The element that has been reduced in the redox reaction [tex]AgNO_3 + Na NaNO_3 + Ag[/tex] is silver (Ag). A redox (reduction-oxidation) reaction involves the reduction of one element by the gain of electrons and the oxidation of another element by the loss of electrons.
When sodium (Na) loses one electron to generate [tex]NaNO_3[/tex] in this reaction, sodium changes from its neutral state (with a zero oxidation number) to a positive oxidation state (+1). On the other hand, when silver (Ag) in AgNO3 gets one electron to create Ag, it moves from a +1 oxidation state to a neutral state (with zero oxidation number).
Silver is the element that undergoes reduction in this process because reduction entails a gain of electrons, reducing it from its +1 oxidation state to its neutral state.
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Which energy profile best shows that the enthalpy of formation of CS2 is 89.4 KJ/mol?
Answer:
Option C. Energy Profile D
Explanation:
Data obtained from the question include:
Enthalpy change ΔH = 89.4 KJ/mol.
Enthalpy change (ΔH) is simply defined as the difference between the heat of product (Hp) and the heat of reactant (Hr). Mathematically, it is expressed as:
Enthalpy change (ΔH) = Heat of product (Hp) – Heat of reactant (Hr)
ΔH = Hp – Hr
Note: If the enthalpy change (ΔH) is positive, it means that the product has a higher heat content than the reactant.
If the enthalpy change (ΔH) is negative, it means that the reactant has a higher heat content than the product.
Now, considering the question given, the enthalpy change (ΔH) is 89.4 KJ/mol and it is a positive number indicating that the heat content of the product is higher than the heat content of the reactant.
Therefore, Energy Profile D satisfy the enthalpy change (ΔH) for the formation of CS2 as it indicates that the heat content of product is higher than the heat content of the reactant.
Help PLZ!!! Which statement accurately represents the arrangement of electrons in Bohr’s atomic model? -Electrons move around the nucleus in fixed orbits of equal levels of energy. -Electrons move around the nucleus in fixed orbits of increasing levels of energy. -Electrons move randomly in the relatively large space surrounding the nucleus. -Electrons vibrate in fixed locations around the nucleus.
Answer:
electrons move around the nucleus in fixed orbits of equal amounts of energy
Explanation:
To see the number of atoms of an element in a given molecule we need to multiply stoichiometry to the number that is written on the foot of the element that is stoichiometry. The correct option is option B.
What is atom?Atom is the smallest particle of any element, molecule or compound. Atom can not be further divided. Atoms contains nucleus in its center and electron that revolve around the atom in fixed orbit.
In the nucleus, proton and neutron are present. Electron has -1 charge while proton has +1 charge. Neutron is neutral that is it has no charge. So overall the charge of nucleus is due to only proton, not by neutron.
According to Bohr’s atomic model, electrons move around the nucleus in fixed orbits of increasing levels of energy.
Therefore, the correct option is option B that is electrons move around the nucleus in fixed orbits of increasing levels of energy.
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