Carbon dioxide enter leaves through a small pore (opening) called the stomata. Gases enter and exit through stoma (plural of stomata)
In cellular respiration oxygen leaves the leaf through the stoma too
what is 10 times 2 divided by 5.
Answer:
4(four)
Step-by-step explanation:
You take the number 10×2=20
Then,20÷5=4
Four{4}is your answer
Answer:
4Step-by-step explanation:
[tex]10 \times 2 \div 5[/tex]
Multiply the numbers
[tex] = 20 \div 5[/tex]
Divide :
[tex] = 4[/tex]
Hope this helps..
Good luck on your assignment..
help please .........
Answer:
30.045
Step-by-step explanation:
the length of rectangle=140 which is also the diameter of circle
R=d/2=140/2=70 ( which is the width of rectangle)
perimeter of rectangle=2l+2w=140+280=420
perimeter of semicircle=πr+d=70π+140=359.911
the difference between two perimeter
(perimeter of rectangle- perimeter of semi circle) =
420-359.911=60.089
since only one shaded area :
60.089/2=30.0445 close to 30.045
This is really confusing I need help with this.
Answer:
Step-by-step explanation:
can you at least telllus what is in the drop box
Determine how many litres of water will fit inside the following container. Round answer and all calculations to the nearest whole number.
Answer:
[tex]\approx[/tex] 11 litres of water will fit inside the container.
Step-by-step explanation:
As per the given figure, we have a container formed with combination of a right angled cone placed at the top of a right cylinder.
Given:
Height of cylinder, [tex]h_1[/tex] = 15 cm
Diameter of cylinder/ cone, D = 26 cm
Slant height of cone, l = 20 cm
Here, we need to find the volume of container.[tex]\\Volume_{Container} = Volume_{Cylinder}+Volume_{Cone}\\\Rightarrow Volume_{Container} = \pi r_1^2 h_1+\dfrac{1}{3}\pi r_2^2 h_2[/tex]
Here,
[tex]r_1=r_2 = \dfrac{Diameter}{2} = \dfrac{26}{2} =13\ cm[/tex]
To find the Height of Cylinder, we can use the following formula:
[tex]l^2 = r_2^2+h_2^2\\\Rightarrow h_2^2 = 20^2-13^2\\\Rightarrow h_2^2 = 400-169\\\Rightarrow h_2^2 = 231\\\Rightarrow h_2=15.2\ cm \approx 15\ cm[/tex]
Now, putting the values to find the volume of container:
[tex]Volume_{Container} = \pi \times 13^2 \times 15+\dfrac{1}{3}\pi \times 13^2 \times 15\\\Rightarrow Volume_{Container} = \pi \times 13^2 \times 15+\pi \times 13^2 \times 5\\\Rightarrow Volume_{Container} = \pi \times 13^2 \times 20\\\Rightarrow Volume_{Container} = 10613.2 \approx 10613\ cm^3[/tex]
Converting [tex]cm^{3 }[/tex] to litres:
[tex]10613 cm^3 = 10.613\ litres \approx 11\ litres[/tex]
[tex]\approx[/tex] 11 litres of water will fit inside the container.
4. You work for an advertising company and have been hired to place a blimp above a football stadium. The angle of elevation from a point directly under the goal post is 72° and the blimp will be directly above the 50 yard line. a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line? b. How high above the ground is the blimp? c. In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet. Will the fans be able to read the advertisement? If not, what possible angle of elevation could we use? d. What is the exact angle if the blimp is at 150 feet?
Answer:
tan θ = [tex]\dfrac{opposite}{adjacent}[/tex]
The height of the blimp above the ground is h = 153.884 yard
No, the fans will not be able to read the advertisement.
The exact angle if the blimp is at 150 feet is 45.74°
Step-by-step explanation:
From the summary of the information given :
The angle of elevation from a point directly under the goal post is 72° and the blimp will be directly above the 50 yard line.
That statement above being illustrated in the attached diagram below for better understanding.
a. Which trigonometric ratio would you use to calculate how high the blimp will be above the 50 yard line?
The trigonometric ratio that can be used to calculate how high the blimp will be above the 50 yard line is :
tan θ = [tex]\dfrac{opposite}{adjacent}[/tex]
b. How high above the ground is the blimp?
Using the above derived trigonometric ratio,
tan θ = [tex]\dfrac{opposite}{adjacent}[/tex]
[tex]tan \ 72^0 = \dfrac{h}{50}[/tex]
[tex]h =tan \ 72^0 \times {50}[/tex]
[tex]h =3.07768 \times {50}[/tex]
h = 153.884 yard
The height of the blimp above the ground is h = 153.884 yard
c. In order to be able to read the advertisement on the side of the blimp the highest the blimp can be is 150 feet.
Will the fans be able to read the advertisement?
No, the fans will not be able to read the advertisement.
This is because, 153.884 yard to feet
= 153.884 × 3
= 461.652 feet which is more than the maximum given 150 feet.
If not, what possible angle of elevation could we use?
The possible angle of elevation can be determined by taking the tangent of the trigonometric ratio.
SO
tan θ = [tex]\dfrac{h}{150}[/tex]
tan θ = [tex]\dfrac{153.884}{150 \ feet}[/tex]
tan θ = 1.026
θ = tan ⁻¹ (1.026)
θ = 45.74°
d. What is the exact angle if the blimp is at 150 feet?
The exact angle if the blimp is at 150 feet is 45.74°
Translate into an algebraic expressions: A number increased by a % and decreased by 80% is 400. What is the number ?
Answer:
(x*(1+a))*0.8 = 400; x = 500/1+a
Step-by-step explanation:
First, increase the number (which we will call x) by a%
x*(1+a) -> You do 1 + a because if you wanted to increase let's say 5 by 20% you would do 5 + 5*0.2 and if you factor that out it becomes 5(1+0.2)
Next, decrease it by 80%.
(x*(1+a))*0.8
Finally, make it into an equation.
(x*(1+a))*0.8 = 400
If you solve it, you get:
x(1+a) = 500
x = 500/1+a
Find all solutions of the equation in the interval [0, 2pi).
2 cos 0 - 13 = 0
Write your answer in radians in terms of t.
If there is more than one solution, separate them with commas.
Answer:
The solutions of 2·cos(θ) - √3 = 0in the interval [0, 2pi) are;
π/6, 13/6·π
Step-by-step explanation:
The given that the equation is 2·cos(θ) - √3 = 0
The solution of the above equation in the interval [0, 2pi) are required
Therefore, the domain includes 0 ≤ θ < 2pi
2·cos(θ) - √3 = 0
2·cos(θ) = √3
cos(θ) = √3/2
Therefore;
θ = cos⁻¹(√3/2)
The values are;
[tex]\theta =\dfrac{12 \cdot \pi \cdot n_1 +\pi }{6} \, or \, \theta =-\dfrac{12 \cdot \pi \cdot n_1 +\pi }{6}[/tex]
Where the domain is 0 ≤ θ < 2pi, we have;
π/6, 13/6·π
Please help! I got 14 but it says it's incorrect! Find the maximum number of real zeros of the polynomial. f(x)=2x^(6)-3x^(3)+1-2x^(5)
Answer:
6
Step-by-step explanation:
The Fundamental theorem of Algebra states that a polynomial of degree n has n roots. These can be real, complex or both.
f(x) = 2[tex]x^{6}[/tex] - 3x³ + 1 - 2[tex]x^{5}[/tex] ← is a polynomial of degree 6
Thus the maximum number of real roots is 6
If a line is perpendicular to each of two intersecting lines at their point of intersection, then the line:
A. not enough information
B. is parallel to the plane determined by the two lines
C. coincides with the plane determined by the two lines
D. is perpendicular to the plane determined by the two lines
D. The line is perpendicular to the plane determined by the two lines.
Remember how you get to 3D space?
You take one axis called x and perpendicularly intersect it with y axis and you get a 2D plane. Now take a 2D plane and perpendicularly intersect it with an axis z and you get 3D euclidean space.
Hope this helps.
there are 9000 children in a town the probability that a child is affected by a virus 1/3 how many children are not likely to be affected
Answer:
6,000 children
Step-by-step explanation:
1/3 of 9,000 is 3,000
Meaning that out of 9,000 children, 3,000 WILL get affected. Since we are trying to figure out how many children will NOT get affected, just subtract the number of infected by the total amount which would be 6,000
PLEASE help me with this question! No nonsense answers and answer with full solutions please!
Answer: b) {-3, 0.5}
Step-by-step explanation:
The new equation is the original equation plus 6. Move the original graph UP 6 units. The solutions are where it crosses the x-axis.
[tex]\text{Original equation:}\quad f(x)=\dfrac{15}{x}-\dfrac{9}{x^2}\\\\\\\text{New equation:}\quad\dfrac{15}{x}+6=\dfrac{9}{x^2}\\\\\\.\qquad \qquad f(x)= \dfrac{15}{x}-\dfrac{9}{x^2}+6[/tex]
+6 means it is a transformation UP 6 units.
Solutions are where it crosses the x-axis.
The curve now crosses the x-axis at x = -3 and x = 0.5.
Which option is equal to 7 1/5
Answer:
D. is the answerStep-by-step explanation:
Question:
7^1/5
The number given has an exponent of a fraction: fraction exponent = 1/5
So, when you have a fraction - you always have a square root - Important!!Since the top is one, the number 7 stays the same. = 7^1 = 7
The bottom is a 5. This means it is to the fifth root.
Answer = D
Hope this helped,
Kavitha
Answer: If 36/7 is one of the options, choose that one.
If the question involves an exponent, you should use the "caret" which is ^ found above the 6 on a keyboard. [Shift + 6]. That helps avoid confusion.
Step-by-step explanation: 7 is equal to 35/5 because 7×5=35
Add 1/5 and you end up with 36/5. A Common rational number.
7^(1/5) = the 5th root of 7. A very small irrational number!
What is the solution set of |–x| = 3.5? {–3.5, 3.5} {–3.5} {3.5} {7}
Answer:
{-3.5, 3.5}
Step-by-step explanation:
Interpreting
|-x| = 3.5
gives
3.5 = +(-x) or 3.5 = -(-x)
or
x = + / - 3.5
so the answer is
{-3.5, 3.5}
Answer:
A
Step-by-step explanation:
Find volume of cylinder if its
radius
height
5.5m and
height 9 m?
Answer:
855.298 m^3
Step-by-step explanation:
The volume of a cylinder equation is piR^2H.
So pi5.5^2×9
855.298 m^3
find the value of the letter in each of the following and give reasons for the steps involved 1 2 A+6 A B=A 0 9
Question:
Find the value of the letter in each of the following and give reasons for the steps involved:
1 2 A
+ 6 A B =
A 0 9
Answer:
128 + 681 = 809
Step-by-step explanation:
Here, let's use the general form of numbers where any letter must represent one value and each digit must be represented by just one letter.
Take the following:
A = 8
B = 1
Thus, A +B = 8 + 1 = 9
Also add:
8 + 2 = 10
In general form, tens digit is zero and the 1 is carried over.
I.e, A = 1 + 6 + 1 = 8
We can now see that,
A = 8
B = 1
Therefore,
1 2 A
+ 6 A B =
A 0 9
Will be written as:
128 + 681 = 809
WILL GIVE THE BRAINLIEST! Which of the following inequalities can be represented by the graph?
=========================================
Explanation:
The boundary line is y = 2x-2. This line goes through (0,-2) and (2,2). Use the slope formula to find the slope to be m = 2, and use the y intercept b = -2 to help form the equation.
Since the boundary line is solid, we will have "or equal to" as part of the inequality sign. This indicates points on the boundary are part of the solution set. Furthermore, we will have a greater than sign because the shaded region is above the boundary. Therefore, we change the equal sign to a "greater than or equal to" sign, going from y = 2x-2 to [tex]y \ge 2x-2[/tex]
If we simply did [tex]y > 2x-2[/tex] without the "or equal to" portion, then the boundary line would be dotted or dashed to tell the reader "points on the boundary are not part of the solution set".
Can someone please explain The measure of angle A to the nearest tenth of a degree is:
Answer:
A =19.5
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin A= opp/ hyp
sin A = 3/9
Take the inverse sin of each side
sin ^-1 sin A = sin ^-1 (3/9)
A =19.47122063
To the nearest tenth of a degree
A =19.5
Answer:
19
Step-by-step explanation:
inverse sin (1/3) = 19.47122060852
[tex]4^{3/4} * 2^{x} =16^{2/5}[/tex]
Answer:
[tex]\sf x=\frac{1}{10}[/tex]
Step-by-step explanation:
Rewrite expression with bases of 4.
[tex]\sf{4^{\frac{3}{4} }} \times \sf({4^\frac{1}{2} )^x =(4^2)^{\frac{2}{5} }[/tex]
Apply law of exponents, when bases are same for exponents in multiplication, add the exponents. When a base with an exponent has a whole exponent, then multiply the two exponents.
[tex]\sf{4^{\frac{3}{4} }} \times \sf{4^{\frac{1}{2} x}=4^{\frac{4}{5} }[/tex]
[tex]\sf{4^{\frac{3}{4} +\frac{1}{2} x}=4^{\frac{4}{5} }[/tex]
Cancel same bases.
[tex]\sf \frac{3}{4} +\frac{1}{2} x=\frac{4}{5}[/tex]
Subtract 3/4 from both sides.
[tex]\sf \frac{1}{2} x=\frac{1}{20}[/tex]
Multiply both sides by 2.
[tex]\sf x=\frac{1}{10}[/tex]
Step-by-step explanation:
2^{2*3/4} × 2^{x}=2^{4×2/5}
2^{3/2} × 2^{x}= 2^{8/5}
2^{3/2+x}=2^{8/5}
equate powers
{3+2x}/2= 2^2
5{3+2x}= 2{8}
15+10x=16
collect like terms
10x=16-15
10x=1
divide both sides by 10
x=1/10
x=0.1
I WILL GIVE BRAINLIEST!!!! A teacher is grading the final exam. He notices that the mean test score is 61, and the standard deviation is 10. The test scores were normally distributed. if there were 450 students in the data sample, how many would have a test score between 61 and 71 *Round your answer to the nearest full value.
Answer:
153.586 close to 154 students
Step-by-step explanation:
mean=61
standard deviation =10
sample 450 students , x between 61 and 71
(x-mean)/deviation for score 61 and 71
61-61/10=0
71-61/10=1
the z-scores is between 0 and 1 ( use calculator)
the percentage is 0.3413 close to 34%
number of students that score between 61 and 71=
450*0.3413= 153.586 close to 154 students
Which of the following represents a function
if you drop a tennis ball from the height of 100in and the rebound is 58in what is the height on the 10th bounce?
Answer:
0.431 inches
Step-by-step explanation:
We were given the following values:
Height the tennis ball was dropped = 100in
Rebound height = 58in
We have to find the rebound ratio
= 58in/100in = 0.58
The formula to be used
Height on nth bounce = Initial height × (Rebound ratio)ⁿ
Where n = number of bounce
Height on the 10th bounce = 100 × (0.58)^10
Height on the 10th bounce = 0.4308042069inches
Approximately, the height on the 10th bounce = 0.431 inches.
The number of representatives of a multi-level marketing company as a function of the number of days that have passed can be modelled by the exponential function R(d). About how many representatives does the company have after 75 days have passed if R(d) =150(1.03)^d
Answer:
About 1377 representatives.Step-by-step explanation:
If the number of representatives of a multi-level marketing company as a function of the number of days that have passed can be modeled by the exponential function R(d) = 150(1.03)^d, to calculate the number of representatives that the company have after 75 days, we will substitute d = 75 into the modeled equation.
R(75) = 150(1.03)^75
R(75) = 150*9.1789
R(75) = 1,376.835
Hence, the company have about 1377 representatives after 75 days.
The table below shows the students in an Algebra 1 class. What is the probability that a randomly chosen student will be a girl? (Note: If your fraction will reduce, you need to reduce it.)
Cece works at a dress shop and needs to calculate the discounts for dresses on sale using the formula d=(p−c)÷2, where d is the discount, p is the original price, and c is the store's cost for the dress. If the store's cost for a dress is $50 and the original price of the dress is $120, what is the discount on the dress?
Answer:
$35
Step-by-step explanation:
Using the formula provided, d=(p−c)÷2 (where d is the discount, p is the original price, and c is the store's cost for the dress.) we can determine the discount.
The original price is 120,
d=(120−c)÷2
The store's cost is 50,
d=(120−50)÷2
So we subtract 120 and 50 to get
d=(70)÷2
70 divide by two is
d= 35
The discount is $35
The app store is offering 15 percent off any purchase for one day, only you decide to buy a game app that cost 12 dollars and 90 cents. If you buy it during the sale, what is the amount of the discount?
Answer:
$1.935
Step-by-step explanation:
As the store is offering a 15% discount, you have to calculate the 15% of the price of the game app to find the amount of the discount:
Price of the game app= 12.90
12.90*15%=1.935
According to this, the answer is that the amount of the discount if you buy the game app during the sale is $1.935 and you would have to pay: 12.90-1.935= $10.965.
3. In the diagram, PQTU is a parallelogram with a
perimeter of 24 cm and an area of 28 cm². Given that
UTS and PQR are straight lines, find the area of the
whole diagram
Answer:
48cm²
Step-by-step explanation:
PQ=(24-5-5)/2=7
This means PR is 14 and US is 10.
The height of the parallelogram is base times height, so 28/7=4
Now we just look at it as one big parallelogram.
4(14+10)/2=48 cm²
do these problems and get 100 points 1. Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. c 22 and 15 2 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. d 13.2 and 6.7 3 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. e 34 and 12 4 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. f 23 and 44
Answer:
[tex]7 < x < 37[/tex] -- Triangle 1
[tex]6.5 < x < 19.9[/tex] -- Triangle 2
[tex]22 < x < 46[/tex] -- Triangle 3
[tex]21 < x < 67[/tex] -- Triangle 4
Step-by-Step Explanation:
Given
2 sides of a triangle
1. 22 and 15
2. 13.2 and 6.7
3. 34 and 12
4. 23 and 44
Required
Determine the range of the third side in the above triangles
Triangle 1: 22 and 15
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]22 + x > 15[/tex]
[tex]22 + 15 > x[/tex]
[tex]15 + x > 22[/tex]
Solving
[tex]22 + x > 15[/tex]
Make x the subject of formula
[tex]x > 15 - 22[/tex]
[tex]x > -7[/tex]
Solving
[tex]22 + 15 > x[/tex]
[tex]37 > x[/tex]
Solving
[tex]15 + x > 22[/tex]
Make x the subject of formula
[tex]x > 22 - 15[/tex]
[tex]x > 7[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]37 > x[/tex] and [tex]x > 7[/tex]
Rewrite both inequalities
[tex]x < 37[/tex] and [tex]7 < x[/tex]
Combine the two inequalities
[tex]7 < x < 37[/tex]
Triangle 2: 13.2 and 6.7
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]13.2 + x > 6.7[/tex]
[tex]13.2 + 6.7 > x[/tex]
[tex]6.7 + x > 13.2[/tex]
Solving
[tex]13.2 + x > 6.7[/tex]
Make x the subject of formula
[tex]x > 6.7 - 13.2[/tex]
[tex]x > -6.5[/tex]
Solving
[tex]13.2 + 6.7 > x[/tex]
[tex]19.9 > x[/tex]
Solving
[tex]6.7 + x > 13.2[/tex]
Make x the subject of formula
[tex]x > 13.2 - 6.7[/tex]
[tex]x > 6.5[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]19.9 > x[/tex] and [tex]x > 6.5[/tex]
Rewrite both inequalities
[tex]x < 19.9[/tex] and [tex]6.5 < x[/tex]
Combine the two inequalities
[tex]6.5 < x < 19.9[/tex]
Triangle 3: 34 and 12
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]34 + x > 12[/tex]
[tex]34 + 12 > x[/tex]
[tex]12 + x > 34[/tex]
Solving
[tex]34 + x > 12[/tex]
Make x the subject of formula
[tex]x > 12 - 34[/tex]
[tex]x > -22[/tex]
Solving
[tex]34 + 12 > x[/tex]
[tex]46 > x[/tex]
Solving
[tex]12 + x > 34[/tex]
Make x the subject of formula
[tex]x > 34 - 12[/tex]
[tex]x > 22[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]46 > x[/tex] and [tex]x > 22[/tex]
Rewrite both inequalities
[tex]x < 46[/tex] and [tex]22 < x[/tex]
Combine the two inequalities
[tex]22 < x < 46[/tex]
Triangle 4: 23 and 44
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]23 + x > 44[/tex]
[tex]23 + 44 > x[/tex]
[tex]23 + x > 44[/tex]
Solving
[tex]23 + x > 44[/tex]
Make x the subject of formula
[tex]x > 23 - 44[/tex]
[tex]x > -21[/tex]
Solving
[tex]23 + 44 > x[/tex]
[tex]67 > x[/tex]
Solving
[tex]23 + x > 44[/tex]
Make x the subject of formula
[tex]x > 44 - 23[/tex]
[tex]x > 21[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]67 > x[/tex] and [tex]x > 21[/tex]
Rewrite both inequalities
[tex]x < 67[/tex] and [tex]21 < x[/tex]
Combine the two inequalities
[tex]21 < x < 67[/tex]
Please solve it 90 POINTS please help- PLEASE HELP its Identify the following for the quadratic relations please solve it all please if you can save the picture and do it on the page
Answer:
Step-by-step explanation:
2)
a) elimination method
b) substitution method
c) substitution method
For the first part we can elimate the y variable by subtracting the equations. We can then find the value of x.
For the second part we can substitute y as 2x+5 in the second equation and solve for x.
For the third part we can substitute y as 4x+3 in the first equation and solve for x.
3)
Ten turns of a wire are helically wrapped around a cylindrical tube with outside circumference 4 inches and length 9 inches. The ends of the wire coincide with ends of the same cylindrical element. Find the length of the wire. (a) 41 inches (b)36 inches (c) 40 inches (d) 90 inches
Answer:
b) 36 inches
Step-by-step explanation:
Length of the wire = Outside circumference of the cylindrical tube * length of the cylinder
= 4 * 9
= 36 inches
Length of the wire will be same to the surface area of the cylinder
Surface area of cylinder = circumference * length
In the picture down below
Answer:
Option C. f¯¹(x) = x + 3
Step-by-step explanation:
f(x) = x – 3
To find the inverse, f¯¹(x) of f(x), we simply do the following:
f(x) = x – 3
Replace f(x) with y
y = x – 3
Interchange y and x
x = y – 3
Make y the subject by rearranging
x + 3 = y
y = x + 3
Replace y with f¯¹(x)
f¯¹(x) = x + 3
Therefore, the inverse of f(x) = x – 3 is f¯¹(x) = x + 3