if mixture didn't exist how would life be different​

PLEASEEE QUICKKKK

Answer:

this not easy

Explanation:

come on

1.83 × 10⁻⁷ mol Au

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

3.60 × 10⁻⁵ g Au (Gold)

Step 2: Identify Conversions

Molar Mass of Au - 196.97 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au

Answer:

It would cause scattering of light and absorbance measurement is going to be reported as too large

Explanation:

The curvette was not inserted correctly into the spectrometer. The effect that this would have on measured absorbance is that it would cause scattering of light.

Failing to line the curvette correctly would cause light to scatter, the light reaching the photodetector would be less. This less light would then be interpreted as more light being absorbed. This would end up making the absorbance value to be read as too large.

The given question is incomplete. The complete question is:

Suppose a current of 0.920 A is passed through an electroplating cell with an aqueous solution of agno3 in the cathode compartment for 47.0 seconds. Calculate the mass of pure silver deposited on a metal object made into the cathode of the cell.

Answer:   0.0484 g

Explanation:

[tex]Q=I\times t[/tex]

where Q= quantity of electricity in coloumbs

I = current in amperes = 0.920 A

t= time in seconds = 47.0 sec

[tex]Q=0.920A\times 47.0s=43.24C[/tex]

[tex]AgNO_3\rightarrow Ag^++NO_3^-[/tex]

[tex]Ag^++e^-\rightarrow Ag[/tex]

96500 Coloumb of electricity electrolyzes 1 mole of Ag

43.24 C of electricity deposits =[tex]\frac{1}{96500}\times 43.24=0.00045moles[/tex] of Ag

[tex]\text{ mass of Ag}={\text{no of moles}\times {\text{Molar mass}}=0.00045mol\times 108g=0.0484g[/tex]

Thus the mass of pure silver deposited on a metal object made into the cathode of the cell is 0.0484 g

Answer:

Mineral deficiencies can lead to a variety of health problems, such as weak bones, fatigue, or a decreased immune system.

Explanation:

There are five main categories of mineral deficiency: calcium, iron, magnesium, potassium, and zinc.

One major cause of mineral deficiency is simply not getting enough essential minerals from food or supplements.

Answer:

it can lead to a variety of health problems, such as weak bones, or a decreased immune system.

Explanation:

Answer:

0.0584 M

Explanation:

From the question given above, the following data were obtained:

Mass of CaCl₂ = 0.808 g

Volume of water = 250 mL

Concentration of chloride =?

Next, we shall determine the number of mole in 0.808 g of CaCl₂. This can be obtained as follow:

Mass of CaCl₂ = 0.808 g

Molar mass of CaCl₂ = 40 + (35.5 × 2)

= 40 + 71

= 111 g/mol

Mole of CaCl₂ =?

Mole = mass / Molar mass

Mole of CaCl₂ = 0.808 / 111

Mole of CaCl₂ = 0.0073 mole

Next, we shall convert 250 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

250 mL = 250 mL × 1 L / 1000 mL

250 mL = 0.25 L

Next, we shall determine the molarity of CaCl₂. This can be obtained as follow:

Mole of CaCl₂ = 0.0073 mole

Volume of water = 0.25 L

Molarity of CaCl₂ =?

Molarity = mole /Volume

Molarity of CaCl₂ = 0.0073 / 0.25

Molarity of CaCl₂ = 0.0292 M

Finally, we shall determine the concentration of the chloride as illustrated below:

CaCl₂ <=> Ca²⁺ + 2Cl¯

From the equation above,

1 mole of CaCl₂ produced 2 mole of Cl¯.

Therefore, 0.0292 M CaCl₂ will produce = 0.0292 × 2 = 0.0584 M Cl¯.

Thus, the concentration of the chloride ion (Cl¯) in the solution is 0.0584 M

Answer:

2KCl + F₂   →     2KF + Cl₂

Explanation:

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by French chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

For example:

2KCl + F₂   →     2KF + Cl₂

In this equation mass of reactant and product is equal. There are 2 potassium 2 chlorine and fluorine atoms on both side of equation it means mass remain conserved.

All other options are incorrect because mass is not conserved.

Answer:

The protic solvents are (CH3)2CHOH, NH3, and HCONH2

The aprotic solvent are CH3NO2, CH2Cl2, and N(CH3)3

Explanation:

A protic solvent is a solvent that has a hydrogen atom bound to an oxygen (O), a nitrogen (N), or fluoride (F). Generally, any solvent that contains a labile H⁺ is called a protic solvent.

a. (CH3)2CHOH

(CH3)2CHOH is a protic solvent because one of the hydrogens is bound to oxygen (O)

b. CH3NO2

CH3NO2 is an aprotic (i.e not a protic solvent) solvent because all the hydrogens are bound to carbon.

c. CH2Cl2

CH2Cl2 is an aprotic solvent because all the hydrogens are bound to carbon.

d. NH3 is a protic solvent because all the hydrogens are bound to Nitrogen (N)

e. N(CH3)3 is an aprotic solvent because all the hydrogens are bound to carbon

f. HCONH2 is a protic solvent because two of the hydrogens are bound to Nitrogen (N)

Answer:

11460 years

Explanation:

0.693/t1/2 = 2.303/t log (No/N)

t1/2 = half life of the carbon

t = age of the fossil

No= amount of radioactive material originally present

N= amount of radioactive material present at time=t

No= mass of carbon + nitrogen = 5g

0.693/5730 = 2.303/t log (5/1.25)

1.21 ×10^-4 = 1.3866/t

t= 1.3866/1.21 ×10^-4

t= 11460 years

Answer:

then it only gotta be 2 other options .

Explanation:

Answer:

0.67 g

Explanation:

We know that 1 mole of an element is 6.02 x 10^(23) atoms

Now, arsenic has 5.49 × 10²¹ atoms

Thus;

Number of moles of arsenic = 5.49 × 10²¹ × 1/6.02 x 10^(23) = 9 × 10^(-3) moles

We are told that;

one mole of arsenic = 74.92 g.

Thus, 9 × 10^(-3) moles = 9 × 10^(-3) × 74.92/1 = 0.67428 g ≈ 0.67 g

Answer:

4

Explanation:

the actual change in phase is 4 on the diagram

Answer:

Explanation:

C

[tex]4.9 \times 10^{23}[/tex]  are present in 18.4L of argon (Ar).

To calculate the amount of particles present in a given amount of volume, it is necessary to have knowledge of the molar volume:

                                          [tex]1 mol = 22.4L[/tex]

Thus, in 22.4L there is 1 mol of an element, remembering that:

                                   [tex]1 mol = 6\times10^{23}[/tex] particles

In this way, it is enough to relate the value of the molar volume given with the value requested by the question:

                                     [tex]\frac{6\times10^{23}particles}{xparticles} = \frac{22.4L}{18.4L}[/tex]

                                    [tex]x = 4.9 \times 10^{23}[/tex] particles

 So, [tex]4.9 \times 10^{23}[/tex] are present in 18.4L of argon (Ar).

Learn more about mole calculation in: brainly.com/question/15209553

Answer:a

Explanation:

Answer:

Answervis A.

Explanation:

Because,so that other scientists can validate the results.

I hope it's helpful!

Answer:

all of the above

Explanation:

Answer:

natural selection

Explanation:

natural selection

Answer:

ptic fiber communication and satellite communication are the leading technologies which are revolutionizing the world of telecommunications. Both technologies have their advantages and limitations which make them suitable for certain type of applications. This article will provide an overview of optic fiber and satellite communication technologies and present a comparison of the features and related issues.

Optic Fiber Communication

Optic Fiber communication transmits information by sending pulses of light (using laser) through an optic fiber. The low signal loss in optic fibers and high data rate of transmission systems, allow signals with high data rates (exceeding several Gbps) to travel over long distances (more than 100 km) without a need of repeater or amplifier. Moreover, using wavelength division multiplexing (WDM) allows a single fiber to carry multiple signals (upto 10 different signals) of multi-Gbps transmissions. Optic Fiber communication offers extremely high bandwidth, immunity to electromagnetic interference, non-existent delays and immunity from interception by external means. In the 1980s and 1990s, the continents were linked together using undersea optic fiber bringing about a paradigm shift in the global telecommunications.

These advancements in optic fiber communication has resulted in decrease of satellite communications for several types of communications. For instance, transmission between fixed locations or point-to-point communications, where large bandwidths are required (such as transoceanic telephone systems) are made through optic fiber instead of using satellite communication. Optic Fiber communication is also used to transmit telephone signals, Internet communication, LAN (Gigabit LAN) and cable television signals.

Satellite Communication

Satellite communications use artificial satellites as relays between a transmitter and a receiver at different locations on Earth. Satellite systems allow users to bypass typical carrier offices and to broadcast information to multiple locations. Communications satellites are used for radio, TV, telephone, Internet, military and other applications. There are more than 2,000 satellites around Earth’s orbit, being used for communication by both government and private organizations.

Communication Satellites are LOS (line-of-sight) microwave systems with a repeater. These satellites rotate around the earth with the speed of earth and are known as geostationary satellites. The limitations of antenna size also limits focusing capability making the coverage for a single satellite transmitter very large. This makes satellite communication ideal for TV and radio services as the signal has to flow from a single point to many points in a single direction. The large distance of satellites from the earth (about 22,300 miles) results in delays which adversely effects two-way communication like mobile conversations. Low earth orbit satellites can be used for two-way mobile communication because less power is required to reach those satellites.

Explanation:

1.14m x MG is the answer

3.33 mol H₂O

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

60.0 g H₂O (Water)

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

Step 4: Convert

Follow sig fig rules and round. We are given 3 sig figs.

3.32963 mol H₂O ≈ 3.33 mol H₂O

Answer:

The half-life of a radioisotope describes the amount of time it takes for said isotope to decay to one-half the original amount present in the sample.

Nitrogen-13, because it has a half-life of ten minutes, will experience two half-lives over the course of the twenty minute period. This means that 25% of the isotope will remain after this.

0.25 x 128mg = 32mg

32mg of Nitrogen-13 will remain after 20 minutes.

Answer:

Hallo

Explanation:

I took that question

The controlled burn cause of wildfires is least likely to lead to catastrophic results. Therefore, option (C) is correct.

A controlled burn is a fire set intentionally for purposes of forest management, prairie restoration, farming, or greenhouse gas. A controlled burn refers to the intentional burning of slash, fuels through burn piles.

Controlled burning can be done during the cooler months to reduce fuel buildup and reduce the likelihood of serious hotter fires. Controlled burning enhances the germination of desirable forest trees, and exposes soil mineral layers which expand seedling vitality.

Controlled burning is also useful in agriculture as it is often referred to as slash and burns. It is one component of shifting cultivation, as a section of field preparation for planting called field burning. This technique is utilized to clear the land of any existing crop residue and kill weeds and weed seeds.

Field burning is less expensive but because it forms smoke and air pollutants, its use is not common in agricultural areas.

Learn more about controlled burn, here:

https://brainly.com/question/28466648

#SPJ2

Answer:

fr

Explanation:

4.2 × 10⁻²¹ moles Sn

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

2500 atoms Sn

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

4.15144 × 10⁻²¹ moles Sn ≈ 4.2 × 10⁻²¹ moles Sn

Answer:

Disease ranching

Explanation:

Floods and Droughts are caused by the enviorment. Diseases are but a product and don't  affect the enviorment.

Answer:

disease ranching is not a natural change to the environment .

Explanation:

This all happen because of human activities

The final temperature : 317 °C

Given

V₁=2.5 L

V₂ = 5 L

T₁ = 22 + 273 = 295 K

Required

The temperature, T₂

Solution

Charles's Law  

When the gas pressure is kept constant, the gas volume is proportional to the temperature  

[tex]\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

Input the value :

T₂ = (T₁ x V₂) : V₁

T₂ = (295 x 5) : 2.5

T₂ = 590 K = 317 °C

Answer:

21 molecules of water.

Explanation:

The polymerization of a 22-monomer long cellulose molecule will require 21 molecules of water. This is because the polymer bond is formed when the -OH group from the 1st monomer of the glucose unit and the H group from the 2nd monomer gets removed as a water molecule. This process is termed to be a condensation reaction.