Answer:
10,341
Step-by-step explanation:
[tex]S_{n}=\frac{n}{2} (a_1}+a_{n})\\S_{54}=\frac{54}{2} (6+377)=27 \times 383=10,341[/tex]
Classify the polynomial 2x^3+6x^2-4 by the number of terms. binomial. trinomial. cubic. quadratic.
Answer:
monomial
Step-by-step explanation:
An object is moving at a speed of 7300 inches every 3 seconds. Express this speed in miles per day.
Answer:
≈3318 miles per day....
Step-by-step explanation:
Help ASAP!!!
A recursive sequence is a sequence where each term is found by adding a common difference
True or false
Answer:
True
Step-by-step explanation:
What is the value of x in the equation 5 (4 x minus 10) + 10 x = 4 (2 x minus 3) + 2 (x minus 4)?
Answer:
x = 1.5
Step-by-step explanation:
5(4x-10)+10x=4(2x-3)+2(x-4)
Distribute(5)
20x-50+10x=4(2x-3)+2(x-4)
Distribute(4)
20x-50+10x=8x-12+2(x-4)
Distribute(2)
20x-50+10x=8x-12+2x-8
Combine like terms
30x-50=10x-20
Subtract(10x)
20x-50=-20
Add(50)
20x=30
Divide(20)
x = 1.5
Hope it helps <3
Answer:
x = 3/2Step-by-step explanation:
5 ( 4x - 10) + 10x = 4(2x - 3) + 2(x - 4)
Expand the terms
That's
20x - 50 + 10x = 8x - 12 + 2x - 8
Simplify
30x - 50 = 10x - 20
Group the constants at the right side of the equation
That's
30x - 10x = - 20 + 50
20x = 30
Divide both sides by 20
x = 3/2
Hope this helps you
Nakashima Gallery had the following petty cash transactions in February of the current year. Nakashima uses the perpetual system to account for merchandise inventory. Feb 2 Write a $400 check to establish a petty cash fund. Feb 5 Purchased paper for the copier for $14.15 that is immediately used. Feb 9 Paid $32.50 shipping charges (transportation in) on merchandise purchased for resale, terms FOB shipping point. These costs are added to merchandise inventory. Feb 12 Paid $7.95 postage to deliver a contract to a client Feb 14 Reimbursed Adina Sharon, the manager, $68 for mileage on her car. Feb 20 Purchased office paper for $67.77 that is immediately used. Feb 23 Paid a courier $20 to deliver merchandise sold to a customer, terms FOB destination. Feb 25 Paid $13.10 shipping charges (transportation in) on merchandise purchased for resale, terms FOB shipping point. These cost are added to merchandise inventory. Feb 27 Paid $54 for postage expenses Feb 28 The fund had $120.42 remaining in the petty cashbox. Sorted the petty cash receipts by accounts affected and exchanged them for a check to reimburse the fund for expenditures. Feb 28 The petty cash fund amount is increased by $100 to a total of $500
Answer:
1. Debit Petty cash for $400; and Credit Cash for $400.
2. Total petty cash payment = $270.57
3(a) Cash reimbursement is $279.58; and Cash over and short is $9.01.
3(b) Debit Petty cash for $100; and Credit Cash for $100.
Step-by-step explanation:
Note: This question is not complete. The full complete question is therefore provided before answering the question. See the attached pdf file for the full question.
The explanations to the answers are now given as follows:
1. Prepare the journal entry to establish the petty cash fund.
Note: See the journal entry in the attached excel file
2. Prepare a petty cash payments report for February with these categories: delivery expense, mileage expense, postage expense, merchandise inventory (for transportation-in), and office supplies expense. Sort the payments into the appropriate categories and total the expenditures in each category.
Note: See the petty cash payments report in the attached excel file.
3. Prepare the journal entries for required 2 to both (a) reimburse and (b) increase the fund amount.
Note: See the journal entries (a) and (b) in the attached excel file
3(a) Reimburse Workings:
w.1: Calculation of Cash reimbursement
Cash reimbursement = Petty cash fund - Petty cash fund balance = $400 - $120.42 = $279.58
w.2: Calculation of the Cash over and short
Cash over and short = Cash reimbursement – Total expenses = $279.58 - $270.57 - $120.42 = $9.01
What is a3 if an=64(12)n−1
Answer:
[tex]\huge\boxed{a_3=9,216}[/tex]
Step-by-step explanation:
[tex]a_n=64(12)^{n-1}\\\\\text{substitute}\ n=3:\\\\a_3=64(12)^{3-1}=64(12)^2=64(144)=9,216[/tex]
magazine provided results from a poll of adults who were asked to identify their favorite pie. Among the respondents, % chose chocolate pie, and the margin of error was given as percentage points. What values do , , n, E, and p represent? If the confidence level is %, what is the value of ?
Complete Question
A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie. Among the 500 respondents, 12 % chose chocolate pie, and the margin of error was given as plus or minus 5 percentage points.What values do [tex]\r p , \ \r q[/tex], n, E, and p represent? If the confidence level is 90%, what is the value of [tex]\alpha[/tex] ?
Answer:
a
[tex]\r p[/tex] is the sample proportion [tex]\r p = 0.12[/tex]
[tex]n[/tex] is the sample size is [tex]n = 500[/tex]
[tex]E[/tex] is the margin of error is [tex]E = 0.05[/tex]
[tex]\r q[/tex] represents the proportion of those that did not chose chocolate pie i.e [tex]\r q = 1- \r p[/tex]
b
[tex]\alpha = 10\%[/tex]
Step-by-step explanation:
Here
[tex]\r p[/tex] is the sample proportion [tex]\r p = 0.12[/tex]
[tex]n[/tex] is the sample size is [tex]n = 500[/tex]
[tex]\r q[/tex] represents the proportion of those that did not chose chocolate pie i.e
[tex]\r q = 1- \r p[/tex]
[tex]\r q = 1- 0.12[/tex]
[tex]\r q = 0.88[/tex]
[tex]E[/tex] is the margin of error is [tex]E = 0.05[/tex]
Generally [tex]\alpha[/tex] is the level of significance and it value is mathematically evaluated as
[tex]\alpha = ( 100 - C )\%[/tex]
Where [tex]C[/tex] is the confidence level which is given in this question as [tex]C = 90 \%[/tex]
So
[tex]\alpha = ( 100 - 90 )\%[/tex]
[tex]\alpha = 10\%[/tex]
Taylor and Jeff have been selling frozen pizzas for a class fundraiser. Taylor has sold half as many
pizzas as Jeff. Together they have sold a total of 126 pizzas. How many pizzas did Taylor sell?
Answer:
Taylor sold 42 pizzas
Step-by-step explanation:
Make a system of equations where t represents the number of pizzas Taylor sold and j represents the number that Jeff sold:
t + j = 126
j = 2t
We can solve this system by substitution, since we can substitute 2t as j.
t + j = 126
t + 2t = 126
3t = 126
t = 42
Taylor sold 42 pizzas.
Answer:
Step-by-step explanation:
Let x represent the number of pizzas that Tailor sold.
Let y represent the number of pizzas that Jeff sold.
Together they have sold a total of 126 pizzas. This means that
x + y = 126- - - - - - - - -1
Taylor has sold half as many
pizzas as Jeff. This means that
x = 1/2 × y = y/2
Substituting x = y/2 into equation 1, it becomes
y/2 + y = 126
Multiplying both sides of the equation by 2, it becomes
y + 2y = 252
3y = 252
y = 252/3
y = 84
x = y/2 = 84/2
x = 42
Taylor sold 42 pizzas
What is the square root of nine?
Answer:
3 or -3
Step-by-step explanation:
sqrt(9)
What number multiplied by itself will give you 9
3*3 =9
-3 * -3 =9
The square root of 9 is 3 or -3
In the last year, the population of Japan had a decay rate of 0.17% and decreased to 127,484,450. If this rate continues, what will be the population in 7 more years? Round your answer to the nearest whole number.
Answer:
125975100 the population in 7 years
Step-by-step explanation:
the population in 7 more years : 127,484450(1-0.0017)^7=125975100.1919 close to 125975100
Answer: 125,976,376 IN 7 YEARS
Step-by-step explanation:
A=127,484,450
R=-0.0017/YEAR
T=7/YEARS
[tex]A=127,484,450E ^{-0.0017.7}[/tex]a=125,976,375.88a=125,976,376 in 7years3/4 (1/2x - 12) + 4/5 HELP
Answer:
3/8x - 9 4/5
Step-by-step explanation:
Well we need to simplify the following expression,
[tex]\frac{3}{4} (\frac{1}{2}x - 12) + \frac{4}{5}[/tex]
So we need to distribute 3/4 to (1/2x - 12)
3/8x - 9 + 4/5
3/8x - 9 4/5
Thus,
the answer is 3/8x - 9 4/5.
Hope this helps :)
What is the missing term that makes these ratios equivalent? 1.5:3, 31.5:____
=========================================
Work Shown:
1.5/3 = 31.5/x
1.5x = 3*31.5 cross multiply
1.5x = 94.5
x = 94.5/1.5 dividing both sides by 1.5
x = 63
-----------
An alternative equation to solve is
1.5/31.5 = 3/x
1.5x = 31.5*3
1.5x = 94.5
The remainder of the steps are the same as in the previous section above.
What is the distance to the earth’s horizon from point P? Enter your answer as a decimal in the box. Round only your final answer to the nearest tenth.
Answer:
156.7 miles
Step-by-step explanation:
Since [tex]x[/tex] is tangent to the circle, then it is also a right angle with the radius, from here, just do Pythagorean theorem ([tex]a^{2}+b^{2}=c^{2}[/tex]) to solve for [tex]x[/tex].
Since 1 leg and the hypotenuse is given to you, you want to solve for the other leg, which is [tex]x[/tex] (either [tex]a[/tex] or [tex]b[/tex]). Lets use [tex]b[/tex] for [tex]x[/tex] and set up the equation.
[tex]b^{2}=c^2-a^2[/tex]
[tex]b^2=(3959+3.1)^2-3959^2[/tex]
[tex]b^2 = 3962.1^2 - 3959^2[/tex]
[tex]b^2 = 15,698,236.41 - 15,673,681[/tex]
[tex]b^2 = 24,555.41[/tex]
[tex]\sqrt{b^2}=\sqrt{24,555.41}[/tex]
[tex]b=156.7016592[/tex]
[tex]b=156.7[/tex] (round to nearest tenth)
The distance to the earth’s horizon from point P is 281.6 miles
What is distance?The distance between two points is the length of the line joining the two points. Distance is a numerical or occasionally qualitative measurement of how far apart objects or points are. In physics or everyday usage, distance may refer to a physical length or an estimation based on other criteria.
here, we have,
to determine the distance to the earth’s horizon from point P:
The tangent line from P meets the radius of the earth at a right angle.
This means that the triangle is a right triangle.
The length of x is then calculated as:
(3959 + 10)^2= 3959^2 + x^2
Rewrite as:
x^2 = (3959 + 10)^2- 3959^2
Evaluate
x^2 = 79280
Take the square root of both sides
x = 281.6
Hence, the distance to the earth’s horizon from point P is 281.6 miles
Read more about distance at:
brainly.com/question/3503424
#SPJ3
Does the mean represent the center of the data? A. The mean represents the center. B. The mean does not represent the center because it is the smallest data value. C. The mean does not represent the center because it is the largest data value. D. The mean does not represent the center because it is not a data value. E. There is no mean age.
Answer:
A. The mean represents the center.
A. The median represents the center.
B. The mode does not represent the center because it is the smallest data value.
Step-by-step explanation:
Mean
(9 + 9 + 12 + 12 + 9 + 8 + 8 + 8 + 10 + 8 + 8 + 8 + 11)/13 = 120/13 = 9.2
The mean 9.2 and it represents the center of data.
Median
By arranging the set of data, the median, the median is the center number
8,8,8,8,8,8,(9),9,9,10,11,12,12
The median is 9 and it represents the center of data.
Mode
The mode is the number that appears most in the set of data.
The number that appears most in the set of data is 8 and does not represent the set of data.
Given the data set, 9, 9, 12, 12, 9, 8, 8, 8, 10, 8, 8, 8,11:
the mean is: 9.2the median is: 9the mode is: 8A. The mean does represents the center of the data set
Given the following data set:
9, 9, 12, 12, 9, 8, 8, 8, 10, 8, 8, 8, 11
Let's find the mean, median, and mode.
Mean of the data set:
Mean = sum of all values / number of values
Mean = [tex]\frac{9 + 9 + 12 + 12 + 9 + 8 + 8 + 8 + 10 + 8 + 8 + 8 + 11}{13}[/tex]
Mean = [tex]\frac{120}{13} = 9.2[/tex]
Median of the data set:
Order the data from the least to the greatest then find the middle value.
Thus:8, 8, 8, 8, 8, 8, (9,) 9, 9, 10, 11, 12, 12
The middle value is 9.
The median = 9Mode of the data set:
The mode = the data value that appears most
8 appeared the most, therefore, the mode = 8
If you observe, you will note that the mean and median of the data set are similar. We can as well conclude that the mean represents the center of the data set.
In summary, given the data set, 9, 9, 12, 12, 9, 8, 8, 8, 10, 8, 8, 8,11:
the mean is: 9.2the median is: 9the mode is: 8A. The mean does represents the center of the data set
Learn more here:
https://brainly.com/question/16882439
WHY CAN'T ANYONE HELP ME :( Solve the formula for the specified variable. tex]D=\frac{1}{4}fk for f.
Answer:
4d/k or [tex]\frac{4d}{k}[/tex]
Step-by-step explanation:
first multiply both sides by four
you will have 4d=fk
then divide by k
4d/k=f
Need help finding the length
Answer:
27
Step-by-step explanation:
First, we need to find x. We are given the perimeter, which is 2l + 2w, so from there, we have an equation of 2(4x-1) + 2(3x+2) = 100. By working through it, we get that x = 7. We're asked to find WX, so plug 7 into 4x - 1 and get 27.
Answer:
27 unitsStep-by-step explanation:
Perimeter of rectangle is 2(l) + 2(w).
The perimeter is given 100 units.
2(4x-1) + 2(3x+2) = 100
Solve for x.
8x-2+6x+4=100
14x+2=100
14x=98
x=7
Plug x as 7 for the side WX.
4(7) - 1
28-1
= 27
Adam is going to cook a turkey for 14 people
Answer:
they divied the turkey into 14 pices
Step-by-step explanation:
A card is drawn from a well shuffled deck of 52 cards. What is the probability of drawing an ace or a 9? Round to nearest thousandth
Answer:
.154
Step-by-step explanation:
There are 52 cards
There are 4 aces and 4 9's for a total of 8 cars
P (ace or 9) = number of aces or 9's / total
= 8/52 = 2 /13 =.153846154
To the nearest thousandth
= .154
Answer:
0.154
Step-by-step explanation:
We want to find the probability of drawing an ace or a 9.
P(ace or 9)= aces and 9s / total cards
There are 4 aces and 4 9s in a standard deck of cards. This means there is a total of 8 aces and 9s.
In a standard deck of cards, there is a total of 52 cards.
P(ace or 9)= aces and 9s / total
aces and 9s= 8
total= 52
P(ace or 9)= 8/52
This fraction can be simplified. Both the numerator and denominator can be evenly divided by 4.
P(ace or 9)= (8/4) / (52/4)
P(ace or 9)= 2/13
P(ace or 9)= 0.153846153846154
Round to the nearest thousandth. The 8 in the ten thousandth place tell sus to round the 3 up to a 4.
P(ace or 9) = 0.154
The probability of drawing an ace or 9 is 0.154
Determine whether the function below is an even function, an odd function, both, or neither.
f(x)=x^6 + 10x^4-11x^2+19
ОА.
neither even nor odd
OB.
odd function
Ос.
both even and odd
OD.
even function
Reset
Next
Answer:
Step-by-step explanation:
even function are symmetrical about the y axis or f(-x)=f(x)
odd function are symmetrical about the origin -f(-x)=f(x)
f(x)=x^6 + 10x^4-11x^2+19
f(-x)=(-x)^6+10(-x)^4+11(-x)^2+19=x^6 + 10x^4-11x^2+19
the function is even
a hardware store ordered cartons of hammers at 100$ per carton and cartons wrenches at 150$ per carton if there were a total of 25 cartons in this order And the total cost of the order was 3,000$ how many cartons of hammers were ordered
Answer:
15 cartons of Hammers were ordered
Step-by-step explanation:
Cost per carton of Hammer = $100
Cost per carton of Wrenches = $150
Total Carton = 25
Total Cost = $3,000
Required
Determine the numbers of Hammer and Wrenches
Represent the hammers with H and the wrenches with W
So;
[tex]H + W = 25[/tex]
and
[tex]100H + 150W = 3000[/tex]
Make W the subject of formula in the first equation:
[tex]H + W = 25[/tex]
[tex]W = 25 - H[/tex]
Substitute 25 - H for W in the second equation
[tex]100H + 150(25 - H) = 3000[/tex]
[tex]100H + 3750 - 150H = 3000[/tex]
Collect Like Terms
[tex]100H - 150H = 3000 - 3750[/tex]
[tex]-50H = -750[/tex]
Divide both sides by -50
[tex]\frac{-50H}{=50} = \frac{-750}{-50}[/tex]
[tex]H = \frac{-750}{-50}[/tex]
[tex]H = 15[/tex]
Hence, 15 cartons of Hammers were ordered
Write 3 expressions containing exponents so that each expression equals 81
Answer:
9x9= 81
3x3x3x3=81
81 to the first power.
Step-by-step explanation:
I hope this helps in any way:)
PLEASEEEEE HELPPOO
For Individual or Group Explorations
Maximizing the Total Profit
Payles at The Christmas Store very periodically with a high ef 550.000 in December
the Christmas Stove also comes the Powe, where profits reach a high of $80,000
in Aurust and a few of $20,000 in February Assume that the profit function for
Crm Store
Save
40
20
10
1 2 3 4 5 6 7 8 9 10 11 12
Month
a) Write the profit function for The Christmas Store as a function of the month
and sketch its graph
b)
Write the profit function for The Pool Store as a function of the month and
sketch its graph.
are are length
Write the total profit as a function of the month and sketch its graph. What is
the period?
are inside the
est enth of a
Use the maximum feature of a graphing calculator to find the owner's maxi-
mum total profit and the month in which it occurs.
Find the owner's minimum total profit and the month in which it occurs.
We know that y -a sin x + bcos x is a sine function. However, the sum of
two arbitrary sine or cosine functions is not necessarily a sine function. Find an
example in which the graph of the sum of two sine functions does not look like
a sine curve.
Explain.
is tangent to one
Answer:
what
Step-by-step explanation:
Pls help!! Thank you sooooo much if you help me on this, pls show proof
Answer:
√468 = 6√13
Step-by-step explanation:
ABCDEF is a regular hexagon of side length 6.
A'B'C'D'E'F' is the reflection of ABCDEF across BC.
The line FE' is the line from F to E'. It is also the hypotenuse of the right triangle FEE'. FE = 6, and EE' = 4a, where a is the apothem of the hexagon.
To find the apothem, draw the 30-60-90 triangle formed by the apothem and the radius (essentially 1/12th of the hexagon).
Using properties of a 30-60-90 triangle:
a = (6/2)√3
a = 3√3
4a = 12√3
Using Pythagorean theorem:
x² = (6)² + (12√3)²
x² = 36 + 432
x = √468
x = 6√13
what are the coordinates of point b on ac such that ab=2/5ac
Answer:
[tex](-\frac{36}{7},\frac{40}{7})[/tex]
Step-by-step explanation:
Coordinates of points A and C are (-8, 6) and (2, 5).
If a point B intersects the segment AB in the ratio of 2 : 5
Then coordinates of the point B will be,
x = [tex]\frac{mx_2+nx_1}{m+n}[/tex]
and y = [tex]\frac{my_2+ny_1}{m+n}[/tex]
where [tex](x_1, y_1)[/tex] and [tex](x_2,y_2)[/tex] are the coordinates of the extreme end of the segment and a point divides the segment in the ratio of m : n.
For the coordinates of point B,
x = [tex]\frac{2\times 2+(-8)\times 5}{2+5}[/tex]
= [tex]-\frac{36}{7}[/tex]
y = [tex]\frac{2\times 5+5\times 6}{2+5}[/tex]
= [tex]\frac{40}{7}[/tex]
Therefore, coordinates of pint B will be,
[tex](-\frac{36}{7},\frac{40}{7})[/tex]
A sample of bacteria is growing at an hourly rate of 10% compounded continuously. The sample began with 4 bacteria. How many bacteria will be in the sample after 18 hours?
Answer:
24
Step-by-step explanation:
The computation of the number of bacteria in the sample after 18 hours is shown below:
We assume the following things
P = 4 = beginning number of bacteria
rate = r = 0.1
Now
We applied the following formula
[tex]A = Pe^{rt}[/tex]
[tex]= 4\times e^{18\times0.1}[/tex]
[tex]=4e^{1.8}[/tex]
[tex]= 4\times6.049647464[/tex]
= 24
We simply applied the above formula to determine the number of bacteria after the 18 hours
The equations x + 5 y = 10, 3 x minus y = 1, x minus 5 y = 10, and 3 x + y = 1 are shown on the graph below. On a coordinate plane, there are 4 lines. Green line goes through (0, negative 1) and (1, 2). Blue line goes through (0, 1) and (1, negative 2). Pink line goes through (0, 2), and (2, 1.5). Orange line goes through (negative 2, negative 2.5) and (2, negative 1.5). Which is the approximate solution for the system of equations x + 5 y = 10 and 3 x + y = 1? (–0.3, 2.1) (–0.3, –2.1) (0.9, –1.8) (0.9, 1.8)
Answer:
A: (–0.3, 2.1)
Answer:a
Step-by-step explanation:
x/3 ≥−33 solve for x answer must be simplified
Answer:
[tex]\boxed{x\geq -99}[/tex]
Step-by-step explanation:
[tex]\frac{x}{3} \geq -33[/tex]
[tex]\sf Multiply \ both \ sides \ by \ 3.[/tex]
[tex]\frac{x}{3} (3) \geq -33(3)[/tex]
[tex]x\geq -99[/tex]
Answer:
[tex]\boxed{\red{x \geqslant - 99}}[/tex]
Step-by-step explanation:
[tex] \frac{x}{3} \geqslant - 33 \\ x \geqslant - 33 \times 3 \\ x \geqslant - 99[/tex]
hope this helps you!
Given the sample mean = 23.375, sample standard deviation = 5.29, and N = 40 for the low income group, Test the claim that the mean nickel diameter drawn by children in the low income group is greater than 21.21 mm. Test at the 0.01 significance level.
a) Identify the correct alternative hypothesis:
A. p > 21.21
B. p < 21.21
C. p = 21.21
D. μ < 21.21
E. μ > 21.21
F. μ = 21.21
Give all answers correct to 3 decimal places
b) The test statistic value is:_______
c) Using the Traditional method, the critical value is:_______
Answer:
Step-by-step explanation:
a. To identify the alternative hypothesis, we have to examine the claim
The claim is that the mean nickel diameter drawn by children in the low income group is greater than 21.21 mm
Thus, alternative hypothesis is μ > 21.21
b. The test statistics is
z score = x - u /(sd/√n)
Where x (sample mean) is 23.375, u is pop. mean is 21.21, sd is 5.29 and n (sample size) is 40
z = 23.375 - 21.21 /(5.29/√40)
z = 2.165 / (5.29/6.3246)
z = 2.165/0.8364
z = 2.588
c. The critical value is
Alpha for this case study is 0.01. Then the critical probability is 1 - (alpha/2) =
1 - (0.01/2) = 1 - 0.005 = 0.995
To express the critical value as a z score, find the z score corresponding to the critical probability using the z table. Which is 0.8389.
Which two points are on the graph of y=-x+ 3?
(-1,-2), (1,4)
(1, 2), (0, -3)
(0, 3), (4, -1)
(4, -1), (1, 3)
Answer:
(0, 3), (4, -1)
(1, 2)
Step-by-step explanation:
If the answers that have been provided to you are only in pairs then it'd just be the first answer I wrote. The points (1, 2) also are on the graph of y=x+3 but if the answers aren't individual than I'd just stick with the (0, 3), (4, -1). Does that make sense? I used a graphing calculator online called Desmos, it's very good. I highly recommend it for problems like these.
I hope this helps:) Select as brainliest because I actually put work into this and tried.
in the life of a car engine, calculatedin miles, is normally distributed, with a mean of 17,000 miels and a standard deviation of 16,500 miles, what should be the guarantee period if the company wants less than 2% of the engines to fail while under warranty g
Answer:
the guarantee period should be less than 136010 miles
Step-by-step explanation:
From the given information;
Let consider Y to be the life of a car engine
with a mean μ = 170000
and a standard deviation σ = 16500
The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.
i.e
P(Y < T ) < 0.02
For the variable of z ; we have:
[tex]z = \dfrac{x - \mu }{\sigma}[/tex]
[tex]z = \dfrac{x - 170000 }{16500}[/tex]
Now;
[tex]P(Y < T ) = P( Z < \dfrac{T- 170000}{16500})[/tex]
[tex]P( Z < \dfrac{T- 170000}{16500})< 0.02[/tex]
From Z table ;
At P(Z < -2.06) ≅ 0.0197 which is close to 0.02
[tex]\dfrac{T- 170000}{16500}<- 2.06[/tex]
[tex]{T- 170000}<- 2.06({16500})[/tex]
[tex]{T- 170000}< - 33990[/tex]
[tex]{T}< - 33990+ 170000[/tex]
[tex]{T}<136010[/tex]
Thus; the guarantee period should be less than 136010 miles