Answer:
The flux through the sphere will remain the same, and the magnitude of the electric field will increase by four times.
Explanation:
The electric flux is the number of electric field, passing through a given area. It is proportional to the electric field strength and the area through which this field passes.
If the radius of the sphere is halved, the area of the sphere will reduce by square of the reduction, which will be four times. The electric field lines will become closer together, or technically increase by a fourth of its initial value. The resultant effect is that the electric flux will remain the same.
If originally,
Φ = EA cos∅
where Φ is the electric flux through the sphere
E is the electric field on the sphere
A is the area of the sphere.
If the area of the sphere is reduced to half, then,
the area reduces to A/4,
and the electric field increases to be 4E on the sphere.
The flux now becomes
Φ = 4E x A/4 cos∅
which reduces to
Φ = EA cos∅
which is the initial electric flux on the sphere.
What does addition of two vectors give you?
Answer:
Explanation:
To add or subtract two vectors, add or subtract the corresponding components. Let →u=⟨u1,u2⟩ and →v=⟨v1,v2⟩ be two vectors. The sum of two or more vectors is called the resultant. The resultant of two vectors can be found using either the parallelogram method or the triangle method .
A mass of 1.15 kg of air at 111 kPa and 27 C is contained in a gas-tight, frictionless piston cylinder device. The air is now compressed to a final pressure of 0.84 MPa. During this process, heat is transferred from the air such that the temperature inside the cylinder remains constant. Calculate the work input (in kJ) during this process.
Answer:
Work input W = -200.39 KJ
Explanation:
From the question, we are given;
m = 1.15 kg
Constant temperature T1 = T2 = 27 + 273 = 300k
Since the temperature is constant, we can say that the process is isothermal
P1 = 111 KPa
P2 = 0.84 MPa = 0.84 * 1000 KPa = 840 KPa
Now what we want to calculate is W1-2
Mathematically, for isothermal process;
W1-2 = mRTlnP1/P2
where R can be obtained from table and it is equal to 0.287 KJ/kg.k
Hence;
W1-2 = (1.15)(0.287)(300)(ln 111/840)
W1-2 = 99.015 * -2.023871690525 = -200.39 KJ
Kindly note that the value of the work is negative because work is done on the system and not by the system
The density of water is 1000 kg m^3. What is the value expressed in gcm^-3 units? please help me..
(1) 1000 (2) 100 (3) 1 (4) 0.1 (5) 0.01
Here's the neat, cool way to convert units like this:
-- 1 kilogram = 1,000 grams
-- 1 meter = 100 centimeters
So . . . . .
(1000 kg/m³) x (1000 g/kg) x (1 m/100 cm)³ =
(1,000 kg/m³) x (1,000 g/kg) x (1 m³/1,000,000 cm³) =
(1,000 x 1,000 x 1 / 1,000,000) (kg-g-m³ / m³-kg-cm³) = 1 g/cm³
Which of the following would cause the force of static friction to increase?
Answer:
Answer B) An increase in [tex]\mu_S[/tex]
Explanation:
Since we are talking about the force of static friction, due to its definition as the product between the normal force to the surface times the coefficient of static friction, the only two ways such force could increase is due to an increase in the normal force, or an increase in the coefficient of static friction [tex]\mu_S[/tex].
So the only valid answer is answer B)
A car engine burns gas at 495 K and exhausts to the air at 293 K. What is the highest possible efficiency it could have?
(NO UNIT)
Answer:
59.19%
Explanation:
Step 1:
Data obtained from the question. This include the following:
Input temperature = 495 K.
Output temperature = 293 K.
Efficiency =..?
Step 2:
Determination of the efficiency of the engine.
Efficiency is simply defined as the ratio of output to input times 100. Mathematically, it is expressed as:
Efficiency = output /input x 100
With the above formula, we can calculate the efficiency of the engine as follow:
Input temperature = 495 K.
Output temperature = 293 K.
Efficiency =..?
Efficiency = output /input x 100
Efficiency = 293/495 x 100
Efficiency = 59.19%
Therefore, the efficiency of the engine is 59.19%
Answer:
0.41
Explanation:
Trust me bro
A river flows with a speed of 3km/h in still water. A man who can swim with a speed of 5km/h wishes to reach a point on the other bank just opposite to the starting point. In which direction should he put his strokes and how long will he take to cross the river of width 1.2km? Please try to provide a diagram and step by step explanation.
Answer:
Explanation:
Let the angle required be θ with direction opposite to current .
cos θ = 3 / 5
θ = 53° .
Resultant velocity towards the opposite side
= √ ( 5 ² - 3²)
= 4 km /h
distance covered = 1.2 km
time taken = 1.2 / 4 = .3 h
= 18 min .
A 70.0 kg skier is at rest at the top of a 120m hill. Assuming friction is negligible.
A) What is the speed of the skiers at the bottom of the hill?
Answer:
49 m/s
Explanation:
Initial potential energy = final kinetic energy
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 10 m/s² × 120 m)
v = 49 m/s
Culture creates the context for behavior in society. true or false
Answer:
True every culture is diffrent and culture is the way to grow up, the people or things you live around, or the ways of life you follow or dress.
Explanation: The definition of culture is: means a particular set of customs, morals, codes and traditions from a specific time and place. All of that develops how a person may behave in society.
Answer:
true
Explanation:
just took the quiz
What is the wavelength of the following waves?
Answer:
i. the wavelength is 7.2 m
ii. the wavelength is 2.4 m
Explanation:
the wavelength of a wave is from crest to crest or from trough to trough.
Suppose the position of an object moving in a straight line is given by s (t )equals 5 t cubed minus 2 t squared plus 9. Find the instantaneous velocity when tequals7.
Answer:
Explanation:
s(t) = 5t³-2t²+9
Instantaneous velocity v = ds / dt
v = ds/dt = 15t²-4t
Putting t = 7
v = 15 x 7² - 4 x 7
= 707
Instantaneous velocity at t = 7
is 707 unit .
A hollow circular shaft made of 304 stainless steel uniformly tapers from an outer diameter of 3.0 cm to an outer diameter of 4.0 cm over a length of 2 meters. The inner diameter of 1.0 cm is constant over the length of the shaft. The shaft is subjected to an applied torque of 500 Nm. Determine the maximum shear stress in the shaft.
Answer:
maximum shear stress = τ(max) = 95.49 × 10⁶N/m²
Explanation:
given
outer diameter at one end(D₁) = 3.0cm
outer diameter at the other end(D₂) = 4.0cm
inner diameter(d₁) = 1.0cm
torque applied(T) = 500Nm
maximum shear stress will occur at lower outer diameter
the formula is τ/r = T/J
τ= T × r/J
where r is radius
T is the torque
J is the polar 2nd M of area
attached is the calculation of the question
Calculate the speed of a car that travels 355km in 15 hours , a good answer please
Answer:
23.67 km / hr
Explanation:
car travels 355 km (d)
duration = 15 hrs (t)
average speed formula = v = d / t
v = 355 km / 15 hr
v = 23.67 km / hr
Explanation:
Hello, there!!!
Here, your question is asking about the speed and the given are:
distance (s)= 355km
time (t) = 15hrs.
speed (v)=?
now,
we have the formula:
v= s/t
or, v = 335km /15 hrs.
Therefore, the speed of car was 23.67km/hr.
Hope it helps..
The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volume of the balloon? (Hint: n and P are constant) (Unit= m^3)
Answer:
[tex]\boxed{ V_{2}= 0.03189 m^3}[/tex]
Explanation:
According to Charles Law
=> [tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
Where [tex]V_{1}[/tex] = 0.0279 m³, [tex]T_{1}[/tex] = 280 K and [tex]T_{2}[/tex] = 320 K
=> [tex]\frac{0.0279}{280} = \frac{V_{2}}{320}[/tex]
=> [tex]V_{2}[/tex] = 0.03189 m³
The discharge of a stream is Choose one: likely to decrease downstream in arid regions and increase downstream in temperate regions. typically lower in spring than during summer. constant for the length of the stream. calculated by dividing its cross-sectional area by its velocity.
Answer:
likely to decrease downstream in arid regions and increase downstream in temperate regions
Explanation:
Arid regions are is a region with a severe lack of water, usually to the extent that affect the organisms living in the region. Arid regions are characterized by a very low depth of rainfall per year. Temperate region on the other hand experience more distinct seasonal change and wider temperature change. Temperate regions get a fairly large amount of rainfall per year.
In arid regions, the soil is very dry, and the rate of infiltration and percolation is high relative to the amount of rainfall available. The effect is that more water is infiltrated into the soil as you move downstream, leading to a decrease in the discharge of a stream as you move downstream. Most temperate region have soils that are usually saturated in the peak of the rainfall season, leading to a greater stream discharge as you move downstream.
Sally is concerned about the X-ray images her dentist plans to take of her teeth. She has read that X-rays can cause tissue effects, such as skin reddening and hair loss. Which statement would best inform Sally of the level of risk
Answer:
B. The dentist uses X-ray radiography, which takes too short a time to cause those problems.
Explanation:
The statement B would best inform Sally of the level of risk. The dentist uses X-ray radiography, which takes too short a time to cause those problems and risk.
What is X-ray imaging?X-ray imaging provides images of human internal organs. The photos depict your body parts in various colors of black and white.
Because various tissues absorb varying quantities of radiation, this is the case. Because calcium absorbs the most x-rays, bones appear white.
When X-ray radiation passes into our bodies, it damages molecular structures and may cause injury.
Human cells are damaged by extremely high doses of radiation, as indicated by skin burns, hair loss, and an increased risk of cancer.
Sally is concerned about the X-ray images her dentist plans to take of her teeth. She has read that X-rays can cause tissue effects, such as skin reddening and hair loss.
The statement B would best inform Sally about the level of risk. The dentist uses X-ray radiography, which takes too short a time to cause those problems and risk.
Hence, statement B would best inform Sally about the level of risk.
To learn more about the X-ray imaging, refer to the link;
https://brainly.com/question/27425971
#SPJ2
A sports car moving at constant velocity travels 120m in 5.0s. If it then brakes and comes to a stop in 4.0s,what is the magnitude of it's acceleration?
✔ First calculating the speed :
V = d(in m)/t(in s)
V = 120/5 V = 24 m/s✔ You now know the average car's speed, is time it takes to stop it completely, so you can calculate its acceleration :
a = V/t
a = -24/4 a = 6 m/s² The car has an acceleration of 6 m/s².SOMEONE HELP ME PLEASE!!!
a. What is the displacement of the car in the graph?
b. What distance has the car travelled?
Answer:
a. 2 m
b. 4 m
Explanation:
a. Assuming d is the position of the car, the displacement is the difference between the final position and the initial position. 3 m - 1 m = 2 m.
b. From t = 0 to t = 2.5, the car moves a distance of 3 m. From t = 2.5 to t = 4, the car moves another 1 m.
So the car moves a total distance of 4 m.
Janaki Temple and Pashupatinath Temple are increasing our pride how
Answer:
Janaki temple and Pashupatinath Temple are found in Nepal. These structures are religious and they increase the pride of the country through tourism. These temples are important in the country and are mostly visited by tourists.
This also helps to bring in income for the country and also helps by attracting many visitors and a corresponding development of its tourism industry.
Bumper car A (331 kg) moving east at 3.87 m/s hit stationary car B (208 kg). After, the car A moves .88 m/s east. What is the velocity of car B?
Answer:
Ub = 221.99m/s
Explanation:
(Ma x Ua)+(Mb x Ub) = (Ma + Mb)V
(331 x 3.87)+(208 x Ub) = (331 + 208)88
(1257.8) + (208 x Ub) = 47432
(208 x Ub) = 47432 - 1257.8
(208 x Ub) = 46174.2
Ub = 46174.2/208 = 221.99m/s
Ub = 221.99m/s
Answer:
4.75
Explanation:
M1V1 + M2V2 = M1V3 + M2V4
[(331*3.87) , 90°] + 0 = [(331*0.888) , 90°] + M2V4
M2V4 = 987.042 , 90°
divide through by M2
V4 = 4.75 m/s east
Please help me with this question ASAP.
In a a potentiometer circuit, a 1m long potentiometer wire PQ of resistance 10 ohms is connected in series with a cells of e.m.f. 9V with internal resistance 3 ohms Calculate:
i The p.d. across PQ
ii. The e.m.f. of a cell which has a balance point of 75cm.
Answer:
i. 6.923 V
ii. The e.m.f. = 22.5 V
Explanation:
i. The given parameters are;
Length of potentiometer = 1 m
The resistance of the potentiometer = 10 Ω
The e. m. f. of the attached cell = 9 V
The current, I flowing in the circuit = e. m. f/(Total resistance)
The current, I flowing in the circuit = 9 V/(10 + 3) = 9/13 A
The potential difference, p.d. across the 1 m potentiometer wire = I × Resistance of the potentiometer wire
The p.d. across the potentiometer wire = 9/13×10 = 90/13 = 6.923 V
ii) Given that the 1 m potentiometer wire has a resistance of 10 Ω, 75 cm which is 0.75 m will have an e.m.f. given by the following relation;
[tex]\dfrac{E}{R_{balance}} = \dfrac{V}{R_{cell}}[/tex]
Where:
E = e.m.f. of the balance point cell
[tex]R_{balance}[/tex] = Resistance of 75 cm of potentiometer wire = 0.75×10 = 7.5 Ω
[tex]R_{cell}[/tex] = Resistance of the cell in the circuit = 3 Ω
V = e.m.f. attached cell = 9 V
[tex]\dfrac{E}{7.5} = \dfrac{9}{3}[/tex]
E = 7.5*3 = 22.5 V
The e.m.f. = 22.5 V
In a given chemical reaction the time energy of the products is less than the energy of the reactants which statements is true for this chemical reaction
Answer:
Energy is released in this reaction possibly in the form of heat thus it is an exergonic and or exothermic reaction.
Explanation:
The energy is sometimes transferred as heat, inflicting the reaction mixture and its surroundings to become hotter. The temperature increase may be detected employing a measuring device. Some samples of exothermic reactions are: Combustion .An chemical reaction may be a chemical process that releases energy by lightweight or heat
Hope this helps...
Have a nice day!!!!
explain why the term Nano is used to describe nanotechnology
Answer:
Nanotechnology means working with materials at the scale of one billionth of a metre.
Explanation:
The prefix “nano” refers to one billionth: it’s part of the scientific scale of measurement. Its science, engineering, and technology are conducted at the nanoscale, which is about 1 to 100 nanometers. Nanoscience and nanotechnology are the study and application of extremely small things. Thus, this describes why the term nano is used to describe nanotechnology.
I hope this helps :)
Answer:
Nanotechnology is technology that is about a nanometer in size, or between 1 nm and 100 nm.
Explanation:
its the sample response on edge 2021
when vector contains distance and direction it also known as
When vector contain distance and direction it is also known as displacement .
Active 13 minutes ago
6. Thrust exerted by an object of area 20 m experiencing pressure 150 Nm‐² is
a 3000 km
b. 3000 N
c. 2800 Kg
d 2800 N/m
Answer:
3000 N
Explanation:
As we know that
pressure=force/area
force=thrust
so pressure=thrust/area
thrust=pressure*area
pressure=150 Nm^-2
area=20m^2
so thrsut=150*20=3000 N
Is The force of friction always opposite to the motion?
Answer:
Friction force always acts tangent to the surface at points of contact. Friction force acts opposite to the direction of motion.
Explanation:
identify the motion when a car is moving with constant speed along a curve
Answer:
Uniform circular motion
Explanation:
When a car is moving with constant speed along a curve, it will said to have uniform circular motion. The speed of the car remains constant in this case. But its velocity keeps on changing. The velocity can be calculated by drawing the tangent on the circle. Hence, the motion of the car is uniform circular motion.
Answer:
Uniform motion
Explanation:
The motion when a car is moving with constant speed along a curve is an example of uniform motion.
A car moving at constant speed covers equal distances in equal intervals of time. The average speed remains the same in uniform motion.
The curve defines the path of the motion and the speed remains constant.
Is the following nuclear reaction balanced?
Answer:
yes
Explanation:
How do you find the rest mass (kg) of a 3.1 eV electron?
Answer:
Explanation:
The rest energy of any substance is defined by the Einstein's mass energy equivalence relation. Thus the rest mass of a electron is 9.11x10^-31 kg. The speed of light is 299,792,458 m/s. Thus multiplying the square of speed of light with the rest mass of electron gives the rest energy of the electron.
Light travels 300 000 000 m/s and one year has approximately 32 000 000 second a light year is the distance light travels in one year
Explanation:
It is given that,
Speed of light, [tex]v=300 000 000\ m/s=3\times 10^8\ m/s[/tex]
Seconds in 1 year, [tex]t=32 000 000=32\times 10^6\ s[/tex]
We need to find the distance traveled by light in one year. Speed of an object is given by :
[tex]v=\dfrac{d}{t}[/tex]
So,
[tex]d=v\times t\\\\d=3\times 10^8\times 32\times 10^6\\\\d=9.6\times 10^{15}\ m[/tex]
Since,
[tex]1\ \text{light year}=9.46\times 10^{15}\ m\\\\1\ m=\dfrac{1}{9.46\times 10^{15}}\ \text{ly}\\\\9.6\times 10^{15}\ m=\dfrac{9.6\times 10^{15}}{9.46\times 10^{15}}\\\\d=1.01\ \text{ly}[/tex]
So, the distance covered by light is 1.01 light years.
Salt compounds are commonly used to melt ice that forms on sidewalks in the winter. A common chemical that is used to melt sidewalk ice is calcium chloride, CaCl2(s). When calcium chloride dissolves into solution is releases thermal energy which aides in melting
the ice.
The molar mass of water is 18.02 g/mol
The thermal energy, in kilojoules (kJ) that must be released from the calcium chloride,
CaCl2(s), to melt 10.0 kg of ice, expressed in scientific notation is a.bc x 104 k).
46
55
The values of a, b, c, and d.
Answer:
The values of a, b, c and d are
a = 3, b = 3, c = 4 and d = 3
Explanation:
The quantity of heat needed to melt the ice is given by Q = mL where m = mass of ice and L = latent heat of fusion of ice = 334 kJ/kg. This quanity of heat is also the thermal energy needed to be released by the calcium chloride, CaCl₂
Now, the mass of ice = 10 kg. So,
Q = mL
Q = 10 kg × 334 kJ/kg
Q = 3340 kJ
In scientific notation,
Q = 3.34 × 10³ kJ
So the thermal energy needed to be released by the calcium chloride is 3.34 × 10³ kJ
Comparing Q = 3.34 × 10³ kJ with a.bc × [tex]10^{d}[/tex] kJ
So, a = 3, b = 3, c = 4 and d = 3
The values of a, b, c and d are
a = 3, b = 3, c = 4 and d = 3