The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent. If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Answers

Answer 1

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = [tex]\sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}[/tex]

                 = [tex]{^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}[/tex]  + .......+ [tex]{^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}[/tex]

                = 0.04541 + ......+0.0000002079

                = 0.1076

⇒Probability that at least 490 do not result in birth defects = 0.1076


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Answers

Answer:

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Answers

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Answer: False study.

Explanation: This is not true, and is purely by chance.

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

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Answers

Answer:

TE = 12

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