nside of your organization that checks how often client machines access it. If a client machine hasn't accessed the server in three months, the server won't allow the client machine to access its resources anymore. What can you set to make sure that your client machines and the server times are in sync

Answer:

The programming language is not stated (I'll answer using C++)

#include <iostream>

using namespace std;

int convert(float miles)

{

   return miles * 5280;

}

int main() {

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   while(response == 'y')

   {

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   }

   cout<<"Bye!";

   return 0;

}

Explanation:

Here, I'll explain some difficult lines (one after the other)

The italicized represents the function that returns the number of feet

int convert(float miles)

{

   return miles * 5280;

}

The main method starts here

int main() {

The next two lines gives an info about the program

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

This line prompts user for number of miles

   cout<<"How many miles did you walk?. ";

   cin>>miles;

This line calls the function that converts miles to feet and prints the feet equivalent of miles

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

This line prompts user for another conversion

   cout<<"Continue? (y/n): ";

   cin>>response;

This is an iteration that repeats its execution as long as user continue input y as response

   while(response == 'y')

   {

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   }

   cout<<"Bye!";

Answer:

c. suffer from indefinite postponement.

Explanation:

Algorithm is a set of rules that are followed in calculations or other problem solving operation by a computer. An algorithm may execute for unknown amount of time and it may suffer indefinite postponement. Algorithm depends on random numbers and it can execute continuously.

Answer:The new directory method creates a new directory within the current working directory.

Explanation:The new directory function and returns the list of the files within that directory.The new directory function allow to with the built in function MK dir().

To the new directory function create a current working directory.

import OS

OS.MKdir()

The code creates the directory projects in the current working directory to specify the full path.

Answer:

x1 = 39

x2 = 400

x3 = 92

x4 = 62

x5 = 0

Explanation:

This statement calls the f() function passing 2 to the function. The f(x) function takes a number x as parameter and returns the following:

g(x) + math.sqrt(h(x))

This again calls function g() and h()  

The above statement calls g() passing x i.e. 2 to the function g(x) and calls function h() passing x i.e. 2 to h() and the result is computed by adding the value returned by g() to the square root of the value returned by the h() method.

The g(x) function takes a number x as parameter and returns the following:

return 4*h(x)

The above statement calls function h() by passing value 2 to h() and the result is computed by multiplying 4 with the value returned by h().

The h(x) function takes a number x as parameter and returns the following:

return x*x + k(x)-1

The above statement calls function k() by passing value 2 to k() and the result is computed by subtracting 1 from the value returned by k() and adding the result of x*x (2*2) to this.

The k(x) function takes a number x as parameter and returns the following:

return 2 * (x + 1)

As the value of x=2 So

2*(2+1) = 2*(3) = 6

So the value returned by k(x) is 6

Now lets go back to the function h(x)

return x*x + k(x)-1

x = 2

k(x) = 6

So

x*x + k(x)-1 = 2*2 + (6-1) = 4 + 5 = 9

Now lets go back to the function g(x)

return 4*h(x)

As x = 2

h(x) = 9

So

4*h(x)  = 4*9 = 36

Now lets go back to function f(x)

return g(x) + math.sqrt(h(x))

As x=2

g(x) = 36

h(x) = 9

g(x) + math.sqrt(h(x))  = 36 + math.sqrt(9)

                                  = 36 + 3 = 39

Hence

The above statement means that first the function g() calls function h() and function h() is passed a value i.e 2.

As x=2

The function k() returns:

2 * (x + 1)   = 2 * (2 + 1) = 6

The function h() returns:

x*x + k(x)-1 = 2*2 + (6-1) = 4 + 5 = 9

Now The function g() returns:

4 * h(x)  = 4 * h(9)

This method again calls h() and function h() calls k(). The function k() returns:

2 * (x + 1)   = 2 * (9 + 1) = 20

Now The function h() returns:

x*x + k(x)-1 = 9*9 + (20-1) = 81 + 19 = 100

h(9) = 100

Now The function g() returns:

4 * h(x)  = 4 * h(9) = 4 * 100 = 400

Hence

g() returns:

return 4 h(x)

h() returns:

return x*x + k(x)-1

k(2) returns:

return 2 (x + 1)

          = 2 ( 3 ) = 6

Now going back to h(2)

x * x + k(x)-1  = 2*2 + 6 - 1 = 9

Now going back to g(2)

4 h(x)  = 4 * 9 = 36

So k(g(2) + h(2)) becomes:

   k(9 + 36 )

    k(45)

Now going to k():

return 2 (x + 1)

2 (x + 1)   = 2(45 + 1)

             = 2(46)

             = 92

So k(g(2) + h(2)) = 92

Hence

Compute f(0)

f() returns:

return g(0) + math.sqrt(h(0))

f() calls g() and h()

g() returns:

return 4 * h(0)

g() calls h()

h() returns

return 0*0 + k(0)-1

h() calls k()

k() returns:

return 2 * (0 + 1)

2 * (0 + 1)  = 2

Going back to caller function h()

Compute h(0)

0*0 + k(0)-1  = 2 - 1 = 1

Going back to caller function g()

Compute g(0)

4 * h(0)  = 4 * 1 = 4

Going back to caller function f()

compute f(0)

g(0) + math.sqrt(h(0))  = 4 + 1 = 5

f(0) = 5

Compute f(1)

f() returns:

return g(1) + math.sqrt(h(1))

f() calls g() and h()

g() returns:

return 4 * h(1)

g() calls h()

h() returns

return 1*1 + k(1)-1

h() calls k()

k() returns:

return 2 * (1 + 1)

2 * (1 + 1)  = 4

Going back to caller function h()

Compute h(0)

1*1 + k(1)-1  = 1 + 4 - 1 = 4

Going back to caller function g()

Compute g(1)

4 * h(1)  = 4 * 4 = 16

Going back to caller function f()

compute f(1)

g(1) + math.sqrt(h(1))  = 16 + 2 = 18

f(1) = 18

Compute f(2)

f() returns:

return g(2) + math.sqrt(h(2))

f() calls g() and h()

g() returns:

return 4 * h(2)

g() calls h()

h() returns

return 1*1 + k(2)-1

h() calls k()

k() returns:

return 2 * (2+1)

2 * (3)  = 6

Going back to caller function h()

Compute h(2)

2*2 + k(2)-1  = 4 + 6 - 1 = 9

Going back to caller function g()

Compute g(2)

4 * h(2)  = 4 * 9 = 36

Going back to caller function f()

compute f(2)

g(2) + math.sqrt(h(2))  = 36 +3 = 39

f(1) = 13.7

Now

x4 = f(0) + f(l) + f(2)

    = 5 + 18 + 39

    = 62

Hence  

Compute f(-1)

f() returns:

return g(-1) + math.sqrt(h(-1))

f() calls g() and h()

g() returns:

return 4 * h(-1)

g() calls h()

h() returns

return 1*1 + k(-1)-1

h() calls k()

k() returns:

return 2 * (-1+1)

2 * (0)  = 0

Going back to caller function h()

Compute h(-1)

-1*-1 + k(-1)-1  = 1 + 0 - 1 = 0

Going back to caller function g()

Compute g(-1)

4 * h(-1)  = 4 * 0 = 0

Going back to caller function f()

compute f(-1)

g(-1) + math.sqrt(h(-1))  = 0

f(-1) = 0

Compute g(-1)

g() returns:

return 4 * h(-1)

g() calls h()

h() returns

return 1*1 + k(-1)-1

h() calls k()

k() returns:

return 2 * (-1+1)

2 * (0)  = 0

Going back to caller function h()

Compute h(-1)

-1*-1 + k(-1)-1  = 1 + 0 - 1 = 0

Going back to caller function g()

Compute g(-1)

4 * h(-1)  = 4 * 0 = 0

g(-1) = 0

Compute h(-1)

h() returns

return 1*1 + k(-1)-1

h() calls k()

k() returns:

return 2 * (-1+1)

2 * (0)  = 0

Going back to caller function h()

Compute h(-1)

-1*-1 + k(-1)-1  = 1 + 0 - 1 = 0

h(-1) = 0

Compute k(-1)

k() returns:

return 2 (x + 1)

k(-1) = 2 ( -1 + 1 ) = 2 ( 0 ) = 0

k(-1) = 0

x5 = f(-1) + g(-1) + h(-1) + k(-1)

    = 0  + 0 + 0 + 0

    = 0

Hence

Answer:

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

   const int WEIGHT_MIN   =    0,

             WEIGHT_MAX   =   20,

             DISTANCE_MIN =   10,

             DISTANCE_MAX = 3000;

   float package_weight,

         distance,

         total_charges;

   cout << "\nWhat is the weight (kg) of the package? ";

   cin >> package_weight;

   if (package_weight <= WEIGHT_MIN ||

       package_weight > WEIGHT_MAX)

   {

       cout << "\nWe're sorry, package weight must be\n"

            << " more than 0kg and less than 20kg.\n"

            << "Rerun the program and try again.\n"

            << endl;

   }

   else

   {

       cout << "\nDistance? ";

       cin >> distance;

       if (distance < DISTANCE_MIN ||

           distance > DISTANCE_MAX)

       {

           cout << "\nWe're sorry, the distance must be\n"       << "within 10 and 3000 miles.\n"

                << "Rerun the program and try again.\n"

                << endl;

       }

       else

       {

            if (package_weight <= 2)

               total_charges = (distance / 500) * 1.10;

           else if (package_weight > 2 &&

                   package_weight <= 6)

               total_charges = (distance / 500) * 2.20;

           else if (package_weight > 6 &&

                   package_weight <= 10)

               total_charges = (distance / 500) * 3.70;

           else if (package_weight > 10 &&

                   package_weight <= 20)

               total_charges = (distance / 500) * 4.80;

           cout << setprecision(2) << fixed

               << "Total charges are $"

               << total_charges

               << "\nFor a distance of "

               << distance

               << " miles\nand a total weight of "

               << package_weight

               << "kg.\n"

               << endl;

       }

   }

Explanation:

Answer:

/etc/yum.conf

Explanation:

The absolute pathname for YUM is /etc/yum.conf. The configuration file For yum and related utilities can be found there. The file has one compulsory section, and this section can be used to place Yum options with global effect, it could also have one or more sections, that can enable you to set repository-specific options.

Answer:

The answer is "For the stop and wait the value of S and R is equal to 1".

Explanation:

Answer:

ADAC uses powershell

Domain Local, Global, and Universal are examples of group scenes

Explanation:

Active directory software is suitable for directory which is installed exclusively on Windows network. These directories have data which is shared volumes, servers, and computer accounts. The main function of active directory is that it centralizes the management of users.

It should be noted thst statements are true about managing through Active Directory are;

Active Directory can be regarded as directory service that is been put in place by  Microsoft and it serves a crucial purpose for Windows domain networks.

It should be noted that in managing through Active, ADAC uses powershell.

Therefore, in active directory Domain Local, Global, and Universal are examples of group scenes .

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Answer:

Can be executed on multiple platforms.

Explanation:

A program is portable if it is not platform dependent. In other words, if the program is not tightly coupled to a particular platform, then it is said to be portable. Portable programs can run on multiple platforms without having to do much work. By platform, we essentially mean the operating system and hardware configuration of the machine's CPU.

Examples of portable programs are those written in;

i. Java

ii. C++

iii. C

Answer:

What-If Analysis in Excel allows you to try out different values (scenarios) for formulas. The following example helps you master what-if analysis quickly and easily.

Assume you own a book store and have 100 books in storage. You sell a certain % for the highest price of $50 and a certain % for the lower price of $20.

(i really hope this is what u needed)

Answer:

Joyner

David

USA

1.8

30

Explanation:

def saveUserProfile(firstName, lastName, age, height, country):

This is the definition of function named saveUserProfile which accepts the following parameters:

filename = lastName + firstName + ".txt"

When the file is created it will be named as the lastName and firstName string combined with .txt as extension. For example if the lastName contains the name string Joyner and firstName contains the name David then the file created to be written is named as JoynerDavid.txt

outputFile = open(filename, "w")

This statement uses open() method in write mode and uses outputFile object to access the file. "w" represents write mode i.e. file is opened in write mode to write on it.

a) Joyner is written on line 1 of that file because of the following statement of above function:

print(lastName, file = outputFile)

This statement prints the string stored in lastName i.e. Joyner. Here outputFile opens the file in "w" write mode and writes the last name to the first line of the file.

b) David is written on line 2 of that file because of the following statement of above function:

print(firstName, file = outputFile)

This statement prints the string stored in firstName i.e. David. Here outputFile opens the file in "w" write mode and writes the first name to the second line of the file.

c) USA is written on line 3 of that file because of the following statement of above function:

print(country, file = outputFile)

This statement prints the data stored in country i.e. USA. Here outputFile opens the file in "w" write mode and writes the country name to the third line of the file.  

d) 1.8 is written on line 4 of that file because of the following statement of above function:

print(height, file = outputFile)

This statement prints the value stored in height i.e. 1.8. Here outputFile opens the file in "w" write mode and writes the height value to the fourth line of the file.  

e) 30 is written on line 5 of that file because of the following statement of above function:

print(age, file = outputFile)

This statement prints the value stored in age parameter of function saveUserProfile i.e. 30. Here outputFile opens the file in "w" write mode and writes the age value to the fifth line of the file.  

Answer:

Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?

Explanation:

Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?

Answer:

Because your movements, expressions, and posture are also a type of communication

Explanation:

Answer:brain

Explanation:

to think

Answer:

Because if you don't do it BIOS doesn't support it. ... In troubleshooting a boot problem what would be the point of disabling the quick boot feature in BIOS setup

Explanation:

Answer:

I am writing a C program.

#include <stdio.h> // for using input output functions

#include <stdbool.h> // for using a bool value as data type

int main() { // start of the main() function body

 int count=0; //count the number of entries

 double gallons, miles, MilesperGallon, combined_avg, sum; //declare variables

 while(true) {// takes input gallons and miles value from user and computes avg miles per gallon

      printf( "Enter the gallons used (-1 to stop): \n" ); //prompts user to enter value of gallons or enter -1 to stop

      scanf( "%lf", &gallons );//reads the value of gallons from user

   if ( gallons == -1 ) {// if user enters -1

     combined_avg = sum / count; //displays the combined average by dividing total of miles per drives to no of entries

     printf( "Combined miles per gallon for all tankfuls:  %lf\n", combined_avg ); //displays overall average value  

     break;} //ends the loop

     printf( "Enter the miles driven: \n" ); //if user does not enter -1 then prompts the user to enter value of miles

     scanf( "%lf", &miles ); //read the value of miles from user

MilesperGallon = miles / gallons; //compute the miles per gallon

printf( "The miles per gallon for tankful:  %lf\n", MilesperGallon ); //display the computed value of miles per gallon

  sum += MilesperGallon; //adds all the computed miles per gallons values

   count += 1;  } } //counts number of tankfuls (input entries)

Explanation:

The program takes as input the miles driven and gallons used for each tankful. These values are stored in miles and gallons variables. The program calculates and displays the miles per gallon MilesperGallon obtained for each tankful by dividing the miles driven with the gallons used. The while loop continues to execute until the user enters -1. After user enters -1, the program calculates and prints the combined miles per gallon obtained for all tankful. At the computation of MilesperGallon for each tankful, the value of MilesperGallon are added and stored in sum variable. The count variable works as a counter which is incremented to 1 after each entry. For example if user enters values for miles and gallons and the program displays MilesperGallon then at the end of this iteration the value of count is incremented to 1. This value of incremented for each tankful and then these values are added. The program's output is attached.

Answer:

Subject line

Explanation:

Editing the subject line is very important so as to enable the recipient know the source of received the message (document).

For example, if a remote team working on a project called Project X receives a shared document by one member of team, we would expect the subject line of the email to be– Project X document. By so doing the legitimacy of the email is easily verified.

Answer:

b. SIEM.

Explanation:

In this scenario, an organization is struggling to differentiate threats from normal traffic and access to systems. A security engineer has been asked to recommend a system that will aggregate data and provide metrics that will assist in identifying malicious actors or other anomalous activity throughout the environment. The solution the engineer should recommend is the Security information and event management (SIEM).

Security information and event management is an enterprise software that provides a holistic view and analyzes activity from various resources across an entire information technology (IT) infrastructure.

The SIEM is used to aggregate important data from multiple source such as servers, routers, firewall, switches, domain controllers, antivirus software and analyzes the data to detect any threat, deviation from the norm, as well as investigate in order to take appropriate actions. Some examples of the SIEM system are IBM QRadar, Splunk, LogRhythm etc.

Answer:

//Method definition

//Method receives a String argument and returns a String value

public static String removeDuplicates(String str){

       //Create a new string to hold the unique characters

       String newString = "";

       //Create a loop to cycle through each of the characters in the

       //original string.

       for(int i=0; i<str.length(); i++){

           // For each of the cycles, using the indexOf() method,

           // check if the character at that position

           // already exists in the new string.

           if(newString.indexOf(str.charAt(i)) == -1){

               //if it does not exist, add it to the new string

               newString += str.charAt(i);

           }  //End of if statement

       }   //End of for statement

       return newString;   // return the new string

   }  //End of method definition

Sample Output:

removeDuplicates("bookkeeeeeper") => "bokeper"

Explanation:

The above code has been written in Java. It contains comments explaining every line of the code. Please go through the comments.

The actual lines of codes are written in bold-face to distinguish them from comments. The program has been re-written without comments as follows:

public static String removeDuplicates(String str){

       String newString = "";

       for(int i=0; i<str.length(); i++){

           if(newString.indexOf(str.charAt(i)) == -1){

               newString += str.charAt(i);

           }

       }

       return newString;

   }

From the sample output, when tested in a main application, a call to removeDuplicates("bookkeeeeeper") would return "bokeper"

Answer: DHCP (dynamic host configuration protocol)  is a protocol which automatically processes the configuring devices on IP networks.It allows them to to use network services like: NTP and any communication proto cal based on UDP or TCP. DHCP assigns an IP adress and other network configuration parameters to each device on a network so they can communicate with  other IP networks. it is a part of DDI solution.

Explanation:

Answer:

A. These describe the authority level of workers, fair payment practices, communication channels, and the like.  

Explanation:

As seen in the question above, you have been asked to write the project management plan and know that you need to consider elements such as policies, rules, systems, relationships and standards in the organization. These elements are part of EEF's entry into this process, in addition they are fundamental and indispensable for the description not only of the organizational governance structure, but also describe the management elements that will be adopted and used.

However, there is no way to use them to describe the level of authority of workers, fair payment practices, communication channels and the like, as this is not the function of this.

Answer:

Following are the code to this question:

Defining method shiftLeft:

def shiftLeft(bit_string): #defining method shiftLeft, that accepts parameter bit_string

   bit_string= bit_string[1:]+bit_string[0]#use bit_string to provide slicing

   return bit_string#return bit_string value

bit_string =input("Enter value: ")#defining bit_string variable for user input

print (shiftLeft(bit_string))#use print method to call shiftLeft method

Defining method shiftRight:

def shiftRight(bit_string):#defining method shiftRight, which accepts bit_string variable

bit_string=bit_string[len(bit_string)-1]+bit_string[0:len(bit_string)-1]#using bit_string variable for slicing

   return bit_string#return bit_string calculated value

bit_string= input("Enter value: ")#defining bit_string variable for user input

print(shiftRight(bit_string))#use print method to call shiftLeft method

Output:

Please find the attachment.

Explanation:

method description:

Answer:

The summary including its given problem is outlined in the following section on the interpretation.

Explanation:

That's not entirely feasible, since at least n similarities have to be made to order n quantities. Find the finest representation where the numbers of 1 to 10 have already been arranged.

⇒ 1 2 3 4 5 6 7 8 9 10

Let's say that we identify one figure as the key then compared it towards the numbers across the left. Whether the correct number is greater, therefore, left number, are doing nothing to switch the location elsewhere.

Because although the numbers have already been categorized 2 has always been compared to 1 which would be perfect, 3 becomes especially in comparison to 2 and so much more. This should essentially take 9 moves, or nearly O(n) moves.

If we switch that little bit already

⇒ 1 3 2 4 5 6 7 8 9 10

3 Is contrasted with 1. 2 will indeed be matched against 3 as well as 2. Since 2 has indeed been exchanged, it must, therefore, be matched with 1 as there might be a case whereby each number z exchanged is greater than the number Y as well as the quantity X < Y.

Only one adjustment expanded the steps which culminated in n+1.

It should be noted that it won't be possible because at least n similarities have to be made to order n quantities.

From the information given, it should be noted that it's not possible for the engineer to implement an algorithm that can sort n elements (e.g., numbers) in fewer than n steps.

This is because there are at least n similarities have to be made to order n quantities. In this case, the numbers of 1 to 10 have already been arranged. When a number is greater, it should be noted that the left number will do nothing to switch the location elsewhere.

Therefore, the information given by the engineer isn't feasible.

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Answer:

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

   double side, height;

   cout<<"Enter the length of one of the sides of the base: ";

   cin>>side;

   cout<<"Enter the height: ";

   cin>>height;

   double area = side * side;

   double volume = area * height / 3;

   cout<<"The area of the base of the pyramid is: "<<area<<endl;

   cout<<"The height of the pyramid is: "<<height<<endl;

   cout<<"The volume of the pyramid is: "<<fixed<<setprecision(2)<<volume<<endl;

   return 0;

}

Pseudocode:

Declare side, height

Get side

Get height

Set area = side * side

Set volume = area * height / 3

Print area

Print height

Print volume

Explanation:

Include <iomanip> to have two decimal places

Declare the side and height

Ask the user to enter side and height

Calculate the base area, multiply side by side

Calculate the volume using the given formula

Print area, height and volume (use fixed and setprecision(2) to have two decimal places)

Answer:

c. a key found on Windows-oriented computer keyboards.

Explanation:

Hope it helps.

Answer: CSIRT

Explanation: CSIRT is team that specializes in day to day cyber incidents  

The CSIRT is responsible for creating and testing the incident response plan.

CSIRT is the Computer emergency response team. One of the key areas for the efficient operation of a corporation is the legal department. Professionals face enormous challenges, particularly when you take into account the need for other bodies within the company itself.

We can list the reviews of the CSIRT procedures that are conducted through this department as one of its key responsibilities. This department also has the responsibility of comprehending the actions that the CSIRT will take to ensure that they comply with all applicable federal, state, and local laws and regulations.

Therefore, the incident response strategy must be written and tested by the CSIRT.

To learn more about CSIRT, refer to the link:

https://brainly.com/question/18493737

#SPJ2

Answer:

//import the Random class

import java.util.Random;

//Begin class definition

public class CoinFlipper {

   //The main method

    public static void main(String []args){

       //Create an object of the Random class

       Random ran = new Random();

       System.out.println("Result");    

       //Use the object and the number of times for simulation

       //to call the flipCoin method

       flipCoin(ran, 25);

    } //End of main method

    //Method to flip coin

    public static void flipCoin(Random ran, int nooftimes){

        //Create a loop to run as many times as specified in variable nooftimes

       for(int i=1; i<=nooftimes; i++)

           System.out.println(ran.nextInt(2) + 1);

    }

}   //End of class definition

====================================================

Sample Output:

Result

1

1

1

2

1

2

2

1

2

1

1

2

1

2

1

1

1

2

1

1

1

2

2

1

2

========================================================

Explanation:

The above code has been written in Java. It contains comments explaining every part of the code. Please go through the comments.

The sample output from the execution of the code is also given above.

The code is re-written as follows without comments.

import java.util.Random;

public class CoinFlipper {

    public static void main(String []args){

       Random ran = new Random();

       System.out.println("Result");    

       flipCoin(ran, 25);

    }

    public static void flipCoin(Random ran, int nooftimes){

       for(int i=1; i<=nooftimes; i++)

           System.out.println(ran.nextInt(2) + 1);

    }

}

Answer:

well you could use variables in C and display them

Explanation:

Answer:

1. Yes

2. No

Explanation:

1 Note that the term BIOS (Basic input and Output System) refers to instructions that controls a computer device operations. Thus, devices that shows up in BIOS should be in device manager.

2. Not all devices listed in devcie manager of a computer system will be listed in BIOS.