Answer:
speed of light: 299,792,458
what does light travel fasted through?: Light will have the fastest velocity when it travels through the air. Light will have the slowest velocity when it travels through gelatin. Why? Light slows down when passing through different transparent materials. The more it slows down, the more it bends when it hits a medium made of that material
A spring has an unstretched length of
12.0 cm. Its stiffness k is 8 N/cm. What load is
needed to stretch the spring to a length of 15.0 cm?
Answer:
24 N
Explanation:
Given,
Unstretched length or original length , x1 = 12cm
Stiffness constant, k = 8 N/cm
Load required to take spring to a length , x2 of 15cm
Recall the relation :
F = Ke
Where, e = extension
e = x2 - x1
e = (15 - 12) = 3
F = ke
F = 8 N/cm * 3cm
F = 24 N/cm*cm
F = 24 N
Hence, required load = 24 N
Calculator
What is the value of x?
Enter your answer in the box.
Х
24
x =
7
2
3
4 5 6 7 8
9
Answer:
25
Explanation:
By Using Pythagoras Theorem,
h^2=p^2+b^2
or, x^2=(24)^2+7^2
or, x^2=576+49
or, x^2=625
or, x=√625
•°• x=25
The value of x in this figure is 25.
What is Pythagorean theorem ?
Pythagorean theorem is applicable to only right angle tringle. it is defined as square of the hypotonias is equal to the square of sum of base and height.
i.e. hypotonias² = base² + height².
In this figure given values are,
Base = 7
Height = 24
hypotonias x = ?
according to Pythagorean theorem,
hypotonias² = base² + height²
hypotonias² = 7² + 24²
hypotonias² = 625
hypotonias = 25
Hence the value of x is 25.
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A toy train moves round a circular track of radius 0.50 m.
How many radians has the trained turned through in moving 1.4 m along a track?
Answer:
2.8 radians
Explanation:
[tex]s = r \beta \\ 1.4 = 0.50 \beta \\ \beta = 2.8 \: rad[/tex]
A spherical conducting shell has charge -5 C. A particle with charge -8 C is placed at the center of the cavity. The charges (in C) on the inner surface and on the outer surface of the shell, respectively, are:
Answer:
Explanation:
The charge of - 5C will be spread on the outer surface of the shell . The presence of - 8C charge at the Centre will create + 8C charge on the inner surface and - 8C charge on the outer surface . The result is that the total charge on the outer surface of the shell will be - 5C + - 8C = - 13C and the inner surface will have charge of + 8C . + 8C charge will be locked to centrally situated - 8C charge and will not be neutralized by negative charge of outer surface .
Which of the following organs are found in the
lower gastrointestinal tract? Check all that apply.
answers are above
Answer:
small intestine, tongue and large intestine
Explanation:
The GI tract is a series of hollow organs joined in a long, twisting tube from the mouth to the anus. The hollow organs that make up the GI tract are the mouth, esophagus, stomach, small intestine, large intestine, and anus. The liver, pancreas, and gallbladder are the solid organs of the digestive system.
Mark Brainiest if right plzz. Noah wants observe what happens when zinc is placed in a solution of
copper sulfate, as shown in the photo. But when he tries it, nothing happens.
He knows that the reaction might be happening too slowly to see results in a
few minutes. Which action should Noah take to speed up the reaction?
A. Replace the piece of zinc with a larger piece.
B. Decrease the concentration of the copper sulfate solution
C. Decrease the temperature of the solution.
D. Increase the concentration of the copper sulfate solution.
Answer:
A. the place that piece of with a larger piece
Explanation:
Sana nakatulong
Answer:
D. Increase the concentration of the copper sulphate.
Determine both the mass and the charge of a block of material consisting of 3 x 10^27 protons, 3 x 10^37 neutrons, and 3.1 x 10^27 electrons.
Answer:
The mass of the block of material is 3 x 10³⁷ g/mol
The charge of the material is 4.8 x 10⁸ C
Explanation:
Given;
number of protons of the material, P = 3 x 10²⁷
number of neutrons in the material, N = 3 x 10³⁷
number of electrons in the material, E = 3 x 10²⁷
The mass of the block of material is calculated as follows;
M = P + N
M = 3 x 10²⁷ + 3 x 10³⁷
M = 3 x 10³⁷ g/mol
The charge of the material is calculated as follows;
charge of 1 electron = 1.6 x 10⁻¹⁹ C
charge of 3 x 10²⁷ electrons = 3 x 10²⁷ electrons x 1.6 x 10⁻¹⁹ C
= 4.8 x 10⁸ C
How much acceleration does a car need if it is to go a distance of 620 ft. In a time of 20 sec while it is speeding up
Find the electric field a distance z above the midpoint between equal and opposite charges,a distance d apart
Answer:
Ex = [tex]2 k q \frac{x}{(x^2 + z^2) ^{3/2}}[/tex] , E_z =0
Explanation:
To find the electric field of each charge, let's use
E = k q / r²
where the field for a positive charge is outgoing and for a negative charge it is incoming.
Since the electric field is a vector magnitude, let's add its components at the point z
X axis
Eₓ = E₁ₓ + E₂ₓ
Eₓ = 2 E₁ₓ
Z axis
E_z = E_{1z} -E_{2z}
E_z= 0
Let's find the expression for the electric field
the distance from the charge to the test point, using the Pythagorean theorem is
r² = (x-0) ² + (0-z) ²
E = [tex]k \frac{q}{x^2 + z^2}[/tex]
with trigonometry we can find its components
cos θ = E₁ₓ / E
E₁ₓ = E cos θ
we substitute
Eₓ = 2 E cos θ
where the cosine
cos θ = x / r
Ex = [tex]2 k \frac{q}{x^2 + z^2} \ \frac{x}{\sqrt{x^2 + z^2} }[/tex]
Ex = [tex]2 k q \frac{x}{(x^2 + z^2) ^{3/2}}[/tex]
E_z = 0
Tarzan, whose mass is 100 kg, is hanging at rest from a tree limb. Then he lets go and falls to the ground. Just before he lets go, his center of mass is at a height 2.9 m above the ground and the bottom of his dangling feet are at a height 2.1 above the ground. When he first hits the ground he has dropped a distance 2.1, so his center of mass is (2.9-2.1) above the ground. Then his knees bend and he ends up at rest in a crouched position with his center of mass a height 0.5 above the ground. Consider the point particle system. What is the speed v at the instant just before Tarzan's feet touch the ground?
Answer:
[tex]6.42\ \text{m/s}[/tex]
Explanation:
v = Final velocity
u = Initial velocity = 0
s = Displacement of Tarzan's feet = 2.1 m
a = g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
From the kinematic equations we get
[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 2.1+0}\\\Rightarrow v=6.42\ \text{m/s}[/tex]
At the instant just before Tarzan's feet touch the ground the velocity of his feet are [tex]6.42\ \text{m/s}[/tex].
The speed at an instant just before Tarzen's feet touch the ground will be
[tex]V=6.42\ \dfrac{m}{s}[/tex]
What is speed?The speed of any body is defined as the movement of the body with respect to the time.
It is given in the question that
Mass of the Tarzen m=100 kg
The distance of the Tarzen's feet from the ground s=2.1 m
The acceleration due to gravity [tex]a=9.81\ \frac{m}{s^2}[/tex]
The speed of the Tarzen will be calculated by applying the equation of motion.
[tex]v^2=u^2+2as[/tex]
Since initial velocity is zero u=0
[tex]v^2=2as[/tex]
[tex]v=\sqrt{2as}[/tex]
[tex]v=\sqrt{2\times 9.81\times 2.1} =6.42 \ \frac{m}{s}[/tex]
Thus the speed at an instant just before Tarzen's feet touch the ground will be
[tex]V=6.42\ \dfrac{m}{s}[/tex]
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An eighth-grade class is studying the motion of objects. They have learned the following concepts about motion.
Motion occurs when there is a change in the position of an object with respect to a reference point.
While the speed of the object may change at various times during a trip the average speed for the trip is found by dividing the total distance by the total time.
The motion of the object can be changed by varying the amount of net force acting on the object or by varying the mass of the object.
The teacher asked students to design investigations to determine how changing the forces acting on an object or the mass of the object would change its motion.
The materials for the investigation included:
1 - toy cart
3 - 10N weights
1 - pulley
2 - meters of string
One group of students decided to design an investigation to determine how different amounts of mass on the toy cart would affect the speed of the toy cart. They set up their investigation as shown below:
The students performed several trials using different masses in the toy cart (M1). They hung a mass shown as (M2) to pull the toy cart as it dropped.
Below is a table they made to record their results.
Which of the following would be a way to test the effect changing the amount of force acting on the object has on the average speed of the object?
Move the cart at various speeds and determine the force at M1
Add varying numbers of weights to M1 and measure the speed of the car.
Add varying numbers of weights to M2 and measure the speed of the cart.
Move the cart at various speeds and determine the force exerted by M2
Add varying numbers of weights to M1 and measure the speed of the car.
Add varying numbers of weights to M2 and measure the speed of the cart.
How to test the effect of weight on the speed of object?In order to test the changing amount of force that is acting on the object has effect on the average speed of the object we have to change the amount of weight on the object and allows it to move to a certain point in this way we can check the effect of changing amount of weight on the speed of the object.
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PLZ HELP ME ASAP FOR 50 POINTS AND BRAINLIEST!!!
Answer:
1/32
Explanation:
It takes 1600 years for it to "die", when it dies it decomposes by half its original amount, then that half becomes the new total so it goes from 1 to 1/2 to 1/4 to 1/8 to 1/16 to 1/32
A wave carries _____ from one place to another
Mechanical waves carry energy through ______
Answer:
Energy
Matter
Explanation:
Bcuz I just did it on the warm up for edge
Answer:
the answer is energy and matter trust me
Explanation:
Can someone please explain this to me?
Answer:
the anser should be d
Explanation:
michael's house is 5.0 km away from his school. How long would it take him to go ti school, riding a bus, if its velocity is 25 km/h?
Pleaseee answer correctly
I mark brainliest who answer this
Answer:
12 mins
Explanation:
The distance covered is 5 km, divide this by 25 to get the fraction of an hour it takes. Doing this you get .2, times this by 60 min (1 hour) to get how many mins it takes
PLZZZZ HELPPPPPP MEEEEEE!!!!!! ASAP!!! ILL GIVE 20 POINTS AND BRAINLIEST!!!
:'(
I am soooooooooooo desperate.
Answer:
the answers the correct one is C
Explanation:
In radioactive decay processes, a very important concept is the half-life time, which is the time it takes for the parent nuclei to decompose into child nuclei.
expressed this mathematically is
N = N₀ [tex]e^{- \lambda t}[/tex]
for the average life time
N₀ / 2 = N₀ [tex]e^{- \lambda T_{1/2}[/tex]
T =[tex]\frac{ln 2x}{ \lambda}[/tex]
Analyzing this expression, the nuclei that decay are the so-called parents and the new nuclei called children appear.
when checking the answers the correct one is C
Work done depends on
A. Force
B. Displacement
C. Both force and displacement
D. Neither force nor displacement
Answer:
C. Both force and displacement
Explanation:
Hope this helps
work done in taking charge from one point of a conductor to is another point is called
Answer:
⁸
Explanation:
electric potential
I think so
PLA help if you understand
Answer:
b - it is not based on experimental data collected by scientists
Define centre of mass.
Answer:
The center of mass is a position defined relative to an object or system of object
If you go twice as fast, your kinetic energy becomes.
A.2 times smaller
B.4 times smaller
C.2 times bigger
D.4 times bigger
If the radius increased between the two objects what would happen to gravitational force between them?
Answer:
The Gravitational Force would decrease
Explanation:
The equation Gm1m2/r^2 is the equation for gravitational force. If you look, as we increase the radius, the overall value will decrease as we move further apart.
HELP ASAP Which statement describes the water particles when condensation takes place?
A. The particles gain heat energy and move closer to each other
B. The particles lose heat energy and move closer to each other
C. The particles gain heat energy and move away from each other
D. The particles lose heat energy and move away from each other
2. A hanging wind-chime on a calm day would have kinetic or potential energy?
kinetic
potential
Answer:
it would have potential energy
How much heat does it take to raise 0.0438 kg of aluminum from room temperature (20.0°C) to its melting point (660°C)?
HELP
Answer:
2.5x10^4 J (scientific notation)
25,000 (Acellus)
Equation:
Q=mcΔT
where:
Q=heat
m = mass
c = specific heat
ΔT=change in temperature
Any rearranging?
Let's see.
No, we need heat.
So no rearranging.
Plug in the numbers and solve
It takes approximately 28,224 joules of heat to raise 0.0438 kg of aluminum from room temperature to its melting point.
To calculate the heat required to raise the temperature of aluminum from room temperature to its melting point, we need to use the specific heat capacity formula: Q = m × c × ΔT
where:
Q = heat (in joules)
m = mass of aluminum (in kilograms)
c = specific heat capacity of aluminum (in joules per kilogram per degree Celsius)
ΔT = change in temperature (in degrees Celsius)
Given:
Mass of aluminum (m) = 0.0438 kg
Specific heat capacity of aluminum (c) = 900 J/kg°C (approximate value for aluminum)
Change in temperature (ΔT) = melting point (660°C) - room temperature (20°C) = 640°C
Now, let's calculate the heat (Q):
Q = 0.0438 kg × 900 J/kg°C × 640°C
Q = 28,224 J (joules)
So, it takes approximately 28,224 joules of heat to raise 0.0438 kg of aluminum from room temperature to its melting point.
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The Circulatory System is made up of ?
A Blood and Lungs
B Heart and Blood Veins
C arteries, veins, and heart
what made the dinosaurs instinct
Answer:
Eruptions/Volcano
Explanation:
poop fell from the sky
A graph with resistance in ohms on the x-axis from 0 to 200 and current in amps on the y-axis from 0 to 5. The graph is labeled as current as a function of resistance at 50 V. Points are plotted at (10, 5), (20, 2.5), (100, .5) and (200, .25). There is an inverse curve through the points. Use the graph to answer the questions. Based on the graph, what happens to current as resistance increases? This type of graph shows which type of relationship between the two variables? What would be a reasonable estimate for current at a resistance of 50 Ω?
Answer:
1. decreases
2. inverse proportionality
3. 1 A
Explanation
Just did it
Answer:
1. decreases
2. inverse proportionality
3. 1 A
Explanation
Just did it
Light waves travel at 3 × 10 8 m/s. If the light wave has a particular wavelength of 400 nm (400 × 10 –9 m), calculate its frequency.
Answer:
[tex]f=7.5\times 10^{14}\ Hz[/tex]
Explanation:
Given that,
The wavelength of light, [tex]\lambda=400\ nm=400\times 10^{-9}\ m[/tex]
The speed of light, [tex]c=3\times 10^8\ m/s[/tex]
We need to find the frequency of light. We know that,
[tex]c=f\lambda[/tex]
Where
f is the frequency
So,
[tex]f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{400\times 10^{-9}}\\\\f=7.5\times 10^{14}\ Hz[/tex]
So, the frequency of light is [tex]7.5\times 10^{14}\ Hz[/tex].
how much does the angle of refraction change from 380nm to 700nm when the incident angle is 80?
Answer:
35 degrees
Explanation:
The incident angle, an 80-degree angle, and as the angle of incidence increases, the amount of refraction also increases. So, we can expect a significant change in the angle of refraction from blue to red light at an 80-degree angle of incidence.
What is refraction?Refraction refers to the bending of light when it passes from different mediums.The amount of refraction that occurs at an interface between two materials depends on the wavelength of light, the angle of incidence, and the properties of the materials. The relationship between these factors is described by Snell's law:
n1 sinθ1 = n2 sinθ2
where n1 and n2 are the refractive indices of the two materials, θ1 is the angle of incidence, and θ2 is the angle of refraction.
For a given angle of incidence, the amount of refraction that occurs is greater for shorter wavelengths (i.e., blue light) than for longer wavelengths (i.e., red light). This effect is known as dispersion, and it is why we see rainbows when sunlight is refracted through water droplets.
In the absence of any information about the properties of the materials involved, we can assume that the amount of refraction will increase as the wavelength decreases.
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