Passage 1: The creature had thick arms and legs, sharp teeth, and dark eyes. Passage 2: The creature’s legs and arms were tree trunks, its open mouth was lined with razors, and it had eyes like a starless night. How does the author’s use of figurative language in the second passage do a better job of conveying meaning than the first passage? You may choose more than one correct answer. It helps the reader understand how terrifying the creature is. It helps the reader visualize the creature. It describes the creature. It hints that the creature is a predator.

Answer:

10% off

Step-by-step explanation:

When $70 is discounted to $63, you can multiply 70 times 0.1 to get 7 which 70-63=7. To make 0.1 to a percentage, multiply by 100 to get 10%.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

Answer:

x=1/4c+1/4k

Step-by-step explanation:

4x-c=k

move c over

4x=c+k

then divide by 4

x=1/4c+1/4k

hope this helps

Answer:

y = 2b/3

Step-by-step explanation:

The x-coordinate of the intersection point of Line B D and Line C E is at [tex]\frac{2(a+c)}{3}[/tex]. Given that:

[tex]y=\frac{b}{a-2c}x -\frac{2bc}{a-2c} \\\\The\ y\ coordinate\ can\ be \ gotten\ by\ substituting\ the \ value\ of\ x\ and\ simplifying.\\ Substituting\ x:\\\\y=\frac{b}{a-2c}(\frac{2(a+c)}{3} ) -\frac{2bc}{a-2c}[/tex]

[tex]Simplyfing\ the\ parenthesis\\y=\frac{2b(a+c)}{3(a-2c)} -\frac{2bc}{a-2c}\\\\y=\frac{2ab+2bc}{3(a-2c)} -\frac{2bc}{a-2c}\\\\Simplyfying\ using\ LCF\\y=\frac{2ab+2bc-6bc}{3(a-2c)}\\\\y=\frac{2ab-4bc}{3(a-2c)}\\\\Factorizing:\\\\y=\frac{2b(a-2c)}{3(a-2c)}\\\\y=\frac{2b}{3}[/tex]

The y-coordinate of the intersection point of Line B D and Line C E is at [tex]\frac{2b}{3}[/tex].

Answer:

b

Step-by-step explanation:

Answer:

2, 3 , 5, 7

Step-by-step explanation:

2(x - 2)/3 < (x + 1)/2 < 3(5x + 6)/4

Considering:

    2(x - 2)/3 < (x + 1)/2

<=>(2x - 4)/3 < (x + 1)/2

<=> (2x - 4)*2 < (x + 1)*3

<=> 4x - 8 < 3x + 3

<=> 4x - 3x < 8 + 3

<=> x < 11

Considering:

     (x + 1)/2 < 3(5x + 6)/4

<=>(x + 1)/2 < (15x + 18)/4

<=>(x + 1)*4 < (15x + 18)*2

<=> 4x + 4 < 30x + 36

<=> 4x - 30x < 36 - 4

<=> -26x < 32

<=> 26x > -32

<=> x > -32/26

=> -32/26 < x < 11

The prime numbers satisfy the above inequalities: 2, 3 , 5, 7

Answer:

3z/4

Step-by-step explanation:

Here, we start by calculating the 50% of z

mathematically, that would be 50/100 * z = 50z/100 = z/2

Now we want to calculate the 150% of this.

That would be 150/100 * z/2 = 150z/200 = 3z/4

Answer:

3

Step-by-step explanation:

Greetings from Brasil...

Here we have application of Trigonometry

COS β = adjacent side ÷ hypotenuse (H)

bringing to our problem....

COS A = AC ÷ H

But we dont have AC.... We have to use Pitagoras:

AB² = AC² + BC²

AC² = AB² - BC²

AC = √(AB² - BC²)

AC = √(10² - 8²)

AC = √(100 - 64)

AC = √36

So

COS A = AC ÷ H  ⇔ COS A = AC ÷ AB

COS A = 6/10

Answer: B) 3/5

Step-by-step explanation:

Cos = adjacent/hypotenuse

Thus, the cos is AC/AB.

Because of Pythagorean Theorem, AC^2=AB^2-BC^2.  Let AC be x.

[tex]x^2=10^2-8^2\\x^2=100-64\\x^2=36\\x=6[/tex]

Thus, the cos is 6/10, or 3/5

Answer:

the long diagonal d=15.49 ( rounded to the nearest hundredth)

the shortest d=√136-120(cos 30)=5.663 ( rounded to the nearest hundredth)

Step-by-step explanation:

Area=height * base

30=h*6

h=30/6=5 cm

height=asinФ

sinФ=5/10=1/2 (Ф=30)

alternate angle=180

180-30=150 degrees

diagonal²=a^2+b^2-2abcos150

d²=10²+6²-2(10)(6)(-√3/2)

d=√136+60(√3)

the long diagonal d=15.49 ( rounded to the nearest hundredth)

the shortest d=√136-120(cos30)=5.663

Answer:

5400 cycles

Step-by-step explanation:

You have the following function:

[tex]V(t)=220sin(180\pi t)[/tex]

where t is in seconds.

In order to find the number of cycles in 1 minute, you first  calculate the frequency of the function, which is given by:

[tex]f=\frac{180\pi}{2\pi}=90s^{-1}[/tex]

The number of cycles is then given by:

[tex]n=ft=(90s^{-1})(60s)=5400\ cycles[/tex]

There are 5400 cycles in 1 minute

Answer:

your answer is k

Step-by-step explanation:

not all the isosceles triangles are similar

Answer: 1320; 495

Step-by-step explanation:

Explanation is in the attachment file

Answer:

Length of first leg = 1.4feet

Hypotenuse = 4.2feet

Explanation:

Since we are dealing with a right angled triangle, we will apply the Pythagoras theorem to solve the question. According to Pythagoras theorem, the square of the hypotenuse is equal to the sum if the square of the other two legs.

Mathematically, a² = b²+c² where a is the hypotenuse and b, c are the other two legs.

From the question, since hypotenuse of a right triangle is three times the length of its first leg, then a = 3b.

Also the other leg is four feet i.e c= 4

Substituting this values into the Pythagoras formula;

a²=b²+c²

(3b)² = b²+4²

9b² = b²+16

9b²-b² = 16

8b² = 16

b² = 16/8

b² = 2

b = √2

b = 1.4

Since a = 3b

a = 3(1.4)

a = 4.2

Hence, the length of the first leg is 1.4feet and that of the hypotenuse is 4.2feet both to the nearest tenth.

Answer: The store must sell 40 bikes.

Step-by-step explanation:

y=60x+2400

y=120x

120x=60x+2400

-60x on both sides

60x=2400

divide 60 on both sides

2400/60=40

x=40  

Answer:

696.6 in³

Step-by-step explanation:

The formula for the volume of a sphere is 4/3πr³

The diameter of 11 in. is given. Therefore, the radius is 5.5 (11/2 = 5.5).

1. Set up the equation

4/3(3.14)(5.5³)

2. Solve

= 696.6 in³

Answer:

[tex]\boxed{Volume = 696.9 \ in.^3}[/tex]

Step-by-step explanation:

Diameter = 11 inches

Radius = 5.5 inches

Volume of sphere = [tex]\frac{4}{3} \pi r^3[/tex]

Where r = 5.5 inches

Volume = [tex]\frac{4}{3} (3.14)(5.5)^3[/tex]

Volume = [tex]\frac{4}{3} (3.14)(166.375)[/tex]

Volume = [tex]\frac{2090.7}{3}[/tex]

Volume = 696.9 in.³

Answer:

25.52791653032955454422437424679625318128649677442393276098...

Step-by-step explanation:

You can just paste this into wolframalpha.

Answer: 970.72312

Step-by-step explanation:

Straightforward operation.

Answer:

80

Step-by-step explanation:

t is important to note that a square of any non-zero integer is positive, and therefore there is no advantage in using negative integers instead of positive integers to attain the greatest difference of squares. So we will not consider negative integers.

The greatest value of a^2 - b^2 occurs when a^2 is at its largest and b^2 is at its smallest.

The larger a, the larger a^2:

8 ^ 2 = 64

9 ^ 2 = 81

10 ^ 2= 100

Since a^2 can have at most two digits, a=10 is too large, and so a=9 is the largest integral value of a we can use.

Now, b^2 is at its smallest when b is closest to zero on the number line (the further b gets from zero, the larger its square becomes):

2 ^ 2 = 4

1 ^ 2 =1

0 ^ 2 = 0

Remember to go back to the original problem sometimes, to make sure you are taking everything into account. It states b doesn't =0, and therefore the b=1 is the closest b can get to zero as an integer. So, the greatest difference between b^2 and a^2 is when b=1 and a=9, giving the result:

a^2-b^2 =9^2-1^2 =81-1= 80.

So, 80 is your answer.

Answer:

Option (C).

Step-by-step explanation:

To check a graph whether it's a function or not we use a vertical line test. In this test first we draw a vertical line on the given graph. If this line intersects the graph at more than one point, the graph is not a function.

In the given parabola, opening upwards passes the vertical line test.

Therefore, this graph shows a function.

Option (C) will be the answer.

Option  (c) Yes; the graph passes the vertical line test. And

(d) Yes; there are no y-values that have more than one x-value are correct options. Hence, a given graph is a function.

This is a graph of [tex]y = x^2[/tex]

Which is a graph of parabola.

To determine the given graph is a function or not, we do a vertical line test.

The vertical line test says that if a vertical line intersects a graph more than once, then that graph is not a function. And in this case, y-values have more than one x-values.

Let’s draw a vertical line in the given graph  (attached below)

We see that the vertical line touches the graph only at once. That’s why it is a function, and so there are no y-values that have more than one x-value.

Hence, the given graph is a function and option (3) and (4) are correct options.

Learn more about graphs here:

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Answer:

Shaded area: 70cm^2

Step-by-step explanation:

Whole=120cm^2

White Square=

10-2.5-2.5=5

12-1-1=10

5✖️10=50cm^2

Whole-white=70cm^2

Answer:

$96.00

Step-by-step explanation:

Perimeter formula, 2w+2l

2(23)+2(25)=96 feet

1$ per foot

96 feet,

so $96

Answer:

I think it 96.00

Step-by-step explanation:

Answer:

D.  [tex]\boxed{x = 5}[/tex]

Step-by-step explanation:

Let the number be x

Condition:

[tex]\frac{1}{10} x + 2 = \frac{1}{2} x[/tex]

[tex]\frac{x}{10} -\frac{x}{2} = -2\\LCM = 10\\Multiplying \ both \ sides \ by \ 10\\x - 5(x) = -2(10)\\x -5x = -20\\-4x = -20[/tex]

Dividing both sides by -4

x = 5

Answer:

[tex]\boxed{5.0}[/tex]

Step-by-step explanation:

Let the number be [tex]x[/tex].

1/10 of x is added to 2, the result is half of x.

[tex]2+\frac{1}{10} x=\frac{1}{2} x[/tex]

[tex]2=\frac{1}{2} x-\frac{1}{10} x[/tex]

[tex]2=\frac{2x}{5}[/tex]

[tex]10=2x[/tex]

[tex]\frac{10}{2} =x[/tex]

[tex]5=x[/tex]

The number is 5.0

Answer:

a) More.

b) Less.

c) More.

Step-by-step explanation:

a) If you invest $10 with an interest rate of 50% (that's very high I know XD), you would earn 10 / 2 = $5 in interest. If you invest $100 with an interest rate of 50%, you would earn 100 / 2 = $50 in interest. So, the more principal invested, the more interest earned.

b) Let's say you are investing $100. If there is an interest rate of 50%, as stated before, you would earn $50 in interest. If the interest rate were lowered to 25%, you would earn 100 / 4 = $25 in interest. So, the lower the interest rate, the less the interest.

c) The same exact thing as part a.

Hope this helps!

Answer:

12.65

Step-by-step explanation:

In the case of the blue triangle, to calculate the rise, which would be the increase, therefore it would be the hypotenuse formed by the arrow.

We have to Pythagoras is:

h ^ 2 = a ^ 2 + b ^ 2

In this case:

a (x-axis) = 4

b (y-axis) = 12

replacing:

h ^ 2 = 4 ^ 2 + 12 ^ 2

h ^ 2 = 160

h = 12.65

Which means that the rise in the blue triangle is 12.65 units

Answer:1.0111111111

Step-by-step explanation:

18.2 - 18 = .2-18 =1.0111111

We are given that ABCDE is congruent to TVSRK and want to find what corresponds to VSR.

Look at the ordering of the letters. VSR is the second, third, and fourth letters of TVSRK, respectively.

Thus, we just have to select the second, third, and fourth letters of ABCDE and we get BCD.

Thus, VSR corresponds to BCD. Let me know if you need any clarifications, thanks!

Answer: £4

Step-by-step explanation:

From the question, we are informed that when the normal price of a book is reduced by 30%, then the sale price of the book is £2.80.

Since the normal price of a book is reduced by 30%, that means the book is sold at (100% - 30%) = 70% of its normal price.

Let the normal price of the book be y.

70% of y = £2.80

70/100 × y = £2.80

0.7 × y = £2.80

0.7y = £2.80

y = £2.80/0.7

y = £4

The normal price of the book is £4.

Answer:

Step-by-step explanation:

the upper left graph is the correct answer

because "... or equal to" always represents a filled dot, while just "greater/less than" represents blank dot

Answer:

5.65%

Step-by-step explanation:

Principal=$600

Time=20 years

FV=600*3=$1800

n=1

r=?

r= n[(A/P)^1/nt - 1]

=1{(1800/600)^ 1/1*20 - 1}

={(3)^1/20-1}

=3^0.05-1

=1.0565-1

=0.0565

rate=0.0565*100

=5.65% to the nearest hundredth percent

Answer:

For sample size n = 39 ; P(X < 31.6) = 0.9756

For sample size n = 76 ; P(X < 31.6) = 0.9970

Step-by-step explanation:

Given that:

population mean μ = 31

standard deviation σ = 1.9

sample mean  [tex]\overline X[/tex] = 31.6

Sample size n                 Probability

39

76

The probabilities that the sample mean is less than 31.6 for both sample size can be computed as  follows:

For sample size n = 39

[tex]P(X < 31.6) = P(\dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}})[/tex]

[tex]P(X < 31.6) = P(\dfrac{31.6 - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{39}}})[/tex]

[tex]P(X < 31.6) = P(Z< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{39}}})[/tex]

[tex]P(X < 31.6) = P(Z< \dfrac{0.6}{\dfrac{1.9 }{6.245}})[/tex]

[tex]P(X < 31.6) = P(Z< 1.972)[/tex]

From standard normal  tables

P(X < 31.6) = 0.9756

For sample size n = 76

[tex]P(X < 31.6) = P(\dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}})[/tex]

[tex]P(X < 31.6) = P(\dfrac{31.6 - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{76}}})[/tex]

[tex]P(X < 31.6) = P(Z< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{76}}})[/tex]

[tex]P(X < 31.6) = P(Z< \dfrac{0.6}{\dfrac{1.9 }{8.718}})[/tex]

[tex]P(X < 31.6) = P(Z< 2.75)[/tex]

From standard normal  tables

P(X < 31.6) = 0.9970

Answer:

942.5 in²  

Step-by-step explanation:

The formula for the area (A) of a sector of a circle is

A = ½r²θ

where θ is the angle in radians.

1. Convert the angle to radians

θ = 125°  

[tex]\theta = 125^{\circ} \times \dfrac{\pi \text{ rad }}{180^{\circ}} =\frac{25}{36} \pi\text{ rad}[/tex]

2. Area swept out by wiper arm

A = ½r²θ = ½ × (30 in)² × θ = ½ × 900 in²× θ = 450 θ in²

3. Area missed by wiper

A = ½r²θ = ½ × (6 in)² × θ = ½ × 36 in²× θ = 18 θ in ²

4. Area covered by wiper

A = 450 θ in² - 18 θ in² = 432 θ in²

5. Insert the value of θ

A = 432 × 25/36 π in² = 300π in² ≈ 942.5 in²

The area swept out by the wiper blade is 942.5 in².

Answer:

q = 108-n

Step-by-step explanation:

Given: 108 coins containing only quarters and nickels

q = 108-n

since total number of coins is 108, and n= number of nickels

If you want to know how many of each kind of coin, read on:

First solve the number of quarters and nickels.

If all 108 coins are quarters, the value is 108*0.25 = $27

Since this value exceed the actual by 27-21 = $6,

we replace a number of quarters by nickels.

Each replacement will reduce the value by 25 - 5 = 20 cents = 0.2 dollars.

So it will take 6/0.2 = 30 replacements.

Therefore there are 108-35 = 78 quarters and 30 nickels.

The solution is : q = 108-n, is the value could replace q on the chart.

In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.

here, we have,

Given:

108 coins containing only quarters and nickels

q = 108-n

since total number of coins is 108, and n= number of nickels

If you want to know how many of each kind of coin, read on:

First solve the number of quarters and nickels.

If all 108 coins are quarters, the value is 108*0.25 = $27

Since this value exceed the actual by 27-21 = $6,

we replace a number of quarters by nickels.

Each replacement will reduce the value by 25 - 5 = 20 cents = 0.2 dollars.

So it will take 6/0.2 = 30 replacements.

Therefore there are 108-35 = 78 quarters and 30 nickels.

The solution is : q = 108-n, is the value could replace q on the chart.

To learn more on multiplication click:

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