How are velocity and speed related to each other?

Explanation:

Work=ForcexDisplacement

Force= Work/Displacement

= 1300/40

= 32.5 N

Answer:

Explanation:

The momentum of an object can be found by using the formula

From the question

mass = 950 kg

velocity = 10.0 m/s

We have

momentum = 950 × 10

We have the final answer as

Hope this helps you

Answer:

i think its 2.0

Explanation:

hopefully i am right ...

Answer:

yes

Explanation:

Answer: True

Im sure of it i took the test

Explanation:

Answer:

The correct option is;

D. The nervous system signals smooth muscles in the blood vessels to contract to increase blood pressure

Explanation:

The contraction or relaxation of the vascular smooth muscles lead to the blood vessel volume change and blood pressure change such that the blood is redirected to regions of the body that requires instantaneous increased oxygen intake. As such the nervous system signals the blood vessel's vascular smooth muscle to contract, through vasoconstriction so as to raise the blood pressure, when the blood pressure is low.

Answer:

Hope the answer helped you. if yes pls follow me

Explanation:

the fundamental answer is without regular supervision of definition of weights and measures,commerce exchange will be impossible and there would be no market whatsoever for anything.

Answer:

the fundamental answer is without regular supervision of definition of weights and measures,commerce exchange will be impossible and there would be no market whatsoever for anything.

Explanation:

"who"

Answer:

Distance, S = 108 meters.

Explanation:

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

[tex] F = ma[/tex] ............equation 1

Where;

Given the following data;

Since the boat is starting from rest, initial velocity, u = 0

Mass, m = 600kg

Time, t = 12s

Force, F = 900N

Substituting into equation 1, we have;

[tex] 900 = 600*a[/tex]

[tex]a = \frac{900}{600}[/tex]

Acceleration, a = 1.5 m/s²

T

To solve for distance, we would use the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Substituting the values into the equation, we have;

[tex] S = 0(12) + \frac {1}{2}*1.5* 12^{2}[/tex]

[tex] S = 0 + 0.75* 144[/tex]

Distance, S = 108m

Therefore, the distance covered by the boat is 108 meters.

19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J

20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m

21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg

22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J

23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON

24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m

25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J

20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m

21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg

22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J

23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON

24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m

25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J

20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m

21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg

22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J

23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON

24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m

25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m

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Answer:

5.3

Explanation:

Answer:

5.3 m/s east

Explanation:

Answer:

a = 10/s^2

Explanation:

Answer:

a=10 m/s *2 right

Explanation:

The net force (0.5 kg) divided by the mass (5 N) = 10

The force moved the object to the right.

So you Would put this in the equation a=___ m/s *2 _____

And you would get a=10m/s*2 right

HOPE YOU LEARNED SOMETHING SO WHEN WE GO BACK TO SCHOOL YOU WILL KNOW WHAT YOU ARE TALKING ABOUT ! : )

Force is the physical action that can give acceleration to a body upon which it is applied

The true statements about the forces and accelerations of each when they collide are;

The reasons why the above statements are true are given as follows:

Known:

Mass of the truck, m₁ = 5,000 kg

Mass of the car, m₂ = 1,000 kg

Velocity of the truck = [tex]v_t[/tex]

Velocity of the car = [tex]v_c[/tex]

According to Newton's third law of motion, action and reaction are equal and opposite

Force, F = Mass, m × Acceleration, a

Let a₁ represent the acceleration of the truck and let a₂ represent the acceleration of the car, we have;

F = 5,000 × a₁ = 1,000 × a₂

[tex]a_2 = \dfrac{5,000 \ kg}{1,000 \ kg} \times a_1 = 5 \cdot a_1[/tex]

Therefore;

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A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.

A stone is dropped from a bridge and it experiences a uniformly accelerated rectilinear motion. It takes 2.3 s for the stone to reach the water.

We can calculate the height of the bridge, which is equal to the displacement of the stone, using the following kinematic equation.

[tex]s = ut + \frac{1}{2} a t^{2} = (0m/s)(2.3 s) + \frac{1}{2} (9.8m/s^{2} ) (2.3s)^{2} = 26 m[/tex]

where,

A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.

Learn more: https://brainly.com/question/14851168

Answer:

(a). The magnitude of the acceleration of the crate is 1.44 m/s².

(b). The direction  of the crate is 34.60°.

Explanation:

Given that,

Mass of crate = 26.1 kg

Coefficient of kinetic friction = 0.347

We need to calculate the resultant force

Using figure

[tex]F'=\sqrt{(F_{x}+F_{z})^2+F_{y}^2}[/tex]

Put the value into the formula

[tex]F'=\sqrt{(88\cos{55}+54)^2+(88\sin 54)^2}[/tex]

[tex]F'=126.4\ N[/tex]

(a). We need to calculate the acceleration of the crate

Using formula of sum of force

[tex]\sum{F}=F'-\mu N[/tex]

[tex]ma_{total}=F'-\mu mg[/tex]

[tex]a_{total}=\dfrac{F'}{m}-\mu g[/tex]

Put the value into thr formula

[tex]a_{total}=\dfrac{126.4}{26.1}-0.347\times9.8[/tex]

[tex]a_{total}=1.44\ m/s^2[/tex]

(b). We need to calculate the direction

Using formula of the direction

[tex]\theta=\tan^{-1}(\dfrac{F_{y}}{F_{x}+F_{z}})[/tex]

Put the value into the formula

[tex]\theta=\tan^{-1}(\dfrac{88\sin55}{88\cos55+54})[/tex]

[tex]\theta=34.60^{\circ}[/tex]

Hence, (a). The magnitude of the acceleration of the crate is 1.44 m/s².

The direction  of the crate is 34.60°.

Answer:

Hope this helps

Explanation:

Josh Gibson, (born December 21, 1911, Buena Vista, Georgia, U.S.—died January 20, 1947, Pittsburgh, Pennsylvania), American professional baseball catcher who was one of the most prodigious home run hitters in the game’s history. Known as “the black Babe Ruth,” Gibson is considered to be the greatest player who never played in the major leagues, there being an unwritten rule (enforced until the year of his death) against hiring black ballplayers

Answer:

friction, should be correct i think!

The given condition satisfies the Newton's First Law of motion. Hence, option (C) is correct.

Given data:

A boy slides down and friction causes him to slow down and stop.

In the given problem, when boy was sliding down, then he was in the state of motion, such that the when the he reaches at the bottom of hill, the friction plays the role of external agent to stop its motion.

This shows that the first law of motion is clearly followed which says that, "If an object is in motion, then it will be in motion until and unless any external force is applied on it". This is also known as law of inertia.

Thus, we can conclude that the given condition satisfies the Newton's First Law of motion. Hence, option (C) is correct.

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Answer:

Basketball has a mass of 0.1kg

m = 0.1 kg

The basket ball is moving at constant speed, this shows that it is not accelerating. So, acceleration is zero

a = 0m/s²

The constant speed is 6m/s

v = 6m/s

So, force to keep it moving with this constant speed can be calculated using Newton second law of motion

F = ma

F = m × 0

F = 0N

So, since the basket ball is moving at constant speed, then, the force need to keep the ball moving is 0N.

Answer:

density = [tex]\frac{mass}{volume}[/tex]

so,

     d = 2/0.00025

     d = 8000 kg/m3

Answer:

15 cm

Explanation:

using the thin lens formula for convex lens

                            [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\\ \\where f = focal length \\ p = object distance \\ q = image distance\\[/tex]

 so,

         [tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p} \\\\\frac{1}{q} = \frac{1}{10} - \frac{1}{30} \\\frac{1}{q} = \frac{2}{30}\\\frac{1}{q} = \frac{1}{15cm}[/tex]

so,

    q = 15 cm

Answer:

B and D

Explanation:

Did the quiz

Electromagnetic waves require no wires to carry information and can travel through either air or other types of matter.​ Therefore, options (B) and (D) are correct.

Electromagnetic radiations are produced when an electric field comes in contact with the magnetic field. Electromagnetic waves are the composition of oscillating electric as well as magnetic fields.

Infrared radiation is used in security cameras and used for night vision. UV rays are useful to detect forged banknotes as the real banknotes don’t turn fluorescent under UV light.

Electromagnetic radiation can travel energy in a vacuum or air. Electromagnetic waves play a vital role in today's communication technology. Electromagnetic waves are specially used in RADARS to detect aircraft in the earth's atmosphere.

Radio waves, microwaves, infrared (IR), and visible light can be used for communication. Radio waves are used to transmit information on television and radio programs. Microwaves are used to transmit satellites, mobile phones, and television.

Learn more about the electromagnetic wave, here:

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#SPJ5

Answer:

128

Explanation:

One clomiter is 1.06 multipled by 80

Answer:

In space noone can hear you scream.....

Explanation:

There is no sound in space. Sound, like light or heat, is a wave. However, one major distinction is that, unlike light or heat (radiation), sound needs a medium to travel. Sounds require the presence of molecules or particles to travel from one region to another.

Answer: tug vi

Explanation:

Because

Answer:

Hope this answered your question!~ (Sorry if you get it wrong or I got it wrong-)

Explanation:

When an impact event happens, the enormous kinetic energy of the asteroid or meteorite – a massive body travelling at high speed – is partly transferred to the Earth but largely converted into heat and sound, creating pressure waves travelling radially outwards from its centre, similar to that of an atom bomb.

~The Confuzzeled homan

Given parameters:

Initial volume  = 75cm³

New volume  = 30cm³

New pressure  = 110Pa

Unknown:

Initial pressure = ?

Solution:

Condition: temperature is constant

We simply apply Boyle's law to this problem:

   " the volume of a fixed mass(mole) of a gas varies inversely as the pressure changes if the temperature is constant".

  Mathematically;

          P₁ V₁  = P₂ V₂

where P and V are pressure and volume values

          1 and 2 are the initial and final states.

Input the parameters and solve for P₁;

     P₁ x 75  = 110 x 30

   P₁ = 44Pa

The initial pressure is 44Pa