Which of the following actions will increase the inertia of a shopping cart?
-Adding items to the cart
-
-Removing the wheels from the cart
O Rearranging items in the cart

Oiling the cart's wheels

Answers

Answer 1

Answer:

A. Adding items to the cart

Explanation:

Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.

In physics, Sir Isaac Newton's first law of motion is known as law of inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

The inertia of an object such as a shopping cart is greatly dependent or influenced by its mass; the higher quantity of matter in a shopping cart, the greater will be its tendency to continuously remain at rest.

Hence, adding items to the cart is an action which will increase the inertia of a shopping cart, by increasing its tendency to be at rest.

Answer 2

Adding items to the cart will increase the inertia of a shopping cart.

Inertia refers to the resistance that an object has to modify its velocity and/or direction during movement.

Inertia not only includes the speed of the object but also the direction of its movement.

Inertia also can be described as the inherent tendency of a given object to resist changes in its state of movement (motion).

In conclusion, adding items to the cart will increase the inertia of a shopping cart.

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Related Questions

write an essay on the great wall of china​

Answers

The Great Wall of China is one of the greatest architectural achievements ever recorded in history. The Great Wall translates to “long fortress.” The wall was made entirely by hand. It was built to protect the Chinese from intruders from different Nomadic Tribes. The wall is about 5,500 miles long. The wall did not stretch across all of China but it stretched from Shanhaiguan in the East to Lop Nur in the West. Some people say that you can even see the wall from the moon! Wouldn’t that be something to see? The wall is very old and has been around for about 2,000 years. Parts of the wall are missing from it decaying and crumbling. Despite parts of the wall missing it remains a popular attraction today and is one of the seven spectacular…show more content…
During the Ming dynasty (1368-1644) was when much most of the wall was added. The Mind dynasty suffered from their attackers the Dadan, Nuzhen, and Tufan tribes. The Ming court built a lot more walls in the north as an attempt to keep out the attacking tribes. They built the walls much more elaborate and durable than the Qin Dynasty. There were many walls, fortresses, and watch towers along the wall which made the country more successful. Even with all the new construction on the wall the Ming dynasty was defeated by the Oirats in the battle of Tumu in the year 1449. The Ming dynasty had failed to keep the Mongolian and Manchurian tribes under control and it had weakened the Ming Empire. After the Mings loss in this battle they built more walls to make them less vulnerable if they were attacked. Towards the end of the Ming dynasty the Great Wall helped a lot to defend them from the Manchu invaders. The Manchus got into Beijing through the Shanhaiguan gates and took over the city ending the rule of the Ming dynasty and starting the new rule of the Qing Dynasty. The Qing Dynasty extended Chinas territory farther north beyond the Great Wall. The wall didn’t protect China’s border anymore so, construction on the wall stopped and soldiers abandoned their posts on the wall. The wall wasn’t used again after.
Today, the Great Wall is still standing in some parts but people fear that itthe Great Wall] demonstrates the manifestation of the wisdom and tenacity of the Chinese people.”(cortland.edu). China is considered one of the world’s oldest civilizations with the first dynasty beginning in 221 B.C.. A famous icon of this great civilization is the Great Wall of China, or known to the Chinese as Wan Li Chang Cheng. During the Warring States period, many feudal societies built their own sections for security. Eventually the walls were connected and there was a unified China. With The Great Wall of China is known as the largest construction project to be put in effect in all of world history. The wall, also known in China as "long wall of 10,000 li," is a collection of numerous short walls extending along the crest of hills on the southern edge of the Mongolian plain. Although it is a common misconception that the Great Wall of China is one long continuous wall, it 's structural inconsistency in no way undermines its greatness. The wall has been built, destructed,includes modules of ________ so you can see the construction of _____ Today I am going to be presenting the Great Wall of China and what political and military reasons it was built for. The construction was a feat of great magnitude and reflected the innovations and technological advancements of the Ancient Chinese. The reason I have decided to focus upon the Ancient Chinese is because I find China a very interesting civilisation. The ancient Chinese civilisation began 7,000 to 8,000 years ago and about
The Great Wall of China James Allen World History 1st period February 1, 2015 The first unified Chinese empire was formed in 221 B.C., that was when seven states were brought together by Shi Huangdi, a conqueror from the state of Qin. Shi Huangdi means “first emperor.” Until the twentieth century all rulers of imperial China called themselves the emperor. The emperor was believed, by the people of China, to be the son of heaven, God-like

What happens to potential energy as the car goes up the hill?

Answers

The potential energy will increase
As a car goes up a hill, gravitational potential energy increases and kinetic energy decreases. I hope this helps!

A box sitting still on the ground by itself has a Normal Force of 700N, what is the mass? (gravity’s acceleration is 9.80 m/s²)

Answers

Answer:

Mass, m = 71.42 kg

Explanation:

Given that,

Normal force acting on a box, F = 700 N

We need to find the mass of a box. Let it is m. Normal force acting on an object is balanced by its weight such that,

F = mg

Where m is the mass of the box

[tex]m=\dfrac{F}{g}\\\\m=\dfrac{700\ N}{9.8\ m/s^2}\\\\m=71.42\ kg[/tex]

So, the mass of the box is 71.42 kg.

Two students are measuring the Gravitational Attraction between each other. One student weighs 120 kg. The other student weighs 108 kg. Calculate the gravitational pull they have on each other.

Answers

Answer:

[tex]F=8.64\times 10^{-9}\ N[/tex]

Explanation:

Given that,

Mass of student 1, m₁ = 120 kg

Mass of student 2, m₂ = 108 kg

Let they are at a distance of 10 m.

We need to find the gravitational pull they have on each other. The gravitational force acting between two objects is given by :

[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{120\times 108}{(10)^2}\\\\=8.64\times 10^{-9}\ N[/tex]

So, the gravitational pull between students is [tex]8.64\times 10^{-9}\ N[/tex].

Why does a liquid thermometer work

Answers

Liquid-in-glass thermometers are based on the principle of thermal expansion of substances. A liquid in a glass tube (called a capillary) expands when heated and contracts when cooled. ... In liquid-in-glass thermometers, the thermal expansion of liquids is used for measuring the temperature!

DO boys cheat more than girls?

Answers

Answer:

I'm not sure.

Explanation:

Look up the statistics

Answer: honestly girls cheat more than guys, its statically proven that females cheat more than guys its because they dont believe in value in a relationship

Explanation:

A soccer ball is kicked with an initial velocity 13 m/s at an angle of 35 degrees from the horizontal. What is the maximum height reached by the ball?

Answers

Answer:

The maximum height reached by the ball is 2.84 m

Explanation:

Given;

initial velocity of the soccer, u = 13 m/s

angle of projection, θ = 35°

The maximum height reached by the ball = ?

Apply the following kinematic equation, to determine the maximum height reached by the ball.

Maximum height (H) is given as;

[tex]H = \frac{U^2sin^2\theta}{2g} \\\\H = \frac{(13)^2(sin \ 35^0)^2}{2*9.8}\\\\H = 2.84 \ m[/tex]

Therefore, the maximum height reached by the ball is 2.84 m

A weight lifter is trying to lift a 1,500 N weight but can apply a force of only 1,200 N on the weight. One of his friends helps him lift it at a constant velocity. What force was applied to the rope

Answers

Answer:

400N is applied to the rope

Answer:

300N

Explanation:

Assuming his friend didn't throw the box, they would need a total of 1,500N to lift it, if the first person is already applying 1,200N, the only other amount of force needed is 300N to make a total of 1,500N! Simple math problem :)

Hope this helps! <3

If a chicken has a weight of 300 N on Earth, what would be its weight on Mercury if the gravity is 0.38.​

Answers

Answer:

114N

Explanation:

gravity on earth: 10m/s (exact: 9.82)

mass if chicken = 300/10 = 30Kg

weight of chicken on mercury = 3.8 x 30 = 114N (you wrote 0.38 but Mercury's gravity is about 3.7)

Answer:

113.15 g

Explanation:

That's because the planets weigh different amounts, and therefore the force of gravity is different from planet to planet. For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That's because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.

Al inicio de un paseo recorrerá una distancia de 200 km/h, los primeros 120 km lo hará a una velocidad constante de 60 km/h y el resto a una velocidad constante de 90 km/h,¿Cuánto tiempo en horas total durará el viaje?

Answers

Responder:

1 hora 20 min

Explicación:

Paso uno:

datos dados

Durante los primeros 120 km, se nos dice que la velocidad es de 60 km / h.

sabemos que velocidad = distancia / tiempo

por lo tanto, distancia = velocidad * tiempo

deja que el tiempo sea ty la velocidad sea s

distancia = s * t

distancia = 60t -------------------- 1

Segundo paso:

Durante los segundos 80 km, se nos dice que la velocidad es de 90 km / h.

sabemos que velocidad = distancia / tiempo

por lo tanto, distancia = velocidad * tiempo

deja que el tiempo sea ty la velocidad sea s

distancia = s * t

desatancia = 90t ------------------- 2

La distancia total recorrida es de 200 km.

entonces 200 = 60t + 90t

200 = 150t

t = 200/150

t = 1,3 horas

Por lo tanto, el viaje tendrá una duración de 1 hora y 20 minutos aproximadamente.

Which two fundamental forces are only attractive?
O A. Gravitational and strong nuclear
O B. Electromagnetic and weak nuclear
O C. Electromagnetic and strong nuclear
O D. Gravitational and weak nuclear

Answers

The two fundamental forces that are only attractive is  A. Gravitational and strong nuclear.

What connection exists between the strong nuclear force and gravity?

The "strong" nuclear force outperforms gravity by a factor of 10 to the 38th. While gravitational and electromagnetic forces have relatively large ranges of action, the strong and weak nuclear forces operate at close ranges. All objects are affected by the strong and weak nuclear forces, whereas smaller objects are affected by gravitational and electromagnetic forces.

Nuclear forces are the most enticing of the four fundamental forces. There was no explanation provided as to how the nucleus in the atom is kept together by electromagnetism, which maintains matter together.

Therefore, option A is correct.

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A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance travelled by the truck during this?

Answers

Answer:

82.7 m

Explanation:

u= 22m/s

a= 2.4 m/s^2.

t= 3.2 secs

Therefore the distance travelled can be calculated as follows

S= ut + 1/2at^2

= 22 × 3.2 + 1/2 × 2.4 × 3.2^2

= 70.4 + 1/2×24.58

= 70.4 + 12.29

= 82.7 m

Hence the distance travelled by the truck is 82.7 m

help pls!!! this is worth 30 points, can someone pls help even if u can only give a few answers it would be helpful.

Answers

1- potential 2-kinetic

Answer:

1. potential 2. kinetic 3. potential 4. kinetic 5. kinetic 6. kinetic 7. kinetic 8. kinetic. potential

A man carries a load of mass 2.6kg from one end of a uniform pole 100cm long which has a mass 0.4kg. The pole rest on his shoulder at a point 60.0cm from the load and he holds it by the other end. What vertical force must be applied by his hand and what is the force on his shoulder?

Answers

Answer:

F = 39.2 N   (hand force) and    N = 68.6 N (shoulder force)

Explanation:

In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole

Let's set the reference system at the fit point of the shoulder

     ∑ τ = 0

We will assume that the counterclockwise turns are positive

    w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0

all distances are measured from the support of the man (x₀ = 0.60 m)

    F = (w₁ 0.60 + W 0.1) / 0.4

    F = (m₁ 0.6 + m 0.1) g / 0.4

let's calculate

    F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4

    F = 39.2 N

this is the force that the hand must exert to keep the system in balance

We apply the translational equilibrium condition

    -w₁ -W + N - F = 0

     N = w₁ + W + F

     N = (m₁ + m) g + F

let's calculate

     N = (2.6 + 0.4) 9.8 + 39.2

     N = 68.6 N

An object O is acted upon by a 6 N force and a 5 N force. The angle between these two forces is 60°. Draw a scale diagram showing the forces acting on object O and determine the resultant force.​

Answers

Answer:

Resultant force = [tex]\sqrt{91}[/tex]N

Explanation:

Rf = [tex]\sqrt{f1²+f2²+2.f1.f2.cos60}[/tex]

Rf = [tex]\sqrt{6²+5²+2.6.5.1/2}[/tex]

Rf = [tex]\sqrt{36+25+30}[/tex]

Rf = [tex]\sqrt{91}[/tex]

doesn't look right though...

The magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.

What is force?

An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.

The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.

Given parameters:

Two forces are 6 N and 5N.

Angle between them is 60 degree.

So, magnitude of resultant force be = √(6² + 5² + 2× 6 × 5 × cos60°) N =  = 9.54 N.

Angle of the resultant force with respect to 5 N is = tan⁻¹{6sin60°/(5 +6 cos60°)  } = 33⁰.

Hence, magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.

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Please help with this!

Answers

On the way down the ball's velocity is Positive 9.8.

Option A) is the correct answer.

What is velocity:?

This refers to the speed at which an object moves in a given direction. It unit is meters per secocond, m/s.

What is acceleration?

This is the rate of change of velocity with respect to time. The speed and direction of the accelerating object are also very important. It unit is meters per second square, m/s².

What is Gravity?

This is the force that pulls a body toward the center of the earth. This force causes objects to fall freely. This free-falling object has an acceleration of 9.8m/s downward the earth. This is called acceleration gravity.

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Choose the best real world exzample of convection:
A. clouds forming in the atmosphere
B. touching a warm cooking pot handle
C. sitting in front of a warm fireplace

WHICH ONE IS THE ANSWER HELP PLESEEE

Answers

The correct answer is A
I think that it is B. I’m not completely sure. I hope that I helped

Lead-202 has a half-life of 53,000 years. How long will it take for 15/16 of a sample of lead-202 to decay?
106,000 years
159,000 years
212,000 years
265,000 years
(Thank you very much :L)

Answers

Answer:

C. 212,000 years

Explanation:

believe me it's correct.....and you're welcome :)

emotional symptoms that may occur in those with a schizophrenic Disorder generally include all of the following except ______ emotion.
A. Flat
B. Appropriate
C. No
D. Inappropriate

Answers

Answer:

B

Explanation:

edge 2020

The emotional symptoms that may occur in those with a Schizophrenic disorder generally include all of the following except appropriate emotion. Hence, option (B) is correct.

What is schizophrenic disorder?

Schizophrenia is a persistent, severe mental illness that has an impact on a person's relationships with others as well as their thinking, acting, and emotional expression. Despite not being as prevalent as other severe mental illnesses, schizophrenia can be the most persistent and incapacitating.

Schizophrenia patients frequently struggle to function well in relationships, the workplace, and academic settings. They can appear to have lost their sense of reality, feel afraid and withdraw. This chronic illness cannot be cured, but it can be managed with the right care.

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The speed of light in that material is slower or faster?

Answers

Faster..................

The components of a 15-meters-per-second velocity at an angle of 60.° above the horizontal are (1) 7.5 m/s vertical and 13 m/s horizontal (2) 13 m/s vertical and 7.5 m/s horizontal (3) 6.0 m/s vertical and 9.0 m/s horizontal (4) 9.0 m/s vertical and 6.0 m/s horizontal

Answers

Answer:

13 m/s vertical and 7.5 m/s horizontal

Explanation:

❤️

The vertical and horizontal components of a projectile is required.

The correct option is (2) 13 m/s vertical and 7.5 m/s horizontal

u = Initial velocity of projectile = 15 m/s

[tex]\theta[/tex] = Angle of projectile = [tex]60^{\circ}[/tex]

The horizontal component

[tex]u_x=u\cos \theta\\\Rightarrow u_x=15\cos60^{\circ}\\\Rightarrow u_x=7.5\ \text{m/s}[/tex]

The vertical component

[tex]u_y=u\sin \theta\\\Rightarrow u_x=15\sin60^{\circ}\\\Rightarrow u_x=13\ \text{m/s}[/tex]

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Un vagón de carga de 5000-kg se mueve a 2m/s e impacta a un vagón de 10000-kg que se encuentra en reposo. Después de la colisión inelástica a que rapidez se mueven.

Answers

Answer:

0.67 m/s

Explanation:

Mass of car 1, m₁ = 5000 kg

Mass of car 2, m₂ = 10,000 kg

Initial speed of car 1, u₁ = 2 m/s

Final speed of car 2, u₂ = 0 (at rest)

We need to find the final velocity of both cars when inelastic collision occurs. The momentum will remain conserved in case of inelastic collision. Using the conservation of momentum. Let V is the final speed.

[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{5000\times 2}{(5000+10000)}\\\\V=0.67\ m/s[/tex]

So, after the inelastic collision, they will move with a speed of 0.67 m/s.

is it true that scientific theories and scientific laws both describe observed events??? provide evidence!!!!! only 2 people could answer so if you can't then comment and provide evidence thank you very much!!!!!!

Answers

Answer:

I'm not positive but I think the answer is Yes, because both scientific laws and theories are based on evidence.

Explanation:

Sorry I don't have notes on this, hope this helps! :)

Please help I will give brainliest

Answers

Answer:

ask questions that the findings bring up

Explanation:

hope this helps :)

Answer:

ask questions that the findings bring up


W1 has a weight of 220 N acting 0.6m away from the pivot.
How far does W2 whose weight is 180 N need to sit for the see
saw to be in equilibrium.
&
?
W-220 N
W2 - 180N
a) 0.3 m
Ob) 0.73 m
C) 0.5m
O d) 0.83 m

Answers

Answer:

0.73m

Explanation:

Given parameters:

W1  = 220N

D1  = 0.6m

W2 = 180N

Unknown

D2 = ?

Solution:

The torque on each side must be balanced;

 Torque  = force x distance

     T₁   = T₂  

  W1  x D1  = W2 x D2

Insert the parameters and solve for D2;

   220 x 0.6  = 180 x D2

     132  = 180D2

     D2 = [tex]\frac{132}{180}[/tex]   = 0.73m

PLEASE HELP ME QUICKLY!!!!!!!!!!!!!!​

Answers

Answer:

I think thats the correct answer

Explanation:

EARTH SPACE SCIENCE.

I NEED HELP ASAP DUE TODAY. PLEASE 20 POINTS

Using the topographic map above, match the description to the letter that it represents.

Highest point on the map-
[ Select ]

Stream flowing to the East-
[ Select ]

Letter near the steepest slope-
[ Select ]

Letter near the flattest area-
[ Select ]

Stream flowing to the North- F

Answers

Answer:

c,e,f,d

Explanation:

A farmer is pushing a 75 kg plow across a field with 700 N at an angle of 35 degrees above the ground. If the kinetic frictional force between the plow and the field is 250 N. What is the Normal Force from the ground onto the plow? And what is the acceleration of the plow?

Answers

Given :

A farmer is pushing a 75 kg plow across a field with 700 N at an angle of 35 degrees above the ground.

The kinetic frictional force between the plow and the field is 250 N.

To Find :

The Normal Force from the ground onto the plow.

The acceleration of the plow.

Solution :

Normal force = mg + F sin Ф

= 75×10 + 700 × sin 35°

= 1151.50 N

Now,

ma = 700 cos Ф - 250

75×a = 323.4

a = 4.31 m/s²

Hence, this is the required solution.

Due to the friction between a tire and the road surface, the temperature of the air inside a tire increases as one drives. If the tire pressure is 37 psi when the car is in the driveway at 25° C, What is the pressure of the tire when the temperature increases to 50° C?

Answers

Answer:

40.10 atm .

Explanation:

Here volume of tire is assumed to be nearly constant .

Modified gas law ,

P₁ / T₁ = P₂ / T₂

37 / ( 273 + 25 ) = P₂ / ( 273 + 50)

37 / 298 = P₂ / 323

P₂ = 37 x 323 / 298

= 40.10 atm .

A horse gallops for 3.5 minutes around the raceing track. During this time it changes velocity from 543 min to 628 min. Calculate the acceleration of the horse during this 3.5min interval

Answers

Answer:

The acceleration of the horse during this time interval is 24.286 m/min²

Explanation:

Given;

initial velocity of the horse during the gallop, u = 543 m /min

final velocity of the horse during the gallop, v = 628 m /min

time of motion, t = 3.5 minutes

The acceleration of the horse is given by the change in velocity per change in time;

[tex]a = \frac{v-u}{t}\\\\a = \frac{628-543}{3.5}\\\\a = 24.286 \ m/min^2[/tex]

Therefore, the acceleration of the horse during this time interval is 24.286 m/min²

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