True or false? When a change of state starts to occur, the energy supplied changes the temperature but not the internal energy.​

Answer:

5) The approximate height is about 80 m. Choice (c)

6) The stone takes about 3 seconds to rise to its maximum height

Explanation:

Free Fall Motion

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the gravitational acceleration, which value is [tex]g = 9.8 m/s^2[/tex].

The distance traveled by a dropped object is:

[tex]\displaystyle y=\frac{gt^2}{2}[/tex]

Question 5

Given the stone reaches the ground in t=4 seconds, the height of the tower is:

[tex]\displaystyle y=\frac{9.8*4^2}{2}=78.4\ m[/tex]

The approximate height is about 80 m. Choice (c)

Question 6

Vertical Motion

The vertical motion of an object is controlled by the force of gravity. This means that there is a non-zero net force acting on the object that makes it accelerate downwards.

If the object is thrown upwards at speed vo, its speed at time t is:

[tex]v_f=v_o-g.t[/tex]

The stone reaches its maximum height when the final speed is zero, thus:

[tex]v_o-g.t=0[/tex]

Solving for t:

[tex]\displaystyle t=\frac{v_o}{g}[/tex]

The stone is thrown vertically upwards with vo=30 m/s, thus:

[tex]\displaystyle t=\frac{30}{9.8}[/tex]

[tex]t=3.06\ s[/tex]

[tex]t\approx 3\ s[/tex]

The stone takes about 3 seconds to rise to its maximum height

Answer:

t = 3.52 s

Explanation:

Given that,

The deceleration of a car is, a = -1.7 m/s²

The initial velocity of the car, u = 15 m/s

Final velocity of the car, v = 9 m/s

We need to find the time that is required to slow the car from 15 m/s to 9 m/s. The definition of acceleration is :

[tex]a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{9-15}{-1.7}\\\\t=3.52\ s[/tex]

So, it will take 3.52 seconds to slow the car from 15 m/s to 9 m/s.

Answer:

2 moles of H2Nsuperscript(-) or NHsubscript2 , amide group!

I hope it will be useful.

Answer:

Group IA elements have only one valency electron while Group IIA have two valency electrons.

Group IA elements have cations with higher charge density hence polarizing anions easier resulting into covalent character while Group IIA elements have cations with lower charge density hence difficulty in distorting anions resulting into a ionic character. This is due to difference in cationic radii and charges

Answer:

I tried...

Explanation:

Assuming the English system of mass and weight is the same as the Imperial system, the measurements are:

• 1 pound (lb) = 16 ounces (oz)

• 2,000 pounds (lbs) = 1 ton (T)

I think that's everything?

In the English system, mass is measured in pounds and weight is also measured in pounds. However, it is important to understand the difference between mass and weight.

Mass is a measure of the amount of matter in an object and is a scalar quantity. It does not change with location or gravitational force. In the English system, mass is typically measured using a scale or balance, which compares the object's mass to a standard mass. The pound (lb.) is the unit of mass in the English system.

Weight, on the other hand, is a measure of the force exerted on an object due to gravity and is a vector quantity. It depends on the object's mass and the gravitational force acting on it. In the English system, weight is typically measured using a spring scale or a balance that incorporates a spring. The pound (lb.) is also used as the unit of weight in the English system.

Weight = Mass x Acceleration due to gravity

Mass is measured in pounds (lb.) and weight is also measured in pounds (lb.).It is important to note that weight can vary depending on the gravitational force acting on an object.

Learn more about weight here:

https://brainly.com/question/28221042

#SPJ2

Answer:

follow me for the answer

Answer:

104.59 m

Explanation:

The following data were obtained from the question:

Horizontal velocity (u) = 13 ms¯¹

Horizontal distance (s) = 60 m

Height (h) =?

Next, we shall determine the time taken for the car to get to the ground. This can be obtained as follow:

Horizontal velocity (u) = 13 ms¯¹

Horizontal distance (s) = 60 m

Time (t) =?

s = ut

60 = 13 × t

Divide both side by 13

t = 60 / 13

t = 4.62 s

Finally, we shall determine the height cliff. This can be obtained as follow:

Time (t) = 4.62 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

h = ½gt²

h = ½ × 9.8 × 4.62²

h = 4.9 × 21.3444

h = 104.59 m

Thus, the height of the cliff is 104.59 m

Answer:

speed described how fast the object moves velocity describes how fast and in what direction its moved..

Answer:

4g

I hope it will be useful.

Explanation:

KE = (1/2)*m*v^2

Explanation:

vgfbhhhhhjhbgvbhggy

Answer:

In reality, the filament gets so hot it in a real sense bubbles off molecules and electrons. Now and again this material gathers as a dull spot at the highest point of the bulb. Eventually, the filament falls apart, gets frail, and breaks, subsequently finishing the life of the light. Lights radiate light by siphoning an electric flow through a dainty tungsten fiber. The filament warms and emits light. Over the long haul, the filament oxidizes and turns out to be increasingly fragile, until it splits up and the bulb goes out. ... Tungsten picks up obstruction as it warms.

Hope this helped :)

Answer:

The answer to this question is given below in the explanation section.

Explanation:

how the aperture geometry relates to the

diffraction pattern:

Diffraction is the spreading out of waves as they pass through an aperture or around objects.it occurs when the size of the aperture or obstacle is of the same order of magnitude as the wavelength of  the incident wave.For every small aperture sizes,the vast majority of the wave is blocked.For large apertures the wave passes by or through the obstacle without any significant of diffraction.

            in an aperture with width smaller than the wavelength,the wave transmitted through the aperture spreads all the way around the behave like a point sources of waves.

                             single slit diffraction pattern

The diffraction pattern made by waves passing through a slit of width [tex]\alpha[/tex] (larger than∫) can be understood by imagining a series of point sources all in phase along the width of the slit.The waves moving directly forward are all in phase,so they from a large central maximum.

                 if the waves travels at an angle Ф from the normal to the slit,then there is a path difference x between the waves production at the two end of the slit.

           x=a sinΦ

The path difference between the top and middle waves is λ/2 then they are exactly out of phase and cancel each other out. This happens to all consecutive pairs of waves (the ones produced by the second source from the top and the second source past the middle etc.)at the angle so there is no resultant wave at this angle.Thus a minimum is the diffraction pattern is obtained at

                                                   λ=α sinθ

Now slit can be divided into four equal sections and the pairing of sources to give destructive interference can be repeated for the top two section ,which is identical to the result of pairing off matching sources in the bottom two sections.in this case we obtained from the minimum.

             λ/2=α/4 sinθ

we can divided the slit aperture into six equal sections and pair off sources in the top two divisions and then the bottom two,to give destructive interference for every matched pair.The minimum of intensity are obtained at angles

                      nλ = α sinθ

where n is an integer (1,2,......),  but not n=0.There is a maximum of intensity in the center of the pattern. This process only gives the position of the minima,does not work for positions of the maxima,and so does not give the intensities of the maxima.

Answer:

Q = 78375 [J]

Explanation:

To solve this problem we must use the following ideal equation for the thermal energy of an element or substance depending on the temperature change.

[tex]Q=m*C_{p}*(T_{final}-T_{initial})[/tex]

where:

Q = heat [J]

m = mass = 0.25 [kg]

Cp = specific heat = 4180 [J/kg*C]

Tinitial = 25[°C]

Tfinal = 100 [°C]

[tex]Q =0.25*4180*(100-25)\\Q = 78375 [J][/tex]

Answer:

individuality

Explanation:

since he cannot run with paul he decided to run by himself making his exercise individual

Answer: individuality

Explanation:

(you can ignore this its just the deffintion of  individuality)

This is a crucial principle, the fundamental fact that everyone is different! Everyone responds to training in a different way. If you are walking or cycling with a friend, and doing exactly the same amount of training, don’t be concerned if one of you gets fitter faster than the other – this is what individualisation is all about.

It might be that one of you is having some pressure at work or difficulties at home, but wherever it is, it’s surprising what can affect your training. Some days your training can go really well and the next day, even though it was exactly the same length workout, it can be a nightmare. This is individualisation.

Answer: 500 ft

Explanation:

High beam headlights help one to see better at night as the range of vision is greatly expanded. They can however, blind drivers coming on the opposite lane.

It is therefore prudent to ensure that when using high beam headlights, you dim them when a car is coming towards you. The appropriate distance to do so is a minimum of 500 ft from the car.

Answer:

The car drives 108 m

Answer:

Two moles of aluminum chloride [tex](AlCl_3)[/tex] are produced when six miles of hydrogen Chloride [tex](HCl)[/tex] react with plenty of aluminum

Explanation:

6 Moles of [tex]HCl[/tex] will only react with 2 moles of [tex]Al[/tex] irrespective of the number of moles of each compound present. The reaction wiil take place in this ratio only. The products produced will be 2 moles of [tex]AlCl_3[/tex] and 3 moles of [tex]H_2[/tex] this ratio will also be constant.

So, six moles of hydrogen chloride [tex](HCl)[/tex] will react with plenty of aluminum to produce many 2 moles of aluminum chloride [tex](AlCl_3)[/tex].