SAT College

Jermaine has entered a bowling tournament. To prepare, he bowls five games each day and writes down the score of each game, along with the mean of five scores. He is looking at the scores from one day last week and finds that one of the numbers has accidentally been erased. The four remaining scores are 210, 238 , 264 , 262 and . The mean score of the five games is 252 . What is the missing score? The missing score is .

Answers

Answer 1

Based on the mean and the other given scores, the missing score must be 286.

What is the missing score?

Assuming the missing score was x, it can be found as:

Mean score = (Sum of scores + x  / Number of games

Solving gives:

252 = (210 + 238 + 264 + 262 + x) / 5

252 x 5 = 974 + x

x = 1,260 - 974

= 286

In conclusion, the missing score is 286.

Find out more on mean at https://brainly.com/question/26177250.

Related Questions

Suppose that 80% of books are classified as fiction. Two books are chosen at random. What is the probability that both books ara fiction?

Answers

Answer:

64% or 16/25

Explanation:

To calculate probability, we first find the fraction for the number of books that are fiction.

[tex]80= \frac{4}{5}[/tex]

To find out what the probability of choosing a fiction book twice, we multiply 4/5 with 4/5 to get our probability if we selected a book twice.

[tex]\frac{4}{5} *\frac{4}{5} = \frac{16}{25} \\0.64[/tex]

The probability of choosing two fiction books is a 16/25, or 64% chance.

Find the volume, in cubic inches, of the composite solid below, which consists of a 4 -inch square solid rectangular bar that is 16 inches in length. The bar has a 2 -inch diameter cylinder hole cut out of the center of the bar from the top of the bar through the entire length of the bar. Use 3.14 to find the volume. Enter only the number.

Answers

Answer:

10 in³

Explanation:

given:

square box = 4 in²,  length = 16 in

bar diameter = 2 in,   length = 16 in

box volume (in solid) = 4 in² * 16 in = 64 in³

bar volume = pi * d² / 4 = 3.14 * 2² / 4 *  16 in = 50.24 in³

Volume of slotted box = 64 - 50 = 10 in³

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