Please help ASAP! Do not understand how to conduct problem!

Please Help ASAP! Do Not Understand How To Conduct Problem!

Answers

Answer 1

Answer:

AB =-4 24 25

-5 15 15

BC= -5

4

10

2BC = -10

8

20

THE Operation AB -2BC cannot be performed because the unequality of the arrays

Step-by-step explanation:

AB=first row (3*2)+(1/2*0)+(5*-2), (3*-4)+(1/2*2)+(5*7), (3*0),(1/2*0),(5*5)

Second row ((1*1)+(-1*0)+(3*-2),(1*-4)+(-1*2)+(3*7), (1*0)+(-1*0)+(3*5)

AB =-4 24 25

-5 15 15

BC =FIRST ROW (1*1)+(-4*2)+(0*0)

SECOND ROW (0*1)+(2*2)+(0*0)

THIRSD ROW (-2*2)+(7*2)+(5*0)

BC= -5

4

10

2BC = -10

8

20

THE Operation AB -2BC cannot be performed because the unequality of the arrays


Related Questions

Help me find the equation and tell me if 22 or 12 is wrong

Answers

Answer:

your answer is correct.

A rectangle has a width of 3/4 inches and a length of 9/10 inches. Another rectangle
is larger but still proportional to the first rectangle. It has a width of 30 inches and a length of 36 what proportion could model this situation

Answers

Answer:

Bigger size   / smaller size = 40

Step-by-step explanation:

Notice that we      

36 / (9/10)    =    30 / (3/4)   = 40

Therefore the proportion model would be

Bigger size   / smaller size = 40

FOR BRAINLIEST ANSWER HURRY HELP THANKS If (a,b) is a point in quadrant IV, what must be true about a? What must be true about b?

Answers

Answer:

Well if (a,b) is in Quadrant IV which is the last quadrant the a or x is a positive number and the b or y is a negative number.

Answer:

a should be a positive number

b should be a negative number

Evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration.) x4 18x2 4 x5 30x3 20x dx

Answers

Your integrand is missing some symbols. My best interpretation is the following integral:

[tex]I=\displaystyle\int\frac{x^4+18x^2+4}{x^5+30x^3+20x}\,\mathrm dx[/tex]

Decompose into partial fractions; we're looking for an expansion of the form

[tex]\dfrac{x^4+18x^2+4}{x^5+30x^3+20x}=\dfrac ax+\dfrac{bx^3+cx^2+dx+e}{x^4+30x^2+20}[/tex]

Now:

[tex]x^4+18x^2+4=a(x^4+30x^2+20)+(bx^3+cx^2+dx+e)x[/tex]

[tex]=(a+b)x^4+cx^3+(30a+d)x^2+ex+20a[/tex]

Matching up coefficients tells us that

[tex]\begin{cases}a+b=1\\c=0\\30a+d=18\\e=0\\20a=4\end{cases}\implies a=\dfrac15,b=\dfrac45,d=12[/tex]

so that

[tex]I=\displaystyle\frac15\int\frac{\mathrm dx}x+\frac45\int\frac{x^3+15x}{x^4+30x^2+20}\,\mathrm dx[/tex]

The integral is trivial:

[tex]\displaystyle\frac15\int\frac{\mathrm dx}x=\frac15\ln|x|+C[/tex]

For the second integral, notice that

[tex]\mathrm d(x^4+30x^2+20)=(4x^3+60x)\,\mathrm dx[/tex]

Distribute the 4 over the numerator, then substitute [tex]u=x^4+30x^2+20[/tex] and [tex]\mathrm du=(4x^3+60x)\,\mathrm dx[/tex]:

[tex]\displaystyle\frac15\int\frac{4x^3+60x}{x^4+30x^2+20}\,\mathrm dx=\frac15\int\frac{\mathrm du}u=\frac15\ln|u|+C=\frac15\ln(x^4+30x^2+20)+C[/tex]

So we have

[tex]I=\dfrac15\ln|x|+\dfrac15\ln(x^4+30x^2+20)+C[/tex]

and with some simplification,

[tex]I=\boxed{\ln\sqrt[5]{|x^5+30x^3+20x|}+C}[/tex]

QUESTION 4 (10 MARKS)
A retired couple requires an annual return of $2,000 from investment of $20,000. There are 3
options available:
(A) Treasury Bills yielding 9%;
(B) Corporate bonds 11%;
Junk Bonds. 130%
How much should be invested in each to achieve their goal? Give 3 sets of options that can
achieve their goal.[10 Marks]​

Answers

Answer:

  (T, C, J) = (in dollars)

     (10000, 10000, 0),

     (15000, 4915.97, 84.03),

     (18181.82, 1680.67, 137.51)

Step-by-step explanation:

There are a number of ways to approach this question. We have chosen an approach that determines the investments required to achieve interest rate targets.

__

For an overall interest rate of I, the proportion that must be invested at rate I1 < I < I2 is ...

  proportion at I1 = (I2 -I)/(I2 -I1)

Similarly, the proportion that must be invested at I2 is what's left over. It can be computed similarly:

  proportion at I2 = (I -I1)/(I2 -I1)

__

We want an overall interest rate of $2000/$20000 = 10%.

Given available interest rates of 9%, 11%, and 130%, we need to have investments at a rate lower than 10% and at a rate higher than 10%.

If we use only the options for 9% and 11% (no junk bonds), then we can compute ...

  proportion at 9% = (11 -10)/(11 -9) = 1/2

  proportion at 11% = (10 -9)/(11 -9) = 1/2

1st Option:

  $10,000 in treasury bills; $10,000 in corporate bonds

__

Suppose we want to achieve a 13% return on our investments at 11% and 130%. Then the proportion invested at 9% will use this value for I2:

  proportion at 9% = (13 -10)/(13 -9) = 3/4

Of the remaining 1/4 of the money, we can achieve a 13% return by mixing the investments like this:

  proportion at 11% = (130 -13)/(130 -11) = 117/119

  proportion at 130% = (13 -11)/(130 -11) = 2/119

2nd option:

  $20,000 × 3/4 = $15,000 in treasury bills

  $5000 × 117/119 = $4,915.97 in corporate bonds

  The remaining amount, $84.03 in junk bonds

__

Let's suppose we want a 20% return on our investment in junk bonds and corporate bonds. Then the proportion of the money invested at 9% will be ...

  proportion at 9% = (20 -10)/(20 -9) = 10/11

And the proportion at 11% will be ...

  proportion at 11% = (130 -20)/(130 -11) = 110/119 . . . (of the remaining 1/11 of the funds)

3rd option:

  $20,000 × 10/11 = $18,181.82 in treasury bills

  $1,818.18 × 110/119 = $1,680.67 in corporate bonds

  The remaining amount, $137.51 in junk bonds

_____

Additional comment

The most that could be invested in Junk Bonds is $165.29. If the remainder is invested in Treasury Bills, then the overall return will be $2000. (You could consider this to be a 4th option.)

find the area of the shaded region ​

Answers

Answer:

27 in²

Step-by-step explanation:

area of triangle (whole) = 1/2 x base x height

                                       = 1/2 x 10 x 6

                                       = 30 in²

area of small triangle = 1/2 x base x height

                                   = 1/2 x 3 x 2

                                   = 3 in²

area of shaded region = 30 in² - 3 in²

                                     = 27 in²

15 POINTS+BRAINLIEST (Hurry now) A train goes past you in 10 seconds and goes past a 100 meter long bridge in 30 seconds. What is the length (in meters) and the speed (inm/s) of the train?

Answers

Answer:

speed=3.33m/s

Step-by-step explanation:

speed= distance÷time

3.33 m/s

length = ?

Answer:

Length  : 50m

Speed   : 5 m  /  s

im sorry if im too late :'(

the average temperature for one week in Alaska are as follows: 10, 6, 9, 2, 0,3. what is the mean of these tempartures ? show all work.

Answers

Answer:

5

Step-by-step explanation:

We know that we have to add all numbers then divide it by how many numbers there are. So, 10 + 6 + 9 + 2 + 0 + 3 = 30.  30/6 = 5.  

Use Newton's method with initial approximation x1 = −1 to find x2, the second approximation to the root of the equation x3 + x + 8 = 0. (Round your answer to four decimal places.) x2 =

Answers

Answer:

The second approximation to the root of the equation [tex]x^{3}+x+8 = 0[/tex] is -1.5000.

Step-by-step explanation:

The Newton's method is a numerical method by approximation that help find roots of a equation of the form [tex]f(x) = 0[/tex] with the help of the equation itself and its first derivative. The Newton's formula is:

[tex]x_{i+1} = x_{i} - \frac{f(x_{i})}{f'(x_{i})}[/tex]

Where:

[tex]x_{i}[/tex] - i-th approximation, dimensionless.

[tex]x_{i+1}[/tex] - (i+1)-th approximation, dimensionless.

[tex]f(x_{i})[/tex] - Function evaluated at the i-th approximation, dimensionless.

[tex]f'(x_{i})[/tex] - First derivative of the function evaluated at the i-th approximation, dimensionless.

The function and its first derivative are [tex]f(x) = x^{3}+x+8[/tex] and [tex]f'(x) = 3\cdot x^{2}+1[/tex], respectively. Now, the Newton's formula is expanded:

[tex]x_{i+1} = x_{i}-\frac{x_{i}^{3}+x_{i}+8}{3\cdot x_{i}^{2}+1}[/tex]

If [tex]x_{1} = -1[/tex], the value of [tex]x_{2}[/tex] is:

[tex]x_{2} = -1 - \frac{(-1)^{3}+(-1)+8}{3\cdot (-1)^{2}+1}[/tex]

[tex]x_{2} = -1.5000[/tex]

The second approximation to the root of the equation [tex]x^{3}+x+8 = 0[/tex] is -1.5000.

Answer:

-2.5000

Step-by-step explanation:

Enter your answer in the box

____

Answers

Answer:

  [tex]\boxed{2144}[/tex]

Step-by-step explanation:

The sum can be found by adding the parts:

  [tex]\sum\limits_{n=1}^{32}{(4n+1)}=4\sum\limits_{n=1}^{32}{n}+\sum\limits_{n=1}^{32}{1}=4\cdot\dfrac{32\cdot 33}{2}+32\\\\= 2112+32=\boxed{2144}[/tex]

__

The sum of numbers 1 to n is n(n+1)/2.

A hotel rents 210 rooms at a rate of $ 60 per day. For each $ 2 increase in the rate, three fewer rooms are rented. Find the room rate that maximizes daily revenue.

Answers

Answer:

r=$14,400

The hotel should charge $120

Step-by-step explanation:

Revenue (r)= p * n

where,

p = price per item

n = number of items sold

A change in price leads to a change in number sold

A variable to measure the change in p and n needs to be introduced

Let the variable=x

Such that

p + x means a one dollar price increase

p - x means a one dollar price decrease

n + x means a one item number-sold increase

n - x means a one item number-sold decrease

for each $2 price increase (p + 2x) there are 3 fewer rooms are rented (n-3x)

know that at $60 per room, the hotel rents 210 rooms

r = (60 + 2x) * (210 - 3x)

=12,600-180x+420x-6x^2

=12,600+240x-6x^2

r=2100+40x-x^2

= -x^2 +40x+2100=0

Solve the quadratic equation

x= -b +or- √b^2-4ac / 2a

a= -1

b=40

c=2100

x= -b +or- √b^2-4ac / 2a

= -40 +or- √(40)^2 - (4)(-1)(2100) / (2)(-1)

= -40 +or- √1600-(-8400) / -2

= -40 +or- √ 1600+8400 / -2

= -40 +or- √10,000 / -2

= -40 +or- 100 / -2

x= -40+100/-2 OR -40-100/-2

=60/-2 OR -140/-2

= -30 OR 70

x=70

The quadratic equation has a maximum at x=70

p+2x

=60+2(30)

=60+60

=$120

r= (60 + 2x) * (210 - 3x)

={60+2(30)}*{(210-3(30)}

r=(60+60)*(210-90)

=120*120

=$14,400

Click on the solution set below until the correct one is displayed.

Answers

Answer:

{ } or empty set.

Step-by-step explanation:

The solutions should be where the two lines intersect, but in this case, the parallel lines never intersect. That means that they have no solutions.

Hope this helps!

Answer:

{ } or empty set

Step-by-step explanation:

It's because these lines are parallel so they don't intersect to give you a coordinate.

Whats the input value of f(x)=2x+5

Answers

Answer:

x

Step-by-step explanation:

f(x)=2x+5

Input: x

Output: f(x)

For i.e:

Input: 1

Output: f(1) = 2(1) + 5 = 2 + 5 = 7

PLEASE HELP!!! Find the area of the shaded polygon:

Answers

Answer:

147

Step-by-step explanation:

Sven starts walking due south at 7 feet per second from a point 190 feet north of an intersection. At the same time Rudyard starts walking due east at 4 feet per second from a point 130 feet west of the intersection.
A. Write an expression for the distance d between Sven and Rudyard t seconds after they start walking.
B. What is the minimum distance between them?
C. When are Sven and Rudyard closest?

Answers

Answer: A. [tex]d=\sqrt{(190-7t)^2+(130-4t)^2}[/tex]

B. Minimum distance between them  = 18.61 feet.

C. After 28.76 seconds Sven and Rudyard are closest.

Step-by-step explanation:

A) Let (0,0) be the intersection point.

Then, Initial Location of Sven (0,190).

Speed of Sven = 7 feet per second

Then, position of Sven after t seconds = (0,190-7t)  [speed = distance x time]

Similarly, Initial position of Rudyard= (130,0)

Speed of Rudyard = 4 feet per second

Position after t seconds = (130-4t,0)

Distance d between Sven and Rudyard t seconds after they start walking:

[tex]d=\sqrt{(190-7t)^2+(130-4t)^2}[/tex]

B) Let [tex]d(t)=\sqrt{(190-7t)^2+(130-4t)^2}\\[/tex]

[tex]d'(t)=2(190-7t)(-7)+(2)(130-4t)(-4)\\\\=130t-3700[/tex]

Put d'(t)=0

[tex]130t-3700=0\\\\\Rightarrow\ t=\dfrac{3700}{130}\approx28.46\ sec[/tex]

Minimum distance :

[tex]d(28.46)=\sqrt{(190-7(28.46))^2+(130-4(28.46))^2}\\\\=\sqrt{346.154}\approx18.61\ feet[/tex]

Hence, the minimum distance between them  = 18.61 feet.

c) After 28.76 seconds Sven and Rudyard are closest.

your marksmanship score are 6 and 10 on two test . if you want average 9 on the tests , waht must your third score be?

Answers

Answer:

11

Step-by-step explanation:

To do this you would just multiply 9 by 3 so you get 27 and subtract 6+10 which is 16 from it and then you will get 11 and that is what you will need for your third score

The third score which must be added is 11.

What are average?

The average can be calculated by dividing the sum of observations by the number of observations.

Average = Sum of observations/the number of observations

Given; count = 3 (there are three trials)

average = 9

9 = sum / 3

The sum = first score + second score + third score

The sum   =  6 + 10 + third score

9 = (6+10+third score)/3

Then multiply both sides by 3 to remove the denominator

27 = 6 + 10 + third score

27 = 16 + third score

Now, subtract 16 from both sides to isolate the third score

11 = third score

Hence, the third score which must be added is 11.

Learn more about average here;

https://brainly.com/question/27851466

#SPJ2

Check whether these statements are wff or not:(a) (p˅q) ∧∼r

Answers

Answer:

It is a well formed formula

Step-by-step explanation:

1 - p,q,r are well formed formulas.

2 - [tex]p \ \lor \ q[/tex]  is a well formed formula as well.

3 - [tex]\neg r[/tex] is a well formula as well

4 - [tex](\ p \ \lor \ q) \ \land \ \neg r[/tex] is a well formula as well.

A web page is accessed at an average of 20 times an hour. Assume that waiting time until the next hit has an exponential distribution. (a.) Determine the rate parameter λ of the distribution of the time until the first hit? (b.) What is the expected time between hits? (c.) What is the probability that t

Answers

Answer:

Step-by-step explanation:

Given that :

A web page is accessed at an average of 20 times an hour.

Therefore:

a. he rate parameter λ of the distribution of the time until the first hit = 20

b.  What is the expected time between hits?

Let consider E(Y) to be the expected time between the hits; Then :

E(Y) = 1/λ

E(Y) = 1/20

E(Y) = 0.05 hours

E(Y) = 3 minutes

(c.)  What is the probability that there will be less than 5 hits in the first hour?

Let consider X which follows Poisson Distribution; Then,

P(X<5) [tex]\sim[/tex] G(∝=5,  λ = 20)

For 5 hits ; the expected time will be :

Let 5 hits be X

E(X) = ∝/λ

E(X) = 5/20

E(X) =1/4

E(X) = 0.25 hour

E(X) = 15 minutes

From above ; we will see that  it took 15 minutes to get 5 hits; then

[tex]P(\tau \geq 0.25) = \int\limits^{\alpha}_{0.25} \dfrac{\lambda^{\alpha}}{\ulcorner^{\alpha}} t^{a\pha-1} \ e^{-\lambda t} \, dt[/tex]

[tex]P(\tau \geq 0.25) = \int\limits^{5}_{0.25} \dfrac{20^{5}}{\ulcorner^{5}} t^{5-1} \ e^{-20 t} \, dt[/tex]

[tex]\mathbf{P(\tau \geq 0.25) =0.4405}[/tex]

What is the base of the expression 11^12? A. 3 B. 11 C. 12 D. 21

Answers

Answer: B. 11

An exponential has the base at the bottom, or the lower portion. Think of "basement" to help remember this. The exponent is the number up top, so 12 is the exponent.

Answer:

The person above me is correct ( :

Step-by-step explanation:

B

Consider the following scores. (i) a score of 40 from a distribution with mean 50 and standard deviation 10 (ii) a score of 45 from a distribution with mean 50 and standard deviation 5 How do the two scores compare relative to their respective distributions

Answers

Answer:

The scores are equal

Step-by-step explanation:

The z-score for any normal distribution is:

[tex]z=\frac{X-\mu}{\sigma}[/tex]

(i) Score (X) = 40

Mean (μ)= 50

Standard deviation (σ) = 10

[tex]z=\frac{40-50}{10}\\ z=-1[/tex]

(ii) Score (X) = 45

Mean (μ)= 50

Standard deviation (σ) = 5

[tex]z=\frac{45-50}{5}\\ z=-1[/tex]

Both scores have the same z-score, which means that, relative to their respective distributions, the scores are equal.

W varies inversely as the square root of x when x=4 w=4 find when x=25

Answers

Answer:

8/5

Step-by-step explanation:

w = k / √x

4 = k / √4

k = 8

w = 8 / √x

w = 8 / √25

w = 8/5

Help ASAP it’s Math I need this rightnow 31 points

Answers

Answer:

AC (b)

Step-by-step explanation:

Since 10 is half of 20, you have to find the variable closest to the middle. Which in this case, is C. So, your awnser is B. (AC)

Answer:

[tex]\boxed{\sf C}[/tex]

Step-by-step explanation:

The whole segment is [tex]\sf \sqrt {20}[/tex], we can see that AD is approximately 75% of the segment AE.

[tex]75\%*\sqrt{20} = 3.354102[/tex]

[tex]\sqrt{10}= 3.162278[/tex]

AC is almost half of AE.

[tex]\frac{\sqrt{20} }{2} = 2.2360679775[/tex]

[tex]\sqrt{10} = 3.16227766017[/tex]

It isn’t close to the option C.

Discuss the validity of the following statement. If the statement is always​ true, explain why. If​ not, give a counterexample. If the 2 times 2 matrix P is the transition matrix for a regular Markov​ chain, then, at​ most, one of the entries of P is equal to 0. Choose the correct answer below. A. This is false. In order for P to be​ regular, the entries of​ P^k must be​ non-negative for some value of k. For​ k=1 the matrix Start 2 By 2 Table 1st Row 1st Column 0 2nd Column 1 2nd Row 1st Column 0 2nd Column 1 EndTable has​ non-negative entries and has two zero entries.​ Thus, it is a regular transition matrix with more than one entry equal to 0. B. This is true. If there is more than one entry equal to​ 0, then the number of entries equal to zero will increase as the power of P increases. C. This is true. If there is more than one entry equal to​ 0, all powers of P will contain 0 entries.​ Hence, there is no power k for which Upper P Superscript k contains all positive entries. That​ is, P will not satisfy the definition of a regular matrix if it has more than one 0. D. This is false. The matrix P must be​ regular, which means that P can only contain positive entries. Since zero is not a positive​ number, there cannot be any entries that equal 0.

Answers

Answer:

C. This is true. If there is more than one entry equal to​ 0, all powers of P will contain 0 entries.​ Hence, there is no power k for which Upper P Superscript k contains all positive entries. That​ is, P will not satisfy the definition of a regular matrix if it has more than one 0

Step-by-step explanation:

The correct option is C as it represents that by considering a matrix P that involves more than one zero and at the same time the powers for all P has received minimum one zero or it included at least one zero

Therefore the statement C verified and hence it is to be considered to be valid

Hence, all the other statements are incorrect

A committee has members. There are members that currently serve as the​ board's . Each member is equally likely to serve in any of the positions. members are randomly selected and assigned to be the new . What is the probability of randomly selecting the members who currently hold the positions of and reassigning them to their current​ positions? The probability is nothing.

Answers

Complete Question

A committee has six members. There are three members that currently serve as the​ board's chairman comma vice chairman comma and treasurer . Each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman comma vice chairman comma and treasurer . What is the probability of randomly selecting the three members who currently hold the positions of chairman comma vice chairman comma and treasurer and reassigning them to their current​ positions?

The probability is ?

Answer:

The probability is [tex]P(3 ) = \frac{ 1 }{20 }[/tex]

Step-by-step explanation:

From the question we are told that

       The total number of members is  n = 6  

       The  number of member to be selected is  r =  3  

Generally the number of ways of selecting 3 members from 6  is mathematically evaluated as

          [tex]\left n } \atop {}} \right. C _r = \frac{n! }{(n-r ) ! r !}[/tex]

=>       [tex]\left 6 } \atop {}} \right. C _ 3 = \frac{6 ! }{(6-3) ! 3 !}[/tex]

=>        [tex]\left n } \atop {}} \right. C _r = \frac{6* 5* 4 * 3! }{3 ! 3*2 * 1}[/tex]

=>       [tex]\left n } \atop {}} \right. C _r = \frac{6* 5* 4 }{3 *2 * 1}[/tex]

=>        [tex]\left n } \atop {}} \right. C _r =20[/tex]

Now the number of ways of selecting the 3 members who currently hold the position is  n  = 1

  So the probability is mathematically represented as

                 [tex]p(k ) = \frac{ n }{\left n } \atop {}} \right. C _r }[/tex]

substituting values

                  [tex]P(3 ) = \frac{ 1 }{20 }[/tex]

6th grade math help me, please. :)

Answers

Step-by-step explanation:

Hello there!!

no need to be panic we will help you, alright.

look solution in picture ok...

sorry for cutting in middle.

Hope it helps...

If x = 2, y = 8, find (i) x³+y³ (ii) ∛y

Answers

Answer:

(i) 520

(ii) 2

Step-by-step explanation:

(i) x³ + y³

Plug x as 2, and y as 8.

(2)³ + (8)³

Solve for exponents.

8 + 512

Add.

= 520

(ii) ∛y

Plug y as 8.

∛(8)

Solve for cube root.

= 2

Answer:

( i ) 520

( ii ) 2

Step-by-step explanation:

We can find this solution by plugging in known values -

If x = 2, y = 8

x³+y³ = ( 2 )³ + ( 8 )³ = 8 + 512

= 520

Know let us move on to the second half -

We only need one part of this information now, y = 8. If so,

∛y = ∛8

2 x 2 x 2 = 8 - and thus 2 should be our solution for this portion.

Part F
I NEED HELP!
What is the geometric mean of the measures of the line segments A Dand DC? Show your work.

Answers

Answer:

AC2  =  AB2 + BC2     --->     AC2  =  122 + 52     --->   AC  =  13

AD / AB  =  AB / AC     --->     AD / 12  =  12 / 13     --->     AD  =  144/13

DC  =  AC - AD     --->   DC  =  13 - 144/13     --->     DC  =  25/13

AD / DB  =  DB / DC     --->   DB2  =  AD · DC     --->     DB2  =  (144/13) · (25/13)  --->     DB  =  60/13

DB is the geometric mean of AD and DC.

Step-by-step explanation:

please help Find: ∠x ∠a ∠b

Answers

9514 1404 393

Answer:

  x = 22

  a = 88°

  b = 92°

Step-by-step explanation:

The angles marked with x-expressions are same-side interior angles, so are supplementary.

  5x -18 +3x +22 = 180

  8x +4 = 180

  8x = 176

  x = 22

Then the other marked angles are ...

  a = 3x +22 = 3(22) +22 = 88 . . . degrees

  b = 5x -18 = 5(22) -18 = 92 . . . degrees

When the input is 4, the output of f(x) = x + 21 is

Answers

Answer:

25

Step-by-step explanation:

When the input is 4, the output of f(x) = x + 21 is f(4).

Substitute x = 4 to f(x):

f(4) = 4 + 21 = 25

Answer:

25

Step-by-step explanation:

We can find the output by plugging in 4 as x into the function:

f(x) = x + 21

f(4) = 4 + 21

f(4) = 25

The prices for a loaf of bread and a gallon of milk for two supermarkets are shown below. Sue needs to buy bread and milk for her church picnic. At Supermarket A, she would pay $137.24. At Supermarket B, she would pay $140.04. Which of the following system of equations represents this situation?

Answers

Answer:

B. 3.19b + 4.59m = 137.24

3.49b + 4.39m = $140.04

Step-by-step explanation:

A B

Bread $3.19 $3.49

Milk $4.59 $4.39

Sue paid $137.24 in supermarket A

Sue paid $140.04 in supermarket B

Let

Price of bread A=$3.19

Price of bread B=$3.49

Price of milk A=$4.59

Price of milk B=$4.39

Quantity of Bread=b

Quantity of Milk=m

Pb=price of bread

Pm=price of milk

Qb=Quantity of bread

Qm=Quantity of milk

For each supermarket

Supermarket A Equation

PbQb + PmQm =$137.24

3.19b+ 4.59m = 137.24

Supermarket B Equation

PbQb + PmQm=$140.04

3.49b + 4.39m = $140.04

Combining both equations

3.19b + 4.59m = 137.24

3.49b + 4.39m = $140.04

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