If a light ray travels from air into glass that has a refractive index of 1.6, and the incident light ray makes an angle with the normal that's 31 degrees, what angle will the transmitted ray make with the normal? Enter your answer using two significant figures. Enter the number only, not the units, which should be degrees. 19 Question 2 Incident Ray Normal Medium 1 Medium 2 Refracted Ray 1 pts What angle will the reflected light ray make relative to the normal, in the previous problem? Enter your answer using two significant figures. Enter the number only, not the units, which should be degrees.​

Answers

Answer 1

Using Snell's law, we can find the angle the transmitted ray will make with the normal:

[tex]n1sin(theta1) = n2sin(theta2)[/tex]

Where [tex]n1[/tex] is the refractive index of the incident medium (air), [tex]theta1[/tex] is the angle the incident ray makes with the normal, [tex]n2[/tex] is the refractive index of the second medium (glass), and [tex]theta2[/tex] is the angle the transmitted ray makes with the normal.

Plugging in the given values, we get:

[tex](1.00)(sin(31)) = (1.6)(sin(theta2))[/tex]

Solving for [tex]theta2[/tex], we get:

[tex]theta2 = sin^(-1)((1.00)*(sin(31))/(1.6)) = 19 degrees (rounded to two significant figures)[/tex]

To find the angle the reflected ray makes with the normal, we can use the fact that the angle of incidence is equal to the angle of reflection:

[tex]theta1 = theta_r[/tex]

where [tex]theta_r[/tex] is the angle the reflected ray makes with the normal.

Plugging in the given value of [tex]theta1[/tex], we get:

[tex]theta_r[/tex] = 31 degrees

Related Questions

a pendulum is swinging upward and is halfway toward its highest position, as shown, when the string breaks. which of the paths shown best represents the one that the ball would take after the string breaks?

Answers

The option A is  best representation of the path that the ball would take after the string breaks.

When the string of a pendulum breaks, the ball's path will follow the laws of motion, specifically the law of conservation of energy. As the ball was halfway to its highest position, it had a certain amount of potential energy.

When the string broke, this potential energy would convert to kinetic energy, causing the ball to move in a straight line tangent to the point where the string broke.

Therefore, the path that the ball would take after the string breaks would be a straight line away from the pivot point of the pendulum, as shown in option A. The other paths shown do not follow the laws of motion and do not account for the conservation of energy. Option (A) is the correct answer.

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Note the full question is

A pendulum is swinging upward and is halfway toward its highest position, as shown, when the string breaks. which of the paths shown best represents the one that the ball would take after the string breaks?

A) A

B) B

C) C

D) D

E) E

a star less luminous than our sun will have a habitable zone that is

Answers

Stars that are more luminous than the Sun will have their habitable zone away further away from the star that is the case in in our solar system.

Potable water is ____.
A. also known as industrial wastewater
B. also known as irrigation water
C. also known as sewage
D. also known as groundwater
E. fit for drinking

Answers

Potable water is fit for drinking. Option E

What is portable water?

Potable water is water that is safe for human consumption and considered fit for drinking. It is free from harmful bacteria, viruses, chemicals, and other contaminants that can cause health problems.

Potable water can come from different sources such as groundwater, surface water, or treated wastewater, and it is typically treated and disinfected to ensure its safety before being distributed to consumers.

Portable water isn't known as industrial wastewater, irrigation water, groundwater and sewage.

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Which word best describes something that works in the same way as a radar

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The word that best describes something that works in the same way as a radar is "sonar".

Sonar is an acronym for "sound navigation and ranging," and it is a technology that uses sound waves to detect and locate objects underwater. Sonar works by emitting a sound wave or pulse and then measuring the time it takes for the sound to bounce back from an object and return to the source. This information is then used to calculate the distance to the object and its location. Like radar, sonar is used in a variety of applications, including military, scientific, and commercial.

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when does a star become a main-sequence star? when the rate of hydrogen fusion within the star's core is high enough to maintain gravitational equilibrium when hydrogen fusion is occurring throughout a star's interior when the protostar assembles from a molecular cloud when a star becomes luminous enough to emit thermal radiation the instant when hydrogen fusion first begins in the star's core

Answers

Answer: hope it helps

Explanation:

A protostar becomes a main sequence star when its core temperature exceeds 10 million K. This is the temperature needed for hydrogen fusion to operate efficiently.

15) monochromatic coherent light shines through a pair of slits. if the distance between these slits is decreased, which of the following statements are true of the resulting interference pattern? (there is more than one correct choice.) a) the distance between the maxima stays the same. b) the distance between the maxima decreases. c) the distance between the minima stays the same. d) the distance between the minima increases. e) the distance between the maxima increases.

Answers

Two of the correct statements regarding this are:
b) the distance between the maxima decreases
d) the distance between the minima increases

When monochromatic coherent light shines through a pair of slits, an interference pattern is created. This pattern is dependent on the distance between the slits. If the distance between the slits is decreased, the resulting interference pattern will be affected.

When the distance between the slits is decreased, the interference pattern becomes wider, and the distance between the maxima decreases. The distance between the minima, on the other hand, increases.

This is because the interference pattern is created by the interaction of waves, and when the distance between the slits is decreased, the waves interfere with each other differently.

This causes the pattern to shift and change. Therefore, the resulting interference pattern is affected by the distance between the slits.

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. for schrodinger's equation of the h2 molecule, the kinetic energy has contributions from a. electrons only b. nuclei only c. both electrons and nuclei d. only one electron and one nucleus

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The kinetic energy in Schrödinger's equation for the H2 molecule includes contributions from both electrons and nuclei. Thus the correct option is C.

The kinetic energy term in Schrödinger's equation for the H2 molecule refers to the energy involved in the motion of the particles. The H2 molecule comprises two hydrogen nuclei and two electrons, therefore the electrons and the nuclei both contribute to the kinetic energy.

The nuclei contribute to the kinetic energy by their mobility, whereas the electrons do so through their wave-like behaviour. The H2 molecule's kinetic energy term in Schrödinger's equation includes contributions from both electrons and nuclei, making option C the right response.

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The kinetic energy in Schrödinger's equation for the H2 molecule includes contributions from both electrons and nuclei. Thus the correct option is C

explanation - For Schrödinger's equation of the H2 molecule, the kinetic energy has contributions from both electrons and nuclei. This is because the kinetic energy term in the equation accounts for the motion of all particles in the system, which in this case includes both the electrons and nuclei of the H2 molecule. Therefore, options a, b, and d are incorrect.

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at the sea level the plane can takeoff at the speed of 150 mi/hr. what is the required takeoff speed at albuquerque

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The indicated airspeed (IAS) of the aircraft should be raised by roughly 2% for every 1,000 feet above sea level, according to a pilot's rule of thumb.

In order to generate enough lift during takeoff from a sea level airport, an aeroplane must attain a specific speed. Less dense air can be found at higher altitudes, such at Albuquerque, where the airport is situated at an altitude of 5,355 feet above sea level.

This necessitates a faster takeoff speed. Generally speaking, the plane's takeoff speed must rise by around 2% for every 1,000 feet of height. Under normal conditions and with conventional aeroplane characteristics, the estimated necessary takeoff speed at Albuquerque would be roughly 166 miles per hour.

The indicated airspeed (IAS) of the aircraft should be raised by roughly 2% for every 1,000 feet above sea level, according to a pilot's rule of thumb.

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higher takeoff speed to generate enough lift to take of

The required takeoff speed at Albuquerque would depend on several factors such as altitude, temperature, and runway length. If Albuquerque is at a higher altitude than sea level, the air is less dense and the plane would require a higher takeoff speed to generate enough lift to take off.

Additionally, if the temperature is higher, the air is less dense and the plane would also require a higher takeoff speed. The length of the runway at Albuquerque would also play a role in determining the required takeoff speed. Without more specific information, it is difficult to provide an exact answer to your question.

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what is the quantum number of an electron confined in a 5.4- nm -long one-dimensional box if the electron's de broglie wavelength is 1.8 nm ?

Answers

The calculation produced a non-integer number using the supplied inputs. The values provided may include approximations or rounding mistakes as a result.

How can the de-Broglie wavelength of an electron at a certain speed be determined?

The following is a definition of the deBroglie wavelength: Lambda is the Greek letter for wavelength, while h, Planck's constant, m, and v are the particle's mass and velocity.

The following equation describes the energy levels of an electron contained in a one-dimensional box:

E = (n² * h²) / (8 * m * L²)

An electron's de Broglie wavelength is determined by:   λ = h / p

The following equation can be used to link an electron's energy and momentum:  E = p² / (2 * m)

In the equation above, we can solve for p by inserting the expression for and obtain:  p = h / λ

Using this expression as p's replacement in the energy equation, we obtain:  E = (n² * h² * λ²) / (8 * m)

The box's length, L, and de Broglie's wavelength,, are both given as 5.4 nm and 1.8 nm, respectively. Planck's constant, h = 6.626 x 10⁻³⁴ J*s, and the mass of an electron, m = 9.1094 x 10⁻³¹ kg, respectively.

In the following equation, we can solve for n by substituting these numbers. The result is:

n = sqrt(8 * m * E) / (h * λ)

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standing waves result from the superposition of two waves that have group of answer choices the same amplitude, frequency, and direction of propagation. the same amplitude and frequency and opposite directions of propagation. the same amplitude, slightly different frequencies, and the same direction of propagation. the same amplitude, slghtly different frequencies, and opposite directions of propagation.

Answers

The correct option is B, Standing waves result from the superposition of two waves that have the same amplitude and frequency and opposite directions of propagation .

Amplitude is a fundamental concept in physics and refers to the maximum displacement or distance of an oscillating system from its equilibrium position. It is commonly used to describe the magnitude of a wave or vibration, and is measured in units such as meters or volts.

In the context of waves, amplitude represents the maximum height or depth of the wave crest or trough, and is often used to describe the intensity or strength of the wave. In sound waves, amplitude is directly related to the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds. In electrical engineering, amplitude refers to the maximum voltage or current of an alternating current (AC) waveform.

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Complete Question:-

Standing waves result from the superposition of two waves that have

a. the same amplitude, frequency, and the direction of propagation.

b. the same amplitude and frequency and opposite directions of propagation .

c. the same amplitude, slightly different frequencies, and the same direction of propagation.

d.the same amplitude, slightly different frequencies, and opposition directions of propagation

after a sci a patient may experience all of the following except: a. spasticity b. resting tremor c. autonomic dysreflexia d. orthostatic hypotension

Answers

The right response is resting tremor (option b). A patient may have spasticity, autonomic dysreflexia, and orthostatic hypotension following a spinal cord injury (SCI). SCI is not often linked to resting tremor.

SCI can interfere with the body's ability to communicate with the brain, leading to a variety of physical symptoms. Spasticity, which manifests as stiffness, muscle spasms, and increased muscle tone, is a frequent consequence. Patients with SCI at or above the T6 level may develop autonomic dysreflexia, a potentially fatal illness that is characterised by an abrupt rise in blood pressure. When someone stands up, their blood pressure drops, causing lightheadedness and dizziness. This condition is known as orthostatic hypotension.

While essential tremor, Parkinson's disease, and other neurological illnesses are frequently linked to resting tremor, SCI is not typically one of them.

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The right response is resting tremor (option b). A patient may have spasticity, autonomic dysreflexia, and orthostatic hypotension following a spinal cord injury (SCI). SCI is not often linked to resting tremor.

SCI can interfere with the body's ability to communicate with the brain, leading to a variety of physical symptoms. Spasticity, which manifests as stiffness, muscle spasms, and increased muscle tone, is a frequent consequence. Patients with SCI at or above the T6 level may develop autonomic dysreflexia, a potentially fatal illness that is characterised by an abrupt rise in blood pressure. When someone stands up, their blood pressure drops, causing lightheadedness and dizziness. This condition is known as orthostatic hypotension.

While essential tremor, Parkinson's disease, and other neurological illnesses are frequently linked to resting tremor, SCI is not typically one of them.

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an oscillator creates periodic waves on a stretched string. if the period of the oscillator doubles, what happens to the wavelength and wave speed

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If the period of the oscillator doubles, the wavelength of the waves on the string will also double and the wave speed does not change.

When an oscillator creates periodic waves on a stretched string and the period of the oscillator doubles, the following happens to the wavelength and wave speed:

1. Wavelength (λ): The relationship between the period (T), frequency (f), and wavelength (λ) is given by the equation:

T = 1/f

Since the period doubles (T becomes 2T), the frequency will halve (f becomes f/2) to maintain the relationship. The equation for the wave speed (v) is:

v = fλ

As the frequency is halved, to maintain the same wave speed, the wavelength must also double (λ becomes 2λ). So, the wavelength will increase.

2. Wave speed (v): In this situation, the wave speed remains constant. As mentioned above, when the frequency is halved, the wavelength doubles, which means the product of the frequency and wavelength (v = fλ) remains the same. Therefore, the wave speed does not change.

In summary, when the period of the oscillator doubles, the wavelength will double, and the wave speed will remain constant.

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catching a wave, a 73.2-kg surfer starts with a speed of 1.44 m/s, drops through a height of 1.84 m, and ends with a speed of 8.89 m/s. how much nonconservative work was done on the surfer?

Answers

The nonconservative work done on the surfer is 2845.5 J.

We can use the work-energy theorem to solve this problem. The work-energy theorem states that the net work done on an object is equal to its change in kinetic energy. In this case, we can calculate the initial and final kinetic energies of the surfer and find the difference, which will give us the net work done.

The initial kinetic energy of the surfer is:

[tex]K_i = (1/2) * m * v_i^2[/tex]

[tex]K_i = (1/2) * 73.2 kg * (1.44 m/s)^2[/tex]

K_i = 75.7 J

The final kinetic energy of the surfer is:

[tex]K_f = (1/2) * m * v_f^2[/tex]

[tex]K_f = (1/2) * 73.2 kg * (8.89 m/s)^2[/tex]

K_f = 2921.2 J

The change in kinetic energy is:

ΔK = K_f - K_i

ΔK = 2921.2 J - 75.7 J

ΔK = 2845.5 J

According to the work-energy theorem, this change in kinetic energy must be equal to the net work done on the surfer. Therefore, the nonconservative work done on the surfer is:

W_nc = ΔK

W_nc = 2845.5 J

So, the nonconservative work done on the surfer is 2845.5 J.

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a satellite circles a spherical planet of unknown mass in a circular orbit of radius 2.5×107 m . the magnitude of the gravitational force exerted on the satellite by the planet is 110 n .

Answers

Since we don't know the mass of the satellite or its velocity, we can't solve for the mass of the planet with the given information alone. We would need at least one more piece of information to do so.

Answer -  Based on the given information, we can use the equation for gravitational force:

F = (G * m1 * m2) / r^2
where F is the force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers.
Since we don't know the mass of the planet, we can't directly solve for it. However, we can use the fact that the satellite is in a circular orbit, which means that the gravitational force is equal to the centripetal force:
F = (m * v^2) / r
where m is the mass of the satellite and v is its velocity.
We can solve for m by rearranging the equation:
m = (F * r) / v^2

Now we can use this mass value and plug it into the original equation for gravitational force, along with the given values for r and F, to solve for the mass of the planet:
110 N = (G * m * m_planet) / (2.5x10^7 m)^2
m_planet = (110 N * (2.5x10^7 m)^2) / (G * m)

where G is a constant equal to 6.67x10^-11 N*m^2/kg^2.
Unfortunately, since we don't know the mass of the satellite or its velocity, we can't solve for the mass of the planet with the given information alone. We would need at least one more piece of information to do so.

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what are reasons that a promontory will be more vulnerable to wave erosion than a bay? multiple select question. waves bend around a promontory and strike it from both sides. larger waves enter into a bay than strike a promontory. a promontory will receive more wave action than a bay. powerful waves focus most of their energy at a promontory.

Answers

The reasons that a promontory will be more vulnerable to wave erosion than a bay;- Waves bend around a promontory and strike it from both sides,- Powerful waves focus most of their energy at a promontory and - A promontory will receive more wave action than a bay.

A promontory is more vulnerable to wave erosion than a bay due to the following reasons:

1. Waves bend around a promontory and strike it from both sides: This phenomenon, called wave refraction, concentrates the wave energy on the promontory, making it more prone to erosion.

2. A promontory will receive more wave action than a bay: Bays are generally more sheltered and have a lower exposure to waves, whereas promontories are exposed to the full force of waves, leading to more erosion.

3. Powerful waves focus most of their energy at a promontory: Due to the shape of the coastline, waves tend to focus their energy on the headlands, like promontories, which makes them more vulnerable to erosion compared to bays.

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what is the typical voltage drop (in volts) across the collector and emitter (vce) of a bjt when in saturation?

Answers

The VCE voltage drop in saturation for a typical BJT can be assumed to be between 0.1V and 0.3V.

How VCE voltage drop in saturation for a typical BJT?

The voltage drop across the collector and emitter (VCE) of a bipolar junction transistor (BJT) when it is in saturation depends on several factors such as the type of BJT, the collector current, and the biasing conditions.

However, as a general rule of thumb, the VCE voltage drop in saturation for a typical BJT can be assumed to be between 0.1V and 0.3V, depending on the specific characteristics of the transistor. This value may vary based on the operating conditions and the specific transistor used.

It's worth noting that the VCE voltage drop in saturation is typically lower than the voltage drop in the active region, where the BJT behaves as a current amplifier. In the active region, the VCE voltage drop can range from a few tenths of a volt up to several volts, depending on the transistor's characteristics and operating conditions.

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is a mirror magnetic or nonmagnetic​

Answers

Mirrors are magnetic objects. The form of a concentrated static magnetic field, or magnetic mirror, causes oncoming charged particles to be thrown back along their route of approaches. Mirrors can reflect the good vibes coming from attractive things
Good luck

the threshold frequency (minimum frequency) of aluminum for the photoelectric effect is in the ultraviolet range. what will happen if infrared light shines on the aluminum surface?

Answers

Any electromagnetic radiation with a frequency lower than 9.84 x 10¹⁴ Hz (infrared, microwave, radio waves) will not cause the photoelectric effect in aluminum.

If infrared light shines on the aluminum surface, no electrons will be emitted via the photoelectric effect because the frequency of infrared light is lower than the threshold frequency of aluminum. The photoelectric effect occurs when a photon with enough energy (frequency) is absorbed by an electron in a metal, causing the electron to be emitted from the metal.

The minimum frequency or threshold frequency ([tex]f_{t}[/tex]) of a metal can be calculated using the equation:

[tex]f_{t}[/tex] = Φ ÷ h

where Φ is the work function of the metal (the minimum energy required to remove an electron from the metal) and h is Planck's constant. For aluminum, Φ = 4.08 eV.

Converting Φ to joules and using h = 6.626 x 10⁻³⁴ J s, we get:

Φ = 4.08 eV x 1.6 x 10⁻¹⁹ J/eV

Φ = 6.528 x 10⁻¹⁹ J

[tex]f_{t}[/tex] = 6.528 x 10⁻¹⁹ J ÷ 6.626 x 10⁻³⁴ J s

≈ 9.84 x 10¹⁴ Hz

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019 (part 1 of 2) 10.0 points
A Carnot engine has a power output of
197 kW. The engine operates between two
reservoirs at 20◦C and 425◦C.
How much thermal energy is absorbed each
hour?
Answer in units of J.
020 (part 2 of 2) 10.0 points
How much thermal energy is lost per hour?
Answer in units of J.

Answers

Thermal energy is absorbed each hour is  13.53 x 10¹² J  and thermal energy lost per hour  is  7.092 x 10¹² J.

What is the Carnot engine's operating principle?

a technique of isothermal gas expansion that is reversible. In this process, the ideal gas in the system receives  amount heat from a heat source at a high temperature Thigh, expands and does work on surroundings. a technique of adiabatic gas expansion that is reversible. The system is thermally insulated throughout this process.

Temp_cold = 20°C + 273.15 = 293.15 K

Temp_hot = 425°C + 273.15 = 698.15 K

efficiency = 1 - (Temp_cold / Temp_hot)

                     = (698.15 K * 293.15 K) / (698.15 K)² - (293.15 K)²

efficiency = 0.524 or 52.4%

thermal energy absorbed/ hour = power output / efficiency

= 197 kW / 0.524

= 375.95 MJ/h  x 3.6 x 10⁶ J/kWh = 13.53 x 10¹² J

thermal energy is lost per hour

W = power output x time = 197 kW x 1 h = 197 kWh

W = 197 kWh x 3.6 x 10⁶ J/kWh = 7.092 x 10¹²1J

Since the engine is running in a cycle, the system's internal energy is equal to zero, hence U = 0.

Q = ΔU + W

hence, thermal energy lost per hour = Q = W = 7.092 x 10^11 J

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what does the technique of interferometry allow?what does the technique of interferometry allow?it allows two or more telescopes to obtain a total light-collecting area much larger than the total light-collecting area of the individual telescopes.it allows us to determine the chemical composition of stars.it allows two or more telescopes to obtain the angular resolution of a single telescope much larger than any of the individual telescopes.it allows the same telescope to make images with both radio waves and visible light.it allows astronomers to make astronomical observations without interference from light pollution.

Answers

The technique of interferometry allows two or more telescopes to obtain the angular resolution of a single telescope much larger than any of the individual telescopes.

This is achieved by combining the signals received by the telescopes to create a single image with a higher resolution. Interferometry is especially useful for studying objects with small angular sizes, such as stars and planets.

Additionally, interferometry allows astronomers to make astronomical observations without interference from light pollution, as it can separate the signals from the object being observed from the background light.

However, interferometry does not directly determine the chemical composition of stars, although it can provide information about their temperature and other physical properties.

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a circuit breaker is rated for a current of 15 a rms at a voltage of 240 v rms. (a) what is the largest value of imax that the breaker can carry?

Answers

The largest value of I_max that the breaker can carry is approximately 21.21 A.

Given a circuit breaker rated for 15 A RMS at 240 V RMS, we want to find the largest value of Imax (maximum current) that the breaker can carry. To do this, we'll use the following formula:

I_max = √2 * I_RMS

Where I_RMS is the rated current in RMS, which is 15 A in this case.

Substitute the value of I_RMS into the formula:
Imax = √2 * 15 A

Calculate the value of Imax:
Imax ≈ 21.21 A

Therefore approximately 21.21 A is the largest value of Imax that the breaker can carry.

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The majority of Venus's surface is:
A. volcanic plains with flowing lava.
B large, flat mesas with tiny valleys.
C. thick, soupy clouds of hydrogen.
D. frozen dunes of dust and sand.​

Answers

Answer:

C.

Explanation:

When Venus surface get bit cold when weather hits the planet gets soupy clouds and etc.

how far from the nut of the guitar must a fret (and your finger) be placed on this string to play g (392 hz )?

Answers

To play G note (392 Hz) on a guitar string, place the fret and your finger at a distance of approximately 40.4 cm (or 16 inches) from the nut of the guitar.

The distance that the fret and your finger must be placed from the nut of the guitar is determined by the length of the string that is allowed to vibrate when the string is plucked. The length of the vibrating string determines the frequency of the sound produced by the guitar string.

The distance from the nut of the guitar to the fret that must be placed to play a G note with a frequency of 392 Hz can be calculated using the formula:

[tex]L = (v / 2f) * (n^2 - 1)[/tex]

where L is the length of the string from the nut to the fret, v is the velocity of the wave (which is dependent on the tension and mass per unit length of the string), f is the frequency of the note, and n is the fret number (with n=1 corresponding to the distance from the nut to the first fret).

For a standard guitar tuning and using typical values for the velocity of the wave and string tension, the distance from the nut to the third fret would be approximately 40.4 cm to play a G note with a frequency of 392 Hz.

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help me please oml 2 one

Answers

Color: Both the bromine gas and steak have a brownish color.

What is bromine gas?

Bromine gas is a reddish-brown, nonflammable, and highly toxic gas with a very strong, unpleasant odor. It is composed of two heavy, diatomic, halogen molecules, Br2, and is the only nonmetal element that exists as a liquid at room temperature. Bromine gas is denser than air and is soluble in water and organic solvents.

Texture: The bromine gas is a gas and therefore has no texture, while the steak is solid and has a firm texture.
Temperature: The bromine gas is a gas and therefore has a lower temperature than the steak, which is at room temperature.
Bromine Gas and Juice:
Color: The bromine gas is brownish and the juice is a yellowish or orange color.
Texture: The bromine gas is a gas and therefore has no texture, while the juice is a liquid and has a smooth texture.
Temperature: The bromine gas is a gas and therefore has a lower temperature than the juice, which is at room temperature.

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calculate the period of a horizontal mass-on-a-spring system where the stiffness of the spring is 500 n/m and the mass of the system is 25.7 kg.

Answers

The period of the horizontal mass-on-a-spring system with a stiffness of 500 N/m and a mass of 25.7 kg is approximately 1.424 seconds.

We'll use the following terms in our calculation: stiffness of the spring (k), mass of the system (m), and period (T).

The formula to calculate the period of a mass-on-a-spring system is:

T = 2π √(m/k)

where:
T = period (in seconds)
m = mass of the system (25.7 kg)
k = stiffness of the spring (500 N/m)

Now, we'll plug in the values:

T = 2π √(25.7 kg / 500 N/m)

To calculate the square root:

T = 2π √(0.0514)

T = 2π × 0.2266

Finally, multiply by 2π:

T ≈ 1.424 seconds

So, the period of the horizontal mass-on-a-spring system is approximately 1.424 seconds.

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water is drawn from a well in a bucket tied to the end of a rope whose other end wraps around a cylinder of mass 50 kg and diameter 25 cm. as you turn this cylinder with a crank, the rope raises the bucket. if the mass of a bucket of water is 20 kg, what torque must you apply to the crank to raise the bucket of water at a constant speed?

Answers

m_c (mass of cylinder)=50 kg

d=25 cm so r=12.5 cm = 0.125 m m_b

(mass of bucket)=20 kg

So using the equations: RT = � = I � RT= I � (m_b)g-T= (m_b)aR And from what I understand, this is the same as the tangential acceleration? (m_b)g-T=(m_b) � r = F T= ( i � ) / r (m_b)g -(( i � ) / r ) = m � r � ( ((m_b)r) + (I /R ) ) = (m_b)g Leaving us with the final : � = ((m_b)g)/(((m_b)r) + (I /r)) Using this equation, I found I = 0.390625 and the final answer would be 35 rad/s^2 Sorry for such a long post--this is my first time on the website and I read the rules so hopefully I've done everything correctly! Thank you all!

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A 0. 300 kg
toy car moving with a speed of 0. 820 m/s
collides with a wall. The figure shows the force exerted on the car by the wall over the course of the collision

Answers

The negative sign indicates that the force is exerted in the opposite direction to the motion of the car. This force is applied over a short time interval and is relatively large, causing the car to experience a significant deceleration during the collision.

During the collision, the toy car experiences a change in momentum. Since momentum is conserved in the absence of external forces, the momentum of the car before the collision must be equal in magnitude and opposite in direction to the momentum after the collision.

The initial momentum of the car is given by:

p = mv = 0.3 kg * 0.82 m/s = 0.246 kgm/s

After the collision, the car comes to a stop, so its final momentum is zero. Therefore, the change in momentum is:

Δp = p_final - p_initial = -0.246 kg*m/s

The force exerted by the wall on the car during the collision can be calculated using the impulse-momentum theorem

J = Δp = FΔt

where J is the impulse, Δt is the time interval over which the force is applied, and F is the force

From the figure, we can see that the time interval for the collision is approximately 0.020 s. Therefore, the force exerted by the wall on the car is: F = Δp / Δt = -0.246 kg*m/s / 0.020 s = -12.3 N

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Please help I need to answer fast the fate of my graduation depends on it.

Answers

First, we need to find the total mass of the system by adding the masses of the two objects: m_total = m1   m2 = 50.0 kg   75.0 kg = 125.0 kg  Next, we can plug in the given force and mass values into the equation: F = ma 40.0 N = 125.0 kg * a  Solving for a: a = 40.0 N

125.0 kg * a

Solving for a:

a = 40.0 N / 125.0 kg

a = 0.32 m/s^2

Therefore, the acceleration of the system is 0.32 m/s^2.

at 2.1 km from the transmitter, the peak electric field of a radio wave is 350 mv/m . what is the peak electric field 10 km from the transmitter?

Answers

The peak electric field 10 km from the transmitter is approximately 15.435 mV/m.

To find the peak electric field 10 km from the transmitter, we can use the inverse square law.

This law states that the intensity of a wave (such as the electric field in this case) is inversely proportional to the square of the distance from the source.

Here's a step-by-step explanation:

1. Note the initial distance (d1) and electric field (E1):

d1 = 2.1 km, E1 = 350 mV/m.


2. Convert d1 to meters:

d1 = 2100 m.


3. Note the final distance (d2):

d2 = 10 km.


4. Convert d2 to meters:

d2 = 10,000 m.


5. Use the inverse square law formula:

E2 = E1 * (d1²) / (d2²).


6. Plug in the values:

E2 = 350 * (2100²) / (10,000²).


7. Calculate E2:

E2 ≈ 15.435 mV/m.

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4. how does the intensity of a linearly polarized electromagnetic wave relate to its electric field?

Answers

The intensity of a linearly polarized electromagnetic wave is directly proportional to the square of its electric field amplitude.

The electric field of a linearly polarized electromagnetic wave can be represented by a sine or cosine function, where the amplitude of the wave represents the maximum value of the electric field.

The intensity of the wave is proportional to the average power per unit area that is carried by the wave.

Mathematically, the intensity (I) of an electromagnetic wave is given by the formula:

I = (1/2)εcE0^2

where ε is the electric constant (approximately equal to 8.85 x 10^-12 F/m), c is the speed of light in a vacuum (approximately equal to 3.00 x 10^8 m/s), and E0 is the amplitude of the electric field.

From this formula, it is clear that the intensity of the wave is proportional to the square of the electric field amplitude.

Therefore, if the electric field amplitude of a linearly polarized electromagnetic wave is increased by a factor of 2, the intensity of the wave will increase by a factor of 4 (i.e., 2 squared).

Similarly, if the electric field amplitude is decreased by a factor of 2, the intensity of the wave will decrease by a factor of 4.

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