Answer: I x - 16ozI ≤ 0.4oz
Step-by-step explanation:
The weight is supposed to be exactly 16 oz.
But we can accept a maximum error of 0.4oz.
Now, if x is the weight of the sugar bag, the error can be calculated as:
E = x - 16oz
if x is larger than 16oz, we have E positive, which means that we have more sugar than 16oz
if x is smaller than 16 oz, we have E negative, which means that we are a little bit short of sugar in the bag.
Now, we know that the maximum error acceptable is 0.4 oz (negative or positive)
So we can write:
-0.4oz ≤ E ≤ 0.4oz
-0.4 ≤ x - 16oz ≤ 0.4oz
Now, if we apply absolute value to the error, we get:
I x - 16ozI ≤ 0.4oz
So the correct option is the fourth one (or the bottom one)
Answer:
D.) |x−16|≤0.4
Step-by-step explanation:
Prove that a cubic equation x 3 + ax 2 + bx+ c = 0 has 3 roots by finding the roots.
That's a pretty tall order for Brainly homework. Let's start with the depressed cubic, which is simpler.
Solve
[tex]y^3 + 3py = 2q[/tex]
We'll put coefficients on the coefficients to avoid fractions down the road.
The key idea is called a split, which let's us turn the cubic equation in to a quadratic. We split unknown y into two pieces:
[tex]y = s + t[/tex]
Substituting,
[tex](s+t)^3 + 3p(s+t) = 2q[/tex]
Expanding it out,
[tex]s^3+3 s^2 t + 3 s t^2 + t^3 + 3p(s+t) = 2q[/tex]
[tex]s^3+t^3 + 3 s t(s+t) + 3p(s+t) = 2q[/tex]
[tex]s^3+t^3 + 3( s t + p)(s+t) = 2q[/tex]
There a few moves we could make from here. The easiest is probably to try to solve the simultaneous equations:
[tex]s^3+t^3=2q, \qquad st+p=0[/tex]
which would give us a solution to the cubic.
[tex]p=-st[/tex]
[tex]t = -\dfrac p s[/tex]
Substituting,
[tex]s^3 - \dfrac{p^3}{s^3} = 2q[/tex]
[tex](s^3)^2 - 2 q s^3 - p^3 = 0[/tex]
By the quadratic formula (note the shortcut from the even linear term):
[tex]s^3 = q \pm \sqrt{p^3 + q^2}[/tex]
By the symmetry of the problem (we can interchange s and t without changing anything) when s is one solution t is the other:
[tex]s^3 = q + \sqrt{p^3+q^2}[/tex]
[tex]t^3 = q - \sqrt{p^3+q^2}[/tex]
We've arrived at the solution for the depressed cubic:
[tex]y = s+t = \sqrt[3]{q + \sqrt{p^3+q^2}} + \sqrt[3]{ q - \sqrt{p^3+q^2} }[/tex]
This is all three roots of the equation, given by the three cube roots (at least two complex), say for the left radical. The two cubes aren't really independent, we need their product to be [tex]-p=st[/tex].
That's the three roots of the depressed cubic; let's solve the general cubic by reducing it to the depressed cubic.
[tex]x^3 + ax^2 + bx + c=0[/tex]
We want to eliminate the squared term. If substitute x = y + k we'll get a 3ky² from the cubic term and ay² from the squared term; we want these to cancel so 3k=-a.
Substitute x = y - a/3
[tex](y - a/3)^3 + a(y - a/3)^2 + b(y - a/3) + c = 0[/tex]
[tex]y^3 - ay^2 + a^2/3 y - a^3/27 + ay^2-2a^2y/3 + a^3/9 + by - ab/3 + c =0[/tex]
[tex]y^3 + (b - a^2/3) y = -(2a^3+9ab) /27 [/tex]
Comparing that to
[tex]y^3 + 3py = 2q[/tex]
we have [tex] p = (3b - a^2) /9, q =-(a^3+9ab)/54 [/tex]
which we can substitute in to the depressed cubic solution and subtract a/3 to get the three roots. I won't write that out; it's a little ugly.
The altitude of an airplane is decreasing at a rate of 41 feet per second. What is the change in altitude of the airplane over a period of 32 seconds?
Answer:
1312 feet
Step-by-step explanation:
41 ft=1 sec
how about 32 sec
41 x 32=1312/1=1312
If a dozen eggs cost $1.35, what is the unit cost?
A) $0.11
B) $0.13
C) $1.23
D) $4.29
Answer:
A) $0.11
Step-by-step explanation:
Since a dozen (12) eggs cost $1.35. You will divide $1.35 by 12. And it will equal 0.1125. Round it up it equals to 0.11.
WHICH EXPRESSION IS NOT EQUIVALENT?
Answer:
C
Step-by-step explanation:
First, factor the original expression:
[tex]2x^2+10x+12\\2(x^2+5x+6)\\2(x+3)(x+2)[/tex]
As we can see, D is the same as above. Eliminate D.
Go through each of the answer choices.
A:
[tex](2x+4)(x+3)\\=2(x+2)(x+3)[/tex]
This is equivalent to what we factored. Eliminate A.
B:
[tex](2x+6)(x+2)\\=2(x+3)(x+2)[/tex]
This is again equivalent to what we factored. Eliminate B.
C:
[tex](2x+3)(x+4)\\[/tex]
This cannot be simplified and it is not equivalent to what we have previously. C is not the equivalent expression.
Answer:
The expression that is not equivalent to 2x²+ 10x + 12 is c)
Step-by-step explanation:
Hello!
To resolve these equations you have to do the following steps:
For example, you have (a+b)(c+d) you have to multiply the first term included in the first parenthesis with the terms of the second parenthesis and add them:
a*c + a*d
Then do the same with the second term:
b*c + b*d
Finally, you add them
ac+ad+bc+bd
If there are common terms, you have to add them.
a)
(2x+4)(x+3)
First you multiply 2x by the terms contained in the second parenthesis.
2x*x + 2x*3= 2x²+6x
Then you do the same with 4
4*x + 4*3= 4x + 12
Now you put it all together:
2x²+6x + 4x + 12
and add common terms 6x + 4x= 10x
2x²+ 10x + 12
b)
(2x+6)(x+2)= 2x²+4x +6x +12= 2x²+ 10x + 12
c)
(2x+3)(x+4)= 2x²+8x + 3x + 12= 2x² + 11x + 12
d)
2(x+3)(x+2)
In this case you have three terms in the equation "2" "(x+3)" and "(x+2)"
First you have to resolve the multiplication between the parenthesis and then you can multiply it by two
First:
(x+3)(x+2)= x*x+x*2+3*x+3*2= x²+2x+3x+6= x²+ 5x + 6
Now you can multiply it by two:
2(x²+ 5x + 6)= 2*x²+ 2*5x + 2*6= 2x² + 10x + 12
The expression that is not equivalent to 2x²+ 10x + 12 is c)
I hope this helps!
if the focus of an ellipse are (-4,4) and (6,4), then the coordinates of the enter of the ellipsis are
Answer:
The center is (1,4)
Step-by-step explanation:
The coordinates of the center of an ellipse are the coordinates that are in the middle of the two focus.
Then if we have a focus on [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], we can say that the coordinates for x and y can be calculated as:
[tex]x=\frac{x_1+x_2}{2}\\ y=\frac{y_1+y_2}{2}[/tex]
So, replacing [tex](x_1,y_1)[/tex] by (-4,4) and [tex](x_2,y_2)[/tex] by (6,4), we get that the center is:
[tex]x=\frac{-4+6}{2}=1\\ y=\frac{4+4}{2}=4[/tex]
Noah tried to prove that cos(θ)=sin(θ) using the following diagram. His proof is not correct.
Answer:
The first statement is incorrect. They have to be complementary.
Step-by-step explanation:
You can't say the measure of angle B is congruent to theta because it is possible for angles in a right triangle to be different.
You can only say that what he said is true if the angle was 45 degrees, but based on the information provided it is not possible to figure that out.
The other two angles other than the right angle in a right triangle have to add up to 90 degrees, which is the definition of what it means for two angles to be complementary. A is the correct answer.
Answer:
[tex]\boxed{\sf A}[/tex]
Step-by-step explanation:
The first statement is incorrect. The angle B is not equal to theta θ. The two acute angles in the right triangle can be different, if the triangle was an isosceles right triangle then angle B would be equal to theta θ.
Help anyone????? (this is due today)
Answer: not enough data shown to proceed with this question
Step-by-step explanation:
please help it's Factorisation with Numbers
Answer:
C.
6a + 18x + 18p
Step-by-step explanation:
3(2a + 6 (x + p)) firs multiply (x + p) with 6
3 (2a + 6x + 6z) now multiply inside the parenthesis with 3 and the answer would be 6a + 18x + 18p
tje mean of 12 scores is 8.8 what is the sum of tue 12 scores
Answer:
105.6
Step-by-step explanation:
If the mean is 8.8, than that means that in total the sum must be (8.8 * 12) which equals 105.6.
This is because the sum of all the numbers in a list divided by the amount of numbers in a list equals the mean.
Which interval contains a local minimum for the graphed
function?
Answer:
[2.5 ,4]
Step-by-step explanation:
The graph in this interval has a vertex while opening up wich means it's a minimum
Heights for teenage boys and girls were calculated. The mean height for the sample of 46 boys was 195 cm and the variance was 58. For the sample of 66 girls, the mean was 165 cm and the variance was 75. Estimate how much taller teenage boys are using a 85% confidence level. Round answers to the nearest hundredth and provide the point estimate together with the margin of error.
Answer:
With a 85% confidence level you'd expect the teenage boys to be on average between [29.217; 30.783]cm taller than the girls.
Step-by-step explanation:
Hello!
Given the variables:
X₁: height of a teenage boy.
n₁= 46
[tex]\frac{}{X}[/tex]₁= 195cm
S₁²= 58cm²
X₂= height of a teenage girl
n₂= 66
[tex]\frac{}{X}[/tex]₂= 165cm
S₂²= 75cm²
If the boys are taller than the girls then you'd expect μ₁ > μ₂ or expressed as a difference between the two population means: μ₁ - μ₂ > 0
To estimate the difference between both populations you have to calculate the following interval:
([tex]\frac{}{X}[/tex]₁- [tex]\frac{}{X}[/tex]₂) + [tex]t_{n_1+n_2-2; 1-\alpha /2}[/tex] * [tex]\sqrt{\frac{S_1}{n_1} +\frac{S_2}{n_2} }[/tex]
[tex]t_{n_1+n_2-2; 1-\alpha /2}= t_{110; 0.925}= 1.450[/tex]
Point estimate: ([tex]\frac{}{X}[/tex]₁- [tex]\frac{}{X}[/tex]₂) = (195-165)= 30
Margin of error:[tex]t_{n_1+n_2-2; 1-\alpha /2}[/tex] * [tex]\sqrt{\frac{S_1}{n_1} +\frac{S_2}{n_2} }[/tex]= 1.450*0.54= 0.783
30 ± 0.783
[29.217; 30.783]
With a 85% confidence level you'd expect the teenage boys to be on average between [29.217; 30.783]cm taller than the girls.
I hope this helps!
Graph image of figure using transformation given. Reflection across x-axis.
Answer:
Q(1,1), N(3,2) A(2,5)
Step-by-step explanation:
Which statement must be true if ?
A.
B.
C.
D.
Answer:
D
Step-by-step explanation:
D because they are congruent try measuring it.
Answer:
[tex]\boxed{\mathrm{D}}[/tex]
Step-by-step explanation:
The triangles are congruent.
The angles that are corresponding on both triangles must be congruent.
Angle Q in triangle PQR must be congruent to angle T in triangle STU.
a person can do a job in 6 day days . another can do the same job in 4days . if they work together, how long do they need to finish the job?
Answer:
It will take them 2 2/5 days working together
Step-by-step explanation:
To find the time worked
1/a + 1/b = 1/t
Where a and b are the times worked individually and t is the time worked together
1/4 + 1/6 = 1/t
Multiply each side by 12t to clear the fractions
12t( 1/4 + 1/6 = 1/t)
3t + 2t =12
Combine like terms
5t = 12
Divide by 5
t = 12/5
t = 2 2/5
It will take them 2 2/5 days working together
The instructor wants to give an A to the students whose scores were in the top of the class. What is the minimum score needed to get an A
Answer:
The minimum svore required to get an A is 85.3.
Step-by-step explanation:
Complete Question
Exam grades: Scores on a statistics final in a large class were normally distributed with a mean of 75 and a standard deviation of 8.
The instructor wants to give an A to the students whose scores were in the top 10% of the class. What is the minimum score needed to get an A?
Solution
Scores in the top 10% of the class will have a minimum greater than the remaining bottom 90% of the class.
If the minimum score for the top 10% of the class is x'
P(X ≤ x') = 90% = 0.90
If the z-score of this minimum score of the top 10%, x', is z'.
P(X ≤ x') = P(z ≤ z') = 0.90
using the z-distribution tables
z' = 1.282
But the z-score of any value is given as the value minus the mean divided by the standard deviation.
z = (x - μ)/σ
So,
z' = (x' - μ)/σ
Mean = 75
Standard deviation = 8
z' = 1.282
1.282 = (x' - 75)/8
x' = (1.282 × 8) + 75 = 85.256
= 85.3 to 3 s.f.
Hope this Helps!!!
A sample of 150 CBC students was taken, and each student filled out a
survey. The survey asked students about different aspects of their college
and personal lives. The experimenter taking the survey defined the
following events:
A=The student has children
B = The student is enrolled in at least 12 credits
C = The student works at least 10 hours per week
The student found that 44 students in the sample had children, 73 were
enrolled in at least 12 credits, and 105 were working at least 10 hours per
week. The student also noted that 35 students had children and were
working at least 10 hours per week.
Calculate the probability of the event BC for students in this sample. Round
your answer to four decimal places as necessary.
Answer:
The probability of the event BC
= the probability of B * C = 48.6667% * 70%
= 34.0667%
Step-by-step explanation:
Probability of A, students with children = 44/150 = 29.3333%
Probability of B, students enrolled in at least 12 credits = 73/150 = 48.6667%
Probability of C, students working at least 10 hours per week = 105/150 = 70%
Therefore, the Probability of BC, students enrolled in 12 credits and working 10 hours per week
= 48.6667% * 70%
= 34.0667%
4.5/y = 12.5/4 PLEASE HELP!!! SOS
Answer:
y = 1.44
Step-by-step explanation:
What are you aiming to do here? Please share all instructions with each problem.
If you want to solve 4.5/y = 12.5/4 for y: Multiply both sides by 4y:
18 = 12.5y. Then y = 1.44
plz help.... 2|x-3|-5=7
Answer:
x = -3 and x = 9.
Step-by-step explanation:
2|x - 3| - 5 = 7
2|x - 3| = 12
|x - 3| = 6
x - 3 = 6
x = 9
-(x - 3) = 6
-x + 3 = 6
-x = 3
x = -3
Hope this helps!
Answer:
x=9 x=-3
Step-by-step explanation:
2|x-3|-5=7
Add 5 to each side
2|x-3|-5+5=7+5
2|x-3|=12
Divide by 2
2/2|x-3|=12/2
|x-3|=6
There are two solutions to an absolute value equation, one positive and one negative
x-3 =6 x-3 = -6
Add 3 to each side
x-3+3 = 6+3 x-3+3 = -6+3
x=9 x = -3
need help with these 3 questions (giving brainiest if you can answer with equations)
Problem 10
Answer: approximately 57.39159 kmExplanation: You'll use the equation cos(28) = d/65 to solve for d to get d = 65*cos(28) = 57.39159 approximately. We use the cosine ratio because it ties together the adjacent and hypotenuse.
=====================================
Problem 11
Answer: approximately 10.46162 metersExplanation: This time we use the sine rule. We have the height as the opposite side (which is unknown, call it x) and the hypotenuse is the ladders length (11). So we have sin(72) = x/11 which solves to x = 11*sin(72) = 10.46162
=====================================
Problem 12
Answer: approximately 16.05724 cmExplanation: Now we use the tangent rule to connect the opposite and adjacent sides.
tan(37) = 12.1/x
x*tan(37) = 12.1
x = 12.1/tan(37)
x = 16.05724 approximately
Suppose that you expect SugarCane stock price to decline. So you decide to ask your broker to short sell 2000 shares. The current market price is $40. The proceeds from the short sale $80,000 is credited into your account. However, a few days later the market price of the stock jumps to $80 per share and your broker asks you close out your position immediately. What is your profit or loss from this transaction?
Answer:
Loss = $80000
Step-by-step explanation:
To determine if it's a profit or loss is simple.
He predicted the sugar cane stock to fall so he sold , but few days later the stock grew and went bullish.
He sold at$ 40 for 2000 shares
=$ 80000
But the stock went up to $80 per share that is gaining extra $40
So it was actually a loss.
The loss is =$40 * 2000
The loss = $80000
Connor has a collection of dimes and quarters with a total value of $6.30. The number of dimes is 14 more than the number of quarters. How many of each coin does he have?
Answer:
14 Quarters and 28 dimes
Step-by-step explanation: 14 quarters $3.50
28 dimes is $2.80 total is $6.30
Determine which expression could represent a polynomial with a factor of (x - √3i)
Answer:
Option (3)
Step-by-step explanation:
[tex](x-i\sqrt{3})[/tex] is a factor of a polynomial given in the options, that means a polynomial having factor as [tex](x-i\sqrt{3})[/tex] will be 0 for the value of x = [tex]i\sqrt{3}[/tex].
Option (1),
3x⁴ + 26x² - 9
= [tex]3(i\sqrt{3})^{4}+26(i\sqrt{3})^2-9[/tex] [For x = [tex]i\sqrt{3}[/tex]]
= 3(9i⁴) + 26(3i²) - 9
= 27 - 78 - 9 [Since i² = -1]
= -60
Option (2),
4x⁴- 11x² + 3
= [tex]4(i\sqrt{3})^4-11(i\sqrt{3})^2+3[/tex]
= 4(9i⁴) - 33i² + 3
= 36 + 33 + 3
= 72
Option (3),
4x⁴ + 11x² - 3
= [tex]4(i\sqrt{3})^4+11(i\sqrt{3})^2-3[/tex]
= 4(9i⁴) + 33i² - 3
= 36 - 33 - 3
= 0
Option (4),
[tex]3x^{4}-26x^{2}-9[/tex]
= [tex]3(i\sqrt{3})^4-26(i\sqrt{3})^{2}-9[/tex]
= 3(9i⁴) - 26(3i²) - 9
= 27 + 78 - 9
= 96
Therefore, [tex](x-i\sqrt{3})[/tex] is a factor of option (3).
Solve the equation and give the solution 6x – 3y = 3 –2x + 6y = 14
Answer:
x=3.9 or 39/10 and y=3.13333 or 47/15
Step-by-step explanation:
Since both expressions (6x-3y) and (3-2x+6y) are equal to 14, separate the equations:
6x-3y=14 and 3-2x+6y=14
Simplify the equations
6x-3y=14 and -2x+6y=11
Now, line the equations up and pick a variable (either x or y) to eliminate
6x-3y=14
-2x+6y=11
In this case, let's eliminate y first. To do so make the y values in both equations the same but with opposite signs. Make both be 6y but one is +6y and the other -6y
Multiply (6x-3y=14) by 2 to get:
12x-6y=28
Line the equations up and add or subtract the terms accordingly
12x-6y=28
-2x+6y=11
This becomes:
10x+0y=39
Isolate for x
x= 39/10 or x= 3.9
Now substitute the x value into either of the original equations
6x-3y=14
6(3.9)- 3y=14
Isolate for y
23.4-14=3y
3y= 9.4
y= 3.1333 (repeating) or y= 47/15
Answer: x = 39/10, y = 94/30
Step-by-step explanation:
6x - 3y = 3 - 2x + 6y,
Now solving this becomes
6x + 2x -3y - 6y = 3
8x - 9y = 3 ------------------- 1
3 - 2x + 6y. = 14
-2x + 6y = 14 - 3
-2x. + 6y = 11
Now multiply both side by -1
2x. - 6y = -11 ----------------- 2
Solve equations 1 & 2 together
8x - 9y. = 3
2x - 6y = -11
Using elimination method
Multiply equation 1 through by 2 ,and equation 2 be multiplied by 8
16x - 18y = 6
-16x - 48y = -88 ------------------------- n, now subtract
30y = 94
Therefore. y = 94/30.
Now substitute for y in equation 2
2x - 6y = -11
2x - 6(94/30) = -11
2x - 94/5 = -11
Now multiply through by 5
10x - 94 = -55
10x = -55 + 94
10x = 39
x = 39/10
In the figure below, which term best describes point L?
Explanation:
The tickmarks show which pieces are congruent to one another, which in turn show the segments have been bisected (cut in half). The square angle markers show we have perpendicular segments. So we have three perpendicular bisectors. The perpendicular bisectors intersect at the circumcenter. The circumcenter is the center of the circumcircle. This circle goes through all three vertex points of the triangle.
A useful application is let's say you had 2 friends and you three wanted to pick a location to meet for lunch. Each person traveling from their house to the circumcenter's location will have each person travel the same distance. We say the circumcenter is equidistant from each vertex point of the triangle. In terms of the diagram, LH = LJ = LK.
Answer: B.) Circumcenter
Step-by-step explanation:
540 beads are shared in the ratio 4:5. The larger share of beads is
Answer:
300
Step-by-step explanation:
A(dd): 4+5= 9
D(ivide): 540/9 = 60
T(imes): 4 x 60= 240 beads
5 x 60= 300 beads
I hope this helped :)
Number of larger share of beads is 300 seeds
Given that;
Number of total beads = 540
Beads ratio = 4:5
Find:
Number of larger share of beads
Computation:
Number of larger share of beads = 5[540 / (4+5)]
Number of larger share of beads = 5[540 / 9]
Number of larger share of beads = 5[60]
Number of larger share of beads = 300 seeds
Learn more:
https://brainly.com/question/13419413?referrer=searchResults
The _________ measures the strength and direction of the linear relationship between the dependent and the independent variable.
Answer:
Correlation Coefficient
Step-by-step explanation:
The shape in the figure is constructed from several identical squares. If the side of each square is 1 unit, what is the area and the perimeter of the shape?
Answer:
Area = 7 square units
Perimeter = 14 units
Step-by-step explanation:
The figure shown above consists of 7 squares, each having a side length of 1 unit.
==>Area of shape = area of 1 square × 7
Area of shape = s² × 7.
Where, s = side length = 1 unit
Area of shape = 1² × 7
= 1 × 7
Area = 7 square units
==>Perimeter of shape:
The perimeter of the shape is the sum of all the external sides of the 7 squares that form along the boundary of the shape. Check the attachment to see each side length that makes up the length of the entire boundary.
Perimeter of shape = 1 + 1 + 1 + ½ + ½ + 1 + 1 + ½ + 1½ + 1 + 4 + 1 = 14 units.
Two types of survey questions are open questions and closed questions. An open question allows for any kind of response; a closed question allows for only a fixed response. An open question and a closed question with its possible choices are given below. List the advantages and disadvantages of each question.
Open question: What can be done to get students to eat healthier foods?
Closed question: How would you get students to eat healthier foods?
1. Mandatory nutrition course
2. Offer only healthy foods in the cafeteria and remove unhealthy foods
3. Offer more healthy foods in the cafeteria and raise the prices on unhealthy foods
What are the advantag?
A. It is easy to compare the results of surveys with open questions.
B. An open question allows for new solutions to be introduced.
C. It is easy to quantify the responses of open questions.
D. An open question allows the respondent to go in-depth with their answer.
What are the disadvantages of an open question?
A. It is difficult to compare the results of surveys with open questions.
B. It is difficult to quantify the responses of open questions.
C. The form of the question may influence the opinion of the respondent.
D. An open question limits the possible responses of the respondent.
Answer and explanation:
Advantages of open questions:
B. An open question allows for new solutions to be introduced.
D. An open question allows the respondent to go in-depth with their answer.
Disadvantages of open questions:
A. It is difficult to compare the results of surveys with open questions.
B. It is difficult to quantify the responses of open questions.
Advantages of closed questions:
- It is easy to compare the results of surveys with closed questions.
- It is easy to quantify the responses of closed questions.
Disadvantages of closed questions:
- A closed question limits the possible responses of the respondent.
-The researcher must spend time to generate a satisfactory list of possible responses from the respondent.
- possible answers may also be insufficient to be useful.
Open questions and closed questions in research questionnaires are two popular methods of getting data from respondents. They both have advantages and disadvantages and can be used interchangeably or together in questionnaires.
Closed Questions have defined answer alternatives or answer categories. Eg: Which is your favourite time of the day? (Morning or Evening etc)
Open Questions have free answers, not clear defined alternatives or categories. Eg : Why do you like morning/ evening time the most ?
Closed Questions give brief concrete answers, Open Questions have more essence of subjective & personal elaboration.
Advantages of Open Questions
Open questions allows for new solutions to be introduced. Open questions allows the respondent to go in-depth with their answer.Disadvantages of Open Questions
It is difficult to compare the results of surveys with open questions.It is difficult to quantify the responses of open questions.Advantages of Closed Questions
It is easy to quantify the responses, with these questions. It is easy to compare the results, with these questionsDisadvantages of Closed Questions
The form of question may influence potential of respondent. It limits the possible responses of respondentTo learn more, refer https://brainly.com/question/2855510?referrer=searchResults
A researcher wants to study the relationship between salary and gender. She randomly selects 297 individuals and determines their salary and gender. Can the researcher conclude that salary and gender are dependent?
Answer:
The researcher cannot conclude that salary and gender are dependent.
Step-by-step explanation:
A dependent variable is a variable, for example "Salary" that depends on an independent variable, e.g. "Gender." Salary is the dependent variable while gender is the independent variable. This means that the value of salary changes in relation to the gender and not vice versa. Two variables become dependent if they change based on another independent variable that is operating on them. In this research, the researcher is not trying to measure gender but the relationship between salary and gender. To achieve her purpose, she shows that salary depends on gender and not that gender depends on salary.
Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?
Answer:
The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is [tex]z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)[/tex].
The domain of the function is all real numbers and its range is between -4 and 5.
The graph is enclosed below as attachment.
Step-by-step explanation:
Let be [tex]z (x) = \cos x[/tex] the base formula, where [tex]x[/tex] is measured in sexagesimal degrees. This expression must be transformed by using the following data:
[tex]T = 180^{\circ}[/tex] (Period)
[tex]z_{min} = -4[/tex] (Minimum)
[tex]z_{max} = 5[/tex] (Maximum)
The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of [tex]2\pi[/tex] radians. In addition, the following considerations must be taken into account for transformations:
1) [tex]x[/tex] must be replaced by [tex]\frac{2\pi\cdot x}{180^{\circ}}[/tex]. (Horizontal scaling)
2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:
[tex]\Delta z = \frac{z_{max}-z_{min}}{2}[/tex]
[tex]\Delta z = \frac{5+4}{2}[/tex]
[tex]\Delta z = \frac{9}{2}[/tex]
3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)
[tex]z_{m} = \frac{z_{min}+z_{max}}{2}[/tex]
[tex]z_{m} = \frac{1}{2}[/tex]
The new function is:
[tex]z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)[/tex]
Given that [tex]z_{m} = \frac{1}{2}[/tex], [tex]\Delta z = \frac{9}{2}[/tex] and [tex]T = 180^{\circ}[/tex], the outcome is:
[tex]z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)[/tex]
The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.