Answers
Answer:
c. [tex]|F_T|=8\frac{Gm^2}{d^2}[/tex]
Explanation:
In order to calculate the gravitational force on the mass of the center, you take into account the following formula:
[tex]F=G\frac{m_1m_2}{r}[/tex] (1)
Furthermore, you take into account the components of the resultant vector.
By the illustration, you have that the force is given by:
[tex]F_T=F_1+F_2+F_3+F_4\\\\F_1=\frac{Gm_1m}{r^2}[-cos45\°\hat{i}+sin45\°\hat{j}]\\\\F_2=\frac{Gm_2m}{r^2}[cos45\°\hat{i}+sin45\°\hat{j}]\\\\F_3=\frac{Gm_3m}{r^2}[cos45\°\hat{i}-sin45\°\hat{j}]\\\\F_4=\frac{Gm_4m}{r^2}[-cos45\°\hat{i}-sin45\°\hat{j}][/tex]
where:
m1 = m
m2 = 2m
m3 = m
m4 = 4m
m: mass at the center of the system
The distance r is:
[tex]r=\sqrt{(\frac{d}{2})^2+(\frac{d}{2})^2}=\frac{d}{\sqrt{2}}[/tex]
You replace the values for all masses and sum the contributions of all forces:
[tex]F_1=\frac{\sqrt{2}}{2}\frac{Gm^2}{(\frac{d^2}{2})}[-\hat{i}+\hat{j}]=\sqrt{2}\frac{Gm^2}{d^2}[-\hat{i}+\hat{j}]\\\\F_2=\frac{\sqrt{2}}{2}\frac{2Gm^2}{(\frac{d^2}{2})}[\hat{i}+\hat{j}]=2\sqrt{2}\frac{Gm^2}{d^2}[\hat{i}+\hat{j}]\\\\F_3=\frac{\sqrt{2}}{2}\frac{Gm^2}{(\frac{d^2}{2})}[\hat{i}-\hat{j}]=\sqrt{2}\frac{Gm^2}{s^2}[\hat{i}-\hat{j}]\\\\F_4=\frac{\sqrt{2}}{2}\frac{4Gm^2}{(\frac{d^2}{2})}[-\hat{i}-\hat{j}]=4\sqrt{2}\frac{Gm^2}{d^2}[-\hat{i}-\hat{j}]\\\\F_T=-2\sqrt{2}\frac{Gm^2}{d^2}}[\hat{i}+\hat{j}][/tex]
and the magnitude is:
c. [tex]|F_T|=8\frac{Gm^2}{d^2}[/tex]
Related Questions
1.3kg of gold at 300K comes in thermal contact with 2.4kg copper at 400K. The specific heats of Au and Cu are 126 J/kg-K and 386 J/kg-K respectively. What equilibrium temperature do they reach
Answers
Answer:
The final temperature of the metals will be 384.97 K
Explanation:
For the gold;
mass = 1.3 kg
temperature = 300 K
specific heat = 126 J/kg-K
For the copper;
mass = 2.4 kg
temperature = 400 K
specific heat = 386 J/kg-K
Firstly, we will have to calculate for the thermal energy possessed by each of the metal.
The heat possessed by a body = mcT
Where,
m is the mass of the body
c is the specific heat of the body, and
T is the temperature of the body at that instance
so we calculate for the thermal energy of the gold and the copper below
For gold;
heat energy = mcT = 1.3 x 126 x 300 = 49140 J
For copper;
heat energy = mcT = 2.4 x 386 x 400 = 370560 J
When the two metal come in thermal contact, this heat is evenly distributed between them.
The total heat energy = 49140 J + 370560 J = 419700 J
At thermal equilibrium, the two metals will be at the same temperature, to get this temperature, we equate the total thermal energy to the heat energy that will be possessed by the metals at equilibrium.
419700 = (1.3 x 126 x T) + (2.4 x 386 x T) = 163.8T + 926.4T
419700 = 1090.2T
T = 419700/1090.2 = 384.97 K
The final temperature of the metals will be 384.97 K
A wire has an electric field of 6.2 V/m and carries a current density of 2.4 x 108 A/m2. What is its resistivity
Answers
Answer:
The resistivity is [tex]\rho = 2.5 *10^{-8} \ \Omega \cdot m[/tex]
Explanation:
From the question we are told that
The magnitude of the electric field is [tex]E = 6.2 V/m[/tex]
The current density is [tex]J = 2.4 *10^{8} \ A/m^2[/tex]
Generally the resistivity is mathematically represented as
[tex]\rho = \frac{E}{J}[/tex]
substituting values
[tex]\rho = \frac{6.2}{2.4 *10^{8}}[/tex]
[tex]\rho = 2.5 *10^{-8} \ \Omega \cdot m[/tex]
A copper transmission cable 180 km long and 11.0 cm in diameter carries a current of 135 A.
Required:
a. What is the potential drop across the cable?
b. How much electrical energy is dissipated as thermal energy every hour?
Answers
Answer:
a) 43.98 V
b) E = 21.37 MJ
Explanation:
Parameters given:
Length of cable = 180 km = 180000 m
Diameter of cable = 11 cm = 0.11 m
Radius = 0.11 / 2 = 0.055 m
Current, I = 135 A
a) To find the potential drop, we have to find the voltage across the wire:
V = IR
=> V = IρL / A
where R = resistance
L = length of cable
A = cross-sectional area
ρ = resistivity of the copper wire = 1.72 * 10^(-8) Ωm
Therefore:
V = (135 * 1.72 * 10^(-8) * 180000) / (π * 0.055^2)
V = 43.98 V
The potential drop across the cable is 43.98 V
b) Electrical energy is given as:
E = IVt
where t = time taken = 1 hour = 3600 s
Therefore, the energy dissipated per hour is:
E = 135 * 43.98 * 3600
E = 21.37 MJ (mega joules, 10^6)
a ring with a clockwise current is situated with its center directly above another ring. The current in the top ring is decreasing. What is the directiong of the induced current in the bottom ring
Answers
Answer:
clockwise
Explanation:
when current flows through a ring in a clockwise direction, it produces the equivalent magnetic effect of a southern pole of a magnet on the coil.
Since the current is decreasing, there is a flux change on the lower ring; generating an induced current on the lower ring. According to Lenz law of electromagnetic induction, "the induced current will act in such a way as to oppose the motion or the action producing it". In this case, the induced current will have to be the same polarity to the polarity of the current change producing it so as to repel the two rings far enough to stop the electromagnetic induction. The induced current will then be in the clockwise direction on the lower ring.
The direction of the induced current in the bottom ring is in the clockwise direction.
The given problem is based on the concept and fundamentals of the induced current and the direction of flow of the induced current.
When current flows through a ring in a clockwise direction, it produces the equivalent magnetic effect of a southern pole of a magnet on the coil. Since the current is decreasing, there is a flux change on the lower ring; generating an induced current on the lower ring. According to Lenz law of electromagnetic induction, "the induced current will act in such a way as to oppose the motion or the action producing it". In this case, the induced current will have to be the same polarity to the polarity of the current change producing it so as to repel the two rings far enough to stop the electromagnetic induction. The induced current will then be in the clockwise direction on the lower ring.Thus, we can conclude that the direction of the induced current in the bottom ring is in the clockwise direction.
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Find the force on a proton moving with velocity (2i+3j+4k)10^5m/s in a uniform magnetic field of 0.5k T. What is the angle between the magnetic field lines and the velocity?
Answers
Answer:
Explanation:
Force on charge particles
F = q ( v x B )
= 1.6 x 10⁻¹⁹ x [ ( 2i+3j+4k) x .5k ] x 10⁵
= 1.6 x 10⁻¹⁴ x ( 1.5 i - j )
= (2.4 i - 1.6 j ) x 10⁻¹⁴ N
magnitude of this vector
= 2.88 x 10⁻¹⁴ N
Angle between B and v
cosθ = [tex]\frac{(2i+3j+4k).(.5k)}{\sqrt{2^2+3^2+4^2}\times .5 }[/tex]
= [tex]\frac{2}{2.69}[/tex]
cosθ = .74
θ = 42° .
Which of the following scenarios would be optimal for obtaining a date from radioactive decay using these isotopes: 87Rb, 147Sm, 235U, 238U, 40K, or 14C? There may be more than one answer that is appropriate. Explain your reasoning for why the remaining scenario(s) would be inappropriate/impossible to use that particular isotope. Answers should include a discussion on usable ages for each system and whether the necessary isotopes would be found in the material to be dated.
a. A meteorite that formed early in the formation of the solar system.
b. A rock formed through a mountain building event around 420 million years ago.
c. Volcanic ash from an eruption 60 million years ago.
d. An earthquake scarp that formed along the San Andreas Fault 50 years ago.
e. An Incan archaeological dig site in the highlands of Peru.
f. A tree from a forest in England that is suspected to be the oldest in the British Isles.
Answers
Answer:
a) 238U, 40K and 87Rb, b) 235U and to a lesser extent 40K , c) he 235U,
d) possibility is 14C , e)this period would be ideal for 14C , f) 14C should be used since it is the one with the least average life time, even though the measurements must be very careful
Explanation:
One of the applications of radioactive decay is the dating of different systems.
To do this, the quantity of radioactive material in a meter is determined and with the average life time, the time of the sample is found.
Let's write the half-life times of the given materials
87Rb T ½ = 4.75 1010 years
147Sm T ½ = 1.06 1011 years
235U = 7,038 108 years
238U = 4.47 109 years
40K = 1,248 109 years
14C = 5,568 103 years
we already have the half-life of the different elements given
a) meteors. As these decomposed in the formation of the solar system, their life time is around 3 109 to 5 109 years, so it is necessary to look for elements that have a life time of this order, among the candidates we have 238U, 40K and 87Rb if these elements were at the moment of the formation of these meteors, there must still be rations in them, instead elements 14C already completely adequate
b) rock. The formation period is 4.20-108 years, therefore one of the most promising elements is 235U and to a lesser extent 40K since it is more abundant in rocks. The other elements with higher life times have not decayed and therefore will not give a true value and the 14C is completely decayed
c) volcanic ash. Formation time 6107 years, the only element that has the possibility of having a count is the 235U, the others have a life time so long that they have not decayed and the 14C is complete, unbent
d) scarp of an earthquake formation time 5 101 years, The only one that has any possibility is 14C even when it has declined very little, all the others, you have time to long that has not decayed
e) INCA excavation. The time of this civilization is about 10000 to 500 years (104 to 5 102 years), we see that this period would be ideal for 14C since it has some period of cementation, the others have not decayed
f) Tree in Blepharitis. 14C should be used since it is the one with the least average life time, even though the measurements must be very careful because of a period of disintegration. We have such a long time that they have not decayed
Can someone explain what is loss of seismic energy ?
Answers
Answer:
Seismic attenuation describes the energy loss experienced by seismic waves as they propagate. It is controlled by the temperature, composition, melt content, and volatile content of the rocks through which the waves travel.
Explanation:
An electric current through neon gas produces several distinct wavelengths of visible light. What are the wavelengths (in nm) of the neon spectrum, if they form first-order maxima at angles of 49.67°, 50.65°, 52.06°, and 52.89° when projected on a diffraction grating having 11,000 lines per centimeter? (Round your answers to the nearest nanometer. Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign. Enter your answers from smallest to largest.)
Answers
Answer:
Explanation:
If a be grating element
a = 1 x 10⁻² / 11000
= .0909 x 10⁻⁵
= 909 x 10⁻⁹ m
for first order maxima , the condition is
a sinθ = λ where λ is wavelength
909 x 10⁻⁹ sin 49.67 = λ₁
λ₁ = 692.95 nm .
λ₂ = 909 x 10⁻⁹ sin 50.65
= 702.91 nm
λ₃ = 909 x 10⁻⁹ sin 52.06
= 716.88 nm
λ₄ = 909 x 10⁻⁹ sin 52.89
= 724.90 nm
692.95 nm , 702.91 nm , 716.88 nm , 724.90 nm .
You have negotiated with the Omicronians for a base on the planet Omicron Persei 7. The architects working with you to plan the base need to know the acceleration of a freely falling object at the surface of the planet in order to adequately design the structures. The Omicronians have told you that the value is gOP7=7.29 flurggrom2, but your architects use the units metersecond2, and from your previous experience you know that both the Omicronians and your architects are terrible at unit conversion. Thus, it's up to you to do the unit conversion. Fortunately, you know the unit equality relationships: 5.24flurg=1meter and 1grom=0.493second. What is the value of gOP7 in the units your architects will use, in meter-second2?
Answers
Answer:
5.724 meters / second^2
Explanation:
We are given two pieces of information, 5.24 flurg = 1 meter, 1 grom = 0.493 second. If that is so, we can say that there are two possible conversion units, 5.25 flurg / meter, and 0.493 second / grom.
_____
We want to convert 7.29 flurg / grom^2 ( I believe? ) to the units meters / second^2. But, let's break this down into bits. It would be convenient to first convert 7.29 flurg / grom^2 to the units meters / grom^2, by dividing the conversion factors as to cancel out the appropriate things, which we will go into detail on a bit later ( using the first conversion factor ). Respectively we can convert meters / grom^2 to meters / grom * s, canceling out the flurg ( through the second conversion factor ). And now we would need to get rid of the grom, dividing similarly.
_____
( 1 ) ( flurg / grom^2 ) / ( flurg / meters ) - first conversion unit
= flurg / grom^2 * meters /flurg
= ( meters * flurg ) / ( grom^2 * flurg )
= meters /grom^2,
7.29 flurg / grom^2 / 5.24 flurg / meter = ( About ) 1.39 meter / grom^2
( 2 ) ( meter / grom^2 ) / ( second / grom ) - second conversion unit
= meter / grom^2 * grom / second
= ( meter * grom ) / ( grom^2 * second )
= meter / ( grom * second ),
( 1.39 meter / grom^2 ) / 0.493 second / grom = ( About ) 2.82195 meter / grom * second
( 3 ) ( 2.82195 meter / ( grom * second ) ) / 0.493 second / grom = 5.724 meter / second^2
( And thus, the value of gOP7 in the units the architects will use should be about 5.724 meters / second^2 )
The value of gOP7 in the units your architects will use is 5.724 [tex]m/s^2[/tex]
Given that 5.24 flurg = 1 meter,
1 grom = 0.493 second.
First, we will convert the length units:
[tex]7.29 flurg / grom^2 / 5.24 flurg / meter = 1.39 meter / grom^2[/tex]
Now we convert the time units:
[tex]1.39 meter / grom^2 / 0.493 second / grom = 2.82195 meter / grom * second[/tex]
[tex]2.82195 meter / ( grom * second ) ) / 0.493 second / grom = 5.724 meter / second^2[/tex]
The value of gOP7 in the units the architects will use is [tex]5.724m/s^2[/tex]
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A train accelerates at -1.5 m/s2 for 10 seconds. If the train had an initial
speed of 32 m/s, what is its new speed?
A. 17 m/s
B. 15 m/s
C. 47 m/s
D. 32 m/s
Answers
Answer:
17 m/s
Explanation:
Using formula a = (v-u) /t
acceleration a = -1.5 m/s2
final velocity v = unknown
initial velocity u = 32 m/s
time t = 10s
-1.5 = (v-32)/10
-15 = v - 32
-15 + 32 = v
v = 17 m/s
In a circus act, a uniform board (length 3.00 m, mass 25.0 kg ) is suspended from a bungie-type rope at one end, and the other end rests on a concrete pillar. When a clown (mass 79.0 kg ) steps out halfway onto the board, the board tilts so the rope end is 30∘ from the horizontal and the rope stays vertical. Calculate the force exerted by the rope on the board with the clown on it.
Answers
Answer:
Force of Rope = 122.5 N
Force of Rope = 480.2N
Explanation:
given data
length = 3.00 m
mass = 25.0 kg
clown mass = 79.0 kg
angle = 30°
solution
we get here Force of Rope on with and without Clown that is
case (1) Without Clown
pivot would be on the concrete pillar so Force of Rope will be
Force of Rope × 3m = (25kg)×(9.8ms²)×(1.5m)
solve it and we get
Force of Rope = 122.5 N
and
case (2) With Clown
so here pivot is still on concrete pillar and clown is standing on the board middle and above the centre of mass so Force of Rope will be
Force of Rope × 3m = (25kg+73kg)×(9.8ms²)×(1.5m)
solve it and we get
Force of Rope = 480.2N
A helicopter rotor blade is 3.40m long from the central shaft to the rotor tip. When rotating at 550rpm what is the radial acceleration of the blade tip expressed in multiples of g?
Answers
Answer:
a = 1.15 10³ g
Explanation:
For this exercise we will use the relations of the centripetal acceleration
a = v² / r
where is the linear speed of the rotor and r is the radius of the rotor
let's use the relationships between the angular and linear variables
v = w r
let's replace
a = w² r
let's reduce the angular velocity to the SI system
w = 550 rev / min (2pi rad / 1 rev) (1 min / 60 s)
w = 57.6 rad / s
let's calculate
a = 57.6² 3.4
a = 1.13 10⁴ m / s²
To calculate this value in relation to g, let's find the related
a / g = 1.13 10⁴ / 9.8
a = 1.15 10³ g
Wind erosion can be reduced by _____.
Answers
A very bouncy ball is dropped from a height of 2.47 m to an asphalt playground surface and the height of its 4 th bounce is measured to be 1.71 m. Find the coefficient of restitution of the ball for a collision with asphalt.
Answers
Answer:
0.912
Explanation:
Given that
Height of bouncing of the ball, h = 1.71 m
Number of times the ball bounced, n = 4 times
Height from which the ball was dropped, H = 2.47
First, let's start by defining what coefficient of restitution means
Coefficient of Restitution, CoR is the "ratio of the final to initial relative velocity between two objects after they collide. It normally ranges from 0 to 1 where 1 would be a perfectly elastic collision."
It is mathematically represented as
CoR = (velocity after collision) / (velocity before collision)
1.71 = 2.47 * c^4, where c = CoR
1.71/2.47 = c^4
c^4 = 0.6923
c = 4th root of 0.6923
c = 0.912
Jerome places a bag of flour on a scale. The scale shows that the bag has a weight of 17 N. Which is the reaction force of the bag sitting on the scale?
The scale exerts a 17 N force up on the bag.
The scale exerts a 17 N force down on the counter.
Earth exerts a 17 N force down on the bag.
The bag exerts a 17 N force down on the scale.
Answers
Answer:
A. The scale exerts a 17 N force up on the bag.
Explanation:
I Just took the test
Reaction force of the bag sitting on the scale a)The scale exerts a 17 N force up on the bag.
What is newton's third law of motion ?
According to newton's third law of motion , every action have a equal and opposite reaction
When bag is being put on the scale to measure its weight , then bag must have exerted a force on the scale , in result of which an equal and opposite force must be exerted by the scale on the bag (according to newton's third law of motion) in order to keep an equilibrium state where both the forces are equal but opposite to each other .
correct option is a)The scale exerts a 17 N force up on the bag.
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# SPJ2
Four forces act on bolt A as shown; F1 150N, F2 80N, F3 110N and F4 100N. Determine the magnitude and direction of the resultant of the forces of the bolt, A.
Answers
Complete Question
The complete question(reference (chegg)) is shown on the first uploaded image
Answer:
The magnitude of the resultant force is [tex]F = 199.64 \ N[/tex]
The direction of the resultant force is [tex]\theta = 4.1075^o[/tex] from the horizontal plane
Explanation:
Generally when resolving force, if the force (F )is moving toward the angle then the resolve force will be [tex]Fcos(\theta )[/tex] while if the force is moving away from the angle then the resolved force is [tex]Fsin (\theta )[/tex]
Now from the diagram let resolve the forces to their horizontal component
So
[tex]\sum F_x = 150 cos(30) + 100cos(15) -80sin (20)[/tex]
[tex]\sum F_x = 199.128 \ N[/tex]
Now resolving these force into their vertical component can be mathematically evaluated as
[tex]\sum F_{y} = 150 sin(30) - 100sin(15) -110 +80 cos(20)[/tex]
[tex]\sum F_{y} = 14.30[/tex]
Now the resultant force is mathematically evaluated as
[tex]F = \sqrt{F_x^2 + F_y^2}[/tex]
substituting values
[tex]F = \sqrt{199.128^2 + 14.3^2}[/tex]
[tex]F = 199.64 \ N[/tex]
The direction of the resultant force is evaluated as
[tex]\theta = tan^{-1}[\frac{F_y}{F_x} ][/tex]
substituting values
[tex]\theta = tan^{-1}[\frac{ 14.3}{199.128} ][/tex]
[tex]\theta = 4.1075^o[/tex] from the horizontal plane
What is the one single most important reason that human impact on the planet has been so great?
Answers
Answer:
Increasing population
Explanation:
As we can see that the death rate is decreasing while at the same time the birth rate is increasing due to which it increased the population that directly impact the planet so great
Day by day the population of the villages, cities, states, the country is increasing which would create a direct human impact on the planet
Therefore the increasing population is the one and single most important reason
In an oscillating LC circuit, the total stored energy is U and the maximum current in the inductor is I. When the current in the inductor is I/2, the energy stored in the capacitor is
Answers
Answer:
The definition of that same given problem is outlined in the following section on the clarification.
Explanation:
The Q seems to be endless (hardly any R on the circuit). So energy equations to describe and forth through the inducer as well as the condenser.
Presently take a gander at the energy stored in your condensers while charging is Q.
⇒ [tex]U =\frac{Qmax^2}{C}[/tex]
So conclude C doesn't change substantially as well as,
When,
⇒ [tex]Q=\frac{Qmax}{2}[/tex]
⇒ [tex]Q^2=\frac{Qmax^2}{4}[/tex]
And therefore only half of the population power generation remains in the condenser that tends to leave this same inductor energy at 3/4 U.
When separated by distance d, identically charged point-like objects A and B exert a force of magnitude F on each other. If you reduce the charge of A to one-fourth its original value, and the charge of B to one-fourth, and reduce the distance between the objects by half, what will be the new force that they exert on each other in terms of force F
Answers
Answer:
F ’= F 0.25
Explanation:
This problem refers to the electric force, which is described by Coulomb's law
F = k q₁ q₂ / r²
where k is the Coulomb constant, q the charges and r the separation between them.
The initial conditions are
F = k q_A q_B / d²
they indicate that the loads are reduced to ¼ q and the distance is reduced to ½ d
F ’= k (q / 4 q / 4) / (0.5 d)²
F ’= k q / 16 / 0.25 d²
F ’= k q² / d² 0.0625 / 0.25
F ’= F 0.25
Two identically charged point-like objects A and B exert a force of magnitude F on each other when separated by distance d. If the charges are reduced to one-fourth of their original values and the distance is halved, the new force will be one-fourth of the original force.
Two identically charged point-like objects A and B exert a force of magnitude F on each other when separated by distance d. This can be explained through Coulomb's law.
What is Coulomb's law?Coulomb's law is a law stating that like charges repel and opposite charges attract, with a force proportional to the product of the charges and inversely proportional to the square of the distance between them.
[tex]F = k \frac{q_Aq_B}{d^{2} } = k \frac{q^{2} }{d^{2} } [/tex]
where,
[tex]q_A [/tex] and [tex]q_B[/tex] are the charges of A and B (and equal to q).k is the Coulomb's constant.If you reduce the charge of A to one-fourth its original value, and the charge of B to one-fourth, and reduce the distance between the objects by half, the new force will be:
[tex]F_2 = k \frac{(0.25q_A)(0.25q_B)}{(0.5d)^{2} } = 0.25k\frac{q^{2} }{d^{2} } = 0.25 F[/tex]
Two identically charged point-like objects A and B exert a force of magnitude F on each other when separated by distance d. If the charges are reduced to one-fourth of their original values and the distance is halved, the new force will be one-fourth of the original force.
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If the set W is a vector space, find a set S of vectors that spans it. Otherwise, state that W is not a vector space. W is the set of all vectors of the form [a - 4b 5 4a + b -a - b], where a and bare arbitrary real numbers.
a. [1 5 4 -1], [-4 0 1 -1]
b. [1 0 4 -1], [-4 5 1 -1]
c. [1 0 4 -1], [-4 0 1 -1], [0 5 0 0]
d. Not a vector space
Answers
Answer:
Choice d. The set of vectors: [tex]\displaystyle \left\{\begin{bmatrix}a - 4\, b \\ 5 \\ 4\, a+ b\\ -a -b\end{bmatrix},\; a,\, b\in \mathbb{R} \right\}[/tex] isn't a vector space over [tex]\mathbb{R}[/tex].
Explanation:
Let a set of vectors [tex]V[/tex] to be a vector field over some field [tex]\mathbb{F}[/tex] (for this question, that "field" is the set of all real number.) The following must be true:
The set of vectors [tex]V[/tex] includes the identity element [tex]\mathbf{0}[/tex]. In other words, there exists a vector [tex]\mathbf{0} \in V[/tex] such that for all [tex]\mathbf{v} \in V[/tex], [tex]\mathbf{v} + \mathbf{0} = \mathbf{v}[/tex].[tex]V[/tex] should be closed under vector addition. In other words, for all [tex]\mathbf{u},\, \mathbf{v} \in V[/tex], [tex]\mathbf{u} + \mathbf{v} \in V[/tex].[tex]V[/tex] should also be closed under scalar multiplication. In other words, for all [tex]\mathbf{v} \in V[/tex] and all "scalar" [tex]m \in \mathbb{F}[/tex] (in this question, the "field" is the set of all real numbers, so [tex]m[/tex] can be any real number,) [tex]a\,\mathbf{v} \in V[/tex].Note that in the general form of a vector in [tex]V[/tex], the second component is a always non-zero. Because of that non-zero component,
Assume by contradiction that [tex]V[/tex] is indeed a vector field. Therefore, it should contain a zero vector. Let [tex]\mathbf{0}[/tex] denote that zero vector. For all [tex]\mathbf{v} \in V[/tex], [tex]\mathbf{v} + \mathbf{0} = \mathbf{v}[/tex].
Using the definition of set [tex]V[/tex]: [tex]\displaystyle \left\{\begin{bmatrix}a - 4\, b \\ 5 \\ 4\, a+ b\\ -a -b\end{bmatrix},\; a,\, b\in \mathbb{R} \right\}[/tex], there exist real numbers [tex]a[/tex] and [tex]b[/tex], such that:
[tex]\displaystyle \mathbf{v} = \begin{bmatrix}a - 4\, b \\ 5 \\ 4\, a+ b\\ -a -b\end{bmatrix}[/tex].
Hence, [tex]\mathbf{v} + \mathbf{0} = \mathbf{v}[/tex] is equivalent to:
[tex]\displaystyle \begin{bmatrix}a - 4\, b \\ 5 \\ 4\, a+ b\\ -a -b\end{bmatrix} + \mathbf{0} = \begin{bmatrix}a - 4\, b \\ 5 \\ 4\, a+ b\\ -a -b\end{bmatrix}[/tex].
Apply the third property that [tex]V[/tex] is closed under scalar multiplication. [tex]-1[/tex] is indeed a real number. Therefore, if [tex]\mathbf{v}[/tex] is in
Therefore:
[tex]\displaystyle -\begin{bmatrix}a - 4\, b \\ 5 \\ 4\, a+ b\\ -a -b\end{bmatrix} \in V[/tex].
Apply the second property and add [tex]\displaystyle - \mathbf{v} = -\begin{bmatrix}a - 4\, b \\ 5 \\ 4\, a+ b\\ -a -b\end{bmatrix}[/tex] to both sides of [tex]\mathbf{v} + \mathbf{0} = \mathbf{v}[/tex]. The left-hand side becomes:
[tex]\mathbf{v} - \mathbf{v} + \mathbf{0} = \mathbf{0}[/tex].
The right-hand side becomes:
[tex]\displaystyle \begin{bmatrix}a - 4\, b \\ 5 \\ 4\, a+ b\\ -a -b\end{bmatrix} -\begin{bmatrix}a - 4\, b \\ 5 \\ 4\, a+ b\\ -a -b\end{bmatrix} = \begin{bmatrix}a - 4\, b - (a - 4\, b) \\ 5 - 5 \\ 4\, a+ b-(4\, a+ b)\\ -a -b - (-a -b)\end{bmatrix} = \begin{bmatrix}0 \\ 0 \\ 0 \\0\end{bmatrix}[/tex].
Therefore:
[tex]\displaystyle \mathbf{0} = \begin{bmatrix}0 \\ 0 \\ 0 \\0\end{bmatrix}[/tex].
However, [tex]\mathbf{0} = \displaystyle \begin{bmatrix}0 \\ 0 \\ 0 \\0\end{bmatrix}[/tex] isn't a member of the set [tex]\displaystyle V = \left\{\begin{bmatrix}a - 4\, b \\ 5 \\ 4\, a+ b\\ -a -b\end{bmatrix},\; a,\, b\in \mathbb{R} \right\}[/tex]. That's a contradiction, because [tex]\mathbf{0}[/tex] was supposed to be part of [tex]V[/tex].
Hence, [tex]V[/tex] isn't a vector space by contradiction.
Quadrupling the power output from a speaker emitting a single frequency will result in what increase in loudness (in units of dB)
Answers
Answer:
6.02 dB increase
Explanation:
Let us take the initial power from the speaker P' = P Watt
then, the final power P = 4P Watt
for a given unit area, initial intensity (power per unit area) will be
I' = P Watt/m^2
and the final quadrupled sound will produce a sound intensity of
I = 4P Watt/m^2
Increase in loudness is gotten from the relation
ΔL = [tex]10log_{10} \frac{I}{I'}[/tex]
where
I = final sound intensity
I' = initial sound intensity
imputing values of the intensity into the equation, we have
==> [tex]10log_{10} \frac{4P}{P}[/tex] = [tex]10log_{10} 4[/tex] = 6.02 dB increase
a fixed amount of ideal gas is held in a rigid container that expands negligibly when heated. at 20 the gas pressure is p. if we added enough heat to increase the temperature from 20 to 40, the pressure will be
Answers
Answer:
When the temperature of the gas is increased from 20 to 40, the pressure will be 2p
Explanation:
Given;
initial temperature of the gas, T₁ = 20 K
final temperature of the gas, T₂ = 40 k
initial pressure of the gas, P₁ = P
final pressure of the gas, P₂ = ?
Apply pressure law of gases;
[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\P_2 = \frac{P_1T_2}{T_1} \\\\P_2 = \frac{40P}{20} \\\\P_2 = 2P[/tex]
Therefore, when the temperature of the gas is increased from 20 to 40, the pressure will be 2p
A wire of radius 0.6 cm carries a current of 94 A that is uniformly distributed over its cross-sectional area. Find the magnetic field B at a distance of 0.2 cm from the center of the wire.
Answers
Answer:
0.00299T
Explanation:
The magnetic field B = 0.00299T
If a water wave completes one cycle in 2 seconds, what is
the period of the wave?
0.5 seconds
O4 seconds
2 seconds
0.2 seconds
Done
Answers
The period of a wave is the time it takes the wave to complete one cycle (at a fixed location).
So if a wave completes one cycle in 2 seconds, then that is its period.
Initially stationary, a train has a constant acceleration of 0.8 m/s2. (a) What is its speed after 27 s? m/s (b) What is the total time required for the train to reach a speed of 41 m/s?
Answers
Answer:
(a) v1 = 21.6 m/s
(b) t = 51.25 s
Explanation:
Use kinematics equation
v1 = v0 + at
Given
v0 = 0 = initial velocity
a = 0.8 m/s^2 = acceleration
(a) t = 27 seconds
v1 = v0 + at = 0 + 0.8*27 = 21.6 m/s
(b) v1 = 41 m/s
v1 = v0 + at
solve for t
t = (v1-v0)/a = (41-0)/0.8 = 51.25 s
Given:
Acceleration, a = 0.8 m/s²Time, t = 41 m/sSpeed, v = 41 m/sBy using Kinematics equation, we get
→ [tex]v_1 = v_0+at[/tex]
(a)
At t = 27 seconds,
→ [tex]v_1 = v_0 +at[/tex]
[tex]= 0+0.8\times 27[/tex]
[tex]= 21.6 \ m/s[/tex]
(b)
When [tex]v_1 = 41 \ m/s[/tex]
→ [tex]t = \frac{(v_1-v_0)}{a}[/tex]
[tex]= \frac{41.0}{0.8}[/tex]
[tex]= 51.25 \ s[/tex]
Thus the response above is right.
Learn more about acceleration here:
https://brainly.com/question/18401853
. A mass m is traveling at an initial speed of 25.0 m/s. It is brought to rest in a distance of 62.5 m by a net force of 15.0 N. The mass is
Answers
Answer:
m = 3 kg
The mass m is 3 kg
Explanation:
From the equations of motion;
s = 0.5(u+v)t
Making t thr subject of formula;
t = 2s/(u+v)
t = time taken
s = distance travelled during deceleration = 62.5 m
u = initial speed = 25 m/s
v = final velocity = 0
Substituting the given values;
t = (2×62.5)/(25+0)
t = 5
Since, t = 5 the acceleration during this period is;
acceleration a = ∆v/t = (v-u)/t
a = (25)/5
a = 5 m/s^2
Force F = mass × acceleration
F = ma
Making m the subject of formula;
m = F/a
net force F = 15.0N
Substituting the values
m = 15/5
m = 3 kg
The mass m is 3 kg
A small charged bead has a mass of 3.6 g. It is held in a uniform electric field E = (200,000 N/C, up). When the bead is released, it accelerates upward with an acceleration of 24 m/s^2. What is the charge on the bead?
Answers
Answer:
The charge on the bead is [tex]q = 6.084 *10^{-7}\ C[/tex]
Explanation:
From the question we are told that
The mass of the bead is [tex]m = 3.6 \ g = 0.0036 \ kg[/tex]
The magnitude of the electric field is [tex]E = 200,000 \ N/C[/tex]
The acceleration of the bead is [tex]a = 24 m/s^2[/tex]
Generally, the electric force on the bead is mathematically represented as
[tex]F_ e = q E[/tex]
Where q is the charge on the bead
Now the gravitational force opposing the upward movement of the bead is mathematically represented as
[tex]F_g = mg[/tex]
Generally the net force on the bead is mathematically represented as
[tex]F = F_e - F_g = m* a[/tex]
=> [tex]qE - mg = ma[/tex]
Now substituting values
[tex]q * 200000 - 0.0036 *9.8 = 0.0036 * 24[/tex]
[tex]q = 6.084 *10^{-7}\ C[/tex]
You measure the current through a 27.7 Ω resistor to be 753 mA . What is the potential difference across the contacts of the resistor?
Answers
Answer:
20.9 volts
Explanation:
R = 27.7 Ω
I = 753 mA = 0.753 A
V = ?
From Ohms law, V = IR
V = 0.753×27.7
V = 20.8581
V = 20.9 volts
(Equation 17.6) Write the equation for the path-length difference at a bright fringe (constructive interference). Define all variables. What are the SI units of each variable
Answers
Answer:
d sin tea = m λ
Explanation:
When we have a two-slit system, the optical path difference determines whether the intensity reaching an observation screen is maximum or zero.
To find this difference in optical path, we assume that the screen is much farther than the gap is, we draw a perpendicular from ray 1 to the second ray
OP = d sin θ
now to have constructive interference and see a bright line this leg must be an integer number of wavelengths, ose
d sin tea = m λ
where
d is the distance between the two slits
θ complexion the angle sea the point hold it between the two slits
λ the wavelength of the coherent light used
m an integer, which counts the number of lines of interference
Units in the SI system
d, lam in meters
θ degrees
m an integer
What is unique about the c-ray that is not about other rays? Note: Refer to the concave mirror video Select one: a. only ray whose angle of incidence = angle of reflection b. only ray that reflects back in the same direction it came from c. both the above statements are true d. none of the above
Answers
Answer:
b. only ray that reflects back in the same direction it came from
Explanation:
C-rays can be said to be a ray that comes from the center of the curvature. It is known that any ray that comes from the center of the curvature reflects back in the same direction it came from, this is because the line joining from the center of the curvature to any point in the mirror is perpendicular to the mirror.
Correct answer is option B.
C-ray is the only ray that reflects back in the same direction it came from.
Option A is incorrect because for other rays, angle of incidence = angle of reflection. This is not a property of c-ray.