We will pass in a value N. Write a program that outputs the complete Fibonacci sequence for N iterations. Important: If N is 0, then we expect to get an output of 0. If N=1 then we expect 0, 1 etc.

Answer:

//import the Random class

import java.util.Random;

//Begin class definition

public class CoinFlipper {

   //The main method

    public static void main(String []args){

       //Create an object of the Random class

       Random ran = new Random();

       System.out.println("Result");    

       //Use the object and the number of times for simulation

       //to call the flipCoin method

       flipCoin(ran, 25);

    } //End of main method

    //Method to flip coin

    public static void flipCoin(Random ran, int nooftimes){

        //Create a loop to run as many times as specified in variable nooftimes

       for(int i=1; i<=nooftimes; i++)

           System.out.println(ran.nextInt(2) + 1);

    }

}   //End of class definition

====================================================

Sample Output:

Result

1

1

1

2

1

2

2

1

2

1

1

2

1

2

1

1

1

2

1

1

1

2

2

1

2

========================================================

Explanation:

The above code has been written in Java. It contains comments explaining every part of the code. Please go through the comments.

The sample output from the execution of the code is also given above.

The code is re-written as follows without comments.

import java.util.Random;

public class CoinFlipper {

    public static void main(String []args){

       Random ran = new Random();

       System.out.println("Result");    

       flipCoin(ran, 25);

    }

    public static void flipCoin(Random ran, int nooftimes){

       for(int i=1; i<=nooftimes; i++)

           System.out.println(ran.nextInt(2) + 1);

    }

}

Answer:

Here is the function PrintSongsShorterThan() which prints all the songs from the album shorter than the value of the parameter songDuration.

void Album::PrintSongsShorterThan(int songDuration) const {

unsigned int i;

Song currSong;  

cout << "Songs shorter than " << songDuration << " seconds:" << endl;  

for(int i=0; i<albumSongs.size(); i++){  

currSong = albumSongs.at(i);  

if(currSong.GetDuration()<songDuration){  

currSong.PrintSong();     } } }

Explanation:

I will explain the working of the for loop in the above function.

The loop has a variable i that is initialized to 0. The loop continues to execute until the value of i exceeds the albumSongs vector size. The albumSongs is a Song type vector and vector works just like a dynamic array to store sequences.

At each iteration the for loop checks if the value of i is less than the size of albumSongs. If it is true then the statement inside the loop body execute. The at() is a vector function that is used to return a reference to the element at i-th position in the albumSongs.  So the album song at the i-th index of albumSongs is assigned to the currSong. This currSong works as an instance. Next the if condition checks if that album song's duration is less than the specified value of songDuration. Here the method GetDuration() is used to return the value of duration of the song. If this condition evaluates to true then the printSong method is called using currSong object. The printSong() method has a statement cout << name << " - " << duration << endl;  which prints/displays the name of the song with its duration.

If you see the main() function statement: musicAlbum.PrintSongsShorterThan(210);

The musicAlbum is the Album object to access the PrintSongsShorterThan(210) The value passed to this method is 210 which means this is the value of the songDuration.

As we know that the parameter of PrintSongsShorterThan method is songDuration. So the duration of each song in albumSongs vector is checked by this function and if the song duration is less than 210 then the name of the song along with its duration is displayed on the output screen.

For example if the album name is Anonymous and the songs name along with their duration are:

ABC 400

XYZ 123

CDE 300

GHI 200

KLM 100

Then the above program displays the following output when the user types "quit" after entering the above information.

Anonymous                                                                              

Songs shorter than 210 seconds:                                                                        

XYZ - 123                                                                                                              

GHI - 200                                                                                                              

KLM - 100

Notice that the song name ABC and CDE are not displayed because they exceed the songDuration i.e. 210.

The output is attached.

Answer:

well you could use variables in C and display them

Explanation:

Answer:

cell_count = int(input("Enter the value: "))

cell_count *= 10

print(cell_count)

Explanation:

Ask the user to enter a value and set it to the cell_count variable

Multiply the cell_count by 10 and assign it to the cell_count (It can also be written as cell_count = cell_count * 10)

Print the cell_count

Answer:

1. Yes

2. No

Explanation:

1 Note that the term BIOS (Basic input and Output System) refers to instructions that controls a computer device operations. Thus, devices that shows up in BIOS should be in device manager.

2. Not all devices listed in devcie manager of a computer system will be listed in BIOS.

Answer:

What-If Analysis in Excel allows you to try out different values (scenarios) for formulas. The following example helps you master what-if analysis quickly and easily.

Assume you own a book store and have 100 books in storage. You sell a certain % for the highest price of $50 and a certain % for the lower price of $20.

(i really hope this is what u needed)

Answer:

The first thing that is judged in the interview is the self confidence. If a person is self confident he is better able to express himself. The employer wants a candidate who has potential to bring good to the organization.

Explanation:

The employer for enthusiasm in the candidate to work passionately. He also considers relevant skills and expertise and relevant knowledge of work. The qualification also matters. It is important for a candidate to read the person specifications carefully before applying for a job. There can be certain tests conducted by employer during the interview process to identify the candidates potential and how he reacts in certain situations.

Answer:

Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?

Explanation:

Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?

Answer:

c. a key found on Windows-oriented computer keyboards.

Explanation:

Hope it helps.

Answer: DHCP (dynamic host configuration protocol)  is a protocol which automatically processes the configuring devices on IP networks.It allows them to to use network services like: NTP and any communication proto cal based on UDP or TCP. DHCP assigns an IP adress and other network configuration parameters to each device on a network so they can communicate with  other IP networks. it is a part of DDI solution.

Explanation:

Answer:

223 8s an order of algorithm faults refrénce fifio 14 suppose in 14 and 123 no need to take other numbers

Answer:

Can be executed on multiple platforms.

Explanation:

A program is portable if it is not platform dependent. In other words, if the program is not tightly coupled to a particular platform, then it is said to be portable. Portable programs can run on multiple platforms without having to do much work. By platform, we essentially mean the operating system and hardware configuration of the machine's CPU.

Examples of portable programs are those written in;

i. Java

ii. C++

iii. C

Answer:brain

Explanation:

to think

Answer:

num_ones = amount_to_change % 5

Explanation:

It is given that the cashier has to change the money in the maximum number of 5 dollar bills and remaining as $1 bills.

We have to write a single statement of code to assign the value to variable num_ones to find the value of $1 bills given amount_to_change.

Let us solve this by taking example:

If amount_to_change = $19

Then total number of $5 bills that can be given is 3. And amount that can be given as $5 bills is [tex]\bold{3 \times 5 = \$15}[/tex]

So, the remaining amount i.e. $19 - $15 = $4 will be given as one dollar bills.

Out of these $19, 4 bills of $1 can be found using the Modulus (%) operator.

Modulus operator leaves the remainder i.e.

Output of p % q is the remainder when a number 'p' is divided by 'q'.

19 % 5 = 4

4 is the number of one dollar bills to be given.

So, single line of code for the number of one dollar bills can be written as:

num_ones = amount_to_change % 5

Let us try it for amount_to_change  = $30

We know that 6 number of $5 bills can be used to change the amount of $30 and no one dollar bill required.

num_ones = 30 % 5 = 0 (because 30 is completely divisible by 5 so remainder is 0)

So, the correct statement is:

num_ones = amount_to_change % 5

Answer:

/etc/yum.conf

Explanation:

The absolute pathname for YUM is /etc/yum.conf. The configuration file For yum and related utilities can be found there. The file has one compulsory section, and this section can be used to place Yum options with global effect, it could also have one or more sections, that can enable you to set repository-specific options.

Answer:

The answer is to simplify the logic diagrams.

Explanation:

With the help of K-map, we can find the Boolean expression with the minimum number of the variables. To solve the K-map, there is no need of theorems of the Boolean algebra. There are 2 forms of the K-map - POS (Product of Sum) and SOP (Sum of Product), these forms are used according to the requirement. From these forms, the expression can be found.

Answer:

Because if you don't do it BIOS doesn't support it. ... In troubleshooting a boot problem what would be the point of disabling the quick boot feature in BIOS setup

Explanation:

Answer:

ADAC uses powershell

Domain Local, Global, and Universal are examples of group scenes

Explanation:

Active directory software is suitable for directory which is installed exclusively on Windows network. These directories have data which is shared volumes, servers, and computer accounts. The main function of active directory is that it centralizes the management of users.

It should be noted thst statements are true about managing through Active Directory are;

Active Directory can be regarded as directory service that is been put in place by  Microsoft and it serves a crucial purpose for Windows domain networks.

It should be noted that in managing through Active, ADAC uses powershell.

Therefore, in active directory Domain Local, Global, and Universal are examples of group scenes .

Learn more about Active Directory  at:

https://brainly.com/question/14364696

Answer:

a.

Explanation:

Two bytes have 2 times 8 bits is 16 bits.

Max value that can be expressed is 2¹⁶-1 = 65535

Answer:

The answer is "For the stop and wait the value of S and R is equal to 1".

Explanation:

Answer:

I am writing a C program.

#include <stdio.h> // for using input output functions

#include <stdbool.h> // for using a bool value as data type

int main() { // start of the main() function body

 int count=0; //count the number of entries

 double gallons, miles, MilesperGallon, combined_avg, sum; //declare variables

 while(true) {// takes input gallons and miles value from user and computes avg miles per gallon

      printf( "Enter the gallons used (-1 to stop): \n" ); //prompts user to enter value of gallons or enter -1 to stop

      scanf( "%lf", &gallons );//reads the value of gallons from user

   if ( gallons == -1 ) {// if user enters -1

     combined_avg = sum / count; //displays the combined average by dividing total of miles per drives to no of entries

     printf( "Combined miles per gallon for all tankfuls:  %lf\n", combined_avg ); //displays overall average value  

     break;} //ends the loop

     printf( "Enter the miles driven: \n" ); //if user does not enter -1 then prompts the user to enter value of miles

     scanf( "%lf", &miles ); //read the value of miles from user

MilesperGallon = miles / gallons; //compute the miles per gallon

printf( "The miles per gallon for tankful:  %lf\n", MilesperGallon ); //display the computed value of miles per gallon

  sum += MilesperGallon; //adds all the computed miles per gallons values

   count += 1;  } } //counts number of tankfuls (input entries)

Explanation:

The program takes as input the miles driven and gallons used for each tankful. These values are stored in miles and gallons variables. The program calculates and displays the miles per gallon MilesperGallon obtained for each tankful by dividing the miles driven with the gallons used. The while loop continues to execute until the user enters -1. After user enters -1, the program calculates and prints the combined miles per gallon obtained for all tankful. At the computation of MilesperGallon for each tankful, the value of MilesperGallon are added and stored in sum variable. The count variable works as a counter which is incremented to 1 after each entry. For example if user enters values for miles and gallons and the program displays MilesperGallon then at the end of this iteration the value of count is incremented to 1. This value of incremented for each tankful and then these values are added. The program's output is attached.

Answer:

When using find command in word we can search all of the above

Answer:

The number of execution can't always be determines

Explanation:

The following points should be noted

Variable d relies on variable x (both of double data type) for its value

d is calculated as

[tex]d = \sqrt{x}^2 - x[/tex]

Mere looking at the above expression, the value of d should be 0;

However, it doesn't work that way.

The variable x can assume two categories of values

The range of the above values depend on the system running  the application;

When variable x assumes a small value,

[tex]d = \sqrt{x}^2 - x[/tex] will definitely result in 0 and the loop will terminate immediately because [tex]\sqrt{x}^2 = x[/tex]

When variable x assumes a large value,

[tex]d = \sqrt{x}^2 - x[/tex] will not result in 0  because their will be [tex]\sqrt{x}^2 \neq x[/tex]

The reason for this that, the compiler will approximate the value of [tex]\sqrt{x}^2[/tex] and this approximation will not be equal to [tex]x[/tex]

Hence, the loop will be executed again.

Since, the range of values variable x can assume can not be predetermined, then we can conclude that the number of times the loop will be executed can't be determined.

Answer:

A. These describe the authority level of workers, fair payment practices, communication channels, and the like.  

Explanation:

As seen in the question above, you have been asked to write the project management plan and know that you need to consider elements such as policies, rules, systems, relationships and standards in the organization. These elements are part of EEF's entry into this process, in addition they are fundamental and indispensable for the description not only of the organizational governance structure, but also describe the management elements that will be adopted and used.

However, there is no way to use them to describe the level of authority of workers, fair payment practices, communication channels and the like, as this is not the function of this.

Answer:

Since the get_seconds function is not given, I'll implement it myself;

The full program (get_seconds and main) written in python is as follows:

def  get_seconds(hour,minute,seconds):

    seconds = hour * 3600 + minute * 60 + seconds

    return seconds

time1 = get_seconds(2,30,0)

time2 = get_seconds(0,45,15)

result = time1 + time2

print(result)

Explanation:

The get_seconds defines hour, minute and seconds as its arguments

This line defines the get_seconds function

def  get_seconds(hour,minute,seconds):

This line calculates the second equivalent of the time passed to the function

    seconds = hour * 3600 + minute * 60 + seconds

This line returns the the calculated seconds equivalent of time

    return seconds

The main starts here

This line calculates the number of seconds in 2 hours and 30 minutes

time1 = get_seconds(2,30,0)

This line calculates the number of seconds in 45 minutes and 15 seconds

time2 = get_seconds(0,45,15)

This line adds both together

result = time1 + time2

This line prints the result

print(result)

Answer:

Network.

Explanation:

Availability is an essential part of network security, and user behavior analysis and application analysis provide the data needed to ensure that systems are available.

Availability in computer technology ensures that systems, applications, network connectivity and data are freely available to all authorized users when they need them to perform their daily routines or tasks. In order to make network systems available regularly, it is very essential and important to ensure that all software and hardware technical conflicts are always resolved as well as regular maintenance of the systems.

A network administrator can monitor the network traffics and unusual or unknown activities on the network through the user behavior analysis and data gathered from the application analysis to ensure the effective and efficient availability of systems.

Answer:

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

   const int WEIGHT_MIN   =    0,

             WEIGHT_MAX   =   20,

             DISTANCE_MIN =   10,

             DISTANCE_MAX = 3000;

   float package_weight,

         distance,

         total_charges;

   cout << "\nWhat is the weight (kg) of the package? ";

   cin >> package_weight;

   if (package_weight <= WEIGHT_MIN ||

       package_weight > WEIGHT_MAX)

   {

       cout << "\nWe're sorry, package weight must be\n"

            << " more than 0kg and less than 20kg.\n"

            << "Rerun the program and try again.\n"

            << endl;

   }

   else

   {

       cout << "\nDistance? ";

       cin >> distance;

       if (distance < DISTANCE_MIN ||

           distance > DISTANCE_MAX)

       {

           cout << "\nWe're sorry, the distance must be\n"       << "within 10 and 3000 miles.\n"

                << "Rerun the program and try again.\n"

                << endl;

       }

       else

       {

            if (package_weight <= 2)

               total_charges = (distance / 500) * 1.10;

           else if (package_weight > 2 &&

                   package_weight <= 6)

               total_charges = (distance / 500) * 2.20;

           else if (package_weight > 6 &&

                   package_weight <= 10)

               total_charges = (distance / 500) * 3.70;

           else if (package_weight > 10 &&

                   package_weight <= 20)

               total_charges = (distance / 500) * 4.80;

           cout << setprecision(2) << fixed

               << "Total charges are $"

               << total_charges

               << "\nFor a distance of "

               << distance

               << " miles\nand a total weight of "

               << package_weight

               << "kg.\n"

               << endl;

       }

   }

Explanation:

Answer:

//Method definition

//Method receives a String argument and returns a String value

public static String removeDuplicates(String str){

       //Create a new string to hold the unique characters

       String newString = "";

       //Create a loop to cycle through each of the characters in the

       //original string.

       for(int i=0; i<str.length(); i++){

           // For each of the cycles, using the indexOf() method,

           // check if the character at that position

           // already exists in the new string.

           if(newString.indexOf(str.charAt(i)) == -1){

               //if it does not exist, add it to the new string

               newString += str.charAt(i);

           }  //End of if statement

       }   //End of for statement

       return newString;   // return the new string

   }  //End of method definition

Sample Output:

removeDuplicates("bookkeeeeeper") => "bokeper"

Explanation:

The above code has been written in Java. It contains comments explaining every line of the code. Please go through the comments.

The actual lines of codes are written in bold-face to distinguish them from comments. The program has been re-written without comments as follows:

public static String removeDuplicates(String str){

       String newString = "";

       for(int i=0; i<str.length(); i++){

           if(newString.indexOf(str.charAt(i)) == -1){

               newString += str.charAt(i);

           }

       }

       return newString;

   }

From the sample output, when tested in a main application, a call to removeDuplicates("bookkeeeeeper") would return "bokeper"

Answer:

[tex]\boxed{2}[/tex]

Explanation:

[tex](x+3)(x-1)[/tex]

Expand the brackets.

[tex]x(x-1)+3(x-1)[/tex]

[tex]x^2-x+3x-3[/tex]

Combine like terms.

[tex]x^2+2x-3[/tex]

The coefficient of [tex]x[/tex] is [tex]2[/tex].