Answer:
a) 0.39795 kJ/K
b) 79.589.37 kJ
Explanation:
m = Mass of air = 2 kg
Temperature = 200 K
P₁ = Initial pressure = 300 kPa
P₂ = Final pressure = 600 kPa
R = mass-specific gas constant for air = 287.058 J/kgK
a) For isentropic process
∴ Entropy is generated in the process is 0.39795 kJ/K
b)
∴ Amount of lost work is 79.589.37 kJ
IF A CAR AHEAD OF YOU HAS STOPPED AT A CROSSWALK, YOU SHOULD:
A. Stop and then proceed when safe
B. Change lanes, look carefully, and pass
C. Slow down, look both ways, and proceed
D. Drive to the right edge of the road and stop
HELP PLZ
Answer:
well, depend if theres a stop sign or a light signal..you can always just honk at him/her so they proceed
Explanation:
but otherwise, the answer would be
A: stop and proceed when safe
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