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What kind of weather forms with an occluded front?

Answers

Answer 1
Occluded fronts usually form around areas of low atmospheric pressure.
There is often precipitation along with the occluded front with clouds.

Related Questions

Because a water molecule has a negative end and a positive end it displays?

Answers

Answer:

A water molecule displays polarity by having negative and positive ends. Due to this charge difference, a water molecule is called a dipole.

Explanation:

What is the function of an atoms nucleus?
1. It holds protons and
neutrons

2. It contains electrons

3.it communicates with other atoms

4.none and above

Answers

Answer:

The answer to the question is A. :)

The correct answer is Option A.

Protons and neutrons are found in the nucleus.

Explain about atoms nucleus?An atom is a complex configuration of negatively charged electrons arranged around a positively charged nucleus in predetermined shells. Electrically positive protons and electrically neutral neutrons make up atomic nuclei. The strongest fundamental force known to science, also known as the strong force, holds these things together. The nucleus typically makes up more than 99.9% of the atom's mass but much less than.01 percent of its volume.Although protons and neutrons are similar in mass, protons have one unit of positive charge (+ e), while neutrons have no charge. The center of an atom is where all of these particles are crammed into a very small area.The force needed to keep an atom together and in place is produced by the atom's nucleus.

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3. Convert the word equations below to symbolic:
Sodium + chlorine sodium chloride
• Calcium + bromine ---- calcium bromide
• Potassium + water → potassium hydroxide + hydrogen
ot

Answers

Answer:

1)2Na + Cl2 ----> 2NaCl

2)Ca + Br2 ---->CaBr2

3)K + H2O -----> KOH + H2

What is the molarity of a 9.79 L solution that contains 0.400 mol HCI

Answers

Answer:

0.041 M

Explanation:

The molarity of a solution when given the number of moles the substance and it's volume can be found by using the formula

[tex]c = \frac{n}{v} \\ [/tex]

n is the number of moles

v is the volume in L

We have

[tex]c = \frac{0.4}{9.79} \\ = 0.04058...[/tex]

We have the final answer as

0.041 M

Hope this helps you

A mixture of water and water vapor is present in a closed vessel at 20 degrees Celsius. the total pressure of the system is 755.0 mmHg. Partial pressure of water vapor at 20 degrees Celsius equals 17.5 mm Hg. What is the partial pressure of H2

Answers

Answer:

737.5 mmHg

Explanation:

Ptotal=PH2O+PH2

P is the pressure and since we have Ptotal and PH2O, we can solve for PH2

755=17.5+x

755-17.5=x

x=737.5

2. A plant growing in response to the sunlight.
A.Gravitropism
B.Phototropism
C.Thigmotropism
D.Hydrotropism

Answers

Answer:

phototropism

Explanation:

since photo is (light?

Phototropism - because she photo means light hydro is water and gravi thing of earth

Helen is studying the properties of solids. She is comparing the wooden cube and the steel cube shown in the picture below.

mc065-1

Which property is the same for the two cubes?


color

luster

texture

volume

Answers

volume. they are different colors, they aren’t the same luster, and one is smooth while the other might be slightly rough

What is the energy of the reactants?
k]
What is the energy of the products?
k]
What is the activation energy of the forward reaction?
k]
What is the activation energy of the reverse reaction?
k]
What the energy of the forward reaction?
k]
What is the energy of the reverse reaction?
Is the forward reaction endothermic or exothermic?
Is the reverse reaction endothermic or exothermic?

Answers

Answer:

1. The energy of the reactant is 50 KJ

2. The energy of the product is 100 KJ

3. The activation energy of the forward reaction is 200 KJ.

4. The activation energy of the reverse reaction is 150 KJ.

5. The energy of the forward reaction is +50 KJ

6. The energy of the reverse reaction is –50 KJ

7. Endothermic reaction

8. Exothermic reaction

Explanation:

1. Determination of the energy of reactant.

From the diagram given above, the energy of the reactant is 50 KJ

2. Determination of the energy of product.

From the diagram given above, the energy of the product is 100 KJ.

3. Determination of the activation energy of the forward reaction.

The activation energy is the energy between the reactant and the peak. It can be obtained as follow:

Energy of reactant (Eᵣ) = 50 KJ

Energy at the peak (Eₕ) = 250 KJ

Activation energy (Eₐ) =?

Eₐ = Eₕ – Eᵣ

Eₐ = 250 – 50

Eₐ = 200 KJ

Thus, the activation energy of the forward reaction is 200 KJ

4. Determination of the activation energy of the reverse reaction.

Energy of reactant (Eᵣ) = 100 KJ

Energy at the peak (Eₕ) = 250 KJ

Activation energy (Eₐ) =?

Eₐ = Eₕ – Eᵣ

Eₐ = 250 – 100

Eₐ = 150 KJ

Thus, the activation energy of the reverse reaction is 150 KJ

5. Determination of the energy of the forward reaction.

Energy of reactant (Eᵣ) = 50 KJ

Energy of product (Eₚ) = 100 KJ

Enthalpy change (ΔH) =?

ΔH = Eₚ – Eᵣ

ΔH = 100 – 50

ΔH = +50 KJ

Thus, the energy of the forward reaction is +50 KJ

6. Determination of the energy of the reverse reaction.

Energy of reactant (Eᵣ) = 100 KJ

Energy of product (Eₚ) = 50 KJ

Enthalpy change (ΔH) =?

ΔH = Eₚ – Eᵣ

ΔH = 50 – 100

ΔH = –50 KJ

Thus, the energy of the reverse reaction is –50 KJ

7. The forward reaction is endothermic reaction because the energy of the product is higher than the energy of the reactant which leads to positive energy of the forward reaction (+50 KJ).

8. The reverse reaction is exothermic reaction because the energy of the product is lesser than the energy of the reactant which leads to negative energy of the reverse reaction (–50 KJ). In a nut shell, we can say that the energy of the reverse reaction is exothermic because its energy of reaction is –50 KJ.

Identify the Lewis base in this balanced equation: 6 upper H subscript 2 upper O plus UPper C r (upper H subscript 2 upper O) subscript 6 superscript 3 plus. H2O Cr3+ Cr(H2O)63+

Answers

The Lewis base that we can see in the equation is [tex]H_{2} O[/tex]

What is the Lewis base?

We have to bear in mind that the Lewis base is the substance that is able to donate a pair of electrons. The substances that is able to accept the pair of electrons is what we call the Lewis acid.

The Lewis acid must possess a space for the addition of an electron pair while the Lewis base would have to be a specie that has a lone pair of electrons or has a negative charge. Thus the water molecule would serve as a Lewis base in this regard.

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Answer:

6 upper H subscript 2 upper O plus UPper C r (upper H subscript 2 upper O) subscript 6 superscript 3 plus.

✔ H2O or A.)

Cr3+

Cr(H2O)63+

The initial volume of a gas is 21 L and the final volume is 38.7 L. If the initial temperature was 261 K, what is the final temperature (in Kelvin)?

Answers

Answer:

480.9K

Explanation:

V1=21L

V2=38.7L

T1=261K

T2=?

Using Charles law,

V1/T1=V2/T2

Inputting the given values,

21/261=38.7/T2

T2=480.9K

pH de un jugo de naranja con [H+]=5.6×10-4M.​

Answers

Explanation:

[tex]pH = - log[H {}^{ + } ] \\ = - log(5.6 \times {10}^{ - 4} ) \\ = 3.25[/tex]

3. How many oxygen atoms are there in 5.0 mol of water?

Answers

Answer:

3.01 * 10^23 oxygen atoms

Explanation:

Water is H2O. So there are one oxygen atom for every molecule of water.

So in 5.0 mol of water molecules, there are 5.0 mol of oxygen atoms.

Since 5.0 mol = 5 * 6.02 * 10^23 molecules, there are 3.01 * 10^23 oxygen atoms.

If I have 7.0 x 10^24 formula units of magnesium chloride, how many grams of chlorine would I have?

Answers

Answer:

824 g

Explanation:

First we convert 7.0 x 10²⁴ formula units of magnesium chloride (MgCl₂) into moles, using Avogadro's number:

7.0 x 10²⁴ formula units ÷ 6.023x10²³ formula units/mol = 11.62 mol MgCl₂

There are two Cl moles per MgCl₂ moles, meaning that we have (2 * 11.62) 23.24 moles of Cl

Finally we convert 23.24 moles of chlorine into grams, using chlorine's molar mass:

23.24 mol * 35.45 g/mol = 824 g

What is the fundamental different between combustion and nuclear reaction

Answers

Answer:

Nuclear reactions involve a change in an atom's nucleus, usually producing a different element. Chemical reactions, on the other hand, involve only a rearrangement of electrons and do not involve changes in the nuclear.

Explain what is meant by a river’s load, and describe how the load is carried.
Please hurry I m timed T-T

Answers

Answer:

A rivers load is gravel and sand. It is carried by being dragged, rolled, and bounced along the bed of the river.

Explanation:

Answer:

the amount of gravel and sand at a river

the load is carried by the moving water

please answer asap!

What is the molarity of a KOH solution if 200 ml of the solution contains 0.6 moles KOH?

a. 0.3 M
b. 0.6 M
c. 3.0 M
d. 6.0 M

Answers

200 ml is 1/5 of a liter, so the answer is five times the number of moles present in the solution. 0.6 moles/0.2 liter = x moles/1.0 liter. Solving for x gives 0.2 x = 0.6 or x = 3.0 M

so the answer is c

A chemist titrates 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid. How many mL of NaOH will be required to titrate to the endpoint

Answers

[tex](normality \: of \: acid)×(volum \: of \: acid) = (normality \: of \: base)×(volum \: of \: base)[/tex]

0.15N × 50mL = 0.2N × (Vbase)

75mL = Volum of base

37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid to the endpoint.

How to calculate volume?

The volume of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

C1 = initial concentrationC2 = final concentrationV1 = initial volumeV2 = final volume

C1 = 0.200MC2 = 0.150MV1 = ?V2 = 50mL

0.2 × V1 = 0.150 × 50

0.2V1 = 7.5

V1 = 7.5/0.2

V1 = 37.5mL

Therefore, 37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 mL of 0.150 M HCI, strong acid to the endpoint.

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a layer of paint can be used to prevent iron rusting true or false​

Answers

Answer:

true

Explanation:

This layer will prevent moisture from reaching the metal and therefore prevent rust. oil paint especially

A 1.4639-g sample of limestone is analyzed for Fe, Ca, and Mg. The iron is determined as Fe2O3 yielding 0.0357 g. Calcium is isolated as CaSO4, yielding a precipitate of 1.4058 g, and Mg is isolated as 0.0672 g of Mg2P2O7. Report the amount of Fe, Ca, and Mg in the limestone sample as %w/w Fe2O3, %w/w CaO, and %w/w MgO

Answers

Answer:

A) w/w % of Fe - 2.44%

B) w/w % of Mg - 4.590%

C) w/w % of Ca - 96%

Explanation:

A) w/w % of Fe in limestone as Fe2O3 = (Mass of Fe2O3 /Mass of limestone) x 100

 0.0357/1.4639 X 100

= 2.438 =2.44

B) w/w % of Mg in limestone as Mg2P2O7 = (Mass of Mg2P2O7 /Mass of limestone) x 100

= 0.0672/1.4639 X 100

= 4.590

C) w/w % of Ca in limestone as CaSO4 = (Mass of CaSO4/Mass of limestone) x 100

= 1.4058/1.4639 X 100

= 96

                                                           

Answer:Fe =1.71%    Ma=0.99%    Ca=28.24%

Explanation:

Which of the statements below about an acid-base buffer solution is/are true?
I. It can be prepared by combining a strong acid with a salt of its conjugate base.
II. It can be prepared by combining a weak acid with a salt of its conjugate base.
III. It can be prepared by combining a weak base with its conjugate acid.
IV. The pH of a buffer solution does not change when the solution is diluted.
V. A buffer solution resists changes in its pH when an acid or base is added to it.
A. I, II, and IV.
B. II, III, and V.
C. II, III, IV, and V.
D. I, II, IV, and V.
E. II, III, and IV.

Answers

Answer:

C. II, III, IV, and V.

Explanation:

Acid buffer is  generally formed by the combination of a weak acid as well as the salt of the conjugate base.

Basic buffer is formed the combination of a weak base and also the salt of the conjugate acid.

On dilution the ration of the concentration terms of the salt and weak acid/base does not change. Hence the pH of the buffer solution does not change.

When acid or base is added to buffer, it resists changes in the pH.

Therefore, option (C) is correct.

Try moving an electron from the metal to the non metal.What happens?

Answers

Answer:

Sodium becomes a positive ion and chlorine becomes a negative ion. ... Each atom is neutrally charged, which means that each atom has the same number of protons and electrons.

Explanation:

Identify the reaction type of the chemical reaction below. Check all that apply.
Mg (s)+2 HCl (aq) MgCl 2 (aq)+H 2 (g)

Answers

Answer:

The type of reaction is a single-replacement reaction.

Explanation:

Mg switches places with H, leaving H by itself.

How many moles of OH−(aq) (hydroxide ions)are present in the balanced redox reaction?
NO3−(aq) + ClO−(aq) + H2O(l) → NO(g) + ClO2−(aq) + OH−(aq)

Answers

There are 4 moles of (aq) showed in the reaction i think

How many grams of CuSO4 are required to make a 5.0 ml solution that has a concentration of 400 mg/ml?

Answers

Answer:  molecular weight of CUSO4 or grams. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CUSO4, or 346.10221 grams. Note that rounding errors may occur, so always check the results.

Explanation:

Only animals and not plants can adapt to their environment true or false

Answers

Answer:

true

Explanation:

np have a good day brainliest?

the solubility of PbSO4 is 0.048g/Liter. what is the Ksp of PbSO4? (MMPbSO4 = 303.3)​

Answers

Answer:

Ksp of PbSO4 is 2.5 *10^-8

Explanation:

Given -

Solubility of PbSO4 = 0.048g/Liter

[Pb+2] * [SO42-] = mass/molecular weight of PbSO4

[Pb+2] * [SO42-] =  0.048g/Liter/303.3g/mol = 0.000158 M

Concentration of PbSO4 = moles/volume = 0.000158 M/1L = 0.000158 M

Ksp = [Pb+2] * [SO42-]

ksp = 0.000158 * 0.000158 = 2.5 *10^-8

Express your answer as a balanced half-reaction. Identify all of the phases in your answer.
(acidic) Cr2O7 2−(aq)⟶Cr 3+(aq)
(acidic) CrO4 2−(aq)⟶Cr(OH)4 −(aq)
(acidic) Bi 3+(aq)⟶BiO3 −(aq)
(acidic) CIO −(aq)⟶Cl −(aq)
(^for CIO - that is an i not an L)

Answers

Answer:

1. Cr₂O₇²−(aq) + 14H+ (aq) + 6e- ---->⟶2 Cr³+(aq) + 7H₂O (l)

2. CrO₄²− (aq)⟶+ 4H+ (aq) + 3e- ---> Cr(OH)₄ −(aq)

3. Bi³+ (aq) + 3H₂O (l) ---> BiO₃− (aq) + 6 H+ (aq) + 2 e-

4. CIO −(aq)⟶+ 2H+ (aq) + 2e- ---> Cl −(aq) + H₂O

Explanation:

The given equations are redox reaction equations expressed as as half reactions.

The first step is to identify whether the half-reaction is oxidation reduction.

Then the number of electrons gained or lost are added on the right side of the equation.

Appropriate H+ ions and water molecules are added where necessary since the reaction takes place in acidic environment

The atoms of elements involved in the reaction are balanced by adding the correct coefficients.

1. (acidic) Cr2O7 2−(aq)⟶Cr 3+(aq)

The half-reaction is reduction as the oxidation number of chromium changes from +6 to +3. Two Cr⁶+ ions accepts 3 electrons each to form Cr³+ ions

Cr₂O₇²−(aq) + 6e- ---->⟶2 Cr³+(aq)

Cr₂O₇²−(aq) + 14H+ (aq) + 6e- ---->⟶2 Cr³+(aq) + 7H₂O (l)

2. (acidic) CrO₄²− (aq)⟶---> Cr(OH)₄ −(aq)

The half-reaction is a reduction. One Cr⁶+ accepts 3 electrons to become Cr³+

CrO₄²− (aq)⟶+ 3e- ---> Cr(OH)₄ −(aq)

CrO₄²− (aq)⟶+ 4H+ (aq) + 3e- ---> Cr(OH)₄ −(aq)

3, (acidic) Bi³+ (aq)⟶---> BiO₃− (aq)

The half-reaction is an oxidation. One Bi³+ ion gives up two electrons to become Bi⁵+

Bi³+ (aq)⟶---> BiO₃− (aq) + 2e-

Bi³+ (aq) + 3H₂O (l) ---> BiO₃− (aq) + 6 H+ (aq) + 2 e-

4. (acidic) CIO −(aq)⟶---> Cl −(aq)

The half-reaction is a reduction. One Cl+ ion accepts two electrons to become Cl- ion.

CIO −(aq) + 2e-⟶---> Cl −(aq)

CIO −(aq)⟶+ 2H+ (aq) + 2e- ---> Cl −(aq) + H₂O

Express each of the following answers in the IUPAC format. Do not include any capitals or spaces in your name. Separate multiple substituent numbers using a comma. Use a hyphen between numbers and names. (ex: 1,2-dichloro-3-methylcyclopentane). Part A Spell out the full name of the molecule. Part B Spell out the full name of the molecule. Part C Spell out the full name of the molecule. Part D Spell out the full name of the molecule.

Answers

The full question is shown in the image attached

Answer:

See explanation

Explanation:

In naming an alkane, the first thing we do is to obtain the parent chain by counting the number of carbon atoms in the chain.

When we obtain that, then we identify the substituents and number them in such a way that they have the lowest numbers. The compounds shown have the following names according to the order in which the structures appear in the image attached;

1. 2-methyl propane

2. 2,4-dimethyl heptane

3. 2,2,3,3-tetramethyl butane

4. 5-ethyl-2,4-dimethyl octane

I will mark brainliest
What kind of weather forms with an occluded front?

Answers

Answer:Occluded fronts usually form around areas of low atmospheric pressure. There is often precipitation along an occluded front from cumulonimbus or nimbostratus clouds. Wind changes direction as the front passes and the temperature either warms or cools.

Explanation:

Occluded fronts usually form when the area is of low atmospheric pressure.

The diagram shows that the boiling point of water is 100°C At a pressure of one atm.

How could you reduce the boiling point of water in this system?


A. Increase the size of the flame

B. Decrease the volume of the water

C. Decrease the pressure to 0 atm.

D. Increase the pressure to 2 atm

Answers

Answer:

I think the answer will be number A

The boiling point of a substance is constant and for water it is 100 degree celsius. However by reducing the surrounding pressure the boiling point can be reduced.

What is boiling point ?

Boiling point of a substances is the temperature at which the vapor pressure of the gas phase above the liquid equals to the atmospheric pressure where, the liquid converts to the vapor state.

Boiling point depends on the bond type, molar mass, temperature and pressure. As the and pressure increases, boiling point increases. Similarly with an increasing mass and more strength intermolecular force results in greater boiling point.

As the atmospheric pressure decreases, the temperature needed to equalise the vapor pressure of the gas phase over the liquid also decreases. Hence, boiling point decreases. Therefore, option C is correct.

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