Let A = {H, T} be the set of outcomes when a coin is tossed, and let B = {1, 2, 3, 4, 5, 6} be the set of outcomes when a die is rolled. The set of outcomes when a coin is tossed twice. Write the set in terms of A and/or B. A ∩ B A × A A × B A ∪ B List the elements of the set.

Answer:

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

Step-by-step explanation:

Using the fundamental theorem of calculus

Taking the derivative of the integral gives back the function

Since the lower limit is a constant when we take the derivative it is zero

d/dx [tex]\int\limits^x_4 {g(t)} \, dt = g(x)[/tex]

g(t) = sinh^-1 ( ln(7t^6 +3) / sqrt( 8+cot( t^( 3+t))))

Replacing t with x

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

Answer:

.154

Step-by-step explanation:

There are 52 cards

There are 4 aces and 4  9's for a total of 8 cars

P (ace or 9) = number of aces or 9's / total

                   = 8/52 = 2 /13 =.153846154

To the nearest thousandth

                      = .154

Answer:

0.154

Step-by-step explanation:

We want to find the probability of drawing an ace or a 9.

P(ace or 9)= aces and 9s / total cards

There are 4 aces and 4 9s in a standard deck of cards. This means there is a total of 8 aces and 9s.

In a standard deck of cards, there is a total of 52 cards.

P(ace or 9)= aces and 9s / total

aces and 9s= 8

total= 52

P(ace or 9)= 8/52

This fraction can be simplified. Both the numerator and denominator can be evenly divided by 4.

P(ace or 9)= (8/4) / (52/4)

P(ace or 9)= 2/13

P(ace or 9)= 0.153846153846154

Round to the nearest thousandth. The 8 in the ten thousandth place tell sus to round the 3 up to a 4.

P(ace or 9) = 0.154

The probability of drawing an ace or 9 is 0.154

Answer:

the guarantee period should be less than 136010 miles

Step-by-step explanation:

From the given information;

Let consider Y to be the life of a car engine

with a mean μ = 170000

and a standard deviation σ = 16500

The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.

i.e

P(Y < T ) < 0.02

For the variable of z ; we have:

[tex]z = \dfrac{x - \mu }{\sigma}[/tex]

[tex]z = \dfrac{x - 170000 }{16500}[/tex]

Now;

[tex]P(Y < T ) = P( Z < \dfrac{T- 170000}{16500})[/tex]

[tex]P( Z < \dfrac{T- 170000}{16500})< 0.02[/tex]

From Z table ;

At P(Z < -2.06) ≅ 0.0197  which is close to 0.02

[tex]\dfrac{T- 170000}{16500}<- 2.06[/tex]

[tex]{T- 170000}<- 2.06({16500})[/tex]

[tex]{T- 170000}< - 33990[/tex]

[tex]{T}< - 33990+ 170000[/tex]

[tex]{T}<136010[/tex]

Thus; the guarantee period should be less than 136010 miles

Answer:

√468 = 6√13

Step-by-step explanation:

ABCDEF is a regular hexagon of side length 6.

A'B'C'D'E'F' is the reflection of ABCDEF across BC.

The line FE' is the line from F to E'.  It is also the hypotenuse of the right triangle FEE'.  FE = 6, and EE' = 4a, where a is the apothem of the hexagon.

To find the apothem, draw the 30-60-90 triangle formed by the apothem and the radius (essentially 1/12th of the hexagon).

Using properties of a 30-60-90 triangle:

a = (6/2)√3

a = 3√3

4a = 12√3

Using Pythagorean theorem:

x² = (6)² + (12√3)²

x² = 36 + 432

x = √468

x = 6√13

Answer:

3/20

Step-by-step explanation:

since there is a total of 20 tulips that would be your denominator then your numerator would be the number of purple tulips which would be 3 so you probability of randomly selecting a purple tulip would be 3/20

Answer:

138,920 m²

Step-by-step explanation:

A square pyramid has 1 square base and 4 lateral triangular faces.

Area of square pyramid is given as BASE Area (BA) + ½*Perimeter of Base (P) × Slant height

Area of pyramid = [tex] b^2 + \frac{1}{2}*4(b)*l [/tex]

Where,

b = base length = 230 m

l = slant height = 187 m (height of the triangular sides)

Surface area = [tex] 230^2 + \frac{1}{2}*4(230)*187 [/tex]

[tex] = 52900 + 2(230)*187 [/tex]

[tex] = 52900 + 86020 [/tex]

[tex] = 138920 [/tex]

Surface area of the pyramid = 138,920 m²

Answer:

hope i helped thank you

Step-by-step explanation:

=========================================

Work Shown:

1.5/3 = 31.5/x

1.5x = 3*31.5  cross multiply

1.5x = 94.5

x = 94.5/1.5  dividing both sides by 1.5

x = 63

-----------

An alternative equation to solve is

1.5/31.5 = 3/x

1.5x = 31.5*3

1.5x = 94.5

The remainder of the steps are the same as in the previous section above.

Answer:

The standard error of the mean is  [tex]\sigma _{\= x } = 1.581[/tex]

Step-by-step explanation:

From the question we are told that

    The sample size is  n  =  250

      The standard deviation is  [tex]\sigma = 25[/tex]

          The sample mean is  [tex]\= x = 20[/tex]

The standard error of the mean is mathematically represented as

        [tex]\sigma _{\= x } = \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

        [tex]\sigma _{\= x } = \frac{25 }{\sqrt{250} }[/tex]

       [tex]\sigma _{\= x } = 1.581[/tex]

Answer:

1. Debit Petty cash for $400; and Credit Cash for $400.

2. Total petty cash payment = $270.57

3(a) Cash reimbursement is $279.58; and Cash over and short is $9.01.

3(b) Debit Petty cash for $100; and Credit Cash for $100.

Step-by-step explanation:

Note: This question is not complete. The full complete question is therefore provided before answering the question. See the attached pdf file for the full question.

The explanations to the answers are now given as follows:

1. Prepare the journal entry to establish the petty cash fund.

Note: See the journal entry in the attached excel file

2. Prepare a petty cash payments report for February with these categories: delivery expense, mileage expense, postage expense, merchandise inventory (for transportation-in), and office supplies expense. Sort the payments into the appropriate categories and total the expenditures in each category.

Note: See the petty cash payments report in the attached excel file.

3. Prepare the journal entries for required 2 to both (a) reimburse and (b) increase the fund amount.

Note: See the journal entries (a) and (b) in the attached excel file

3(a) Reimburse Workings:

w.1: Calculation of Cash reimbursement

Cash reimbursement = Petty cash fund - Petty cash fund balance = $400 - $120.42 = $279.58

w.2: Calculation of the Cash over and short

Cash over and short = Cash reimbursement – Total expenses = $279.58 - $270.57 - $120.42 = $9.01

Answer:

15 cartons of Hammers were ordered

Step-by-step explanation:

Cost per carton of Hammer  = $100

Cost per carton of Wrenches = $150

Total Carton = 25

Total Cost = $3,000

Required

Determine the numbers of Hammer and Wrenches

Represent the hammers with H and the wrenches with W

So;

[tex]H + W = 25[/tex]

and

[tex]100H + 150W = 3000[/tex]

Make W the subject of formula in the first equation:

[tex]H + W = 25[/tex]

[tex]W = 25 - H[/tex]

Substitute 25 - H for W in the second equation

[tex]100H + 150(25 - H) = 3000[/tex]

[tex]100H + 3750 - 150H = 3000[/tex]

Collect Like Terms

[tex]100H - 150H = 3000 - 3750[/tex]

[tex]-50H = -750[/tex]

Divide both sides by -50

[tex]\frac{-50H}{=50} = \frac{-750}{-50}[/tex]

[tex]H = \frac{-750}{-50}[/tex]

[tex]H = 15[/tex]

Hence, 15 cartons of Hammers were ordered

Answer:

D. [tex] y = \frac{8}{x} [/tex]

Step-by-step explanation:

The inverse variation between two variables usually takes the following equation form:

[tex] y = \frac{k}{x} [/tex]

In the equation form given above,

[tex] k [/tex] could be value of any real number

x is the explanatory variable (independet variable), while y is the response variable (dependent variable)

Therefore, [tex] y = \frac{8}{x} [/tex] , is an example of an equation that shows inverse variation between the x and y variables.

 The right option is D. [tex] y = \frac{8}{x} [/tex]

Answer:

Since it is a right triangle, you can use pythagorean theorem to find the missing side.

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

The computation of the number  of bacteria in the sample after 18 hours is shown below:

We assume the following things

P = 4 = beginning number of bacteria

rate = r = 0.1

Now

We applied the following formula

[tex]A = Pe^{rt}[/tex]

[tex]= 4\times e^{18\times0.1}[/tex]

[tex]=4e^{1.8}[/tex]

[tex]= 4\times6.049647464[/tex]

= 24

We simply applied the above formula to determine the number of bacteria after the 18 hours

Answer:

t

Step-by-step explanation:

Answer:

True

Step-by-step explanation:

Answer:

-7/3x + 3

Step-by-step explanation:

Answer:

(9x-7)/3x or (3-7/3x)

Step-by-step explanation:

Divide each term of numerator by denominator.

-28x^5/12x^6 +36x^6/12x^6

-7/3x +3

Answer:

SOHCAHTOA

Step-by-step explanation:

Usually, in American schools, the term "SOHCAHTOA" is used to remember them. "SOH" is sine opposite hypotenuse, "CAH" is cosine adjacent hypotenuse, and "TOA" is tangent opposite adjacent. There is also Csc which is hypotenuse/opposite, Sec which is hypotenuse/adjacent, and Cot is adjacent/opposite.

Answer: SOHCAHTOA

Step-by-step explanation:

The pneumonic I learned is SOH-CAH-TOA.  it says that Sin = opposite/hypotenuse.  Cos = adjacent/hypotenuse.  Tan = opposite/adjacent.

Hope it helps <3

Answer:

$960

Step-by-step explanation:

A shortcut method.

If you get a discount of 1/5, then that means you would end up paying 4/5 of the whole cost. That means all you have to do then is plug in what it costs, which in this case is 1200, and then multiply it by 4/5, so you end up with $960.

Answer:

$960

Step-by-step explanation:

1200*1/5 = 240

1200 - 240 = $960

Would appreciate brainliest!! But it's ok if not

Answer:

J = 32

E = 0

Step-by-step explanation:

E is the number of hours for the Escobar family

J is the number of hours for the Johnson family

E + J = 32

E * 20 + J * 30 = 960

Multiply the first equation by -20 so we can use elimination

-20 E -20 J = -640

Add this to the second equation

E * 20 + J * 30 = 960

-20 E -20 J = -640

---------------------------------

         10 J = 320

Divide by 10

J = 32

Now find E

E + J = 32

E  + 32 = 32

E = 0

Answer:

x= 37/36

Step-by-step explanation:

−12(3x−4)=11

Step 1: Simplify both sides of the equation.

−12(3x−4)=11

(−12)(3x)+(−12)(−4)=11(Distribute)

−36x+48=11

Step 2: Subtract 48 from both sides.

−36x+48−48=11−48

−36x=−37

Step 3: Divide both sides by -36.

−36x

−36

=

−37

−36

x=

37

36

Answer:

x=

37

36

-1/2(3x-4) = 11

Multiply both sides by -2:

3x-4 = -22

Add 4 to both sides:

3x = -18

Divide both sides by 3:

X = -6

Answer:

1 , - ( 3x^2/2), + (25x^4/24).

Step-by-step explanation:

We are given the following information:

y = (e^-x^2)cosx.

STEP ONE: Write out the power series out(either by deriving it or otherwise).

If you check the power series table, you will get the power series for the two functions that is cos x and e^-x^2.

e^-x^2 = 1 - (x^2) + ( x^4/2! ) - (x^6/3!) +...

Cos x = 1 - (x^2/2!) + x^4/4!) + (x^6/6!) -...

STEP TWO: Multiply both the power series of e^-x^2 and Cos x together because we are to determine or find the first three nonzero terms in the maclaurin series for the given function.

1 - (x^2) + ( x^4/2! ) - (x^6/3!) +... - 1 - (x^2/2!) + x^4/4!) + (x^6/6!) -...

= 1 - ( 3x^2/2) + (25x^4/24).

= 1, - ( 3x^2/2) , + (25x^4/24) => comma- separated list.

Answer:

0.95988 (Accuracy of the test )

Step-by-step explanation:

To determine the accuracy of this test we have to list out the given values

Prevalence rate of the disease = 0.3% = 0.003

sensitivity rate of the disease = 92% = 0.92

specificity rate for the test = 96% = 0.96

The accuracy of the test can be found using this equation

Accuracy = sensitivity * prevalence + specificity ( 1 - prevalence )

                = 0.92 * 0.003 + 0.96 ( 1 - 0.003 )

                = 0.00276 + 0.95712

                = 0.95988

Answer:

solution

given a=1_9k and b=j+k

Now,ab=(1_9k)(j+k)

=1((j+k)-9k(j+k)

=j+k_9jk-9k^2

=k_9k^2+j_9jk

=k((1_9k)+j(1_9k)

=(1_9k)(k+k)

Answer:

the answer i would go with is A

Good luck on your Test :)

Step-by-step explanation:

B doesnt really have a constant rate of change as it depends on how many games happen and usually the longer an arena stays open has no correlation on how many people attend the games there

C has no real constant rate of change as it always ends up stopping after a little bit, and the change is usually not a constant one

D this could count, but since its a number that would go down if its not brought back up, its not a real constant rate of change, since it cant go below or above a certain range

so by process of elimination, A is the answer. also seeing as how its saying the distance with the number of times, that means that its an objective thing, as a track is a set distance, and the distance of a run or the track cant be affected by time or anything and could technically never end. so its a constant thing, meaning the longer the distance is, the higher the laps around the track are, and it could theoretically go on forever.

i hope this helped answer your question! :)

Answer:

3 or -3

Step-by-step explanation:

sqrt(9)

What number multiplied by itself will give you 9

3*3 =9

-3 * -3 =9

The square root of 9 is 3 or -3

Answer:

Answer:

156.75 tons

Step-by-step explanation:

627/4 = 156.75

Answer:

156(3/4)

Step-by-step explanation:

with this your divide.

627/4=156.75

as a mixed numer it would 156(3/4). It is 3/4 because the number ends in .75

Answer:

value of Ft(-15,50) = 1.3

Value of Fv(-15,50) = -0.15

Step-by-step explanation:

W = perceived temperature

T = actual temperature

W = f( T,V)

Estimate the values of  ft ( -15,50) and  fv(-15,50)

calculate the Linear approximation of   f at(-15,50)

[tex]f_{t}[/tex] (-15,50) =  [tex]\lim_{h \to \o}[/tex] [tex]\frac{f(-15+h,40)-f(-15,40)}{h}[/tex]

from the table take h = 5, -5

[tex]f_{t}(-15,40) = \frac{f(-10,40)-f(-15,40)}{5}[/tex]  = [tex]\frac{-21+27}{5} = 1.2[/tex]

[tex]f_{t} = \frac{f(-20,40)-f(-15,40)}{-5}[/tex] = 1.4

therefore the average value of [tex]f_{t} (-15,40) = 1.3[/tex]

This means that when the Temperature is -15⁰c and the 40 km/h the  value of Ft (-15,40) = 1.3

calculate the linear approximation of

[tex]f_{v} (-15,40) = \lim_{h \to \o} \frac{f(-15,40+h)-f(-15,40)}{h}[/tex]

from the table take h = 10, -10

[tex]f_{v}(-15,40) = \frac{f(-15,50)-f(-15,40)}{10}[/tex]  = [tex]\frac{-29+27}{10} = -0.2[/tex]

[tex]f_{v} (-15,40) = \frac{f(-15,30)-f(-15,40)}{-10}[/tex]  = [tex]\frac{-26+27}{-10}[/tex]  = -0.1

therefore the average value of [tex]f_{v} (-15,40) = -0.15[/tex]

This means that when the temperature = -15⁰c and the wind speed is 40 km/h the temperature will decrease by 0.15⁰c

w = f(T,v)

   = -27 + 1.3(T+15) - 0.15(v-40)

   = -27 + 1.3T + 19.5 - 0.15v + 6

   = 1.3T - 0.15v -1.5  

calculate the linear approximation

[tex]\lim_{v \to \infty}[/tex][tex]\frac{dw}{dv} = \lim_{v \to \infty} \frac{d(1.3T-0.15v-1.5)}{dv}[/tex]  = -0.15

Answer:

Ok so we have a set of 8 numbers {1,2,...,8}

a) 5 and 8 are picked.The probability here is:

In the first selection we can pick 5 or 8, so we have two possible outcomes out of 8 total outcomes, then the probability for the first selection is:

P = 2/8 = 1/4.

Now, if one of those numbers was picked in the first selection, only one outcome is possible in this second selection, (if before we picked a 5, here we only can pick an 8)

Then the probability is:

P = 1/8

The joint probability is equal to the product of the individual probabilities, so here we have:

P = (1/4)*(1/8) = 1/32 = 0.003

b) The numbers match:

In the first selection we can have any outcome, so the probability is:

P = 8/8 = 1

Now, based on the previous outcome, in the second selection we can have only one outcome, so here the probability is:

P = 1/8 = 0.125

The joint probability is p = 1/8

c) The sum is smaller than 4:

The combinations are:

1 - 1

1 - 2

2 - 1

We have 3 combinations, and the total number of possible combinations is:

8 options for the first number and 8 options for the second selection:

8*8  = 64

The probabilty is equal to the number of outcomes that satisfy the sentence divided by the total numberof outcomes:

P = 3/64 = 0.047

Using the probability concept, it is found that there is a:

i. 0.03125 = 3.125% probability that 5 and 8 are picked.

ii. 0.125 = 12.5% probability that both numbers match.

iii. 0.046875 = 4.6875% probability that the sum of the two numbers picked is less than 4.

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, two integers are chosen from a set of 8, hence, there are [tex]8^2 = 64[/tex] total outcomes.

Item i:

Two outcomes result in 5 and 8 being picked, (5,8) and (8,5), hence:

[tex]p = \frac{2}{64} = 0.03125[/tex]

0.03125 = 3.125% probability that 5 and 8 are picked.

Item ii:

8 outcomes result in both numbers matching, (1,1), (2,2), ..., (8,8), hence:

[tex]p = \frac{8}{64} = 0.125[/tex]

0.125 = 12.5% probability that both numbers match.

Item ii:

Three outcomes result in a sum of less than 2, (1,1), (1,2), (2,1), hence:

[tex]p = \frac{3}{64} = 0.046875[/tex]

0.046875 = 4.6875% probability that the sum of the two numbers picked is less than 4.

A similar problem is given at https://brainly.com/question/15536019

Answer:

27

Step-by-step explanation:

First, we need to find x. We are given the perimeter, which is 2l + 2w, so from there, we have an equation of 2(4x-1) + 2(3x+2) = 100. By working through it, we get that x = 7. We're asked to find WX, so plug 7 into 4x - 1 and get 27.

Answer:

Step-by-step explanation:

Perimeter of rectangle is 2(l) + 2(w).

The perimeter is given 100 units.

2(4x-1) + 2(3x+2) = 100

Solve for x.

8x-2+6x+4=100

14x+2=100

14x=98

x=7

Plug x as 7 for the side WX.

4(7) - 1

28-1

= 27