PLEASE HELP ME QUICKLY!!!!!!!!!!!!!!​

Answer: C

Explanation:

A: 100kg*0m/s (obviously not answer)

B: 20kg*2m/s (=40)

C: 5kg*50m/s (=250, safe bet this one is it)

D: 10kg*5m/s (=50)

5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.

Hence, the correct option is C.

To calculate momentum, we use the formula:

Momentum (p) = Mass (m) × Velocity (v)

Let's calculate the momentum for each option:

A. 100 kg at rest

Momentum = 100 kg × 0 m/s = 0 kg m/s

B. 20 kg at 2 m/s

Momentum = 20 kg × 2 m/s = 40 kg m/s

C. 5 kg at 50 m/s

Momentum = 5 kg × 50 m/s = 250 kg m/s

D. 10 kg at 5 m/s

Momentum = 10 kg × 5 m/s = 50 kg m/s

Therefore, 5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.

Hence, the correct option is C.

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Answer:

It is not connected by any way

Answer:

a' = 3a

Explanation:

Newton's Second Law gives the magnitude of the unbalanced force applied to an object as follows:

F = ma

where,

F = Force Applied

m = Mass of Object

a = acceleration

FOR RAMONA'S PUSH:

F = F

m = m

a = a

Therefore,

F = ma  

a = F/m   ---------------- equation (1)

FOR FRANSICO'S PUSH:

F = 3F

m = m  (mass of turtle will be same)

a = a'

Therefore,

3F = ma'  

a' = 3F/m

using equation 1

a' = 3a

Answer: False

Explanation:

Answer:

velocity

Explanation:

plz mark brainliestʕ•ᴥ•ʔ

Answer:

Explanation:

Gneiss is a high grade metamorphic rock, meaning that it has been subjected to higher temperatures and pressures than schist. However, unlike slate and schist, gneiss does not preferentially break along planes of foliation because less than 50% of the minerals formed during the metamorphism are aligned in thin layers.

Answer:

Mass, m = 71.42 kg

Explanation:

Given that,

Normal force acting on a box, F = 700 N

We need to find the mass of a box. Let it is m. Normal force acting on an object is balanced by its weight such that,

F = mg

Where m is the mass of the box

[tex]m=\dfrac{F}{g}\\\\m=\dfrac{700\ N}{9.8\ m/s^2}\\\\m=71.42\ kg[/tex]

So, the mass of the box is 71.42 kg.

Answer:

101 J

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 101 \ Joules}}[/tex]

Explanation:

Kinetic energy can be found using the following formula:

[tex]KE=\frac{1}{2}mv^2[/tex]

The mass of the baseball is 0.140 kilograms and the velocity is 38.0 meters per second.

[tex]m= 0.140 \ kg \\v= 38.0 \ m/s[/tex]

Substitute the values into the formula.

[tex]KE=\frac{1}{2} [0.140 \ kg][(38.0 \ m/s)^2][/tex]

First, evaluate the exponent.

[tex]KE=\frac{1}{2}(0.140 \ kg)(1444 \ m^2/s^2)[/tex]

Multiply the two numbers in parentheses together.

[tex]KE=\frac{1}{2}(202.16 \ kg*m^2/s^2)[/tex]

Multiply the fraction by the number, or divide the number by 2.

[tex]KE=101.08 \ kg*m^2/s^2[/tex]

Round to the nearest whole number. The 0 in the tenth place tells us we can leave the number as is.

[tex]KE\approx 101 \ kg*m^2/s^2[/tex]

1 kg*m²/s² is equal to 1 Joule. Therefore, our answer of 101 kg*m²/s² is equal to 101 Joules (J).

[tex]KE\approx 101 \ J[/tex]

The kinetic energy of the baseball is about 101 Joules.

The two fundamental forces that are only attractive is  A. Gravitational and strong nuclear.

The "strong" nuclear force outperforms gravity by a factor of 10 to the 38th. While gravitational and electromagnetic forces have relatively large ranges of action, the strong and weak nuclear forces operate at close ranges. All objects are affected by the strong and weak nuclear forces, whereas smaller objects are affected by gravitational and electromagnetic forces.

Nuclear forces are the most enticing of the four fundamental forces. There was no explanation provided as to how the nucleus in the atom is kept together by electromagnetism, which maintains matter together.

Therefore, option A is correct.

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Solution:

Mass of liquid water and water vapor in the insulated tank initially = 1.4 kg

Temperature = 200 °C

And 25% of the volume by liquid water is steam.

State 1

[tex]$m=\frac{V}{v}$[/tex]

[tex]$m=m_f+m_g$[/tex]

[tex]$1.4=\frac{0.25V}{v_f}+\frac{0.75V}{v_g}$[/tex]

[tex]$1.4=\frac{0.25V}{1.1565 \times 10^{-3}}+\frac{0.75V}{0.1274}$[/tex]       (taking the value of [tex]$v_g$[/tex] and [tex]$v_g$[/tex] at 200°C  )

[tex]$V=6.304 \times 10^{-3}$[/tex]

Now quality of vapor

[tex]$x=\frac{m_g}{m}$[/tex]

  [tex]$=3.377 \times 10^{-3}$[/tex]

Internal energy at state 1 can be found out by

[tex]$u_1=u_f+xu_{fg}$[/tex]

    [tex]$=850.65+3.377\times10^{-3}\times 1744.65$[/tex]

    = 856.54 kJ/kg

After heating with the resistor for 20 minutes, at state 2, the tank contains saturated water vapor [tex]$v_2=v_g \text { and }\ x=1$[/tex]

Tank is rigid, so volume of tank is constant.

[tex]$v_g=v_2=\frac{V}{m}$[/tex]

[tex]$v_g=\frac{6.304\times 10^{-3}}{1.4}$[/tex]

[tex]$v_g=4.502 \times 10^{-3} \ m^3 /kg$[/tex]

Now interpolate the value to get temperature at state 2 with specific volume value to get final temperature

[tex]$T_2=360+(374.14-360)\left(\frac{0.004502-0.006945}{0.003155-0.006945}\right)$[/tex]

   = 369.11° C

Internal energy at state 2

[tex]$u_2=2154.9 \ kJ/kg$[/tex]

Now power rating of the resistor

[tex]$P=\frac{m(u_2-u_1)}{t}$[/tex]

[tex]$P=\frac{1.4(2154.9-856.54)}{20 \times 60}$[/tex]

  = 1.51 kW

Explanation:

pls help me with this question pls

Answer:

F = 39.2 N   (hand force) and    N = 68.6 N (shoulder force)

Explanation:

In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole

Let's set the reference system at the fit point of the shoulder

     ∑ τ = 0

We will assume that the counterclockwise turns are positive

    w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0

all distances are measured from the support of the man (x₀ = 0.60 m)

    F = (w₁ 0.60 + W 0.1) / 0.4

    F = (m₁ 0.6 + m 0.1) g / 0.4

let's calculate

    F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4

    F = 39.2 N

this is the force that the hand must exert to keep the system in balance

We apply the translational equilibrium condition

    -w₁ -W + N - F = 0

     N = w₁ + W + F

     N = (m₁ + m) g + F

let's calculate

     N = (2.6 + 0.4) 9.8 + 39.2

     N = 68.6 N

Answer:

Assuming they're unit vectors (length of 1)

You simply add them together.

The vector pointing right can be described with X and Y

(1, 0).

The vector pointing down

(0, -1).

The numbers are taken from the axis in X and Y directions.

If you add them together you get a final vector.

(1, - 1)

This gives you -45° pointing South East.

Or 360°-45°=315°

Answer:

Medium: something in a middle position, maybe in between sizes big or small, or in a situation it's not negative or positive it's just neutral.  (I'm sorry if that wasn't helpful)

Explanation:

Answer:

C.

Explanation:

Answer:B

Explanation:

Mass

More mass is added to a wheelbarrow, and a larger force is required to move it - illustrates Newton's second law.

An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration."

Hence more mass is added to a wheelbarrow, and a larger force is required to accelerate, i.e., move it.

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Answer:

Speed of lighter ball is 4 m/s.

Explanation:

Applying the principle of conservation of linear momentum,

momentum before collision = momentum after collision.

[tex]m_{1}[/tex][tex]u_{1}[/tex] + [tex]m_{2}[/tex] [tex]u_{2}[/tex] = [tex]m_{1}[/tex][tex]v_{1}[/tex] - [tex]m_{2}[/tex][tex]v_{2}[/tex]

[tex]m_{1}[/tex] = 3 kg, [tex]u_{1}[/tex] = 8 m/s, [tex]m_{2}[/tex] = 2 kg, [tex]u_{2}[/tex] = 0 m/s ( since it is at rest), [tex]v_{1}[/tex] = 2 m/s, [tex]v_{2}[/tex] = ?

(3 x 8) + (2 x 0) = (8 x 2) - (2 x [tex]v_{2}[/tex])

24 + 0 = 16 - 2[tex]v_{2}[/tex]

2[tex]v_{2}[/tex] = 16 - 24

2[tex]v_{2}[/tex] = -8

[tex]v_{2}[/tex] = [tex]\frac{-8}{2}[/tex]

   = -4 m/s

This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.

Answer:

1) Deadball

2) Leather

3) Foot Fault

4) Pass

5) Captain

Explanation:

1) In most sports when a ball is out of play or termed temporarily unplayable, it is said to be a Deadball.

2) Volleyballs are generally made of leather materials be it synthetic or genuine leather.

3) In volleyball, when a server steps on or over the end line, it is called foot fault.

4) The first contact of a ball by a player after a serve from a passer is usually called a pass.

5) In volleyball, the referee issues a coin toss in presence of both captains and the captain with the winning toss is the one that makes the choice of play area and the first server.

Answer:

5 no

Explanation:

actually the 4kg lying on table has no influence

it slides towards 4kg weight hung

as it has excess 2kg force

force=miu × m ×g

The magnitude of acceleration of the entire system is  [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.

Given data:

The masses  suspended from the table are, m = 2 kg and m' = 4 kg.

And the mass kept on the table is, m'' = 4 kg.

The frictional force will oppose the motion of mass 4 kg, kept on the table. Then the required value of frictional force is,

[tex]f = \mu \times m'' \times g\\\\f = 0.11 \times 4 \times 9.8\\\\f = 4.312 \;\rm N[/tex]

Since, the mass kept on the right side is more. Then at equilibrium,

-f + m''g + (m' +m)a = m'g

Here,

a is the magnitude of acceleration of the system.

Solving as,

-4.312+ 4(9.8) + (4 -2)a = 4(9.8)

2a = 4.312

[tex]a \approx 2.1315 \;\rm m/s^{2}[/tex]

Thus, we can conclude that the magnitude of acceleration of the entire system is  [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.

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Answer:

1.

d . A stream of particles

2. D. Radiowave

3. Microwaves

Answer:

1.

d . A stream of particles

2. D. Radiowave

3. Microwaves

Explanation:

Answer:

C

Explanation:

Answer:

The gravitational force on the elevator = 4500N

Explanation:

The given parameters are;

The force applied by the elevator, F  = 4500 N

The acceleration of the elevator = Not accelerating

From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows;

F = W + Mass of elevator × Acceleration of elevator

∴ F = W + Mass of elevator × 0 = W

F = 4500 N = W

The net force on the elevator is F - W = 0

The gravitational force on the elevator = W = 4500N.

The gravitational force on the elevator, if the elevator is NOT accelerating is 4500 N.

Given data:

The magnitude of force on the elevator is, F = 4500 N.

From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows,

F = W + ma

Here, a is the acceleration of the elevator. Since, the elevator is not accelerating. Then, a = 0 .

The weight of the elevator is due to the gravitational force. So, we need to obtain the weight as gravitational force.

Solving as,

[tex]F = W+ma\\\\F=W +(m \times 0)\\\\4500=W\\\\W = 4500 \;\rm N[/tex]

Thus, we can conclude that the gravitational force on the elevator, if the elevator is NOT accelerating is 4500 N.

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I can try and help whats it about?

Answer:

82.7 m

Explanation:

u= 22m/s

a= 2.4 m/s^2.

t= 3.2 secs

Therefore the distance travelled can be calculated as follows

S= ut + 1/2at^2

= 22 × 3.2 + 1/2 × 2.4 × 3.2^2

= 70.4 + 1/2×24.58

= 70.4 + 12.29

= 82.7 m

Hence the distance travelled by the truck is 82.7 m

Answer:

When the elevator is accelerating downward, the person feels lighter due to the downward normal force being less than the person's weight.

Explanation:

A person riding in an elevator subjected to a series of unbalanced forces depending on the direction the elevator is travelling.

Two forces are acting on the person; the force of gravity and the upward normal force from the elevator.

When the elevator is going upwards with acceleration a, the person feels heavier than his normal weight, due to the upward normal force being greater than the person's weight. N = mg + ma

When the elevator is moving downwards with acceleration a, the person feels lighter due to the downward normal force being less than the person's weight. N = mg - ma

However, when the elevator is moving up or down at constant velocity ie. acceleration a = 0, the person experience a normal force equal to weight. N = mg

When the elevator is moving downwards with acceleration a = g, the person experiences weightlessness. N = (mg - mg) = 0

Answer:

The maximum height reached by the ball is 2.84 m

Explanation:

Given;

initial velocity of the soccer, u = 13 m/s

angle of projection, θ = 35°

The maximum height reached by the ball = ?

Apply the following kinematic equation, to determine the maximum height reached by the ball.

Maximum height (H) is given as;

[tex]H = \frac{U^2sin^2\theta}{2g} \\\\H = \frac{(13)^2(sin \ 35^0)^2}{2*9.8}\\\\H = 2.84 \ m[/tex]

Therefore, the maximum height reached by the ball is 2.84 m