Answer:
Different
Explanation:
The hollow one will expand even more making it have a larger volume then the solid one so they are different
A horse gallops for 3.5 minutes around the raceing track. During this time it changes velocity from 543 min to 628 min. Calculate the acceleration of the horse during this 3.5min interval
Answer:
The acceleration of the horse during this time interval is 24.286 m/min²
Explanation:
Given;
initial velocity of the horse during the gallop, u = 543 m /min
final velocity of the horse during the gallop, v = 628 m /min
time of motion, t = 3.5 minutes
The acceleration of the horse is given by the change in velocity per change in time;
[tex]a = \frac{v-u}{t}\\\\a = \frac{628-543}{3.5}\\\\a = 24.286 \ m/min^2[/tex]
Therefore, the acceleration of the horse during this time interval is 24.286 m/min²
Charlie's father built a tree house in their backyard. He constructed a spiral staircase around the tree trunk and installed a ladder. Which will involve more work in climbing up the tree house from the ground?
Answer:
The spiral staircase will require more work
Explanation:
This is because, work can be calculated as force (which is mass of the individual climbing the stairs in this case) multiplied by distance (or length) of the stairs. The only variable that changes in the work done while climbing any of the two (ladder or spiral staircase) is the distance and it is obvious the length of the spiral staircase will be longer; thus the spiral staircase will involve more work.
A man carries a load of mass 2.6kg from one end of a uniform pole 100cm long which has a mass 0.4kg. The pole rest on his shoulder at a point 60.0cm from the load and he holds it by the other end. What vertical force must be applied by his hand and what is the force on his shoulder?
Answer:
F = 39.2 N (hand force) and N = 68.6 N (shoulder force)
Explanation:
In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole
Let's set the reference system at the fit point of the shoulder
∑ τ = 0
We will assume that the counterclockwise turns are positive
w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0
all distances are measured from the support of the man (x₀ = 0.60 m)
F = (w₁ 0.60 + W 0.1) / 0.4
F = (m₁ 0.6 + m 0.1) g / 0.4
let's calculate
F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4
F = 39.2 N
this is the force that the hand must exert to keep the system in balance
We apply the translational equilibrium condition
-w₁ -W + N - F = 0
N = w₁ + W + F
N = (m₁ + m) g + F
let's calculate
N = (2.6 + 0.4) 9.8 + 39.2
N = 68.6 N
An object O is acted upon by a 6 N force and a 5 N force. The angle between these two forces is 60°. Draw a scale diagram showing the forces acting on object O and determine the resultant force.
Answer:
Resultant force = [tex]\sqrt{91}[/tex]N
Explanation:
Rf = [tex]\sqrt{f1²+f2²+2.f1.f2.cos60}[/tex]
Rf = [tex]\sqrt{6²+5²+2.6.5.1/2}[/tex]
Rf = [tex]\sqrt{36+25+30}[/tex]
Rf = [tex]\sqrt{91}[/tex]
doesn't look right though...
The magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Given parameters:
Two forces are 6 N and 5N.
Angle between them is 60 degree.
So, magnitude of resultant force be = √(6² + 5² + 2× 6 × 5 × cos60°) N = = 9.54 N.
Angle of the resultant force with respect to 5 N is = tan⁻¹{6sin60°/(5 +6 cos60°) } = 33⁰.
Hence, magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
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The English Channel is 35 km wide at its narrowest point, which is where most swimmers attempt to cross north to south from England to France. The current across this portion of the English Channel runs at about 2 km/h east to west.
a. If a swimmer has a relative velocity to the shore of 3 km/h north to south, how long will it take her to cross the 35 km distance?
b. What must be her velocity relative to the water if she has a velocity of 3 km/h north to south relative to the shore?
Answer:
a.) 20.4 h
b.) 3.46 km/h
Explanation:
Given that an English Channel is 35 km wide at its narrowest point, which is where most swimmers attempt to cross north to south from England to France. The current across this portion of the English Channel runs at about 2 km/h east to west.
a.) If a swimmer has a relative velocity to the shore of 3 km/h north to south, The resultant velocity (Vr) will be achieved by using Pythagoras theorem
Vr = [tex]\sqrt{2^{2} + 3^{2} }[/tex]
Vr = [tex]\sqrt{4 + 9}[/tex]
Vr = [tex]\sqrt{12}[/tex]
Vr = 3.46 m/s
To get how long it take her to cross the 35 km distance, Let us first find acceleration by using third equation of motion.
[tex]V^{2} = U^{2} + 2aS[/tex]
Where U = 0
Substitute all the parameters into the equation
[tex]3.46^{2} = 2 x a x 35[/tex]
11.97 = 70a
a = 11.97/70
a = 0.17 km/h^2
The time can be found by using equation
V = U + at
let U = 0
3.46 = 0.17t
t = 3.46/0.17
t = 20.35h
b. What must be her velocity relative to the water if she has a velocity of 3 km/h north to south relative to the shore?
her velocity relative to the water will be
Vr = [tex]\sqrt{2^{2} + 3^{2} }[/tex]
Vr = [tex]\sqrt{4 + 9}[/tex]
Vr = [tex]\sqrt{12}[/tex]
Vr = 3.46 m/s
What happens to potential energy as the car goes up the hill?
does anyone know the answer ?
Answer:
it is 2 and 3 trust me I gotcha
Al inicio de un paseo recorrerá una distancia de 200 km/h, los primeros 120 km lo hará a una velocidad constante de 60 km/h y el resto a una velocidad constante de 90 km/h,¿Cuánto tiempo en horas total durará el viaje?
Responder:
1 hora 20 min
Explicación:
Paso uno:
datos dados
Durante los primeros 120 km, se nos dice que la velocidad es de 60 km / h.
sabemos que velocidad = distancia / tiempo
por lo tanto, distancia = velocidad * tiempo
deja que el tiempo sea ty la velocidad sea s
distancia = s * t
distancia = 60t -------------------- 1
Segundo paso:
Durante los segundos 80 km, se nos dice que la velocidad es de 90 km / h.
sabemos que velocidad = distancia / tiempo
por lo tanto, distancia = velocidad * tiempo
deja que el tiempo sea ty la velocidad sea s
distancia = s * t
desatancia = 90t ------------------- 2
La distancia total recorrida es de 200 km.
entonces 200 = 60t + 90t
200 = 150t
t = 200/150
t = 1,3 horas
Por lo tanto, el viaje tendrá una duración de 1 hora y 20 minutos aproximadamente.
Parker (73.2 kg) is being dragged down the hall with an applied force of 123 N. If the frictional force is 27.4 N, what is the coefficient of friction in the hall?
Answer:
The coefficient of friction in the hall is 0.038
Explanation:
Given;
mass of the Parker, m = 73.2 kg
applied force on the parker, F = 123 N
frictional force, Fs = 27.4 N
the coefficient of friction in the hall = ?
frictional force is given by;
Fs = μN
Where;
μ is the coefficient of friction
N is normal reaction = mg
Fs = μmg
μ = Fs / mg
μ = (27.4) / (73.2 x 9.8)
μ = 0.038
Therefore, the coefficient of friction in the hall is 0.038
How does the law of conservation of mass apply to this reaction: C2H4 + O2 → 2H2O + 2CO2?
Answer:
The equation needs to be balanced. There are fewer oxygen atoms in the equation than hydrogen or carbon. ... There is an equal number of each element on both sides of the equation.
Explanation:
A bar magnet is a permanent magnet, While an electromagnetic temperary?
yes an electromagnetic is temporary
Two students are measuring the Gravitational Attraction between each other. One student weighs 120 kg. The other student weighs 108 kg. Calculate the gravitational pull they have on each other.
Answer:
[tex]F=8.64\times 10^{-9}\ N[/tex]
Explanation:
Given that,
Mass of student 1, m₁ = 120 kg
Mass of student 2, m₂ = 108 kg
Let they are at a distance of 10 m.
We need to find the gravitational pull they have on each other. The gravitational force acting between two objects is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{120\times 108}{(10)^2}\\\\=8.64\times 10^{-9}\ N[/tex]
So, the gravitational pull between students is [tex]8.64\times 10^{-9}\ N[/tex].
A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance travelled by the truck during this?
Answer:
82.7 m
Explanation:
u= 22m/s
a= 2.4 m/s^2.
t= 3.2 secs
Therefore the distance travelled can be calculated as follows
S= ut + 1/2at^2
= 22 × 3.2 + 1/2 × 2.4 × 3.2^2
= 70.4 + 1/2×24.58
= 70.4 + 12.29
= 82.7 m
Hence the distance travelled by the truck is 82.7 m
A soccer ball is kicked with an initial velocity 13 m/s at an angle of 35 degrees from the horizontal. What is the maximum height reached by the ball?
Answer:
The maximum height reached by the ball is 2.84 m
Explanation:
Given;
initial velocity of the soccer, u = 13 m/s
angle of projection, θ = 35°
The maximum height reached by the ball = ?
Apply the following kinematic equation, to determine the maximum height reached by the ball.
Maximum height (H) is given as;
[tex]H = \frac{U^2sin^2\theta}{2g} \\\\H = \frac{(13)^2(sin \ 35^0)^2}{2*9.8}\\\\H = 2.84 \ m[/tex]
Therefore, the maximum height reached by the ball is 2.84 m
Due to the friction between a tire and the road surface, the temperature of the air inside a tire increases as one drives. If the tire pressure is 37 psi when the car is in the driveway at 25° C, What is the pressure of the tire when the temperature increases to 50° C?
Answer:
40.10 atm .
Explanation:
Here volume of tire is assumed to be nearly constant .
Modified gas law ,
P₁ / T₁ = P₂ / T₂
37 / ( 273 + 25 ) = P₂ / ( 273 + 50)
37 / 298 = P₂ / 323
P₂ = 37 x 323 / 298
= 40.10 atm .
If a chicken has a weight of 300 N on Earth, what would be its weight on Mercury if the gravity is 0.38.
Answer:
114N
Explanation:
gravity on earth: 10m/s (exact: 9.82)
mass if chicken = 300/10 = 30Kg
weight of chicken on mercury = 3.8 x 30 = 114N (you wrote 0.38 but Mercury's gravity is about 3.7)
Answer:
113.15 g
Explanation:
That's because the planets weigh different amounts, and therefore the force of gravity is different from planet to planet. For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That's because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.
Please help I will give brainliest
Answer:
ask questions that the findings bring up
Explanation:
hope this helps :)
Answer:
ask questions that the findings bring up
The speed of light in that material is slower or faster?
A juggler throws a beanbag into the air with a speed of 1.0 m/s.
How long does it take for the beanbag to reach its maximum height?
Which of the following actions will increase the inertia of a shopping cart?
-Adding items to the cart
-
-Removing the wheels from the cart
O Rearranging items in the cart
Oiling the cart's wheels
Answer:
A. Adding items to the cart
Explanation:
Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.
In physics, Sir Isaac Newton's first law of motion is known as law of inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.
The inertia of an object such as a shopping cart is greatly dependent or influenced by its mass; the higher quantity of matter in a shopping cart, the greater will be its tendency to continuously remain at rest.
Hence, adding items to the cart is an action which will increase the inertia of a shopping cart, by increasing its tendency to be at rest.
Adding items to the cart will increase the inertia of a shopping cart.
Inertia refers to the resistance that an object has to modify its velocity and/or direction during movement. Inertia not only includes the speed of the object but also the direction of its movement.Inertia also can be described as the inherent tendency of a given object to resist changes in its state of movement (motion).In conclusion, adding items to the cart will increase the inertia of a shopping cart.
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is it true that scientific theories and scientific laws both describe observed events??? provide evidence!!!!! only 2 people could answer so if you can't then comment and provide evidence thank you very much!!!!!!
Answer:
I'm not positive but I think the answer is Yes, because both scientific laws and theories are based on evidence.
Explanation:
Sorry I don't have notes on this, hope this helps! :)
emotional symptoms that may occur in those with a schizophrenic Disorder generally include all of the following except ______ emotion.
A. Flat
B. Appropriate
C. No
D. Inappropriate
Answer:
B
Explanation:
edge 2020
The emotional symptoms that may occur in those with a Schizophrenic disorder generally include all of the following except appropriate emotion. Hence, option (B) is correct.
What is schizophrenic disorder?Schizophrenia is a persistent, severe mental illness that has an impact on a person's relationships with others as well as their thinking, acting, and emotional expression. Despite not being as prevalent as other severe mental illnesses, schizophrenia can be the most persistent and incapacitating.
Schizophrenia patients frequently struggle to function well in relationships, the workplace, and academic settings. They can appear to have lost their sense of reality, feel afraid and withdraw. This chronic illness cannot be cured, but it can be managed with the right care.
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What allows us to categorize rocks into the three rock types: Igneous, Sedimentary, and Metamorphic?
Whether or not the rock melts
Involvement of sediment
Process of formation
O Magma or weathering.
Answer:process of formation
Explanation:
Please help with this!
On the way down the ball's velocity is Positive 9.8.
Option A) is the correct answer.
What is velocity:?
This refers to the speed at which an object moves in a given direction. It unit is meters per secocond, m/s.
What is acceleration?
This is the rate of change of velocity with respect to time. The speed and direction of the accelerating object are also very important. It unit is meters per second square, m/s².
What is Gravity?
This is the force that pulls a body toward the center of the earth. This force causes objects to fall freely. This free-falling object has an acceleration of 9.8m/s downward the earth. This is called acceleration gravity.
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A box sitting still on the ground by itself has a Normal Force of 700N, what is the mass? (gravity’s acceleration is 9.80 m/s²)
Answer:
Mass, m = 71.42 kg
Explanation:
Given that,
Normal force acting on a box, F = 700 N
We need to find the mass of a box. Let it is m. Normal force acting on an object is balanced by its weight such that,
F = mg
Where m is the mass of the box
[tex]m=\dfrac{F}{g}\\\\m=\dfrac{700\ N}{9.8\ m/s^2}\\\\m=71.42\ kg[/tex]
So, the mass of the box is 71.42 kg.
A weight lifter is trying to lift a 1,500 N weight but can apply a force of only 1,200 N on the weight. One of his friends helps him lift it at a constant velocity. What force was applied to the rope
Answer:
400N is applied to the rope
Answer:
300N
Explanation:
Assuming his friend didn't throw the box, they would need a total of 1,500N to lift it, if the first person is already applying 1,200N, the only other amount of force needed is 300N to make a total of 1,500N! Simple math problem :)
Hope this helps! <3
You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.
Complete Question
You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.
(a) How much static frictional force does the floor exert on the refrigerator? Give both magnitude and direction.
magnitude N
direction
(b) What maximum force do you need to apply before the refrigerator starts to move?
Answer:
a
The magnitude is [tex]F_f = 339.57 \ N[/tex]
The direction is [negative x - axis ]
b
The maximum force to be applied for the refrigerator to start moving is
[tex]F_{max} = 339.57 \ N[/tex]
Explanation:
From the question we are told that
The horizontal force applied is [tex]F_a = 280 \ N[/tex] the direction is +ve x-axis
The mass of the refrigerator is [tex]m = 63 \ kg[/tex]
The coefficient of static friction is [tex]\mu_s = 0.55[/tex]
Generally the frictional force exerted on the refrigerator is mathematically represented as
[tex]F_f = \mu * m * g[/tex]
=> [tex]F_f = 0.55 * 63 * 9.8[/tex]
=> [tex]F_f = 339.57 \ N[/tex]
From the value obtained we see that the static force exerted by the floor on the refrigerator is greater than the force (280 N ) exerted by the person and the direction is -ve x-axis
Generally the maximum force that is to be applied by the person is mathematically equal to the force exerted by the floor on the refrigerator but the direction is in the positive x-axis i.e
[tex]F_{max} = F_f = 339.57 \ N[/tex]
W1 has a weight of 220 N acting 0.6m away from the pivot.
How far does W2 whose weight is 180 N need to sit for the see
saw to be in equilibrium.
&
?
W-220 N
W2 - 180N
a) 0.3 m
Ob) 0.73 m
C) 0.5m
O d) 0.83 m
Answer:
0.73m
Explanation:
Given parameters:
W1 = 220N
D1 = 0.6m
W2 = 180N
Unknown
D2 = ?
Solution:
The torque on each side must be balanced;
Torque = force x distance
T₁ = T₂
W1 x D1 = W2 x D2
Insert the parameters and solve for D2;
220 x 0.6 = 180 x D2
132 = 180D2
D2 = [tex]\frac{132}{180}[/tex] = 0.73m
I need help on this question
Answer:
at rest because time is passing and speed is still at 0
Explanation:
A farmer is pushing a 75 kg plow across a field with 700 N at an angle of 35 degrees above the ground. If the kinetic frictional force between the plow and the field is 250 N. What is the Normal Force from the ground onto the plow? And what is the acceleration of the plow?
Given :
A farmer is pushing a 75 kg plow across a field with 700 N at an angle of 35 degrees above the ground.
The kinetic frictional force between the plow and the field is 250 N.
To Find :
The Normal Force from the ground onto the plow.
The acceleration of the plow.
Solution :
Normal force = mg + F sin Ф
= 75×10 + 700 × sin 35°
= 1151.50 N
Now,
ma = 700 cos Ф - 250
75×a = 323.4
a = 4.31 m/s²
Hence, this is the required solution.