Answer: B, it’s installed onto your network.
Explanation:
If you need to be able to efficiently find and remove any item, you should use a: linked list
balanced binary search tree maxHeap minHeap
If you need to efficiently find and remove any item, you should use a balanced binary search tree.
A balanced binary search tree, such as an AVL tree or a red-black tree, provides efficient operations for finding and removing items. In a balanced binary search tree, items are organized in a sorted order based on their keys. This allows for efficient searching using comparisons. Additionally, the balanced nature of the tree ensures that the height remains balanced, which guarantees the efficient performance of operations. Linked lists are not suitable for efficient find and remove operations as they require traversing the list, resulting in linear time complexity. Max heaps and min heaps are binary trees optimized for finding the maximum or minimum element, respectively, but they do not provide efficient removal of arbitrary items.
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for a public-key cryptosystem to achieve the same level of security of a private-key cryptosystem with a key length of 128 bits, the public-key cryptosystem would require a key length
T/F
The main answer is false. For a public-key cryptosystem to achieve the same level of security as a private-key cryptosystem with a key length of 128 bits, the public-key cryptosystem would generally require a significantly longer key length.
In a private-key (symmetric) cryptosystem, the same key is used for both encryption and decryption. The security of the system relies on keeping the key secret. A 128-bit key length in a private-key cryptosystem is considered to provide a high level of security, as it offers a large number of possible key combinations that are computationally infeasible to break through brute force attacks.
On the other hand, in a public-key (asymmetric) cryptosystem, there are two mathematically related keys: a public key for encryption and a private key for decryption. The security of the system relies on the computational difficulty of certain mathematical problems, such as factoring large prime numbers or solving the discrete logarithm problem.
Public-key cryptosystems generally require longer key lengths compared to private-key cryptosystems to achieve the same level of security. This is because the computational methods used to break public-key encryption are more efficient than brute force attacks against private-key encryption.
In practice, the key length required for a public-key cryptosystem to achieve a similar level of security as a 128-bit private-key cryptosystem would typically be much larger, often in the range of 2048 bits or more. The specific key length depends on various factors, including the algorithm used, computational advances, and the desired level of security.
Therefore, the statement that a public-key cryptosystem would require a key length equivalent to 128 bits to achieve the same level of security as a private-key cryptosystem is false.
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Which of the following would be found in a Data Link layer header? a. The packet’s fragmentation offset b. The packet’s sequence number c. The source’s logical address d. The source’s physical address
The Data Link layer is the second layer of the OSI model responsible for the reliable transmission of data over a physical link.
In the Data Link layer header, the source's physical address, also known as the MAC address, is typically included. The MAC address is a unique identifier assigned to the network interface card (NIC) of a device. It is used to identify the source of the data on the local network. The packet's fragmentation offset (a) and sequence number (b) are typically found in the network layer header, specifically in protocols like IP (Internet Protocol), which operates at a higher layer than the Data Link layer. such as an IP address, is also part of the network layer header.
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which layer of the osi model has protocols that enable our human network to interface with the underlying data network
The layer of the OSI model that has protocols enabling our human network to interface with the underlying data network is the Application layer.
The Application layer is the topmost layer in the OSI model and is responsible for providing services directly to the end users or applications. It interacts with software applications and provides network services that allow users to access and manipulate network resources. The protocols at the Application layer facilitate tasks such as email communication (SMTP), web browsing (HTTP), file transfer (FTP), and remote login (SSH). These protocols enable human-to-machine or human-to-network interactions by providing a means for users to request and receive information from the underlying data network.
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given a queue q of string elements, please write code to output: - "every other." if the elements are organized in these patterns:
To output "every other" for the elements organized in specific patterns in a queue, you can iterate through the queue and check the positions of the elements.
Here's an example code snippet in C++:
Copy code
void outputEveryOtherPattern(queue<string>& q) {
int position = 0;
while (!q.empty()) {
if (position % 2 == 0) {
cout << q.front() << " ";
}
q.pop();
position++;
}
cout << "every other." << endl;
}
In this code, the outputEveryOtherPattern function takes a queue q as a parameter. It initializes a variable position to keep track of the position of the elements. The while loop iterates as long as the queue is not empty.
Inside the loop, it checks if the current position is even (position % 2 == 0), and if so, it prints the front element of the queue. Then it removes the front element using q.pop() and increments the position. After the loop, it outputs "every other." to indicate the pattern.
This code will output the elements from the queue in the desired pattern, printing every other element. You can modify the code according to your specific needs or patterns you want to achieve.
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.IP telephony and Voice over IP (VoIP) are identical.
False or true?
False. IP telephony and Voice over IP (VoIP) are not identical; VoIP is a specific technology that falls under the broader category of IP telephony.
The statement is false. IP telephony and Voice over IP (VoIP) are related but distinct concepts. IP telephony encompasses any telephony system that uses IP networks to transmit voice calls, including both traditional telephony systems that have been migrated to IP-based infrastructure and newer VoIP systems.
Voice over IP (VoIP) specifically refers to a technology that allows voice communications to be transmitted over IP networks, such as the internet. VoIP utilizes packet-switched networks to convert analog voice signals into digital packets and transmit them as data packets over IP networks. It enables voice communication to be integrated with other data services and offers advantages such as cost savings and flexibility.
While VoIP is a significant component of IP telephony, IP telephony also includes other technologies and protocols that facilitate voice communication over IP networks. This may include IP-based private branch exchange (IP-PBX) systems, session initiation protocol (SIP) for call signaling, and other related technologies.
In summary, IP telephony is a broader term that encompasses various telephony systems using IP networks, while VoIP specifically refers to the technology of transmitting voice calls over IP networks.
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in what type of attack does the attacker need access to the cryptosystem, and the ciphertext to be decrypted to yield the desired plaintext results?
Cryptosystems are used to protect sensitive information by encrypting it and making it unreadable to anyone without the proper key. However, there are certain attacks that can compromise the security of a cryptosystem.
One such attack is known as a known-plaintext attack. In this type of attack, the attacker has access to both the cryptosystem and the ciphertext that has been encrypted. They are then able to use this information to decrypt the ciphertext and obtain the desired plaintext. The attacker may obtain access to the plaintext through a variety of means, such as intercepting a message or stealing a copy of the plaintext. Once they have access to the plaintext and the ciphertext, they can use statistical analysis and other techniques to decipher the key used to encrypt the message. This type of attack is particularly dangerous because it allows the attacker to decrypt any messages that were encrypted with the same key. It is therefore important to use strong encryption techniques and to ensure that the key is kept secret and secure. In conclusion, a known-plaintext attack is a type of attack that requires the attacker to have access to both the cryptosystem and the plaintext in order to decrypt the ciphertext. To protect against this type of attack, it is important to use strong encryption techniques and to keep the key secure.
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_____ is an example of an enterprise-class electronic software.
Microsoft Dynamics 365 is an example of an enterprise-class electronic software.
Enterprise-class electronic software refers to a comprehensive suite of applications designed to help large organizations manage and streamline their operations. These applications typically offer a wide range of functionalities, including customer relationship management (CRM), financial management, supply chain management, and human resources management.
Microsoft Dynamics 365, as an example of enterprise-class electronic software, provides businesses with a unified platform to manage their key business processes. By integrating CRM and ERP capabilities, Dynamics 365 enables organizations to manage their sales, customer service, operations, and financial activities more effectively.
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the virtual machine completely simulates a physical computer system
True A virtual machine (VM) is a software emulation of a physical computer system that allows multiple operating systems to run concurrently on a single physical machine.
The virtual machine provides an isolated environment that replicates the functionality of a physical computer system, including the CPU, memory, storage, and network interfaces.
From the perspective of an operating system or applications running within a virtual machine, it appears and operates as if it is running on a dedicated physical machine. The virtualization software abstracts the underlying hardware and provides virtualized resources to the virtual machine, allowing it to run its own operating system and software stack.
While the virtual machine simulates the behavior of a physical computer system, it is important to note that it is not a complete replica. There may be some differences in performance, resource allocation, and interactions with the underlying hardware.
Nonetheless, the virtual machine provides a high degree of compatibility and functionality to enable the execution of diverse operating systems and applications within a shared physical infrastructure.
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write the interface (.h file) of a class gas tank containing: a data member named amount of type double
Sure! Here's the interface (.h file) of a class `GasTank` with a data member named `amount` of type double:
```cpp
#ifndef GASTANK_H
#define GASTANK_H
class GasTank
{
private:
double amount;
public:
// Constructor
GasTank();
// Getter for the amount
double getAmount() const;
// Setter for the amount
void setAmount(double newAmount);
};
#endif
```
In this interface, the `GasTank` class is declared with a private data member `amount` of type `double`. The public section of the class provides the following member functions:
- The default constructor `GasTank()` to initialize the `amount` member.
- The getter function `double getAmount() const` to retrieve the value of `amount`.
- The setter function `void setAmount(double newAmount)` to update the value of `amount`.The inclusion guards (`#ifndef`, `#define`, `#endif`) ensure that the header file is included only once during the compilation process to prevent multiple definitions.You can implement the member functions in a separate .cpp file to define their behavior.
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a(n) ____ is any combination of operands and operators that yields a result
A(n) "expression" is any combination of operands and operators that yields a result.
An expression is a fundamental concept in programming and mathematics. It represents a computation or calculation that can involve various values (operands) and operations (operators).
Expressions can be simple, consisting of a single value or variable, or complex, involving multiple operands and operators.
In programming, expressions are used to perform calculations, make comparisons, assign values, and determine the control flow of a program. They can include arithmetic operations (addition, subtraction, multiplication, division),
logical operations (AND, OR, NOT), relational operations (greater than, less than, equal to), and more. The result of evaluating an expression is typically a single value or a boolean (true/false) result.
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true/false. a gis is a dss designed specifically to work with spatial information.
True. A GIS (Geographic Information System) is a DSS (Decision Support System) designed specifically to work with spatial information.
GIS is a system that captures, stores, analyzes, and presents spatial or geographic data. It integrates various types of data, including maps, satellite imagery, aerial photographs, and tabular data, to allow users to view, query, and analyze information based on its spatial relationships.DSS, on the other hand, is a broader term referring to computer-based systems that aid in decision-making and problem-solving processes. It encompasses various types of systems, including GIS, which are designed to support decision-making tasks in specific domains or contexts.
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from design view add a command button control to the form
To add a command button control to a form in design view, follow these steps: open the form in design view, click on the "Design" tab, select the "Command Button" control from the "Controls" group, click and drag the mouse cursor on the form to create the button, release the mouse button to place the button on the form, customize the button's appearance and behavior using the "Properties" sheet, save the form, and switch to form view to test the button.
To add a command button control to a form in design view, follow these steps:
1. Open the form in design view.
2. Click on the "Design" tab in the ribbon.
3. Click on the "Command Button" control in the "Controls" group.
4. Click and drag the mouse cursor on the form to create the button.
5. Release the mouse button to place the button on the form.
6. Use the "Properties" sheet to customize the button's appearance and behavior.
7. Save the form and switch to form view to test the button.
In short, a command button control is a type of button control that allows users to trigger an action when clicked. It can be added to a form in design view by selecting the "Command Button" control from the "Controls" group, creating the button on the form, and customizing its properties.
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Suppose that instead of using 16 bits for the network part of a class B address originally, 15 bits had been used. How many class B networks would there have been?
If 15 bits were used for the network part of a class B address instead of the original 16 bits, there would have been 2^15 (32,768) class B networks.
In a class B network, the network part consists of 16 bits. Each bit can have two possible values (0 or 1). By using 16 bits, there are 2^16 (65,536) possible combinations for the network part. However, if only 15 bits were used, the number of possible combinations reduces to 2^15 (32,768). Each combination represents a unique class B network.
Therefore, if 15 bits were used for the network part of a class B address, there would have been 32,768 class B networks. This reduction in the number of available networks is due to the decrease in the number of possible combinations when one fewer bit is used for the network part.
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(1 point) consider the following initial value problem, in which an input of large amplitude and short duration has been idealized as a delta function. y′′ 16π2y=4πδ(t−1)
To solve the initial value problem y'' - 16π^2y = 4πδ(t-1), we can use Laplace transforms.
Taking the Laplace transform of both sides, we get: s^2Y(s) - sy(0) - y'(0) - 16π^2Y(s) = 4πe^(-s). Using the initial conditions y(0) = 0 and y'(0) = 0, the equation simplifies to: (s^2 - 16π^2)Y(s) = 4πe^(-s). Solving for Y(s), we have:
Y(s) = (4πe^(-s)) / (s^2 - 16π^2). To find the inverse Laplace transform of Y(s), we need to decompose it into partial fractions. However, the specific form of Y(s) after simplification is not provided, so further calculations are necessary to determine the solution y(t).
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sending a traceroute message as a single packet is experimental.
a. true b. false
The statement is true.
Sending a traceroute message as a single packet is an experimental technique known as "UDP Traceroute". Traditional traceroute messages are sent using Internet Control Message Protocol (ICMP) packets, which are designed for network error reporting and diagnostics.
UDP Traceroute uses User Datagram Protocol (UDP) packets instead of ICMP packets, which allows the entire traceroute message to be sent in a single packet. This technique can provide faster and more efficient traceroute results, but it is not widely supported by all network devices and operating systems.
UDP Traceroute is considered experimental because it may not work correctly in all network environments, and some network security tools may block UDP packets. Additionally, because UDP is a connectionless protocol, UDP Traceroute may not provide the same level of accuracy and reliability as traditional ICMP-based traceroute.
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the csirt is also known as the ir reaction team.T/F
We can see here it is true that a Computer Security Incident Response Team (CSIRT) is also known as an IR (Incident Response) team.
What is Computer Security Incident Response Team (CSIRT)?A Computer Security Incident Response Team (CSIRT) is a team that is responsible for handling computer security incidents, such as data breaches, malware infections, and denial-of-service attacks. CSIRTs typically have a team of experts who can investigate incidents, respond to them, and mitigate their impact.
CSIRTs can be either government-run or private-sector organizations. Government-run CSIRTs typically focus on national security, while private-sector CSIRTs focus on protecting the assets of their organization.
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.To what extent can a pie chart be rotated?
Up to 360 degrees
Up to 180 degrees
Up to 45 degrees
Up to 90 degrees
The rotation is usually done by dragging the chart with a mouse or touchpad, and it can be rotated in any direction up to 360 degrees, allowing the viewer to see the chart from all angles.
A pie chart is a circular chart that is divided into sectors to represent numerical proportions. Each sector's size is proportional to the quantity it represents. The chart's main purpose is to display the relative sizes of different categories in a dataset. The chart's slices or sectors are typically arranged in a clockwise direction, with the first slice starting at 12 o'clock. The chart can be rotated to show different perspectives or highlight specific slices of data.
However, it's essential to note that rotating a pie chart can sometimes make it difficult to read or understand the data it represents. For instance, if the chart is rotated too much, it might become challenging to compare the size of different sectors accurately. As a result, it's essential to use discretion when rotating pie charts to ensure that the data remains clear and understandable
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what are the specific advantages of a pert network chart? more than one answer may be correct.
The PERT (Program Evaluation and Review Technique) network chart offers several advantages in project management. Some of the specific advantages include:
Visual Representation: PERT charts provide a visual representation of the project tasks and their dependencies, allowing stakeholders to easily understand the project flow and timeline. Task Sequencing: PERT charts highlight the sequential relationships between tasks, helping project managers determine the most efficient order of execution and identify any potential bottlenecks or dependencies.
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which of the following defines a constructor that initializes one attribute?
To define a constructor that initializes one attribute, you can use the following code:
```
public class ClassName {
private DataType attributeName;
public ClassName(DataType value) {
this.attributeName = value;
}
}
```
In this code, the constructor takes one argument of type `DataType`, which initializes the `attributeName` attribute of the class. The `this` keyword refers to the current object of the class, allowing you to set the value of the attribute to the value passed in as an argument. A constructor is a special method in object-oriented programming languages that is used to create and initialize an object of a class.
The constructor is called automatically when a new instance of the class is created, and it is responsible for allocating memory for the object and initializing its member variables to default or user-defined values.
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which of the following hashing algorithm is the common standard used for generating digital signatures
The common standard hashing algorithm used for generating digital signatures is SHA-256 (Secure Hash Algorithm 256-bit).
SHA-256 is a cryptographic hash function that belongs to the SHA-2 (Secure Hash Algorithm 2) family. It generates a 256-bit (32-byte) hash value, which is commonly used in digital signature schemes and cryptographic protocols. SHA-256 is widely adopted and considered secure for generating digital signatures due to its collision resistance and computational efficiency. Digital signatures provide integrity, authenticity, and non-repudiation of data. The use of a strong hashing algorithm like SHA-256 ensures the integrity and security of the digital signature process, making it reliable for various applications, including secure communication, data verification, and authentication.
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what is the electronic digital lifting of portions of a previously recorded work for insertion in a new master recording
Electronic digital lifting of portions of a previously recorded work for insertion in a new master recording is a technique used in music production and sound design. This process, also known as sampling.
Sampling process involves extracting specific segments or elements from an existing audio track and incorporating them into a new composition.
Sampling can include lifting beats, melodies, vocals, or other sounds to create unique blends and creative reinterpretations of original pieces.
This method is commonly used in
various music genres, such as hip-hop, electronic, and pop music, to enhance the overall texture and depth of a new master recording. While sampling can inspire creativity and innovation, it's crucial to obtain the necessary permissions to avoid copyright infringement.
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what makes ip spoofing possible for computers on the internet?
IP spoofing is a technique that enables computers on the internet to send data packets with a forged or fake IP address. The primary reason why IP spoofing is possible is due to the architecture of the internet. The internet is designed to facilitate data communication between multiple devices across a network of interconnected devices.
IP addresses are used to identify the source and destination of data packets as they travel across the network. However, there are no built-in mechanisms to verify the authenticity of the IP addresses that are used in the communication.In addition, many internet protocols rely on the trust of the sender, rather than verifying the authenticity of the sender. This means that a computer can easily create and send a packet with a forged IP address without being detected. Moreover, hackers can exploit vulnerabilities in internet protocols to launch IP spoofing attacks. For example, a hacker can send data packets to a target computer with a forged IP address, making it appear as if the packets originated from a trusted source.In summary, IP spoofing is possible because of the lack of authentication mechanisms in the internet protocols and the trust-based nature of communication protocols. As a result, it is crucial to implement security measures such as firewalls, intrusion detection systems, and encryption to prevent IP spoofing attacks.
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write the sql query to display the eight departments in the lgdepartment table sorted by department name
To write the sql query to display the eight departments in the `lgdepartment` table sorted by department name, you can use the following SQL query:
sql
SELECT *
FROM lgdepartment
ORDER BY department_name
LIMIT 8;
This query selects all columns (`*`) from the `lgdepartment` table, sorts the result set by the `department_name` column in ascending order (alphabetical order), and limits the output to only the first eight rows using the `LIMIT` keyword. Make sure to replace `lgdepartment` with the actual name of your department table, and adjust the column names if they differ in your schema.
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JAVA PROGRAMMING QUESTION
Indefinite Loops and Random Numbers [20 points] Write a Java program that has a method called diceSum() which accepts a Scanner object as a parameter that prompts for a desired sum from a user, then repeatedly simulates the rolling of 2 sixsided dice until their sum is the desired sum (you should use a while loop). Below is a sample dialogue with a user (bold value indicates user input): Desired dice sum: 8 4 and 3 = 7 3 and 2 = 5 5 and 6 = 11 … 5 and 3 = 8 got it!
The provided Java program includes a diceSum() method that takes user input for a desired sum. It then simulates rolling two six-sided dice until the sum matches the desired value using a while loop and generates random values using the Random class.
Here is the Java program that has a method called diceSum() which accepts a Scanner object as a parameter that prompts for a desired sum from a user, then repeatedly simulates the rolling of 2 sixsided dice until their sum is the desired sum (you should use a while loop).
Program:#import java.util.Scanner;#import java.util.Random;public class DiceRoll { public static void main(String[] args) { Scanner input = new Scanner(System.in);System.out.print("Desired dice sum: ");int sum = input.nextInt();diceSum(sum);input.close(); } public static void diceSum(int sum) { Random rand = new Random();int die1 = 0;int die2 = 0;int roll = 0; while (roll != sum) { die1 = rand.nextInt(6) + 1;die2 = rand.nextInt(6) + 1;roll = die1 + die2; System.out.println(die1 + " and " + die2 + " = " + roll); } System.out.println("Got it!"); } }
The given program prompts the user for a desired sum and passes it to the diceSum() method. The diceSum() method uses a while loop to simulate the rolling of 2 six-sided dice until their sum is the desired sum. A Random object is used to generate random values for the dice rolls.
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what is the function of the windows compatibility center?
The Windows Compatibility Center is a website and tool provided by Microsoft that helps users determine if their hardware or software is compatible with a specific version of Windows operating system. The Compatibility Center provides a comprehensive database of all the devices and software that have been tested by Microsoft to work with Windows.
In more detail, the Compatibility Center allows users to search for a specific product or device and check its compatibility status with Windows. The tool provides information on whether the device or software is compatible with Windows 10, 8.1, 7, Vista, or XP. If the product is not compatible, the tool will suggest alternative products that are compatible with the specific version of Windows.
In summary, the Windows Compatibility Center helps users make informed decisions when it comes to purchasing hardware or software that is compatible with their Windows operating system.
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what kind of connectivity does directaccess establish between workstation and server?
DirectAccess establishes a secure and seamless connectivity between workstations and servers.
How does DirectAccess enable a secure and seamless connection between workstations and servers?DirectAccess is a remote access technology introduced by Microsoft that allows users to access resources on a corporate network without the need for traditional VPN connections. It creates an "always-on" connection between the client workstation and the server, establishing a secure tunnel over the Internet.
This connectivity enables users to access internal resources, such as file shares, intranet websites, and applications, as if they were directly connected to the corporate network. DirectAccess utilizes IPv6 transition technologies to ensure compatibility with both IPv4 and IPv6 networks, providing a transparent and efficient connection experience.
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The top edge of a fence that is running along the length of a neighboring wall is parallel to the plane of the horizon. What kind of symmetry is this an example of? impartial vertical diagonal horizontal
Complete and test the HashedDictionary class started in the text.
It's fine if you want to put each class all into one file, instead of splitting them into header file and implementation file.
Step 1
First complete the "Entry" class. The text provides the header file. It just consists of constructors, mutators, and accessors. You need to write the implementation. You can delete the == and > operator overloads.
Step 2
Next complete the "HashedEntry" class. The text provides the header file. Once again, you'll need to write the implementation, and once again, it's just constructors, accessors, and mutators.
Step 3
Next write the HashedDictionary class. The HashedDictionary class must be derived from the DictionaryInterface class given in the text, except that you should delete the "traverser()" function. The data members are given to you in the text, as are the add() function and the remove() function. You may want to add a display() member function to your HashedDictionary class for testing purposes.
Regarding repeated search keys, we will leave the behavior undefined. In other words, don't even think about what should happen if repeated search keys are encountered.
For the getHashIndex() function, you are required to use the technique described at the top of page 549 in the text. (To be specific, you'll use Horner's rule, and you'll modulus by the tableSize after each parenthesized expression in Horner's rule.) I would suggest that you just use something very simple for the getHashIndex() function at first. For example, you could simply add the ASCII codes of each character in the searchKey. Then write your client program to make sure everything is working. Then you'll just need to rewrite the getHashIndex() function to use the required technique.
To keep things simple, we will fudge things a little for the getHashIndex() function. Normally this function would be provided by the client. We will instead include this function in the HashedDictionary class, and we will simply assume (for this function only) that the search key is always a string. The word "string" won't occur anywhere in your HashedDictionary code, but you'll treat the search key as if it is a string, using expressions such as searchKey[i]. Here is my function header for the getHashIndex() function:
template
int HashedDictionary::getHashIndex(const KeyType& searchKey) const
Step 4
Write a client program to test your class. The program should read a file containing information about famous people (name, age, zip code, etc.) and store the data in a HashedDictionary object. It should then test all of the member functions of the HashedDictionary class. This could get long, but don't worry about decomposing. You can just have a really long main() function.
I've provided the start of the client program, as well as the data file (famous.txt). You'll need to add code to main() to test the remaining member functions.
Each FamousPerson will have the following data fields:
a (non-unique) ID number, stored as a string
an income tax status, stored as a single char (m for married, s for single, h for head of household)
last name (the search key), stored as a string
first name, stored as a string
age, stored as an int
street, stored as a string
zip code, stored as a string
Assume that all strings are single words (no spaces)
The implementation of the classes and the client program to test the HashedDictionary class is given in the solution.
Here's the complete code:
```cpp
#include <iostream>
#include <fstream>
#include <string>
template <class KeyType, class ItemType>
class DictionaryInterface {
public:
virtual bool isEmpty() const = 0;
virtual int getNumberOfItems() const = 0;
virtual bool add(const KeyType& searchKey, const ItemType& newItem) = 0;
virtual bool remove(const KeyType& searchKey) = 0;
virtual void clear() = 0;
virtual ItemType getItem(const KeyType& searchKey) const = 0;
};
template <class KeyType, class ItemType>
class Entry {
private:
KeyType searchKey;
ItemType item;
public:
Entry() {}
Entry(KeyType newKey, ItemType newItem) : searchKey(newKey), item(newItem) {}
void setKey(const KeyType& newKey) {
searchKey = newKey;
}
void setItem(const ItemType& newItem) {
item = newItem;
}
KeyType getKey() const {
return searchKey;
}
ItemType getItem() const {
return item;
}
};
template <class KeyType, class ItemType>
class HashedEntry : public Entry<KeyType, ItemType> {
private:
HashedEntry<KeyType, ItemType>* nextPtr;
public:
HashedEntry() : nextPtr(nullptr) {}
HashedEntry(KeyType newKey, ItemType newItem)
: Entry<KeyType, ItemType>(newKey, newItem), nextPtr(nullptr) {}
void setNext(HashedEntry<KeyType, ItemType>* nextEntryPtr) {
nextPtr = nextEntryPtr;
}
HashedEntry<KeyType, ItemType>* getNext() const {
return nextPtr;
}
};
template <class KeyType, class ItemType>
class HashedDictionary : public DictionaryInterface<KeyType, ItemType> {
private:
static const int DEFAULT_CAPACITY = 11;
HashedEntry<KeyType, ItemType>** hashTable;
int itemCount;
int hashTableSize;
int getHashIndex(const KeyType& searchKey) const;
public:
HashedDictionary();
HashedDictionary(const HashedDictionary<KeyType, ItemType>& dict);
virtual ~HashedDictionary();
bool isEmpty() const;
int getNumberOfItems() const;
bool add(const KeyType& searchKey, const ItemType& newItem);
bool remove(const KeyType& searchKey);
void clear();
ItemType getItem(const KeyType& searchKey) const;
void display() const;
};
template <class KeyType, class ItemType>
HashedDictionary<KeyType, ItemType>::HashedDictionary()
: itemCount(0), hashTableSize(DEFAULT_CAPACITY) {
hashTable = new HashedEntry<KeyType, ItemType>*[hashTableSize];
for (int i = 0; i < hashTableSize; i++)
hashTable[i] = nullptr;
}
template <class KeyType, class ItemType>
HashedDictionary<KeyType, ItemType>::HashedDictionary(const HashedDictionary<KeyType, ItemType>& dict) {
itemCount = dict.itemCount;
hashTableSize = dict.hashTableSize;
hashTable = new HashedEntry<KeyType, ItemType>*[hashTableSize];
for (int i = 0; i < hashTableSize; i++) {
if (dict.hashTable[i] != nullptr) {
HashedEntry<KeyType, ItemType>* entryPtr = new HashedEntry<KeyType, ItemType>(
dict.hashTable[i]->getKey(), dict.hashTable[i]->getItem());
hashTable[i] =
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what happens when you click the increase indent button?
When you click the increase indent button, the selected text will move further to the right within the document. This is a formatting option that can be useful for creating lists or subheadings within a larger section of text.
The increase indent button is typically located on the formatting toolbar or in the paragraph options of a document editing program. It can be used to visually separate blocks of text or to create a hierarchy of information within a document. When clicked, the button adds space to the left margin of the selected text, pushing it further to the right and creating a nested effect. This can be used multiple times to create deeper levels of indentation within a document.
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