probability that 3 of the 9 randomly selected subjects entered a profession closely related to their college major is approximately 0.1665, or 16.65%.

To find the probability that 3 out of 9 randomly selected subjects entered a profession closely related to their college major, we can use the binomial probability formula:
[tex]P(X = k) = (n choose k) * p^k * (1 - p)^{n - k}[/tex]
where:
- P(X = k) is the probability of k successes (in this case, 3 people entering a profession closely related to their major)
- n is the number of trials (9 subjects)
- k is the number of successes (3 people)
- p is the probability of success (53% or 0.53)
- (n choose k) is the number of combinations of n items taken k at a time, which can be calculated as C(n, k) = n! / (k! * (n - k)!)
Plugging in the values, we get:
[tex]P(X = 3) = C(9, 3) * (0.53)^3 * (1 - 0.53)^{9 - 3}[/tex]
First, calculate the combinations (n choose k):
C(9, 3) = 9! / (3! * (9 - 3)!)
C(9, 3) = 9! / (3! * 6!)
C(9, 3) = 362880 / (6 * 720)
C(9, 3) = 84
Now, calculate the probabilities:
[tex]P(X = 3) = 84 * (0.53)^3 * (0.47)^6[/tex]
P(X = 3) = 84 * 0.148877 * 0.013325
P(X = 3) ≈ 0.1665.

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Thus, the density of the silver picture frame is found to be 10 grams / cubic centimeters.

We use the word "density" to indicate how much space (or "volume") an object or substance occupies in relation to the total quantity of matter contained therein (its mass).

Density can also be defined as the quantity of mass per unit of volume. A dense object is one that is both hefty and small. An object has a low density if it is light and occupies a large amount of space.

Density = mass / volume

given data:

mass of the silver picture frame = 100 grams

Volume = 10 cubic centimetres

Density = mass / volume

Density = 100 grams/ 10 cubic centimeters

Density = 10 grams / cubic centimeters

Thus, the density of the silver picture frame is found to be 10 grams / cubic centimeters.

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Answer:

The answer is B ([tex]x=\frac{6}{5}[/tex])

Step-by-step explanation:

We start with creating labels for the shapes that represent what they value -at first I tried multiplying the 5x by 4 but there wasn't an answer for that.

[tex]5x+4=10[/tex]

First we just simplify,

[tex]5x (-4)=10(-4)[/tex]

[tex]5x=6[/tex]

then divide,

[tex]\frac{5x}{5} =\frac{6}{5}[/tex]

and we end up with:

[tex]x=\frac{6}{5}[/tex]

or

B

The assumption that AXB is a bounded angle is false, as a result, if AXB is a circumscribed angle of circle C, then AXB and ACB are supplementary.

To complete the proof of the Circumscribed Angle Theorem, use the fact that an inscribed angle of a circle is equal to half of the central angle that intercepts the same arc.

Since angle ∠AXB is circumscribed by the circle, point X lies on the circumference of the circle. Therefore, angles ∠CXA and ∠CXB are inscribed angles that intercept the same arc AB.

By the Inscribed Angle Theorem:

∠CXA = ½∠CAB

∠CXB = ½∠CAB

Adding these two equations:

∠CXA + ∠CXB = ½∠CAB + ½∠CAB

∠CXA + ∠CXB = ∠CAB

Now, observe that angles ∠CAB and ∠ACB form a linear pair, since they are adjacent angles that together make a straight line. Therefore, they are supplementary, which means:

∠CAB + ∠ACB = 180°

Substituting ∠CAB with ∠CXA + ∠CXB:

∠CXA + ∠CXB + ∠ACB = 180°

Finally, ∠AXB and ∠CXB form a linear pair, since they are adjacent angles that together make a straight line. Therefore, they are supplementary, which means:

∠AXB + ∠CXB = 180°

Substituting ∠CXB with ∠CAB - ∠CXA:

∠AXB + ∠CAB - ∠CXA = 180°

Adding ∠CXA to both sides:

∠AXB + ∠CAB = ∠ACB + 180°

Substituting ∠AXB + ∠CAB with 180° (since they are adjacent angles that together make a straight line):

180° = ∠ACB + 180°

Simplifying:

∠ACB = 0°

This is a contradiction, since we know that ∠ACB is a non-zero angle. Therefore, our assumption that ∠AXB is a circumscribed angle must be false. Hence, we have proved that if ∠AXB is a circumscribed angle of circle C, then ∠AXB and ∠ACB are supplementary.

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(a) This is an observational study.

The reason is that the researchers did not manipulate any variables or conditions; they simply observed and collected data on the two groups of babies (VLBW and normal birth weight) as they grew up.
(b) The p-value (0.0013) is less than the significance level (typically 0.05), we reject the null hypothesis.  

There is sufficient evidence to suggest that the graduation rate among the VLBW group is significantly lower than the normal-birth-weight controls.

To determine if the graduation rate among the VLBW group is significantly lower than the normal-birth-weight controls, we can perform a hypothesis test using the proportion of high school graduates in each group.
State the null and alternative hypotheses.
Null hypothesis (H0):

There is no significant difference in graduation rates between the VLBW group and the control group ([tex]p_VLBW = p_control).[/tex]
Alternative hypothesis (Ha):

The graduation rate among the VLBW group is significantly lower than the control group [tex](p_VLBW < p_control).[/tex].

Calculate the sample proportions and the pooled proportion.
[tex]p_VLBW[/tex] = 179/242 = 0.7397
[tex]p_control = 193/233 = 0.8283.[/tex]
[tex]p_pooled = (179 + 193) / (242 + 233) = 0.7842[/tex]
Calculate the test statistic.
[tex]z = (p_VLBW - p_control) / sqrt(p_pooled * (1 - p_pooled) * (1/242 + 1/233)) = -3.0074[/tex]
Determine the p-value.
Using a z-table or calculator, the p-value for z = -3.0074 is approximately 0.0013.

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The rule for the nth term of the sequence is: an = [tex]3 * 13.0^(n-1)[/tex]

An arithmetic progression is a list of numbers in which each term is obtained by adding a fixed number to the preceding term except the first term.

The rule for the nth term of a geometric sequence is given by:

an = a1 * rn-1

where:

an = the nth term of the sequence

a1 = the first term of the sequence

r = the common ratio of the sequence

n = the position of the term in the sequence

Using the given values, we can write the rule for the nth term of the sequence as:

an =[tex]a * r^(n-1)[/tex]

where:

a = 3 (given)

r = 13.0 (given)

Therefore, the rule for the nth term of the sequence is:

an =[tex]3 * 13.0^(n-1)[/tex]

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Answer:

[tex]\frac{1}{50}[/tex]

Step-by-step explanation:

[tex]\frac{54.5-55.5}{225-275}[/tex] = [tex]\frac{-1}{-50}[/tex] = [tex]\frac{1}{50}[/tex]

We can use the equation y = 38.8x to find how many miles Camila can drive her car for each gallon of gas, and then use that information to find how many gallons of gas she would need to drive the same distance as Julieta.

Julieta drives 333 miles using 10 gallons of gas, so her car can travel 333/10 = 33.3 miles per gallon.

To find how many miles Camila's car can travel per gallon, we can use the equation y = 38.8x, where x is the number of gallons of gas. If Camila uses 1 gallon of gas, then y = 38.8(1) = 38.8 miles. Therefore, Camila's car can travel 38.8 miles per gallon.

To travel 333 miles like Julieta, Camila would need to use:

333 miles / 38.8 miles per gallon = 8.58 gallons of gas

Therefore, Camila would need to use 8.58 gallons of gas to travel the same distance as Julieta.

the measure of the smallest angle of ΔDEF is approximately 41.41°.

How to solve the question?

In ΔDEF, DM is a median and M is on EF. Additionally, DM = EF, and DL is an angle bisector of ∠EDF, L is on EF, and m∠DLF = 64°. We need to find the measure of the smallest angle of ΔDEF.

Since DM is a median, it divides EF into two equal parts, EM and MF. Thus, EM = MF = DM/2 = EF/2.

Let x be the measure of ∠EDF. Then, we know that ∠EDM = ∠FDM = 90° because DM is a median.

Using the angle bisector theorem, we know that DL/EL = DF/EF. Since DL is an angle bisector, we also know that ∠DLE = ∠ELF = x/2. Therefore, we have:

DL/EL = DF/EF

DL/(EF/2) = DF/EF

DL = DF/2

Now, we can use the Law of Cosines in ΔDEF to find DF in terms of x:

DF² = DE² + EF² - 2(DE)(EF)cos(x)

DF² = DM² + MF² - 2(DM)(MF)cos(x)

DF² = (EF)²/4 + (EF)²/4 - (EF)²cos(x)

DF² = (EF)²/2 - (EF)²cos(x)

Since DL = DF/2, we have:

DL² = (EF)²/8 - (EF)²cos(x)/4

Using the angle bisector theorem again, we know that EL/FL = DE/DF. Since DL = DF/2, we also know that FL = EF - DL = EF/2. Therefore, we have:

EL/EF - EL/2 = DE/DF

EL/EF - EL/(2DL) = DE/DF

EL/EF - EL/(EF/4) = DE/DF

EL = EF(DE/DF)/3

Now, we can use the Law of Cosines again in ΔDEL to find DE in terms of x:

DE² = DL²+ EL² - 2(DL)(EL)cos(x/2)

DE² = (EF)²/8 - (EF)^2cos(x)/4 + [EF(DE/DF)/3]² - 2(DL)(EF(DE/DF)/3)cos(x/2)

DE² = (EF)²/8 - (EF)^2cos(x)/4 + (EF)²(DE/DF)^2/9 - (EF)(DE/DF)(EF/6)cos(x/2)

Since DM = EF, we have DE = DM - EM = EF/2 - EF/4 = EF/4. Thus, we can substitute this into the equation above and simplify:

(EF/4)²= (EF)²/8 - (EF)^2cos(x)/4 + (EF)^2(DE/DF)²/9 - (EF)(DE/DF)(EF/6)cos(x/2)

(EF)²/16 = (EF)²/8 - (EF)²cos(x)/4 + (EF)²(DE/DF)²/9 - (EF)(DE/DF)(EF/6)cos(x/2)

0 = (EF)²/72 - (EF)²cos(x)/4 + (EF)²(DE/DF)²/9 - (EF)(DE/DF)(EF/6)cos(x/2)

Now, we can substitute DL = DF/2 = (EF/4)/2 = EF/8 and EL = EF(DE/DF)/3 = EF(DE)/(3EF/4) = 4DE/3 into the equation above and simplify:

0 = (EF)²/72 - (EF)²cos(x)/4 + (EF)²(DE/DF)²/9 - (EF)(DE/DF)(EF/6)cos(x/2)

0 = (EF)²/72 - (EF)²cos(x)/4 + (EF)^2(DE/DF)²/9 - (EF/8)(4DE/3)(EF/6)cos(x/2)

0 = (EF)²/72 - (EF)²cos(x)/4 + (EF)²(DE/DF)²/9 - (EF²/72)cos(x/2)

0 = (EF)²/72 - (EF)²cos(x)/4 + (EF)²(DE/DF)²/9 - (EF)²cos(x/2)/18

Simplifying this equation, we get:

cos(x)/4 - cos(x/2)/18 = (EF)²/72 - (EF)²(DE/DF)²/9

Now, we can substitute DE = EF/4 and DF = EF/2 into the equation above and simplify:

cos(x)/4 - cos(x/2)/18 = (EF)²/72 - (EF)²/144

cos(x)/4 - cos(x/2)/18 = (EF)²/144

We know that cos(x) is negative because x is the measure of the smallest angle of ΔDEF, so we can take the absolute value of both sides of the equation:

|cos(x)/4 - cos(x/2)/18| = (EF)²/144

Since 0° < x < 180°, we know that cos(x/2) > cos(x), so we can simplify further:

cos(x/2)/18 - cos(x)/4 = (EF)²/144

Now, we can substitute the given value of ∠DLF = 64° into the equation above and solve for EF:

cos(32°)/18 - cos(128°)/4 = (EF)^2/144

0.0289 - (-0.2113) = (EF)²/144

0.2402 = (EF)²/144

EF = √(0.2402*144)

EF ≈ 4.8044

Finally, we can use the Law of Cosines in ΔDEF to find x:

cos(x) = (DE² + EF² - DF²)/(2(DE)(EF))

cos(x) = (EF²/16 + EF² - EF²/4)/(2(EF/4)(EF))

cos(x) = 3/4

x = arccos(3/4)

x ≈ 41.41°

Therefore, the measure of the smallest angle of ΔDEF is approximately 41.41°.

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Using the law of sines, the value of the indicated side x, is calculated to one decimal place as: 125.3.

The Law of Sines is a trigonometric formula used to relate the side lengths and angles of any triangle. It states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is equal for all three sides of the triangle. Mathematically, this can be represented as:

sin A/a = sin B/b = sin C/c

Thus, we have:

C = 180 - 102 - 28 = 50°

a = 160

A = 102°

c = x = ?

Applying the law of sines, we have:

sin 102/160 = sin 50/x

Cross multiply:

x = sin 50 * 160 / sin 102

x ≈ 125.3

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The average arrival rate is 0.4167 customers per minute.

The average arrival rate (lambda) can be calculated using Little's Law, which states that the average number of

customers in a system (L) is equal to the average arrival rate (lambda) multiplied by the average time spent in the

system (W).

Since we know that the service times are exponentially distributed with an average of 2.4 minutes per customer, we

can use the formula for the mean of an exponential distribution, which is 1/lambda.

So, 2.4 = 1/lambda

Solving for lambda, we get lambda = 1/2.4 = 0.4167 customers per minute

Therefore, the average arrival rate is 0.4167 customers per minute.

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Answer:

The width is 4 inches

Step-by-step explanation:

Volume is the length x the width x height

84 = 7w3

84 = 21w  Divide both sides by 21

4 = w

Helping in the name of Jesus.

Answer: To calculate the amount of money you would need to invest in a period annuity that offers 4.5% APR compounded monthly for 20 years to receive an annual income of $42,000, you can use the following formula:

PV = A * [(1 - (1+r)^(-n)) / r]

where:

PV = present value (amount of money you need to invest)

A = annual income ($42,000 in this case)

r = interest rate per period (4.5% APR compounded monthly, or 0.045/12 = 0.00375 per month)

n = total number of periods (20 years x 12 months per year = 240 months)

Plugging in the numbers, we get:

PV = $42,000 * [(1 - (1+0.00375)^(-240)) / 0.00375]

PV = $553,229.03

Therefore, the answer is (A) $553,229.03.

Step-by-step explanation:

The total amount of the bill, including tax and gratuity, was $191.85.

What is the percentage?

A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%", although the abbreviations "pct.", "pct" and sometimes "pc" are also used. A percentage is a dimensionless number; it has no unit of measurement.

The first step is to calculate the amount of tax and the amount of gratuity:

Amount of tax = 6% of $158.56 = $9.51

Amount of gratuity = 15% of $158.56 = $23.78

Next, we add the tax and the gratuity to the original bill:

Total bill = $158.56 + $9.51 + $23.78 = $191.85

Therefore, the total amount of the bill, including tax and gratuity, was $191.85.

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The ratio of the weight to the mass and the value of x in the table is B) The ratio is 10/98, x = 110.

The quantity of matter in an object is measured by its mass, which is commonly expressed in kilogrammes or grammes. Since mass is a scalar quantity, the gravitational field has no effect on it. The force of gravity acting on an object is quantified by weight, which is commonly expressed in newtons or pounds. Weight is a vector quantity that is influenced by the strength of the gravitational field. While an object's mass is constant, its weight might vary depending on the gravitational field.

The ratio of weight to mass according to the given table is:

weight / mass = 196 / 20 = 98/10

The ratio is constant thus for x we have:

1078 / x = 98 / 10

Using cross multiplication we have:

x = 1078 (10) / 98 = 110

Hence, the ratio of the weight to the mass and the value of x in the table is B) The ratio is 10/98, x = 110.

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The complete question is:

The baseball field's fence, soil and sod requirements will be-: Length of fencing ≈ 1410.5 feet, Area of the sod ≈ 118017.13 ft², Area of of the field covered with dirt ≈ 7,049.6 ft²

To find the area of a sector of a circle:

The amount of fencing, dirt, and sod can be found using the formula for finding the circumference of a circle and the area of a circle as follows;

Circle's Area can be given by, (A)= π × r²

Circle's Circumference can be given by, (C) = 2 × π × r

Where, 'r' denotes the radius of the circle

The area of a quarter of a circle is therefore= A ÷ 4

The perimeter of a quarter of a circle = C ÷ 4

Taking reference from the image,

Fencing; (1/4) × 2 × π × 380 + 2 × 15 + 2 × 380 + (1/4) × 2 × π × 15

Fencing = 190·π + 790 + 7.5·π = 197.5·π + 790 ≈ 1410.5

The fencing ≈ 1410.5 feet

Grass; π/4 × (380 - 6)² + 87² - π/4 × (87 + 30)² + 2 × 380 × 15 + π/4 × 15² - (3/4) × π × 10² - 25·π = 31528·π + 18969 ≈ 118017.13

The area covered by the sod is about 118017.13 square feet

Dirt; π/4 × 380² - π/4 × (380 - 6)² + π/4 × (87 + 30)²- 87² + π·100 = (18613·π - 30276)/4 ≈ 7049.6

The area occupied by the dirt is about 7049.6 square feet

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Complete Question:Find the amount of fencing, dirt, and sod needed to rebuild the baseball field?(refer to image attached for dimensions of field)

Approximately 9.63% of the energy consumed by the person would be derived from protein.

To calculate the percentage of energy derived from protein, we need to first convert the amount of protein consumed from grams to calories. Protein provides approximately 4 calories per gram. Therefore, 65 grams of protein would provide:

65 grams * 4 calories/gram = 260 calories

This gives us 260 calories from protein.

To find the percentage of energy derived from protein, we can divide the calories from protein by the total calories consumed and multiply by 100:

260 calories / 2700 calories * 100% ≈ 9.63%

Therefore, approximately 9.63% of the energy consumed by the person would be derived from protein.

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Yuto and Riko will meet 73.5 minutes after Yuto started riding, or 52.5 minutes after Riko started riding.

How to find distance when rate and time are given?

We can find the distance by following formula ,

Distance = rate × time

Let t be the time in minutes that Riko rides until she catches up with Yuto. At that time, Yuto will have also ridden for t minutes, plus the additional time it took for him to get to his starting point, which we don't know yet.

The distance Riko covers in t minutes is

distance = rate × time

distance = 0.35 miles/minute × t minutes

distance = 0.35t miles

At the time that Riko catches up with Yuto, Yuto will have ridden a total distance,

distance = rate × time + distance from starting point

distance = 0.25t + 5.25 miles

Since Riko catches up with Yuto at the same location, their distances will be equal. So we can set the two expressions for distance equal to each other,

0.35t = 0.25t + 5.25

Simplifying this equation,

0.1t = 5.25

t = 52.5 minutes

So, Riko will catch up with Yuto 52.5 minutes after she starts riding. To find out when they will meet, we can add 52.5 minutes to Yuto's starting time. Since Yuto's speed is 0.25 miles/minute, he covers 5.25 miles in

time = distance / rate

time = 5.25 miles / 0.25 miles/minute

time = 21 minutes

So Yuto started riding 21 minutes before Riko, which means they will meet,

meeting time = Riko's starting time + time to catch up

meeting time = Yuto's starting time + 52.5 minutes

meeting time = 21 minutes + 52.5 minutes

meeting time = 73.5 minutes

Therefore, Yuto and Riko will meet 73.5 minutes after Yuto started riding, or 52.5 minutes after Riko started riding.

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Correct question is "Yuto and Riko went for a bike ride on the same path. When Riko left their house, Yuto was 5.25 miles along the path. If Yuto's average speed was 0.25 miles per minute and Riko's average speed was 0.35 miles per minute, then Riko will be behind Yuto when 0 . When will they meet?"

A) Their graphs will be different from the graph of the linear parent function. B) In real-world context, comparing functions can be useful in many scenarios, such as predicting sales or analyzing trends.

The y-intercept is the point where the graph of a function intersects with the y-axis. It is the point at which the value of x is 0.

Part A:

The linear parent function is represented by y = mx + b, where m is the slope and b is the y-intercept. The slope of the linear parent function is constant, while the y-intercept can vary.

In Jack's function, d = 0.05t, the slope is 0.05, which means that for every minute he runs, he travels 0.05 miles. The y-intercept is 0, which means that he starts at 0 miles.

In Jill's function, d = 0.04t + 0.5, the slope is 0.04, which means that for every minute she runs, she travels 0.04 miles. The y-intercept is 0.5, which means that she starts at 0.5 miles.

Both functions are linear, but they have different slopes and y-intercepts. Therefore, their graphs will be different from the graph of the linear parent function.

Part B:

Comparing Jack and Jill's functions to the linear parent function can give us insights into their race. The fact that their functions are linear means that they are running at a constant rate. However, the different slopes and y-intercepts mean that they are running at different rates and starting at different distances.

For example, we can see from their functions that Jack is running faster than Jill since his slope is larger. We can also see that Jill has a head start since her y-intercept is larger. By comparing their functions, we can make predictions about who will win the race or how far ahead one person will be at a certain time.

In real-world context, comparing functions can be useful in many scenarios, such as predicting sales or analyzing trends. By understanding the relationship between variables, we can make informed decisions and predictions.

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Emmy and Liam each played 4 games according to the given statement.

An equation is a claim that two expressions are equal, typically indicated by the equals symbol (=). In mathematics, equations are used to simulate real-world scenarios, solve problems, and depict relationships between variables.

Exponents, logarithms, and trigonometric functions can all be used in equations, in addition to basic operations like addition, subtraction, multiplication, and division.

Let us suppose the number of games played = x.

Thus, for Emmy we have:

E = 1 + 2x

For Liam the equation is:

L = 5 + 1x

Equating the two equations we have:

1 + 2x = 5 + 1x

x = 4

Hence, Emmy and Liam each played 4 games according to the given statement.

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There were 100 small pine cone patterns and 50 large pine cone patterns used in the camp.

When 50 students constructed one craft project each using two little pine cone patterns and one giant pine cone pattern, it is the question of how many small and large pine cone patterns were utilised overall:

We can begin by figuring out how many little pine cone patterns were utilized overall to solve this.

Since each student used 2 small pine cone patterns, we can multiply 2 by 50 (the number of students) to get:

2 x 50 = 100 small pine cone patterns used

Similarly, we can calculate the total number of large pine cone patterns used by multiplying the number of students (50) by 1 :

1 x 50 = 50 large pine cone patterns used

Therefore, in total, there were 100 small pine cone patterns and 50 large pine cone patterns used in the camp.

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--The complete Question is, If a camp has 50 students and each student made one craft project using 2 small pine cone patterns and 1 large pine cone pattern, how many small and large pine cone patterns were used in total? --

2(4/3) represents the shaded area in the diagram as two rectangles of equal size, each with a length of 4 units and a width of 2/3 units.

4 * 2/3 represents the shaded area in the diagram as a rectangle with a length of 4 units and a width of 2/3 units.

4 * 2 * 1/3 represents the shaded area in the diagram as a rectangle with a length of 4 units, a width of 2 units, and a smaller rectangle with a length of 1 unit and a width of 1/3 units.

What is the area of the rectangle?

To find the area of a rectangle, we multiply the length of the rectangle by the width of the rectangle.

a. The diagram shows 3/5 by dividing the whole rectangle into 5 equal parts horizontally and shading 3 of those parts. This means that the shaded portion represents 3 out of 5 equal parts.

b. The diagram shows 3 * 1/5 by shading one-fifth of the rectangle, and then repeating this process three times. This means that the shaded portion represents three times one-fifth of the whole.

c. The value of 3/5 is equivalent to 0.6 or 60%. This means that if we divide a whole into 5 equal parts, and take 3 of those parts, we have 60% of the whole.

a. The expression 2(4/3) represents the shaded parts of the diagram by first finding the area of one shaded rectangle, which is 4/3. Then, we multiply this area by 2 because there are two shaded rectangles in the diagram. Therefore, 2(4/3) gives us the total shaded area.

b. The expression 4 * 2/3 represents the shaded parts of the diagram by multiplying the width of the shaded rectangle (2 units) by its height (2/3 units), and then multiplying that by the number of shaded rectangles (4). Therefore, 4 * 2/3 gives us the total shaded area.

c. The expression 4 * 2 * 1/3 represents the shaded parts of the diagram by multiplying the length of the shaded rectangle (4 units) by its width (2 units) by its height (1/3 units), and then multiplying that by the number of shaded rectangles (4). Therefore, 4 * 2 * 1/3 gives us the total shaded area.

Hence, 2(4/3) represents the shaded area in the diagram as two rectangles of equal size, each with a length of 4 units and a width of 2/3 units.

4 * 2/3 represents the shaded area in the diagram as a rectangle with a length of 4 units and a width of 2/3 units.

4 * 2 * 1/3 represents the shaded area in the diagram as a rectangle with a length of 4 units, a width of 2 units, and a smaller rectangle with a length of 1 unit and a width of 1/3 units.

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Answer:200.734

Step-by-step explanation:

150(1+0.06)^t

t=number of years

150(1.060)^5

200.73383664

round

200.734

The balance of this account after 5 years is $200.73

Compound interest is the interest earned on the principal and the interest previously accumulated. It is given by

Amount = [tex]P(1+r/n)^n^t[/tex] where P = Principal, r = annual rate of interest, n = number of times interest is compounded per year, & t = time in years.

The given principal is $150 for 5 years & annual interest rate is 6%.

To find the amount compunded annualy at 6% for 5 years substituting the given values in the above formula i.e.

Amount =  [tex]P(1+r/n)^n^t[/tex]

Amount = $[tex]150(1+0.06)^5[/tex]

Amount = $200.73

Hence, the total amount accumulated for 5 years will be $200.73

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Answer:

19.5625

Step-by-step explanation:

Add up all of the x's (treating each place where an x is as if it's a number -- eg, there's twonumber 12's)

12+12+15+15+15+15+16+18+20+20+22+25+25+25+29 = 313

Divide by the number of x's

313 / 16 = 19.5625

Therefore, the expression [tex]-3(2x - 8) + 4x[/tex] is equivalent to option B, which is. [tex]-2x+24[/tex].

To simplify an expression, you typically want to combine like terms and perform any necessary operations in the correct order. Here are the steps you can follow:

Identify any like terms in the expression. Like terms are terms that have the same variables raised to the same powers.

Combine the coefficients of like terms. If there are no like terms, leave the expression as is.

Simplify any operations in the expression, such as multiplication, division, addition, or subtraction, according to the order of operations.

Check if the expression can be simplified further. If it can, repeat steps 1-3 until the expression cannot be simplified further.

Here's an example of how to simplify the expression. [tex]3x + 2x^2 - 5x - x^2[/tex]:

Identify like terms: 3x and -5x are like terms, as are. [tex]2x^2[/tex] and [tex]-x^2[/tex].

Combine the coefficients of like terms: [tex]3x - 5x = -2x[/tex], and [tex]2x^2 - x^2[/tex]= [tex]x^2[/tex]. So, the expression becomes:

[tex]-2x + x^2[/tex]

To simplify the expression [tex]-3(2x - 8) + 4x[/tex], we can start by using the distributive property to get:

[tex]-3(2x - 8) + 4x = -6x + 24 + 4x[/tex]

Next, we can combine the like terms −6x and 4x to get:

[tex]-6x + 4x + 24 = -2x + 24[/tex]

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Answer:

236 cm^2  and  8 cm

Step-by-step explanation:

width=w

240=6(5)(w)

w=8 cm

area=2[(6)(5)+(6)(8)+(5)(8)]

area=236 cm^2