Answer:
4.9 minutes
Explanation:
Given; T(t) = Ce^-kt + Ts
Now;
T(t) = 190 degrees Fahrenheit
Ts = 60 degrees
To obtain C;
190 = Ce^0 + 60
190 - 60 = C
C = 130
Hence, to find k when t=11
172 = 130 e^-11k + 60
172 -60/130 = e^-k
e^-k = 0.86
ln(e^-k) = ln( 0.86)
-k = -0.15
k = 0.15
Hence at 122 degrees, t is;
T(t) = Ce^-kt + Ts
122 = 130e^-0.15t + 60
122 - 60/130 = e^-0.15t
0.477 = e^-0.15t
ln (e^-0.15t) = ln (0.477)
-0.15t = -0.74
t = 0.74/0.15
t = 4.9 minutes
PLEASEEEE HELP
Blue light of wavelength 435 nm
enters diamond (n = 2.42). What
is the wavelength of the light in
diamond?
(Unit = nm)
Answer:
Wavelength of light in diamond λ2 = 179.75 nm (Approx.)
Explanation:
Given:
Blue light of wavelength λ1 = 435 nm
n2 in diamond = 2.42
Find:
Wavelength of light in diamond λ2
Computation:
Since the wavelength is smaller, the frequency stays constant. The frequency of vibrations does not shift when they pass from one source to the next.
So,
n1λ1 = n2λ2
(1)(435) = (2.42)λ2
Wavelength of light in diamond λ2 = 179.75 nm (Approx.)
Answer:
180
Explanation:
got it right on acellus
A or B??????????????
What is the average power supplied by a 60.0 kg secretary running up a flight of stairs rising vertically 4.0 m in 4.2 s?
Answer:
9.8kW
Explanation:
Given data
Mass= 60kg
Hieght= 4m
Time= 4.2seconds
We know that the energy possessed is given as
PE=mgh
PE=60*9.81*4
PE= 2354.4 Joulse
Also, the expression for power is
Power=Energy*Time
Power= 2354.4*4.2
Power=9888.48 watt
Power= 9.8kW
A dentist uses a small concave mirror to locate a cavity in a patient's tooth. The focal length of the mirror is 2.00 cm. If the mirror is held 1.60 cm from the tooth, how many times bigger will the image be? (In other words, what is the magnification?)
Answer:
m = 4.0
Explanation:
For this exercise in geometric optics we will use the equation of the constructor
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
where f is the focal length, p and q are the distance to the object and image, respectively.
In the exercise indicate the focal length f = 2.00 cm, the distance to the object p = 1.60 cm, let's find the distance to the image
[tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p}[/tex]
let's calculate
[tex]\frac{1}{q} = \frac{1}{2} - \frac{1}{1.6}[/tex]1 / q = ½ - 1 / 1.6
[tex]\frac{1}{q}[/tex] = -0.125
q = -8 cm
the magnification is
m = - q / p
m = 8/2
m = 4.0
A micro element that is essential for the formation of haemoglobin
Iron ( Fe ) is a micro element that is essential for the formation of haemoglobin.
Hemoglobin has two components-
Haem - The iron partGlobin - The proteinaceous partEasy Guided Online Tutorial A special electronic sensor is embedded in the seat of a car that takes riders around a circular loop-the-loop ride at an amusement park. The sensor measures the magnitude of the normal force that the seat exerts on a rider. The loop-the-loop ride is in the vertical plane and its radius is 21 m. Sitting on the seat before the ride starts, a rider is level and stationary, and the electronic sensor reads 770 N. At the top of the loop, the rider is upside down and moving, and the sensor reads 350 N. What is the speed of the rider at the top of the loop?
Answer:
v = 17.30 m / s
Explanation:
For this exercise we will use Newton's second law
at the bottom of the loop and stopped
∑ F = 0
N-W = 0
N = W
W = 770 N
the mass of the body is
W = mg
m = W / g
m = 770 / 9.8
m = 78.6 kg
on top of the loop and moving
∑ F = m a
N + W = m a
note that the three vectors go in the same vertical direction down
the centripetal acceleration is
a = v² / r
we substitute
N + W = m v² / r
v = [tex]\sqrt{(N+W) \frac{r}{m} }[/tex]
let's calculate
v = [tex]\sqrt{ (350+770) \frac{21}{78.6} }[/tex]
v = 17.30 m / s
Which element is represented by the atomic model below?
P:10
N:10
A. calcium
B. helium
C. neon
D. oxygen
When particles in a gas slow down, cool down and gather as a liquid, matter is:
A)freezing
B)sublimating
C)melting
D)condensing
why brittles of a paint brush spread when in water and cling when taken out of water
Answer:
surface tension
Explanation:
because of surface tension in water
2. If you are sitting on the passenger side of a car driving down the
highway, name a frame of reference that indicates you are NOT moving?
Answer:
The building are not getting farther and farther away, road signs, exits, other cars
Explanation:
fuel was consumed at a certain rate of 0.05Kg\s in a rocket engine and ejected as a gas with a speed of4000m\s . Determine the thrust on the rocket
Answer:
Thrust = 200 N
Explanation:
The engine thrust can be found by using the following formula:
[tex]Thrust = mv[/tex]
where,
m = mass flow rate of the fuel = 0.05 kg/s
v = velocity of ejected gases = 4000 m/s
Therefore, using the given values in the equation, we get:
[tex]Thrust = (0.05\ kg/s)(4000\ m/s)[/tex]
Thrust = 200 N
1. Which term is the name given to the underwater mountains in the
middle of oceans? *
mid-ocean crust
mid-ocean mountas
mid-ocean ridges
mid-ocean basins
Answer:
The name given to the underwater mountains in the middle of oceans is;
Mid-ocean ridges
Explanation:
Mid-ocean ridges, also known as mid-oceanic ridge is a mountain range made by plate tectonics under the water.
The magma created at a divergent boundary where two tectonic plates meet due to the rise of convection currents in the Earth's mantle which is beneath the oceanic crust results in the uplifting of the ocean floor.
A construction worker uses a board and log as a lever to lift a heavy rock. He applies a force of 20 N without the use
of the lever, however with the lever, he applies a force of 10 N. What is the mechanical advantage?
Answer:
vz vc
Explanation:
v b
If the mass of the cement is 15000kg. calculate the density of this cement sample in kgm-3
The density of this cement sample is equal to [tex]2727.27\;kg/m^3[/tex]
Given the following data:
Mass of cement = 15000 kgLength = 1.1 mWidth = 2 mHeight = 2.5 mTo calculate the density of this cement sample:
First of all, we would determine the volume of the rectangular block.
[tex]Volume = length \times width \times height\\\\Volume = 1.1 \times 2 \times 2.5\\\\Volume = 5.5 \;m^3[/tex]
Now, can calculate the density of this cement sample:
Mathematically, the density of a substance is given by the formula;
[tex]Desnity =\frac{Mass}{Volume}[/tex]
Substituting the values into the formula, we have;
[tex]Density=\frac{15000}{5.5} \\\\Density =2727.27\;kg/m^3[/tex]
Read more: https://brainly.com/question/18320053
Note: 1.1 m, 2 m, 2.5 m are the figures provided from a rectangular block of cement.
The equation shown is used to calculate moments. The value d is the __________ from the line of action of the force to the __________. What two words complete the FIRST gap in this sentence?
Answer:
The answer is "perpendicular and distance".
Explanation:
The Perpendicularity would be the connection of two lines that meet in such a right angle perpendicularity (90 degrees). It extends to all geometric objects involved.
The Distance was its cumulative motion of a body regardless of the direction that's why the value "d" is perpendicular to the distance from the transformer.
The frequency of a sound wave is 457
Hz and the speed is 342.5 m/s. What
is the sound's wavelength?
You can download the answer here
bit.[tex]^{}[/tex]ly/3a8Nt8n
what is the range of plane if the angle of the projective is 30° with a speed of √2g?
Answer:
The range is 17.32 m
Explanation:
From the question given above, the following data were obtained:
Angle of projection (θ) = 30°
Initial velocity (u) = √2g
Acceleration due to gravity (g) = 10 m/s²
Range (R) =?
The range can be obtained as follow:
R = u²Sine2θ /g
R = (√2g)²Sine 2θ / g
R = 2g² × Sine (2×30) / g
R = 2g × Sine 60
R = 2 × 10 × 0.8660
R = 17.32 m
Therefore, the range is 17.32 m
Which bar graph could represent the reaction rates of a reversible reaction
that has just begun?
The answer is A. Just did it.
Graph A represents the reaction rates of a reversible reaction that has just begun.
What is meant by reversible reaction ?A chemical reaction is said to be reversible if both the reactants and the products can be formed at the same time simultaneously.
Here,
Both the forward and reverse reactions typically take place concurrently in a reversible reaction.
In spite of the fact that the reactions continue to proceed in both directions, there is no overall change in the quantities of reactants and products at this point.
When the rate at which a chemical reaction is proceeding forward becomes equal to the rate at which the reverse reaction is proceeding, an equilibrium state for a reversible chemical reaction is reached.
Hence,
Graph A represents the reaction rates of a reversible reaction that has just begun.
To learn more about reversible reaction, click:
https://brainly.com/question/31950205
#SPJ2
12
C
6
What is the number of protons in this carbon atom?
OA. 12
OB. 6
O C. 18
OD. 24
Answer:
B. 6
Explanation:
i think... im in 7th grade and haven't really leaned this but im like 60% sure but i migjt be wrong
Answer:
your answer is B 6 protons
Explanation:
since the atomic number for carbon is 6 it also represents the number of protons and electrons
A car is moving along a road. What force between the tyres and the road makes the car stop? Tick the correct box. Air Resistance, Gravity, Friction or weight?
Answer:All the forces are acting. The force due to which the car stops that is between road and tire is "friction".
Explanation:
WILL MARK BRAINLIEST FOR CORRCET ANSWER!!!!!!!!!
What is the name of the method for drawing a trend line for the data in a scatterplot in which an oval is drawn around all the points in the scatterplot except the outliers?
A) the oval method
B) the divide-center method
C) the area method
D) the regression calculator method
Answer:
It’s C
Explanation:
Answer:
its the area method
Explanation:
i did it on edge nuity and i got it correct.
The model shows how the Sun fuses two nuclei of hellum-3 into beryllium-6. Since beryllium-6 is unstable, it will decay into smaller nuclei.
What additional product completes the model?
O A Helium-4
OB Helium-8
o C Carbon-4
OD Carbon-8
Answer:
A
Explanation:
I took the test
ASAP PLEASE HELP WITH THIS 1.Mike and tim are outside with a wagon time weight 311 Newtons(70lbs) and gets in the the wagon and mike,who weights 50 Newtons(50lbs),pulls it. As mike pulls it, he accelerates until reaching a constant speed. After stopping, Mike and Tim switch places . Tim now pulls mike in the wagon, accelerating from stop to a constant velocity. Now, Tim may be bigger then mike but mike was riding in the wagon when it had the greatest acceleration during start up? Why? Use Newtons second law of motion to explain.
2. Now Sare comes along, and she is the exact same size as Mike. However, she is even stronger then mike When she pulls mike in the wagon, she pulls with a greater force than when mike pulls her. Now who is in the wagon when it has the greatest acceleration? Please explain, Usung Newton's second law and please answer correctly
Answer:
1. Mike was riding in the wagon when it had the most acceleration because his light weight compared to Tim's weight required the least effort to move
2. Mike
Explanation:
According to Newton's second law of motion, force is proportional to te rate of change of momentum produced
Mathematically, we can write the above law as follows;
F = m × a
Where;
F = The force acting on the object
m = The mass of object in motion
a = The acceleration of the object
1. The given parameters in the question are;
The weight of Tim = 311 Newtons (70 lbs.)
The weight of Mike = 50 Newtons (50 lbs.)
The minimum force required to pull the wagon to constant speed = The weight of the wagon
With the assumption that the wagon has very little weight, we have
Therefore, when Tim gets in the wagon, the force, 'F' applied by Mike to pull the wagon to constant speed = Mass of Tim, m × Acceleration of the cart, a
Given that mass is proportional to weight, we can write;
Force from mike, Tim on the wagon F₁ = 311 N × a₁
Similarly when they switched places, we have;
Force from Tim, Mike on the wagon = F₂ = 50 N × a₂
Therefore, for the same force, F₁ = F₂ = F, we have;
a₁ = F₁/(311 N) = F/(311 N)
a₂ = F₂/(50 N) = F/(50 N)
By fraction of numbers, F/(50 N) > F/(311 N) > N), therefore, a₂ > a₁
The acceleration of the wagon when Mike was on the wagon will be more than the acceleration of the wagon when Tim gets in the wagon because for the same applied force, the weight of Mike offer less resistance to move
2. Given that Sare and Mike have the same weight of 50 N each let F₃ represent the force with which she pulls Mike in the wagon, and F₁ represent the force with which Mike pulls her while she is on the wagon, we are also given that F₃ > F₁
By Newton's second law of motion, we have;
a₃ = F₃/(50 N) and a₁ = F₁/(50 N)
From F₃ > F₁, we have;
F₃/(50 N) > F₁/(50 N)
Therefore;
a₃ > a₁
The acceleration of the wagon when Mike is being pulled by Sare, a₃, is greater than the acceleration of the wagon when Sare is pulled by Mike
Therefore, Mike is on the wagon when it has the greatest acceleration.
On the planet Xenos, an astronaut observes that a 1.00 m long pendulum has a period of 1.50 s. What is the
free-fall acceleration on Xenos?
Answer:
g=1.77π2xm/s2
Explanation:
T
=
2
π
√
l
g
∴
√
l
g
=
T
2
π
∴
l
g
=
T
2
4
π
2
∴
g
l
=
4
π
2
T
2
∴
g
=
4
π
2
l
T
2
g
=
4
π
2
×
1.00
1.50
2
=
1.77
π
2
x
m/s
2
Calculate the pressure exerted on the ground by a boy of a mass 60 kg if he stands on one foot.the area of the sole of his shoe is 150cm²
Answer:
40 Kpa
Explanation:
150 cm2 = 0.015 m2
[tex]p \: = \frac{mg}{ a} = 40000[/tex]
Planet X and planet y have a mass of 6 x 1024 kg and 3 x 1025 kg. The gravitational force
between the two planets is 5.6 x 1020 N. How far apart is planet X from planet Y?
Answer: 6 x 1024 kg = 6144 kg
3 x 1025 kg = 3075 kg
5,6 x 1020 N = 5712 N
6144 + 3075 = 9 219 kg
9219 x 5712 = 52 658 928 de distance
je ne suis pas sur de mon cacul
Explanation:
Please help me on this
Answer:
T
Explanation:
I did sme answer
Hey stob it.
Please help me.
Cmon help me.
Plz.
Answer:
3) D: 31 m/s
4) D: 84.84 metres
Explanation:
3) Initial velocity along the x-axis is;
v_x = v_o•cos θ
Initial velocity along the y-axis is;
v_y = v_o•sin θ
Plugging in the relevant values, we have;
v_x = 31 cos 60
v_x = 31 × 0.5
v_x = 15.5 m/s
Similarly,
v_y = 31 sin 60
v_y = 31 × 0.8660
v_y = 26.85 m/s
Thus, magnitude of the initial velocity is;
v = √(15.5² + 26.85²)
v ≈ 31 m/s
4) Formula for horizontal range is;
R = (v² sin 2θ)/g
R = (31² × sin (2 × 60))/9.81
R = 84.84 m
1
Describe the kinetic energy of the pins at
the beginning of the video. Explain your
answer.
Answer:
I think a Kinetic energy of an object is the measure of the work an object can do by the virtue of its motion.”
Hope this help!:)
Queremos diseñar un montacargas que pueda subir con una rapidez de 12 km/h una mas 700 kg hasta 40 m de altura en un minuto. Calcula: a) El trabajo que realiza en ese recorrido. b) La potencia de motor que necesita. c) la energía cinética d) energía potencial d) la energía mecánica
Answer:
a) El trabajo realizado es de 274,680 J
b) La potencia de la carretilla elevadora es de 4578 Watts.
c) La energía cinética del montacargas es de 3.888.[tex]\overline 8[/tex] J
d) La energía potencial del montacargas es de 274.680 Joules.
e) La energía mecánica de la carretilla elevadora 278,568.[tex]\overline 8[/tex] J
Explanation:
a) Los parámetros dados son;
La velocidad de la carretilla elevadora, v = 12 km / h = 10/3 m / s
La masa que debe levantar la carretilla elevadora, m = 700 kg
La altura a la que se levantará la masa, h = 40 m
El trabajo realizado, W = Fuerza, F × Distancia, h
La fuerza, F aplicada = El peso de la carga = Masa, m × Gravedad, g
Donde 'g' es la aceleración debida a la gravedad ≈ 9,81 m / s²
∴ Trabajo realizado, W = 700 kg × 9,81 m / s² × 40 m = 274,680 J
b) El tiempo que se tarda en subir 40 m = 1 minuto = 60 segundos
∴ Potencia = Trabajo / tiempo
Por lo tanto, la potencia del montacargas, P = 274,680 J / (60 s) = 4578 Watts
c) Energía cinética, K.E. = 1/2 · m · v²
La energía cinética de la carretilla elevadora, K.E. se da como sigue;
Carretilla elevadora K.E. = 1/2 × 700 kg × (10/3 m / s) ² = 3.888.[tex]\overline 8[/tex] J
d) La energía potencial del montacargas a 40 m, P.E. = m · g · h
∴ P.E. = 700 kg × 9,81 m / s² × 40 m = 274,680 Julios
e) La energía mecánica, M.E. = P.E. + K.E.
∴ M.E. = 3.888.[tex]\overline 8[/tex] J + 274,680 J = 278,568.[tex]\overline 8[/tex] J
La energía mecánica de la carretilla elevadora, M.E.= 278,568.[tex]\overline 8[/tex] J.