A large rectangular prism is 5 feet long, 3 feet wide, and 4 feet tall. A small rectangular prism is 2.5 feet long, 1.5 feet wide, and 2 feet tall.
How many small prisms would it take to fill the large prism?
Write your answer as a whole number or decimal. Do not round.
The answer of the given question based on the rectangular prism is , , it would take 8 small rectangular prisms to fill the large rectangular prism.
What is Rectangular prism?A rectangular prism, also known as a rectangular parallelepiped, is a three-dimensional solid object that has six rectangular faces, with opposite faces being congruent and parallel. It is a special case of a parallelepiped in which all angles are right angles and all six faces are rectangles.
To find how many small rectangular prisms will fit inside the large rectangular prism, we need to calculate the volume of each prism and then divide the volume of the large prism by the volume of the small prism.
The volume of the large prism is:
V_large = length × width × height = 5 ft × 3 ft × 4 ft = 60 feet³
The volume of the small prism is:
V_small = length × width × height = 2.5 ft × 1.5 ft × 2 ft = 7.5 feet³
Dividing the volume of the large prism by the volume of the small prism, we get:
number of small prisms = V_large / V_small = 60 ft³ / 7.5 ft³ = 8
Therefore, it would take 8 small rectangular prisms to fill the large rectangular prism.
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what is the maximum number of consecutive odd positive integers that can be added together before the sum exceeds ?
The maximum number of consecutive odd positive integers that can be added together before the sum exceeds 401 is 11.
Let's assume the first odd integer is x. Then, the sum of the next n consecutive odd integers would be given by:
x + (x+2) + (x+4) + ... + (x+2n-2) = nx + 2(1+2+...+n-1) = nx + n(n-1)
We want to find the largest n such that the sum is less than or equal to 401:
nx + n(n-1) ≤ 401
Since the integers are positive and odd, we can start with x=1 and then try increasing values of n until we find the largest value that satisfies the inequality:
n + n(n-1) ≤ 401
n² - n - 401 ≤ 0
Using the quadratic formula, we find that the solutions are:
n = (1 ± √(1+1604))/2
n ≈ -31.77 or n ≈ 32.77
We discard the negative solution and round down to the nearest integer, giving us n = 11. Therefore, the maximum number of consecutive odd positive integers that can be added together before the sum exceeds 401 is 11.
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Complete Question:
what is the maximum number of consecutive odd positive integers that can be added together before the sum exceeds 401?
What is the equation of the line in slope-intercept form?
Answer:
y = 3/5x + 3
Step-by-step explanation:
points on the graph
(-5,0) and (0,3)
0- 3 = -3
-5 - 0 = -5
-3/-5= 3/5
y = 3/5x + B
use a point from the graph
3 = 3/5 x 0 + B
3 = 0 + B
3 -0 = 3
3 = B
check answer
(-5,0)
Y = 3/5 x -5 + 3
Y = -15/3 + 3
Y = -3 + 3
Y = 0
Making the equation true y = 3/5x + 3
the rule T(-3,1) is applied to point 2,-7 in which part of the coordinate system is the translated point
the translated point is located in the third quadrant of the coordinate system, since both coordinates are negative.
What is Cartesian coordinate?
A coordinate system, also known as a Cartesian coordinate system, is a system used to describe the position of points in space. It is named after the French mathematician and philosopher René Descartes, who introduced the concept in the 17th century. In a coordinate system, each point is assigned a unique pair of numbers, called coordinates, that describe its position relative to two perpendicular lines, called axes. The horizontal axis is usually labeled x and the vertical axis is usually labeled y.
To apply the translation rule T(-3, 1) to the point (2, -7), we need to add the translation vector (-3, 1) to the coordinates of the point:
(2, -7) + (-3, 1) = (-1, -6)
The resulting point after the translation is (-1, -6).
Therefore, the translated point is located in the third quadrant of the coordinate system, since both coordinates are negative.
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Select the GCF of these numbers. 48 and 60 22 ·3 2· 112 32 23 · 5 13· 193 ·232
The GCF of 48 and 60 is 12
To find the greatest common factor (GCF) of 48 and 60, we can start by finding the prime factorization of each number
48 = 2^4 × 3
60 = 2^2 × 3 × 5
Next, we can identify the common factors of both numbers by looking at their prime factorization
The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
The factors of 60 are: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
The common factors of 48 and 60 are: 1, 2, 3, 4, 6, and 12.
The greatest common factor is the largest number that both 48 and 60 can be divided evenly by. In this case, that number is 12. Therefore, the GCF is 12.
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The given question is incomplete, the complete question is:
Find the GCF of 48 and 60.
Given that £1 = $1.62
a) How much is £650 in $?
b) How much is $405 in £?
Answer:
a 1053
b 250
multiply 650 by 1.62 for part a.
for part b divide by 1.62 since pound is less than dollar
hope this helps :)
state the nameof this quadrilateral...70 points
Answer:
Step-by-step explanation:
its a rectanlge
assume that arrivals occur according to a poisson process with an average of seven per hour. what is the probability that exactly two customers arrive in the two-hour period of time between a 2:00 p.m. and 4:00 p.m. (one continuous two-hour period)? b 1:00 p.m. and 2:00 p.m. or between 3:00 p.m. and 4:00 p.m. (two separate one-hour periods that total two hours)?
a) The probability that exactly two customers arrive between 2:00 p.m. and 4:00 p.m. is 0.0915 (or approximately 9.15%).
b) The probability of at least one customer arriving between 1:00 p.m. and 2:00 p.m. or between 3:00 p.m. and 4:00 p.m. is approximately 0.99999917.
For a Poisson process, the number of arrivals in a fixed time interval follows a Poisson distribution.
Let's denote the number of arrivals in a two-hour period as X.
Since the average number of arrivals per hour is 7, the average number of arrivals in a two-hour period is 14.
Therefore, we have λ = 14.
a) Probability of exactly 2 customers arriving between 2:00 p.m. and 4:00 p.m.:
Using the Poisson distribution formula, the probability of X arrivals in a two-hour period is:
[tex]P(X = x) = (e^{-\lambda} * \lambda^x) / x![/tex]
So, for X = 2, we have:
[tex]P(X = 2) = (e^{-14} * 14^2) / 2! = 0.0915[/tex] (rounded to four decimal places)
Therefore, the probability that exactly two customers arrive between 2:00 p.m. and 4:00 p.m. is 0.0915 (or approximately 9.15%).
b) Probability of at least one customer arriving between 1:00 p.m. and 2:00 p.m. or between 3:00 p.m. and 4:00 p.m.:
We can approach this problem by using the complementary probability. The complementary probability of at least one customer arriving in a two-hour period is the probability of no customers arriving in that period. Since the arrival rate is the same for each hour, we can divide the two-hour period into two one-hour periods and use the Poisson distribution formula for each period separately.
The probability of no customers arriving in a one-hour period with λ = 7 is:
[tex]P(X = 0) = (e^{-7}* 7^0) / 0! = 0.000911[/tex]
The probability of no customers arriving in a two-hour period is the product of the probabilities for each one-hour period:
P(no customers in two-hour period) = P(X = 0) * P(X = 0) = 0.000911 * 0.000911 = 8.30e-7
The complementary probability of at least one customer arriving in a two-hour period is:
P(at least one customer in two-hour period) = 1 - P(no customers in two-hour period) = 1 - 8.30e-7 = 0.99999917 (rounded to eight decimal places).
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shawna is going out of town for the day, so she asks a friend to watch her 3 dogs. she wants to leave 12 of a pound of food for each dog. if a can of dog food has 0.75 pounds of food, how many cans should shawna leave?write your answer as a whole number, decimal, fraction, or mixed number. simplify any fractions.
Shawna wants to make sure her three dogs are fed and cared for when she leaves town for the day. She intends to give each of her dogs 12 ounces of food to achieve this. She must therefore leave a total of 36 ounces of food (3 dogs x 12 ounces of food per dog). 36 ounces are equivalent to 2.25 pounds of food because 16 ounces make up one pound.
There are 0.75 pounds of food in each can of dog food. We must divide 2.25 by 0.75 to find the quantity of dog food Shawna should leave for her companion. 3 dog food cans are the end outcome.Shawna ought to give her buddy three cans of dog food so that she can feed her dogs.
Shawna may make sure her dogs have enough food and are well cared for while she is away by leaving adequate food for them. Shawna may put any fears or concerns about her pets' welfare to rest by leaving ample food and clear directions.
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Part B
Based on your construction, what do you know about ΔABD and ΔBCD?
The construction and the resulting triangles are interesting because they allow us to explore the properties of perpendicular lines and the angles they form.
Now, let's look at the two triangles that are formed as a result of this construction - ΔABD and ΔBCD. Since line BD is perpendicular to line AC, we know that angle ABD and angle CBD are both right angles. This is because any line that is perpendicular to another line forms a right angle with that line.
Now, let's look at the other sides of the triangles. In ΔABD, we have side AB, which is different from side BC in ΔBCD. Similarly, in ΔBCD, we have side CD, which is different from side AD in ΔABD.
So, although the two triangles share a common side (BD), they have different lengths for their other sides. This means that the two triangles are not congruent, since congruent triangles must have the same length for all their sides.
However, we can still find some similarities between the two triangles. For example, since angle ABD and angle CBD are both right angles, we know that they are congruent. Additionally, we can use the fact that angle ADB is congruent to angle CDB, since they are alternate interior angles formed by a transversal (line BD) intersecting two parallel lines (line AC and the line perpendicular to it passing through point B).
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Complete Question:
Draw a line through point B that is perpendicular to line AC Label the intersection of the line and line AC as point D. Take a screenshot of your work, save it, and insert the image in the space below.
Part B
Based on your construction, what do you know about ΔABD and ΔBCD?
an agency has specialists who analyze the frequency of letters of the alphabet in an attempt to decipher intercepted messages. suppose a particular letter is used at a rate of 6.6%. what is the mean number of times this letter will be found on a typical page of 2650 characters? 174.9 what is the standard deviation for the number of times this letter will be found on a typical page of 2650 characters ? round your answer to 1 decimal place. in an intercepted message, a page of 2650 characters is found to have the letter occurring192 times. would you consider this unusual?
Standard deviation normal distribution table or calculator to determine the probability of observing a z-score of 1.3 or higher.
The probability is approximately 0.0968, or 9.68%.
To determine the mean number of times the letter appears on a page, we can multiply the probability of the letter appearing (0.066) by the total number of characters on the page (2650):
[tex]Mean = 0.066 \times 2650 = 174.9[/tex]
To calculate the standard deviation, we can use the formula:
Standard deviation = [tex]\sqrt(n \times p \times q)[/tex]
n is the sample size (2650), p is the probability of success (0.066), and q is the probability of failure [tex](1 - p = 0.934)[/tex].
Standard deviation = [tex]sqrt(2650 \times 0.066 \times 0.934) = 13.2[/tex] (rounded to 1 decimal place)
Determine whether 192 occurrences of the letter on a page is unusual, we can use the z-score formula:
z = (x - mean) / standard deviation
x is the observed number of occurrences (192), mean is the expected number of occurrences (174.9), and standard deviation is the standard deviation we just calculated (13.2).
[tex]z = (192 - 174.9) / 13.2 = 1.3[/tex]
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Kubin Company’s relevant range of production is 25,000 to 33,500 units. When it produces and sells 29,250 units, its average costs per unit are as follows: Average Cost per Unit Direct materials $ 8. 50 Direct labor $ 5. 50 Variable manufacturing overhead $ 3. 00 Fixed manufacturing overhead $ 6. 50 Fixed selling expense $ 5. 00 Fixed administrative expense $ 4. 00 Sales commissions $ 2. 50 Variable administrative expense $ 2. 00 Required: 1. For financial accounting purposes, what is the total amount of product costs incurred to make 29,250 units? 2. For financial accounting purposes, what is the total amount of period costs incurred to sell 29,250 units? 3. For financial accounting purposes, what is the total amount of product costs incurred to make 33,500 units? 4. For financial accounting purposes, what is the total amount of period costs incurred to sell 25,000 units? (For all requirements, do not round intermediate calculations. )
1. Total amount of product costs
2. Total amount of period costs incurred
3. Total amount of product costs
4. Total amount of period costs
For the relevant range of production of units total amount of product and period cost as per units are,
Total amount of product costs for 29,250 units is $687,375.
Total amount of period costs incurred for 29,250 units is $58,511.50
Total amount of product costs for 33,500 units is equal to $787,250.
Total amount of period costs for 25,000 units is equal to $50,011.50.
Average Cost per Unit Direct materials = $ 8. 50
Direct labor = $ 5. 50
Variable manufacturing overhead = $ 3. 00
Fixed manufacturing overhead = $ 6. 50
Fixed selling expense = $ 5. 00
Fixed administrative expense = $ 4. 00
Sales commissions = $ 2. 50
Variable administrative expense = $ 2. 00
Total unit produced = 29,250 units,
Total product costs
= (Direct materials + Direct labor + Variable manufacturing overhead + Fixed manufacturing overhead) x Number of units produced
= ($8.50 + $5.50 + $3.00 + $6.50) x 29,250
= $23.50 x 29,250
= $687,375
The total amount of product costs incurred to make 29,250 units is $687,375.
Total period costs
= Fixed selling expense + Fixed administrative expense + Sales commissions + (Variable administrative expense x Number of units sold)
= $5.00 + $4.00 + $2.50 + ($2.00 x 29,250)
= $5.00 + $4.00 + $2.50 + $58,500
= $58,511.50
The total amount of period costs incurred to sell 29,250 units is $58,511.50
For the number of units produced changed to 33,500.
Total product costs
= (Direct materials + Direct labor + Variable manufacturing overhead + Fixed manufacturing overhead) x Number of units produced
= ($8.50 + $5.50 + $3.00 + $6.50) x 33,500
= $23.50 x 33,500
= $787,250
The total amount of product costs incurred to make 33,500 units is $787,250.
The number of units sold changed to 25,000.
Total period costs
= Fixed selling expense + Fixed administrative expense + Sales commissions + (Variable administrative expense x Number of units sold)
= $5.00 + $4.00 + $2.50 + ($2.00 x 25,000)
= $5.00 + $4.00 + $2.50 + $50,000
= $50,011.50
The total amount of period costs incurred to sell 25,000 units is $50,011.50.
Therefore, the total amount of the product and period cost for different situations are,
Total amount of product costs is equal to $687,375.
Total amount of period costs incurred is equal to $58,511.50
Total amount of product costs is equal to $787,250.
Total amount of period costs is equal to $50,011.50.
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Answer every question. Pick one option for each question. Show your work.
1. Over one week, a snack booth at a fair sold 362 cans of soft drinks for $1.75 each and
221 hot dogs for $2.35 each. Which calculation will give the total sales of soft drinks and
hot dogs?
A. 362(2.35) + 221(1.75)
B. 221(2.35) + 362(2.35)
C. 221(1.75) + 362(1.75)
D. 362(1.75) + 221(2.35)
Divide and write your answer in standard notation to the nearest whole number with commas.
Answer:
The answer is 1×10⁶ to the nearest whole number
Step-by-step explanation:
7.6×10⁰/5.4×10‐⁶
7.6×10^(0-(-6)/5.4
7.6×10^(0+6)/5.4
7.6×10⁶/5.4
=1×10⁶ to the nearest whole number
why would you use a trigonometric function to set-up an application problem instead of a non-trigonometric function
Trigonometric functions are used to model relationships between angles and sides of a right triangle. They are particularly useful in solving problems that involve angles, distances, heights, and lengths that are difficult to measure directly.
For example, consider a problem that involves finding the height of a building. By measuring the length of the shadow cast by the building at a particular time of day, the angle of the sun's rays can be calculated using trigonometry. Once the angle is known, the height of the building can be determined using the tangent function.
In contrast, a non-trigonometric function may not be able to model the relationship between the given quantities in such problems, and may not provide an accurate solution. Therefore, when a problem involves angles or distances that are not directly measurable, trigonometric functions are typically the best tool for setting up and solving the problem.
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What is the answer to this problem?
The area of the shaded area is 3.27 ft²
How to the area of the shaded area?We can find the area of the shaded area by subtracting the area of the triangle from the area of the sector. That is;
Area of shaded area = Area of sector - area of triangle
Area of shaded area = (60/360 * π * 6²) - (1/2 * 6 * 6 * sin 60)
Area of shaded area = (60/360 * 22/7 * 36) - (1/2 * 36 * 0.866)
Area of shaded area = 3.27 ft²
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what is the degree of the polynomial 8 x to the power of 5 plus 4 x cubed minus 5 x squared minus 9 ?
Out of these powers, the highest is 5.
Therefore, the degree of the polynomial is 5.
The degree of a polynomial is the highest power of the variable in the polynomial. In the given polynomial, the highest power of x is 5,
so the degree of the polynomial is 5.
The degree of a polynomial is the highest power of the variable (x) in the expression.
In the polynomial you provided:
[tex]8x^5 + 4x^3 - 5x^2 - 9[/tex]
Let's identify the terms and their respective powers of x:
[tex]8x^5[/tex]has a power of 5.
[tex]4x^3[/tex]has a power of 3.
[tex]-5x^2[/tex] has a power of 2.
-9 is a constant term, so there is no power of x.
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profitability empirical rule with this dataset? why or why not. no, the measures the proportion of a movies budget recovered. a profitability less than 1 the movie did not make enough money to cover the budget, while a profitability greater than means means it made a profit. a boxplot of the profitability ratings of 136 movies that came out in 2011 is shown below. (the largest outlier is the movie 1 insidi high gross revenue.)
The empirical rule does not apply to this dataset because the empirical rule is used to describe data that is normally distributed.
The empirical rule is a statistical rule that states that for a normal distribution.
Approximately 68% of the data will fall within one standard deviation of the mean, 95% of the data will fall within two standard deviations of the mean, and 99.7% of the data will fall within three standard deviations of the mean.
The dataset is normally distributedThe dataset is normally distributed, determine if the empirical rule appliesThe empirical rule does not apply, identify an alternative method to describe the datasetThe empirical rule does not apply to this dataset because the empirical rule is used to describe data that is normally distributed.
This dataset does not appear to be normally distributed, as evidenced by the large outlier (1 Insidi High Gross Revenue).
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HURRY 40 POINTS!!
What is the surface area of this right rectangular prism?
Enter your answer as a mixed number in simplest form by filling in the boxes.
ft²
The surface area of the rectangular prism is 29 2/3 ft²
How to determine the surface areaThe formula for calculating the surface area of a rectangular prism is expressed as;
SA = 2(wl + hw + hl)
Where the parameters are;
SA is the surface areaw is the width of the prismh is the height of the prisml is the length of the prismFrom the information given, we have that;
Wl = 3 × 5/2
multiply the values
wl = 15/2
hw = 4/3 × 3
hw = 4
hl = 4/3 × 5/2 = 20/6 = 10/3
Substitute the values
Surface area = 2(4 + 10/3 + 15/2)
Surface area = 2(24 + 20 + 45/6)
Surface area = 2(89)/6
Surface area = 89/3 = 29 2/3 ft²
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Given the quadratic equation x^(2)+4x+c=0, what must the value of c be in order for the equation to have solutions at x=-3 and x=-1 ?
Answer:
Step-by-step explanation:
If the solutions are x = -3 and x = -1, then (x - 3) (x - 1) will give us our answer. Using the FOIL method,
(x - 3) (x - 1)
x^2 - x - 3x + 3
x^3 - 4x + 3 = 0
Your answer is 3
three bolts and three nuts are in a box. two parts are chosen at random. find the probability that one is a bolt and one is a nut.
The probability of picking one bolt and one nut is 1/2 or 50%.
To find the probability that one is a bolt and one is a nut, we need to use the formula for calculating the probability of two independent events happening together: P(A and B) = P(A) × P(B)
Let's first calculate the probability of picking a bolt from the box:
P(bolt) = number of bolts / total number of parts = 3/6 = 1/2
Now, let's calculate the probability of picking a nut from the box:
P(nut) = number of nuts / total number of parts = 3/6 = 1/2
Since the events are independent, the probability of picking a bolt and a nut in any order is:
P(bolt and nut) = P(bolt) × P(nut) + P(nut) × P(bolt)
P(bolt and nut) = (1/2) × (1/2) + (1/2) × (1/2)
P(bolt and nut) = 1/2
Therefore, the probability of picking one bolt and one nut is 1/2 or 50%.
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the probability that one chosen part is a bolt and the other chosen part is a nut is 1, or 100%. This makes sense because if we choose two parts at random, we must get one bolt and one nut since there are three of each in the box.
To find the probability that one chosen part is a bolt and the other chosen part is a nut, we need to use the formula for probability:
Probability = (number of desired outcomes) / (total number of outcomes)
There are two ways we could choose one bolt and one nut: we could choose a bolt first and a nut second, or we could choose a nut first and a bolt second. Each of these choices corresponds to one desired outcome.
To find the number of ways to choose a bolt first and a nut second, we multiply the number of bolts (3) by the number of nuts (3), since there are 3 possible bolts and 3 possible nuts to choose from. This gives us 3 x 3 = 9 total outcomes.
Similarly, there are 3 x 3 = 9 total outcomes if we choose a nut first and a bolt second.
Therefore, the total number of desired outcomes is 9 + 9 = 18.
The total number of possible outcomes is the number of ways we could choose two parts from the box, which is the number of ways to choose 2 items from a set of 6 items. This is given by the formula:
Total outcomes = (6 choose 2) = (6! / (2! * 4!)) = 15
Putting it all together, we have:
Probability = (number of desired outcomes) / (total number of outcomes)
Probability = 18 / 15
Probability = 1.2
However, this answer doesn't make sense because probabilities should always be between 0 and 1. So we made a mistake somewhere. The mistake is that we double-counted some outcomes. For example, if we choose a bolt first and a nut second, this is the same as choosing a nut first and a bolt second, so we shouldn't count it twice.
To correct for this, we need to subtract the number of outcomes we double-counted. There are 3 outcomes that we double-counted: choosing two bolts, choosing two nuts, and choosing the same part twice (e.g. choosing the same bolt twice). So we need to subtract 3 from the total number of desired outcomes:
Number of desired outcomes = 18 - 3 = 15
Now we can calculate the correct probability:
Probability = (number of desired outcomes) / (total number of outcomes)
Probability = 15 / 15
Probability = 1
So the probability that one chosen part is a bolt and the other chosen part is a nut is 1, or 100%. This makes sense because if we choose two parts at random, we must get one bolt and one nut since there are three of each in the box.
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when a researcher uses the pearson product moment correlation, two highly correlated variables will appear on a scatter diagram as what?
When a researcher uses the Pearson product-moment correlation, two highly correlated variables will appear on a scatter diagram as a tightly clustered group of points that form a linear pattern.
The scatter diagram is a visual representation of the correlation between two variables, where one variable is plotted on the x-axis, and the other variable is plotted on the y-axis. If the two variables have a high positive correlation, then the points on the scatter diagram will form a cluster that slopes upwards to the right.
On the other hand, if the two variables have a high negative correlation, then the points will form a cluster that slopes downwards to the right. The tighter the cluster of points, the higher the correlation between the variables.
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Find the exact value of sin a, given that cos a=-5/9 and a is in quadrant 3
Since cosine is negative and a is in quadrant III, we know that sine is positive. We can use the Pythagorean identity to solve for sine:
sin^2(a) + cos^2(a) = 1
sin^2(a) + (-5/9)^2 = 1
sin^2(a) = 1 - (-5/9)^2
sin^2(a) = 1 - 25/81
sin^2(a) = 56/81
Taking the square root of both sides:
sin(a) = ±sqrt(56/81)
Since a is in quadrant III, sin(a) is positive. Therefore:
sin(a) = sqrt(56/81) = (2/3)sqrt(14)
Find the avatar rate of change f(x)=3√x-1 +2; 9 ≤ x ≤ 65
Answer: To find the average rate of change of the function f(x) over the interval [9, 65], we can use the formula:
average rate of change = (f(b) - f(a)) / (b - a)
where a = 9, b = 65, f(a) = f(9) = 3√8 + 2, and f(b) = f(65) = 3√64 + 2.
Plugging in these values, we get:
average rate of change = (f(65) - f(9)) / (65 - 9)
average rate of change = (3√64 + 2 - 3√8 - 2) / 56
average rate of change = (3(4) + 2 - 3(2) - 2) / 56
average rate of change = (12 - 4) / 56
average rate of change = 8 / 56
average rate of change = 1 / 7
Therefore, the average rate of change of the function f(x) over the interval [9, 65] is 1/7.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer: To find the average rate of change of the function f(x) over the interval [9, 65], we can use the formula:
average rate of change = (f(b) - f(a)) / (b - a)
where a = 9, b = 65, f(a) = f(9) = 3√8 + 2, and f(b) = f(65) = 3√64 + 2.
Plugging in these values, we get:
average rate of change = (f(65) - f(9)) / (65 - 9)
average rate of change = (3√64 + 2 - 3√8 - 2) / 56
average rate of change = (3(4) + 2 - 3(2) - 2) / 56
average rate of change = (12 - 4) / 56
average rate of change = 8 / 56
average rate of change = 1 / 7
Therefore, the average rate of change of the function f(x) over the interval [9, 65] is 1/7.
There is 6/8 of a cake
leftover after a birthday
party. How many 1/4
pieces can be made from
the leftover cake?
Answer: 3 pieces
Step-by-step explanation:First, 6/8 can be converted into fourths by dividing the numerator and the denominator by 2 and we get 3/4. if we want 1/4 slices we divide 3/4 by 1/4 and get 3.
in a role playing game two special dice are rolled. one die has 4 faces numbered 1 through 4 and the other has 6 faces numbered 1 thorugh 6. what is the probabilty that the total shown on the two dice after they are rolled is greater than or equal to 8?
The probability that the total shown on the two dice after they are rolled is greater than or equal to 8 is 1/9.
Please help me !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
The equivalent exponential expression for this problem is given as follows:
A. 4^15 x 5^10.
How to simplify the exponential expression?The exponential expression in the context of this problem is defined as follows:
[tex]\left(\frac{4^3}{5^{-2}}\right)^5[/tex]
To simplify the expression, we must first apply the power of power rule, which means that when one exponential expression is elevated to an exponent, we keep the base and multiply the exponents, hence:
4^(15)/5^(-10)
The negative exponent at the denominator means that the expression can be moved to the numerator with a positive exponent, hence the simplified expression is given as follows:
4^15 x 5^10.
More can be learned about exponent rules at https://brainly.com/question/11975096
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The cost of 1 cup of tea and 6 cakes is £13. The cost of 1 cup of tea and 4 cakes is £9 a) How much do 2 cakes cost? b) How much does 1 cake cost?
The answers are:
a) 2 cakes cost £5
b) 1 cake costs £2.5.
What is an algebraic expression?
An algebraic expression is a mathematical phrase that contains variables, constants, and mathematical operations. It may also include exponents and/or roots. Algebraic expressions are used to represent quantities and relationships between quantities in mathematical situations, often in the context of problem-solving.
To find the cost of 1 cupcake, we need to subtract the cost of the tea from the total cost of 3 cupcakes:
3 cupcakes + 1 tea = £9
3 cupcakes = £9 - 1 tea = £9 - £1.5 (assuming the cost of 1 tea is the same in both cases) = £7.5
1 cupcake = £7.5 ÷ 3 = £2.5
So 2 cupcakes would cost:
2 cupcakes = 2 × £2.5 = £5
Therefore, the answers are:
a) 2 cakes cost £5
b) 1 cake costs £2.5.
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A student is helping a family member build a storage bin for their garage. They would like for the bin to have a volume of 240 ft3 If they already have the length measured at 8 feet and the width at 6 feet, what is the height needed to reach the desired volume?
(A) 3 feet
(B) 3.5
(C) 4 feet
(D) 5 feet
Answer: The answer to your question is D! Brainliest?
Step-by-step explanation:
To find the height needed to reach a volume of 240 ft^3, we can use the formula:
Volume = length x width x height
Substituting the given values, we get:
240 = 8 x 6 x height
Simplifying:
240 = 48 x height
height = 240/48
height = 5
Therefore, the height needed to reach a volume of 240 ft^3 is 5 feet.
Answer: (D) 5 feet.
a culture contains 10,000 bacteria initially. after an hour the bacteria count is 25,000. (a) find the doubling period. (b) find the number of bacteria after 3 hours.