Answer:
[tex]x=-1[/tex]
Step-by-step explanation:
[tex]2x-3x-1=0\\(2x-3x)+(-1)=0\\-x-1=0\\-x-1+1=0+1\\-x=1\\\frac{-x}{1}=\frac{1}{-1}\\ x=-1[/tex]
Sunland Mining Company purchased land on February 1, 2020, at a cost of $975,900. It estimated that a total of 57,600 tons of mineral was available for mining. After it has removed all the natural resources, the company will be required to restore the property to its previous state because of strict environmental protection laws. It estimates the fair value of this restoration obligation at $110,700. It believes it will be able to sell the property afterwards for $123,000. It incurred developmental costs of $246,000 before it was able to do any mining. In 2020, resources removed totaled 28,800 tons. The company sold 21,120 tons.
Sunland Mining Company purchased land on February 1, 2020, at a cost of $975,900. It estimated that a total of 57,600 tons of mineral was available for mining. After it has removed all the natural resources, the company will be required to restore the property to its previous state because of strict environmental protection laws. It estimates the fair value of this restoration obligation at $110,700. It believes it will be able to sell the property afterwards for $123,000. It incurred developmental costs of $246,000 before it was able to do any mining. In 2020, resources removed totaled 28,800 tons. The company sold 21,120 tons.
Calculate :
a. Per unit mineral cost.
b. Total material cost of December 31, 2020, inventory
c. Total materials cost in cost of goods sold at December 31, 2014.
Answer:
a. Per unit mineral cost is $21
b. Total material Cost of ending inventory is $161280
c. Total materials cost in cost of goods sold is $443520
Step-by-step explanation:
The Per unit mineral cost can be computed as follows:
Details Amount ($)
Cost of land 975900
Add: Restoration obligation 110700
Add: Development cost 246000
1332600
Less: Resale value of property 123000
Total cost of land 1209600
Divide:Total estimated cost 57600
of minerals
Per unit mineral cost 21
b. The ending inventory cost on December 31, 2020 can be calculated as follows:
Ending inventory = Total mined tons - sold tons
Ending inventory = 28800 - 21120
Ending inventory = 7680
Cost per ton= $21
Cost of ending inventory = 7680 × $21
Cost of ending inventory = $161280
c.To calculate the cost of goods sold in December 2020; we have:
Cost per ton = $21
Total units sold = 21120
Cost of goods sold = 21120 × $21
Cost of goods sold = $443520
Complete the square to rewrite y = x2 + 8x+ 3 in vertex form, and then identify
the minimum y-value of the function.
Please answer ASAP!!!
====================================================
Work Shown:
y = x^2 + 8x + 3 is the same as y = 1x^2 + 8x + 3
It is in the form y = ax^2 + bx + c
a = 1
b = 8
c = 3
Plug the values of a and b into the formula below to get the x coordinate of the vertex (h,k)
h = -b/(2a)
h = -8/(2*1)
h = -8/2
h = -4
Plug this into the original equation to get its paired y value. This will get us the value of k
y = x^2 + 8x + 3
y = (-4)^2 + 8(-4) + 3
y = 16 - 32 + 3
y = -13
This is the smallest y output possible. Therefore it is the minimum. The minimum occurs at the vertex (h,k) = (-4, -13)
We know we are dealing with a minimum because a = 1 is positive forming a parabola that opens upward. If a < 0, then the parabola would open downward to yield a maximum.
If f(x)= x/2 -2 and g(x) = 2x² + x - 3, find (f + g)(x).
O A. x²-6
O B. 2x²+ 3/2x +1
O C. 2x² - x/2 +1
O D. 2x² + 3/2 x-5
Answer:
Step-by-step explanation:
Its d
S and T are two-digit positive integers that have the same digits but in reverse order. If the positive difference between S and T is less than 40, what is the greatest possible value of S minus T
Answer :Answer: Did you get helped on this one?
Step-by-step explanation: okay yup yup have a good day OKAY
Step-by-step explanation: HAVE A GOOD ONE OKAY
How much water is wasted by the leaky faucet in 1 day? 15 drips per 30 seconds
Answer:
a. 43,200 drips
b. 4 gallons (approximately, actual value is 3.8)
c. 61 cups(approximately, actual value is 60.8, using 3.8 gallons and not 4 gallons)
Step-by-step explanation:
Here, we have a faucet wasting water at a rate of 15 drips per 30 seconds, now we want to calculate the number of drips wasted in a day
To find this, what we need to do is fund the number of seconds in a day first
There are 24 hours with 60 minutes, with each minute having 60 seconds
So the number of seconds in a day = 24 * 60 * 60 = 86,400 seconds
Now 15 drips is wasted in 30 seconds
x will be wasted in 86,400 seconds
x = (15 * 86400)/30 = 43,200 drips are wasted in a day
b. Mathematically , there are about 3,000 drips in a liter of water
So;
3,000 drips = 1 liter
43,200 drips = x liter
x = 43200/3000 = 14.4 liters of water
Mathematically,
1 liter = 0.264 gallons
So 14.4 liters = 14.4 * 0.264 = 3.8 gallon
which is equal to 4 gallons of water approximately
c. Mathematically;
1 gallon = 16 cups of water
So 3.8 gallons of water will measure 3.8 * 16 = 60.8 which is approximately 61 gallons of water
Marta is solving the equation x2+x=3 by completing the square what number should be added to both sides of the equation to complete the square?
Answer:
C = 1/4
Step-by-step explanation:
When solving a quadratic equation, there are steps to follow and I'll highlight them here.
Assuming we have an equation
ax² + bx + c = 0
Step 1
If a is not equal to 1, divide all through by a
x² + bx + c = 0
Take c to the other side of the equation
x² + bx = c
Step 2
Add (b/2)² to both sides of the equation
x² + bx + (b/2)² = c + (b/2)²
In our original question,
We had x² + x = 3
a = 1 , b = 1 c = 3
Using step two, we would have
(b / 2)² = (½)² = ¼ (which is the answer)
Now back to the steps
Step 3
We factor our left side of the equation so as to have a perfect square
[x + (b/2)]² = c + (b/2)²
Step 4
Take the square root of both sides of the equation and solve for x
x + b/2 = ±√[c + (b/2)²]
The answer to the question is ¼
Answer:
1/4
Step-by-step explanation:
ese
i). nx n2 =343 (2mks)
I
Answer:
Are you asking what the value of x is if [tex]n^{x} * n^2 = 343[/tex] ?
Step-by-step explanation:
f(x)=x^2. What is g(x)?
Answer:
A
Step-by-step explanation:
With this one, you can just plug in 3 into each of the equations until the answer is 1.
When u plug 3 into x for solution A.
(1/3)×3=1
1^2=1
Answer:
[tex]\boxed{ \mathrm{A} }[/tex]
Step-by-step explanation:
The point is given (3, 1)
x = 3
y = 1
y = (1/3x)²
Plug x as 3 and y as 1.
The equation should be equal.
1 = (1/3(3))²
1 = 1²
1 = 1 True
Find the area of the shape shown below. I NEED HELP NOWWWWWW
Answer:
12.5 units[tex] {}^{2} [/tex]Step-by-step explanation:
Given figure : Trapezoid
Base sides,
a = 2.5
b = 7.5
Height ( h ) = 2.5
Now, finding the area:
[tex] \frac{1}{2} (a + b) \times h[/tex]
Plug the values
[tex] = \frac{1}{2 } \times (2.5 + 7.5) \times 2.5[/tex]
Calculate the sum
[tex] = \frac{1}{2} \times 10 \times 2.5[/tex]
Reduce the numbers with G.C.F 2
[tex] = 5 \times 2.5[/tex]
Calculate the product
[tex]12.5 \: \: {units}^{2} [/tex]
Hope this helps...
Best regards!
A circle with center A and radius three inches is tangent at C to a circle with center B, as shown. If point B is on the small circle, what is the area of the shaded region? Express your answer in terms of \pi.
Answer:
27π Sq in.
Step-by-step explanation:
Circle A is equal to 9π sq inches. (Radius squared times Pi), Segment BC is a radii of Circle B and the diameter of Circle A. Meaning Circle B's radius is 6 inches. The area of circle B would be 36π sq inches. Now we subtract Circle A's area from Circle B's area(36π sq in. - 9π sq in.), the area of the shaded region is 27π sq in.
Please answer it now in two minutes
Answer:
[tex] f = 10.7 [/tex]
Step-by-step explanation:
Given ∆DEF,
<F = 36°
DF = e = 15
EF = d = 6
DE = f = ?
f can be found using the Law of Cosine as shown below:
[tex] f^2 = d^2 + e^2 - 2(d)(e)*cos(F) [/tex]
Plug in your values:
[tex] f^2 = 6^2 + 15^2 - 2(6)(15)*cos(36) [/tex]
Evaluate:
[tex] f^2 = 36 + 225 - 180*0.809 [/tex]
[tex] f^2 = 261 - 145.62 [/tex]
[tex] f^2 = 115.38 [/tex]
[tex] f = 10.74 [/tex]
[tex] f = 10.7 [/tex] (to nearest tenth)
In a survey men in a certain country (ages 20-29), the mean height was 62.8 inches with a standard deviation of 2.8 inches, what height represents the 99th percentile?
Answer:
the height that represents the 99th percentile is 69.324 inches
Step-by-step explanation:
Given that :
the mean height = 62.8 inches
standard deviation = 2.8 inches
For 99th percentile;
Let X be the random variable;
SO, P(Z≤ z) = 0.99
From the standard normal z tables
P(Z )= 2.33
The standard z score formula is :
[tex]z = \dfrac{X- \mu}{\sigma}[/tex]
[tex]2.33 = \dfrac{X- 62.8}{2.8}[/tex]
2.33 × 2.8 = X - 62.8
6.524 = X - 62.8
6.524 +62.8 = X
69.324 = X
X = 69.324
Therefore; the height that represents the 99th percentile is 69.324 inches
A. 60
B. 15
C. 120
D. 6
Answer:
C. 120
Step-by-step explanation:
The figure shows that angles BEC and KEC are congruent. Their measures are equal.
m<KEC = m<BEC
10x = 6x + 24
4x = 24
x = 6
m<BEK = 2m<KEC
m<BEK = 2 * 10x
m<BEK = 2 * (10)(6)
m<BEK = 2 * 60
m<BEK = 120
Help please!!!!!!!I don’t know this! Tyy
====================================================
Explanation:
Each cube has a side length of 4. Placed together like this, the total horizontal side combines to 4+8 = 8. This is the segment HP as shown in the diagram below. I've also added point Q to form triangle HPQ. This is a right triangle so we can find the hypotenuse QH
Use the pythagorean theorem to find QH
a^2 + b^2 = c^2
(HP)^2 + (PQ)^2 = (QH)^2
8^2 + 4^2 = (QH)^2
(QH)^2 = 64 + 16
(QH)^2 = 80
QH = sqrt(80)
Now we use segment QH to find the length of segment EH. Focus on triangle HQE, which is also a right triangle (right angle at point Q). Use the pythagorean theorem again
a^2 + b^2 = c^2
(QH)^2 + (QE)^2 = (EH)^2
(EH)^2 = (QH)^2 + (QE)^2
(EH)^2 = (sqrt(80))^2 + (4)^2
(EH)^2 = 80 + 16
(EH)^2 = 96
EH = sqrt(96)
EH = sqrt(16*6)
EH = sqrt(16)*sqrt(6)
EH = 4*sqrt(6), showing the answer is choice C
-------------------------
A shortcut is to use the space diagonal formula. As the name suggests, a space diagonal is one that goes through the solid space (rather than stay entirely on a single face; which you could possibly refer to as a planar diagonal or face diagonal).
The space diagonal formula is
d = sqrt(a^2+b^2+c^2)
which is effectively the 3D version of the pythagorean theorem, or a variant of such.
We have a = HP = 8, b = PQ = 4, and c = QE = 4 which leads to...
d = sqrt(a^2+b^2+c^2)
d = sqrt(8^2+4^2+4^2)
d = sqrt(96)
d = sqrt(16*6)
d = sqrt(16)*sqrt(6)
d = 4*sqrt(6), we get the same answer as before
The space diagonal formula being "pythagorean" in nature isn't a coincidence. Repeated uses of the pythagorean theorem is exactly why this is.
Find the center and radius of x^2 – 18x + y^2 -10y = -6. part two write x2 – 18x + y2 -10y = -6 in standard form
Answer:
see explanation
Step-by-step explanation:
I will begin with part two, first.
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius.
Given
x² - 18x + y² - 10y = - 6
Using the method of completing the square
add ( half the coefficient of the x/ y terms )² to both sides
x² + 2(- 9)x + 81 + y² + 2(- 5)y + 25 = - 6 + 81 + 25, that is
(x - 9)² + (y - 5)² = 100 ← in standard form
with centre = (9, 5 ) and r = [tex]\sqrt{100}[/tex] = 10
Find the volume in cubic meters, of the 3-Dimensional composite
figure.
8m
5m
Answer:
890 m^3 to the nearest whole number.
Step-by-step explanation:
Volume = volume of the cylinder + volume of the hemisphere:
= π r^2 h + 1/2 * 4/3 π r^3
= π*5^2 * 8 + 1/2 * 4/3 π 5^3
= 890.12
What is the value of discontinuity of x^2+8x+4/x^2-x-6? Choices:
Answer:
-2
Step-by-step explanation:
Hello,
First of all, let's check the denominator.
[tex]x^2-x-6 \ \ \text{ *** How to factorise it ...? ***}\\\\\text{*** The product of the roots is -6=-2*3 and their sum is 1 ***}\\\\x^2-x-6=x^2-3x+2x-6=x(x-3)+2(x-3)=(x+2)(x-3)[/tex]
Now, let's see the numerator.
[tex]x^2+8x+4 \ \text{ *** -2 is not a zero as ***}\\\\(-2)^2+8*(-2)+4=4-16+8=-4\\\\\text{*** 3 is not a zero as ***}\\\\3^2+8*3+4=9+24+4=37\\[/tex]
So we cannot factorise the numerator with (x+2) or (x-3)
Then, -2 and 3 are the the discontinuities of the expression.
There is only -2 in the list, this is the correct answer.
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
EXPLANATION NEEDED:
In right triangle ABC, ∠ B is a right angle and sin ∠ C = x. cos ∠ A =
a. √x² - 1
b. √1 - x²
c. x
d. √x² + 1
e. x²
Answer:
C. xStep-by-step explanation:
AC denotes the length of the hypotenuse and AB and BC denote the lengths of the other two sides, so:
[tex]\cos(\angle A)=\dfrac{AB}{AC}=\sin(\angle C)=x[/tex]
A lake has a small patch of lily pads and every day the patch grows to double its size. It takes 32 days for the patch to cover the lake – how long would it take the patch to cover half the lake?
Answer:
It took 31 days for the patch to cover half the lake
Step-by-step explanation:
The patch grows to double its size everyday
the patch completely covers the lake in 32 days
Since the patch doubles itself everyday, this means that the previous day before the 32nd day, the lake was just half covered.
Therefore, the the patch covered half the lake on the 31st day, i.e it took 31 days for the patch to cover half the lake
n the diagram below, points $A,$ $E,$ and $F$ lie on the same line. If $ABCDE$ is a regular pentagon, and $\angle EFD=90^\circ$, then how many degrees are in the measure of $\angle FDE$?
[asy]
size(5.5cm);
pair cis(real magni, real argu) { return (magni*cos(argu*pi/180),magni*sin(argu*pi/180)); }
pair a=cis(1,144); pair b=cis(1,72); pair c=cis(1,0); pair d=cis(1,288); pair e=cis(1,216);
pair f=e-(0,2*sin(pi/5)*sin(pi/10));
dot(a); dot(b); dot(c); dot(d); dot(e); dot(f);
label("$A$",a,WNW);
label("$B$",b,ENE);
label("$C$",c,E);
label("$D$",d,ESE);
label("$E$",e,W);
label("$F$",f,WSW);
draw(d--f--a--b--c--d--e);
draw(f+(0,0.1)--f+(0.1,0.1)--f+(0.1,0));
[/asy]
Answer:
18
Step-by-step explanation:
Each interior angle of a regular pentagon is 108 degrees. So Angle AED is 108 degrees. Since Angle AEF is a straight line (180 degrees), Angle FED is 72. This is because 180-108 = 72. Now, since a triangle has a total of 180 degrees, we add 72 and 90, because those are the 2 degrees we have calculated. This gives us a total of 162. Now, we subtract 162 from 180 to find out the degree of Angle FDE. This is 18. So our final answer is 18.
Sidenote: I hope this answer helps!
The properties of a pentagon and the given right triangle formed by
segments EF and FD give the measure of ∠FDE.
Response:
∠FDE = 18°Which properties of a pentagon can be used to find ∠FDE?The given parameters are;
A, E, F are points on the same line.
ABCDE is a regular pentagon
∠EFD = 90°
Required:
The measure of ∠FDE
Solution:
The points A and E are adjacent points in the pentagon, ABCDE
Therefore;
line AEF is an extension of line side AE to F
Which gives;
∠DEF is an exterior angle of the regular pentagon = [tex]\frac{360 ^{\circ}}{5}[/tex] = 72°∠EFD = 90°, therefore, ΔEFD is a right triangle, from which we have;
The sum of the acute angles of a right triangle = 90°
Therefore;
∠DEF + ∠FDE = 90°
Which gives;
72° + ∠FDE = 90°
∠FDE = 90° - 72° = 18°
∠FDE = 18°
Learn more about the properties of a pentagon here:
https://brainly.com/question/15392368
For one of the quadrilaterals: the corner are not the right angles, the quadrilateral has rotational symmetry of order 2 and the diagonals cross at the right angles. Write down the name of this quadrilateral
Answer:
Rhombus.
Step-by-step explanation:
A rhombus is a quadrilateral, meaning that it has four lateral sides. A Rhombus is a 2-dimensional shape, and has two lines of symmetry. A Rhombus has a rotational symmetry of order two, and the opposite sides are parallel. Also, the opposite angles in Rhombus are equal. Th diagonals of a Rhombus bisect each other at a right angle.
Other quadrilateral shapes includes the Rectangle, Parallelogram, and the Kite.
a
simplified form of -3 + 2(x - 1)?
8. Which expression
a. -X + 1
b. 2x-5
c. 2x - 4
d. -X-1
Answer:
2x -5
Step-by-step explanation:
-3 + 2(x - 1)
Distribute
-3 +2x -2
Combine like terms
2x -5
Answer:
5x -2
Step-by-step explanation:
Find a12 of the sequence 1/4,7/12,11/12,5/4,
Answer:
Your ans is. a12 = 47/12
Step-by-step explanation:
First, you need to find if the series has a common ratio or a common difference between each term. Based from observation, there is a common difference of 1/3 so the series is an arithmetic series.
The solution for this problem goes like this
an=a1+(n-1)d
a12=1/n+(12-1)(1/3)
a12=47/12
Hope it helped you.. Please mark BRAINLIEST
Tysm
What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12? (–∞, –3] [–3, ∞) (–∞, 15] [15, ∞) SORRY THIS IS THE FULL QUESTION
Answer:
[15, ∞).
Step-by-step explanation:
–3(6 – 2x) ≥ 4x + 12
-18 + 6x ≥ 4x + 12
6x - 4x ≥ 12 + 18
2x ≥ 30
x ≥ 15
This means that the minimum of x is 15, and the most is infinity, which is the same thing as [15, ∞).
Hope this helps!
Solve the inequality 47.75 + x Less-than-or-equal-to 50 to determine how much more weight can be added to Li’s suitcase without going over the 50-pound limit. What is the solution set?
x Less-than-or-equal-to 2.25
x Less-than-or-equal-to 2.75
x Greater-than-or-equal-to 2.25
x Greater-than-or-equal-to 2.75
Answer: x Less-than-or-equal-to 2.25
Step-by-step explanation:
The given inequality: 47.75 + x Less-than-or-equal-to 50.
To determine: How much more weight can be added to Li’s suitcase without going over the 50-pound limit.
i.e. inequality for x.
[tex]47.75+x\leq50[/tex]
Subtract 47.75 from both the sides, we get
[tex]x\leq50-47.75\\\\\Rightarrow\ x\leq2.25[/tex]
So, the solution set is "x Less-than-or-equal-to 2.25"
Hence, the correct answer is "x Less-than-or-equal-to 2.25."
Answer
A x <_ 2.25
Step-by-step explanation:
I promise I will mark as brainiest
There are 18 rectangles inside the playing field. And if you include the fence around the field, that makes 19.
Look at picture to see question
from the figure below identify a)Obtuse vertically opposite angles b) A pair of adjacent complementary angles c) a pair of equal supplementary angles d) a pair of unequal supplementary angles e) a pair of adjacent angles that don’t form a linear pair
Answer:
a) BOC and AOD
b) BOA and AOE
c) BOE and EOD
d) BOA and AOD
e) AOE and EOD
Step-by-step explanation:
An obtuse angle is an angle that has more than 90° and vertically opposite angles are angle formed by two lines crossed. So, Obtuse vertically opposite angles are BOC and AOD
Adjacent angles are angles in which one angle is beside the other and complementary angles are angles whose sum is equal to 90°, so, a pair of adjacent complementary angles are BOA and AOE.
Supplementary angles are angles whose sum is equal to 180°, so BOE and EOD are equal suplementary angles and BOA and AOD are unequal supplementary angles
Finally, AOE and EOD are adjacent angles that don’t form a linear pair.
Factor this polynomial.
-3x^2– 5x-2
Answer:
[tex]-(3x+2)(x+1)[/tex]
Step-by-step explanation:
So we have the polynomial:
[tex]-3x^2-5x-2\\=-(3x^2+5x+2)[/tex]
(I moved the negative to the outside. This is optional, but it makes things cleaner and you will have to do it eventually.)
This is a quadratic. To factor this, we need to find two numbers p and q such that:
[tex]p\cdot q=ac\\p+q=b[/tex]
From there, we can substitute these numbers in for b.
From the quadratic, a=3, b=5, and c=2. We ignore the negative sign.
In other words, ac=6 and b=5.
After guessing and checking, two numbers that work are 3 and 2 since 3(2)=6 ad 3+2=5. We substitute these values in for b. So:
[tex]-(3x^2+5x+2)\\-(3x^2+3x+2x+2)\\=-(3x(x+1)+2(x+1))\\=-(3x+2)(x+1)[/tex]
In a local town, 54,000 families have incomes less than $25,000 per year. This number of families is 60% of the families that had this income level 12 years ago. What was the number of families who had incomes less than 25,000 per year 12 years ago
Answer: 90,000
Step-by-step explanation:
From the question, we are informed that in a local town, 54,000 families have incomes less than $25,000 per year. We are further told that this number of families is 60% of the families that had this income level 12 years ago.
To calculate the number of families who had incomes less than 25,000 per year 12 years ago goes thus:
Let the the number of families who had incomes less than 25,000 per year 12 years ago be represented by x.
Since we are told that this number of families is 60% of the families that had this income level 12 years ago. This means that:
60% of x = 54,000
60/100 × x = 54,000
0.6 × x = 54,000
0.6x = 54,000
Divide by 0.6
0.6x/0.6 = 54000/0.6
x = 90,000
The number of families who had incomes less than 25,000 per year 12 years ago was 90,000.