Consider the addition of an electron to the following atoms from the fourth period. Rank the atoms in order from the most negative to the least negative electron affinity values based on their electron configurations. Atom or ion Electron configuration BrBr 1s22s22p63s23p64s23d104p51s22s22p63s23p64s23d104p5 GeGe 1s22s22p63s23p64s23d104p21s22s22p63s23p64s23d104p2 KrKr 1s22s22p63s23p64s23d104p61s22s22p63s23p64s23d104p6 Rank the electron affinity from most negative to least negative. To rank items as equivalent, overlap them. View Available Hint(s)
Answer:
Br>Ge>Kr
Explanation:
Electron affinity is the energy change that results from adding an electron to a gaseous atom(Khan Academy). It is also defined as "the amount of energy released when an electron is attached to a neutral atom or molecule in the gaseous state to form a negative ion" (Wikipedia).
Electron affinity increases from left to right in the periodic table. However, the noble gases possess a complete outermost electron shell.
Hence, electron affinity can be raked from the most negative to the least negative for the three atoms as follows; Br>Ge>Kr
What are Renewable Resoures?
Answer:
resources that you can use more than 1 time like rechargeable battery or solar energy
Explanation:
Calculate how many moles of NO2 form when each
quantity of reactant completely reacts.
2 N2O5(9) + 4NO2(g) + O2(9)
Part B
6.4 mol N205
Express your answer using two significant figures.
VALO
n =
Submit
Request Answer
Part C
16.2 g N205
Express your answer using three significant figurer
Answer:
partB: n=2N205
partc:17.20
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezing point of pure . On the other hand, when of sodium chloride are dissolved in the same mass of , the freezing point of the solution is lower than the freezing point of pure . Calculate the van't Hoff factor for sodium chloride in . Be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.
The given question is incomplete. The complete question is:
When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.
Answer: The vant hoff factor for sodium chloride in X is 1.9
Explanation:
Depression in freezing point is given by:
[tex]\Delta T_f=i\times K_f\times m[/tex]
[tex]\Delta T_f=T_f^0-T_f=8.2^0C[/tex] = Depression in freezing point
[tex]K_f[/tex] = freezing point constant
i = vant hoff factor = 1 ( for non electrolyte)
m= molality =[tex]\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9[/tex]
[tex]8.2^0C=1\times K_f\times 1.9[/tex]
[tex]K_f=4.32^0C/m[/tex]
Now Depression in freezing point for sodium chloride is given by:
[tex]\Delta T_f=i\times K_f\times m[/tex]
[tex]\Delta T_f=20.0^0C[/tex] = Depression in freezing point
[tex]K_f[/tex] = freezing point constant
m= molality = [tex]\frac{136g\times 1000}{950g\times 58.5g/mol}=2.45[/tex]
[tex]20.0^0C=i\times 4.32^0C\times 2.45[/tex]
[tex]i=1.9[/tex]
Thus vant hoff factor for sodium chloride in X is 1.9
How many grams are in 8.3 moles of CaCl2?
Answer:
(8.3×40)+(8.3×71)
921.3grames
Answer:
[tex]\Large \boxed{\sf 921.3 \ g}[/tex]
Explanation:
Use formula
[tex]\displaystyle moles=\frac{mass}{M_r}[/tex]
[tex]M_r=40+35.5 \times 2 = 111[/tex]
Solve for mass
[tex]mass=8.3 \times 111=921.3[/tex]
What is one way that minerals crystallize from materials dissolved in water?
Answer:
From solutions that evaporate
From hot water solutions when the solution cools
Explanation:
The substances that can form minerals can be dissolved in the water to form a solution. Solution can be described as as a mixture in which a solute is dissolved in a solvent. When a particular dissolved solute evaporates from the solution, crystals of minerals might form. The mineral halite was formed when seas evaporated over a period of time.
The minerals can also be formed when a hot water solution gets cooled.
someone help i will give branliest:)
Answer:
i think answer is B negative effects and benefits
Knowing that Boyle's Law is P1V1 = P2V2, How would we rearrange the formula if we needed to solve for P1?
A. P1 = V1 -P2
B. P1 = P2V2 - V1
C. P1 = P2V2/V1
D. P1= V1/V2
Answer:
your answer is C
Explanation:
because when u make P1 the subject formula then P2 V2 will be divided with V1
1. Which kingdom is made up of only autotrophs?
A. Protista
I
B. Animalia
C. Plantae
D. Phylum
Answer: I believe it's C
Hope this helped<3
Can you please make my answer brainly
what components of static electricity theory does Electrostatic Precipitator make use of
Answer:
Electrostatic smoke precipitators work by forcing dirty flue gas (the gas escaping from a smokestack) past two electrodes (electrical terminals), which take the form of metal wires, bars, or plates inside a pipe or smokestack
Explanation:
Question #37.P.2A.2
Which statement about the periodic table is true?
a. Elements in the same column share similar properties.
b. Elements in the same row share similar properties.
c. Elements on the left have a larger nucleus than elements on the right.
d. Elements at the top of each column have the highest atomic mass in that column.
In what part of the atom do alpha or beta particles originate?
Answer:
Nucleus
Explanation:
they originate in the nucleus
Which of the following is the correct definition of "weathering"? *
The movement of rocks
The breakdown of rocks.
The dropping off of rocks
All of the above
explanation and answer and you’ll get brain list
Answer:
Option B.
Explanation:
2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂First we convert 9.90 g of Pb(NO₃)₂ into moles, using its molar mass:
9.90 g ÷ 331.2 g/mol = 0.0299 mol Pb(NO₃)₂Then we convert moles of Pb(NO₃)₂ into moles of PbO, using the stoichiometric coefficients:
0.0299 mol Pb(NO₃)₂ * [tex]\frac{2molPbO}{2molPb(NO_3)_2}[/tex] = 0.0299 mol PbONow we convert 0.0299 mol PbO into grams, using its molar mass:
0.0299 mol PbO * 223.2 g/mol = 6.67 g PbOSo 6.67 g is the theoretical yield. With that in mind we calculate the percent yield:
% yield = 5.51 / 6.67 * 100 % = 82.6%So the correct answer is option B.
what energy is stored
Answer: potential energy is stored
Explanation:
How many moles of gold atoms do 3.45x10^24 gold atoms constitute?
Answer:
3.45E24
Explanation:
calculator I'm not that great at math but I'm good at science but that isn't really science but it's aix between it tho
8. A liquid boils when the vapor pressure of the liquid equals the atmospheric pressure on the surface
of the liquid. Using Reference Table H, determine the boiling point of water when the atmospheric
pressure is 90. kPa
Answer:
It is 98 degrees C.
Explanation:
Convert 25.6 L of a gas at STP to molecules
Which of the following apply to concentration?
Answer:Concentration of products can vary.
As more solute dissolves, more ions form; but the volume in which they are contained does not change.
Concentration of the solid phase does not change.
Explanation:
Which contributes to the polarity of a water molecule?
Oa linear shape along with strong covalent bonds
O deflection of hydrogen atoms by lone pairs of electrons
O no difference in the electronegativity of oxygen and hydrogen
Ohydrogen bond formation between water molecules
Answer:
B
Explanation:
Answer:
B
Explanation:
Edge 2022
The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m2 at 500C. Assume a diffusion coefficient of 1.0 108 m2 /s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained
This question is incomplete, the complete question is;
The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.
Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained
Answer:
the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg
Explanation:
Given the data in the question;
thickness of sheet t = 5 mm
Area A = 0.20 m²
Temperature T = 500°C
diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s
concentration high pressure side C[tex]_A[/tex] = 2.4
concentration low pressure side C[tex]_B[/tex] = 0.6 kg
from the question, we calculate the concentration gradient
dc/dx = (C[tex]_A[/tex] - C[tex]_B[/tex])/dt
so we substitute
dc/dx = (2.4 - 0.6) / ( - 5 × 10⁻³ )
dc/dx = -360
now, mass of hydrogen per hour that diffuse through a pd sheet
M = -∝AT(dc/dx)
where time t is 1 hour ( 3600 sec )
we substitute
M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)
M = 0.002592
M = 2.592 × 10⁻³ kg per one hour
Therefore, the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg
The number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500°C is 2.592 × 10⁻³ kg.
Purification: It refers to the process of removing impurities or contaminants from a substance in order to make it cleaner, purer, or more refined. It also involves the elimination or reduction of unwanted substances or components that may be present in the original material.
According to the question, given data is:
Thickness of sheet t = 5 mm
Area A = 0.20 m²
Temperature T = 500°C
Diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s
Concentration high pressure side [tex]C_A[/tex] = 2.4
Concentration low pressure side[tex]C_B[/tex]= 0.6 kg
from the question, we calculate the concentration gradient,
[tex]dc/dx = (C _A- C_B)/dt[/tex]
so, we substitute the values,
[tex]dc/dx[/tex] = (2.4 - 0.6)/ ( - 5 × 10⁻³)
[tex]dc/dx = -360[/tex]
Now, mass of hydrogen per hour that diffuse through a Palladium sheet,
M = -∝[tex]AT(dc/dx)[/tex]
where time t is 1 hour (3600 sec)
We substitute,
M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)
M = 0.002592
M = 2.592 × 10⁻³ kg per hour.
Therefore, the number of kilograms of hydrogen that pass per hour through a palladium sheet is approximately 2.592 × 10⁻³ kg.
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This question is incomplete, the complete question is;
The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.
Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.
HELP ANYONE THERE
At a research lab, a scientist carelessly pours cultures of living microbes down the drain. Which type of pollution is this?
Question 4 options:
toxic
sediment
nutrient
bacterial
A scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.
What is bacterial pollution?Bacterial pollution refers to the uncontrolled proliferation of bacteria in the surrounding environment and ecosystems.
Bacterial pollution can be a subject of concern because bacteria may be pathogenic microorganisms.Bacterial pollution may cause serious harm to the public health and the well-being of a population.In conclusion, a scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.
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Name the SI base units that are important in chemistry.
Units of the SI System
There are seven base units in the SI system:
the kilogram (kg), for mass
the second (s), for time
the kelvin (K), for temperature
the ampere (A), for electric current
the mole (mol), for the amount of a substance
the candela (cd), for luminous intensity
the meter (m), for distance
_BaS + _PtF2 → _BaF2 + _Pts
[tex]\huge\underline\mathbb\pink{ANSWER\::}\\\\[/tex]
_BaS + _PtF2 → _BaF2 + _Pts
Barium Sulfide + Platinum(II) Fluoride = Barium Fluoride + Platinum(II) Sulfide.
=> 1 BaS + 1 PtF2 → 1 BaF2 + 1 PtS
[tex]\\\\\\[/tex]
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Explain about Bose-Einstein condensate.
Answer:
A Bose-Einstein condensate or BEC in simple words is a group of atoms cooled near absolute zero.
what are the three components of a chemical formula?
Answer:
The three components of a chemical formula are the empirical formula, the molecular formula, and the structural formula.Hope this answer helps.
Which of the following is the Brønsted-Lowry definition of an acid?
Answer:
A Brønsted-Lowry acid is any species that can donate a proton (H +) to another molecule. A Brønsted-Lowry base is any species that can accept a proton from another molecule. In short, a Brønsted-Lowry acid is a proton donor (PD), while a Brønsted-Lowry base is a proton acceptor (PA).
#8 explain and answer
Answer:
B. The limiting reactant determines the maximum amount of product that can be formed.
Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis
The given question is incomplete. The complete question is:
Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced
Answer: 60.0 g of glucose
Explanation:
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
a) moles of [tex]CO_2[/tex]
[tex]\text{Number of moles}=\frac{88.0g}{44g/mol}=2.0moles[/tex]
b) moles of [tex]H_2O[/tex]
[tex]\text{Number of moles}=\frac{64.0g}{18g/mol}=3.5moles[/tex]
[tex]6CO_2+6H_2O\rightarrow C_{6}H_{12}O_6+6O_2[/tex]
According to stoichiometry :
6 moles of [tex]CO_2[/tex] require = 6 moles of [tex]H_2O[/tex]
Thus 2.0 moles of [tex]CO_2[/tex] require=[tex]\frac{6}{6}\times 2.0=2.0moles[/tex] of [tex]H_2O[/tex]
Thus [tex]CO_2[/tex] is the limiting reagent as it limits the formation of product.
As 6 moles of [tex]CO_2[/tex] give = 1 moles of glucose
Thus 2.0 moles of [tex]CO_2[/tex] give =[tex]\frac{1}{6}\times 2.0=0.33moles[/tex] of glucose
Mass of glucose = [tex]moles\times {\text {Molar mass}}=0.33moles\times 180g/mol=60g[/tex]
Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water
In green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis produces 60.0 g of glucose.
To calculate the moles, we use the equation:
Number of moles Given mass Molar mass a) moles ofNumber of moles = (88.0g)/(44g / mol) = 2.0mol*epsilonb) moles of H2ONumber of les = (64.0g)/(18g / mol) = 3.5molesAccording to stoichiometry6 moles of re = 6mol of H2OWhat is mole fraction ?Mole fraction is a unit of concentration, described to be same to the range of moles of a element divided via way of means of the entire range of moles of a solution.
Thus it is well explained.
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A student said, "You can't see the full Moon during the day because it rises close to sunset."
Which diagram supports this statement? (Diagrams are not to scale. You are looking down from
a north polar view fisa person standing on Earth at sunset.)
Oq. Ooo
Ooo
OD
ОА
OB
ОС
OD
Answer:
I think it would be B.
Explanation: