You are at the top of the Empire State Building on the 102nd floor, which is located 373 mm above the ground, when your favorite superhero flies over the building parallel to the ground at 70.0 %% the speed of light. Part A You have never seen your favorite superhero in real life. Out of curiosity you calculate her height to be 1.57 mm . If the superhero landed next to you, how tall would she be when standing

F = Kq₁q₂/(r)²

K is a constant

R is the distance between them

F = 9.0 E9 × 1.0 E-6 × 1.0 E-6/(0.30)²

= 9.0E-3/0.30² = 9.0E-3/0.09 = 0.1 N

The electrostatic force of repulsion between two charges can be determined using Coulomb's law of electrostatic force. The force of repulsion between the point charges of magnitude 1 ×10 ⁻⁶ C separated by 0.30 m is 0.1 N.

According Coulomb's law of electrostatic forces, the force between two charges q1 and q2 separated by a distance of r meters is given by the expression:

F =  K q1 q2/r²

Where, K is Coulomb's Constant equal to  9.0 ×10⁹ Nm²/C²

Given q1 = q2 = 1 ×10 ⁻⁶ C

r = 0.30 m

k = 9.0 ×10⁹ Nm²/C².

Then the electrostatic force of repulsion between the two point charges is calculated as follows:

F = 9.0 ×10⁹ Nm²/C² × 1 ×10 ⁻⁶ C × 1 ×10 ⁻⁶ C/ (0.30 m )²

  = 0.1 N.

Therefore, the repulsive force exerted on two point charges that each carry 1.0 E-6 C of negative charge and are 0.30 meters apart is 0.1 N.

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Answer:

[tex]I=0.0987kg.m^2[/tex]

Explanation:

From the question we are told that:

Mass [tex]M=1.80kg[/tex]

Deviation [tex]d=0.250[/tex]

Time [tex]t=0.940s[/tex]

Generally the equation for moment of inertia is mathematically given by

 [tex]I=\frac{T}{2\pi}^2(mgd)[/tex]

 [tex]I=\frac{0.94}{2.3.142}^2(1.80*9.8*0.250)[/tex]

 [tex]I=0.0987kgm^2[/tex]

Answer:

Explanation:

a= (v-u)/t where v = the final velocity at 50m/s, u= the inital velocity at 30m/s and t= the time taken at 30 seconds

a=(50-30)/30

a= 2/3m/s^-2 or 0.67m/s^-2  (m/s^-2 is the units for accelaration)

Answer:

Un'auto si muove lungo un percorso rettilineo con velocità variabile come mostrato in figura. Quando l'auto è in possesso di A, la sua velocità è 10 ms-1 e quando è in posizione B, la sua velocità è 20 ms-1. Se l'auto impiega 5 secondi per spostarsi da A a B, trova l'accelerazione dell'auto.

Explanation:

Answer:

19

Explanation:

I legit did this and it took 19.

Answer:

100N in the opposite direction

Explanation:

as the block is not moving, we can apply the formula f=ma where the total force is equal to the mass times accelaration, since the block is not moving, the net force is zero meaning that the other force is completely cancelling out the force of 100N, or to put it in a maths equation, 100-force=0 as the block is stationary. we can therefore assume that the force cancelling the 100N out is equal to it and therefore 100N in the opposite direction

Answer:

Magnitude of the average force = 7.85 N

Explanation:

Data given:

Mass of bullets, m = 6.4 g

Rate of bullets/min, r = 92 bullets/min

Speed of each bullet, v = 400 m/s

Change in momentum here, Δ B = Bf - Bi

where f is the final and i is the initial

Note that change in momentum = force X time

So, Δ B = m(vf - vi)

              = 2mv

             = 2 X 0.0064 kg X 400 m/s        (convert g to kg)

            = 5.12 kg.m/s (for one bullet)

        so for the 92 bullets = 92 X 5.12 kg.m/s

           = 471.04 kg.m/s

         The force = Δ B ÷ Δt

where t = time measured in 60 seconds

        =  471.04 kg.m/s ÷ 60 seconds

       = 7.85 N

Answer:

9.2 V

Explanation:

The RMS value of an AC is the effective value of a varying voltage or current in DC, that is the equivalent value of the AC which produces the same effect as an DC. For example if a motor is supplied by a 9V RMS voltage, it will rotate as if the voltage applied was 9V DC.

The RMS value is given by:

RMS voltage = Peak voltage * 1/√2

Given that the maximum voltage should not exceed 13 V, this means that the peak voltage is 13 V. The maximum RMS voltage is:

RMS voltage = Peak voltage * 1/√2 = 13 * 1/√2 = 9.2 V

Answer:

1.20Nm

Explanation:

Given data

Force= 53.5N

Perpendicular distance= 2.25cm= 2.25/100= 0.0225m

The expression for the torque is given as

Torque= Force* Perpendicular distance

Torque= 53.5*0.0225

Torque= 1.20Nm

Hence the toque produced is  1.20Nm

Answer:

The correct answer is -

B. The velocity would double (v = 2v).

C. The wavelength would be half (λ = λ/2).

Explanation:

A wave has a speed or velocity that is related to the wavelength of the wave and the frequency of the wave and this relationship can be represented by the following equation-

Wave velocity V = Wavelength (λ) * Frequency (f)

Frequency (f) = Velocity (V) / Wavelength(λ).

The frequency and wavelength are inversely proportional and frequency and velocity are directly proportional to each other.

So, if f = 2f then,

putting value in the formula,

2f = 2v/λ, which means, f = 2v and f = λ/2

when the frequency is doubled, the wavelength will be halved and velocity will be doubled.

Answer:

the ratio Kf : Ki is  1 / 4 or 1 : 4

Explanation:

Given the data in the question;

Since this is a perfectly inelastic collision, momentum is conserved;

[tex]P_{initial[/tex] = [tex]P_{final[/tex]

Now for BLOCK 1

mass = M₁ = M

KE = K[tex]_i[/tex]

[tex]\frac{1}{2}[/tex]mv[tex]_i[/tex]₁² = K[tex]_i[/tex]

we solve for v[tex]_i[/tex]₁

mv[tex]_i[/tex]₁² = 2K[tex]_i[/tex]

v[tex]_i[/tex]₁ = √( 2K[tex]_i[/tex] / m )

for BLOCK 2

mass = M₂ = 3m and since its at rest v[tex]_i[/tex]₂ = 0

Now after the collision; Total mass = m + 3m = 4m

KE = K[tex]_f[/tex]

[tex]\frac{1}{2}[/tex]( 4m )v[tex]_f[/tex]² = K[tex]_f[/tex]

(2m)v[tex]_f[/tex]² = K[tex]_f[/tex]

v[tex]_f[/tex] = √(K[tex]_f[/tex] / 2m)

so since [tex]P_{initial[/tex] = [tex]P_{final[/tex]

[m₁ × v[tex]_i[/tex]₁] + [m₂ × v[tex]_i[/tex]₂] = ( m + 3m ) × v[tex]_f[/tex]

so

[ m₁ × √( 2K[tex]_i[/tex] / m ) ] + [ m₂ × 0 ] = ( m + 3m ) × [ √(K[tex]_f[/tex] / 2m) ]

[ m × √( 2K[tex]_i[/tex] / m ) ] = 4m × [ √(K[tex]_f[/tex] / 2m) ]

square both side

m² ×  2K[tex]_i[/tex] / m  = (4m)² × K[tex]_f[/tex] / 2m

m² ×  2K[tex]_i[/tex] / m  = 16m² × K[tex]_f[/tex] / 2m

m × 2K[tex]_i[/tex]  = 8m × K[tex]_f[/tex]

2K[tex]_i[/tex]  =  8K[tex]_f[/tex]

K[tex]_f[/tex] = 2K[tex]_i[/tex] / 8

K[tex]_f[/tex] / K[tex]_i[/tex] = 2 / 8

K[tex]_f[/tex] / K[tex]_i[/tex] = 1 / 4

Therefore,  the ratio Kf : Ki is  1 / 4 or 1 : 4

The ratio of the final kinetic energy to initial kinetic energy of the blocks is determined as 1:4.

The speed of the two blocks after collision is determined by applying the principle of conservation of linear momentum as follows;

m1u1 + m2u2 = v(m1 + m2)

mu1 + m2(0) = v(m + 3m)

mu1 = v(4m)

u1 = 4v

[tex]\frac{K.E_f}{K.E_i} = \frac{0.5(4m)v_f^2}{0.5(m)u_1^2} \\\\\frac{K.E_f}{K.E_i} = \frac{4(v_f)^2}{u_1^2} \\\\\frac{K.E_f}{K.E_i} = \frac{4v_f^2}{(4v_f)^2} = \frac{4v_f^2}{16v_f^2} = \frac{1}{4} = 1:4[/tex]

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Answer: [tex]1.67\ V[/tex]

Explanation:

Given

Work function [tex]\phi =1.17\ eV[/tex]

The wavelength of the light is [tex]\lambda =437\ nm[/tex]

Energy associated with this wavelength is

[tex]E=\dfrac{hc}{\lambda}\\\\\Rightarrow E=\dfrac{1.99\times 10^{-25}}{437\times 10^{-9}}\\\\\Rightarrow E=4.553\times 10^{-19}\ J\\\\\Rightarrow E=2.841\ eV[/tex]

Stopping potential is

[tex]V=\dfrac{E-\phi }{e}\\\\\Rightarrow V=\dfrac{\left(2.841-1.17\right)e}{e}\\\\\Rightarrow V=1.67\ V[/tex]

Answer:

convex       f = 33 cm

concave     f = -33 cm

Explanation:

In geometric optics the focal length of a lens is given by

         [tex]\frac{1}{f} = ( n-1) \ (\frac{1}{R_2} - \frac{1}{R_1} )[/tex]

where n is the refractive index of the medium, R₁ and R₂   are the focal lengths on each side of the lens.

In this case one of the sides is flat so its focal length is infinite, if the lens is convex the focal length is positive, convergent lens and if it is concave the focal length is negative, divergent lens.

         [tex]\frac{1}{f} = (n-1) \ \frac{1}{R}[/tex]

the refractive index of the glass is n = 1.5

let's calculate

         1 / f = (1.5 -1) 1 / 16.5

         1 / f = 0.03030

          f = 33 cm

convex       f = 33 cm

concave     f = -33 cm

Answer:

Explanation:

Geostationary satellites orbit around the Earth at the same rate as the Earth rotates so that the satellites are over the same spot on Earth all the time.

They are called geostationary due to their movement.

Geostationary satellites are a key tool for scientists to monitor and observe the Earth's atmosphere.  

Answer:

the magnitude of the average contact force exerted on the leg is  3466.98 N

Explanation:

Given the data in the question;

Initial velocity of hand v₀ = 5.25 m/s

final velocity of hand v = 0 m/s

time interval t = 2.65 ms = 0.00265 s

mass of hand m = 1.75 kg

We calculate force on the hand F[tex]_{hand[/tex]

using equation for impulse in momentum

F[tex]_{hand[/tex] × t = m( v - v₀ )

we substitute

F[tex]_{hand[/tex] × 0.00265  = 1.75( 0 - 5.25 )

F[tex]_{hand[/tex] × 0.00265  = 1.75( - 5.25 )

F[tex]_{hand[/tex] × 0.00265  = -9.1875

F[tex]_{hand[/tex] = -9.1875 / 0.00265  

F[tex]_{hand[/tex] = -3466.98 N

Next we determine force on the leg F[tex]_{leg[/tex]

Using Newton's third law of motion

for every action, there is an equal opposite reaction;

so, F[tex]_{leg[/tex] = - F[tex]_{hand[/tex]

we substitute

F[tex]_{leg[/tex] = - ( -3466.98 N )

F[tex]_{leg[/tex] = 3466.98 N

Therefore, the magnitude of the average contact force exerted on the leg is  3466.98 N

Answer:

The correct answer is "164.06 nm".

Explanation:

Refractive index,

n = 1.75

Wavelength,

λ = 525 nm

Now,

The maximum thickness of the film will be:

⇒ [tex]t=\frac{\lambda}{2n}[/tex]

On substituting the values, we get

⇒    [tex]=\frac{525}{2\times 1.75}[/tex]

⇒    [tex]=\frac{525}{3.5}[/tex]

⇒    [tex]=164.06 \ nm[/tex]

Answer:

Gy = 3.14x10⁻⁴ Gy

Explanation:

To get the dose in Gy we need to use the following expression:

Gy = E / m  (1)

Where:

Gy: dose

E: energy absorbed per atom

m: mass of the human body.

We don't have the energy per atom, but we can calculate that by following the next procedure.

First, let's determine the number of atoms of potassium in our body. For that we need to determine the moles in the 140 g of potassium, with the molecular mass and then, use the avogadro's number:

moles = m/MM

moles = 140 / 39.1 = 3.58 moles

N° atoms = 3.58 * 6.02x10²³ atoms = 2.16x10²⁴ atoms of K.

The abundance of the ⁴⁰K is 0.012% so the atoms of this isotope would be:

N = 2.16x10²⁴ * (0.012/100) = 2.59x10²⁰ atoms of ⁴⁰K.

With this number, and the half life rate, we can determine the number of decay atoms in a year (λ) using the following expression:

λ = ln2 / t(1/2)

λ = ln2 / 1.3x10⁹ = 5.33x10⁻¹⁰ year⁻¹

This number, multiplied by the number of atoms:

R = 5.33x10⁻¹⁰ * 2.59x10²⁰ = 1.38x10¹¹ atoms/year

Now, each atom of K gives an average energy of 1 MeV, so with the atoms we have:

E = 1.38x10¹¹ * 1x10⁶ eV = 1.38x10¹⁷ eV

This value can be expressed in Joules so:

E = 1.38x10¹⁷ eV * (1 J / 6.24x10¹⁸ eV) = 0.022 J

Finally, we can use (1) to get the dose in Gy:

Gy = 0.022 / 70

Hope this helps

Answer:

The total resistance is 106 Ω and the current in the circuit is 0.11 A.

Explanation:

Given that,

Voltage of the battery, V = 12 V

Resistors 34 Ω, 42Ω, and 30Ω are connected in series.

The total resistance is given by :}

R = 34 + 42 +30

= 106Ω

Let I is the total current in the circuit. Using ohm's law to find it such that,

[tex]I=\dfrac{V}{R}\\\\I=\dfrac{12}{106}\\\\I=0.11\ A[/tex]

Hence, the total resistance is 106 Ω and the current in the circuit is 0.11 A.

Answer:

B. Frequency

Explanation:

Answer:

1 > X

Explanation:

8 > 3x + 5

-5 - 5

---------------

3 > 3x

3÷3=1

A tennis ball and a bowling ball can have the same momentum. This is because, it depends upon both the mass of object and velocity of object.

Momentum can be defined as the mass in motion. All objects which have mass so, if an object is moving in space, then it has some amount of momentum which has its mass in motion. The amount of momentum which an object has depend upon two variables which include how much stuff is moving that is the mass of object and how fast the stuff is moving that is the speed.

A fast-moving tennis ball may have the same momentum as a slow-bowling ball. It is important to understand here that the momentum of an object which depends on the product of the mass and velocity of an object, but not the mass or the velocity alone.

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Answer:

1700 kg

Explanation:

Let’s use conservation of momentum

32.5 * 388 = 7.42 * mc

mc = 1699.46

mc = 1700 kg

Answer: 708 N

Explanation:

Given

At rest, Elevator reads 588 N

When it starts moving upward at [tex]2\ m/s^2[/tex], apparent weight changes

i.e. weight can be given by

[tex]\Rightarrow W'=m(g+a)\\\Rightarrow W'=mg+mg\cdot \dfrac{a}{g}\\\\\Rightarrow W'=W\left(1+\dfrac{a}{g}\right)\\\\\Rightarrow W'=588\left(1+\dfrac{2}{9.8}\right)\\\\\Rightarrow W'=707.99\approx 708\ N[/tex]

The apparent weight is 708 N

Answer:

I think concave

Explanation:

Answer:

(a) The work function is 1.86 eV.

(b) The cut off frequency is 450 THz.

(c) The stopping potential is 1.16 V.

Explanation:

incident wavelength = 620 nm

Kinetic energy, K = 0.14 eV

According to the photoelectric equation

E = W + KE

where, W is the work function, KE is the kinetic energy.

(a) Let the work function is W.

[tex]W = E - KE\\W = \frac{h c}{\lambda }- KE\\W =\frac{6.63\times 10^{-34}\times3\times 10^{8}}{620\times 10^{-9}\times 1.6\times 10^{-19}}-0.14\\\\W =1.86 eV[/tex]

(b) Let the cut off frequency is f.

W = h f

[tex]1.86\times 1.6\times 10^{-19} = 6.63\times 10^{-34}\times f\\f = 4.5\times 10^{14} Hz =450 THz[/tex]

(c) Let the stopping potential is V.

[tex]E = W + eV\\\frac{6.63\times 10^{-34}\times 3\times 10^{8}}{420\times 10^{-9}\times 1.6\times 10^{-19}}=1.8 + eV\\\\V = 1.16 V[/tex]

Answer:

P = 756.84 Watts

Explanation:

As the tension is stationary or innitial, T₀ = 31 N, the mean would be:

T₁ + T₂ / 2 = T₀    (1)

T₁ + T₂ = 2 * 31 = 62 N

Now, with the following expression we can determine the linear speed:

V = πWD  (2)

W: angular speed of the wheel  (rev/s)

D: diameter of the wheel (in meters)

W = 1547 rev/min * (1 min/60 s) = 25.78 rev/s

V = π * 25.78 * 0.379 = 30.695 m/s

We also know that:

T₁ / T₂ = exp (μθ)

T₁ = T₂ exp(μθ)   (3)

We already have those values so replacing:

T₁ = T₂ exp(0.3 * 161 * π/180)

T₁ = 2.32T₂   (4)

We can now replace (4) in (1) like this:

T₁ + T₂ = 62 N

2.32T₂ + T₂ = 62

3.32T₂ = 62

T₂ = 18.67 N

Which means that T₁:

T₁ = 2.32(18.67)

T₁ = 43.33 N

Finally, the power can be determined using the following expression:

P = (T₁ - T₂)V  (5)       Replacing we have:

P = (43.33 - 18.67)*30.695

Hope this helps