What is the precipitate in the following reaction?
2AgNO3(aq) + Na2S(aq) → Ag2S(s) + 2NaNO3(aq)

What Is The Precipitate In The Following Reaction?2AgNO3(aq) + Na2S(aq) Ag2S(s) + 2NaNO3(aq)

Answers

Answer 1

Answer:

2Ag(+1)(aq) + S(-2)(aq) --> Ag2(+1)S(-2)(aq)

Explanation:

The final equation is

2Ag(+1)(aq) + S(-2)(aq) --> Ag2(+1)S(-2)(aq)

2Ag(+1)NO3(-1)(aq) + Na2(+1)S(-2)(aq) --> Ag2(+1)S(-2)(s) + 2Na(+1)NO3(-1)(aq)

AgNO3, Na2S, and NaNO3 are all strong electrolytes, so we immediately separate those, making the new equation:

2Ag(+1)(aq) + 2NO3(-1)(aq) + 2Na(+1)(aq) + S(-2)(aq) --> Ag2(+1)S(-2)(s) + 2Na(+1)(aq) + 2NO3(-1)(aq)

After that, you cancel out all the ions that appear more than once, which in this case would leave us with a final equation of...

2Ag(+1)(aq) + S(-2)(aq) --> Ag2(+1)S(-2)(aq)

Answer 2

Answer:

Explanation:

C


Related Questions

A 35 L tank of oxygen is at 42°C with an internal pressure of 5000.mmHg. If the temperature changes to 88°C, what would the new pressure be ? the volume is held constant

Answers

Answer:

5730 mmHg.

Explanation:

The following data were obtained from the question:

Initial temperature (T1) = 42 °C.

Initial pressure (P1) = 5000 mmHg.

Final temperature (T2) = 88 °C.

Final pressure (P2) =.?

Next we shall convert celsius temperature,T(°C) to Kelvin temperature, T(K).

This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T1) = 42 °C.

Initial temperature (T1) = 42 °C + 273 = 315 K

Final temperature (T2) = 88 °C.

Final temperature (T2) = 88 °C + 273 = 361 K

Finally, we shall determine the new pressure.

Since the volume of the container is constant, the new pressure can be obtained as follow:

Initial temperature (T1) = 315 K.

Initial pressure (P1) = 5000 mmHg.

Final temperature (T2) = 361 K.

Final pressure (P2) =.?

P1/T1 = P2/T2

5000/315 = P2/361

Cross multiply

315 x P2 = 5000 x 361

Divide both side by 315

P2 = (5000 x 361) / 315

P2 = 5730.1 ≈ 5730 mmHg

Therefore, the new pressure is 5730 mmHg.

------------neutral particles in an atom​

Answers

Answer:

neutrons :

Explanation:

Protons are positively charged, while electrons are negatively charged. Neutrons are electrically neutral, as the name suggests. The electric charge, noted Q , is a physical quantity.

A sample of O2 gas is collected over water at 25oC at a barometric pressure of 751 torr. The vapor pressure of water at 25oC is 23.8 torr. What is the partial pressure of the O2 gas in the sample

Answers

Answer:

727.7 torr

Explanation:

Since the gas was collected over water, it is likely to be saturated with water vapour and the total pressure is given as;

Ptotal = Pgas + Pwater

From the question;

Ptotal = 751 torr

Pgas = ?

Pwater = 23.8 torr

Making Pgas subject of equation, we have;

Pgas = Ptotal - Pwater

Pgas = 751 torr - 23.8 torr

Pgas = 727.7 torr

how many sigma and pi bonds in propionic bond

Answers

Propanoic acid formula is ch ch 2 so it has 8 bonds

what happens when ca no3 2 is heating it gives CaO ,NO2 and 02

Answers

Answer:

balanced equation:

2Ca(NO3)2 (aq)-----> 2CaO (s) + 4NO2 (g) + O2 (g)

So heating 2 moles of Ca(NO3)2 gives 2 moles of CaO, 4 moles of NO2 and 1 mole of O2. This is a heat decomposition reaction. It gives a white precipitate (CaO), and brown pungent gas (NO2).

Answer:

The balanced equation of the reaction is below.

Explanation:

2Ca(NO3)2 -----> 2CaO + 4NO2 + O2.

calculate the mass of sodium sulphate required to prepare its 20%of solution in 100 g ofwater​

Answers

Answer:

25 g

Explanation:

Mass percent implies the mass of solute dissolved in a solution

Mass percent = mass of solute/mass of solute + mass of solvent × 100/1

Since mass percent concentration= 20%

Mass of solvent = 100g

Let mass of solute = x

Hence;

20 = x/x +100 ×100/1

20/100= x/x + 100

0.2 = x/x + 100

0.2(x + 100) = x

0.2x + 20 = x

20 = x - 0.2x

20 = 0.8x

x= 20/0.8

x= 25 g

Which of the following elements does not lose an electron easily? NA F MG AL

Answers

Answer:

F

EXPLANATION

Among the given elements fluorine(F)can not lose electrons easily because of its high electron affinity, high nuclear charge and high electronegativity.

Answer:

F

Explanation:

it won't lose electron , rather it would gain electron to complete its octate......

Electronic Configuration of F = 2,7

So F will gain 1 electron ....

Explain this
When a small piece of glowing sodium is placed inside a gas jar filled with chlorine gas, the sodium continues to burn brightly but when the gas is replaced by argon gas, the glowing sodium becomes extinguished. ​

Answers

Answer:

Because Argon is a inert gas

Explanation:

Inert gases don't take place in any experiments

Answer:

Below.

Explanation:

The sodium reacts strongly with the chlorine to form NaCl and the heat of reaction continues the brightness, whereas it does not react with the inert gas  argon and soon cools down.

List four examples of diffusion seen in daily life.

Answers

Answer:

Spraying perfume in one corner of the room and the smell travels to the other side of the room

Explanation:

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